This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The LCM of two coprime number is 5005 if one of the number is 65 then find the other number |
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Answer» LET the other number be x since the lcm is 5005 and one number is 65 we KNOW that the numbers are co primes so HCF = 1 because co primes have only one 1 as their common factor using EQUATION HCF ×LCM =PRODUCT OF TWO NUMBERS we GET 1 × 5005= 65 × other number so other number = 5005/ 65= 77 so the required number is 77 |
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| 2. |
In a non leap year what is the probability that the last day of the year starts with the letter ‗t‘? |
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Answer» TOTAL Outcomes =365 Favourable outcome= 2 P(last DAY of YEAR STARTING with letter t)=2/365 |
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| 3. |
If the angle (4x+4)° and (6x-4)° are supplementary angles, find the value of x |
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Answer» (4x+4)+(6x-4)=180° |
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| 4. |
Correct answer would be marked as brainliest....:) |
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Answer» Bggskyydu do uitstyy |
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| 5. |
If the area of a rhombus be 24 cm square and one of its diagonal be 4 cm. Find the other diagonal. |
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Answer» Solutions :- |
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| 6. |
Solve : 7/2 ( y-1) = 4+3y |
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Answer» 7y-7=8+6y |
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| 7. |
Pls answer this questionPls no scamWill mark Brainliest for first answer if it is correct |
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Answer» 58=11+1/2th OBSERVATION |
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| 8. |
Prove that:cosh3x=4cosh^3x-3coshx |
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Answer» cosh 3x = (e^(3x) + e^(-3x) ) / 2 cosh 3x = (1/2) e^(3x) + (1/2) e^(-3x) ----------- (1) 4 cosh^3 x - 3 cosh x = 4 ( (e^(x) + e^(-x) ) / 2)^3 - 3 ( e^(x) + e^(-x) ) /2 = (4/8) ( e^x+ e^(-x))^3 - 3 ( e^(x) + e^(-x) )^2 (a+B)^3 = a^3 + 3a^2 b + 3 a b^2 + b^3 (a+b)^2 = a^2+ 2AB + b^2 4 cosh^3 x - 3 cosh x = (1/2) ( e^(3x) + 3 e^(2x) e^(-x) + 3 e^(x) e^(-2x) + e^(-3x) ) - 3 ( (e^(x) + e^(-x) )/2) = (1/2) e^(3x) + (3/2) e^(x) + (3/2) e^(-x) + (1/2) e^(-3x) -(3/2) e^(x) - (3/2) e^(-x) = (1/2) e^(3x) + (1/2) e^(-3x) + (3/2) e^(x) + (3/2) e^(-x) - (3/2) e^(x) - (3/2) e^(-x) = (1/2) e^(3x) + (1/2) e^(-3x) -------------- (2) (1) = (2) |
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| 9. |
Find the value of(216)-2 upon3 |
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Answer» Here U can get ur ANSWER..... |
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| 10. |
Show that the conic 8x2-24xy+15y2+48x-48y=0 represents a hyperbola and hence find its eccentricity , lengths , and equations of the axes and foci ? |
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Answer» Hey mate , here is ur ANSWER MARK as BRAINLIEST answer |
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| 11. |
As classmates entered the room , a student kept a record of the colors of shoes they were wearing. The results are Shown in the table. |
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Answer» I don't UNDERSTAND the QUESTION |
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| 12. |
Write the nthterm of an AP1/m,1+m/m,1+2/m,...... |
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Answer» Your question NEEDS a correction. Correct equation : 1 / m , ( 1 + m ) / m , ( 1 + 2m ) / m ..... Step-by-step explanation: Given equation : 1 / m , ( 1 + m ) / m , ( 1 + 2m ) / m..... From the given sequence : First term = a = 1 / m SECOND term = a + d = ( 1 + m ) / m Common Difference = a + d - a ⇒ ( 1 + m ) / m - 1 / m ⇒ ( 1 + m - 1 ) / m ⇒ m / m ⇒ 1 From the identities of arithmetic progressions, n th term = a + ( n - 1 ) d Therefore, the value of nth term of the AP is { 1 + ( n - 1 )m } / m . |
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| 13. |
Evaluate each of the following (9.5)³ |
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Answer» Step-by-step explanation: 9.5CROSE9.5CROSE9.5 ANS:857.375 |
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| 14. |
If the sp of 16 bottle is equal to the cp of 17 bottle find gain or loss percent |
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Answer» LET CP of 16 BOTTLE be X CP of 17 bottle = 17x/16 sp of 16 bottle = 17 x/16 gain℅ = 17 x/ 16 - x)/ x ×.100 =100/16= 6.25% |
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| 15. |
The area of a rectangle is 650cm and its breath is13cm find the perimiter of the rectangle is |
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Answer» AREA of a RECTANGLE =l×b 650=l×13 l=650/13=50 CM perm=2 (l+b) =2×(13+50) =2×63 =126 cm |
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| 16. |
From 17:02 hours to5:15 hours,calculate the duration of time |
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| 17. |
The base and height of a triangle are in ratio 5:3 and the area is 43.2m>2 . find the base and height of the triangle. |
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Answer» UR ANSWER is the pic hope it will HELP u plz MARK as BRAINLIEST. |
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| 18. |
Measure of Central tendency trick icse 10th |
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Answer» In statistics, ARRANGE your set of numbers from smallest to largest. Determine which measure of central TENDENCY you wish to calculate. The three types are mean, median and MODE. To calculate the mean, add all your data and divide the RESULT by the number of data. |
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| 19. |
If the sum of first 14 terms of an arithmetic progression is 1050 and its first term is 10 then the 201h term is : |
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Answer» Tn=a+(n-1)×d |
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| 20. |
If A+B=45° then show that tanA+tanB+tanAtanB=1 |
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Answer» I hope that you will understand CLEARLY then MARK as BRAINLIEST answer |
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| 23. |
Find the area of an isoscles triangle with base of length 6 cm and length of each equal side is 5 cm |
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Answer» Hi Mate!!! |
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| 24. |
1kg=500g+?g give me a answer this question |
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Answer» Here is your answer |
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| 27. |
The greatest number which divides 624 and 936 exactly is 312 . Find the smallest number which is divisible by 624 and 936. |
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Answer» Answer: 1872 is the smallest number which is divisible by 624 and 936. Step-by-step explanation: To find the smallest number which is divisible by 624 and 936, we need to find the LCM of these numbers. We can write these numbers as a FACTOR of 312 as follow: 624= 2 x 312 936= 3 x 312 Now, LCM(624,936)= 312 x 2 x 3 => 1872 |
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| 28. |
Hi ! friends please help me fast Q.A man had rupees 75000 he invested Rs 35,000 in a company which pays him 9% interest per annum and he invested rest of the money in another company which pays him 9.5 % interest per annum find the total compound interest received by him after 2 years? |
Answer» Here is your solutionGIVEN :- A man had rupees 75000 . invested RS 35,000 in a company which PAYS him 9% 75000-35000=Rs. 40000(rest amount ) To find the total compound interest received by him after 2 years:- CASE :-1Rs. 35000 at 9% interest:- A = p (1+r/100)^t A=35000 (1+9/100)^2 A= Rs 4158.3✔ Case:- 2Rs 40000 at 9.5% interest :- A=p (1+r/100)^t A=40000 (1+9.5)^2 A= Rs 47961✔ Total amount = 41583.5+47961=89544.5 Compound interest = 89544.5 - 75000 =>Rs14544.5 Hence, Total compound interest received by him after 2 years is Rs 14544.5 Hope it helps you |
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| 29. |
Prove that diagonal of rectangle is equal toIf x = lengthAnd y = breadth |
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Answer» HEYYYY MATE here is your answer hope it HELP you |
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| 30. |
What is the mean of (^)? tell me in detail. |
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Answer» Hey MATE , |
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| 31. |
Base of pyramid is a ploygon and other faces are of the shape of |
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Answer» the other SHAPE will be cone HOPE it will HELP you |
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| 32. |
The base and height of the triangle in the ratio 3:2 if the area of a triangle is 243cm square find the base and height of a triangle |
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Answer» Ur answer is in the pic |
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| 33. |
If anita scores 66 out of 100 then how much does she scores out of 75? |
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| 34. |
Cumulative frequency. Find the mean age of 100 residents of a colony from the following data:Age in years No. of PersonsGreater than 0 100Greater than 10 90 " " 20 75 " " 30 50 " " 40 25 " " 50 15 " " 60 5 " " 70 0 |
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| 35. |
Find the value of k for which one root of the quadratic equation kx^2-14x+8=0 is 2 |
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Answer» Kx²-14x+8=0 x=2 |
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| 36. |
Sum of two integers=48One number is=25Find other number |
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Answer» 48-25 =23 ............. |
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| 37. |
A room is 6.2 m long , 3.8 m wide and 3.2 m high . It has 2 doors each 2m × 1.2 m and 2 windows each 1.2 m × 1.5 m . Find the cost of white-washing it's wall at the rate of rs 10 per square meter |
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Answer» Here AREA of WHITE washing = |
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| 39. |
Mr Gupta bought 5 kg of potatoes at 18.75 per kg 3 kg of onions at 22.50 per kg and 2kg of potatoes at 35.25 per kg how much did she spend all |
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Answer» Answer:231.7 Step-by-step EXPLANATION: For POTATOES 5×18.75=93.7 For ONIONS 3×22.50=67.5 For potatoes 2×35.25=70.5 Adding all COST =93.7+67.5+70.5=231.7 |
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| 40. |
If a dice is thrown 5 times what is the probability of getting 5 even numbers |
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Answer» PROBABILITY will be 3 |
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| 41. |
पवन एक आयताकार खेत के दो चक्कर लगाता है जिसकी लंबाई 30 मीटर तथा चौड़ाई 25 मीटर है मोहन एक 40 मीटर भुजा वाले वर्गाकार खेत के चारों ओर 3 चक्कर लगाता है। प्रत्येक कितनी दूरी तय करता है। कौन अधिक दूरी तय करता है और कौन कितनी दूरी होनी तय करता है? |
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Answer» PERIMETER of rectangle=2(l+b) =2(30+25) =2×55 =110m Perimeter of square=4×side =4×40 160m Total DISTANCE COVERED by Pawan=2×110 =220m Total distance covered by Mohan=160×3 =480m Difference=480-220=260M So, Mohan covers more distance by 260m. |
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| 42. |
Asymptotes of the curve x^2y^2=a^2(x^2+y^2) form a square of side 2a |
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Answer» Axx2+bxy2=1axx2+bxy2=1 |
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| 43. |
The solution of the recurrence relation t(m) = t( 3m 4) + 1 is |
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Answer» We can solve this using substitution method. Claim: T(n) <= c n^2 IH: We ASSUME that claim is true for all values of n < m. INDUCTIVE Step: T(m) = T(m/4) + T(3m/4) + m^2 <= cm^2/16 + c 9 m^2 / 16 + m^2 = cm^2 (1/16 + 9/16 + 1/c) = c m^2 (10/16 + 1/c) <= c m^2 as long as 1/c <= 6/16. So, we can choose a value of c >= 16/6 and the rest of the math holds up. QED. Therefore, by PMI, T(n) <= c n^2, that is, T(n) = O(n^2). Alternative Proof: FOLLOW the same logic, but instead of c, USE a larger constant such as 10. T(n) = 10 n^2/16 + 10 9n^2/16 + n^2. <= 10 n^2 |
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| 44. |
Find the common factor of 12xand 36 |
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Answer» Solution: FIRSTLY We NEED to convert each of these terms in simple factors forms and then CHOOSE the common factors
i) 12x, 36 12x =2×2×3×x 36=2×2×3×3
Common Factor are 2,2,3 2×2×3=12 |
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| 45. |
a solid cylinder has a total surface area of 231 sq.cm .its curved surface area is one by three of TSA . find the volume of cynilder. |
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Answer» TOTAL SURFACE area = 231 2πr(r+h) =231 ...(1) Curved surface area = 2/3 of total surface area , |
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| 46. |
If an nth degree polynomial is divide by a mth degree polynomial , then the possible degree of the quotient is : |
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Answer» HI MATE!! POSSIBLE DEGREE of POLYNOMIAL is m |
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| 47. |
Plz answer tis question |
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Answer» A +B = -1 |
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| 48. |
Find2.5%of 10%×1×1000000 m cube |
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Answer» FIRST CALCULATE 10% of 1×1000000 10/100×1000000 =100000 Now calculate 2.5% of 100000 2.5/100×100000 2.5×1000 =25×100 =2500 |
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| 49. |
2/3 of a class are girls. What is the ratio girls to boys in the class? |
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Answer» 1/3 is the ratio of BOYS in the CLASS . Please MAKE me as a brainalist |
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| 50. |
A metallic cylinder of base radius 5 cm and height 12cm is melted and recast into spheres of radius 2cm.How many such spheres are got? |
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