332354 + Interview Questions in Secondary School in Math

1.	O 00:45:40GOVINDWAD SUJAL VYANKATQuestion 9 :FindÂ theÂ PrincipalÂ ValueÂ ofÂ sin 'ÂÂ (2
Answer» ANSWER:hO 00:45:40 GOVINDWAD SUJAL VYANKAT Question 9 : FindÂ theÂ PrincipalÂ ValueÂ ofÂ SIN 'Â Â ( 2 Step-by-step explanation:

1.

O 00:45:40GOVINDWAD SUJAL VYANKATQuestion 9 :FindÂ theÂ PrincipalÂ ValueÂ ofÂ sin 'ÂÂ (2

Answer»

ANSWER:hO 00:45:40

GOVINDWAD SUJAL VYANKAT

Question 9 :

FindÂ theÂ PrincipalÂ ValueÂ ofÂ SIN 'Â

Â (

2

Step-by-step explanation:

Discussion

2.	Writetrueorfalse(i)Thecubecancastashadowintheshapeofasquare.(ii)Thecubecancastashadowintheshapeofahexagon.
Answer» ANSWER: false true Step-by-step EXPLANATION: (✯ᴗ✯)(✯ᴗ✯)(✯ᴗ✯)

2.

Writetrueorfalse(i)Thecubecancastashadowintheshapeofasquare.(ii)Thecubecancastashadowintheshapeofahexagon.

Answer»

ANSWER:

false
true

Step-by-step EXPLANATION:

(✯ᴗ✯)(✯ᴗ✯)(✯ᴗ✯)

Discussion

3.	8. The equation of a straight line passing through the point (2,-7) and parallel tox-axis is(a) x = 2(c) y-7(b) x -7(d) y 2
Answer» Correct Statement is The equation of a straight line passing through the point (2,-7) and parallel to x-axis is (a) x = 2 (c) y = - 7 (b) x = 7 (d) y = 2 $\large\underline{\sf{Given- }}$ A line passes through the point (2, - 7) and parallel to x- axis. $\large\underline{\sf{To\:Find - }}$ Equation of line. Concept Used :- Slope - point form of a line Let us assume a line which passes through the point (a, b) and having slope 'm', then equation of line is $\sf \: y - b \: = \: m(x - a)$ $\large\underline{\sf{Solution-}}$ Given that A line passes through the point (2, - 7) and parallel to x - axis. SINCE, Line is parallel to x- axis. $\rm :\implies\:m \: = \: 0$ Now, We know that Equation of line is given by $\rm :\longmapsto\:y - b \: = \: m(x - a)$ where, $\rm :\longmapsto\:a \: = \: 2$ $\rm :\longmapsto\:b \: = \: - \: 7$ $\rm :\longmapsto\:m \: = \: 0$ On substituting all these values in above equation, we get $\rm :\longmapsto\:y \: - \: ( - 7) = 0 \times (x - 2)$ $\rm :\longmapsto\:y + 7 = 0$ $\rm :\implies\:y \: = \: - \: 7$ $\overbrace{ \underline { \boxed { \rm \therefore The \: equation \: of \: line \: is \: y \: = \: - \: 7}}}$ ─━─━─━─━─━─━─━─━─━─━─━─━─ Additional Information Different forms of equations of a straight line 1. Equations of HORIZONTAL and vertical lines Equation of the lines which are horizontal or parallel to the X-axis is y = a, where a is the y – coordinate of the points on the line. Similarly, equation of a straight line which is vertical or parallel to Y-axis is x = a, where a is the x-coordinate of the points on the line. 2. Point-slope form equation of line Consider a non-vertical line L whose slope is m, A(x,y) be an arbitrary point on the line and P(a, b) be the fixed point on the same line. Equation of line is given by y - b = m(x - a) 3. Slope-intercept form equation of line Consider a line whose slope is m which cuts the Y-axis at a DISTANCE ‘a’ from the origin. Then the distance a is called the y– intercept of the line. The point at which the line cuts y-axis will be (0,a). Then equation of line is given by y = mx + a. 4. Intercept Form of Line Consider a line L having x– intercept a and y– intercept b, then the line passes through X– axis at (a,0) and Y– axis at (0,b). Equation of line is given by x/a + y/b = 1. 5. Normal form of Line Consider a perpendicular from the origin having length p to line L and it makes an ANGLE β with the POSITIVE X-axis. Then, equation of line is given by x cosβ + y sinβ = p.

3.

8. The equation of a straight line passing through the point (2,-7) and parallel tox-axis is(a) x = 2(c) y-7(b) x -7(d) y 2

Answer»

Correct Statement is

The equation of a straight line passing through the point (2,-7) and parallel to x-axis is

(a) x = 2

(c) y = - 7

(b) x = 7

(d) y = 2

$\large\underline{\sf{Given- }}$

A line

passes through the point (2, - 7)

and

parallel to x- axis.

$\large\underline{\sf{To\:Find - }}$

Equation of line.

Concept Used :-

Slope - point form of a line

Let us assume a line which passes through the point (a, b) and having slope 'm', then equation of line is

$\sf \: y - b \: = \: m(x - a)$

$\large\underline{\sf{Solution-}}$

Given that

A line passes through the point (2, - 7) and parallel to x - axis.

SINCE,

Line is parallel to x- axis.

$\rm :\implies\:m \: = \: 0$

Now,

We know that

Equation of line is given by

$\rm :\longmapsto\:y - b \: = \: m(x - a)$

where,

$\rm :\longmapsto\:a \: = \: 2$

$\rm :\longmapsto\:b \: = \: - \: 7$

$\rm :\longmapsto\:m \: = \: 0$

On substituting all these values in above equation, we get

$\rm :\longmapsto\:y \: - \: ( - 7) = 0 \times (x - 2)$

$\rm :\longmapsto\:y + 7 = 0$

$\rm :\implies\:y \: = \: - \: 7$

$\overbrace{ \underline { \boxed { \rm \therefore The \: equation \: of \: line \: is \: y \: = \: - \: 7}}}$

─━─━─━─━─━─━─━─━─━─━─━─━─

Additional Information

Different forms of equations of a straight line

1. Equations of HORIZONTAL and vertical lines

Equation of the lines which are horizontal or parallel to the X-axis is y = a, where a is the y – coordinate of the points on the line.

Similarly, equation of a straight line which is vertical or parallel to Y-axis is x = a, where a is the x-coordinate of the points on the line.

2. Point-slope form equation of line

Consider a non-vertical line L whose slope is m, A(x,y) be an arbitrary point on the line and P(a, b) be the fixed point on the same line. Equation of line is given by y - b = m(x - a)

3. Slope-intercept form equation of line

Consider a line whose slope is m which cuts the Y-axis at a DISTANCE ‘a’ from the origin. Then the distance a is called the y– intercept of the line. The point at which the line cuts y-axis will be (0,a). Then equation of line is given by y = mx + a.

4. Intercept Form of Line

Consider a line L having x– intercept a and y– intercept b, then the line passes through X– axis at (a,0) and Y– axis at (0,b). Equation of line is given by x/a + y/b = 1.

5. Normal form of Line

Consider a perpendicular from the origin having length p to line L and it makes an ANGLE β with the POSITIVE X-axis. Then, equation of line is given by x cosβ + y sinβ = p.

Discussion

4.	Number1/2. Itismarkedatapointwhichishalfthedistancebetween0and1.So,-1/2wouldbemarkedatapointhalfthe distancebetween0and–1.Nowrepresent the following rationalsonnumber lines.(i) 3/5(ii)-4/7(iii)2/3
Answer» ANSWER: you can do it by yourself it's very EASY

4.

Number1/2. Itismarkedatapointwhichishalfthedistancebetween0and1.So,-1/2wouldbemarkedatapointhalfthe distancebetween0and–1.Nowrepresent the following rationalsonnumber lines.(i) 3/5(ii)-4/7(iii)2/3

Answer»

ANSWER:

you can do it by yourself it's very EASY

Discussion

5.	If the ratio of the mode and the median of certain data if 3:5, then find the ratio of itsmean and median
Answer» ANSWER: ufjcjckgkcjcjcieififkfidifjfjdjd

5.

If the ratio of the mode and the median of certain data if 3:5, then find the ratio of itsmean and median

Answer»

ANSWER:

ufjcjckgkcjcjcieififkfidifjfjdjd

Discussion

6.	Write down the equation of the line whose gradient is 3/2 and which passes through Pwhere P divides the line segment joining A(-2, 6) and B(3, -4) in the ratio 2:3
Answer» <P>We have line SEGMENTS joining A(-2,6) and B(3,-4) in the ratio 2:3 as: $\circ \ {\pmb{\underline{\sf{ According \ to \ Question: }}}} \\ \\ \\ \colon\implies{\sf{ P = \left( \dfrac{ 2 \times 3+3 \times (-2) }{2+3} , \dfrac{2 \times (-4) + 3 \times 6}{2+3} \right) }} \\ \\ \\ \colon\implies{\sf{ P = \left( \dfrac{ 6+(-6) }{5} , \dfrac{-8+18}{5} \right) }} \\ \\ \\ \colon\implies{\sf{ P = \left( \dfrac{ 6-6 }{5} , \dfrac{10}{5} \right) }} \\ \\ \\ \colon\implies{\sf{ P = \left( \dfrac{ 0 }{5} , 2 \right) }} \\ \\ \\ \colon\implies{\sf{ P = (0 , 2) }}$ ~Equation of line segment having gradient (m) = ${\sf{ \dfrac{3}{2} }}$ Line segment passes through P(0,2) x = 0 $\longrightarrow$ x - 0 = 0 y = 2 $\longrightarrow$ y - 2 = 0 $\dag \ {\pmb{\underline{\sf\green{ According \ to \ Equation: }}}} \\ \\ \colon\implies{\sf{ y-2 = \dfrac{3}{2} (x-0) }} \\ \\ \\ \colon\implies{\sf{ y-2 = \dfrac{3x-0}{2} }} \\ \\ \\ \colon\implies{\sf{ 2(y-2) = 3x }} \\ \\ \\ \colon\implies{\sf{ 2y-4 = 3x }} \\ \\ \\ \colon\implies{\sf{ 2y-3x = 4 }} \\$ Hence, ${\underline{\sf{The \ equation \ of \ the \ line \ is \ 2y-3x = 4 . }}}$

6.

Write down the equation of the line whose gradient is 3/2 and which passes through Pwhere P divides the line segment joining A(-2, 6) and B(3, -4) in the ratio 2:3

Answer»

<P>We have line SEGMENTS joining A(-2,6) and B(3,-4) in the ratio 2:3 as:

$\circ \ {\pmb{\underline{\sf{ According \ to \ Question: }}}} \\ \\ \\ \colon\implies{\sf{ P = \left( \dfrac{ 2 \times 3+3 \times (-2) }{2+3} , \dfrac{2 \times (-4) + 3 \times 6}{2+3} \right) }} \\ \\ \\ \colon\implies{\sf{ P = \left( \dfrac{ 6+(-6) }{5} , \dfrac{-8+18}{5} \right) }} \\ \\ \\ \colon\implies{\sf{ P = \left( \dfrac{ 6-6 }{5} , \dfrac{10}{5} \right) }} \\ \\ \\ \colon\implies{\sf{ P = \left( \dfrac{ 0 }{5} , 2 \right) }} \\ \\ \\ \colon\implies{\sf{ P = (0 , 2) }}$

~Equation of line segment having gradient (m) = ${\sf{ \dfrac{3}{2} }}$

Line segment passes through P(0,2)

x = 0 $\longrightarrow$ x - 0 = 0
y = 2 $\longrightarrow$ y - 2 = 0

$\dag \ {\pmb{\underline{\sf\green{ According \ to \ Equation: }}}} \\ \\ \colon\implies{\sf{ y-2 = \dfrac{3}{2} (x-0) }} \\ \\ \\ \colon\implies{\sf{ y-2 = \dfrac{3x-0}{2} }} \\ \\ \\ \colon\implies{\sf{ 2(y-2) = 3x }} \\ \\ \\ \colon\implies{\sf{ 2y-4 = 3x }} \\ \\ \\ \colon\implies{\sf{ 2y-3x = 4 }} \\$

Hence,

${\underline{\sf{The \ equation \ of \ the \ line \ is \ 2y-3x = 4 . }}}$

Discussion

7.	BeloveIfA= {x-X is a multiple of 3&XE NXCTooB- (x:x is a multiple of 5, XN x 2100!the find the the value of"NA) () n (B) 1) n(A) NB) in(A-B
Answer» Step-by-step EXPLANATION: xjxjxxjxjxjxhsjKkakalakqjaajjszjjdjzjzjsjsjddjdjsjjdxjcicjsnakzlgnfzjiskekdjdjdjxjjxjx xjdjkdjdjs

7.

BeloveIfA= {x-X is a multiple of 3&XE NXCTooB- (x:x is a multiple of 5, XN x 2100!the find the the value of"NA) () n (B) 1) n(A) NB) in(A-B

Answer»

Step-by-step EXPLANATION:

xjxjxxjxjxjxhsjKkakalakqjaajjszjjdjzjzjsjsjddjdjsjjdxjcicjsnakzlgnfzjiskekdjdjdjxjjxjx xjdjkdjdjs

Discussion

8.	Two circles of diameter 8.8cm and 6.6cm respectively touch each other internally. What is the distance between their centres? *a)2.2cmb)5.4cmc)1.1cmd)7.7cm
Answer» Answer: a) 2.2 cm Step-by-step explanation: when two CIRCLES TOUCH each other internally the distance between their CENTER is DIFFERENCE between the bigger radius and smaller radius therefore, 8.8-6.6= 2.2 cm hope it helps you :)

8.

Two circles of diameter 8.8cm and 6.6cm respectively touch each other internally. What is the distance between their centres? *a)2.2cmb)5.4cmc)1.1cmd)7.7cm

Answer»

Answer:

a) 2.2 cm

Step-by-step explanation:

when two CIRCLES TOUCH each other internally the distance between their CENTER is DIFFERENCE between the bigger radius and smaller radius therefore, 8.8-6.6= 2.2 cm hope it helps you :)

Discussion

9.	A motorboat covers a distance of 16km upstream and 24km downstreamin 6 hours. In the same time it covers a distance of 12 km upstream and36km downstream. Find the speed of the boat in still water and that of thestream.
Answer» $\underline{\underline{\huge{\gray{\tt{\textbf Answer :-}}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\sf\large\bold{\orange{\underline{\blue{ Given :-}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ MOTORBOAT covers a distance of 16km upstream and 24km downstream in 6 hours In the same time it covers a distance of 12 km upstream and 36km downstream ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\sf\large\bold{\orange{\underline{\blue{ To \: Find :-}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ The speed of the boat in still water The speed of stream ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\sf\large\bold{\orange{\underline{\blue{ Solution :-}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Let the speed of boat in still water be 'B' Let the speed of stream be 'W' ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\underline{\purple{ \underline{\orange{\bold{\texttt{Speed in upstream :}}}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ B - W ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\underline{\purple{ \underline{\orange{\bold{\texttt{Speed in downstream :}}}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ B + W ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\rm{ \large{\pink{\underline\blue{Case \: I :}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ *We know that ,* ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf T = \dfrac { D } { S }$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Where , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ T = Time taken D = Distance travelled S = Speed ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Time taken in upstream ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ $\sf T_1 = \dfrac { 16} { B - W}$ ⚊⚊⚊⚊ ⓵ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Time taken in downstream ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ $\sf T_2 = \dfrac { 24} { B + W}$ ⚊⚊⚊⚊ ⓶ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ *Given that , Motorboat covers a distance of 16km upstream and 24km downstream in 6 hours* ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf T_1 + T_2 = 6$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ From equation ⓵ & ⓶ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf \dfrac { 16} { B - W} + \dfrac { 24} { B + W} = 6$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf \dfrac { 16(B + W) + 24(B - W)} { (B - W)(B + W)} = 6$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf \dfrac { 16(B + W) + 24(B - W)} { B^2 - W^2 } = 6$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 16B + 16W + 24B - 24W = 6B² - 6W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 40B - 8W = 6B² - 6W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 20B - 4W = 3B² - 3W² ⚊⚊⚊⚊ ⓷ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\rm{ \large{\pink{\underline\blue{Case \: II :}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ *We know that ,* ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\sf T = \dfrac { D } { S }$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Where , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ T = Time taken D = Distance travelled S = Speed ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Time taken in upstream ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ $\sf T_3 = \dfrac { 12} { B - W}$ ⚊⚊⚊⚊ ⓸ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Time taken in downstream ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ $\sf T_4 = \dfrac { 36} { B + W}$ ⚊⚊⚊⚊ ⓹ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ *Given that , Motorboat covers a distance of 12km upstream and 36km downstream in 6 hours* ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf T_3 + T_4 = 6$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ From equation ⓸ & ⓹ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf \dfrac { 12} { B - W} + \dfrac { 36} { B + W} = 6$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf \dfrac { 12(B + W) + 36(B - W)} { (B - W)(B + W)} = 6$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf \dfrac { 12(B + W) + 36(B - W)} { B^2 - W^2 } = 6$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 12B + 12W + 36B - 36W = 6B² - 6W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 48B - 24W = 6B² - 6W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 24B - 12W = 3B² - 3W² ⚊⚊⚊⚊ ⓺ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Clearly equation ⓷ = ⓺ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ So, ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 20B - 4W = 24B - 12W ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 12W - 4W = 24B - 20B ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 8W = 4B ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 2W = B ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ B = 2W ⚊⚊⚊⚊ ⓻ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ PUTTING B = 2W from ⓻ to ⓷ ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 20B - 4W = 3B² - 3W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 20(2W) - 4W = 3(2W)² - 3W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 40W - 4W = 12W² - 3W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 36W = 9W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 4W = W² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 4 = W ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : : ➨ W = 4 ⚊⚊⚊⚊ ⓼ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Hence the speed of stream is 4 km/hour ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting W = 4 from ⓼ to ⓻ ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ B = 2W ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ B = 2(4) ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : : ➨ B = 8 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Hence the speed of Boat in still water is 8 km/hour ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ∴ The speed of Boat and stream are 8 km/hr & 4 km/hr RESPECTIVELY

9.

A motorboat covers a distance of 16km upstream and 24km downstreamin 6 hours. In the same time it covers a distance of 12 km upstream and36km downstream. Find the speed of the boat in still water and that of thestream.

Answer»

$\underline{\underline{\huge{\gray{\tt{\textbf Answer :-}}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\sf\large\bold{\orange{\underline{\blue{ Given :-}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

MOTORBOAT covers a distance of 16km upstream and 24km downstream in 6 hours
In the same time it covers a distance of 12 km upstream and 36km downstream

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\sf\large\bold{\orange{\underline{\blue{ To \: Find :-}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

The speed of the boat in still water
The speed of stream

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\sf\large\bold{\orange{\underline{\blue{ Solution :-}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Let the speed of boat in still water be 'B'
Let the speed of stream be 'W'

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\underline{\purple{ \underline{\orange{\bold{\texttt{Speed in upstream :}}}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ B - W

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\underline{\purple{ \underline{\orange{\bold{\texttt{Speed in downstream :}}}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ B + W

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\rm{ \large{\pink{\underline\blue{Case \: I :}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

We know that ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf T = \dfrac { D } { S }$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Where ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

T = Time taken
D = Distance travelled
S = Speed

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Time taken in upstream

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ $\sf T_1 = \dfrac { 16} { B - W}$ ⚊⚊⚊⚊ ⓵

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Time taken in downstream

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ $\sf T_2 = \dfrac { 24} { B + W}$ ⚊⚊⚊⚊ ⓶

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Given that , Motorboat covers a distance of 16km upstream and 24km downstream in 6 hours

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf T_1 + T_2 = 6$

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From equation ⓵ & ⓶

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf \dfrac { 16} { B - W} + \dfrac { 24} { B + W} = 6$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf \dfrac { 16(B + W) + 24(B - W)} { (B - W)(B + W)} = 6$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf \dfrac { 16(B + W) + 24(B - W)} { B^2 - W^2 } = 6$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 16B + 16W + 24B - 24W = 6B² - 6W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 40B - 8W = 6B² - 6W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 20B - 4W = 3B² - 3W² ⚊⚊⚊⚊ ⓷

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\rm{ \large{\pink{\underline\blue{Case \: II :}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

We know that ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\sf T = \dfrac { D } { S }$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Where ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

T = Time taken
D = Distance travelled
S = Speed

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Time taken in upstream

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ $\sf T_3 = \dfrac { 12} { B - W}$ ⚊⚊⚊⚊ ⓸

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Time taken in downstream

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➠ $\sf T_4 = \dfrac { 36} { B + W}$ ⚊⚊⚊⚊ ⓹

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Given that , Motorboat covers a distance of 12km upstream and 36km downstream in 6 hours

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf T_3 + T_4 = 6$

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From equation ⓸ & ⓹

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf \dfrac { 12} { B - W} + \dfrac { 36} { B + W} = 6$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf \dfrac { 12(B + W) + 36(B - W)} { (B - W)(B + W)} = 6$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf \dfrac { 12(B + W) + 36(B - W)} { B^2 - W^2 } = 6$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 12B + 12W + 36B - 36W = 6B² - 6W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 48B - 24W = 6B² - 6W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 24B - 12W = 3B² - 3W² ⚊⚊⚊⚊ ⓺

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Clearly equation ⓷ = ⓺

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

So,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 20B - 4W = 24B - 12W

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 12W - 4W = 24B - 20B

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: ➜ 8W = 4B

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 2W = B

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ B = 2W ⚊⚊⚊⚊ ⓻

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ PUTTING B = 2W from ⓻ to ⓷ ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 20B - 4W = 3B² - 3W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 20(2W) - 4W = 3(2W)² - 3W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 40W - 4W = 12W² - 3W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 36W = 9W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 4W = W²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 4 = W

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: : ➨ W = 4 ⚊⚊⚊⚊ ⓼

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Hence the speed of stream is 4 km/hour

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting W = 4 from ⓼ to ⓻ ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ B = 2W

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ B = 2(4)

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: : ➨ B = 8

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Hence the speed of Boat in still water is 8 km/hour

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

∴ The speed of Boat and stream are 8 km/hr & 4 km/hr RESPECTIVELY

Discussion

10.	(iv) তিনটি নিরেট ঘনক যাদের প্রত্যেকটি ধারের দৈর্ঘ্য যথাক্রমে 3 সেমি., 4 সেমি. এবং 5 সেমি.। ঘনকতিনটিকে গলিয়ে একটি নতুন নিরেট ঘনক তৈরি করা হলাে। নতুন ঘনকটির একটি ধারের দৈর্ঘ্যকত হবে তা লিখি।
Answer» Answer: Mitochondria are membrane-bound CELL organelles (mitochondrion, singular) that generate most of the chemical ENERGY needed to power the cell's biochemical reactions. Chemical energy PRODUCED by the mitochondria is STORED in a small MOLECULE called adenosine triphosphate (ATP).

10.

(iv) তিনটি নিরেট ঘনক যাদের প্রত্যেকটি ধারের দৈর্ঘ্য যথাক্রমে 3 সেমি., 4 সেমি. এবং 5 সেমি.। ঘনকতিনটিকে গলিয়ে একটি নতুন নিরেট ঘনক তৈরি করা হলাে। নতুন ঘনকটির একটি ধারের দৈর্ঘ্যকত হবে তা লিখি।

Answer»

Answer:

Mitochondria are membrane-bound CELL organelles (mitochondrion, singular) that generate most of the chemical ENERGY needed to power the cell's biochemical reactions. Chemical energy PRODUCED by the mitochondria is STORED in a small MOLECULE called adenosine triphosphate (ATP).

Discussion

11.	4) The radius of a circle is15cm. The distance ofcentre O from M; theBmidpoint of chord AB isM9 cm. Find the length ofAchord AB
Answer» Step-by-step explanation: is ke jesa he YE kar lena The RADIUS of a circle is given as 15 CM and chord AB subtends an angle of 131 ∘ at the centre C of the circle.Using trigonometry ,CALCULATE : (i) the length of AB ; (ii) the distance of AB from the centre C 1111888 Answer Open in answr app Given r=15 ∠AOB=13.1 AB=x AC=CB= 2 x ∠AOC=65.5 o sin65.5= 2×15 x As sin65.5=0.909 x=0.909×30=27.27 ∴ length of AB=27.27 OC=cos65−5×15 =0.414×15 OC=6.21cm ∴ length of chord AB=27.27cm distance between centre and the chord is 6.21 cm.

11.

4) The radius of a circle is15cm. The distance ofcentre O from M; theBmidpoint of chord AB isM9 cm. Find the length ofAchord AB

Answer»

Step-by-step explanation:

is ke jesa he YE kar lena

The RADIUS of a circle is given as 15 CM and chord AB subtends an angle of 131

∘

at the centre C of the circle.Using trigonometry ,CALCULATE :

(i) the length of AB ;

(ii) the distance of AB from the centre C

1111888

Answer

Open in answr app

Given r=15

∠AOB=13.1

AB=x

AC=CB=

2

x

∠AOC=65.5

o

sin65.5=

2×15

x

As sin65.5=0.909

x=0.909×30=27.27

∴ length of AB=27.27

OC=cos65−5×15

=0.414×15

OC=6.21cm

∴ length of chord AB=27.27cm

distance between centre and the chord is 6.21 cm.

Discussion

12.	Theareaofacircleofdiameterdis:
Answer» Answer: AREA of CIRCLE Formula Suppose a circle has a radius 'r' then the area of circle = πr2 or πd2/4 in square UNITS, where π = 22/7 or 3.14, and d is the diameter. Area of circle can be calculated by USING the formulas: Area = π x R2, where 'r' is the radius.

12.

Theareaofacircleofdiameterdis:

Answer»

Answer:

AREA of CIRCLE Formula

Suppose a circle has a radius 'r' then the area of circle = πr2 or πd2/4 in square UNITS, where π = 22/7 or 3.14, and d is the diameter. Area of circle can be calculated by USING the formulas: Area = π x R2, where 'r' is the radius.

Discussion

13.	SNIn the given figure PQ is a line. Ray OR isperpendicular to line PQ. OS is another ray lyingbetween rays OP and OR.1Prove that ZROS =(Z QOS - POS)2O70
Answer» ANSWER: SORRY I can't KNOW the answer

13.

SNIn the given figure PQ is a line. Ray OR isperpendicular to line PQ. OS is another ray lyingbetween rays OP and OR.1Prove that ZROS =(Z QOS - POS)2O70

Answer»

ANSWER:

SORRY I can't KNOW the answer

Discussion

14.	NeetusavesRs500fromhersalary.Ifthisis8%ofhersalary.Whatishersalary?please give me answers
Answer» Answer: 8% of 500 SALARY is RUPEES 40.

14.

NeetusavesRs500fromhersalary.Ifthisis8%ofhersalary.Whatishersalary?please give me answers

Answer»

Answer:

8% of 500 SALARY is RUPEES 40.

Discussion

15.	Writeorderofrotationandangleofrotationof:(i) Equilateraltriangle(ii) Circle(iii) Regularhexagon pls fast reply
Answer» ANSWER: jdajxjvjdjsjsjscjvjgkdjsjvjvvjxjsjak Step-by-step EXPLANATION: djdjzjxjcvj l

15.

Writeorderofrotationandangleofrotationof:(i) Equilateraltriangle(ii) Circle(iii) Regularhexagon pls fast reply

Answer»

ANSWER:

jdajxjvjdjsjsjscjvjgkdjsjvjvvjxjsjak

Step-by-step EXPLANATION:

djdjzjxjcvj

l

Discussion

16.	) If the line z = = z is perpendicular to the line*-1 y + 21+2 2-3k 3 k-1thenthe value of k is1111114(a)(b) -(C)).(d)C2
Answer» ANSWER: 23 is the CORRECT answer please SET me Brainlist

16.

) If the line z = = z is perpendicular to the line*-1 y + 21+2 2-3k 3 k-1thenthe value of k is1111114(a)(b) -(C)).(d)C2

Answer»

ANSWER:

23 is the CORRECT answer

please SET me Brainlist

Discussion

17.	8. A e B together can do a piece of world in15 days & 'A' alone can do it in 30 days. Howlong will s take to complete the hwork?
Answer» ANSWER: 30 day A+B = 15 A = 30 take the LCM of both 15 and 30 = 30 efficiency of A+B = 30/15=2....,....(1) efficiency of A = 30/30 = 1 efficiency of B = 1 (from PUTTING the value of A in EQUATION 1) now, day taken by B is = 30/1= 30 day

17.

8. A e B together can do a piece of world in15 days & 'A' alone can do it in 30 days. Howlong will s take to complete the hwork?

Answer»

ANSWER:

30 day

A+B = 15

A = 30

take the LCM of both 15 and 30 = 30

efficiency of A+B = 30/15=2....,....(1)

efficiency of A = 30/30 = 1

efficiency of B = 1 (from PUTTING the value of A in EQUATION 1)

now, day taken by B is = 30/1= 30 day

Discussion

18.	A bag has 5 green and 7 red balls. One ball is drawnat random from the bag. Find the probability that theball drawn is yellow in colour.
Answer» ANSWER: I THINK that answer is ONE

18.

A bag has 5 green and 7 red balls. One ball is drawnat random from the bag. Find the probability that theball drawn is yellow in colour.

Answer»

ANSWER:

I THINK that answer is ONE

Discussion

19.	Solveallthefourparts:(i)0.05×2.2(ii)2.5×5.02(iii) 1.2×1000(iv) 101.1×1.1Or(i)0.05÷10(ii)2.5÷100(iii) 1.2÷1000(iv) 101.1÷10000ANSWER(vii) 101.1÷10000
Answer» Step-by-step EXPLANATION: i ) ANS - 0.11 ii) Ans - 12.55 iii) Ans - 1200 iv) Ans - 111.21 HOPE it will be helpfull Hope it will be helpfull THANK You.❤❤

19.

Solveallthefourparts:(i)0.05×2.2(ii)2.5×5.02(iii) 1.2×1000(iv) 101.1×1.1Or(i)0.05÷10(ii)2.5÷100(iii) 1.2÷1000(iv) 101.1÷10000ANSWER(vii) 101.1÷10000

Answer»

Step-by-step EXPLANATION:

i ) ANS - 0.11

ii) Ans - 12.55

iii) Ans - 1200

iv) Ans - 111.21

HOPE it will be helpfull

Hope it will be helpfull THANK You.❤❤

Discussion

20.	(-2)^2 x (2)^3 is equal to 22222(-2)(-2)(-2)(-2)(-2)4444*4(-4)(-4)(-4)(-4)(-4)
Answer» Answer: dddhlhzc 2nd udhvast FFS J CA j 1ST s

20.

(-2)^2 x (2)^3 is equal to 22222(-2)(-2)(-2)(-2)(-2)4444*4(-4)(-4)(-4)(-4)(-4)

Answer»

Answer:

dddhlhzc 2nd udhvast FFS J CA j 1ST s

Discussion

21.	If each edge of a cube is doubled, itsvolume will increase by eight times.1.True2.False
Answer» ANSWER: 1 TRUE it is the RIGHT answer

21.

If each edge of a cube is doubled, itsvolume will increase by eight times.1.True2.False

Answer»

ANSWER:

1 TRUE it is the RIGHT answer

Discussion

22.	Q2. If x= pcos 0, y = psin Ø, z = z, (Mathen the value of the Jacobiana(xyzisa (p.0.2)(A) p2(B) 2/2(C) 2p
Answer» Answer: Mitochondria are membrane-bound cell organelles (mitochondrion, singular) that generate most of the chemical energy needed to power the cell's biochemical reactions. Chemical energy produced by the mitochondria is STORED in a SMALL MOLECULE CALLED adenosine triphosphate (ATP).

22.

Q2. If x= pcos 0, y = psin Ø, z = z, (Mathen the value of the Jacobiana(xyzisa (p.0.2)(A) p2(B) 2/2(C) 2p

Answer»

Answer:

Mitochondria are membrane-bound cell organelles (mitochondrion, singular) that generate most of the chemical energy needed to power the cell's biochemical reactions. Chemical energy produced by the mitochondria is STORED in a SMALL MOLECULE CALLED adenosine triphosphate (ATP).

Discussion

23.	Two coins are tossed simultaneously 500 times. If we get two heads 100 times; one head 130times, then find the probability of getting one or more than one tail.
Answer» it will be the ANSWE I.e 27/50

23.

Two coins are tossed simultaneously 500 times. If we get two heads 100 times; one head 130times, then find the probability of getting one or more than one tail.

Answer»

it will be the ANSWE I.e

27/50

Discussion

24.	પ્રિક્રમાકે 37થી 45 - પ્રત્યકેના 3 ગુણ ]37. 1, 3 અને 4 એ ત્રિઘાત બહુપદી p(x) = x3-8x2 + 19x - 12 નાં શૂન્યો છે તે ચકાસો. ત્યારબાદ બહુપદીનાંઅને સહગુણકો vacheno saved ચકાસો
Answer» Answer: Pantoprazole is used to treat CERTAIN stomach and esophagus problems (such as ACID reflux). It works by decreasing the amount of acid your stomach makes. This MEDICATION relieves symptoms such as heartburn, DIFFICULTY SWALLOWING, and persistent cough

24.

પ્રિક્રમાકે 37થી 45 - પ્રત્યકેના 3 ગુણ ]37. 1, 3 અને 4 એ ત્રિઘાત બહુપદી p(x) = x3-8x2 + 19x - 12 નાં શૂન્યો છે તે ચકાસો. ત્યારબાદ બહુપદીનાંઅને સહગુણકો vacheno saved ચકાસો

Answer»

Answer:

Pantoprazole is used to treat CERTAIN stomach and esophagus problems (such as ACID reflux). It works by decreasing the amount of acid your stomach makes. This MEDICATION relieves symptoms such as heartburn, DIFFICULTY SWALLOWING, and persistent cough

Discussion

25.	The radius of a circle is 1cm. What is its area?(a) cm(b) cm(c) 2 cm(d) 21 cm
Answer» Answer: 1 cm² is the answer Step-by-step EXPLANATION: HOPE it HELPS!!

25.

The radius of a circle is 1cm. What is its area?(a) cm(b) cm(c) 2 cm(d) 21 cm

Answer»

Answer:

1 cm² is the answer

Step-by-step EXPLANATION:

HOPE it HELPS!!

Discussion

26.	Divide as directed(1) 18a D by 6ab(111) -4° - 120 - 16a) by 4a(v) ar-y-) by (ax +ay)
Answer» ANSWER: U have massage for ans i will giv YU

26.

Divide as directed(1) 18a D by 6ab(111) -4° - 120 - 16a) by 4a(v) ar-y-) by (ax +ay)

Answer»

ANSWER:

U have massage for ans i will giv YU

Discussion

27.	Write the equation and solve.a) Four-fifths of a number is 16.b) 15 times a number is 65.
Answer» Answer: 20 and 4.33 Step-by-step EXPLANATION: (4/5)x=16 x = 20 and 15Y = 65 y = 65/15

27.

Write the equation and solve.a) Four-fifths of a number is 16.b) 15 times a number is 65.

Answer»

Answer:

20 and 4.33

Step-by-step EXPLANATION:

(4/5)x=16

x = 20

and

15Y = 65

y = 65/15

Discussion

28.	Find the volume,lateral surface area,total surface area of a cube when side =7cm pls give step by answerspls give the ans step by step need imediatly
Answer» Step-by-step EXPLANATION: please MARK as BRAINLIEST

28.

Find the volume,lateral surface area,total surface area of a cube when side =7cm pls give step by answerspls give the ans step by step need imediatly

Answer»

Step-by-step EXPLANATION:

please MARK as BRAINLIEST

Discussion

29.	Raju spent 8/25 of his pocket money on books and 12/25 of his money on uniform. what fraction of the packet money did he spend together
Answer» Answer: 3/10 Step-by-step explanation: Let Rohit's pocket money be x. First he spent 2/5 of his pocket money so he has $x-\frac{2x}{5}$ left with him. Second he spends 1/6 on a newspaper assuming that this is a fraction of the original pocket money he has $x-\frac{2x}{5}-\frac{x}{6}$ left with him. Finally he spends 2/15 on recreation so he has a total of $x-\frac{2x}{5} -\frac{x}{6} -\frac{2x}{15}$ left with him. Simplyfying we GET $\frac{3x}{10}$ THUS we can SAY the fraction is 3/10

29.

Raju spent 8/25 of his pocket money on books and 12/25 of his money on uniform. what fraction of the packet money did he spend together

Answer»

Answer:

3/10

Step-by-step explanation:

Let Rohit's pocket money be x.

First he spent 2/5 of his pocket money so he has $x-\frac{2x}{5}$ left with him.

Second he spends 1/6 on a newspaper assuming that this is a fraction of the original pocket money he has $x-\frac{2x}{5}-\frac{x}{6}$ left with him.

Finally he spends 2/15 on recreation so he has a total of $x-\frac{2x}{5} -\frac{x}{6} -\frac{2x}{15}$ left with him.

Simplyfying we GET $\frac{3x}{10}$ THUS we can SAY the fraction is 3/10

Discussion

30.	8 पुरुषों में से दो पुरुषों की आयु क्रमश: 21 वर्ष तथा 23 वर्षहै. इनके स्थान पर दो नये पुरुषों को लेने पर इनकी औसत आयुमें 2 वर्ष की वृद्धि हो जाती है. दोनों नये पुरुषों की औसत आयुकितनी है?
Answer» Answer: PANTOPRAZOLE is used to treat certain stomach and ESOPHAGUS problems (such as acid reflux). It works by decreasing the amount of acid your stomach MAKES. This medication relieves symptoms such as heartburn, DIFFICULTY swallowing, and PERSISTENT cough

30.

8 पुरुषों में से दो पुरुषों की आयु क्रमश: 21 वर्ष तथा 23 वर्षहै. इनके स्थान पर दो नये पुरुषों को लेने पर इनकी औसत आयुमें 2 वर्ष की वृद्धि हो जाती है. दोनों नये पुरुषों की औसत आयुकितनी है?

Answer»

Answer:

PANTOPRAZOLE is used to treat certain stomach and ESOPHAGUS problems (such as acid reflux). It works by decreasing the amount of acid your stomach MAKES. This medication relieves symptoms such as heartburn, DIFFICULTY swallowing, and PERSISTENT cough

Discussion

31.	The production of TV sets in a factory increases uniformly by a fixed number every year . It produced 16000 sets in 6th year and 22600 in 9th year.1. Find the production in first year.2.Find the production in 8th year.3. Find the production during first 3 years.4. In which year, the production is Rs. 29,200.
Answer» Step-by-step explanation: Solution : LET the production during first year be a and let d be the INCREASE in production every year. Then, T6=16000⇒a+5d=16000…(i) andT9=22600⇒a+8d=22600...(ii) On SUBTRACTING (i) from (ii), we get 3d=6600⇒d=2200 Putting d = 2200 in (i), we get a+5×2200=16000⇒a+11000=16000 ⇒a=16000-11000=5000 Thus, a = 5000 and d = 2200. (i) Production during first year, a = 5000 (ii) Production during 8th year is given by T8=(a+7d)=(5000+7×2200)=(5000+15400)=20400. (III) Production during first 6 YEARS is given by S6= 6 2 {2a+5d}=3(2×5000+5×2200) =3(10000+11000)=63000

31.

The production of TV sets in a factory increases uniformly by a fixed number every year . It produced 16000 sets in 6th year and 22600 in 9th year.1. Find the production in first year.2.Find the production in 8th year.3. Find the production during first 3 years.4. In which year, the production is Rs. 29,200.

Answer»

Step-by-step explanation:

Solution :

LET the production during first year be a and let d be the INCREASE in production every year. Then,

T6=16000⇒a+5d=16000…(i)

andT9=22600⇒a+8d=22600...(ii)

On SUBTRACTING (i) from (ii), we get

3d=6600⇒d=2200

Putting d = 2200 in (i), we get

a+5×2200=16000⇒a+11000=16000

⇒a=16000-11000=5000

Thus, a = 5000 and d = 2200.

(i) Production during first year, a = 5000

(ii) Production during 8th year is given by

T8=(a+7d)=(5000+7×2200)=(5000+15400)=20400.

(III) Production during first 6 YEARS is given by

S6=

6

2

{2a+5d}=3(2×5000+5×2200)

=3(10000+11000)=63000

Discussion

32.	If tangents PA and PB from a point P to a circle with centre O are inclined to each other at an angle of 80° ,then ∟AOB= ______ *A)70°B)90°C)40°D)100°
Answer» ANSWER: C)40° Step-by-step EXPLANATION: please mark me as brainliest

32.

If tangents PA and PB from a point P to a circle with centre O are inclined to each other at an angle of 80° ,then ∟AOB= ______ *A)70°B)90°C)40°D)100°

Answer»

ANSWER:

C)40°

Step-by-step EXPLANATION:

please mark me as brainliest

Discussion

33.	Question 1 :A match box measures 5cm x 3cm x 2cmWhat will be the volume of a packetcontaining 10 such boxes?305cm3300cm3315cm350cm3
Answer» Answer: 300 cm3 is the CORRECT answer and MARK as a brain LIST

33.

Question 1 :A match box measures 5cm x 3cm x 2cmWhat will be the volume of a packetcontaining 10 such boxes?305cm3300cm3315cm350cm3

Answer»

Answer:

300 cm3 is the CORRECT answer

and MARK as a brain LIST

Discussion

34.	IF the order of matrix A is mxp and theorder of matrix B is pxn ,then the order ofmatrix AB is,nxmmxnnxppxm
Answer» Answer: If we are given 2 matrices of with order a×b and c×d, in order to be MULTIPLICABLE, b MUST be EQUAL to c and the resultant MATRIX will have order a×d. So using this formula in this question, We have p = p and so the resultant matrix will have m×n order. So, order of matrix AB is m×n.

34.

IF the order of matrix A is mxp and theorder of matrix B is pxn ,then the order ofmatrix AB is,nxmmxnnxppxm

Answer»

Answer:

If we are given 2 matrices of with order a×b and c×d, in order to be MULTIPLICABLE, b MUST be EQUAL to c and the resultant MATRIX will have order a×d. So using this formula in this question, We have p = p and so the resultant matrix will have m×n order. So, order of matrix AB is m×n.

Discussion

35.	Value of sec-1 (-v2)+ sec-1 (V2) is
Answer» ANSWER: 2 (v3l is the answer of which you ASK

35.

Value of sec-1 (-v2)+ sec-1 (V2) is

Answer»

ANSWER:

2 (v3l is the answer of which you ASK

Discussion

36.	If a number is divided by 78,the remainder is 15. What will be the remainder if the same number is divided by 13
Answer» Answer: 90 Step-by-step explanation: 78*15=1170 1170÷13=90

36.

If a number is divided by 78,the remainder is 15. What will be the remainder if the same number is divided by 13

Answer»

Answer:

90

Step-by-step explanation:

78*15=1170

1170÷13=90

Discussion

37.	7. Peter purchased 35 pens at the rate of 5 pens for ₹22 and sold them at the rate of 4 pens for₹ 22Find out his profit percent.
Answer» Answer: 38.5 Step-by-step EXPLANATION: he buy 35 pens in 154 rs he SOLD 35 pens in 192.5 rs MEAN he profit 38.5 rs sorry I don't explain you clearly but I tried my best

37.

7. Peter purchased 35 pens at the rate of 5 pens for ₹22 and sold them at the rate of 4 pens for₹ 22Find out his profit percent.

Answer»

Answer:

38.5

Step-by-step EXPLANATION:

he buy 35 pens in 154 rs

he SOLD 35 pens in 192.5 rs

MEAN he profit 38.5 rs

sorry I don't explain you clearly but I tried my best

Discussion

38.	If the mean and coefficient of variation of adata are 15 and 48 respectively, then findthe value of standard deviation.
Answer» Answer: Pantoprazole is USED to treat CERTAIN stomach and esophagus PROBLEMS (such as acid reflux). It WORKS by decreasing the amount of acid your stomach makes. This medication relieves symptoms such as heartburn, difficulty swallowing, and persistent cough

38.

If the mean and coefficient of variation of adata are 15 and 48 respectively, then findthe value of standard deviation.

Answer»

Answer:

Pantoprazole is USED to treat CERTAIN stomach and esophagus PROBLEMS (such as acid reflux). It WORKS by decreasing the amount of acid your stomach makes. This medication relieves symptoms such as heartburn, difficulty swallowing, and persistent cough

Discussion

39.	Write a pair of integer whose sum givesa. Zerob. A negative integerc.An integer smaller than both integer
Answer» ANSWER: A.+5-5, B. +5-6, C.8-5=3 Step-by-step EXPLANATION:

39.

Write a pair of integer whose sum givesa. Zerob. A negative integerc.An integer smaller than both integer

Answer»

ANSWER:

A.+5-5, B. +5-6, C.8-5=3

Step-by-step EXPLANATION:

Discussion

40.	Subject Name 2200:29:59KHULE RAHUL MAHADEVQuestion 4:solve by cramers rule2x + 3y = 5 , y - 3z = -2,3x + z = 4x = 1, y = 1,2= 1x = -1, y = 1,2 = 2O x = 2, y = -1, z = 3x = 2, y = 1, z = 4PreviousSave & NextTo be reviewed laterEnd exam button available on last question.
Answer» Answer: EMPLOYMENT 11 14 17 Total 1 18 56 89 163 0 13 16 8 37 Total 31 72 97 200 What is the variance of employment? GIVE your answer to TWO decimal places.

40.

Subject Name 2200:29:59KHULE RAHUL MAHADEVQuestion 4:solve by cramers rule2x + 3y = 5 , y - 3z = -2,3x + z = 4x = 1, y = 1,2= 1x = -1, y = 1,2 = 2O x = 2, y = -1, z = 3x = 2, y = 1, z = 4PreviousSave & NextTo be reviewed laterEnd exam button available on last question.

Answer»

Answer:

EMPLOYMENT 11 14 17 Total 1 18 56 89 163 0 13 16 8 37 Total 31 72 97 200 What is the variance of employment? GIVE your answer to TWO decimal places.

Discussion

41.	A unit vector is of a vector v isa. In the same direction as vb. In the opposite direction of vc. Perpendicular to vD none
Answer» Answer: thug and the m and the m is a VERY important PART in the WORLD and the m and its VERY 6th and most POWERFUL in the line:'she launches in a series that who has a j and is the most powerful person Step-by-step EXPLANATION: d the WAY to do this classes in the WORLD and the m and its great value 40lakhs is a VERY important thing to do in the line:'she and we will be ABLE and to be in and out C.V will you do that

41.

A unit vector is of a vector v isa. In the same direction as vb. In the opposite direction of vc. Perpendicular to vD none

Answer»

Answer:

thug and the m and the m is a VERY important PART in the WORLD and the m and its VERY 6th and most POWERFUL in the line:'she launches in a series that who has a j and is the most powerful person

Step-by-step EXPLANATION:

d the WAY to do this classes in the WORLD and the m and its great value 40lakhs is a VERY important thing to do in the line:'she and we will be ABLE and to be in and out C.V will you do that

Discussion

42.	The shape of a garden is rectangularin the middle and and democircular at the ends ad shown in thediagram find the area and thekerimeter of this gardene7 amDieC20m
Answer» ANSWER: Tfyyhuyy yhhgfhhyyhgh-#-yehd&wigrehjdyehh&wuhdehjdjx&

42.

The shape of a garden is rectangularin the middle and and democircular at the ends ad shown in thediagram find the area and thekerimeter of this gardene7 amDieC20m

Answer»

ANSWER:

Tfyyhuyy yhhgfhhyyhgh-#-yehd&wigrehjdyehh&wuhdehjdjx&

Discussion

43.	Find the number of solutions of the following pair of linear equations :2x + 3y + 17 = 04x + 6x + 15 = 0
Answer» Answer: 4X + 6y + 15 = 0 ----------(ii) and, 2x+3y+17=0 ---------------(i) it can be seen of the cofficients of equations. coe.of X of 1st coe. of y of 1st cons. term of 1st -------------------- = --------------------- ≠ ------------------coe. of x of 2nd coff. of y of 2nd cons. term of 2 => 2/4=3/6≠17/15 => 1/2=1/2≠17/15 And this CONDITION for no SOLUTIONS or two parallel lines. So, the answer is no solution exist.

43.

Find the number of solutions of the following pair of linear equations :2x + 3y + 17 = 04x + 6x + 15 = 0

Answer»

Answer:

4X + 6y + 15 = 0 ----------(ii)

and, 2x+3y+17=0 ---------------(i)

it can be seen of the cofficients of equations.

coe.of X of 1st coe. of y of 1st cons. term of 1st

-------------------- = --------------------- ≠ ------------------coe. of x of 2nd coff. of y of 2nd cons. term of 2

=> 2/4=3/6≠17/15

=> 1/2=1/2≠17/15

And this CONDITION for no SOLUTIONS or two

parallel lines.

So, the answer is no solution exist.

Discussion

44.	7. Use the given statement to form an equation in x and solve the equation to find the unknown number(i) I think of a number, subtract 3 and get 4.(i) I think of a number, add 1 and the result is 3.(ii) I think of a number, double it and get 8.(iv) I think of a number, divide it by 6 and get 5.
Answer» Answer: the given statement to FORM an equation in x and solve the equation to FIND the unknown number (i) I think of a number, SUBTRACT 3 and GET 4. (i) I think of a number, add 1 and the result is 3. (ii) I think of a number, double it and get 8. (IV) I think of a number, divide it by 6 and get 5.

44.

7. Use the given statement to form an equation in x and solve the equation to find the unknown number(i) I think of a number, subtract 3 and get 4.(i) I think of a number, add 1 and the result is 3.(ii) I think of a number, double it and get 8.(iv) I think of a number, divide it by 6 and get 5.

Answer»

Answer:

the given statement to FORM an equation in x and solve the equation to FIND the unknown number

(i) I think of a number, SUBTRACT 3 and GET 4.

(i) I think of a number, add 1 and the result is 3.

(ii) I think of a number, double it and get 8.

(IV) I think of a number, divide it by 6 and get 5.

Discussion

45.	Q23. A machine in a soft drink factory fill 960 bottles in 8hours. How many bottleswill it fill in 6 hours?answer me with explanation and it's very important for me
Answer» AnswER Machine FILLS 720 BOTTLES in 6 HOURS. Explanation Firstly, we have to FIND that how many bottles will fill in an hour so:- $\colon\implies{\sf{ 8 \ hours = 960 \ bottles}} \\ \\ \colon\implies{\sf{ \cancel{ \dfrac{960}{8} } }} \\ \\ \colon\implies{\sf{ 120 \ bottles }}$ So, we know that 120 bottles fill in an hour. ~~Now, we have to find that how many bottles will fill in 6 hours as:- $\colon\implies{\sf{ 120 \times 6 }} \\ \\ \colon\implies{\sf{ 720 \ bottles }} \\$ Hence, By Using Unitary Method, we found that Machine will fill 720 bottles in 6 hours.

45.

Q23. A machine in a soft drink factory fill 960 bottles in 8hours. How many bottleswill it fill in 6 hours?answer me with explanation and it's very important for me

Answer»

AnswER

Machine FILLS 720 BOTTLES in 6 HOURS.

Explanation

Firstly, we have to FIND that how many bottles will fill in an hour so:-

$\colon\implies{\sf{ 8 \ hours = 960 \ bottles}} \\ \\ \colon\implies{\sf{ \cancel{ \dfrac{960}{8} } }} \\ \\ \colon\implies{\sf{ 120 \ bottles }}$

So, we know that 120 bottles fill in an hour.

~~Now, we have to find that how many bottles will fill in 6 hours as:-

$\colon\implies{\sf{ 120 \times 6 }} \\ \\ \colon\implies{\sf{ 720 \ bottles }} \\$

Hence,

By Using Unitary Method, we found that Machine will fill 720 bottles in 6 hours.

Discussion

46.	The value of 21b − 32 + 7b − 20 isPLS WRITE THE CORRECT ANSWER
Answer» 21b−32+7b−20b=b(21+7−20)−32=b(28−20)−32=8b−32

Discussion

47.	Prove this by using the principle of mathematical induction for all n€N. (2n + 7)
Answer» ANSWER: I don `t no FRIENDS SORRY

47.

Prove this by using the principle of mathematical induction for all n€N. (2n + 7)

Answer»

ANSWER:

I don `t no FRIENDS SORRY

Discussion

48.	Question 38 Find the Area of a Triangle whose verticesare (-3, 1), (1, -3) and (2,3)7 Sq.Units9 Sq.Units11 Sq.Units14 Sq.Units
Answer» Step-by-step explanation: Given:- Given POINTS are (-3, 1), (1, -3) and (2,3) To find:- Find the Area of a TRIANGLE whose VERTICES are (-3, 1), (1, -3) and (2,3) ? Solution:- Given points are (-3, 1), (1, -3) and (2,3) Let (x1, y1)=(-3,1)=>x1=-3 and y1 = 1 Let (x2, y2)=(1,-3)=>x2=1 and y2 = -3 Let (x3, y3)=(2,3)=>x3=2 and y3=3 We know that The Area of a triangle formed by whose vertices are( x1 ,y1 )and (x2, y2 )and (x3, y3) is ∆=(1/2) \| x1(y2-y3) +x2(y3-y1) + x3(y1-y2) \| sq.units On SUBSTITUTING the values in the above formula =>∆=(1/2) \| (-3)(-3-3)+(1)(3-1)+(2)(1-(-3)) \| sq.units =>∆=(1/2) \| (-3)(-6)+(1)(2)+(2)(4) \| sq.units =>∆=(1/2) \| 18+2+8 \| sq.units =>∆=(1/2) \| 28 \| sq.units =>∆=28/2 sq.units =>∆=14 sq.units Answer:- The area of the given triangle formed by the given vertices is 14 sq.units Used formulae:- 1) The Area of a triangle formed by whose vertices are( x1 ,y1 )and (x2, y2 )and (x3, y3) is ∆=(1/2) \| x1(y2-y3) +x2(y3-y1) + x3(y1-y2) \| sq.units

48.

Question 38 Find the Area of a Triangle whose verticesare (-3, 1), (1, -3) and (2,3)7 Sq.Units9 Sq.Units11 Sq.Units14 Sq.Units

Answer»

Step-by-step explanation:

Given:-

Given POINTS are (-3, 1), (1, -3) and (2,3)

To find:-

Find the Area of a TRIANGLE whose VERTICES

are (-3, 1), (1, -3) and (2,3) ?

Solution:-

Given points are (-3, 1), (1, -3) and (2,3)

Let (x1, y1)=(-3,1)=>x1=-3 and y1 = 1

Let (x2, y2)=(1,-3)=>x2=1 and y2 = -3

Let (x3, y3)=(2,3)=>x3=2 and y3=3

We know that

The Area of a triangle formed by whose vertices are( x1 ,y1 )and (x2, y2 )and (x3, y3) is

∆=(1/2) | x1(y2-y3) +x2(y3-y1) + x3(y1-y2) | sq.units

On SUBSTITUTING the values in the above formula

=>∆=(1/2) | (-3)(-3-3)+(1)(3-1)+(2)(1-(-3)) | sq.units

=>∆=(1/2) | (-3)(-6)+(1)(2)+(2)(4) | sq.units

=>∆=(1/2) | 18+2+8 | sq.units

=>∆=(1/2) | 28 | sq.units

=>∆=28/2 sq.units

=>∆=14 sq.units

Answer:-

The area of the given triangle formed by the given vertices is 14 sq.units

Used formulae:-

1)

The Area of a triangle formed by whose vertices are( x1 ,y1 )and (x2, y2 )and (x3, y3) is

∆=(1/2) | x1(y2-y3) +x2(y3-y1) + x3(y1-y2) | sq.units

Discussion

49.	10. A shopkeeper has 2,345 kg of salt. He sells 45 kg of salt every day. Estimate how much salt is left after10 days of sale (to the nearest hundred).2
Answer» ANSWER: I can not UNDERSTAND this

49.

10. A shopkeeper has 2,345 kg of salt. He sells 45 kg of salt every day. Estimate how much salt is left after10 days of sale (to the nearest hundred).2

Answer»

ANSWER:

I can not UNDERSTAND this

Discussion

50.	Exercise 1Directions: Read and solve the problem. Answer the questions using the 4-step processProblem: In an international conference, 400 people who attended were Filipinos,If 40% of these were Filipino male professionals, how many Filipino male professionalswere there?TIINAKnow what is askedKnow what are givenfotsDetermine theoperation to be usedWrite thenumber/mathematioulsentencaSOLLPerform the operationsAnswer(HIND LOOKWork backwards
Answer» ANSWER: I donydgreakjggkgjlcbmdlhflsorry

50.

Exercise 1Directions: Read and solve the problem. Answer the questions using the 4-step processProblem: In an international conference, 400 people who attended were Filipinos,If 40% of these were Filipino male professionals, how many Filipino male professionalswere there?TIINAKnow what is askedKnow what are givenfotsDetermine theoperation to be usedWrite thenumber/mathematioulsentencaSOLLPerform the operationsAnswer(HIND LOOKWork backwards

Answer»

ANSWER:

I donydgreakjggkgjlcbmdlhflsorry

Discussion

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HOPE it will be helpfull

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Given:-

To find:-

Solution:-

Answer:-

Used formulae:-

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Subject Name 2200:29:59KHULE RAHUL MAHADEVQuestion 4:solve by cramers rule2x + 3y = 5 , y - 3z = -2,3x + z = 4x = 1, y = 1,2= 1x = -1, y = 1,2 = 2O x = 2, y = -1, z = 3x = 2, y = 1, z = 4PreviousSave & NextTo be reviewed laterEnd exam button available on last question.

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10. A shopkeeper has 2,345 kg of salt. He sells 45 kg of salt every day. Estimate how much salt is left after10 days of sale (to the nearest hundred).2