332354 + Interview Questions in Secondary School in Math

1.	3x2
Answer» ong>ANSWER: don't KNOW bro better luck NEXT time

1.

3x2

Answer»

ong>ANSWER:

don't KNOW bro better luck NEXT time

Discussion

2.	6th std math practice set 34
Answer» ong>Answer: BAHI is a good boy and a good FRIEND of MINE who is a PLANT

2.

6th std math practice set 34

Answer»

ong>Answer:

BAHI is a good boy and a good FRIEND of MINE who is a PLANT

Discussion

3.	Find the product ( 5/4xy+7/4Y²)(3x-6yz)
Answer» ONG>ANSWER: Step-by-step EXPLANATION:

3.

Find the product ( 5/4xy+7/4Y²)(3x-6yz)

Answer» ONG>ANSWER:

Step-by-step EXPLANATION:

Discussion

4.	How many independent measurment to construct square
Answer» ong>ANSWER: STAY safe Step-by-step explanation: PLEASE MAKE me a brainly

4.

How many independent measurment to construct square

Answer»

ong>ANSWER:

STAY safe

Step-by-step explanation:

PLEASE MAKE me a brainly

Discussion

5.	If the mean of 5, 7, 9, 12, 5, 13, a, 10 is 8 then find the value of a.
Answer» ong>Hope it helps!! Mark this answer as brainliest if u FOUND it USEFUL and follow *me for quick and accurate answers...*

Discussion

6.	42' 30'74'56 find odd term
Answer» he ODD term I am not SURE.

Discussion

7.	7. What must be added to 2x⁴– 5x³+ 2x²– x - 3 so that the result is exactly divisible by (x - 2)?
Answer» ONG>ANSWER: DIVIDE the POLYNOMIAL s

7.

7. What must be added to 2x⁴– 5x³+ 2x²– x - 3 so that the result is exactly divisible by (x - 2)?

Answer» ONG>ANSWER:

DIVIDE the POLYNOMIAL s

Discussion

8.	Simplify 1. (✓3-√2)^2 square
Answer» ONG>ANSWER: $(\sqrt{3} {)}^{2} -( \sqrt{2} ) {}^{2} + 2 (\sqrt{3} )( \sqrt{2} )$ Step-by-step EXPLANATION: $3 - 2 + 4.89$ $1 + 4.89$ $5.89$

8.

Simplify 1. (✓3-√2)^2 square

Answer» ONG>ANSWER:

$(\sqrt{3} {)}^{2} -( \sqrt{2} ) {}^{2} + 2 (\sqrt{3} )( \sqrt{2} )$

Step-by-step EXPLANATION:

$3 - 2 + 4.89$

$1 + 4.89$

$5.89$

Discussion

9.	Sin^2+cos^2 = 1 then cos^2 + cos^4 =??
Answer» ong>Step-by-step explanation: SINA+sin 2 A=1⇒sinA=1−sin 2 A⇒(sinA) 2 =(COS 2A) 2 ⇒sin 2 A=cos 4 A⇒1−cos 2A=cos 4A⇒cos 2 A+cos 4 A=1

9.

Sin^2+cos^2 = 1 then cos^2 + cos^4 =??

Answer»

ong>Step-by-step explanation:

SINA+sin 2 A=1⇒sinA=1−sin 2 A⇒(sinA) 2 =(COS 2A) 2

⇒sin 2 A=cos 4 A⇒1−cos 2A=cos 4A⇒cos 2 A+cos 4 A=1

Discussion

10.	[Q.] If one end of the diameter of the circle is the point (–3, 2), then its other end is the point ?● Correct answer is:- ( 11 , 12) I want only steps....please give solutions.
Answer» strong>Question :- ⇒ If one end of the diameter of the circle $x^{2} + y^{2} -8x - 14y + c = 0$ is the point (–3, 2), then its other end is the point ? Answer:- ⇒ As , General equation of circle is ≡ $x^{2} + y^{2} + 2gx + 2fy + K = 0$ -----(1) ⇒ one end of circle is is B: ( -3 , 2 ) and other is A: ( a , b ).. ⇒ As , given equation of circle is ≡ $x^{2} + y^{2} -8x - 14y + c = 0$ comparing with equation (1).. We get , $<klux>G</klux> = - <klux>4</klux>$ and $f = - 7$ ⇒ As, we KNOW that center of circle is : C = ( -g , -f ) ⇒ So, center is C : ( 4 , 7 ). So, by using MID point ⇒ $( 4 , 7 ) =( \frac{a-3}{2} , \frac{b + 2}{2} )$ ∴ 8 = a - 3 . ⇒ a = 11 ∴ 14 = b + 2 . ⇒ b = 12 So, another point is $A(a,b) = ( 11,12 )$ I hope this will help you thank you.

10.

[Q.] If one end of the diameter of the circle is the point (–3, 2), then its other end is the point ?● Correct answer is:- ( 11 , 12) I want only steps....please give solutions.

Answer»

strong>Question :-

⇒ If one end of the diameter of the circle $x^{2} + y^{2} -8x - 14y + c = 0$ is the point (–3, 2), then its other end is the point ?

Answer:-

⇒ As , General equation of circle is

≡ $x^{2} + y^{2} + 2gx + 2fy + K = 0$ -----(1)

⇒ one end of circle is is B: ( -3 , 2 ) and other is A: ( a , b )..

⇒ As , given equation of circle is

≡ $x^{2} + y^{2} -8x - 14y + c = 0$

comparing with equation (1)..

We get ,

$<klux>G</klux> = - <klux>4</klux>$ and $f = - 7$

⇒ As, we KNOW that center of circle is : C = ( -g , -f )

⇒ So, center is C : ( 4 , 7 ).

So, by using MID point

⇒ $( 4 , 7 ) =( \frac{a-3}{2} , \frac{b + 2}{2} )$

∴ 8 = a - 3 . ⇒ a = 11

∴ 14 = b + 2 . ⇒ b = 12

So,

another point is $A(a,b) = ( 11,12 )$

I hope this will help you
thank you.

Discussion

11.	For a wedding photoshoot Ravi needs two bulbs around the mirror. There are only two slots for the light bulbs on either side. He has 8 bulbs out of which 4 are working and other four are not working. He need to try it out to find a pair that lights up properly. what is the least number of trials he need for proper lightning.
Answer» ong>Answer: For a WEDDING photoshoot Ravi needs two bulbs around the MIRROR. There are only two slots for the light bulbs on either SIDE. He has 8 bulbs out of which 4 are working and other four are not working. He need to try it out to find a pair that lights up properly. what is the least NUMBER of trials he need for proper lightning.

11.

For a wedding photoshoot Ravi needs two bulbs around the mirror. There are only two slots for the light bulbs on either side. He has 8 bulbs out of which 4 are working and other four are not working. He need to try it out to find a pair that lights up properly. what is the least number of trials he need for proper lightning.

Answer»

ong>Answer:

For a WEDDING photoshoot Ravi needs two bulbs around the MIRROR. There are only two slots for the light bulbs on either SIDE. He has 8 bulbs out of which 4 are working and other four are not working. He need to try it out to find a pair that lights up properly. what is the least NUMBER of trials he need for proper lightning.

Discussion

12.	ऐसी छोटी-से-छोटी संख्या बताइए, जिसमें 3 जोड़ दें तो योगफल 75, 45 तथा 50 से अलग-अलग पूरा-पूरा विभाजित हो जाए।
Answer» ong>Answer: 447 Step-by-step explanation: First of all, we take lCM Answer comes 450 According to the question we have to find a value in which 3 is ADDED. So we SUBTRACT 3 from 450 . Hence, answer is 447. I hope it will help you. ☺️☺️☺️

12.

ऐसी छोटी-से-छोटी संख्या बताइए, जिसमें 3 जोड़ दें तो योगफल 75, 45 तथा 50 से अलग-अलग पूरा-पूरा विभाजित हो जाए।

Answer»

ong>Answer:

447

Step-by-step explanation:

First of all, we take lCM

Answer comes 450

According to the question we have to find a value in which 3 is ADDED.

So we SUBTRACT 3 from 450 .

Hence, answer is 447.

I hope it will help you. ☺️☺️☺️

Discussion

13.	एका फाश्याच्या वरच्या पृष्ठभागावर 0,1,2,3,4,5 हे अंक असतील आनण तो फासा िोििा फे कला असेल, तर वरच्या पृष्ठभागावर येणा-या अंकांचा गुणाकार शून्य असण्याची संभाव्यता काढा.
Answer» ONG>Answer: मौसम के आधार पर मुख्य रूप से दो प्रकार की फसलें हैंखरीफ और रबी। वे फसलें जो शीत ऋतु में बोई जाती हैं लेकिन ग्रीष्म ऋतु की शुरुआत से पहले काट ली जाती है, रबी फसल कहलाती है। उदाहरण के लिए गेहूँ, चना, ज्वार टिप्पणी आदि। आवश्यकता होती है वे सिंचित फसलें कहलाती हैं। Step-by-step EXPLANATION: YE SAHI

13.

एका फाश्याच्या वरच्या पृष्ठभागावर 0,1,2,3,4,5 हे अंक असतील आनण तो फासा िोििा फे कला असेल, तर वरच्या पृष्ठभागावर येणा-या अंकांचा गुणाकार शून्य असण्याची संभाव्यता काढा.

Answer» ONG>Answer:

मौसम के आधार पर मुख्य रूप से दो प्रकार की फसलें हैंखरीफ और रबी। वे फसलें जो शीत ऋतु में बोई जाती हैं लेकिन ग्रीष्म ऋतु की शुरुआत से पहले काट ली जाती है, रबी फसल कहलाती है। उदाहरण के लिए गेहूँ, चना, ज्वार टिप्पणी आदि। आवश्यकता होती है वे सिंचित फसलें कहलाती हैं।

Step-by-step EXPLANATION:

YE SAHI

Discussion

14.	Two paths each 2 m wide run across the middle of a rectangular field. If the area of cross path is 196 m2 and itslength is 60 m, find its breadth.(Ans: 40 m) step wise answer for long method
Answer» ong>Answer: TWO paths each 2 m WIDE run across the middle of a rectangular field. If the AREA of cross path is 196 m2 and its length is 60 m, find its breadth. (Ans: 40 m) step wise answer for LONG method

14.

Two paths each 2 m wide run across the middle of a rectangular field. If the area of cross path is 196 m2 and itslength is 60 m, find its breadth.(Ans: 40 m) step wise answer for long method

Answer»

ong>Answer:

TWO paths each 2 m WIDE run across the middle of a

rectangular field. If the AREA of cross path is 196 m2 and its

length is 60 m, find its breadth.

(Ans: 40 m) step wise answer for LONG method

Discussion

15.	Solve : 3(x + 2) = 10
Answer» ══════════════════════ $3(x + 2) = 10 \\ 3x + 6 = 10 \\ 3x = 10 - 6 \\ 3x = 4 \\ x = \frac{4}{3} \\ \\ ❥ 1.33$ ══════════════════════════ HOPE IT HELPS UH

15.

Solve : 3(x + 2) = 10

Answer»

══════════════════════

$3(x + 2) = 10 \\ 3x + 6 = 10 \\ 3x = 10 - 6 \\ 3x = 4 \\ x = \frac{4}{3} \\ \\ ❥ 1.33$

══════════════════════════

HOPE IT HELPS UH

Discussion

16.	How do we solve this and what is the answer
Answer» ONG>Answer: Option a is correct $x + \frac{x}{3} = 48$ Reason:-It SAYS the sum of a number and THRICE a number is 48. Hence, It means:- $x + \frac{x}{3} = 48$

16.

How do we solve this and what is the answer

Answer» ONG>Answer:

Option a is correct

$x + \frac{x}{3} = 48$

Reason:-It SAYS the sum of a number and THRICE a number is 48.

Hence,

It means:-

$x + \frac{x}{3} = 48$

Discussion

17.	If a=5m+11n-15p,b=12m-13n+19p a then the value of a+b-c is
Answer» -2n+4p-c is the ANSWER for the quesri6

Discussion

18.	A number is selected at random from first 100 whole numbers. Find the probability that the number is divisible by 8 or 12.
Answer» PROBABILITY of NUMBER that is divisible by 12 is 8/100 the probability of NUMBERS that is divisible by 8 is 12/100

18.

A number is selected at random from first 100 whole numbers. Find the probability that the number is divisible by 8 or 12.

Answer» PROBABILITY of NUMBER that is divisible by 12 is 8/100

the probability of NUMBERS that is divisible by 8 is 12/100

Discussion

19.	If √3=1.732,then find the value of: (ii) 5√12-3√48+6√75+7√108
Answer» ONG>Step-by-step EXPLANATION: This is the answer PLS MARK AS BRAINLIEST IF THIS HELPED YOU

19.

If √3=1.732,then find the value of: (ii) 5√12-3√48+6√75+7√108

Answer» ONG>Step-by-step EXPLANATION:

This is the answer

PLS MARK AS BRAINLIEST IF THIS HELPED YOU

Discussion

20.	Anyone plz solve the above question
Answer» ONG>Step-by-step EXPLANATION: thankyou have a NICE day

Discussion

21.	Polynomial y = 2x² - 4x meet thx -ares at
Answer» ong>ANSWER: X is polynomial. jeska one term HO use polynomial KEHTE h

21.

Polynomial y = 2x² - 4x meet thx -ares at

Answer»

ong>ANSWER:

X is polynomial. jeska one term HO use polynomial KEHTE h

Discussion

22.	Write the coordinates of the midpoint of the line segment joining the points A(x1,y1) and B(x2,y2).
Answer» ong>Answer: [(x1 + X2)/2 , (Y1 + y2)/2] Using SECTION formula... If a point P (lying on AB) divides AB in the ratio m:N then P = [ (mx2 + nx1)/ (m+n) , (my2 + ny1)/ (m+n) ] for internal division... Hope it helped you....

22.

Write the coordinates of the midpoint of the line segment joining the points A(x1,y1) and B(x2,y2).

Answer»

ong>Answer:

[(x1 + X2)/2 , (Y1 + y2)/2]

Using SECTION formula...

If a point P (lying on AB) divides AB in the ratio m:N then

P = [ (m*x2 + n*x1)/ (m+n) , (m*y2 + n*y1)/ (m+n) ]

for internal division...

Hope it helped you....

Discussion

23.	. Find the difference of17 157. and 618 36\|
Answer» ONG>Answer: 64679 Step-by-step explanation: 61836-17157=64679

23.

. Find the difference of17 157. and 618 36|

Answer» ONG>Answer:

64679

Step-by-step explanation:

61836-17157=64679

Discussion

24.	A farmer has donated a peach ,apple and banana for each learner in deli s class,she has 36learners in her class ,how many fruits were donated?
Answer» ONG>Answer: PLEASE mark me as BRAINLEST

Discussion

25.	the third term of an arithmetic progression is 8 and its ninth term exceeds three times the third term by 2 find the sum of the first 19 terms
Answer» er: Step-by-step explanation: There are four major branches of SCIENCE; each branch is categorized in different type of subjects that covers different areas of studies such US chemistry, physics, MATH, astronomy etc. The four major branches of science are, Mathematics and logic, BIOLOGICAL science, PHYSICAL science and social science.

25.

the third term of an arithmetic progression is 8 and its ninth term exceeds three times the third term by 2 find the sum of the first 19 terms

Answer»

er:

Step-by-step explanation:

There are four major branches of SCIENCE; each branch is categorized in different type of subjects that covers different areas of studies such US chemistry, physics, MATH, astronomy etc. The four major branches of science are, Mathematics and logic, BIOLOGICAL science, PHYSICAL science and social science.

Discussion

26.	Simplify (27)232 Cssify
Answer» ong>Answer: hn pa !! ki THUNDER bee !! hahaha BASS bass .. mu BED upare sooithili !! pura ghoda ghodi heiki !! hahaha love you ☺️☺️❤️❤️ sry baby ☹️ mama 1 sec pain b PHONE dauni !! jadi mate 0.0001 sec pain phone milanta !! mu asanti tate kivhi kahibaku ☹️

26.

Simplify (27)232 Cssify

Answer»

ong>Answer:

hn pa !! ki THUNDER bee !!

hahaha BASS bass .. mu BED upare sooithili !! pura ghoda ghodi heiki !! hahaha

love you ☺️☺️❤️❤️

sry baby ☹️ mama 1 sec pain b PHONE dauni !! jadi mate 0.0001 sec pain phone milanta !! mu asanti tate kivhi kahibaku ☹️

Discussion

27.	Does 16 2/3 is equal to 16.6
Answer» ER: Step-by-step explanation: 16 2/3 = 16.666667

27.

Does 16 2/3 is equal to 16.6

Answer» ER:

Step-by-step explanation:

16 2/3 = 16.666667

Discussion

28.	How many subsets of (1,2,3,4,5,6,7,8,9)contain 5 consequtive number's?
Answer» ong>Answer: Answer 1. Let S⊆X such that S∩A≠∅ . This is equivalent to saying that S is not a subset of B . In other words, S∩A≠∅⇔S⊈B . Therefore, the number of such SETS S plus the number of subsets of B together equal the number of subsets of X . This number is 2n−2n−m . ■ Answer 2. Let S be as before. Then S=S∩X=(S∩A)∪(S∩B) is a disjoint UNION of S1=S∩A and S2=S∩B . So there are as many sets S as there are ordered pairs (S1,S2) of subsets of (A,B) . SET S1 is non-empty but there is no restriction on the set S2 . Therefore the number of such sets Step-by-step explanation: @Ask The MASTER

28.

How many subsets of (1,2,3,4,5,6,7,8,9)contain 5 consequtive number's?

Answer»

ong>Answer:

Answer 1. Let S⊆X such that S∩A≠∅ . This is equivalent to saying that S is not a subset of B . In other words,

S∩A≠∅⇔S⊈B .

Therefore, the number of such SETS S plus the number of subsets of B together equal the number of subsets of X . This number is 2n−2n−m . ■

Answer 2. Let S be as before. Then

S=S∩X=(S∩A)∪(S∩B)

is a disjoint UNION of S1=S∩A and S2=S∩B . So there are as many sets S as there are ordered pairs (S1,S2) of subsets of (A,B) . SET S1 is non-empty but there is no restriction on the set S2 . Therefore the number of such sets

Step-by-step explanation:

@Ask The MASTER

Discussion

29.	5a(b+c)-7(b+c) of math basic question rs aggrawl class 9
Answer» IS YOUR ANSWER . I HOPE IT MAY HELP YOU . PLEASE MARK ME AS A BRAINLIEST . THANK YOU. BRO BUT YOU HAVE TO WRITE THAT IT IS FACTORISATION

29.

5a(b+c)-7(b+c) of math basic question rs aggrawl class 9

Answer»

IS YOUR ANSWER .

I HOPE IT MAY HELP YOU .

PLEASE MARK ME AS A BRAINLIEST .

THANK YOU.

BRO BUT YOU HAVE TO WRITE THAT IT IS FACTORISATION

Discussion

30.	construct a right angled triangle abc at B in which base BC is equals to 4 cm and ac is equal to 7.5 CM
Answer» is the answer. Hope this HELPS

30.

construct a right angled triangle abc at B in which base BC is equals to 4 cm and ac is equal to 7.5 CM

Answer»

is the answer.

Hope this HELPS

Discussion

31.	An ideal gas with k = 1.4 is flowing through a nozzle such that the Mach number is 2.4 where the flow area is 25 cm2. Assuming the flow to be isentropic, determine the flow area at the location where the Mach number is 1.2
Answer» ong>Answer: please mark me as BRAINLEST Step-by-step explanation: please mark me as brainlest as brainlest as a brainlest of the POEM LEISURE and irritated by the assignment of the U

31.

An ideal gas with k = 1.4 is flowing through a nozzle such that the Mach number is 2.4 where the flow area is 25 cm2. Assuming the flow to be isentropic, determine the flow area at the location where the Mach number is 1.2

Answer»

ong>Answer:

please mark me as BRAINLEST

Step-by-step explanation:

please mark me as brainlest as brainlest as a brainlest of the POEM LEISURE and irritated by the assignment of the U

Discussion

32.	One card is selected from well-shuffled deck of 52 cards.Find the probability of getting i) a face card ii) an ace card iii) a heart iv) a jack of spade
Answer» ong>Step-by-step EXPLANATION: (i) Face CARDS: 12 Probability = 12÷52=0.23 ii) Ace cards: 4 Probability = 4÷52=0.07 iii) Hearts: 13 Probability = 13÷52=0.25 iv) JACK of spades: 13 Probability = 13÷52=0.25

32.

One card is selected from well-shuffled deck of 52 cards.Find the probability of getting i) a face card ii) an ace card iii) a heart iv) a jack of spade

Answer»

ong>Step-by-step EXPLANATION:

(i) Face CARDS: 12

Probability = 12÷52=0.23

ii) Ace cards: 4

Probability = 4÷52=0.07

iii) Hearts: 13

Probability = 13÷52=0.25

iv) JACK of spades: 13

Probability = 13÷52=0.25

Discussion

33.	If the cost of 37 pens and 53 pencils together is rupees 320,while 53 pens and 37 pencils together cost rupees 400.Find the cost of two pens.
Answer» ong>Answer: Let us consider x be the no. of pen and y be the no. of pencil According to first condition 37x + 53y = 320. ........... (1) According to second condition 53y + 37x = 400 ..............(2) solving equation (1) and (2)

33.

If the cost of 37 pens and 53 pencils together is rupees 320,while 53 pens and 37 pencils together cost rupees 400.Find the cost of two pens.

Answer»

ong>Answer:

Let us consider x be the no. of pen and y be the no. of pencil

According to first condition

37x + 53y = 320. ........... (1)

According to second condition

53y + 37x = 400 ..............(2)

solving equation (1) and (2)

Discussion

34.	Write a quadratic polynomial,the sum and product of whose zeros are 3 and -2 respectively
Answer» en :- SUM of zeroes (a+B)- 3 product of zeroes (aB)- (-2) To FIND :- quadratic polynomial Solution :- $\\ \\$ EQUATION - k(x^2-(a+B)x+(aB)) PUT value k(x^2-(3)x+(-2)) here k is constant hence quadratic equation is =[x^2 -3x-2] Thanks hope its helpful

34.

Write a quadratic polynomial,the sum and product of whose zeros are 3 and -2 respectively

Answer»

en :-

SUM of zeroes (a+B)- 3
product of zeroes (aB)- (-2)

To FIND :-

quadratic polynomial

Solution :-

$\\ \\$ EQUATION - k(x^2-(a+B)x+(aB))

PUT value

k(x^2-(3)x+(-2))

here k is constant

hence quadratic equation is

=[x^2 -3x-2]

Thanks

hope its helpful

Discussion

35.	Calculate median of the following frequency distribution table C.I 1-4 4 - 7 7 - 10 10 - 13 13 – 16 16 – 19 F 6 30 40 16 4 4
Answer» ong>Answer: firstly we FIND the c.f of this table (c.f:- f1-f2) C.F:- 6+0=6 6+30=36 36+40=76 76+16=92 92+4=96 96+4=100 then:- MEDIAN= L+[(n÷2)-Pc.f÷f]c l=lowest LIMIT of median class Pc.f=privious commutive frequency n=total no. of observation c=size of median class median=

35.

Calculate median of the following frequency distribution table C.I 1-4 4 - 7 7 - 10 10 - 13 13 – 16 16 – 19 F 6 30 40 16 4 4

Answer»

ong>Answer:

firstly we FIND the c.f of this table (c.f:- f1-f2)

C.F:-

6+0=6

6+30=36

36+40=76

76+16=92

92+4=96

96+4=100

then:-

MEDIAN= L+[(n÷2)-Pc.f÷f]c

l=lowest LIMIT of median class

Pc.f=privious commutive frequency

n=total no. of observation

c=size of median class

median=

Discussion

36.	Line is such that its segment between x-2y=5 and 3x+2y=15 is bisected at point (1,1)
Answer» ONG>ANSWER: x=5 MARK me as BRAINLIEST

36.

Line is such that its segment between x-2y=5 and 3x+2y=15 is bisected at point (1,1)

Answer» ONG>ANSWER:

x=5

MARK me as BRAINLIEST

Discussion

37.	Simplify: ( ²+4x+4)(x+2)
Answer» ong>Step-by-step EXPLANATION: DEAR I Think You Should Check The QUESTION

37.

Simplify: ( ²+4x+4)(x+2)

Answer»

ong>Step-by-step EXPLANATION:

DEAR I Think You Should Check The QUESTION

Discussion

38.	If u r genius clear this math problem
Answer» er: any COMPLEX number with REAL part 1/2 has the solution to this , it’s Reimann ZETA function it is , it’s still UNSOLVED Step-by-step EXPLANATION:

38.

If u r genius clear this math problem

Answer»

er: any COMPLEX number with REAL part 1/2 has the solution to this , it’s Reimann ZETA function it is , it’s still UNSOLVED

Step-by-step EXPLANATION:

Discussion

39.	22. दिए गये चित्र मे यदि AB=6cm PB=2cm PD=2.5 cm हो तो CD का मान होगा।a) 3.9 सेमीc) 2.9 सेमीb) 6.4 सेमीd) 4.5 सेमी
Answer» CD = 2.9cm Please MARK me as BRAINLIST

39.

22. दिए गये चित्र मे यदि AB=6cm PB=2cm PD=2.5 cm हो तो CD का मान होगा।a) 3.9 सेमीc) 2.9 सेमीb) 6.4 सेमीd) 4.5 सेमी

Answer»

CD = 2.9cm

Please MARK me as BRAINLIST

Discussion

40.	What is rock cycle? Explain it with help of labelled diagram?
Answer» ong>Answer: SCIENCE is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence. SCIENTIFIC methodology includes the following: ... Evidence. EXPERIMENT and/or observation as BENCHMARKS for TESTING hypotheses. Step-by-step explanation: $\huge{\textbf{\textsf{{\color{red}{@}}{\red{❣}}{\|}}}} \huge{\textbf{\textsf{{\color{navy}{O}}{\purple {P}} {\pink{BO}}{\color{pink}{Y࿐}}}}}$

40.

What is rock cycle? Explain it with help of labelled diagram?

Answer»

ong>Answer:

SCIENCE is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence. SCIENTIFIC methodology includes the following: ... Evidence. EXPERIMENT and/or observation as BENCHMARKS for TESTING hypotheses.

Step-by-step explanation:

$\huge{\textbf{\textsf{{\color{red}{@}}{\red{❣}}{|}}}} \huge{\textbf{\textsf{{\color{navy}{O}}{\purple {P}} {\pink{BO}}{\color{pink}{Y࿐}}}}}$

Discussion

41.	1 A Choose and write the correct alternative. 3(1) The sum of the roots of one of the following equations is 3. Whichone is the equation ?(A) x2 3x + 2 = 0(B) x2 + 3x + 2 = 0(C) 3x2 + 6x + 10 = 0 (D) x2 + 3x - 2 = 0
Answer» ECT option is A ) x^2 −3x+2=0 LET a,b be the roots of the equation. Then by the PROBLEM, a+b=3...….(1) and ab=2...…(2). Then the quadratic equation whose roots are a,b be, x^2 −(a+b)x+ab=0 or, x^2 −3x+2=0.[ Using (1) and (2)]

41.

1 A Choose and write the correct alternative. 3(1) The sum of the roots of one of the following equations is 3. Whichone is the equation ?(A) x2 3x + 2 = 0(B) x2 + 3x + 2 = 0(C) 3x2 + 6x + 10 = 0 (D) x2 + 3x - 2 = 0

Answer» ECT option is

A ) x^2 −3x+2=0

LET a,b be the roots of the equation.

Then by the PROBLEM,

a+b=3...….(1) and ab=2...…(2).

Then the quadratic equation whose roots are a,b be,

x^2 −(a+b)x+ab=0

or, x^2 −3x+2=0.[ Using (1) and (2)]

Discussion

42.	1) ✓2×(1+2✓2) compute this??
Answer» ong>ANSWER: first SQUARE this 2×2=4,then remove BRACKET 4×1=4 and 4+2=6 and again add 6+2=8 then square√8=64 final answer is 64

42.

1) ✓2×(1+2✓2) compute this??

Answer»

ong>ANSWER:

first SQUARE this 2×2=4,then remove BRACKET 4×1=4 and 4+2=6 and again add 6+2=8 then square√8=64 final answer is 64

Discussion

43.	A circle touches all the four sides of a quadrilateral ABCD with AB = 6 cm. BC = 7 cm and CD = 4 cm. Find AD.
Answer» ONG>ANSWER: AD=3cm Step-by-step explanation: Given : A circle inscribed in a quadrilateral ABCD,AB=6cm,BC=7cm,CD=4cm. To find : AD Proof : Let the circle touch the sides AB,BC,CD,DA, at P,Q,R and S, respectively. AP=AS BP=BQ DR=DS CR=CQ {LENGTHS of two tangents DRAWN from an external point of circle, are equal} Adding all these, we get (AP+BP)+(CR+RD)=(BQ+QC)+(DS+SA) AB+CD=BC+DA ⇒6+4=7+AD ⇒AD=10−7=3cm.

43.

A circle touches all the four sides of a quadrilateral ABCD with AB = 6 cm. BC = 7 cm and CD = 4 cm. Find AD.

Answer» ONG>ANSWER:

AD=3cm

Step-by-step explanation:

Given : A circle inscribed in a quadrilateral ABCD,AB=6cm,BC=7cm,CD=4cm.

To find : AD

Proof : Let the circle touch the sides AB,BC,CD,DA, at P,Q,R and S, respectively.

AP=AS

BP=BQ

DR=DS

CR=CQ {LENGTHS of two tangents DRAWN from an external point of circle, are equal}

Adding all these, we get

(AP+BP)+(CR+RD)=(BQ+QC)+(DS+SA)

AB+CD=BC+DA

⇒6+4=7+AD

⇒AD=10−7=3cm.

Discussion

44.	The total surface area of the Solidhemisphere is 1848 cm. the radius
Answer» l SURFACE AREA of hemisphere =3πr ² where R= RADIUS of hemisphere 3πr ² =1848 ⇒3× 22/7×r ² =1848 ⇒r ²= 1848×7/3×22 = 196 r= √196 = 14 cm

44.

The total surface area of the Solidhemisphere is 1848 cm. the radius

Answer»

l SURFACE AREA of hemisphere =3πr ²

where R= RADIUS of hemisphere

3πr ² =1848

⇒3× 22/7×r ² =1848

⇒r ²= 1848×7/3×22 = 196

r= √196 = 14 cm

Discussion

45.	Solve the quratic equation 2x2 + 5x + 2 = 0 using formula method
Answer» ong>GIVEN EQUATION $\sf\to 2x^2+5x+2=0$ Formula $\sf\to x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$ Now Compare with $\sf\to ax^2+bx+c=0$ We GET $\sf\to a=1 , b = 5\: and\:c=2$ Put the value on formula $\sf\to x=\dfrac{-5\pm\sqrt{(5)^2-4\times2\times2} }{2\times2}$ $\sf\to x=\dfrac{-5\pm\sqrt{25-16} }{4}$ $\sf\to x=\dfrac{-5\pm\sqrt{9} }{4}$ $\sf\to x = \dfrac{-5\pm3}{4}$ $\sf\to x=\dfrac{-5+3}{4} \: and \:\dfrac{-5-3}{4}$ $\sf\to x=\dfrac{-2}{4} \: and \: \dfrac{-8}{4}$ $\sf\to x= \dfrac{-1}{2} \:and\: x= -2$ Answer $\sf\to x= \dfrac{-1}{2} \:and\: x= -2$

45.

Solve the quratic equation 2x2 + 5x + 2 = 0 using formula method

Answer»

ong>GIVEN EQUATION

$\sf\to 2x^2+5x+2=0$

Formula

$\sf\to x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

Now Compare with

$\sf\to ax^2+bx+c=0$

We GET

$\sf\to a=1 , b = 5\: and\:c=2$

Put the value on formula

$\sf\to x=\dfrac{-5\pm\sqrt{(5)^2-4\times2\times2} }{2\times2}$

$\sf\to x=\dfrac{-5\pm\sqrt{25-16} }{4}$

$\sf\to x=\dfrac{-5\pm\sqrt{9} }{4}$

$\sf\to x = \dfrac{-5\pm3}{4}$

$\sf\to x=\dfrac{-5+3}{4} \: and \:\dfrac{-5-3}{4}$

$\sf\to x=\dfrac{-2}{4} \: and \: \dfrac{-8}{4}$

$\sf\to x= \dfrac{-1}{2} \:and\: x= -2$

Answer

$\sf\to x= \dfrac{-1}{2} \:and\: x= -2$

Discussion

46.	रात्रीरात्रि में कल में कलाकारों के सख्य का अनाशाको सख्याhoti hai
Answer» ong>ANSWER: YES you are saying that is correct answer

46.

रात्रीरात्रि में कल में कलाकारों के सख्य का अनाशाको सख्याhoti hai

Answer»

ong>ANSWER:

YES you are saying that is correct answer

Discussion

47.	Ormula) Compound . Find the amount and C.I when compounded half yearly1) P = Rs. 10000 rate = 12% T = 18 months
Answer» 3> $hello \: mate$ NOTE :- Kindly REFER the above ATTACHMENT. I *hope* my *answer* *HELPS* *you*...✌

47.

Ormula) Compound . Find the amount and C.I when compounded half yearly1) P = Rs. 10000 rate = 12% T = 18 months

Answer» 3>

$hello \: mate$

NOTE :- Kindly REFER the above ATTACHMENT.

I hope my answer HELPS you...✌

Discussion

48.	एक कक्षा में लड़कों और लड़कियों की संख्या 7:5 के अनुपात में है . लड़कों की संख्या लड़कियों की संख्या से 8 अधिक है। कक्षा में कुल कितने विद्यार्थी है ?(A)48 (B) 58 (C) 68(D) 78
Answer» ong>ANSWER: answer of TOTAL STUDENTS is 48.

48.

एक कक्षा में लड़कों और लड़कियों की संख्या 7:5 के अनुपात में है . लड़कों की संख्या लड़कियों की संख्या से 8 अधिक है। कक्षा में कुल कितने विद्यार्थी है ?(A)48 (B) 58 (C) 68(D) 78

Answer»

ong>ANSWER:

answer of TOTAL STUDENTS is 48.

Discussion

49.	(-5)⁰= -1 True or false
Answer» ONG>ANSWER: true Step-by-step EXPLANATION: (-5)°=-1 -1=-1{°=1}

49.

(-5)⁰= -1 True or false

Answer» ONG>ANSWER:

true

Step-by-step EXPLANATION:

(-5)°=-1

-1=-1{°=1}

Discussion

50.	Find the HCF of the following number by method prime factorization75 and 105
Answer» ANS:-75=5×5×3 105=5×3×7 HCF(75,105)=5×3=15

50.

Find the HCF of the following number by method prime factorization75 and 105

Answer»

ANS:-75=5×5×3

105=5×3×7

HCF(75,105)=5×3=15

Discussion

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