332354 + Interview Questions in Secondary School in Math

1.	In a two digit numbers, the digit in unit place is than twice in
Answer» ong>ANSWER: Q=? Q= 180-(70+20) Q= 180-90 Q= 90( *but* *for* RQS *ANGLE* Q *will* be 45°) In QPR *angle* P *will* be 180-(30+45) 180-75 105° *therefore* *QPR* *angle* P *will* be 105° *THANKU*

1.

In a two digit numbers, the digit in unit place is than twice in

Answer»

ong>ANSWER:

Q=?

Q= 180-(70+20)

Q= 180-90

Q= 90( but for RQS ANGLE Q will be 45°)

In QPR angle P will be

180-(30+45)

180-75

105°

therefore

QPR angle P will be 105°

THANKU

Discussion

2.	48a2b2-3 factorization
Answer» this MEMO ATTACHMENT

2.

48a2b2-3 factorization

Answer»

this MEMO ATTACHMENT

Discussion

3.	Jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest whole number.) 5,280 feet = 1 mile 27 feet per second 59 feet per second 132 feet per second 288 feet per second
Answer» ONG>ANSWER: B: 59 fps Step-by-step EXPLANATION:

3.

Jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest whole number.) 5,280 feet = 1 mile 27 feet per second 59 feet per second 132 feet per second 288 feet per second

Answer» ONG>ANSWER:

B: 59 fps

Step-by-step EXPLANATION:

Discussion

4.	The face value of 7 in 23725 is 7
Answer» ONG>ANSWER: hundreds PLEASE MARK me brilliant

4.

The face value of 7 in 23725 is 7

Answer» ONG>ANSWER:

hundreds

PLEASE MARK me brilliant

Discussion

5.	Differentiate w.r.t.x.y = xe^-x+7
Answer» ONG>Step-by-step explanation: Using product rule d/dx ( uv) = u'v + uv' y' = e^-X + x × e^-x × -1 + 0 = e^-x - xe^-x mark brainliest plz

5.

Differentiate w.r.t.x.y = xe^-x+7

Answer» ONG>Step-by-step explanation:

Using product rule d/dx ( uv) = u'v + uv'

y' = e^-X + x × e^-x × -1 + 0

= e^-x - xe^-x

mark brainliest plz

Discussion

6.	(-8)× (-5) + (-6) what is the answer of this solution please tell
Answer» BHI NHI pata koi BAAT nhi it's 34

6.

(-8)× (-5) + (-6) what is the answer of this solution please tell

Answer» BHI NHI pata

koi BAAT nhi it's 34

Discussion

7.	Find the value p(1) for the p(x)=x^2+5x+4
Answer» ONG>Answer:P> 10 Step-by-step EXPLANATION: p(1)=1+5+4=10 this the answe

7.

Find the value p(1) for the p(x)=x^2+5x+4

Answer» ONG>Answer:P>

10

Step-by-step EXPLANATION:

p(1)=1+5+4=10

this the answe

Discussion

8.	Write additive inverse of 2/3 and -7/9
Answer» ONG>Step-by-step EXPLANATION: $\frac{2}{3} \:-> \frac{ - 2}{3}$ $\frac{ - 7}{9} - > \frac{7}{9}$ *HOPE* *it's* *HELPFUL*

8.

Write additive inverse of 2/3 and -7/9

Answer» ONG>Step-by-step EXPLANATION:

$\frac{2}{3} \:-> \frac{ - 2}{3}$

$\frac{ - 7}{9} - > \frac{7}{9}$

HOPE it's HELPFUL

Discussion

9.	24678 is 15587 then 46823 is?
Answer» ???????????????????

9.

24678 is 15587 then 46823 is?

Answer»

???????????????????

Discussion

10.	Does the clouser property follows under division on rational numbers explain with examples
Answer» ong>Answer: Rational numbers are not CLOSED under DIVISION... Step-by-step explanation: When we divide with TWO rational numbers, we MAY or may not GET a rational number as an answer . This means rational numbers are not closed under division. For example : 11/15÷2/5 = 11/2 ( where 11/2 is a rational number) but 9/2÷0 = not defined ( not a rational number ) HOPE SO THE ANSWER AND EXPLANATION IS HELPFUL

10.

Does the clouser property follows under division on rational numbers explain with examples

Answer»

ong>Answer:

Rational numbers are not CLOSED under DIVISION...

Step-by-step explanation:

When we divide with TWO rational numbers, we MAY or may not GET a rational number as an answer . This means rational numbers are not closed under division. For example : 11/15÷2/5 = 11/2 ( where 11/2 is a rational number) but 9/2÷0 = not defined ( not a rational number )

HOPE SO THE ANSWER AND EXPLANATION IS HELPFUL

Discussion

11.	12 litres of water are poured into an aquarium of dimensions 50 cm length, 30 cm breadth and 40 cm height. How high (in cm) will the water rise? (1lt = 1000 cm 3) [1 marks]
Answer» ong>Answer: hight of WATER rise is 8 cm Step-by-step explanation: 12 litres = 12000 cm³ hight of water rise , h = ? length , l = 50 cm bredth , b = 30 cm lbh = volume 50 × 30 × h = 12000 h = 12000/ 50×30 = 120/ 15 = 8 If it's helpful plz MARK brainliest

11.

12 litres of water are poured into an aquarium of dimensions 50 cm length, 30 cm breadth and 40 cm height. How high (in cm) will the water rise? (1lt = 1000 cm 3) [1 marks]

Answer»

ong>Answer:

hight of WATER rise is 8 cm

Step-by-step explanation:

12 litres = 12000 cm³

hight of water rise , h = ?

length , l = 50 cm

bredth , b = 30 cm

lbh = volume

50 × 30 × h = 12000

h = 12000/ 50×30

= 120/ 15

= 8

If it's helpful plz MARK brainliest

Discussion

12.	Jshछधठधडःडःडलठपदपjsjvshdhdhrhdufu
Answer» ONG>ANSWER: 10203040506070809000010203040506060708

12.

Jshछधठधडःडःडलठपदपjsjvshdhdhrhdufu

Answer» ONG>ANSWER:

10203040506070809000010203040506060708

Discussion

13.	The weight of 4 sweet boxes is 4.32kg find the weight of one sweet box
Answer» ONG>Answer: 1.08 Step-by-step explanation: 4 BOXES -4.32 so 1 box-4.32/4 so it is 1.08

13.

The weight of 4 sweet boxes is 4.32kg find the weight of one sweet box

Answer» ONG>Answer:

1.08

Step-by-step explanation:

4 BOXES -4.32

so 1 box-4.32/4

so it is 1.08

Discussion

14.	Simi covered 89/12 km in 2 hour on bicycle and 20/4 km another 1 hour on foot find the total distance covered by amit in 3 hours
Answer» ong>Answer: LCM OF 12 AND 4= 12 Distance covered by foot -- 20/4km Distance covered by BICYCLE-- 89/12km 20/4×3/3=60/12 km and 89/12×1/1= 89/12 km. now: 60/12+89/12= 149/12km. *PLEASE MARK AS BRAINLIEST AND HOPE IT HELPS YOU.*

14.

Simi covered 89/12 km in 2 hour on bicycle and 20/4 km another 1 hour on foot find the total distance covered by amit in 3 hours

Answer»

ong>Answer:

LCM OF 12 AND 4= 12

Distance covered by foot -- 20/4km

Distance covered by BICYCLE-- 89/12km

20/4×3/3=60/12 km

and

89/12×1/1= 89/12 km.

now: 60/12+89/12= 149/12km.

PLEASE MARK AS BRAINLIEST AND HOPE IT HELPS YOU.

Discussion

15.	The sum of the zerose of the polynomial 3x2– 10x+3
Answer» ong>Answer: The other zeroes of the given QUADRATIC polynomial is 3 Given polynomial : If one zero is To find : The other zero of the polynomial As we know if ax² + bx +c is the standard form of quadratic polynomial Then comparing we get a = 3 , b = -10 , c= 3 Now the SUM of zeroes is given by Hence, the other zeroes of the given quadratic polynomial is 3 #Learn more Find a quadratic poly, the sum of zeroes is 0 and one zero is 5 brainly.in/question/493662

15.

The sum of the zerose of the polynomial 3x2– 10x+3

Answer»

ong>Answer:

The other zeroes of the given QUADRATIC polynomial is 3

Given polynomial :

If one zero is

To find : The other zero of the polynomial

As we know if ax² + bx +c is the standard form of quadratic polynomial

Then comparing we get

a = 3 , b = -10 , c= 3

Now the SUM of zeroes is given by

Hence, the other zeroes of the given quadratic polynomial is 3

#Learn more

Find a quadratic poly, the sum of zeroes is 0 and one zero is 5

brainly.in/question/493662

Discussion

16.	If n(a)=50;n(b)=20 and n(aub)=10 and if the no. of elements of a∆b is k then the sum of digits if k is
Answer» ONG>Step-by-step EXPLANATION: aub=na+nb-anb 10=50+20-anb anb=70-10 anb=60

16.

If n(a)=50;n(b)=20 and n(aub)=10 and if the no. of elements of a∆b is k then the sum of digits if k is

Answer» ONG>Step-by-step EXPLANATION:

aub=na+nb-anb

10=50+20-anb

anb=70-10

anb=60

Discussion

17.	Find the maximum and minimum value of X^3Y^2(1-x-y)
Answer» ong>Step-by-step explanation: We can expand f to f ( x , y ) = x y − x 2 y − x y 2 . Next, find the PARTIAL derivatives and set them equal to zero. ∂ f ∂ x = y − 2 x y − y 2 = y ( 1 − 2 x − y ) = 0 ∂ f ∂ y = x − x 2 − 2 x y = x ( 1 − x − 2 y ) = 0 Clearly, ( x , y ) = ( 0 , 0 ) , ( 1 , 0 ) , and ( 0 , 1 ) are solutions to this system, and so are CRITICAL points of f . The other solution can be found from the system 1 − 2 x − y = 0 , 1 − x − 2 y = 0 . Solving the first equation for y in terms of x gives y = 1 − 2 x , which can be plugged into the second equation to GET 1 − x − 2 ( 1 − 2 x ) = 0 ⇒ − 1 + 3 x = 0 ⇒ x = 1 3 . From this, y = 1 − 2 ( 1 3 ) = 1 − 2 3 = 1 3 as well. To test the nature of these critical points, we find second derivatives: ∂ 2 f ∂ x 2 = − 2 y , ∂ 2 f ∂ y 2 = − 2 x , and ∂ 2 f ∂ x ∂ y = ∂ 2 f ∂ y ∂ x = 1 − 2 x − 2 y . The discriminant is therefore: D = 4 x y − ( 1 − 2 x − 2 y ) 2 = 4 x y − ( 1 − 2 x − 2 y − 2 x + 4 x 2 + 4 x y − 2 y + 4 x y + 4 y 2 ) = 4 x + 4 y − 4 x 2 − 4 y 2 − 4 x y − 1 Plugging the first three critical points in gives: D ( 0 , 0 ) = − 1 < 0 , D ( 1 , 0 ) = 4 − 4 − 1 = − 1 < 0 , and D ( 0 , 1 ) = 4 − 4 − 1 = − 1 < 0 , making these points saddle points. Plugging in the last critical point gives D ( 1 3 , 1 3 ) = 4 3 + 4 3 − 4 9 − 4 9 − 4 9 − 1 = 1 3 > 0 . Also note that ∂ 2 f ∂ x 2 ( 1 3 , 1 3 ) = − 2 3 < 0 . Therefore, ( 1 3 , 1 3 ) is a location of a LOCAL maximum value of f . You can check that the local maximum value itself is f ( 1 3 , 1 3 ) = 1 27 . Below is a picture of the contour map (of level curves) of f (the curves where the OUTPUT of f is constant), along with the 4 critical points of f .

17.

Find the maximum and minimum value of X^3Y^2(1-x-y)

Answer»

ong>Step-by-step explanation:

We can expand

f

to

f

(

x

,

y

)

=

x

y

−

x

2

y

−

x

y

2

. Next, find the PARTIAL derivatives and set them equal to zero.

∂

f

∂

x

=

y

−

2

x

y

−

y

2

=

y

(

1

−

2

x

−

y

)

=

0

∂

f

∂

y

=

x

−

x

2

−

2

x

y

=

x

(

1

−

x

−

2

y

)

=

0

Clearly,

(

x

,

y

)

=

(

0

,

0

)

,

(

1

,

0

)

,

and

(

0

,

1

)

are solutions to this system, and so are CRITICAL points of

f

. The other solution can be found from the system

1

−

2

x

−

y

=

0

,

1

−

x

−

2

y

=

0

. Solving the first equation for

y

in terms of

x

gives

y

=

1

−

2

x

, which can be plugged into the second equation to GET

1

−

x

−

2

(

1

−

2

x

)

=

0

⇒

−

1

+

3

x

=

0

⇒

x

=

1

3

. From this,

y

=

1

−

2

(

1

3

)

=

1

−

2

3

=

1

3

as well.

To test the nature of these critical points, we find second derivatives:

∂

2

f

∂

x

2

=

−

2

y

,

∂

2

f

∂

y

2

=

−

2

x

, and

∂

2

f

∂

x

∂

y

=

∂

2

f

∂

y

∂

x

=

1

−

2

x

−

2

y

.

The discriminant is therefore:

D

=

4

x

y

−

(

1

−

2

x

−

2

y

)

2

=

4

x

y

−

(

1

−

2

x

−

2

y

−

2

x

+

4

x

2

+

4

x

y

−

2

y

+

4

x

y

+

4

y

2

)

=

4

x

+

4

y

−

4

x

2

−

4

y

2

−

4

x

y

−

1

Plugging the first three critical points in gives:

D

(

0

,

0

)

=

−

1

<

0

,

D

(

1

,

0

)

=

4

−

4

−

1

=

−

1

<

0

, and

D

(

0

,

1

)

=

4

−

4

−

1

=

−

1

<

0

, making these points saddle points.

Plugging in the last critical point gives

D

(

1

3

,

1

3

)

=

4

3

+

4

3

−

4

9

−

4

9

−

4

9

−

1

=

1

3

>

0

. Also note that

∂

2

f

∂

x

2

(

1

3

,

1

3

)

=

−

2

3

<

0

. Therefore,

(

1

3

,

1

3

)

is a location of a LOCAL maximum value of

f

. You can check that the local maximum value itself is

f

(

1

3

,

1

3

)

=

1

27

.

Below is a picture of the contour map (of level curves) of

f

(the curves where the OUTPUT of

f

is constant), along with the 4 critical points of

f

.

Discussion

18.	Given log10x=a,log10y=band log10z=c 1) write down 10^2a-3 in terms of x 2)write down 10^3b-1 in terms of y 3)if log10 p=2a+b/2-3c,express p in terms of x,yand z
Answer» ONG>Answer: 2) WRITE down 10^3b-1in TERMS of y

Discussion

19.	3x (4y² + z⁵) =? What the answer?
Answer» ONG>Answer: Distributive PROPERTY of multiplication over addition 12xy^2+3xz^5

19.

3x (4y² + z⁵) =? What the answer?

Answer» ONG>Answer:

Distributive PROPERTY of multiplication over addition

12xy^2+3xz^5

Discussion

20.	What should be added to -7/3 to get 3 / 7
Answer» ONG>ANSWER: answer = 58/21 Step-by-step EXPLANATION: hope my answers will help you.

20.

What should be added to -7/3 to get 3 / 7

Answer» ONG>ANSWER:

answer = 58/21

Step-by-step EXPLANATION:

hope my answers will help you.

Discussion

21.	What can the maximum number of digits be in the repeating block of the decimal expansion of 1/13
Answer» ong>Step-by-step explanation: the maximum number of digits be in the REPEATING block of the decimal expansion of 1/13 is 9/13 . hope it HELPS !!!!

21.

What can the maximum number of digits be in the repeating block of the decimal expansion of 1/13

Answer»

ong>Step-by-step explanation:

the maximum number of digits be in the REPEATING block of the decimal expansion of 1/13 is 9/13 .

hope it HELPS !!!!

Discussion

22.	If the interest is compounded half yearly,than the time period becomes dash and rate is taken dash
Answer» ong>Answer: time period = 2n e.g if the time period is 4 years then in compounded half yearly INTEREST it will BECOME 2(4) Rate of interest = R /200 hope it will HELP you... please follow me....

22.

If the interest is compounded half yearly,than the time period becomes dash and rate is taken dash

Answer»

ong>Answer:

time period = 2n e.g if the time period is 4 years then in compounded half yearly INTEREST it will BECOME 2(4)

Rate of interest = R /200

hope it will HELP you...

please follow me....

Discussion

23.	A rectangle field is 100 m by 80 m. find the ratio of . i) length to its breadth. ii) breadth to its perimeter.
Answer» er Step-by-step explanation: 1-5:4 2-8:36 mark the BRAINLIEST

23.

A rectangle field is 100 m by 80 m. find the ratio of . i) length to its breadth. ii) breadth to its perimeter.

Answer»

er

Step-by-step explanation:

1-5:4

2-8:36

mark the BRAINLIEST

Discussion

24.	Calculate the areaof triangle ABCA) 12B) 12513E) 14.5
Answer» ong>Answer: Calculated ........... Step-by-step EXPLANATION: DONE, don't thank I KNOW

24.

Calculate the areaof triangle ABCA) 12B) 12513E) 14.5

Answer»

ong>Answer:

Calculated ...........

Step-by-step EXPLANATION:

DONE, don't thank I KNOW

Discussion

25.	(a^n - b^n) is always divisible by (a - b). If n is- (A) odd number(B) even number(C) natural number(D) prime number
Answer» ONG>Answer: LET b=0 now, we can write ${a}^{n} - {b}^{n}$ as ${a}^{n}$ and a-b = a (because we let b=0) now a^n can be devided by a if a is NATURAL NUMBER

25.

(a^n - b^n) is always divisible by (a - b). If n is- (A) odd number(B) even number(C) natural number(D) prime number

Answer» ONG>Answer:

LET b=0

now, we can write

${a}^{n} - {b}^{n}$

as

${a}^{n}$

and a-b = a (because we let b=0)

now a^n can be devided by a if a is NATURAL NUMBER

Discussion

26.	Why sin(180-theta)= sin(theta)but cos(180-theta)= -cos(theta)??????why sin is positive and cos would be negative??plz explain correctly i'll mark Brainliest and follow u....!!!!! plz answer fast!!!!
Answer»

Discussion

27.	Identify the property used in 78 + 37 = 37 + 78
Answer» ong>Answer: commutative PROPERTY of ADDITION

27.

Identify the property used in 78 + 37 = 37 + 78

Answer»

ong>Answer:

commutative PROPERTY of ADDITION

Discussion

28.	ABC is a scalene triangle in which side AB is produced to D and side AC is produced to E .Then the angle bisectors of angle DBC and angle ECB met reach other at O . Then OA is joined . Prove that AO is bisector of angle BAC.YOU MUST USE CONGRUENCY OF TRIANLE Correct answer will be marked as brainlist and unimportant answers will be reported
Answer» ONG>ANSWER: ..............................

Discussion

29.	Which number line shows the solution to −4 − (−1)? A A number line is shown from negative 5 to 0 to positive 5. There are increments of 1 on either side of the number line. All the numbers are labeled on either side of the number line. An arrow pointing from 0 to 4 is shown. Above this, another arrow pointing from 4 to 5 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow. B A number line is shown from negative 5 to 0 to positive 5. There are increments of 1 on either side of the number line. All the numbers are labeled on either side of the number line. An arrow pointing from 0 to 4 is shown. Above this, another arrow pointing from 4 to 3 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow. C A number line is shown from negative 5 to 0 to positive 5. There are increments of 1 on either side of the number line. All the numbers are labeled on either side of the number line. An arrow pointing from 0 to negative 4 is shown. Above this, another arrow pointing from negative 4 to negative 5 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow. D A number line is shown from negative 5 to 0 to positive 5. There are increments of 1 on either side of the number line. All the numbers are labeled on either side of the number line. An arrow pointing from 0 to negative 4 is shown. Above this, another arrow pointing from negative 4 to negative 3 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow.
Answer» ong>Answer: Me and my FAMILY loves to watch Best of Luck Nikki. We WANT more episodes in YouTube. Please carry on the serial and do not close this. All characters are superb. ALSO do not change the characters. The family is AWESOME. The DIRECTION and script is awesome.

29.

Which number line shows the solution to −4 − (−1)? A A number line is shown from negative 5 to 0 to positive 5. There are increments of 1 on either side of the number line. All the numbers are labeled on either side of the number line. An arrow pointing from 0 to 4 is shown. Above this, another arrow pointing from 4 to 5 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow. B A number line is shown from negative 5 to 0 to positive 5. There are increments of 1 on either side of the number line. All the numbers are labeled on either side of the number line. An arrow pointing from 0 to 4 is shown. Above this, another arrow pointing from 4 to 3 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow. C A number line is shown from negative 5 to 0 to positive 5. There are increments of 1 on either side of the number line. All the numbers are labeled on either side of the number line. An arrow pointing from 0 to negative 4 is shown. Above this, another arrow pointing from negative 4 to negative 5 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow. D A number line is shown from negative 5 to 0 to positive 5. There are increments of 1 on either side of the number line. All the numbers are labeled on either side of the number line. An arrow pointing from 0 to negative 4 is shown. Above this, another arrow pointing from negative 4 to negative 3 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow.

Answer»

ong>Answer:

Me and my FAMILY loves to watch Best of Luck Nikki. We WANT more episodes in YouTube. Please carry on the serial and do not close this. All characters are superb. ALSO do not change the characters. The family is AWESOME. The DIRECTION and script is awesome.

Discussion

30.	The angle of elevation of the top of a tower from a point on the ground , which is 30m away from the foot of the tower , is 30 degree . Find the height of the tower.
Answer» ONG>ANSWER: we will take $tan(30)$ which is equal to $\frac{1}{ \sqrt{3} }$ LET HEIGHT be x so $\frac{1}{ \sqrt{3} } = \: \frac{x}{30} \\ \frac{1}{3} = \frac{ {x}^{2} }{900} \\ {x}^{2} = 300 \\ x = 10 \sqrt{3}$ that should be the answer according to me hope it helps

30.

The angle of elevation of the top of a tower from a point on the ground , which is 30m away from the foot of the tower , is 30 degree . Find the height of the tower.

Answer» ONG>ANSWER:

we will take

$tan(30)$

which is equal to

$\frac{1}{ \sqrt{3} }$

LET HEIGHT be x

so

$\frac{1}{ \sqrt{3} } = \: \frac{x}{30} \\ \frac{1}{3} = \frac{ {x}^{2} }{900} \\ {x}^{2} = 300 \\ x = 10 \sqrt{3}$

that should be the answer

according to me

hope it helps

Discussion

31.	A can do 1 by 2 of a piece of work in 5 days. B can do 3 by 5 of the same work in 9 days and C can do 2 by 3 of that work in 8 days. In how many days can three of them, together do the work? (1) 3 days (2) 5 days (3) 9 by 2 days (4) 4 days
Answer» ong>Answer: $\huge\underline\bold {Answer:}$ ATQ, A can do 1/2 of the WORK in 5 days => A can do the whole work in 5 × 2/1 = 10 days B can do 3/5 of the work in 9 days => B can do the whole work in 9 × 5/3 = 12 days C can do 2/3 of that work in 8 days => C can do the whole work in 8 × 3/2 days = 12 days. Therefore, ( A + B + C)’s 1 days’ work = 1/10 + 1/15 + 1/12 $= \frac{6 + 4 + 5}{60} = \frac{15}{60} = \frac{1}{4}$ HENCE, A + B + C can complete the whole work in 4 days

31.

A can do 1 by 2 of a piece of work in 5 days. B can do 3 by 5 of the same work in 9 days and C can do 2 by 3 of that work in 8 days. In how many days can three of them, together do the work? (1) 3 days (2) 5 days (3) 9 by 2 days (4) 4 days

Answer»

ong>Answer:

$\huge\underline\bold {Answer:}$

ATQ,

A can do 1/2 of the WORK in 5 days

=> A can do the whole work in 5 × 2/1 = 10 days

B can do 3/5 of the work in 9 days

=> B can do the whole work in 9 × 5/3 = 12 days

C can do 2/3 of that work in 8 days

=> C can do the whole work in 8 × 3/2 days = 12 days.

Therefore, ( A + B + C)’s 1 days’ work

= 1/10 + 1/15 + 1/12

$= \frac{6 + 4 + 5}{60} = \frac{15}{60} = \frac{1}{4}$

HENCE, A + B + C can complete the whole work in 4 days

Discussion

32.	I deposited $500 in bank and a bank offers 4% interest annually determine the amount in account after 3 years. Please answer this question with solution.
Answer» o the ANSWER is $560.

32.

I deposited $500 in bank and a bank offers 4% interest annually determine the amount in account after 3 years. Please answer this question with solution.

Answer»

o the ANSWER is $560.

Discussion

33.	Solve the following pair of equations graphically. x+3y=6, 2x-3y=12.
Answer» ONG>ANSWER: x+3y=6, 2×-3y=12, x+3y=18,

Discussion

34.	Please anyone here to help me . Don't copy from Google as it is not having answer. find value of x in 1/x+4 - 1/x-7 = 30please please find answer
Answer» 2 roots of given Quadratic EQUATION. Explanation: Given \frac{1}{X+4}-\frac{1}{x-7}=\frac{11}{30} x+4 1 − x−7 1 = 30 11 \implies \frac{[x-7-(x+4)]}{(x+4)(x-7)}=\frac{11}{30}⟹ (x+4)(x−7) [x−7−(x+4)] = 30 11 \implies\frac{x-7-x-4}{x^{2}-7x+4x-28}=\frac{11}{30}⟹ x 2 −7x+4x−28 x−7−x−4 = 30 11 \implies\frac{-11}{x^{2}-3x-28}=\frac{11}{30}⟹ x 2 −3x−28 −11 = 30 11 Do the cross multiplication, we get => 30 = 11(x²-3x-28)/(-11) => 30 = -(x²-3x-28) => x²-3x-28+30 =0 => x²-3x+2=0 Splitting the MIDDLE term, we get => x²-1x-2x+2 =0 => x(x-1)-2(x-1)=0 => (x-1)(x-2)=0 =>x-1 = 0 or x-2 = 0 => x = 1 or x = 2 Therefore, Roots of the given quadratic equation are 1 , 2 ••• MARK ME AS BRAINIEST .. FOLLOW ME..✌️✌️

34.

Please anyone here to help me . Don't copy from Google as it is not having answer. find value of x in 1/x+4 - 1/x-7 = 30please please find answer

Answer»

2 roots of given Quadratic EQUATION.

Explanation:

Given

\frac{1}{X+4}-\frac{1}{x-7}=\frac{11}{30}

x+4

1

−

x−7

1

=

30

11

\implies \frac{[x-7-(x+4)]}{(x+4)(x-7)}=\frac{11}{30}⟹

(x+4)(x−7)

[x−7−(x+4)]

=

30

11

\implies\frac{x-7-x-4}{x^{2}-7x+4x-28}=\frac{11}{30}⟹

x

2

−7x+4x−28

x−7−x−4

=

30

11

\implies\frac{-11}{x^{2}-3x-28}=\frac{11}{30}⟹

x

2

−3x−28

−11

=

30

11

Do the cross multiplication, we get

=> 30 = 11(x²-3x-28)/(-11)

=> 30 = -(x²-3x-28)

=> x²-3x-28+30 =0

=> x²-3x+2=0

Splitting the MIDDLE term, we get

=> x²-1x-2x+2 =0

=> x(x-1)-2(x-1)=0

=> (x-1)(x-2)=0

=>x-1 = 0 or x-2 = 0

=> x = 1 or x = 2

Therefore,

Roots of the given quadratic equation are 1 , 2

•••

MARK ME AS BRAINIEST ..

FOLLOW ME..✌️✌️

Discussion

35.	What is the full form of diksha
Answer» ong>Step-by-step explanation: DIGITAL INFRASTRUCTURE for Knowledge Sharing please make me brainlist Dear and FOLLOW me

35.

What is the full form of diksha

Answer»

ong>Step-by-step explanation:

DIGITAL INFRASTRUCTURE for Knowledge Sharing

please make me brainlist Dear and FOLLOW me

Discussion

36.	Simplify : 2 + 2 ÷ 2 Points ♥️♥️
Answer» he RULE of bodmas first we have to DIVIDE then MULTIPLY and then ADD so, according to the rule 2/2=1 2+1=3

36.

Simplify : 2 + 2 ÷ 2 Points ♥️♥️

Answer»

he RULE of bodmas first we have to DIVIDE then MULTIPLY and then ADD so, according to the rule

2/2=1

2+1=3

Discussion

37.	148(82-x)=100 plz answer this question
Answer» ONG>Answer: 148 (82-X) = 100 82-x = 100/148' 82 - x = 25/37 82 - 25/37 = x 3034/37 - 25/37 = x 3009/37 = x x= 81.2 Step-by-step EXPLANATION:

37.

148(82-x)=100 plz answer this question

Answer» ONG>Answer:

148 (82-X) = 100

82-x = 100/148'

82 - x = 25/37

82 - 25/37 = x

3034/37 - 25/37 = x

3009/37 = x

x= 81.2

Step-by-step EXPLANATION:

Discussion

38.	A businessman instituted an annual award in a city school, with a part of the awardgiven to the school itself to improve itsfacilities. It was stated that if a student froma wealthy family were to top the annualexamination, the school would receivetwice the amount awarded to the student.On the other hand, if a student from a poorfamily were to top the annual examination,the student would be awarded twice theamount that the school would receive. Inone year, two students, one rich and onepoor, jointly topped the annual examination.What fraction of the award money did theschool receive in this case?
Answer» ong>ANSWER: The poor STUDENT gets (1/3) of the prize money. The rich student gets (1/6) of the prize money. Step-by-step explanation: Let N be the amount of the prize money. With respect to the rich student, the prize money gets divided into a 1:2 ratio. So the rich student gets 1/3 of N/2 = (1/6)N and the school gets (2/3) of N/2 = (1/3)N The opposite is true for the poor student. So the prize money is divided as follows: (1/6)N goes to the rich student (1/3)N+(1/6)N = (3/6)N = (1/2)N goes to the school (1/3)N goes to the poor student So the school gets half of the price money. The poor student gets (1/3) of the prize money. The rich student gets (1/6) of the prize money. Hope it HELPS!!

38.

A businessman instituted an annual award in a city school, with a part of the awardgiven to the school itself to improve itsfacilities. It was stated that if a student froma wealthy family were to top the annualexamination, the school would receivetwice the amount awarded to the student.On the other hand, if a student from a poorfamily were to top the annual examination,the student would be awarded twice theamount that the school would receive. Inone year, two students, one rich and onepoor, jointly topped the annual examination.What fraction of the award money did theschool receive in this case?

Answer»

ong>ANSWER:

The poor STUDENT gets (1/3) of the prize money.

The rich student gets (1/6) of the prize money.

Step-by-step explanation:

Let N be the amount of the prize money.

With respect to the rich student, the prize money gets

divided into a 1:2 ratio.

So the rich student gets 1/3 of N/2 = (1/6)N

and the school gets (2/3) of N/2 = (1/3)N

The opposite is true for the poor student.

So the prize money is divided as follows:

(1/6)N goes to the rich student

(1/3)N+(1/6)N = (3/6)N = (1/2)N goes to the school

(1/3)N goes to the poor student

So the school gets half of the price money.

The poor student gets (1/3) of the prize money.

The rich student gets (1/6) of the prize money.

Hope it HELPS!!

Discussion

39.	____rounds it takes to read one hour. (urgent )
Answer» ONG>ANSWER: MAY BE a HOUR HAND OF A CLOCK

39.

____rounds it takes to read one hour. (urgent )

Answer» ONG>ANSWER:

MAY BE a HOUR HAND OF A CLOCK

Discussion

40.	Differentiate w.r.t.xy= 5x+9 ------------- 2x-10
Answer» ONG>ANSWER: fgbn Step-by-step EXPLANATION: cfghn okjhg fghj nbn kiujh [poiu

40.

Differentiate w.r.t.xy= 5x+9 ------------- 2x-10

Answer» ONG>ANSWER:

fgbn

Step-by-step EXPLANATION:

cfghn

okjhg

fghj

nbn

kiujh

[poiu

Discussion

41.	No of obse logyYtogn - x2r1.098O30.69312.4802123.041.09863213.551.3862u u3
Answer» ONG>ANSWER: what is this brother/sister??? cannot UNDERSTAND

41.

No of obse logyYtogn - x2r1.098O30.69312.4802123.041.09863213.551.3862u u3

Answer» ONG>ANSWER:

what is this brother/sister???

cannot UNDERSTAND

Discussion

42.	Find the zeores of the following polynomials i) p(x)=(x-3) (x-2)
Answer» ong>ANSWER: ZEROS are 3 and 2 Step-by-step EXPLANATION:

42.

Find the zeores of the following polynomials i) p(x)=(x-3) (x-2)

Answer»

ong>ANSWER:

ZEROS are 3 and 2

Step-by-step EXPLANATION:

Discussion

43.	83 using identities find the value of @ 72²182
Answer» ONG>Answer: 117 = 100+17 83 = 100-17 NOW, 117 × 83 (100+17) (100-17) USING IDENTITY (A+B)(A-B) = A²-B² NOW, (100+17) (100-17) 100²-17² 10000-289 9711 PLZ MARK IT AS BRAINIEST ANSWER AND DROP A ♥

43.

83 using identities find the value of @ 72²182

Answer» ONG>Answer:

117 = 100+17

83 = 100-17

NOW,

117 × 83

(100+17) (100-17)

USING IDENTITY (A+B)(A-B) = A²-B²

NOW,

(100+17) (100-17)

100²-17²

10000-289

9711

PLZ MARK IT AS BRAINIEST ANSWER AND DROP A ♥

Discussion

44.	What is integer I wait for answer
Answer» ong>Answer: a number which is not a FRACTION; a WHOLE number. Step-by-step explanation: PLS MARK me as a brainlist

44.

What is integer I wait for answer

Answer»

ong>Answer:

a number which is not a FRACTION; a WHOLE number.

Step-by-step explanation:

PLS MARK me as a brainlist

Discussion

45.	The cost of milk per litre is Rs 23. A dairy sold 35 litres of milk on one day and 65 litres of milk on the next day. Find the total sale in rupees.
Answer» ONG>Answer: 100 RUPEES SALE Step-by-step EXPLANATION: .......,................. .

45.

The cost of milk per litre is Rs 23. A dairy sold 35 litres of milk on one day and 65 litres of milk on the next day. Find the total sale in rupees.

Answer» ONG>Answer:

100 RUPEES SALE

Step-by-step EXPLANATION:

.......,.................

.

Discussion

46.	Find an acute angle A, when (cosA-sinA)/(cosA+sinA) = (1-√3)/(1+√3)
Answer» ONG>ANSWER: SORRY......☺☺☺☺

Discussion

47.	* 3. How much swork is done is moving a charge of 3C across two points giving a patential difference 6V
Answer» jsndvdcdvsbs jshsvdcdcsvbs Step-by-step EXPLANATION: hzsvvsvsnsnsjddvvddbdbdndjfkfk. djhfbhdbdbdvdv dvxbxnxmkdcgxhdjsknsns. dbdbdbdvdbdbdbd. jdjdjdbbxbxnx. jdjdhddhjdjddjdj. jdhdbdxbnxndnsnsnsbsb

47.

* 3. How much swork is done is moving a charge of 3C across two points giving a patential difference 6V

Answer»

jsndvdcdvsbs jshsvdcdcsvbs

Step-by-step EXPLANATION:

hzsvvsvsnsnsjddvvddbdbdndjfkfk. djhfbhdbdbdvdv dvxbxnxmkdcgxhdjsknsns. dbdbdbdvdbdbdbd. jdjdjdbbxbxnx. jdjdhddhjdjddjdj. jdhdbdxbnxndnsnsnsbsb

Discussion

48.	Write 0.365(bar on 65) in the form of p/q
Answer» ONG>Answer: 362/990 Step-by-step EXPLANATION: LET 0.365 be x 100x = 36.5 100x-x= 36.5656.... - 0.36565... 99X = 36.2 x= 36.2/99 x= 362/990

48.

Write 0.365(bar on 65) in the form of p/q

Answer» ONG>Answer:

362/990

Step-by-step EXPLANATION:

LET 0.365 be x

100x = 36.5

100x-x= 36.5656.... - 0.36565...

99X = 36.2

x= 36.2/99

x= 362/990

Discussion

49.	The sum of two integer is (-30). Find the other integer, if one of the integer 15.
Answer» ONG>Answer: let other integer be x so 15+x = -30 x.= -30-15 x= -45 ... answer hope u found it USEFUL

49.

The sum of two integer is (-30). Find the other integer, if one of the integer 15.

Answer» ONG>Answer:

let other integer be x

so

15+x = -30

x.= -30-15

x= -45 ... answer

hope u found it USEFUL

Discussion

50.	(a) Find the square of (4x2 – 7y2 ) using an appropriate identity.
Answer» ONG>ANSWER: a2-b2=(a+b)(a-b) a=4x, b=7y (4x+7y)(4x-7y) 16x2-28xy+28xy- 49y2 16x2-49y2

50.

(a) Find the square of (4x2 – 7y2 ) using an appropriate identity.

Answer» ONG>ANSWER:

a2-b2=(a+b)(a-b)

a=4x, b=7y

(4x+7y)(4x-7y)

16x2-28xy+28xy- 49y2

16x2-49y2

Discussion

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