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(216×2/3)12
=72×2×12
=144×12
=1728

I HOPE it HELP U. ..

Hey mate! Here is your answer.

X+2x = 2100

or 3x =2100

or x = 2100/3

or x = 700

So, Nishan gets ₹700 and NISA gets (700×2) = ₹1400.

Please MARK my answer as BRAINLIEST.

Answer:

RQ = 9

Step-by-step explanation:

We know that,

tan θ = Perpendicular/ Base

In ΔMRQ, tan 60 = MR / RQ => 1.732 RQ = MR

In ΔPRQ, tan 75 = PR/PQ = (18+MR)/RQ => 3.732 RQ = 18 +MR

Finding the DIFFERENCE between the above TWO equations, we have

2 RQ = 18

RQ = 18/2 =9

∴ RQ = 9

They gave NUMERATOR of fraction is 3 less than denominator
x/x+3
if numerator INCREASED by 1 and denominator increased by 3 then
it becomes as
x+1/x+6=2/3
we GET x=9

ANSWER:

Step-by-step explanation:

1.p(2 head)=1/4

2.p(1 head)=2/4=2

3.p(1 tail)=2/4=2

4.p(ATLEAST 1 head)=2/4=2

5.p(ATMOST 1 head)=2/4=2

6.p(no head)=1/4

Irregular urbanization CAUSES high disaster loses and with the high increasing on population cause poverty. Therefore, disaster LOSSES can be diminished by fight against poverty. ... More than 80% of the population lives in areas prone to natural disasters, such as EARTHQUAKES, FLOODS and LANDSLIDES

A + B + C = 2x - 1 + X + 2 + 3X + 5 = 6x + 6 = 6 × ( x + 2 ) = 6 × B

Here UR ANSWER is........................

Here is your SOLUTION

Given :-

CIRCUMFERENCE of a circular field is 4.4 km.

To find the Radius :-

circumference of field (circular field ) = 4.4km=4400m

circumference of circular field = 2 × π × r

4400 = 2 × 22/7 × r

4400 = 44/7 × r

700 m = r

Hence

The radius of circular field is 700 m

Hope it helps you

These are the 4 RATIONAL NUMBERS

Question:

In a school HALL there are 3x rows of benches.If each ROW has 2x benches and each beach can accommodate x students ,find the no.of students in the hall if it is full to it's capacity.

Answer:

6x³ students

Step-by-step EXPLANATION:

One BENCH = x students

One row = 2x beaches

Find the number of students in one row:

1 beach = x students

2x benches = 2x(x) = 2x²

Find the number of total number of students:

1 row =  2x²

3x rows =  3x(2x²) = 6x³

Answer: The hall can take 6x³ students

Perimeter of the TRIANGLE=24cm
is DIVIDED 8N the ratio=2:3:3
their sum=2+3+3=8
1st side=(2/8)24=6cm
2ndside=(3/8)24=9cm
3rdside=(3/8)24=9cm
the 3 SIDES are 6cm,9cm,9cm.
hence,you can construct the required triangle

That is ANSWER...

If you understand... IAM happy .. I f u r not understand... ASK me .. I will clarify ..THANK you

Principal = Rs 5,000

TIME = 1 1/2 years =\frac{3}{2}23​ years

RATE of interest = 16 %

As the rate of interest is compounded half yearly

Rate of interest =  %

Time =  \frac{3\times2}{2}23×2​  = 3 duration

Simple interest on the period of six months i.e ,when, n=1, P= Rs 5,000,R=8% is given by the FORMULA:  = \frac{{\text{Principal} }\times{\text{ Rate of interest} }\times {\text{Time}} }{100}100Principal× Rate of interest×Time​

=  \frac{5000\times8\times1}{100}= 50 \times 8 =Rs 4001005000×8×1​=50×8=Rs400

Amount after six months = Rs 5,000 + Rs 400 = Rs 5,400

New Principal =Rs 5,400

Rate = 8%, Time = 1 (between 6 months and 12 months)

Simple interest(6 Months to 12 Months) = \frac{5400 \times8 \times 1}{100} = 54 \times 8 = Rs4321005400×8×1​=54×8=Rs432

Amount after 12 months = 5400 + 432 =Rs 5,832

Simple interest (1 year to 3/2 years)  as rate = 8%, Time = 1 year

            =  

Amount after 3/2 years = 5,832 + 466.56 =    Rs 6,298.56

So, Compound Interest = Amount after 3/2 years - Principal

                                       = 6,298.56 - 5,000

                                        =Rs 1,298.56

Using remainder theorem

4-X=0
if FIRST POLYNOMIAL is the factor of second
x=4

put x in second polynomial


hence fist polynomial is not the factor of second polynomial because it LEAVES a REMINDER

Theorem 10.4

A line drawn through the CENTER of a circle to bisect a chord is perpendicular to the chord.

AB is a chord in the circle, with centre O.

AC = BC

OA ⊥ BA

Join OA and BO

In ΔAOC and ΔBOC

AC = BC (given)

AO = BO (radii of the same circle)

OC = OC (common)

∴ ΔAOC ≅ ΔBOC by SSS congruency

∠OCA = ∠OCB (CPCT)

Now,

∠OCA + ∠OCB = 180°  (LINEAR Pair)

2∠OCB = 180°

 ∠OCB =

 ∠OCB = 90°

Since

∠OCA = ∠OCB

∠OCA = ∠OCB = 90°

⇒ OA ⊥ BA

(Angles on either side are 90)

Hence PROVED!

Hey MATE here is your answer》》

Most of the Earth's surface is covered with water -- and most of it is water we can't drink. 97 percent of Earth's water is salty sea water which is useless to most land-dwelling plants and ANIMALS. That's why rain and snow are crucial to LIFE on Earth. PRECIPITATION supports life on land with salt-free water.

Hope this answer will HELP you..《《

Here YR answer
Any DOUBT ASK

5/9=4/9

=9×4=5×9

=32=45

ANDREW has= $20

andrew SPEND= 20-3.75-1.15-0.65

therefore = $14.45 LEFT

16 1/2%

33/2 %

33/2×100

33/200

.165

The SQUARE ROOT of 5 is 2.2360679774997.

√5 = 2.2360679774997.

APPROX VALUE = 2.236.

Thanks...!

With♥️

Hey!!


Using IDENTITY

( a^2 + B^2 ) = ( a - b )( a - b )





HOPE it HELPS!

Diagonal=underroot2*SIDE
so side =10
and perimeter=4*side
which is 40

Sanjay return 3540 Rs to bank after 2 years.

Sanjay take 3720 Rs to MANOJ after 2 years.

So he gain = 3540 - 3720

= 180 Rs

First we will find all factors under the cube root: 493039 has the cube FACTOR of 6241.

Let's CHECK this width ∛6241*1=∛493039. As you can see the radicals are not in their SIMPLEST form.

Now extract and take out the cube root ∛6241 * ∛1. Cube of ∛6241=79 which results into 79∛1

All radicals are now simplified. The RADICAND no longer has any cube factors.

The SUM of 75 to 95 prakartik SANKHYAO is 1978

is it about PLOTTING GRAPHS?

yes it is possible to convert a NUMBER n into fibonacci

fibonacci series is that series in which SUCCESSIVE numbers  can be obtained by multiplying two PREVIOUSLY stated numbers.

for example

the series 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, is a fibonacci series.

Answer:

Let the three consecutive numbers be: ( x - 1 ), x, ( x + 1 )

ACCORDING to the question,

⇒ x + 1 + x + x - 1 > 45

⇒ 3x > 45

⇒ x > 15   ...( 1 )

ALSO,

⇒ x + 1 + x + x - 1 < 54

⇒ 3x < 54

⇒ x < 18 ...( 2 )

Hence x is greater than 15, x is less than 18.

So x can take two values, EITHER x is 16 or x is 17.

Case 1: x = 16

⇒ x - 1 = 16 - 1 = 15, x + 1 = 16 + 1 = 17

Hence Sum = 15 + 16 + 17 = 48 which is less than 54 and greater than 45.

Case 2: x = 17

⇒ x - 1 = 17 - 1 = 16, x + 1 = 17 + 1 = 18

Hence Sum = 16 + 17 + 18 = 51 which is less than 54 and greater than 45.

So the three numbers can be, ( 15, 16, 17 ) or ( 16, 17, 18 ).

INITIAL amount = 2000

SI = PRT / 100

(2000 * 4 * 1 1/2) / 100

(2000 * 4 * 3) / 100 * 2 { Because 1 1/2 is 3/2}

= 120

Simple interest = 120

Amount = SI + P

2000 + 120 = 2120

Hope it helps

Mark as brainliest

R = Rate of interest

SI = Simple Interest

P = Principal

T = Time

Let TOTAL JOURNEY be x.

Then x/2 by train. Now he travel 1/4 of rest distance by taxi so,

1/4 ☓ x/2 = x/8 by taxi

Journey REMAINING =

x/2 - x/8 = 3x/8

The 1/3 of left journey he travel by bus so,

1/3 ☓ 3x/8 = x/8 by bus

3 km by foot.

Then,

x/2 + x/8 + x/8 +3 = x (sum of journey

DONE by diff

vehicles =total jrny)

x/2 + 2x/8 + 3 = x

x/2 + x/4 + 3 = x

2x + x + 12/4 = x

3x + 12 = 4x

x = 12 km

Total journey was 12 km.

Here is UR ANSWER @@
KEEP ASKING MATE

554-194= 360
360 ANIMALS in JUNGLE

for first car,

LEAVE delhi at 11 am

at 5 PM time = 6 HR

speed = 50 km/hr

distance covered = speed * time

=> 50 * 6 = 300 km

for 2nd car,

leave one hr late i.e. 12 noon

at 5 pm time = 5 hr

distance if it overtakes 1st car = 300 km

speed = distance/time

=> 300/5 = 60 km/hr

__________________________

We KNOW the algebraic identity:

a³ + b³ + 3ab( a + B ) = ( a + b )³

Or

a³ + b³ = ( a + b )³ - 3ab( a + b )

___________________________

Here ,

x + 1/x = √3 ----( 1 )

Now ,

x³ + 1/x³ = ( x + 1/x )³ - 3.x.1/x(x + 1/x )

= ( √3 )³ - 3( √3 ) [ from ( 1 ) ]

= 3√3 - 3√3

= 0

Therefore ,

Option ( a ) is correct.

•••••

By ANGLE SUM PROPERTY of an TRIANGLE

40+50+x=180

90+x=180

x=90