This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
Using remainder theorem x³-6x²+9x+3 is divided by x-1 |
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Answer» PUT x-1=0 hence x=1 BY REMAINDER THEOREM WE GET REMAINDER IF WE PUT X=1 IN GIVEN EQUATION Remainder is 7 |
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| 4. |
The base of a parallelogram is 10cmand height is 8cm find the area and perimeter |
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Answer» AREA of a IIgm = base * HEIGHT = 10 * 8= 80 cm^2 |
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| 5. |
The side of a regular polygon is 2.5cmIf the perimetre of the polygon is 15cmThen find the number of sides of the polygon |
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| 6. |
Ratio of milk and water in two vessels a and b is 3:5 and 1:3 respectively . In wjat ratio they must be mixed so resultant solution may contain half milk and half water? |
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Answer» Answer: 2:1 Step-by-step EXPLANATION: Vessel A MILK & water= 3/8 & 5/8 Vessel B milk & water= 1/4 & 3/4 Now milk & water mixed in we get half milk and half water . Then, 3x/8+ y/4= 1/2..............(1) 5x/8 + 3y/4= 1/2 .............(2) solving both (3x+2y)= 4..............(1) 5x+6y= 4................(2) multiply EQUATION 1 by 3 9x+6y=12 5x+6y=4 now SUBTRACT (2) from equation (1) 4x=8 x=2 then y = 1 Therefore ratio is 2:1 |
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| 7. |
A b c and d are points on the circumference of a circle centre o ac is a diameter of the circle |
| Answer» QUESTION is INCOMPLETE | |
| 8. |
Sum of first p, q, r terms of an A. P are a,b,c respectively.SHOW THAT :❌NO SPAM ❌BEST ANSWER WILL BE MARKED AS BRAINLIEST! ✔️ |
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Answer» Note: Sum of n terms = (n/2)[2a + (n - 1) * d]. Let the first term be A and the common difference be d. (i) GIVEN sum of p terms = a. ⇒ (p/2)[2A + (p - 1) * d] = a ⇒ (a/p) = (1/2)[2A + (p - 1) * d] (ii) Given sum of Q terms is b. ⇒ (q/2) = 2A + (q - 1) * d = b ⇒ (q/p) = (1/2)[2A + (q - 1) * d] (III) Given sum of r terms of an AP is c. ⇒ (r/2)[2A + (r - 1) * d] = c ⇒ (r/c) = (1/2)[2A + (r - 1) * d] (IV) On subtracting (ii) from (i), we get (V) On subtracting (iii) from (ii), we get (vi) on subtracting (iii) from (i), we get Now, Given Equation is (a/p)(q - r) + (b/q)(r - p) + (c/r)(p - q) = 0 Hope it helps! |
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| 10. |
Find 13 part i.e value of x |
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Answer» 2^2x - 2^X*2³= -16 |
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| 11. |
Prove mpt. correct answer will be mark as brainlist |
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Answer» Hey friend here is your ANSWER HOPE this helps you plz FOLLOW me plz follow me plz and mark me as BRAINLIEST please |
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| 12. |
⭐Sum of n terms of 2 AP are (3n+8):(7n+15).Find the ration fo their 15 terms.⭐❌NO SPAM ❌BEST ANSWER WILL BE MARKED AS BRAINLIEST! ✔️ |
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Answer» This is the ANSWER................ |
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| 13. |
A certain sum of money amounts to Rs. 1008 in 2 years and to Rs. 1164 in 3 ½ years. Find the sum and rate of interest |
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Answer» As we know,Amount=principal+simple interest |
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| 14. |
(2y +3)(y-2)-(5y+3)(y-2)please answer my question... |
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Answer» |
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| 15. |
Write the coordinates of the vertices of the geometrical figures and find its area. |
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Answer» solution: 1. co-ordinate of square A(2,-1), B(7,-1), C(7,-4) and D(2,-4) Area = length * Breadth Length = 5 units Breadth = 3 units Area = 5*3 = 15 unit²---------------------- Coordinate of second ||gm S(2,-2), P(1,-4), O(4,-4) and R(6,-2) Area OG ||gm = BASE * Altitude Base = 4 units Altitude = 2 units ∴Area = 4*2 = 8units²___________________Amrit_______ |
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| 16. |
Find the cost of fencing a Square park of size 17meter @ rps27.5per meter |
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Answer» Side of SQUARE park= 17m its perimeter= 4*side = 4*17= 68m rate of FENCING= $27.5/metre thus, cost of fencing= $(68*27.5) = $1870 plz mark it as BRAINLIEST |
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| 19. |
A businessman visit Lucknow every fourth day and another Minion Businessman visit Lucknow every 10th day they both visit together on 3rd January which is the next day when they both will again visit Lucknow together |
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| 20. |
A man goes 5m in east and then in north direction. Find the distance from the starting point .give answer of this question |
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| 21. |
A train covers 15 km in 45 minutes ,find the speed of the train in metres per second |
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Answer» it will cover 3 kilometre PER minute Now, CONVERTING it into seconds. it will cover 0.05km per SECOND. If converted into metres, it will cover 50M per second |
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| 22. |
Two mathematicians are sitting opposite to each other for a cup of coffee they looked at the |
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Answer» They will LOOK at the WAITER and other MATHEMATICIANS FACE |
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| 23. |
Koushik read 65 pages in 5/2 hours. how many pages will he read in 4hours? |
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| 24. |
⭐Sum of the first 10 terms is - 80 and that of next 10 terms is - 280.Find AP⭐❌NO SPAM ❌BEST ANSWER WILL BE MARKED AS BRAINLIEST ✔️ |
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Answer» LET a is the first TERM and d is the common difference of AP now use FORMULA, Sn=n/2{2a+(n-1) d} now S10=10/2 {2a+(10-1) d} -80=5 (2a+9d) 2a+9d =-16 ---------------(1) again S20-S10=-280 20/2 {2a+19d} +80=-280 10 (2a+19d)=-360 2a+19d=-36 -----------------(2) solve both equation d=-2 a=1 hence 1, -1,-3,-5 ........ hope helps you ❤️❤️❤️ |
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| 25. |
Anubhav purchased 5 kg 500g of sweets.He gave 4kg 375 g of sweets to his friends.How much sweets are left with him ? |
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Answer» In this TYPE of questions, At first we convert it into simpler. |
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| 26. |
prove that the points (-7 -3) (5 10) (15 8)and(3 -5) taken in order are the vertices of parallelogram |
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Answer» 8) and (3, -5). Distance between (-7, -3), (5, 10) = √[(5 + 7)2 + (10 + 3)2] = √(144 + 169) = √313 Distance between (5, 10), (15, 8) = √[(15 - 5)2 + (8 - 10)2] = √(100 + 4) = √104 Distance between (15, 8), (3, -5) = √[(3 - 15)2 + (-5 - 8)2] = √(144 + 169) = √313 Distance between (3, -5), (-7, -3) = √[(-7 - 3)2 + (-3 + 5)2] = √(100 + 4) = √104Opposite sides of the quadrilateral FORMED by the given points are equal. So, the given points form a parallelogram.Diagonal of a parallelogram divides it into TWO congruent triangles. So, AREA of parallelogram = 2[Area of the triangle formed by (-7, -3), (5, 10) and (15, 8). = 2[1/2 |-7(10 - 8) + 5(8 + 3) + 15(-3 - 10)|] = |-7(2) + 5(11) + 15(-13)| = |-14 + 55 - 195| = |- 154| = 154 sq units. |
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| 27. |
If r square + 1 by r square = 66, find the value of x cube minus 1 /x cube |
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Answer» 1 SQUARE-4side R square -66×4=264x |
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| 28. |
What is the probability of choosing a vowel from the word mathematics? |
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Answer» It is 4/11. Vowels= 4 |
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| 29. |
Two coins are tossed simultaneously.The probaility of getting exactly one tail is |
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Answer» The PROBABILITY of GETTING a TAIL is 1/2 |
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| 30. |
Plz....solve the first part |
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Answer» Your ANS is in the ATTACHMENT... |
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| 31. |
Find the value of p & q. |
| Answer» PLEASE SEE the ATTACHMENT | |
| 32. |
How many students appeare in fiitjee computer based AIITS test. Do anyone know |
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Answer» IF YOU KNOW YOU CAN ANSWER IT BCOZ THIS NOT A QUESTION OF MATH |
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| 33. |
⭐How many terms of the A. P 54,51,48......Should be taken so that their sum is 513?⭐CLASS 10 CHAPTER :ARITHMETIC PROGRESSIONSBEST ANSWER WILL BE MARKED AS BRAINLIEST! |
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Answer» ◼️◼️◼️◼️◼️◼️◼️◼️◼️◼️◼️ Solution:- >>>>>>>>>>>>>>>>>>>>>>>>>> Given :- AP is 54,51,48.... SUM =513 here, a = 54, d = 51-54=-3 Let the NUMBER of terms be Sum of n terms of AP = sum of n terms of Ap = n/2 ( 2×54+(n-1) -3) 513 =n/2 ( 2×54+(n-1) -3) .. 513= n/2(108-3n+3) 2× 513=108n-3n^2+3n 1026=-3n^2+111n 3n^2-111n+1026=0 3n^2-57n-54n+1026=0 (3n-54)(n-19)=0 so, n = 19 or n=54/3=18. THANKS |
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| 34. |
Find out the square root of 6 by long division method? |
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Answer» Here is your answer hope this helps PLZ FOLLOW me plz plz plz and mark me as BRAINLIEST |
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| 35. |
Prove that sin squareA / 2 + sin square B / 2 + sin square C/2 = 1- r / 2R |
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Answer» DEAR Student, Taking LHS: =Sin^2 A/2+sin^2 B/2+sin^2 C/2 =1-cos^2 A/2 +sin^2 B/2+sin^2 C/2 =1-(cos(A+B)/2 cos(A-B)/2) + sin^2 C/2 = 1-(cos(pi-C)/2 cos(A-B)/2)+sin^2C/2 = 1+sin C/2(sin C/2 -cos(A-B)/2) =1+sin C/2(sin(pi –(A+B)/2 -cos(A-B)/2) =1+sin C/2(cos (A+B)/2-cos(A-B)/2) =1+sin C/2(-2sinA/2 sinB/2) = 1-2sinA/2 sin B/2 sin C/2 =RHS [hence PROVED]. CHEERS!! Regards, VIKAS (B. Tech. 4th year Thapar University) |
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| 36. |
how to identify alternate angles interior angles and corresponding angle in paralleogram plz tell me in english and explain in a paper |
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Answer» In parallelogram opposite sides are PARALLEL and hence we use this CONCEPT FIRST either it is parallel or not ,later by constructing diagonal we will get TWO triangles later we have to show them congruent and hence by congruent sides of congruent TRIANGLE (c.s.s.t) you cand identify them |
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| 37. |
The price of an article is reduced by 20% . Find the original price of the article if the reduced price is rs 4000 |
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| 38. |
Observe the following tables and find which pair of variables are in onverse proporyion |
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Answer» Where is table???? UR QUESTION is INCOMPLETE |
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| 39. |
If one third of one fourth of a number is 15 then what is four tenths of the number |
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| 40. |
To go to the office afridi starts from his house by boarding bus he travels 4/5 th of the journey in the bus 1/8 of the journey by rickshaw and 3 km on foot what is the distance travelled by him |
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Answer» Answer: Step-by-step EXPLANATION: |
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| 41. |
What is the hcf of 1168 and 1095 |
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Answer» hey FRIEND! here's your answer: H.C.F of 1168 is 73 H.C.F of 1095 is 73. EXPLAINATION: for first CASE H.C.F of 1168: 1168=1095*1+73. (by EUCLID's division lemma) 1095=73*15+0. so Here, remainder is 0 THEREFORE H.C.F is 73. for second case H.C.F of 1095: 1095=1022*1+73 (by Euclid's division lemma) 1022=73*14+0 so Here, remainder is 0 therefore H.C.F is 73. i hope it will helps you friend please mark my answer as brainlist |
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| 42. |
⭐Sum of 3 numbers is 3 and the product is - 35.Find the numbers.⭐CLASS 10 CHAPTER :ARITHMETIC PROGRESSIONS❌NO SPAM ❌BEST ANSWER WILL BE MARKED AS BRAINLIEST ✔️ |
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Answer» LET three numbers be a, a-d ,a+d now according to the question a+a-d+a+d=3 => a=1 also a(a-d)(a+d)=-35 a(a²-d²)=-35 putting a =1 1(1-d²)=-35 => d=±6 putting a and d in very first step so numbers are 1 , 7 , -5 |
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| 43. |
If point P (x,y) is equidistant from the point A( 5,1) and B ( -1,5) ,show that 3x=2y. |
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| 47. |
Megha purchased 10 metres of curtain material. She stitched 3 curtains if lengths 2 1/4 meter , 1 1/2 meter , and 2 1/3 meter respectively. How much material was left unstitched? |
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Answer» curtain purchased = 10 m stitched = 2 1/4 + 1 1/2 + 2 1/3 => 9/4 + 3/2 + 7/3
CLOTH LEFT UNSTICHED = 10 - 73/12 => [ 120 - 73 ]/12 => 47/12 or 3 11/12 meter |
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| 48. |
Answer the question plz??? |
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Answer» This is the ANSWER .... |
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| 49. |
If 4/7 of a piece of metal weight 28kg.Find the weight of 8/9 of the same piece of metal? |
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Answer» LET the piece of metal be 'X' 4/ 7 of x = 28 4 × x / 7 = 28 4x = 196 => x = 49kg thus, weight of metal x = 49kg Find the 8/ 9 of the same piece of metal , 8 /9 of x = 8 / 9 of 49 8 × 49/ 9 = 392 ÷ 9 = 43.56 kg Answer: -------------- 8/9 of the same piece of metal = 43 .56kg |
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