This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the equation of the line which is perthe given line meets y-axis. |
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Answer» ONG>ANSWER: You FORGOT to paste the picture |
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| 2. |
014 The following table shows the percentage of students who dropped out of school after completing high schoolYear 2005 20072009 2011 2013 2015 2017Page of5.52 5%4.9% 4%4.5%studentswhodroppedOutStudy the above table carefully and draw a line graph to depict it |
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Answer» ONG>Answer: 4554 Step-by-step EXPLANATION: |
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| 3. |
(a) 300 cm2 (b) 74 cm2(c) 250 cm?2.(a) 6(b) 9(c) 18breadth = 960 cm(a) Length = 20.5 m;(b) Breadth = 6 dm 4 cm; length = 7 dm 3 cm4. Find the area of a square whose side is 13 m.5. Find the breadth of a field whose area is 903 sqSelect the correct answer from the given four al1. The area of the rectangle with length 25 cm and breaThe perimeter of a square is 36 cm. Its area (in sq.3. Find the area of the rectangle whose: |
Answer» ONG>ANSWER:no don't KNOW the answer |
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| 4. |
77.44 का वर्गमूल निकाले। |
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Answer» ONG>Answer: 8.8 Step-by-step explanation: |
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| 6. |
227 The ratio of two numbers is 11 : 13 and their sum is 720. The greater of the two numbers is: ps: A.O 216B.390C.O 261D.O 330 |
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Answer» ong>Answer: the GREATER of the two no. is 390 Step-by-step EXPLANATION: the no. are 330 and 390 theri ratio is 11:13 and sum is 790 hope it HELPS |
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| 7. |
Solve the cyptarithm BB*B3=508 |
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Answer» ONG>Answer: 585 is answer Step-by-step EXPLANATION: Follow me Mark as brainlist Give thanks to all my ANSWERS |
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| 8. |
Of the exterior angles ota triangle is 105 mesto 3. 4. then find all the interior anthe interior angles of a triangle if they3.2(b) 1:1:2hat the sum of the angles of a quadrila(Hint: Join A and C and use the angley of triangles for AABC and AADC) |
Answer» ONG>Step-by-step explanation:MATE please resend this question so that I can able to answer u |
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| 9. |
X2+3x2y-4y3-x+y+3=0 asymptotes of following curve |
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Answer» ong>ANSWER: Step-by-step EXPLANATION: FOLLOW me Mark as brainlist Give thanks to all my answers |
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| 10. |
1 P(x) = 2x3 + 3x2 - Ux+6, then find the value of PL |
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Answer» ong>ANSWER: None Step-by-step explanation: SORRY I am also in 9th class i know the polynomial..... but i can't understand your question..... their no any value of x .... no any term LIKE PL...... can't understand UX |
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| 11. |
Find the median of following data 60,32,61,26,35,55,72,89,71 |
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Answer» ONG>ANSWER: kkkkkkkkkkkkkk Step-by-step EXPLANATION: |
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| 12. |
15 men can complete a work in 12 days they start work together. In how many days the total work will be finished when (1) After 4 days 5 more men join the work.(2) After 4 days 5 men left the work. |
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Answer» ONG>Answer: 15 MEN can do the work in 12days. After 4 days remains work of 8days. If 15 men can do that in (12-4) 8 days Then 1 MAN can do in 15x8= 120 days. After 4days 5 more men JOINS the work So total (15+5) 20 men can do the rest work (120÷20)= 6 days. Ans. |
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| 14. |
In a circle of radius 5 cm, a chord is of length 8cm. Find the length of another chord of same circle which is at a distance of 4 cm from the center of the circle ? * 2 points6 cm8 cm10 cm5cm |
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Answer» ME CAN U MAKE A CIRCLE ON YOUR PHONE I AM SORRY I CAN'T |
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| 15. |
2/5(2X-5)-3/4(3X-4)=9/2 |
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Answer» ONG>Answer: 4x/5-2-9x/4+3=9/2 4x/5-9x/4=9/2+2-3 (16x-45x)/20=9/2-1 -29x/20=(9-2)/2 -29x/20=7/2 -29x*2=7*20 -58x=140 x=140/-58 x=-70/29 x=-2.41 |
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| 16. |
Q.1 Draw the graph of each of the following equations (e) 2x + y = 0(d) y = -2(a) x = 5(c) 2x + 3y = 0(b) y = x |
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Answer» ong>ANSWER: ok Step-by-step explanation: PLEASE MARK as BRAINLEAST |
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| 17. |
The roots of 3x^+4x-7=0 |
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Answer» ONG>ANSWER: by middle TERM split method (factorization) Step-by-step explanation: 3x2+4x-7=0 3x2+7x-3x-7=0 x(3x+7)-(3x+7)=0 (x-1)(3x+7)=0 x=1,-7/3 PLZ plz plz plz plz plz plz mark me as brainliest, follow and LIKE also |
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| 18. |
Convert 4 by 5 to percent |
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Answer» ong>Answer: 80% FRACTION to percent conversion table HOPE it helps you. please make me BRAINLIEST! |
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| 19. |
Write the next three consecutive whole numbers of 9298 |
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Answer» ONG>Answer: 9289,9290,9291. . Step-by-step EXPLANATION: |
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| 20. |
Q.1 Find the solution of the equation a. 64 – 2(x – 1) = 14. b. 4-6x=30 c. 5y+35 = 70 d. 45 + 4(y+1)= 15 e. 50 – 6(y+5)= 40 |
| Answer» ONG>ANSWER: | |
| 22. |
The trace of the real 4×4 matrix U = exp(A), where A |
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Answer» ong>Answer: There is a theorem for DETERMINANTS that says that the determinant of the EXPONENTIAL function of a MATRIX is equal to the exponential function of the trace of the matrix; |
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| 23. |
Please answer my question quickly plz plz fast |
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Answer» ong>Step-by-step explanation:
first you mark me as BRAINLIST so then i will ANSWER your question also like and give me a star. |
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| 24. |
Ex-h. Factorine(1) 2a7 - 128a |
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Answer» ONG>ANSWER: Step-by-step EXPLANATION: |
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| 25. |
After 24 years i shall be 3 times as old as i was 4 years .find. my present age |
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Answer» present AGE be = y y + 24 = 3(y - 4) » y + 24 = 3Y - 12 » 2y = 36 » y = 18 YEARS |
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| 26. |
3. On comparing the ratios a to, and find out whether the lines represer Az 'b2following pair of linear equations intersect at a point ,are parallel or coinci2x + 3y - 9= 0 ; 4x + 6y - 18 = 0 |
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Answer» ONG>ANSWER: jkkkkkkkkkkkkkkkkk Step-by-step EXPLANATION: |
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| 27. |
If a, b,c are in G.P. then prove that a²+b² |
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Answer» ong>ANSWER: sinS+SIN(S-A)+sin(S-B)-sin(S-C)
{sinS-sin(S-C)}+{sin(S-A)+sin(S-B)}
2cos(2S-C)/2sin(C/2)+2sin(C/2)cos(B-A)/2
=2sinC/2[cos(A+B)/2 +cos(B-A)/2]
=2sinC/2 .[2cos(B/2)cos(A/2)]
=4cos(A/2)cos(B/2)sin(C/2)
THANKS AKA 0 Step-by-step explanation:NNNNNNNNHHHHHHGJJGJGJGJGJGJGJGJKNINIONININB HB JBJBJ |
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| 29. |
5. The ratio of the measurement of two cuboidsare 1:2:3 and 2:3:4. Find the ratio of theirvolumes.Solution: |
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Answer» ONG>Answer: 6 and 24 is the answer you can varify by renoxing RHE product and MAKING in fraction FORM and simplifing it |
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| 30. |
Evaluate A=2,B=1,C=10 |
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Answer» ong>Answer: first you MARK me as brainlist also LIKE and give me a star. |
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| 31. |
Type-4 Long Answer Type Qu11. Evaluate :(i) (99) 3(v) (402)12. Fyaluate : |
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Answer» ONG>Step-by-step EXPLANATION: टाइप फॉर लोंग आंसर टाइप जी यू इसका मतलब है पहला एक्ट 2003 |
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| 32. |
1)02)13)24)6Give me only correct answer |
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Answer» ong>Answer: The answer is 1 first MAKE me BRAINLIEST |
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| 34. |
Give examples of surd....... |
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Answer» ong>Answer: When we can't simplify a number to remove a square root (or CUBE root etc) then it is a surd. Example: √4 (square root of 4) can be simplified (to 2), so it is not a surd! The different TYPES of surds are as follows: Simple Surds – A surd that has only ONE term is called simple surd. ... Pure Surds – Surds which are completely irrational. ... SIMILAR Surds – The surds having the same common surds factor. |
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| 35. |
Kavita sings a song . which kind of noun in it |
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Answer» ONG>ANSWER: KAVITA is the noun. Step-by-step explanation: A noun is a name, place, animal or thing. Hence the name Kavita in the sentence is the noun. |
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| 37. |
In compound interest the _____goes on changing every conversion period. |
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Answer» ONG>ANSWER: In the compound interest the principal goes on CHANGING |
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| 38. |
The sum of two numbers is 65 ,and the two numbers are in the ratio 6ratio7 .Find the answers. |
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Answer» ong>Step-by-step explanation: LET, the constant in the ratio of the NUMBERS be x. Then, the TWO numbers will be 6x and 7x. A. T. Q, 6x+7x = 65 13x = 65 x = 65/13 x = 5 6x = 6(5) = 30 7x = 7(5) = 35 |
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| 39. |
X/10+y/5+1=15 and x-y/3=3 by elimination methode plzz solve it fast plzz |
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Answer» ONG>ANSWER: REFER to the ATTACHMENT |
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| 41. |
Why is the mean difference subtratced from cos in log book |
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Answer» ONG>ANSWER: Searchfrom google. Step-by-step EXPLANATION: |
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| 42. |
The measures of four strings are 35cm,40cm,and 80cm respectively.find the average of the measures of these strings. |
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Answer» ONG>ANSWER: these are only three strings given where is the FOURTH ONE ?? |
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| 43. |
Draw triangles with two sides 8cm and 6 cm and 12 sq cm what if the area is to be 24 sq cm |
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Answer» ONG>Answer: Answer Answer5.0/5 Area of a TRIANGLE = 1/2.a.c.sinB Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB. Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2 Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°. Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to DRAW. Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°. Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer. Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinB Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1 Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°. Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right ANGLED triangle in which a=8 cm ,c =6 cm and Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer..... Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer.....hope this hepls uh dear.... Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer.....hope this hepls uh dear....pls mark as brainliest Step-by-step explanation: I reall hope it is helping u so plz follow me |
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| 44. |
Ann's ribbon was 3/5m long. Xin's ribbon was 3/4m long than Ann's ribbon. what was the length of Xin's ribbon? |
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Answer» ONG>Xin's ribbon is 27/20 m long Step-by-step explanation: ANN's ribbon = 3/5 m Xin's ribbon = 3/4 m longer than ann's ONE = 3/5 + 3/4 = 3*⁴ + 3*⁵/20 LCM = 5×4=20 =12+15/20 =27/20 HOPE THIS WILL HELP YOU PERHAPS LOL STAY HOME,STAY SAFE AND TATA SEE YOU BYE,BYE |
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| 45. |
find the area of the trapezium in which sum of parallel side is 20 cm and distance between parallel side is 6 cm |
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Answer» ong>Answer: Given, Sum of two parallel sides (a+b) = 20cm Height = 6cm Area of Trapezium = 1/2(a+b)H => 1/2×20×6 => 10×6 => 60cm... Step-by-step EXPLANATION: Hope it HELPS you.... |
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| 46. |
Which of the following numbers is composite |
| Answer» ONG>Answer: | |
| 47. |
Can anybody answer these questions ...? |
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Answer» ONG>Answer: give ONE by one give BACK this question |
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| 48. |
r If the polymomial 2x^(3)-3x^(2)+ax+b is divided by x-2 and 2x+1 the remaindens are 7 and -3 respectively. Find the values of a' and b |
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Answer» ong>Answer: Make sure all WORDS are SPELLED correctly. Try DIFFERENT keywords. Try more GENERAL keywords. Try fewer keywords. |
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