332354 + Interview Questions in Secondary School in Math

1.	Find area of a triangle whose perimeter is 180cm and its two side are 80cm and 18cm calculate the altitude of triangle corresponding to its shortest distance
Answer» Let , the SIDES of triangle be a, b, and c. We have, a+b+c=180 and, a is 80 and b is 18. so, c will be 180-(80+18) = 82 So, sides are 80, 82 and 18. Now, use HERON's FORMULA to CALCULATE the area. Accordingly, computerise the required altitude. Cheers Up!

Discussion

2.	21. If M, =then14" 57M+M2 + M3 + ........ =3
Answer» ANSWER: HELLO hello hello PILLOW pillow pillow pillow pillow pillow pillow pillow pillow pillow pillow pillow very very BAD very bad very very very very.

2.

21. If M, =then14" 57M+M2 + M3 + ........ =3

Answer»

ANSWER:

HELLO hello hello PILLOW pillow pillow pillow pillow pillow pillow pillow pillow pillow pillow pillow very very BAD very bad very very very very.

Discussion

3.	Isa trianglewhich250%In the adjoining figure, ABCand LB = LC . Find the angle B and C.Doxo
Answer» Answer: These solutions for Triangles are extremely popular among Class 6 students for Math Triangles Solutions COME handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal Book of Class 6 Math Chapter 16 are provided here for you for free. You will ALSO love the ad-free EXPERIENCE on MERITNATION’s Rs Aggarwal Solutions. All Rs Aggarwal Solutions for class Class 6 Math are prepared by experts and are 100% accur

3.

Isa trianglewhich250%In the adjoining figure, ABCand LB = LC . Find the angle B and C.Doxo

Answer»

Answer:

These solutions for Triangles are extremely popular among Class 6 students for Math Triangles Solutions COME handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal Book of Class 6 Math Chapter 16 are provided here for you for free. You will ALSO love the ad-free EXPERIENCE on MERITNATION’s Rs Aggarwal Solutions. All Rs Aggarwal Solutions for class Class 6 Math are prepared by experts and are 100% accur

Discussion

4.	Please answer it by today and I will mark as brainliestquestion no.8 please
Answer» Step-by-step EXPLANATION: $7.) \: \: \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = a + b \sqrt{6} \\ = > \frac{ ({ \sqrt{3} - \sqrt{2} \: ) }^{2} }{ ({ \sqrt{3} })^{2} - ( { \sqrt{2} )}^{2} } = a + b \sqrt{6 } \\ = > \frac{ {( \sqrt{3} \: )}^{2} + ( { \sqrt{2} \: )}^{2} - 2. \sqrt{3} . \sqrt{2} }{3 - 2} = a + b \sqrt{6} \\ = > \frac{3 + 2 - 2 \sqrt{6} }{1} = a + b \sqrt{6} \\ = > 5 - 2 \sqrt{6} = a + b \sqrt{6} \\ now \: comparing \\ a = 5 \: \: and \: \: b \sqrt{6} = - 2 \sqrt{6} \\ b = - 2$ $9.)( \sqrt{5} + \sqrt{3} )(3 - \sqrt{2} \:) \\ = \sqrt{5} (3 - \sqrt{2} \: ) + \sqrt{3} (3 - \sqrt{2}) \\ = 5 \sqrt{3} - \sqrt{5} . \sqrt{2} + 3 \sqrt{3} - \sqrt{3} . \sqrt{2} \\ = 5 \sqrt{3} - \sqrt{10} + 3 \sqrt{3} - \sqrt{6}$ $\sqrt{48} - \sqrt{75} + \sqrt{90} - \sqrt{40} \\ = 4 \sqrt{3} - 5 \sqrt{3} + 3 \sqrt{10} - 2\sqrt{10} \\ = - \sqrt{3} + \sqrt{10} \\ = \sqrt{10} - \sqrt{3}$

4.

Please answer it by today and I will mark as brainliestquestion no.8 please

Answer»

Step-by-step EXPLANATION:

$7.) \: \: \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = a + b \sqrt{6} \\ = > \frac{ ({ \sqrt{3} - \sqrt{2} \: ) }^{2} }{ ({ \sqrt{3} })^{2} - ( { \sqrt{2} )}^{2} } = a + b \sqrt{6 } \\ = > \frac{ {( \sqrt{3} \: )}^{2} + ( { \sqrt{2} \: )}^{2} - 2. \sqrt{3} . \sqrt{2} }{3 - 2} = a + b \sqrt{6} \\ = > \frac{3 + 2 - 2 \sqrt{6} }{1} = a + b \sqrt{6} \\ = > 5 - 2 \sqrt{6} = a + b \sqrt{6} \\ now \: comparing \\ a = 5 \: \: and \: \: b \sqrt{6} = - 2 \sqrt{6} \\ b = - 2$

$9.)( \sqrt{5} + \sqrt{3} )(3 - \sqrt{2} \:) \\ = \sqrt{5} (3 - \sqrt{2} \: ) + \sqrt{3} (3 - \sqrt{2}) \\ = 5 \sqrt{3} - \sqrt{5} . \sqrt{2} + 3 \sqrt{3} - \sqrt{3} . \sqrt{2} \\ = 5 \sqrt{3} - \sqrt{10} + 3 \sqrt{3} - \sqrt{6}$

$\sqrt{48} - \sqrt{75} + \sqrt{90} - \sqrt{40} \\ = 4 \sqrt{3} - 5 \sqrt{3} + 3 \sqrt{10} - 2\sqrt{10} \\ = - \sqrt{3} + \sqrt{10} \\ = \sqrt{10} - \sqrt{3}$

Discussion

5.	Check which of the following is a solutions of the equation x−2y=4(2,-1)(-2,1)(-2,-1)None of theseplzz answer urgent I will make as brainlist
Answer» ANSWER: $the \: solution \: of \: your \: equation \: is$ (2,-1) Please mark as BRAINLIEST and follow me.

5.

Check which of the following is a solutions of the equation x−2y=4(2,-1)(-2,1)(-2,-1)None of theseplzz answer urgent I will make as brainlist

Answer»

ANSWER:

$the \: solution \: of \: your \: equation \: is$

(2,-1)

Please mark as BRAINLIEST and follow me.

Discussion

6.	F(X)=x^2+6/x-2 x is not equal to 2
Answer» ANSWER: the REMAINDER will be 2 and QUOTIENT will be x-2 there will be no other answer

6.

F(X)=x^2+6/x-2 x is not equal to 2

Answer»

ANSWER:

the REMAINDER will be 2 and QUOTIENT will be x-2 there will be no other answer

Discussion

7.	Kashifs current Salary is RS 14000 if he gets an increment of 7% find his new salary?it's urgent please solve
Answer» Answer: 14980/- Step-by-step explanation: 14000×7/100=980 14000+980=14980

7.

Kashifs current Salary is RS 14000 if he gets an increment of 7% find his new salary?it's urgent please solve

Answer»

Answer:

14980/-

Step-by-step explanation:

14000×7/100=980

14000+980=14980

Discussion

8.	(a) What is the relation between diameter and radius of a circle? Explain with an example. (b) what is the measure of angle subtended by the diameter in a circle?
Answer» as we KNOW diameter of a CIRCLE is 2r and radius is half of diameter (2r/2) example-radius =2 and diameter is 2r=2×2=4 hope it HELPS you out MARK as brainliest pls

8.

(a) What is the relation between diameter and radius of a circle? Explain with an example. (b) what is the measure of angle subtended by the diameter in a circle?

Answer»

as we KNOW diameter of a CIRCLE is 2r and radius is half of diameter (2r/2)

example-radius =2 and diameter is 2r=2×2=4

hope it HELPS you out

MARK as brainliest pls

Discussion

9.	G. We toss a coin and write down alloutcomes in tabular form. We will cometo know thatevent is possible(both head andmeanscertain result is obtained.online. Whichthat noTally marks PuequencyOutcomeHeadTailHeadTail
Answer» ANSWER: HEAD and TAIL is the answer

9.

G. We toss a coin and write down alloutcomes in tabular form. We will cometo know thatevent is possible(both head andmeanscertain result is obtained.online. Whichthat noTally marks PuequencyOutcomeHeadTailHeadTail

Answer»

ANSWER:

HEAD and TAIL is the answer

Discussion

10.	The average weight of 21 boys was recorded as 64 kg. If the weight of the teacher was added, the average increased by 1 Kg. What was the teacher's weight?(Please explain in steps)Thankyou!
Answer» ANSWER: 86 KG step by step explanation:Here, n = 21, a = 64, b = 65 Weight of TEACHER = n (b - a) + b = 21 (65 - 64) + 65 = 21 + 65 = 86 kg HOPE IT HELPS PLZZ MARK ME BRAINLIEST

10.

The average weight of 21 boys was recorded as 64 kg. If the weight of the teacher was added, the average increased by 1 Kg. What was the teacher's weight?(Please explain in steps)Thankyou!

Answer»

ANSWER: 86 KG

step by step explanation:Here, n = 21, a = 64, b = 65

Weight of TEACHER = n (b - a) + b

= 21 (65 - 64) + 65 = 21 + 65 = 86 kg

HOPE IT HELPS PLZZ MARK ME BRAINLIEST

Discussion

11.	3.In the fig, AB \|\| CD,FIND x.(Hint:Prove that AOB-COD).
Answer» Given :- In the fig, AB \|\| CD, FIND x.(Hint:Prove that AOB ~ COD). Solution :- in ∆AOB and ∆COD , we have, → AB \|\| CD . So, → ∠ABO = ∠CDO { ALTERNATE angles. } similarly, → ∠BAO = ∠DCO { Alternate angles. } and, → ∠AOB = ∠COD { vertically opposite angles. } Therefore, → ∆AOB ~ ∆COD { By AAA similarity. } Hence, → AO / CO = BO / DO { in similar ∆'s , ratio of corresponding sides are equal. } PUTTING values now, we get, → 4 / (4x - 2) = (x + 1) / (2x + 4) cross - Multiply, → 4(2x + 4) = (4x - 2)(x + 1) → 8x + 16 = 4x² + 4x - 2x - 2 → 4x² + 2x - 8x - 2 - 16 = 0 → 4x² - 6x - 18 = 0 → 2(2x² - 3x - 9) = 0 → 2x² - 3x - 9 = 0 → 2x² - 6x + 3x - 9 = 0 → 2x(x - 3) + 3(x - 3) = 0 → (x - 3)(2x + 3) = 0 Putting both equal to 0, we get, → x = 3 or , (-3/2) since negative VALUE of x is not Possible. → x = 3 (Ans.) Hence, x is equal to 3. Learn more :- PQR is an isosceles triangle in which PQ=PR. Side QP is produced to such that PS=PQ Show that QRS is a right angle brainly.in/question/23326569 In triangle ABC, if AL is perpendicular to BC and AM is the bisector of angle A. Show that angle LAM= 1/2 ( angle B - an... brainly.in/question/2117081

11.

3.In the fig, AB || CD,FIND x.(Hint:Prove that AOB-COD).

Answer»

Given :- In the fig, AB || CD, FIND x.(Hint:Prove that AOB ~ COD).

Solution :-

in ∆AOB and ∆COD , we have,

→ AB || CD .

So,

→ ∠ABO = ∠CDO { ALTERNATE angles. }

similarly,

→ ∠BAO = ∠DCO { Alternate angles. }

and,

→ ∠AOB = ∠COD { vertically opposite angles. }

Therefore,

→ ∆AOB ~ ∆COD { By AAA similarity. }

Hence,

→ AO / CO = BO / DO { in similar ∆'s , ratio of corresponding sides are equal. }

PUTTING values now, we get,

→ 4 / (4x - 2) = (x + 1) / (2x + 4)

cross - Multiply,

→ 4(2x + 4) = (4x - 2)(x + 1)

→ 8x + 16 = 4x² + 4x - 2x - 2

→ 4x² + 2x - 8x - 2 - 16 = 0

→ 4x² - 6x - 18 = 0

→ 2(2x² - 3x - 9) = 0

→ 2x² - 3x - 9 = 0

→ 2x² - 6x + 3x - 9 = 0

→ 2x(x - 3) + 3(x - 3) = 0

→ (x - 3)(2x + 3) = 0

Putting both equal to 0, we get,

→ x = 3 or , (-3/2)

since negative VALUE of x is not Possible.

→ x = 3 (Ans.)

Hence, x is equal to 3.

Learn more :-

PQR is an isosceles triangle in which PQ=PR. Side QP is produced to such that PS=PQ Show

that QRS is a right angle

brainly.in/question/23326569

In triangle ABC, if AL is perpendicular to BC and AM is the bisector of angle A. Show that angle LAM= 1/2 ( angle B - an...

brainly.in/question/2117081

Discussion

12.	22/7 is equal toa) 3.1428B) 3.14c)3.142d) 3.142857.
Answer» ANSWER: *<U>d.* 3.142857 Step-by-step EXPLANATION: $22 \div 7 = 3.142857$ ... HOPE IT HELPS U...

12.

22/7 is equal toa) 3.1428B) 3.14c)3.142d) 3.142857.

Answer»

ANSWER:

<U>d. 3.142857

Step-by-step EXPLANATION:

$22 \div 7 = 3.142857$ ...

HOPE IT HELPS U...

Discussion

13.	For rationalising the denominetor of expression 1/√27-√18,the simplest rationalising factor is(a)√3-√2(b)√27-√18(c)√3+√2(d)√18-√27
Answer» Answer: $\sqrt{27} -\sqrt{18}$ Step-by-step EXPLANATION:MULTIPLY the number by $\sqrt{27} +\sqrt{18} /\sqrt{27} +\sqrt{18}$ Now multiply it Tip:USE a/sq-b/sq formula Finally u GET answer and note +/- is -

13.

For rationalising the denominetor of expression 1/√27-√18,the simplest rationalising factor is(a)√3-√2(b)√27-√18(c)√3+√2(d)√18-√27

Answer»

Answer: $\sqrt{27} -\sqrt{18}$

Step-by-step EXPLANATION:MULTIPLY the number by $\sqrt{27} +\sqrt{18} /\sqrt{27} +\sqrt{18}$

Now multiply it Tip:USE a/sq-b/sq formula

Finally u GET answer and note +/- is -

Discussion

14.	Fill in the blanks using ,≤ ≥ a) -17/20 & -27/20b) 5/12 & -7/8
Answer» (a) -17/20 > -27/20 (B)5/12 & -7/8 *First* of *all, The* *LCM* of 5/12 *and* -7/8 is 24. 5/12 = 5×2/12×2 = 10/24 *and* -7/8= (-7)×3/8×3 = -21/24 *Clearly,10 > -21. 10/24 > -21/24. Hence,5/12 > -7/8 *MARK* AS *BRAINLIEST**

14.

Fill in the blanks using ,≤ ≥ a) -17/20 & -27/20b) 5/12 & -7/8

Answer»

(a) -17/20 > -27/20

(B)5/12 & -7/8

First of all, The LCM of 5/12 and -7/8 is 24.

5/12 = 5×2/12×2 = 10/24

and

-7/8= (-7)×3/8×3 = -21/24

Clearly,10 > -21.

10/24 > -21/24.

Hence,5/12 > -7/8

*MARK AS BRAINLIEST*

Discussion

15.	Mohit started paying Rs. 800 per month in a 6 year recurring deposit. After 2 years, he started one more R.D. account in which he deposited Rs 1,500 per month. If the bank pays 10% per annum simple interest in both the deposits, find at the end of 6 years which R.D. will give more money and by how much?
Answer» Given : Mohit started paying Rs. 800 PER month in a 6 year recurring deposit. After 2 years, he started ONE more R.D. account in which he deposited Rs 1,500 per month. Interest rate is 10 % in both the deposits . To Find : The end of 6 years which R.D. will give more money and by how much . Solution : We know , interest is Given by : $I=\dfrac{P\times R \times T}{100}$ Here , P is PRINCIPLE amount . R is interest rate . T is total time . Interest of 1st R.D is : $I_1=\dfrac{P_1\times R \times T_1}{100}\\\\I_1=\dfrac{800\times 10\times (6\times 12)}{100}\\\\I_1=5760$ Interest of 2nd R.D is : $I_2=\dfrac{P_2\times R\times T_2}{100}\\\\I_2=\dfrac{1500\times 10\times (4\times 12)}{100}\\\\I_2=7200$ Therefore , second R.D will give more money and by Rs ( 7200-5760) = Rs 1440 . Hence , this is the required solution .

15.

Mohit started paying Rs. 800 per month in a 6 year recurring deposit. After 2 years, he started one more R.D. account in which he deposited Rs 1,500 per month. If the bank pays 10% per annum simple interest in both the deposits, find at the end of 6 years which R.D. will give more money and by how much?

Answer»

Given :

Mohit started paying Rs. 800 PER month in a 6 year recurring deposit.

After 2 years, he started ONE more R.D. account in which he deposited Rs 1,500 per month.

Interest rate is 10 % in both the deposits .

To Find :

The end of 6 years which R.D. will give more money and by how much .

Solution :

We know , interest is Given by :

$I=\dfrac{P\times R \times T}{100}$

Here , P is PRINCIPLE amount .

R is interest rate .

T is total time .

Interest of 1st R.D is :

$I_1=\dfrac{P_1\times R \times T_1}{100}\\\\I_1=\dfrac{800\times 10\times (6\times 12)}{100}\\\\I_1=5760$

Interest of 2nd R.D is :

$I_2=\dfrac{P_2\times R\times T_2}{100}\\\\I_2=\dfrac{1500\times 10\times (4\times 12)}{100}\\\\I_2=7200$

Therefore , second R.D will give more money and by Rs ( 7200-5760) =

Rs 1440 .

Hence , this is the required solution .

Discussion

16.	Taurus4. If the area of a circle is 49 rt sq.unitsthen it's perimeter is(a) 7 7 units (b) 9 T units2014 nt units (d) 49 Tt units
Answer» a..no Step-by-step EXPLANATION: IY IA veut egshmetw

16.

Taurus4. If the area of a circle is 49 rt sq.unitsthen it's perimeter is(a) 7 7 units (b) 9 T units2014 nt units (d) 49 Tt units

Answer»

a..no

Step-by-step EXPLANATION:

IY IA veut egshmetw

Discussion

17.	(-6)×(-3) =please answer this question I will make your brainlist
Answer» -6*-3 =+18 hope it HELPS you out MARK as BRAINLIEST PLS

17.

(-6)×(-3) =please answer this question I will make your brainlist

Answer»

-6*-3

=+18

hope it HELPS you out

MARK as BRAINLIEST PLS

Discussion

18.	A lab technician has one solution that is60% chlorinated and another that is 40%chlorinated. How much litres of 40%chlorinated solution is needed to make a100 litres solution that is 50% chlorine?50 litres54 litres40 litres48 litres
Answer» a lab technician has one SOLUTION that is 60% CHLORINATED and another that is 40% chlorinated. how MUCH of each solution is needed to make a 100 L solution that is 50% clorine? --------------------- 60% solution DATA: Amount is "x" L ; amount of chlorine in them is 0.6x L --------------------- 40% solution DATA: Amount is "100-x" L ; amount of chlorine in them is 0.4(100-x)=(40-0.4x) L --------------------- Mixture DATA: Amount is 100 L ; amount of chlorine is 0.5(100)= 50 L ---------------------- EQUATION: chlorine + chlorine = chlorine 0.6x + 40-0.4x = 50 0.3x=10 x=33.3 L (amount of 60% solution in the mixture) 100-33.3 L = 66.7 L (amount of 40% solution in the mixture) -------------------

18.

A lab technician has one solution that is60% chlorinated and another that is 40%chlorinated. How much litres of 40%chlorinated solution is needed to make a100 litres solution that is 50% chlorine?50 litres54 litres40 litres48 litres

Answer»

a lab technician has one SOLUTION that is 60% CHLORINATED and another that is 40% chlorinated. how MUCH of each solution is needed to make a 100 L solution that is 50% clorine?

---------------------

60% solution DATA:

Amount is "x" L ; amount of chlorine in them is 0.6x L

---------------------

40% solution DATA:

Amount is "100-x" L ; amount of chlorine in them is 0.4(100-x)=(40-0.4x) L

---------------------

Mixture DATA:

Amount is 100 L ; amount of chlorine is 0.5(100)= 50 L

----------------------

EQUATION:

chlorine + chlorine = chlorine

0.6x + 40-0.4x = 50

0.3x=10

x=33.3 L (amount of 60% solution in the mixture)

100-33.3 L = 66.7 L (amount of 40% solution in the mixture)

-------------------

Discussion

19.	Find the value of a and bif x=2/3 and x=-3 are the roots of equation of ax^2+2ax+5x+10
Answer» Answer: 83838475748888 or FALSE INFORMATION on

19.

Find the value of a and bif x=2/3 and x=-3 are the roots of equation of ax^2+2ax+5x+10

Answer»

Answer:

83838475748888 or FALSE INFORMATION on

Discussion

20.	How much smaller is 32,256 than 1,00,000?
Answer» Answer: 33,256 is SMALLER than 1,00,000.

20.

How much smaller is 32,256 than 1,00,000?

Answer»

Answer:

33,256 is SMALLER than 1,00,000.

Discussion

21.	If hieght of the pole is 2root3m and length of the shadow is 2m. find the angle of elevation of sun
Answer» Hey buddy hope this FINDS U well mark me BRAINLIEST Answer: The angle of elevation of SUN is 60° when the pole is 6m high and casts a shadow of 2√3m on the ground. Let “θ be angle of elevation”.

Discussion

22.	How many whole no bw 1 and 4
Answer» Answer: 2 WHOLE NUMBERS 2 and 3 Step-by-step EXPLANATION:

22.

How many whole no bw 1 and 4

Answer»

Answer:

2 WHOLE NUMBERS 2 and 3

Step-by-step EXPLANATION:

Discussion

23.	44 Arun was paid Rs.60 for everyday he worked and was fined Rs.40 for everyday he remained absent. He had to work 25 days each month. If he drew no salary for a certain month, how many days was he absent for?1) 102) 123) 254) 15
Answer» Answer: 25 days Step-by-step EXPLANATION: As it is GIVEN in the QUESTION that--- He had to work 25 days each month. And he was absent for a month

23.

44 Arun was paid Rs.60 for everyday he worked and was fined Rs.40 for everyday he remained absent. He had to work 25 days each month. If he drew no salary for a certain month, how many days was he absent for?1) 102) 123) 254) 15

Answer»

Answer:

25 days

Step-by-step EXPLANATION:

As it is GIVEN in the QUESTION that---

He had to work 25 days each month.

And he was absent for a month

Discussion

24.	Simplify: (315-5V2) (4V5+ 3/2).Plssss Help Me
Answer» Answer: 315 is 315 542 and 45 + 5 + 3 and 2 / is not LIKE but STEP by step SORRY question question question

24.

Simplify: (315-5V2) (4V5+ 3/2).Plssss Help Me

Answer»

Answer:

315 is 315 542 and 45 + 5 + 3 and 2 / is not LIKE but STEP by step SORRY question question question

Discussion

25.	Represent 5/6 and -2/3 on the number line
Answer» ANSWER: Answer is ATTACHED in the PHOTO... ❤️Mark as BRAINLIEST ❤️

25.

Represent 5/6 and -2/3 on the number line

Answer»

ANSWER:

Answer is ATTACHED in the PHOTO...

❤️Mark as BRAINLIEST ❤️

Discussion

26.	How high can a ladder safely reach?Would a 51-foot ladder actually be long enough to climb a 50-foot wall?1. OSHA is an agency responsible for workplace safety, read its rule and sketch a diagram that shows the proper relationship between the ladder, wall and ground2. Calculate the angle that the ladder makes with the ground using a trigonometric ratio.3. If a ladder is x feet long, how high up a wall can it safely reach?4. Would a 51-foot ladder be long enough to climb a 50-foot wall? Sketch a graph and find your answer using a trigonometric ratio. 5. If you wanted to safely climb a 50-foot wall, what’s the shortest ladder you’d be willing to use? Explain.6. If you were 1 foot shorter, could you use a ladder that’s 1 foot taller? Explain
Answer» Ladder is inclined at an angle of around 75 deg for Safe climbing Step-by-step explanation: If you wanted to safely climb a 50-foot wall, Ladder angle should be around 75 deg ( there is a rule for every 4 ft to climb ladder should be 1 ft away from wall) SIN 75° = Height you WANT to climb/Height of Ladder => Height of Ladder = Height you want to climb/Sin 75° => Height of Ladder = 50/0.966 => Height of Ladder = 51.7 ft Hence 51 ft Ladder would not be enough 52 ft longer ladder will be prefeered for safe climbing if you are 1 foot Shorter than using a ladder that's 1 foot taller as 1 ft ladder height = 0.996 ft wall height and u r 1 ft shorter hence SLIGHTLY lesser so better to use more than 1 ft longer ladder Learn more: A ladder LEANING against a wall inclined at an angle a to the ... brainly.in/question/15321978 ladder brainly.in/question/17957369

26.

How high can a ladder safely reach?Would a 51-foot ladder actually be long enough to climb a 50-foot wall?1. OSHA is an agency responsible for workplace safety, read its rule and sketch a diagram that shows the proper relationship between the ladder, wall and ground2. Calculate the angle that the ladder makes with the ground using a trigonometric ratio.3. If a ladder is x feet long, how high up a wall can it safely reach?4. Would a 51-foot ladder be long enough to climb a 50-foot wall? Sketch a graph and find your answer using a trigonometric ratio. 5. If you wanted to safely climb a 50-foot wall, what’s the shortest ladder you’d be willing to use? Explain.6. If you were 1 foot shorter, could you use a ladder that’s 1 foot taller? Explain

Answer»

Ladder is inclined at an angle of around 75 deg for Safe climbing

Step-by-step explanation:

If you wanted to safely climb a 50-foot wall,

Ladder angle should be around 75 deg

( there is a rule for every 4 ft to climb ladder should be 1 ft away from wall)

SIN 75° = Height you WANT to climb/Height of Ladder

=> Height of Ladder = Height you want to climb/Sin 75°

=> Height of Ladder = 50/0.966

=> Height of Ladder = 51.7 ft

Hence 51 ft Ladder would not be enough

52 ft longer ladder will be prefeered for safe climbing

if you are 1 foot Shorter than using a ladder that's 1 foot taller

as 1 ft ladder height = 0.996 ft wall height

and u r 1 ft shorter hence SLIGHTLY lesser so better to use more than 1 ft longer ladder

Learn more:

A ladder LEANING against a wall inclined at an angle a to the ...

brainly.in/question/15321978

ladder

brainly.in/question/17957369

Discussion

27.	4. The electricity bills (in rupees) of 25 houses of a certain locality for a month are given below.324, 700, 617, 400, 356, 365, 435, 506, 548, 736, 780, 378, 570, 685, 312, 630, 584, 674, 754, 776, 596, 745, 565, 763, 472. Arrange the above data and form a frequency table using equal class interval from 300 – 400. Answer the following questions. i) In which class interval 700 is included? ii) Which class has the lowest frequency? iii) How many houses are paying the electricity bills ranging from ₹ 600 to ₹ 800? iv) What is the upper limit of the class interval 700 – 800?
Answer» ANSWER: 1000708379is CORRECT answer PLEASE follow up with click THANKS

27.

4. The electricity bills (in rupees) of 25 houses of a certain locality for a month are given below.324, 700, 617, 400, 356, 365, 435, 506, 548, 736, 780, 378, 570, 685, 312, 630, 584, 674, 754, 776, 596, 745, 565, 763, 472. Arrange the above data and form a frequency table using equal class interval from 300 – 400. Answer the following questions. i) In which class interval 700 is included? ii) Which class has the lowest frequency? iii) How many houses are paying the electricity bills ranging from ₹ 600 to ₹ 800? iv) What is the upper limit of the class interval 700 – 800?

Answer»

ANSWER:

1000708379is CORRECT answer PLEASE follow up with click THANKS

Discussion

28.	How many millions have there in 10 crore
Answer» 100 MILLIONS = 10 CRORE.

Discussion

29.	Petrol and diesel are mixed in two vesselsA and B in the ratio 4:3 and 2:3respectively. In what ratio, should Petroland Diesel mixed in these vessels bemixed again to obtain a new mixture inVessel C so that the mixture contains halfpetrol and half diesel?7:45:37:52:5
Answer» Step-by-step EXPLANATION: ASK me if any DOUBT.....

29.

Petrol and diesel are mixed in two vesselsA and B in the ratio 4:3 and 2:3respectively. In what ratio, should Petroland Diesel mixed in these vessels bemixed again to obtain a new mixture inVessel C so that the mixture contains halfpetrol and half diesel?7:45:37:52:5

Answer»

Step-by-step EXPLANATION:

ASK me if any DOUBT.....

Discussion

30.	Find all the zeros of the polynomial f(x)=2x²-3x²-6x-2 if two of its zero are √2 and -√2
Answer» SINCE 2 ZEROS are √2 and-√2, (x-√2)(x+√2)=x^2 -2 is a factor of given polynomial. Now, we divide the given polynomial by x^2-2. We get, 2x^2-3x+1 Then factorise the 2x^2 -3x+1 So we get, (2x-1)(x-1) So it's ZERO are given by x=1/2 and x=1. Therefore, the zeros of given polynomial are √2,-√2,1/2 and 1.

30.

Find all the zeros of the polynomial f(x)=2x²-3x²-6x-2 if two of its zero are √2 and -√2

Answer»

SINCE 2 ZEROS are √2 and-√2, (x-√2)(x+√2)=x^2 -2 is a factor of given polynomial. Now, we divide the given polynomial by x^2-2.

We get, 2x^2-3x+1

Then factorise the 2x^2 -3x+1

So we get, (2x-1)(x-1)

So it's ZERO are given by x=1/2 and x=1.

Therefore, the zeros of given polynomial are √2,-√2,1/2 and 1.

Discussion

31.	Answer it...............
Answer» Answer: 0.2 Step-by-step explanation: F(4/3)= 6(4/3)³ - 11(4/3)² +a(4/3)20 0=6(64/27) - 11(16/9) + a(80/3) 0=(128/9)-(176/9)+80a/3 0=128-176+240a 0= -48 + 240a 48=240a 48/240=a a=0.2

31.

Answer it...............

Answer»

Answer:

0.2

Step-by-step explanation:

F(4/3)= 6(4/3)³ - 11(4/3)² +a(4/3)20

0=6(64/27) - 11(16/9) + a(80/3)

0=(128/9)-(176/9)+80a/3

0=128-176+240a

0= -48 + 240a

48=240a

48/240=a

a=0.2

Discussion

32.	The perimeter of a rectangle is 250 cm and its breadth is 50 cm find its area
Answer» Answer: LENGTH is 75cm area=3750sq.cm Step-by-step EXPLANATION: So area =L ×b 50×75 =3750sq.cm

32.

The perimeter of a rectangle is 250 cm and its breadth is 50 cm find its area

Answer»

Answer:

LENGTH is 75cm area=3750sq.cm

Step-by-step EXPLANATION:

So area =L ×b

50×75

=3750sq.cm

Discussion

33.	If the sum of n terms and 2 AP are in the ratio 3n + 5 ratio 5n+ 7 then there and nth term are in the ratio
Answer» Answer: In the ratio 3n + 5 : 5n + 7, if you put the value of n as 2N - 1, then you'll GET the ratio of nth TERMS. So this is the answer. So remember this that, if the ratio of SUMS of two APs are in the ratio an + b : cn + d, then put the value of n as 2k - 1 to find the ratio of kth terms.

33.

If the sum of n terms and 2 AP are in the ratio 3n + 5 ratio 5n+ 7 then there and nth term are in the ratio

Answer»

Answer:

In the ratio 3n + 5 : 5n + 7, if you put the value of n as 2N - 1, then you'll GET the ratio of nth TERMS. So this is the answer. So remember this that, if the ratio of SUMS of two APs are in the ratio an + b : cn + d, then put the value of n as 2k - 1 to find the ratio of kth terms.

Discussion

34.	4) How many circles can be drawn through two given points?a) oneb) twoc) none
Answer» Answer: Infinite number of circles can be drawn from two POINTS. Starting from the two points as a diameter, we can draw a circle. As the circle is MOVING up it becomes a CHORD to the next circle with bigger diameter. In such a way, we can draw infinite number of circles passing through two points. Step-by-step explanation: plz MARK it BEST

34.

4) How many circles can be drawn through two given points?a) oneb) twoc) none

Answer»

Answer:

Infinite number of circles can be drawn from two POINTS.

Starting from the two points as a diameter, we can draw a circle. As the circle is MOVING up it becomes a CHORD to the next circle with bigger diameter. In such a way, we can draw infinite number of circles passing through two points.

Step-by-step explanation:

plz MARK it BEST

Discussion

35.	What should be divided by (-7) to obtain 12?
Answer» 12 *-7 = -84 PLEASE MARK ME AS BRAINLIEST

35.

What should be divided by (-7) to obtain 12?

Answer»

12 *-7 = -84

PLEASE MARK ME AS BRAINLIEST

Discussion

36.	Solve the equation adx² -(ab-cd)x =bc
Answer» Answer: (a) The given EQUATION can be re written as Σax-Σ a 2 = 2Σbc or xΣ a = Σ a 2 + 2Σbc or xΣa = (Σ a) 2 or Σa (X - Σa) = 0 ∴ x=Σa=a+b+c, provided a + b + c  = 0 (b) L.H.S. = x−a−b x 2 −ax−bx+ab = x−a−b x(x−a−b) + x−a−b ab =x+ x−a−b ab ∴ x−a−b ab = x−c−d CD or ab (x-c + d) = cd (x- a-b) ac(b-a) + bd(a - c) or x= ab−cd ac(b−d)+bd(a−c) Step-by-step explanation:

36.

Solve the equation adx² -(ab-cd)x =bc

Answer»

Answer:

(a) The given EQUATION can be re written as

Σax-Σ a

2

= 2Σbc

or xΣ a = Σ a

2

+ 2Σbc

or xΣa = (Σ a)

2

or Σa (X - Σa) = 0

∴ x=Σa=a+b+c,

provided a + b + c



= 0

(b) L.H.S. =

x−a−b

x

2

−ax−bx+ab

=

x−a−b

x(x−a−b)

+

x−a−b

ab

=x+

x−a−b

ab

∴

x−a−b

ab

=

x−c−d

CD

or ab (x-c + d) = cd (x- a-b)

ac(b-a) + bd(a - c)

or x=

ab−cd

ac(b−d)+bd(a−c)

Step-by-step explanation:

Discussion

37.	Simplify 480÷20of [40-{21+(36÷6+3)}]
Answer» Step-by-step EXPLANATION: MARK as BRAINLIEST and FOLLOW me

37.

Simplify 480÷20of [40-{21+(36÷6+3)}]

Answer»

Step-by-step EXPLANATION:

MARK as BRAINLIEST and FOLLOW me

Discussion

38.	Area of trapezium formula
Answer» ANSWER: 1/2 × sum of PARALLEL sides × HEIGHT I HOPE you LIKE my answer PLZ MARK ME AS A BRAINLIST

38.

Area of trapezium formula

Answer»

ANSWER:

1/2 × sum of PARALLEL sides × HEIGHT

I HOPE you LIKE my answer

PLZ MARK ME AS A BRAINLIST

Discussion

39.	Can somebody solve the riemann hypothesis
Answer» Answer: Over the past few DAYS, the mathematics world has been abuzz that Sir MICHAEL Atiyah, the famous Fields Medalist and ABEL Prize winner, may have SOLVED the Riemann hypothesis. If his proof turns out to be correct, this would be one of the most important mathematical achievements in many years. hope it helps u

39.

Can somebody solve the riemann hypothesis

Answer»

Answer:

Over the past few DAYS, the mathematics world has been abuzz that Sir MICHAEL Atiyah, the famous Fields Medalist and ABEL Prize winner, may have SOLVED the Riemann hypothesis. If his proof turns out to be correct, this would be one of the most important mathematical achievements in many years.

hope it helps u

Discussion

40.	Fast fast fast fast fast fast
Answer» HOPE the SOLUTION HELPS you. .....!

40.

Fast fast fast fast fast fast

Answer»

HOPE the SOLUTION HELPS you. .....!

Discussion

41.	2. The measures of some angles are givenbelow. Write the type of each angle.(1) 75°(3) 215°(5) 180°(7) 148°(2) 0°(4) 360°(6) 120°(8) 90°and one more question
Answer» Answer: 1.acute ANGLE 3.reflex angle 5.obtuse angle 7.obtuse angle 2.cant FORM angle with this measurement 4.straight angle 6.obtuse angle 8.right angle

41.

2. The measures of some angles are givenbelow. Write the type of each angle.(1) 75°(3) 215°(5) 180°(7) 148°(2) 0°(4) 360°(6) 120°(8) 90°and one more question

Answer»

Answer:

1.acute ANGLE

3.reflex angle

5.obtuse angle

7.obtuse angle

2.cant FORM angle with this measurement

4.straight angle

6.obtuse angle

8.right angle

Discussion

42.	In the given numbers select the largest number255370253072570325730
Answer» Answer: 255370 Step-by-step explanation: 255370 have 6 DIGIT

42.

In the given numbers select the largest number255370253072570325730

Answer»

Answer:

255370

Step-by-step explanation:

255370 have 6 DIGIT

Discussion

43.	Find 10 rational numbers between -3/4 and 5/6
Answer» Step-by-step EXPLANATION: find 10 rational numbers between -3/4 and 5/6https://brainly.in/question/17735617 I HOPE it will help you mark me as a BRAINLIEST

43.

Find 10 rational numbers between -3/4 and 5/6

Answer»

Step-by-step EXPLANATION:

find 10 rational numbers between -3/4 and 5/6https://brainly.in/question/17735617

I HOPE it will help you

mark me as a BRAINLIEST

Discussion

44.	3 A and B enter into a partnership contributing 800 and 1000respectively for 3 years. At the end of 6 months of the first they admit C who contributes 600. Find the share of each partner if the total profit is 966.
Answer» ANSWER: i DONT KNOW SORRY.......

44.

3 A and B enter into a partnership contributing 800 and 1000respectively for 3 years. At the end of 6 months of the first they admit C who contributes 600. Find the share of each partner if the total profit is 966.

Answer»

ANSWER:

i DONT KNOW SORRY.......

Discussion

45.	In a two digit number, the sum of the two digits is 9.If the digit in the tenth place is increased by 3 then number so formed is 5/3 of the original number .What is the number?
Answer» ANSWER: Step-by-step EXPLANATION: the NUMBER is 100

45.

In a two digit number, the sum of the two digits is 9.If the digit in the tenth place is increased by 3 then number so formed is 5/3 of the original number .What is the number?

Answer»

ANSWER:

Step-by-step EXPLANATION:

the NUMBER is 100

Discussion

46.	Find the square root corrected upto decimal places 19.6
Answer» Answer: 19.10 Step-by-step EXPLANATION: GIVE it BRAINLIEST ANS. PLZ.

46.

Find the square root corrected upto decimal places 19.6

Answer»

Answer:

19.10

Step-by-step EXPLANATION:

GIVE it BRAINLIEST ANS. PLZ.

Discussion

47.	If x coordinates of a point is zero then this point always lies on
Answer» ANSWER: HEY MATE your answer is y-*axis*

47.

If x coordinates of a point is zero then this point always lies on

Answer»

ANSWER:

HEY MATE your answer is y-axis

Discussion

48.	1. Match the following.Measure of Type of anglethe angle(1) 180°(a) Zero angle(2) 240°(b) Straight angle(3) 360°(c) Reflex angle(4) 0°(d) Complete anglecan you tell me this ans
Answer» Answer: 1.) - B 2.) - c 3.) - d 4.) - a

48.

1. Match the following.Measure of Type of anglethe angle(1) 180°(a) Zero angle(2) 240°(b) Straight angle(3) 360°(c) Reflex angle(4) 0°(d) Complete anglecan you tell me this ans

Answer»

Answer:

1.) - B

2.) - c

3.) - d

4.) - a

Discussion

49.	If x2+2x+1=0 and x2+ax+9=0 has one common root then the value of a is
Answer» Answer: a = 10 Step-by-step explanation: Given a quadratic equation such that, ${x}^{2} + 2x + 1 = 0$ To find it's ROOTS, we NEED to factorise it. Therefore, we will get, $= > {x}^{2} + 2 \times x \times 1 + {1}^{2} = 0 \\ \\ = > {(x + 1)}^{2} = 0 \\ \\ = > x + 1 = 0 \\ \\ = > x = - 1$ Therefore, the root is -1. Now, given ANOTHER quadratic equation, ${x}^{2} + ax + 9 = 0$ But, it's given that, The root of first eqn is also COMMON for the second eqn. Therefore, it will satisfy the second eqn also. Therefore, substituting the value, we get, $= > {( - 1)}^{2} + a( - 1) + 9 = 0 \\ \\ = > 1 - a + 9 = 0 \\ \\ = > 10 - a = 0 \\ \\ = > a = 10$ Hence, required value of a = 10.

49.

If x2+2x+1=0 and x2+ax+9=0 has one common root then the value of a is

Answer»

Answer:

a = 10

Step-by-step explanation:

Given a quadratic equation such that,

${x}^{2} + 2x + 1 = 0$

To find it's ROOTS, we NEED to factorise it.

Therefore, we will get,

$= > {x}^{2} + 2 \times x \times 1 + {1}^{2} = 0 \\ \\ = > {(x + 1)}^{2} = 0 \\ \\ = > x + 1 = 0 \\ \\ = > x = - 1$

Therefore, the root is -1.

Now, given ANOTHER quadratic equation,

${x}^{2} + ax + 9 = 0$

But, it's given that,

The root of first eqn is also COMMON for the second eqn.

Therefore, it will satisfy the second eqn also.

Therefore, substituting the value, we get,

$= > {( - 1)}^{2} + a( - 1) + 9 = 0 \\ \\ = > 1 - a + 9 = 0 \\ \\ = > 10 - a = 0 \\ \\ = > a = 10$

Hence, required value of a = 10.

Discussion

50.	The taxi fare in a city is as follows: For the first kilometer, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. [Taking the distance covered as x km and total fare as Rs y, Tick from the following options its linear equation and some possible solutions.x=5y+3, solutions=(8,1), (53,10), (13,2), (-7,-2)y=3x+5 solutions= (1,8), (2,11), (3,14) (10,35)y=5x+3 solutions= (1,8), (2,13), (3,18) (10,53)None of theseplzz answer urgent
Answer» Answer: option c Step-by-step explanation: total FARE = y total DISTANCE = X distance TRAVELLED after 1 KM = (x-1) km y = 8 + 5 ( x-1) y = 8 + 5x -5 y = 5x + 3

50.

The taxi fare in a city is as follows: For the first kilometer, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. [Taking the distance covered as x km and total fare as Rs y, Tick from the following options its linear equation and some possible solutions.x=5y+3, solutions=(8,1), (53,10), (13,2), (-7,-2)y=3x+5 solutions= (1,8), (2,11), (3,14) (10,35)y=5x+3 solutions= (1,8), (2,13), (3,18) (10,53)None of theseplzz answer urgent

Answer»

Answer:

option c

Step-by-step explanation:

total FARE = y

total DISTANCE = X

distance TRAVELLED after 1 KM = (x-1) km

y = 8 + 5 ( x-1)

y = 8 + 5x -5

y = 5x + 3

Discussion

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