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pulling and pushing to any OBJECT US CALLED force. there are two types of force:- CONTACT and non-contact force.

also there are two types of force more that is-balanced and unbalanced force

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Time =10/60 = 1/6

u=20

v=80

v=u +at

80= 20+ a×1/6

a=360 m/ s^2

Now,

s = UT +1/2 at^2

s =20×1/6 + 1/2 ×360 ×1/36

s=35/3= 11.6 KM (APP))

ANSWER:

ZERO

force=mass*ACCELERATION

but no acceleration

force=zero

Answer:

The body is dropped from rest so, u=0

When the body dropped its speed increases and hence its DISPLACEMENT also increases.

From the equation of MOTION  

S= ut + ½ at2

u=0 ,a=10 m/s2  

Time (t in SECONDS) Displacement (s in metres)  

t= 0                                     s= 0+1/2 X 10 X 0 = 0

t= 1                                    s= 0+1/2 X 10 X 1 2 = 5

t= 2                                    s= 0+1/2 X 10 X 2 2 = 20

t= 3                                     s= 0+1/2 X 10 X 3 2 = 45

The graph will be a curve starting from origin as displacement is DIRECTLY proportional to square of time

Explanation:

ANSWER:

EXPLANATION:

with the HELP of its ENGINE and DIESEL

Answer:

Emperor Aurangzeb was the last effective Mughal king of India Third SON of Emperor SHAH Jahan, the man famous for building the Taj Mahal, Aurangzeb's CRUELTY manifested from a very young age. He had already started demolishing TEMPLES and building mosques over them by the time he was 17.

Answer:

Two (2) as after RATIONALIZING 1/a VALUE comes √2-1 and after OPENING the bracket √2 + 1 - ( √ 2 - 1 ) = √ 2 +1 - √ 2 + 1 = 2

Answer:

Explanation:

Displacement is ZERO because it’s inital and final POSITION both are same

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Classical MECHANICS is a branch of physicsthat deals with the motion of bodies based on Isaac Newton's laws of mechanics. Classical mechanics describes the motion of point masses (infinitesimally small objects) and of rigid bodies (LARGE objects that rotate but cannot change shape).In brief, the main difference between quantum and classical PHYSICS is thedifference between a ramp and a staircase. In classical mechanics, events (in general) are continuous, which is to say they move in SMOOTH, orderly and predicable patterns. Projectile motion is a good example ofclassical mechanics

Answer:

The woodwind family of instruments includes, from the highest sounding instruments to the lowest, the piccolo, flute, oboe, ENGLISH horn, CLARINET, E-flat clarinet, BASS clarinet, bassoon and contrabassoon.

Answer:

When the wire is doubled the LENGTH will be halved and area will be DOUBLE or TWICE 

R = PL/A 

R1 = P(L/2) / 2A Where R1 is the new resistance 

So R1/R = {P(L/2) / 2A} / {PL/A} 

When we SOLVE this we get  R1/R = ¼ 

=> R1 = R/4 = 4/4 = 1 OHM

Answer:

24. LPG is stored in the FORM of gas in cylinder.

This image will help you. Some answers are in this image.

HOPE it HELPS

Explanation:

they exert maximum pressure when the boxes kept in VERTICAL way means when they are kept in top of one BOX then other because pressure will be maximum WHE they have LESS area

because pressure is inversely proportional to area

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ANSWER:

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Answer:

3

Explanation:

The UNCERTAIN DIGIT is ALWAYS the LAST digit.

Answer:

RHS = LHS

Dimensions of Force = [M^1 L^1 T^-2]

Dimensions of MASS =[M^1]

Dimensions of velocity =[L^1 T^-2]

Dimensions of RADIUS =[L^1]

Now ,put the dimensions of mass, velocity and radius in the GIVEN equation.

You will see that LHS =RHS i. E [M^1 L^1 T^-2]

ANSWER:

CURRENT.(denoted by I)

EXPLANATION:

Current is defined the rate of flow of charge through a conductor.

I=dQ/dT

When a FLUID is in motion, it must move in such a way that mass is conserved. To SEE how mass conservation places RESTRICTIONS on the velocity field, consider the steady flow of fluid through a duct (that is, the inlet and outlet flows do not vary with time). The inflow and outflow are one-dimensional, so that the velocity V and density \rho are constant over the AREA A
Now we apply the principle of mass conservation. Since there is no flow through the side walls of the duct, what mass comes in over A_1 goes out of A_2, (the flow is steady so that there is no mass ACCUMULATION). Over a short time interval \Delta t,
This is a statement of the principle of mass conservation for a steady, one-dimensional flow, with one inlet and one outlet. This equation is called the continuity equation

In fluid dynamics, Bernoulli's principle states that an increase in the speed of a fluid occurs simultaneously with a decrease in pressure or a decrease in the fluid's potential energy. The principle is named after Daniel Bernoulli who published it in his book Hydrodynamica in 1738

1litre = 1000cm^3

1kg = 1000g

MASS of WATER =5×1000 = 5000

VOLUME of water = 5×1000 = 500

density = mass / volume

= 5000/5000

= 1gm^-3

ANSWER:

ROOT 3+1/root3

Explanation:

BCS tan60=root3=V/I=R same is anotherone

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The work is a scalar quantity.

This is because it is FORMED by the DOT product of the FORCE and displacement.

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ANSWER:

your answer is

i. = C =5

ii.=d=3

iii. =E =6

iv. =F = 1

v.= b=4

vi.= a = 2

ANSWER:

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Answer:

Spring balance, weighing device that utilizes the relation between the applied load and the deformation of a spring. This relationship is usually linear; i.e., if the load is doubled, the deformation is doubled. In the circular balance SHOWN in the figure, the upper ends of the helical SPRINGS are attached to the casing and the lower ends to a crossbar that can move relative to the casing and to which the load hook is attached. The PINION to which the indicating pointer is attached is pivoted in the casing and meshes with the rack, which is pivotally connected to the crossbar and is pressed into contact with the pinion by the rack spring.

When a load is applied, the springs are stretched, and movement of the crossbar with the rack attached rotates the pinion and the load-indicating pointer. The dial is graduated in scale units that depend on the stiffness of the springs: the stiffer springs have larger scale units and higher load capacity.

Spring balances are WIDELY used commercially. Those with high-load capacities are frequently SUSPENDED from crane hooks and are known as crane scales. Smaller units for household use are called fish scales

Explanation:

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When forces are used to OPEN doors, steer and pedal bicycles or turn a tap they are causing turning. The effect that a force has in turning an object round depends on: the size of the force. the perpendicular (shortest) distance between the force line and the PIVOT (the AXIS of rotation).

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Answer:

we can find the ACCELERATION by using the following FORMULA..

acceleration =( FINAL velocity - initial velocity ) / time TAKEN..

The turning EFFECT of a forceis known as the MOMENT. It is the product of the force multiplied by the perpendicular distance from the LINE of action of the force to the PIVOT or point where the object will turn. Examples of turning effect of force: A person pushing a swing will make the swing rotate about its pivot.

A moment is the turning effect of a force around a fixed point called a pivot . For example, this COULD be a door OPENING around a fixed hinge or a SPANNER turning around a fixed NUT. The size of a moment depends on two factors: ... the perpendicular distance from the pivot to the LINE of action of the force.

ANSWER:

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Answer:

EXPLANATION: acceleration = CHANGE in VELOCITY/ TIME

a = v2-v1 / t

a = 30-10/40

a= 20/40

a = 1/2

a= 0.5 m/sec2

SINCE the train starts from rest ( from station),

INITIAL velocity (U)= 0m/s

time= 2 minutes= 120 seconds

distance (s)= 400m

s=ut+ 1/2at²

400 = 0×120+1/2×a×120²

400=0+14400a/2

400×2=14400a

800=14400a

14400a=800

a=800/14400

a=1/18

a=0.055...m/s²

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The cosmic MICROWAVE background (CMB) is thought to be leftover radiation from the Big Bang, or the time when the UNIVERSE began. As the theory goes, when the universe was born it UNDERWENT a rapid inflation and expansion. (The universe is still expanding TODAY, and the expansion rate appears different depending on where you look). The CMB REPRESENTS the heat left over from the Big Bang.

ANSWER:

the COOLEST ELEMENT on EARTH is HYDROGEN

..............

ANSWER:

a marking on a ship's side showing the limit of LEGAL submersion when loaded with CARGO under VARIOUS sea conditions.

Answer:

when the DENSITY of the SUBSTANCE is less than the density of water than the substance will float..... i. E CALLED floating....

but when the density of the substance is more than the density of water then the substance will sink that is called SINKING........ ✌✌✌✌

ANSWER:

heya mate

see the attachment

third EQUATION of MOTION is 2as=v^2-u^2

hope it helps you

Answer:

No it is not possible

Explanation:

It is not possible to separate the NORTH and South poles of a magnet. They coexist. If a bar magnet is cut at its middle (its NEUTRAL LINE), each piece BECOMES an INDEPENDENT magnet possessing a South pole and a North pole of its own.

MegaGram and GigaGram are some UNITS BIGGER than KiloGram.

Relation Of MegaGram & KiloGram :-

1 MegaGram = 10^6 Gram

1 Gram = 10^-3 KiloGram ( Because 1 KiloGram = 10^3 Gram)

so, 1 MegaGram = 10^6 X 10^-3 KiloGram

=> 1 MegaGram = 10^3 KiloGram

Relation Of GigaGram & Kilogram :-

1 GigaGram = 10^9 Gram

1 Gram = 10^-3 KiloGram ( Because 1 KiloGram = 10^3 Gram)

so, 1 GigaGram = 10^9 x 10^-3 KiloGram

=> 1 GigaGram = 10^6 KiloGram

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ANSWER: it will be B 60

Explanation:

Answer:

when area above(POSITIVE) and below(NEGATIVE) the time axis are equal

Explanation:

integration DV= integration a .dt

left hand side is ZERO if final velocity is same as initial velocity

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EXPLANATION:

SPEED for GOING:-20m/sec

Speed for RETURN:-30m/sec

Average VELOCITY:-20+30÷2=25

R=v/I

R=w/Iq

[Ml²t-²]/[AT][A]

[Ml²T-³A-²]

this is your ANSWER

ANSWER:

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BIKE

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ANSWER:

EXPLANATION:

The resistivity of a material is the resistance of a WIRE of that material of unit length and unit cross-sectional AREA. The unit for resistivity is the ohm-metre. The resistivity of a material depends on its nature and the temperature of the CONDUCTOR, but not on its shape and size.

ANSWER:

RESISTANCE will REMAIN same

ANSWER:

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ANSWER:

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in first CASE to find acceleration we have

U = 36km/h = 10m/s

V = 72km/h = 20m/s

t = 1s

we KNOW ,

a = (v - u) / t

= (20 - 10)m/s / 1s

= 10m/s^2

in second case to find retardation we have

u = 20m/s

v = 0m/s

t = 20s

we know,

a = (v - u) /t

= (0 - 20)m/s / 20s

= -1m/s^2

hope it will help you..........

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