332354 + Interview Questions in Secondary School in Math

1.	Find out the angular distance at 07:30AM
Answer» Step-by-step explanation: DONT ASK ANWERS in this group you are CHEATING I this app cha

1.

Find out the angular distance at 07:30AM

Answer»

Step-by-step explanation:

DONT ASK ANWERS in this group you are CHEATING I this app cha

Discussion

2.	Using57viappropriate propertiesa) 2 x 4 +5-3x42 x4
Answer» ANSWER: THANK you my LOVELY GUYS

2.

Using57viappropriate propertiesa) 2 x 4 +5-3x42 x4

Answer»

ANSWER:

THANK you my LOVELY GUYS

Discussion

3.	Find the sum of -522 and -160
Answer» ANSWER: -682 Step-by-step EXPLANATION: -522+(-160) -522-160 -682 hope it helps U...

3.

Find the sum of -522 and -160

Answer»

ANSWER:

-682

Step-by-step EXPLANATION:

-522+(-160)

-522-160

-682

hope it helps U...

Discussion

4.	6. On a map of scale 1 cm to 250 m the area of a car park is 3 cm². What is the actual area of the car park in hectares? (1 hectare = 10 000 m²)
Answer» ANSWER: you are PAGALE MENTAL STUDENT

4.

6. On a map of scale 1 cm to 250 m the area of a car park is 3 cm². What is the actual area of the car park in hectares? (1 hectare = 10 000 m²)

Answer»

ANSWER:

you are PAGALE MENTAL STUDENT

Discussion

5.	7. Out of 450 students in a school, 193 students read science today, 200 students read Juniorstatesmen, while 80 students read neither. How many students read both the magazines? A) 137B) 80C) 57D) 23
Answer» your ANSWER is: 137 distance your answer

5.

7. Out of 450 students in a school, 193 students read science today, 200 students read Juniorstatesmen, while 80 students read neither. How many students read both the magazines? A) 137B) 80C) 57D) 23

Answer»

your ANSWER is:

137 distance your answer

Discussion

6.	A,B,C,D BE the angles of quadrilateral then tanA +tanB +tanC+tanD/cotA +cotB+cotC+-cotD=?
Answer» Answer: A + B = 2π – (C + D) TAN(A + B) = – tan(C + D) (TANA + tanB)/(1 - tanA tanB) = (- tanC - TAND)/(1 - tanC tanD) tanA – tanA tan C tan D + tan B – tan B tan C tan D = – tanC + tan A tan B tan C – tan D + tan A tan B tan D tan A + tan B + tan C + tan D = tan A tan C tan D + tan B tan C tan D + tan A tan B tan C + tan A tan B tan D = tan A tan B tan C tan D (COT A + cot B + cot C + cot D) ∴ = tan A tan B tan C tan D./if-a-are-the-angles-of-quadrilateral-then-tana-tanb-tanc-tand-cota-cotb-cotc-cotd-is-equal-to Step-by-step explanation:

6.

A,B,C,D BE the angles of quadrilateral then tanA +tanB +tanC+tanD/cotA +cotB+cotC+-cotD=?

Answer»

Answer:

A + B = 2π – (C + D) TAN(A + B) = – tan(C + D) (TANA + tanB)/(1 - tanA tanB) = (- tanC - TAND)/(1 - tanC tanD) tanA – tanA tan C tan D + tan B – tan B tan C tan D = – tanC + tan A tan B tan C – tan D + tan A tan B tan D tan A + tan B + tan C + tan D = tan A tan C tan D + tan B tan C tan D + tan A tan B tan C + tan A tan B tan D = tan A tan B tan C tan D (COT A + cot B + cot C + cot D) ∴ = tan A tan B tan C tan D./if-a-are-the-angles-of-quadrilateral-then-tana-tanb-tanc-tand-cota-cotb-cotc-cotd-is-equal-to

Step-by-step explanation:

Discussion

7.	True or false1)point (3,0) lies in 1 quadrant:2)points (1,-1) and (-1,1) lies in same quadrant
Answer» 1)True 2)False Hpe it HELPS :)

7.

True or false1)point (3,0) lies in 1 quadrant:2)points (1,-1) and (-1,1) lies in same quadrant

Answer»

1)True

2)False

Hpe it HELPS :)

Discussion

8.	Question no. 9???????????
Answer» ANSWER: I THINK so it is (d) does not EXIST

8.

Question no. 9???????????

Answer»

ANSWER:

I THINK so it is (d) does not EXIST

Discussion

9.	Find the quotient when 12√15 is divided by 4√3
Answer» ANSWER: The QUOTIENT is 3 root5 Step-by-step EXPLANATION:

9.

Find the quotient when 12√15 is divided by 4√3

Answer»

ANSWER:

The QUOTIENT is 3 root5

Step-by-step EXPLANATION:

Discussion

10.	In a mixture of 45 litres, the ratio of sugar solution to salt solution is 1:2. What is the amount of sugar solution to be added if the ratio has to be 2:1?
Answer» SOLUTION : *Number of litres of sugar solution in the MIXTURE = (1/(1+2)) 45 = 15 litres. So, 45-15 = 30 litres of salt solution is present in it. Let the QUANTITY of sugar solution to be ADDED be x litres. Setting up the proportion, sugar solution / salt solution = (15+x)/30 = 2/1 → x = 45. Therefore, 45 litres of sugar solution has to be added to bring it to the ratio 2:1.**

10.

In a mixture of 45 litres, the ratio of sugar solution to salt solution is 1:2. What is the amount of sugar solution to be added if the ratio has to be 2:1?

Answer»

SOLUTION :

Number of litres of sugar solution in the MIXTURE = (1/(1+2)) *45 = 15 litres.

So, 45-15 = 30 litres of salt solution is present in it.

Let the QUANTITY of sugar solution to be ADDED be x litres.

Setting up the proportion,

sugar solution / salt solution = (15+x)/30 = 2/1 → x = 45.

Therefore, 45 litres of sugar solution has to be added to bring it to the ratio 2:1.

Discussion

11.	If A and B are two finite sets such that n[P(A)] = n[P(B)] + 992 , n(A) + n(B) is:
Answer» <P>Answer: if A and B are two finite sets such that N[P(A)]=n[P(B)]+992,then FIND n(A)+n(B) Step-by-step EXPLANATION: please mark me as brainliest

11.

If A and B are two finite sets such that n[P(A)] = n[P(B)] + 992 , n(A) + n(B) is:

Answer»

<P>Answer:

if A and B are two finite sets such that N[P(A)]=n[P(B)]+992,then FIND n(A)+n(B)

Step-by-step EXPLANATION:

please mark me as brainliest

Discussion

12.	In a class test (+4) marks are given for every correct answer and (-2) marks are given for every incorrect answer and no marks for not attempting any questions. Amana answered all the questions and scored 30 though she got 10 correct answers.
Answer» Answer: 10×+4=40 mark for CORRECT answer 30 INCORRECT 30×(-2) -60 mark for incorrect answers

12.

In a class test (+4) marks are given for every correct answer and (-2) marks are given for every incorrect answer and no marks for not attempting any questions. Amana answered all the questions and scored 30 though she got 10 correct answers.

Answer»

Answer:

10×+4=40 mark for CORRECT answer

30 INCORRECT

30×(-2)

-60 mark for incorrect answers

Discussion

13.	Draw the coordinate plane with scale
Answer» ANSWER: Step-by-step EXPLANATION: here is your answer

13.

Draw the coordinate plane with scale

Answer»

ANSWER:

Step-by-step EXPLANATION:

here is your answer

Discussion

14.	6. In a community of 175 persons, 40 read the Times, 50 read the Samachar and 100 do not readany. How many persons read both the papers?A) 10B) 15C) 20D) 25
Answer» ANSWER: SINCE 100 do not read any n(T∪S)=175−100=75 By set theory n(T∩S)=n(T)+n(S)−n(T∪S) =40+50−75=15 Step-by-step explanation: MARK ME AS BRAINLIEST !!

14.

6. In a community of 175 persons, 40 read the Times, 50 read the Samachar and 100 do not readany. How many persons read both the papers?A) 10B) 15C) 20D) 25

Answer»

ANSWER:

SINCE 100 do not read any

n(T∪S)=175−100=75

By set theory

n(T∩S)=n(T)+n(S)−n(T∪S)

=40+50−75=15

Step-by-step explanation:

MARK ME AS BRAINLIEST !!

Discussion

15.	Identify the property used in the following: 2 x 13 + 8 x 13 = ( 2+8 ) x 13(a) Commutative (b) Closure (c) Associative (d) Distributive
Answer» ANSWER: COMMUTATIVE and DISTRIBUTIVE PROPERTY

15.

Identify the property used in the following: 2 x 13 + 8 x 13 = ( 2+8 ) x 13(a) Commutative (b) Closure (c) Associative (d) Distributive

Answer»

ANSWER:

COMMUTATIVE and DISTRIBUTIVE PROPERTY

Discussion

16.	Give all integration formulas and differentiation formulas
Answer» Answer: Hii Step-by-step EXPLANATION: ∫ 1 dx = x + C. ∫ a dx = ax+ C. ∫ XN dx = ((xn+1)/(n+1))+C ; n≠1. ∫ SIN x dx = – cos x + C. ∫ cos x dx = sin x + C. ∫ sec2 dx = tan x + C. ∫ csc2 dx = -cot x + C. ∫ sec x (tan x) dx = sec x + C.

16.

Give all integration formulas and differentiation formulas

Answer»

Answer:

Hii

Step-by-step EXPLANATION:

∫ 1 dx = x + C.
∫ a dx = ax+ C.
∫ XN dx = ((xn+1)/(n+1))+C ; n≠1.
∫ SIN x dx = – cos x + C.
∫ cos x dx = sin x + C.
∫ sec2 dx = tan x + C.
∫ csc2 dx = -cot x + C.
∫ sec x (tan x) dx = sec x + C.

Discussion

17.	Help me out guys ..Fast brothers and sisters
Answer» Step-by-step EXPLANATION: Here is your ANSWER HOPE you GET it.

17.

Help me out guys ..Fast brothers and sisters

Answer»

Step-by-step EXPLANATION:

Here is your ANSWER HOPE you GET it.

Discussion

18.	A number is increased by 5 and the resulting number is 15 find the number
Answer» ANSWER: The NUMBER is 10 Step-by-step EXPLANATION:

18.

A number is increased by 5 and the resulting number is 15 find the number

Answer»

ANSWER:

The NUMBER is 10

Step-by-step EXPLANATION:

Discussion

19.	for some integer q , every odd integer is of the form
Answer» ANSWER: p/q is the answer......

19.

for some integer q , every odd integer is of the form

Answer»

ANSWER:

p/q is the answer......

Discussion

20.	Multiply-9/16 by the multiplicativeinverse of 15/36
Answer» ANSWER IS ATTACHED .............................!

Discussion

21.	1 point2. Which of the following isirrational? *0.14O O0.4014001400014....O0.250.41
Answer» ANSWER: 0.4014001400014..... is the answer

21.

1 point2. Which of the following isirrational? *0.14O O0.4014001400014....O0.250.41

Answer»

ANSWER:

0.4014001400014.....

is the answer

Discussion

22.	divide rs.3010 among A B C in such a way that A gets double of what B gets and B gets double of what C gets
Answer» Given :- TOTAL amount distributed AMONG A, B & C = Rs. 3010 Total amount A gets = twice the amount B gets. Total amount B gets = twice the amount C gets. To FIND :- Total amount A, B & C will GET separately. Solution :- Suppose Rs. x be the total amount C will get. Then, Total amount B will get = Rs. 2x (twice the amount of C). Total amount A will get = Rs. 4x (twice the amount of B). ACCORDING to the question, ⇒ 4x + 2x + x = 3010 ⇒ 7x = 3010 ⇒ x = 3010/7 ⇒ x = 430 Therefore, C will get Rs. 430. Also, B will get = Rs. 860 ( 2 × 430) A will get = Rs. 1720 ( 2 × 860)

22.

divide rs.3010 among A B C in such a way that A gets double of what B gets and B gets double of what C gets

Answer»

Given :-

TOTAL amount distributed AMONG A, B & C = Rs. 3010
Total amount A gets = twice the amount B gets.
Total amount B gets = twice the amount C gets.

To FIND :-

Total amount A, B & C will GET separately.

Solution :-

Suppose Rs. x be the total amount C will get. Then,

Total amount B will get = Rs. 2x (twice the amount of C).
Total amount A will get = Rs. 4x (twice the amount of B).

ACCORDING to the question,

⇒ 4x + 2x + x = 3010

⇒ 7x = 3010

⇒ x = 3010/7

⇒ x = 430

Therefore, C will get Rs. 430.

Also,

B will get = Rs. 860 ( 2 × 430)
A will get = Rs. 1720 ( 2 × 860)

Discussion

23.	Give all integration formulas
Answer» Answer: ∫X n = x n+1 /n+1 + C. ∫cos x = sin x + C. ∫sin x = -cos x + C. ∫sec 2 x = TAN x + C. ∫cosec 2 x = -cot x + C. ∫sec x tan x = sec x + C. ∫cosec x cot x = -cosec x + C. ∫dx/√ 1- x 2 = sin -1 x + C. Step-by-step explanation: mark it has brainlist and PLEASE follow me

23.

Give all integration formulas

Answer»

Answer:

∫X n = x n+1 /n+1 + C.

∫cos x = sin x + C.

∫sin x = -cos x + C.

∫sec 2 x = TAN x + C.

∫cosec 2 x = -cot x + C.

∫sec x tan x = sec x + C.

∫cosec x cot x = -cosec x + C.

∫dx/√ 1- x 2 = sin -1 x + C.

Step-by-step explanation:

mark it has brainlist and PLEASE follow me

Discussion

24.	Pls. give the correct answer fast
Answer» PLEASE MARK as BRAINLIEST

24.

Pls. give the correct answer fast

Answer»

PLEASE MARK as BRAINLIEST

Discussion

25.	Find the value of-(-5/8+7/20)
Answer» $\frac{ - 5}{8} + \frac{7}{20}$ $= \frac{ - 25 + 14}{40}$ $= \frac{ - 11}{40}$ $= 0.275$ HOPE it will HELP you

25.

Find the value of-(-5/8+7/20)

Answer»

$\frac{ - 5}{8} + \frac{7}{20}$

$= \frac{ - 25 + 14}{40}$

$= \frac{ - 11}{40}$

$= 0.275$

HOPE it will HELP you

Discussion

26.	If p (x) =x square-2x-3 ,then find the value of p(3) +p(-1)+p(2)
Answer» ANSWER: $- 3$ Step-by-step EXPLANATION: $p(x) = {x}^{2} - 2x - 3 \\ \\ p(3) = {3}^{2} - 2(3) - 3 = 9 - 6 - 3 = 0 \\ \\ p( - 1) = {( - 1)}^{2} - 2( - 1) - 3 = 2 + 1 - 3 = 0 \\ \\ p(2) = {2}^{2} - 2(2) - 3 = 4 - 4 - 3 = - 3 \\ \\ now \\ \\ p(3) + p( - 1) + p(2) = - 3 \\ \\$ HOPE it HELPS

26.

If p (x) =x square-2x-3 ,then find the value of p(3) +p(-1)+p(2)

Answer»

ANSWER:

$- 3$

Step-by-step EXPLANATION:

$p(x) = {x}^{2} - 2x - 3 \\ \\ p(3) = {3}^{2} - 2(3) - 3 = 9 - 6 - 3 = 0 \\ \\ p( - 1) = {( - 1)}^{2} - 2( - 1) - 3 = 2 + 1 - 3 = 0 \\ \\ p(2) = {2}^{2} - 2(2) - 3 = 4 - 4 - 3 = - 3 \\ \\ now \\ \\ p(3) + p( - 1) + p(2) = - 3 \\ \\$

HOPE it HELPS

Discussion

27.	Please prove it................
Answer» Answer: Step-by-step explanation: To write a letter showing proof of residence for a tenant, ask the tenant who you're addressing the letter to and what SPECIFIC details to include. OPEN the letter with a simple salutation LIKE, "To Whom It May Concern," and state that you're writing to verify that the tenants LIVE on your PROPERTY.

27.

Please prove it................

Answer»

Answer:

Step-by-step explanation:

To write a letter showing proof of residence for a tenant, ask the tenant who you're addressing the letter to and what SPECIFIC details to include. OPEN the letter with a simple salutation LIKE, "To Whom It May Concern," and state that you're writing to verify that the tenants LIVE on your PROPERTY.

Discussion

28.	Compound interest on a certain amount for 2 years at 8%p.a. is ₹312 . What will be the simple interest on the same amount,at same rate and same time?
Answer» Answer: Let P=100, TIME (n)=3 years, Rate (r)=8% AMOUNT =P(1+ 100 r ) 3 =100(1+ 100 8 ) 3 =100×1.08×1.08×1.08 =126 CI =A−P=126−100=26 Now, SIMPLE Interest = 100 PTR = 100 (100×3×8) =24 Difference =26−24=2 CI more than SI = 24 (2×100) =8.33%

28.

Compound interest on a certain amount for 2 years at 8%p.a. is ₹312 . What will be the simple interest on the same amount,at same rate and same time?

Answer»

Answer:

Let P=100, TIME (n)=3 years, Rate (r)=8%

AMOUNT =P(1+

100

r

)

3

=100(1+

100

8

)

3

=100×1.08×1.08×1.08

=126

CI =A−P=126−100=26

Now, SIMPLE Interest =

100

PTR

=

100

(100×3×8)

=24

Difference =26−24=2

CI more than SI =

24

(2×100)

=8.33%

Discussion

29.	Factorise 1 - 64a^3 - 12a + 48a^2
Answer» Answer: The given EQ is in TBE form of a^3-b^3-3a^2b+3ab^2 =>1-(4a)^3-31(4a)+31(4a)^2 =>(1-4a)^3 Step-by-step explanation:*

29.

Factorise 1 - 64a^3 - 12a + 48a^2

Answer»

Answer:

The given EQ is in TBE form of a^3-b^3-3a^2b+3ab^2

=>1-(4a)^3-3*1*(4a)+3*1(4a)^2

=>(1-4a)^3

Step-by-step explanation:

Discussion

30.	If x = 2 + √3, find the value of 1/x
Answer» ANSWER: $2 - \sqrt{3}$ Step-by-step EXPLANATION: HOPE its HELP you i do it by rationalitation

30.

If x = 2 + √3, find the value of 1/x

Answer»

ANSWER:

$2 - \sqrt{3}$

Step-by-step EXPLANATION:

HOPE its HELP you i do it by rationalitation

Discussion

31.	74×95= 74×100-74×__please tell
Answer» Answer: 5 Step-by-step explanation: 74x100 - 74x A = 74x95 or, 74x(100-A) = 74x95 or, 100-A= 95 or, A=100-95 or, A=5

31.

74×95= 74×100-74×__please tell

Answer»

Answer:

5

Step-by-step explanation:

74x100 - 74x A = 74x95

or, 74x(100-A) = 74x95

or, 100-A= 95

or, A=100-95

or, A=5

Discussion

32.	Prove that(1+cot theeta-cosec theeta) (1+tan theeta+sec theeta)=2
Answer» Step-by-step EXPLANATION: HOPE it's HELPFUL for you if helpful MARK as BRAINLIEST

32.

Prove that(1+cot theeta-cosec theeta) (1+tan theeta+sec theeta)=2

Answer»

Step-by-step EXPLANATION:

HOPE it's HELPFUL for you

if helpful MARK as BRAINLIEST

Discussion

33.	Simplify -7/10 + 13/15 + 27/50 hey guys ! whoever know this answer please give it the answer in fraction
Answer» Answer: 53/75 Step-by-step EXPLANATION:

33.

Simplify -7/10 + 13/15 + 27/50 hey guys ! whoever know this answer please give it the answer in fraction

Answer»

Answer:

53/75

Step-by-step EXPLANATION:

Discussion

34.	I want answers fastly
Answer» ANSWER: Q.1 - (C) and (a) is in one variable because it is a linear equation and the others are not in one variable because the X and y are never in root

34.

I want answers fastly

Answer»

ANSWER:

Q.1 - (C) and (a) is in one variable because it is a linear equation

and the others are not in one variable because the X and y are never in root

Discussion

35.	गुणनखंड ज्ञात करें x(x+1)(x+2)(x+3)/x(x+1)
Answer» Step-by-step EXPLANATION: x²+x+x+2+x+3 x+x+x+2+3+x²=3x+5+x² 3x+5+x²/x=3x+5+x=4x+5 4x+5+x+1=5x+6

35.

गुणनखंड ज्ञात करें x(x+1)(x+2)(x+3)/x(x+1)

Answer»

Step-by-step EXPLANATION:

x²+x+x+2+x+3

x+x+x+2+3+x²=3x+5+x²

3x+5+x²/x=3x+5+x=4x+5

4x+5+x+1=5x+6

Discussion

36.	Find a single discount equivalent to the discount series of 5 percent, 15 percent, and 25 Percent?
Answer» Answer: CONSIDER 100/- A DISCOUNT of 10% would save you 10/-, leaving you with 90/- Another discount, of 15% this time would be on 90/- 90 x 15/100 = 13.5. Hence money LEFT is (90-13.5) = 76.5 Now, a discount of 20% on 76.5/- = 76.5 x 20/100 = 15.3/- Hence total discount = sum of total money saved(in this scenario when you work with base 100/-) = 15.3 + 13.5 + 10 = 38.8 = 38.8% of the ORIGINAL price. Hence the discount is 38.8% ATTACHMENT is not for u)

36.

Find a single discount equivalent to the discount series of 5 percent, 15 percent, and 25 Percent?

Answer»

Answer:

CONSIDER 100/-

A DISCOUNT of 10% would save you 10/-, leaving you with 90/-

Another discount, of 15% this time would be on 90/-

90 x 15/100 = 13.5. Hence money LEFT is (90-13.5) = 76.5

Now, a discount of 20% on 76.5/- = 76.5 x 20/100 = 15.3/-

Hence total discount = sum of total money saved(in this scenario when you work with base 100/-)

= 15.3 + 13.5 + 10

= 38.8

= 38.8% of the ORIGINAL price.

Hence the discount is 38.8%

ATTACHMENT is not for u)

Discussion

37.	The discriminant of the quadratic equation 3x^2-4x-2=0 is equal to
Answer» $\huge\purple{\underline{\underline{\pink{Ans}\red{wer:}}}}$ $\sf{The \ value \ of \ Discriminant \ is \ 30.}$ $\sf\blue{Explanation:}$ $\sf{Discriminant (\Delta)=b^{2}-4ac}$ $\sf{If, \Delta>0 \ Roots \ are \ real \ and \ distinct.}$ $\sf{\Delta=0 \ Roots \ are \ real \ and \ equal.}$ $\sf{\Delta$ $\sf\orange{Given:}$ $\sf{The \ quadratic \ equation \ is}$ $\sf{\implies{3x^{2}-4x-2=0}}$ $\sf\purple{To \ find:}$ $\sf{The \ value \ of \ Discriminant.}$ $\sf\green{\underline{\underline{Solution:}}}$ $\sf{The \ quadratic \ equation \ is}$ $\sf{\implies{3x^{2}-4x-2=0}}$ $\sf{Here, \ a=3, \ b=-4 \ and \ c=-2}$ $\sf{Discriminant (\Delta)=b^{2}-4ac}$ $\sf{\implies{\Delta=(-4)^{2}-4(3)(-2)}}$ $\sf{\implies{\Delta=16+24}}$ $\sf{\implies{\Delta=30}}$ $\sf\purple{\tt{\therefore{The \ value \ of \ Discriminant \ is \ 30.}}}$

37.

The discriminant of the quadratic equation 3x^2-4x-2=0 is equal to

Answer»

$\huge\purple{\underline{\underline{\pink{Ans}\red{wer:}}}}$

$\sf{The \ value \ of \ Discriminant \ is \ 30.}$

$\sf\blue{Explanation:}$

$\sf{Discriminant (\Delta)=b^{2}-4ac}$

$\sf{If, \Delta>0 \ Roots \ are \ real \ and \ distinct.}$

$\sf{\Delta=0 \ Roots \ are \ real \ and \ equal.}$

$\sf{\Delta$

$\sf\orange{Given:}$

$\sf{The \ quadratic \ equation \ is}$

$\sf{\implies{3x^{2}-4x-2=0}}$

$\sf\purple{To \ find:}$

$\sf{The \ value \ of \ Discriminant.}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{The \ quadratic \ equation \ is}$

$\sf{\implies{3x^{2}-4x-2=0}}$

$\sf{Here, \ a=3, \ b=-4 \ and \ c=-2}$

$\sf{Discriminant (\Delta)=b^{2}-4ac}$

$\sf{\implies{\Delta=(-4)^{2}-4(3)(-2)}}$

$\sf{\implies{\Delta=16+24}}$

$\sf{\implies{\Delta=30}}$

$\sf\purple{\tt{\therefore{The \ value \ of \ Discriminant \ is \ 30.}}}$

Discussion

38.	Which avem-4419of thethe Ap - 5, 9, -13, -7 ... is-141
Answer» ANSWER: Here, a= -5, b = -9(correctly). So, d = -4 Now, an = -141 => -5+(N-1)(-4) = -141 => -4n-1 = -141 => n = 35 Hence, 35th term is -141

38.

Which avem-4419of thethe Ap - 5, 9, -13, -7 ... is-141

Answer»

ANSWER:

Here, a= -5, b = -9(correctly). So, d = -4

Now, an = -141

=> -5+(N-1)(-4) = -141

=> -4n-1 = -141

=> n = 35

Hence, 35th term is -141

Discussion

39.	Degree of polynomial (xcube -2)(xsquare +11)
Answer» Answer: degree is 3 pls LIKE and subscribe YOUTUBE channel shlok THAKKAR

39.

Degree of polynomial (xcube -2)(xsquare +11)

Answer»

Answer:

degree is 3

pls LIKE and subscribe YOUTUBE channel shlok THAKKAR

Discussion

40.	गुणनखंड ज्ञात करेंx(x+1)(x+2)(x+3)/x(x+1)
Answer» MATH HINDI BANGALORE anepali

Discussion

41.	A pair of shoes was sild at Rs 840 after giving a discount of 16%.find its marked price
Answer» Step-by-step EXPLANATION: The ANSWER is RS. 974.4/-

41.

A pair of shoes was sild at Rs 840 after giving a discount of 16%.find its marked price

Answer»

Step-by-step EXPLANATION:

The ANSWER is RS. 974.4/-

Discussion

42.	What is the value of √10 X √5
Answer» ANSWER: √50 is the answer please FOLLOW me and MARK as BRAINLIEST plz plz I need it plz

42.

What is the value of √10 X √5

Answer»

ANSWER:

√50 is the answer

please FOLLOW me and MARK as BRAINLIEST plz plz I need it plz

Discussion

43.	Integerशामिलहड़कंपककी मौतnegalएथाना प्रभारीThe productBA
Answer» Step-by-step EXPLANATION: yeeuororour9ru0rouruoryd ukduo

43.

Integerशामिलहड़कंपककी मौतnegalएथाना प्रभारीThe productBA

Answer»

Step-by-step EXPLANATION:

yeeuororour9ru0rouruoryd
ukduo

Discussion

44.	Evaluate sin26'÷cos 64
Answer» $\huge\bf\red{Answer}$ $\implies \frac {sin26°}{cos64°} \\ \implies \frac{sin90-26}{sin64} \\ \implies \frac{sin64°}{sin64°} (both\: cancel\:out\:by\:itself)\\ \implies 1$

44.

Evaluate sin26'÷cos 64

Answer»

$\huge\bf\red{Answer}$

$\implies \frac {sin26°}{cos64°} \\ \implies \frac{sin90-26}{sin64} \\ \implies \frac{sin64°}{sin64°} (both\: cancel\:out\:by\:itself)\\ \implies 1$

Discussion

45.	Solve 235×998 with suitable identity
Answer» Answer: 2,34,530 CLOSURE PROPERTY under MULTIPLICATION

45.

Solve 235×998 with suitable identity

Answer»

Answer:

2,34,530 CLOSURE PROPERTY under MULTIPLICATION

Discussion

46.	Let be the set of all pairs (, ) of real numbers and let be the field of realnumbers. Define (1, 1) + (2, 2) = (1, 1) and (1, 1) = ( 1, 1) ∀ (1, 1), (2, 2) ∈ and ∈ Examine with these operations whether is a vector space over the field of real numbers or not?
Answer» ANSWER: yes I can tell you that it answer is wrong but I can tell you again that it equation is too much long the BRAINLY APP for given you brainly ANSWERS all list you can search all this Step-by-step explanation: I cannot EXPLAIN it question

46.

Let be the set of all pairs (, ) of real numbers and let be the field of realnumbers. Define (1, 1) + (2, 2) = (1, 1) and (1, 1) = ( 1, 1) ∀ (1, 1), (2, 2) ∈ and ∈ Examine with these operations whether is a vector space over the field of real numbers or not?

Answer»

ANSWER:

yes I can tell you that it answer is wrong but I can tell you again that it equation is too much long the BRAINLY APP for given you brainly ANSWERS all list you can search all this

Step-by-step explanation:

I cannot EXPLAIN it question

Discussion

47.	2. Write a Pythagorean triplet whose one member is.(1) 14
Answer» Step-by-step EXPLANATION: hope you GOT the answer PLEASE MAKE me BRAINIST

47.

2. Write a Pythagorean triplet whose one member is.(1) 14

Answer»

Step-by-step EXPLANATION:

hope you GOT the answer PLEASE MAKE me BRAINIST

Discussion

48.	Write Definition of Line, Line segment, Parallel lines, interesting line ,Ray,,Radius, and square, and send to me one by one
Answer» ANSWER: line: which has no END points line segment: which has end points intersecting: when two lines meet at a place is called intersecting point Ray: which has only ONE end point radius:the line which is HALF in the middle of the circle square:in a figure where all sides are equal mark me as brianalist

48.

Write Definition of Line, Line segment, Parallel lines, interesting line ,Ray,,Radius, and square, and send to me one by one

Answer»

ANSWER:

line: which has no END points

line segment: which has end points

intersecting: when two lines meet at a place is called intersecting point

Ray: which has only ONE end point

radius:the line which is HALF in the middle of the circle

square:in a figure where all sides are equal

mark me as brianalist

Discussion

49.	Toss a coin 50times and record the data. Find the number of times heads and tails occur init. Then find the probability of occurring head and tail.
Answer» ANSWER: is this the COMPLETE QUESTION

49.

Toss a coin 50times and record the data. Find the number of times heads and tails occur init. Then find the probability of occurring head and tail.

Answer»

ANSWER:

is this the COMPLETE QUESTION

Discussion

50.	Show that ( - 8 by 9 * 1 by 5 )+( - 8 by 9 * 7 by 11 )is equal to 8 by 9+(1 by 5 + 7 by 11)
Answer» L.H.S =((-8/9)(1/5))+((18/9)(7/11)) =(-8/45)+(136/99) solve further RHS =8/9+(1/5+7/11) =8/9+46/55 SOLVE further

50.

Show that ( - 8 by 9 * 1 by 5 )+( - 8 by 9 * 7 by 11 )is equal to 8 by 9+(1 by 5 + 7 by 11)

Answer»

L.H.S

=((-8/9)*(1/5))+((18/9)*(7/11))

=(-8/45)+(136/99)

solve further

RHS

=8/9+(1/5+7/11)

=8/9+46/55

SOLVE further

Discussion

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