67486 + Interview Questions in Secondary School in Physics

1.	A 240m long train crosses aplatform having length of twice of the train's length in 4 sec. What is the speed of train
Answer» Question⇒ A 240m LONG train crosses aplatform having length of twice of the train's length in 4 sec. What is the speed of train. Explanation: length of the train is 240m PLATFORM length is 2 times the length of the train 2240=480 The train ENGINE should start at the beginning of the platform and the last coach should end at the end of the platform Additionally the train has to move 240 m to cross the platform because the end coach should leave the platform 480+240=720 Distance =720m Time=4 sec Velocity =distance /time =720/4 =180m/sec 18o18/5=64.8kmph the speed of the train is 648kmph

1.

A 240m long train crosses aplatform having length of twice of the train's length in 4 sec. What is the speed of train

Answer»

Question⇒ A 240m LONG train crosses aplatform having length of twice of the train's length in 4 sec. What is the speed of train.

Explanation:

length of the train is 240m
PLATFORM length is 2 times the length of the train 2*240=480
The train ENGINE should start at the beginning of the platform and the last coach should end at the end of the platform
Additionally the train has to move 240 m to cross the platform because the end coach should leave the platform
480+240=720
Distance =720m
Time=4 sec
Velocity =distance /time
=720/4
=180m/sec
18o*18/5=64.8kmph
the speed of the train is 648kmph

Discussion

2.	Prepare any chart on physics.
Answer» ANSWER: PLEASE TELL the TOPIC FIRST

2.

Prepare any chart on physics.

Answer»

ANSWER:

PLEASE TELL the TOPIC FIRST

Discussion

3.	A hemispherical surface of radius r is located in a uniform electric field that is parallel to the axis of the hemisphere what is the magnitude of the electric flux through the hemisphere surface
Answer» Question⇒ A hemispherical surface of radius R is located in a UNIFORM electric field that is parallel to the axis of the hemisphere what is the magnitude of the electric flux through the hemisphere surface? Explanation: Since number of field lines ENTERING from circular side is equal to number of field lines LEAVING the hemispherical surface, net flux is 0. therefore (Flux)h + (flux)C = 0 ——→ 1[* (flux)h means flux from hemispherical surface and (flux)c means flux from circular surface] Therefore, (flux)h = - (flux)c ———→ 2 Flux = E.A [ Where E and A are vectors ] Flux = E A cos θ (Flux)c = EA cos π [ Because field and surface area vector are anti parallel] (flux)c = E πR^2 (-1) ———→ 3 [ Because area of circular surface is πR^2 ] From equation 2 and 3 (flux)h = - (- EπR^2) => (Flux)h = EπR^2 Hope this helped !

3.

A hemispherical surface of radius r is located in a uniform electric field that is parallel to the axis of the hemisphere what is the magnitude of the electric flux through the hemisphere surface

Answer»

Question⇒ A hemispherical surface of radius R is located in a UNIFORM electric field that is parallel to the axis of the hemisphere what is the magnitude of the electric flux through the hemisphere surface?

Explanation:

Since number of field lines ENTERING from circular side is equal to number of field lines LEAVING the hemispherical surface, net flux is 0.
therefore (Flux)h + (flux)C = 0 ——→ 1[* (flux)h means flux from hemispherical surface and (flux)c means flux from circular surface]
Therefore, (flux)h = - (flux)c ———→ 2
Flux = E.A [ Where E and A are vectors ]
Flux = E A cos θ
(Flux)c = EA cos π [ Because field and surface area vector are anti parallel]
(flux)c = E πR^2 (-1) ———→ 3 [ Because area of circular surface is πR^2 ]
From equation 2 and 3
(flux)h = - (- EπR^2)
=> (Flux)h = EπR^2
Hope this helped !

Discussion

4.	A man was a distance of 50 metre in 1 minute and another 15 metre in 1.5 minutes is the motion and non-uniform also find his average speed in metre per second
Answer» EXPLANATION: In this WAY we can SOLVE the PROBLEM for you my FRIEND...

4.

A man was a distance of 50 metre in 1 minute and another 15 metre in 1.5 minutes is the motion and non-uniform also find his average speed in metre per second

Answer»

EXPLANATION:

In this WAY we can SOLVE the PROBLEM for you my FRIEND...

Discussion

5.	A diatomic gas does 200 j of work when it expands isobarically. Find the heat given to the gas in the process
Answer» Solution : For an diatomic gas $\sf \implies C_v = \frac{5}{2} \\ \\ \sf \implies C_p = \frac{7}{2}$ The WORK DONE in an isobaric PROCESS is $\sf \implies W = p(V_2 -V_1) \\ \\\sf \implies W = nRT_2 - nRT_1 \\ \\\sf \implies T_2 - T_1 = \frac{W}{nR}$ The HEAT given in an isobaric process is $\sf \implies Q = nC_p(T_2 - T_1) \\ \\\sf \implies Q = nC_p \frac{W}{nR} = \frac{7}{2}W \\ \\\sf \implies Q = \frac{7}{2} \times 200 \\ \\\sf \implies Q = 700\:J$

5.

A diatomic gas does 200 j of work when it expands isobarically. Find the heat given to the gas in the process

Answer»

Solution :

For an diatomic gas

$\sf \implies C_v = \frac{5}{2} \\ \\ \sf \implies C_p = \frac{7}{2}$

The WORK DONE in an isobaric PROCESS is

$\sf \implies W = p(V_2 -V_1) \\ \\\sf \implies W = nRT_2 - nRT_1 \\ \\\sf \implies T_2 - T_1 = \frac{W}{nR}$

The HEAT given in an isobaric process is

$\sf \implies Q = nC_p(T_2 - T_1) \\ \\\sf \implies Q = nC_p \frac{W}{nR} = \frac{7}{2}W \\ \\\sf \implies Q = \frac{7}{2} \times 200 \\ \\\sf \implies Q = 700\:J$

Discussion

6.	Which substance is used to remove chloroplast from A green leaf during photosynthesis experiment
Answer» ANSWER:ETHANOL Explanation: if ethanol is used, then it REACTS and automatically decolorizes the GREEN leaf, and it also removes the green colored chlorophyll pigment from that leaf

6.

Which substance is used to remove chloroplast from A green leaf during photosynthesis experiment

Answer»

ANSWER:ETHANOL

Explanation:

if ethanol is used, then it REACTS and automatically decolorizes the GREEN leaf, and it also removes the green colored chlorophyll pigment from that leaf

Discussion

7.	What is the function of an electric fuse?Name the material used for making fuse? In household circuit where is fuse connected?
Answer» Answer: electronic fuse is a safety device used to save d electrical appliances. the fuse is placed in series with the device. ... the fuse wire is usually enclosed in a cartridge of porcelain or similar material with metal ends i) Electric fuse is a device which acts as a circuit breaker and prevents electrical appliances from being damaged. It is generally composed two main parts; an alloy wire (typically tin and copper) which is thin and has a low melting point and aSafety Overcurrent protective devices that have TRIPPED are often reset without first investigating the cause of the fault. Electromechanical devices may not have the reserve capacity to open safely when a second or third fault occurs. When a fuse OPENS it is replaced with a NEW fuse, so the protection level is not degraded by previous faults. Our current limiting fuses MEET the UL and NEC codes. 2Cost-effective Fuses typically are the most cost-effective means of providing overcurrent protection. This is especially true where high fault currents exist or where small components such as Control Transformers or DC power supplies need protection. 3High interrupting rating With most low voltage current limiting fuses (< 600 volts) having a 200,000 amp interrupting rating, you are not paying a high premium for a high interrupting capacity. Current limiting fuses from AutomationDirect meet the UL and NEC codes. 4Reliability Fuses have no moving parts to wear out or become contaminated by dust or oil. 5North American standards Tri-National Standards specify fuse performance and maximum allowable fuse Ip and I²t let-thru values. Peak let-thru current (Ip) and I²t are two measures of the degree of current limitation provided by a fuse. 6Component protection The high current limiting action of a fuse minimizes or eliminates component damage. 7Extended protection Devices with low interrupting ratings are often rendered obsolete by service upgrades or increases in available fault current. Updated NEC and UL standards are causing the need for potentially expensive system upgrades to non-fused systems. 8Selectivity Fuses can be easily coordinated to provide selectivity under both overload and short-circuit conditions. 9Minimal maintenance Fuses do not require periodic recalibration as do some electromechanical overcurrent protective devices. 10Long life As a fuse ages, the speed of response will not slow down or change. A fuse’s ability to provide protection will not be adversely affected by the passing of time.n insulated outer casing of ceramic, fibre glass, plastic ETC.

7.

What is the function of an electric fuse?Name the material used for making fuse? In household circuit where is fuse connected?

Answer»

Answer:

electronic fuse is a safety device used to save d electrical appliances. the fuse is placed in series with the device. ... the fuse wire is usually enclosed in a cartridge of porcelain or similar material with metal ends

i) Electric fuse is a device which acts as a circuit breaker and prevents electrical appliances from being damaged. It is generally composed two main parts; an alloy wire (typically tin and copper) which is thin and has a low melting point and aSafety

Overcurrent protective devices that have TRIPPED are often reset without first investigating the cause of the fault. Electromechanical devices may not have the reserve capacity to open safely when a second or third fault occurs. When a fuse OPENS it is replaced with a NEW fuse, so the protection level is not degraded by previous faults. Our current limiting fuses MEET the UL and NEC codes.

2Cost-effective

Fuses typically are the most cost-effective means of providing overcurrent protection. This is especially true where high fault currents exist or where small components such as Control Transformers or DC power supplies need protection.

3High interrupting rating

With most low voltage current limiting fuses (< 600 volts) having a 200,000 amp interrupting rating, you are not paying a high premium for a high interrupting capacity. Current limiting fuses from AutomationDirect meet the UL and NEC codes.

4Reliability

Fuses have no moving parts to wear out or become contaminated by dust or oil.

5North American standards

Tri-National Standards specify fuse performance and maximum allowable fuse Ip and I²t let-thru values. Peak let-thru current (Ip) and I²t are two measures of the degree of current limitation provided by a fuse.

6Component protection

The high current limiting action of a fuse minimizes or eliminates component damage.

7Extended protection

Devices with low interrupting ratings are often rendered obsolete by service upgrades or increases in available fault current. Updated NEC and UL standards are causing the need for potentially expensive system upgrades to non-fused systems.

8Selectivity

Fuses can be easily coordinated to provide selectivity under both overload and short-circuit conditions.

9Minimal maintenance

Fuses do not require periodic recalibration as do some electromechanical overcurrent protective devices.

10Long life

As a fuse ages, the speed of response will not slow down or change. A fuse’s ability to provide protection will not be adversely affected by the passing of time.n insulated outer casing of ceramic, fibre glass, plastic ETC.

Discussion

8.	क्या दिया गया समीकरण (फार्मूला) विमीय रूप से सही है ? T=2H√m/F/xजहाँ, T = आवर्तकाल, m = द्रव्यमान F = बल ;x = दूरी है।(A) सही है।(B) यूनिट (इकाई) रूप से सही है लेकिन विमीय रूप से गलत है।(C) गलत है।(D) उपरोक्त में से कोई नहीं
Answer» ANSWER:YES the DIYA HUA samikaran Explanation:

8.

क्या दिया गया समीकरण (फार्मूला) विमीय रूप से सही है ? T=2H√m/F/xजहाँ, T = आवर्तकाल, m = द्रव्यमान F = बल ;x = दूरी है।(A) सही है।(B) यूनिट (इकाई) रूप से सही है लेकिन विमीय रूप से गलत है।(C) गलत है।(D) उपरोक्त में से कोई नहीं

Answer»

ANSWER:YES the DIYA HUA samikaran

Explanation:

Discussion

9.	Why i.e Erodov is publically copyrighted
Answer» Question⇒ Why i.e Erodov is publically copyrighted Explanation: I THINK I AM ELIGIBLE TO ANSWER THIS QUESTION, BECAUSE I’VE SPENT TWO YEARS WITH THIS BOOK . I first touched this book when i was in 7 th standard ( don’t get overwhelmed .i just touched it ! ) i completed hc verma mechanics part while i was in standard 6 , it is very easy to grasp concepts from hcv . i solved most of the problems from hcv at that time ( i did’nt go to any coaching) i became a physics lover ! i came to know about irodov from my seniors , i asked one of them about it , he said that even it is a nightmare to our college topper ! even many physics teachers of my school were not able to solve a single problem from it ,i wondered all night about this nightmare of my college toppers . next day morning i went to my school library and bought this book . many of my seniors told me “ you will end up with this book within an hour “ . i developed my tempo and dared to OPEN this book ! i spent a whole day on problem no. 1.2 finally after a day toil , success ! the answer on my rough sheet matched with that given at the end of the book OMG ! finally i was able to break at least a CHUNK from this hard rock ! i became fully determined and tried to solve the next problem . after a toil for a week the result is nothing . i became sad , my confidence was drained completely . at that instant a sudden sound from somewhere saying “ try and try until you succeed “ . that was a sound from a film ,which is being watched by my friend in his smartphone . i thought god had sent me this message ! THANK god ! i started to analyse why i was not able to solve i.e irodov , thought for a whole day . and finally understood my mistakes . i will write my mistakes so that you would not commit these mistakes before solving irodov . build your concepts rock hard , by reading some classical books like hc verma , sears and zemansky or resnick halliday . don’t read each and every book you find in the market . only study the standard ones . you need to practice a lot , “because practice makes a man perfect’’ .again solve each and every problem from hcv . you at least need to complete hcv before going with irodov . 3.now the last but not the least “you need to fall in LOVE with the subject’’. you also must be clear with some fundamental mathematical concepts such as calculus ,because many problems can be easily solved if you know how to use calculus in some practical physical SITUATIONS . now i am in class 9 , i solved nearly 150+ problems only from mechanics part ( excluding relativity ). also did 100 + problems in electrodynamics . i am preparing for physics olympiad ( conducted by hbcse ) . and i am pretty sure that i will break this rock someday ! so i finally conclude that nothing is tough ! once your fundamental concepts are clear then nothing would be difficult . you also must fall in love with the subject . thanks for reading . please upvote my answer if you like it , because your upvotes help me to boost my interest in writing similar answers and help share my preparation strategies with you , they mean a lot to me .

9.

Why i.e Erodov is publically copyrighted

Answer»

Question⇒ Why i.e Erodov is publically copyrighted

Explanation:

I THINK I AM ELIGIBLE TO ANSWER THIS QUESTION, BECAUSE I’VE SPENT TWO YEARS WITH THIS BOOK .
I first touched this book when i was in 7 th standard ( don’t get overwhelmed .i just touched it ! )
i completed hc verma mechanics part while i was in standard 6 , it is very easy to grasp concepts from hcv .
i solved most of the problems from hcv at that time ( i did’nt go to any coaching)
i became a physics lover !
i came to know about irodov from my seniors , i asked one of them about it ,
he said that even it is a nightmare to our college topper !
even many physics teachers of my school were not able to solve a single problem from it ,i wondered all night about this nightmare of my college toppers .
next day morning i went to my school library and bought this book .
many of my seniors told me “ you will end up with this book within an hour “ .
i developed my tempo and dared to OPEN this book !
i spent a whole day on problem no. 1.2 finally after a day toil , success !
the answer on my rough sheet matched with that given at the end of the book
OMG !
finally i was able to break at least a CHUNK from this hard rock !
i became fully determined and tried to solve the next problem .
after a toil for a week the result is nothing .
i became sad , my confidence was drained completely .
at that instant a sudden sound from somewhere saying “ try and try until you succeed “ .
that was a sound from a film ,which is being watched by my friend in his smartphone .
i thought god had sent me this message ! THANK god !
i started to analyse why i was not able to solve i.e irodov , thought for a whole day .
and finally understood my mistakes .
i will write my mistakes so that you would not commit these mistakes before solving irodov .
build your concepts rock hard , by reading some classical books like hc verma , sears and zemansky or resnick halliday . don’t read each and every book you find in the market . only study the standard ones .
you need to practice a lot , “because practice makes a man perfect’’ .again solve each and every problem from hcv . you at least need to complete hcv before going with irodov .
3.now the last but not the least “you need to fall in LOVE with the subject’’.
you also must be clear with some fundamental mathematical concepts such as calculus ,because many problems can be easily solved if you know how to use calculus in some practical physical SITUATIONS .
now i am in class 9 , i solved nearly 150+ problems only from mechanics part ( excluding relativity ).
also did 100 + problems in electrodynamics .
i am preparing for physics olympiad ( conducted by hbcse ) .
and i am pretty sure that i will break this rock someday !
so i finally conclude that nothing is tough ! once your fundamental concepts are clear then nothing would be difficult .
you also must fall in love with the subject .
thanks for reading .
please upvote my answer if you like it , because your upvotes help me to boost my interest in writing similar answers and help share my preparation strategies with you , they mean a lot to me .

Discussion

10.	How does the relaxation time of electron in conductor change when temperature ofconductor decrease?
Answer» Answer: as we know that the elecrons of a CONDUCTOR are randomly vibrating.as the temperature is INCREASED the vibration of the ELECTRONS increases,due to which the relaxation time decreases. when the temperature is decreased then the vibration of the electrons decreases which results in increase in the time GAP between two successive collision.ie relaxation time.

10.

How does the relaxation time of electron in conductor change when temperature ofconductor decrease?

Answer»

Answer:

as we know that the elecrons of a CONDUCTOR are randomly vibrating.as the temperature is INCREASED the vibration of the ELECTRONS increases,due to which the relaxation time decreases.

when the temperature is decreased then the vibration of the electrons decreases which results in increase in the time GAP between two successive collision.ie relaxation time.

Discussion

11.	An object is moving with the uniform speed in a circle of radius r. Calculate thedistance and displacement(a) when it completes half the circle
Answer» Answer:Hey there ! Radius = r a)When it completes half circle Distance = πr Displacement = 2r [ diameter of the circle ] b) When it completes full circle Distance=2πr Displacement = 0 [ INITIAL POSITION and final position is same ] The OBJECT posses circular motion . Click to let others know, how helpful is it Explanation:when it completes half circle, distance=πr displacement=2r when it completes full circle, distance=2πr displacement=0 the object posses circular motion because it is moving in a circular path.

11.

An object is moving with the uniform speed in a circle of radius r. Calculate thedistance and displacement(a) when it completes half the circle

Answer»

Answer:Hey there !

Radius = r

a)When it completes half circle

Distance = πr

Displacement = 2r [ diameter of the circle ]

b) When it completes full circle

Distance=2πr

Displacement = 0 [ INITIAL POSITION and final position is same ]

The OBJECT posses circular motion .

Click to let others know, how helpful is it

Explanation:when it completes half circle,

distance=πr

displacement=2r

when it completes full circle,

distance=2πr

displacement=0

the object posses circular motion because it is moving in a circular path.

Discussion

12.	WRITE SOME CHARACTERISTICS OF WEAK NUCLEAR FORCE??
Answer» Answer: The weak nuclear FORCE (or just the weak force, or weak interaction) ACTS inside individual nucleons, which means that it is even shorter ranged than the strong force. It is the force that ALLOWS protons to turn into neutrons and vice versa through beta DECAY.

12.

WRITE SOME CHARACTERISTICS OF WEAK NUCLEAR FORCE??

Answer»

Answer:

The weak nuclear FORCE (or just the weak force, or weak interaction) ACTS inside individual nucleons, which means that it is even shorter ranged than the strong force. It is the force that ALLOWS protons to turn into neutrons and vice versa through beta DECAY.

Discussion

13.	1A current is flowing through a cylindrical conductorof radius R such that current density at radialdistance r is given by J =Jnote Calculatetotal current through cross-section of conductor.
Answer» you mean, current density at radial distance r is given by, $J_0\left(1-\frac{r}{R}\right)$ , right? we KNOW, current density is the rate of flowing of current through UNIT CROSS sectional area. i.e., J = dI/dA or, $I=\int{J}\,dA$ so, first of all, finding ELEMENTARY area of cylinderical conductor. A = πr² differentiating both SIDES, dA = 2πr . dr then, current, I = $\int\limits^R_0{J}\,(2\pi r).dr$ = $2\pi J_0\int\limits^R_0{\left(r-\frac{r^2}{R}\right)}\,dr$ = $2\pi J_0\left[\frac{r^2}{2}-\frac{r^3}{3R}\right]^R_0$ = $2\pi J_0\left[\frac{R^2}{2}-\frac{R^2}{3}\right]$ = $\frac{\pi J_0R^2}{3}$ This is our required answer.

13.

1A current is flowing through a cylindrical conductorof radius R such that current density at radialdistance r is given by J =Jnote Calculatetotal current through cross-section of conductor.

Answer»

you mean, current density at radial distance r is given by, $J_0\left(1-\frac{r}{R}\right)$ , right?

we KNOW, current density is the rate of flowing of current through UNIT CROSS sectional area.

i.e., J = dI/dA

or, $I=\int{J}\,dA$

so, first of all, finding ELEMENTARY area of cylinderical conductor.

A = πr²

differentiating both SIDES,

dA = 2πr . dr

then, current, I = $\int\limits^R_0{J}\,(2\pi r).dr$

= $2\pi J_0\int\limits^R_0{\left(r-\frac{r^2}{R}\right)}\,dr$

= $2\pi J_0\left[\frac{r^2}{2}-\frac{r^3}{3R}\right]^R_0$

= $2\pi J_0\left[\frac{R^2}{2}-\frac{R^2}{3}\right]$

= $\frac{\pi J_0R^2}{3}$ This is our required answer.

Discussion

14.	Write the mathematical expression for eletric current
Answer» ANSWER: SORRY I didn't KNOW. ....

14.

Write the mathematical expression for eletric current

Answer»

ANSWER:

SORRY I didn't KNOW. ....

Discussion

15.	A body covers 200cm in the first 2 sec. and 220 cm innext 4sec. What is the velocity of the body at the endof 7th second ?(1) 40 cm/sec(2) 20 cm/sec10 cm/sec(4) 5 cm/sec
Answer» Answer: 40 cm/s Have a GREAT DAY!

15.

A body covers 200cm in the first 2 sec. and 220 cm innext 4sec. What is the velocity of the body at the endof 7th second ?(1) 40 cm/sec(2) 20 cm/sec10 cm/sec(4) 5 cm/sec

Answer»

Answer:

40 cm/s

Have a GREAT DAY!

Discussion

16.	1. A bus is moving at a speed of 18 km/h. It is retarding at a rate of 2 m/s^2 and comes to rest finally.find the distance travelled by it
Answer» ANSWER: what WOULD be the answer i THINK when it comes to REST finally its DISTANCE would be 25km/h.

16.

1. A bus is moving at a speed of 18 km/h. It is retarding at a rate of 2 m/s^2 and comes to rest finally.find the distance travelled by it

Answer»

ANSWER:

what WOULD be the answer i THINK when it comes to REST finally its DISTANCE would be 25km/h.

Discussion

17.	Airplanes have pressurised cabins for passengers safety while flying high in the atmospere.
Answer» AIRPLANES are PRESSURIZED because the air is very THIN at the altitude they fly. The average passenger jet has a cruising altitude of about 30,000 to 40,000 FEET. Atthis altitude humans can't breathe very well and our body GETS less.

17.

Airplanes have pressurised cabins for passengers safety while flying high in the atmospere.

Answer»

AIRPLANES are PRESSURIZED because the air is very THIN at the altitude they fly. The average passenger jet has a cruising altitude of about 30,000 to 40,000 FEET. Atthis altitude humans can't breathe very well and our body GETS less.

Discussion

18.	1℃ is equal to-(a)57.3° (b)573°(c)180°(d)360°
Answer» ANSWER: C 180 Explanation: this is the answer do the PROCESS by yourself

18.

1℃ is equal to-(a)57.3° (b)573°(c)180°(d)360°

Answer»

ANSWER:

C 180

Explanation:

this is the answer do the PROCESS by yourself

Discussion

19.	Magnetic field lines due to a straight current carrying wire
Answer» Answer: They are concentric circles whose centre lie on wire. Explanation: The direction of magnetic field lines can be determined by RIGHT hand THUMB RULE.

19.

Magnetic field lines due to a straight current carrying wire

Answer»

Answer:

They are concentric circles whose centre lie on wire.

Explanation:

The direction of magnetic field lines can be determined by RIGHT hand THUMB RULE.

Discussion

20.	Which book best for neet
Answer» SANSKRIT.... m.m.. m..........

Discussion

21.	Answer asap Motion in a plane
Answer» ANSWER: AREA = 1/2 (-3-4+3) =4/2 =2 Explanation: HEY MATE here is your answer

21.

Answer asap Motion in a plane

Answer»

ANSWER:

AREA = 1/2 (-3-4+3)

=4/2

=2

Explanation:

HEY MATE here is your answer

Discussion

22.	if a body changes its velocity from 35 metre per second to 12 metre per second in 10 seconds what is the retardation of the body
Answer» Explanation: Initial VELOCITY = 35m/s Final velocity = 12m/s TIME = 10s acceleration= CHANGE in velocity / time take 12-35/10 -23/10 =-2.3m/s² is the retardation of the body

22.

if a body changes its velocity from 35 metre per second to 12 metre per second in 10 seconds what is the retardation of the body

Answer»

Explanation:

Initial VELOCITY = 35m/s

Final velocity = 12m/s

TIME = 10s

acceleration= CHANGE in velocity / time take

12-35/10

-23/10

=-2.3m/s² is the retardation of the body

Discussion

23.	a bus is moving at a speed of 18 km/h. it is retarding at a rate of 2 m/s^2 and comes to rest finally. find the distance travelled by it.
Answer» Given INITIAL VELOCITY=18km/h=18*5/18 =5m/sec FINAL velocity= 0 RETARDATION = -2m/sec SQUARE Distance= ? ${v}^{2} = {u }^{2} + 2as$ ${0}^{2} = {5}^{2} + 2( - 2)(s)$ 0=25-4s 25 =-4s 25/-4=s 6.25=s Distance= 6.25m

23.

a bus is moving at a speed of 18 km/h. it is retarding at a rate of 2 m/s^2 and comes to rest finally. find the distance travelled by it.

Answer»

Given

INITIAL VELOCITY=18km/h=18*5/18

=5m/sec

FINAL velocity= 0

RETARDATION = -2m/sec SQUARE

Distance= ?

${v}^{2} = {u }^{2} + 2as$

${0}^{2} = {5}^{2} + 2( - 2)(s)$

0=25-4s

25 =-4s

25/-4=s

6.25=s

Distance= 6.25m

Discussion

24.	Two wires A and B of which lengths are in the ratio 1:2 and the area of cross-sectionain the ratio 2:1 and of same resistivity are connected in parallel with the same sourceemf. Find the ratio of drift velocities in the given two wires.
Answer» ANSWER: i am BAD in maths Explanation:

24.

Two wires A and B of which lengths are in the ratio 1:2 and the area of cross-sectionain the ratio 2:1 and of same resistivity are connected in parallel with the same sourceemf. Find the ratio of drift velocities in the given two wires.

Answer»

ANSWER:

i am BAD in maths

Explanation:

Discussion

25.	Resistance of a wire is 3.4 kQ+5%. Write the order of colored rings representing the givenresistance
Answer» EXPLANATION: Sorry mate if u WANT to KNOW the answer then follow me.

25.

Resistance of a wire is 3.4 kQ+5%. Write the order of colored rings representing the givenresistance

Answer»

EXPLANATION:

Sorry mate if u WANT to KNOW the answer then follow me.

Discussion

26.	What is refraction?
Answer» ANSWER: *the FACT or phenomenon of light, radio waves, etc. being deflected in passing OBLIQUELY through the interface between one MEDIUM and another or through a medium of VARYING density.*

26.

What is refraction?

Answer»

ANSWER:

the FACT or phenomenon of light, radio waves, etc. being deflected in passing OBLIQUELY through the interface between one MEDIUM and another or through a medium of VARYING density.

Discussion

27.	Describe rankines with viscocity of liquid
Answer» ANSWER: ghjouted to OI TALLAHASSEE SLATE

27.

Describe rankines with viscocity of liquid

Answer»

ANSWER:

ghjouted to OI TALLAHASSEE SLATE

Discussion

28.	Name the unit used in selling electric energy to consumers.
Answer» ANSWER: CURRENT is the answer MAY be

28.

Name the unit used in selling electric energy to consumers.

Answer»

ANSWER:

CURRENT is the answer MAY be

Discussion

29.	What principle is used in a mass spectograph to estimate very small distances?
Answer» ANSWER: EXPLANATION:this is the MASS of SPECTOMETER

29.

What principle is used in a mass spectograph to estimate very small distances?

Answer»

ANSWER:

EXPLANATION:this is the MASS of SPECTOMETER

Discussion

30.	What is sodium fusion extract?
Answer» It is a general test for the detection of HALOGENS, nitrogen and sulphur in an organic compound. ... The ionic compounds formed during the are extracted in aqueous solution and can be DETECTED by simple chemical tests. The is CALLED or Lassaigne's . *hope* it *will* *help* *you* *MARK* as brain list PLZZZZZ .......

30.

What is sodium fusion extract?

Answer»

It is a general test for the detection of HALOGENS, nitrogen and sulphur in an organic compound. ... The ionic compounds formed during the are extracted in aqueous solution and can be DETECTED by simple chemical tests. The is CALLED or Lassaigne's .

hope it will help you

MARK as brain list PLZZZZZ .......

Discussion

31.	Which is not a vector quantity?
Answer» HEY! MATE, GOOD AFTERNOON☺ SPEED is not a VECTOR quantity. HOPE IT HELPS YOU❤❤❤

31.

Which is not a vector quantity?

Answer»

HEY! MATE, GOOD AFTERNOON☺

SPEED is not a VECTOR quantity.

HOPE IT HELPS YOU❤❤❤

Discussion

32.	Use the expression of magnetic lorentz force to define the s.I unit of magnetic field
Answer» Answer: The magnetic field B is defined from the LORENTZ Force Law, and specifically from the magnetic force on a MOVING CHARGE: The implications of this expression include: 1. The force is perpendicular to both the VELOCITY v of the charge Q and the magnetic field B. ... The direction of the force is given by the right hand rule.

32.

Use the expression of magnetic lorentz force to define the s.I unit of magnetic field

Answer»

Answer:

The magnetic field B is defined from the LORENTZ Force Law, and specifically from the magnetic force on a MOVING CHARGE: The implications of this expression include: 1. The force is perpendicular to both the VELOCITY v of the charge Q and the magnetic field B. ... The direction of the force is given by the right hand rule.

Discussion

33.	Prove greater exposed surface area ensures fast evaporation
Answer» ANSWER: EXPLANATION: HOPE it will HEP you

33.

Prove greater exposed surface area ensures fast evaporation

Answer»

ANSWER:

EXPLANATION:

HOPE it will HEP you

Discussion

34.	If we. Weld hard iron with soft iron what will happen with hysteresis loop?
Answer» ANSWER: As the current is increased, the DEFLECTION increases up to a maximum value. ... Steel has a "fat" hysteresis loop. It is difficult to DEMAGNETIZE, so steel is used for permanent magnets. SUBSTANCES, such as SOFT iron, with thin hysteresis loops, are used for transformer cores.

34.

If we. Weld hard iron with soft iron what will happen with hysteresis loop?

Answer»

ANSWER:

As the current is increased, the DEFLECTION increases up to a maximum value. ... Steel has a "fat" hysteresis loop. It is difficult to DEMAGNETIZE, so steel is used for permanent magnets. SUBSTANCES, such as SOFT iron, with thin hysteresis loops, are used for transformer cores.

Discussion

35.	If vibrations of a string are to be increased to a factor of two
Answer» Answer: INCREASED to a FACTOR of 2 means, the VIBRATION frequency is made TWICE the INITIAL. we know, vibration

35.

If vibrations of a string are to be increased to a factor of two

Answer»

Answer:

INCREASED to a FACTOR of 2 means, the VIBRATION frequency is made TWICE the INITIAL. we know, vibration

Discussion

36.	If two bulbs of power 60 words and hundred words respectively each rated 110 volt are connected in series with the supply of 220 volts then
Answer» ANSWER: EXPLANATION: HOPE it HELP U

36.

If two bulbs of power 60 words and hundred words respectively each rated 110 volt are connected in series with the supply of 220 volts then

Answer»

ANSWER:

EXPLANATION:

HOPE it HELP U

Discussion

37.	If transfer efficiency is 100% then why band are not visible on x ray film
Answer» Answer: Explanation: This is partially because X-rays have very small wavelengths. It is also because X-ray light tends to act more like a PARTICLE than a wave. X-ray detectors COLLECT ACTUAL photons of X-ray light - which is very different from the radio telescopes that have large dishes DESIGNED to FOCUS radio waves!

37.

If transfer efficiency is 100% then why band are not visible on x ray film

Answer»

Answer:

Explanation:

This is partially because X-rays have very small wavelengths. It is also because X-ray light tends to act more like a PARTICLE than a wave. X-ray detectors COLLECT ACTUAL photons of X-ray light - which is very different from the radio telescopes that have large dishes DESIGNED to FOCUS radio waves!

Discussion

38.	an athlete completes one round of a circular track of diameter 200m in 40s .what is the distance covered and displacement at the end of 2min 20s ?
Answer» Answer: Explanation: HI there !! DISPLACEMENT is the SHORTEST distance possible between initial and final position. As the athlete is in circular motion , displacement is ZERO. [ THis is because , the initial and final position is the same ] Distance covered in 1 round = Circumference of the circle Circumference of the circle = 2πr Diameter = 200 m Radius = 100 m Distance covered in 1 round[ 40 sec ] = 2 × 22/7 × 100 = 628.57 m Distance covered in 1 sec = 628.57 ÷ 40 = 15.71 m 2min 20 sec = 140 sec Distance covered in 140 sec = 15.71 × 140 = 2199.4 m

38.

an athlete completes one round of a circular track of diameter 200m in 40s .what is the distance covered and displacement at the end of 2min 20s ?

Answer»

Answer:

Explanation:

HI there !!

DISPLACEMENT is the SHORTEST distance possible between initial and final position.

As the athlete is in circular motion , displacement is ZERO. [ THis is because , the initial and final position is the same ]

Distance covered in 1 round = Circumference of the circle

Circumference of the circle = 2πr

Diameter = 200 m

Radius = 100 m

Distance covered in 1 round[ 40 sec ] = 2 × 22/7 × 100 = 628.57 m

Distance covered in 1 sec = 628.57 ÷ 40 = 15.71 m

2min 20 sec = 140 sec

Distance covered in 140 sec = 15.71 × 140 = 2199.4 m

Discussion

39.	Question no. 42 plz answer it fast it is a 5 marks question
Answer» Answer: 1))===when both VELOCITIES are in the same direction then Va-Vb. When they both in same direction then RELATIVE velocity of a WRT B will be SUBTRACTED Explanation:

39.

Question no. 42 plz answer it fast it is a 5 marks question

Answer»

Answer: 1))===when both VELOCITIES are in the same direction then Va-Vb. When they both in same direction then RELATIVE velocity of a WRT B will be SUBTRACTED

Explanation:

Discussion

40.	The volume of water in a measuring cylinder is 50 ml .After dropping a pebble ,the water level raised to 60 ml .find the volume of the pebble
Answer» $the \: volume \: of \: the \: pebble \: = 10ml \: or \: 10 \: {cm}^{3} . \\ since \: 60ml - 50ml = 10ml. \\ and \: according \: to \: the \: archimedes \: principle \: the \: voume \: of \: liquid \: displaced \: by \: an \: object \: is \: equal \: to \: the \: object \: s \: volume. \\ so \: answer \: = 10ml \: or \: 10 {cm}^{3} .$

40.

The volume of water in a measuring cylinder is 50 ml .After dropping a pebble ,the water level raised to 60 ml .find the volume of the pebble

Answer»

$the \: volume \: of \: the \: pebble \: = 10ml \: or \: 10 \: {cm}^{3} . \\ since \: 60ml - 50ml = 10ml. \\ and \: according \: to \: the \: archimedes \: principle \: the \: voume \: of \: liquid \: displaced \: by \: an \: object \: is \: equal \: to \: the \: object \: s \: volume. \\ so \: answer \: = 10ml \: or \: 10 {cm}^{3} .$

Discussion

41.	The mass of half mole of electron is about
Answer» *Plz* *mention* the total mass ALSO in the QUES then only I will be able to Ans.**..

Discussion

42.	a farmer goes around a square field of 10m side 60s .evaluvate the distance and displacement of the farmer at the end of 2.5 mins
Answer» U can SEE from GOGGLE

Discussion

43.	Rain drop is falling under gravity on the earth surface. Its speed remain constant near theearth surface, this constant speed is known as terminal velocity. This velocity depends onviscosity of air n radius of drop (r.), difference in density of water and air (d) and accelerationdue to gravity (g). Then terminal velocity is [Given that: F = 6xrnV.):-
Answer» a is the CORRECT OPTION.

Discussion

44.	With the help of graph drive the relation V = u+at
Answer» ANSWER: I HOPE it is right mark it as BRAINLIEST

44.

With the help of graph drive the relation V = u+at

Answer»

ANSWER:

I HOPE it is right

mark it as BRAINLIEST

Discussion

45.	Study about frictional force from everyday life where it is useful or harmful explain
Answer» Explanation: frictional force- the force of friction ACTING between two contact surfaces and which bring about changes in state of rest or motion is called frictional force! advantages- friction helps us maintain our stability and prevents us from slipping. Friction also works the same WAY with cars and vehicles in general, preventing them from skidding and helping them stop when the BRAKES are applied. disadvantage- Friction causes moving objects to stop or slow down. Friction produces heat causing wastage of energy in machines. Friction causes wear and TEAR of moving parts of macinery, soles of SHOES, etc. hope it helps dear! mark as brainlist if this answer satisfies u dear!✌✌

45.

Study about frictional force from everyday life where it is useful or harmful explain

Answer»

Explanation:

frictional force- the force of friction ACTING between two contact surfaces and which bring about changes in state of rest or motion is called frictional force!

advantages- friction helps us maintain our stability and prevents us from slipping. Friction also works the same WAY with cars and vehicles in general, preventing them from skidding and helping them stop when the BRAKES are applied.

disadvantage- Friction causes moving objects to stop or slow down. Friction produces heat causing wastage of energy in machines. Friction causes wear and TEAR of moving parts of macinery, soles of SHOES, etc.

hope it helps dear!

mark as brainlist if this answer satisfies u dear!✌✌

Discussion

46.	A swimmer reaches the other Bank of a flowing river exactly opposite to starting point if he was swimming at 2 km / he while maintaining 150° with the flow then time taken by him to cross the river 1 km wide is
Answer» Answer: 1 hr Explanation: A swimmer reaches the other Bank of a flowing river exactly opposite to STARTING POINT if he was SWIMMING at 2 km / he while MAINTAINING 150° with the flow then time taken by him to cross the river 1 km wide is Swimming at 2 km/hr Angle = 150° Horizontal Speed = 2 * Cos150° = 2 * (-√3/2) = -√3 km /hr Compensated the flow ( as he reaches just opposite ) Vertical speed = 2 Sin 150° = 2 * (1/2) = 1 km/Hr Resultant Speed = 1 km/hr River Width = 1 km Time taken = 1/1 = 1 hr

46.

A swimmer reaches the other Bank of a flowing river exactly opposite to starting point if he was swimming at 2 km / he while maintaining 150° with the flow then time taken by him to cross the river 1 km wide is

Answer»

Answer:

1 hr

Explanation:

A swimmer reaches the other Bank of a flowing river exactly opposite to STARTING POINT if he was SWIMMING at 2 km / he while MAINTAINING 150° with the flow then time taken by him to cross the river 1 km wide is

Swimming at 2 km/hr

Angle = 150°

Horizontal Speed = 2 * Cos150° = 2 * (-√3/2) = -√3 km /hr

Compensated the flow ( as he reaches just opposite )

Vertical speed = 2 Sin 150° = 2 * (1/2) = 1 km/Hr

Resultant Speed = 1 km/hr

River Width = 1 km

Time taken = 1/1 = 1 hr

Discussion

47.	The addition and subtraction of a rational and irrational number is a -----(irrational)
Answer» The ADDITION and SUBTRACTION of a rational and IRRATIONAL number is must be rational or irrational... I hope it HELPS...

47.

The addition and subtraction of a rational and irrational number is a -----(irrational)

Answer»

The ADDITION and SUBTRACTION of a rational and IRRATIONAL number is must be rational or irrational...

I hope it HELPS...

Discussion

48.	How is the frictional force of in Galileo experiment on an inclined plane minimised
Answer» When we rub 2 OBJECTS frictional force is PRODUCED ( DON'T FORGET TO MARK ME BRAINLEIST )

Discussion

49.	Give me the 3 equations of motion
Answer» ANSWER: In case of uniform acceleration, there are three equations of motion which are also known as the LAWS of constant acceleration. Hence, these equations are used to derive the components LIKE displacement(s), velocity (initial and FINAL), time(t) and acceleration(a). ... The three equations are, v = u + at. HOPE you like and it's help you

49.

Give me the 3 equations of motion

Answer»

ANSWER:

In case of uniform acceleration, there are three equations of motion which are also known as the LAWS of constant acceleration. Hence, these equations are used to derive the components LIKE displacement(s), velocity (initial and FINAL), time(t) and acceleration(a). ... The three equations are, v = u + at.

HOPE you like and it's help you

Discussion

50.	4 characteristics of Alpha decay plz fast
Answer» Explanation: 1-ALPHA particles are energetic nuclei of helium and they are relatively heavy and carry a double positive charge. 2-Typical alpha particle have kinetic energy about 5 MeV. This is DUE to the nature of alpha decay. 3-Pure alpha decay is very RARE, alpha decay is frequently accompanied by gamma radiation. 4-Alpha particles interact with matter PRIMARILY through coulomb forces (ionization and excitation of matter) between their positive charge and the negative charge of the electrons from atomic orbitals

50.

4 characteristics of Alpha decay plz fast

Answer»

Explanation:

1-ALPHA particles are energetic nuclei of helium and they are relatively heavy and carry a double positive charge.

2-Typical alpha particle have kinetic energy about 5 MeV. This is DUE to the nature of alpha decay.

3-Pure alpha decay is very RARE, alpha decay is frequently accompanied by gamma radiation.

4-Alpha particles interact with matter PRIMARILY through coulomb forces (ionization and excitation of matter) between their positive charge and the negative charge of the electrons from atomic orbitals

Discussion

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