332354 + Interview Questions in Secondary School in Math

1.	which of the following is pair of adjacent angles of a parallelogram a. 30°,150° b.90°,100 c.60°,90° d.75°,115°
Answer» ONG>ANSWER: *OPTION* A : 30⁰ , *150⁰ IS THE* *ANSWER*

Discussion

2.	in a parallelogram ABCD , triangleA=60° then find measure of trianglec=? (1)50° (2)60° (3) 120° (4)180°
Answer» ong>Answer: Option 2. 60 ° is the CORRECT answer Step-by-step EXPLANATION: OPPOSITE angles of. Parallelogram are same

2.

in a parallelogram ABCD , triangleA=60° then find measure of trianglec=? (1)50° (2)60° (3) 120° (4)180°

Answer»

ong>Answer:

Option 2. 60 ° is the CORRECT answer

Step-by-step EXPLANATION:

OPPOSITE angles of. Parallelogram are same

Discussion

3.	1 1. Total number of elements in the power set of Acontaining 15 elements is(d) 215-1(a) 215(b) 152(c) 215-1
Answer» ong>ANSWER: गटात न बसणारा शब्द ठरवा अणि त्याचे स्पष्टीकरण दया : GALLIUM, scandium, GERMANIUM, calcium

3.

1 1. Total number of elements in the power set of Acontaining 15 elements is(d) 215-1(a) 215(b) 152(c) 215-1

Answer»

ong>ANSWER:

गटात न बसणारा शब्द ठरवा अणि त्याचे स्पष्टीकरण दया : GALLIUM, scandium, GERMANIUM, calcium

Discussion

4.	what is the differences detween comopound interests for 2 years and 3 years for Rs. 500 at 10% rate compounded annually?
Answer» en Principal= RS. 500 Rate = 10% TIME = 2 YEAR's and 3 year's To Find Differences detween COMOPOUND interests for 2 years and 3 years Solution $~~~~~~~~~\boxed{\sf \pink{CI= P\{\left( 1+\dfrac{R}{100}\right) ^{n} -1\}}}$ Compound Interest For 2 year's ${\implies \sf \: CI= 500\{\left( 1+\dfrac{10}{100}\right) ^{2} -1\}}$ ${\implies\sf \: CI= 500\{\left(\dfrac{110}{100}\right) ^{2} -1\}}$ ${\implies\sf \: CI= 500\{\left(\dfrac{11}{10}\right) ^{2} -1\}}$ ${\implies\sf \: CI= 500\left(\dfrac{121}{100} - 1\right) }$ ${\implies\sf \: CI= 500 \times \dfrac{121 - 100}{100}}$ ${\implies\sf \: CI= 5 \times 21}$ $~~~~~~~ \boxed{\sf \: CI_{\pink{2 year's}}=Rs. 105}$ Now Compound Interest For 3 Years ${\implies \sf \: CI= 500\{\left( 1+\dfrac{10}{100}\right) ^{3} -1\}}$ ${\implies \sf \: CI= 500\{\left(\dfrac{110}{100}\right) ^{3} -1\}}$ ${\implies \sf \: CI= 500\{\left(\dfrac{11}{10}\right) ^{3} -1\}}$ ${\implies \sf \: CI= 500\left(\dfrac{1331}{1000} - 1\right) }$ ${\implies \sf \: CI= 500 \times \dfrac{1331 - 1000}{1000}}$ ${\implies\sf \: CI= \dfrac{331}{2}}$ $~~~~~~~ \boxed{\sf \: CI_{\pink{3~ years}}= Rs. 165.5}$ Differences detween compound interests for 2 years and 3 years = 165.5- 105 =Rs. 60.5

4.

what is the differences detween comopound interests for 2 years and 3 years for Rs. 500 at 10% rate compounded annually?

Answer»

en

Principal= RS. 500
Rate = 10%
TIME = 2 YEAR's and 3 year's

To Find

Differences detween COMOPOUND interests for 2 years and 3 years

Solution

$~~~~~~~~~\boxed{\sf \pink{CI= P\{\left( 1+\dfrac{R}{100}\right) ^{n} -1\}}}$

Compound Interest For 2 year's

${\implies \sf \: CI= 500\{\left( 1+\dfrac{10}{100}\right) ^{2} -1\}}$

${\implies\sf \: CI= 500\{\left(\dfrac{110}{100}\right) ^{2} -1\}}$

${\implies\sf \: CI= 500\{\left(\dfrac{11}{10}\right) ^{2} -1\}}$

${\implies\sf \: CI= 500\left(\dfrac{121}{100} - 1\right) }$

${\implies\sf \: CI= 500 \times \dfrac{121 - 100}{100}}$

${\implies\sf \: CI= 5 \times 21}$

$~~~~~~~ \boxed{\sf \: CI_{\pink{2 year's}}=Rs. 105}$

Now Compound Interest For 3 Years

${\implies \sf \: CI= 500\{\left( 1+\dfrac{10}{100}\right) ^{3} -1\}}$

${\implies \sf \: CI= 500\{\left(\dfrac{110}{100}\right) ^{3} -1\}}$

${\implies \sf \: CI= 500\{\left(\dfrac{11}{10}\right) ^{3} -1\}}$

${\implies \sf \: CI= 500\left(\dfrac{1331}{1000} - 1\right) }$

${\implies \sf \: CI= 500 \times \dfrac{1331 - 1000}{1000}}$

${\implies\sf \: CI= \dfrac{331}{2}}$

$~~~~~~~ \boxed{\sf \: CI_{\pink{3~ years}}= Rs. 165.5}$

Differences detween compound interests for 2 years and 3 years = 165.5- 105 =Rs. 60.5

Discussion

5.	State Newton’s divided difference formula.
Answer» ONG>Answer: Newton's divided difference interpolation formula is a interpolation TECHNIQUE used when the interval difference is not same for all sequence of values. Divided differences are symmetric with respect to the ARGUMENTS i.e independent of the ORDER of arguments.

Discussion

6.	construct a triangle ABC in which Bc = 5.5 cm and then angle B is 60°. sum of other two sides =8.6cm
Answer» ONG>Step-by-step EXPLANATION: I *hope* it *will* *HELP* u *dear*

Discussion

7.	1000 तिकिटांमध्ये 5 तिकिटांवर लॉटरी चे बक्षीस आहे. तर बक्षीस जिंकण्याची संभाव्यता ………. आहे 1️⃣ 199/2002️⃣ 1/2003️⃣ 198/2004️⃣ यापैकी नाही
Answer» ER: HINDI ENGLISH only Step-by-step EXPLANATION:

7.

1000 तिकिटांमध्ये 5 तिकिटांवर लॉटरी चे बक्षीस आहे. तर बक्षीस जिंकण्याची संभाव्यता ………. आहे 1️⃣ 199/2002️⃣ 1/2003️⃣ 198/2004️⃣ यापैकी नाही

Answer» ER: HINDI ENGLISH only

Step-by-step EXPLANATION:

Discussion

8.	Inverse of A=[2 -2 4 3]
Answer» ONG>ANSWER: LAL = 6+8 = 14 inverse of A = 1/14 (3. 2 -4. 2)

8.

Inverse of A=[2 -2 4 3]

Answer» ONG>ANSWER:

LAL = 6+8 = 14

inverse of A = 1/14 (3. 2

-4. 2)

Discussion

9.	If cos O = M/2, then what is the value of 0 ?
Answer» ONG>ANSWER: hdfjddtjdsthdtjftdhtstjruteureruejtrjrejtey

Discussion

10.	a Bank offers 6% compound interest calculated on half yearly Basis. a Customer deposited rs 20000 each on 1st Jan and 1st July in a year. what amount he would have gained through interest by the end of the year . ITS URGENT... I WILL MARK BRAINLIEST...
Answer» ong>Answer: Mitochondria are membrane-bound cell organelles (mitochondrion, SINGULAR) that generate most of the chemical energy NEEDED to POWER the cell's biochemical reactions. Chemical energy produced by the mitochondria is stored in a small molecule CALLED adenosine triphosphate (ATP).

10.

a Bank offers 6% compound interest calculated on half yearly Basis. a Customer deposited rs 20000 each on 1st Jan and 1st July in a year. what amount he would have gained through interest by the end of the year . ITS URGENT... I WILL MARK BRAINLIEST...

Answer»

ong>Answer:

Mitochondria are membrane-bound cell organelles (mitochondrion, SINGULAR) that generate most of the chemical energy NEEDED to POWER the cell's biochemical reactions. Chemical energy produced by the mitochondria is stored in a small molecule CALLED adenosine triphosphate (ATP).

Discussion

11.	Write the place value of 2 in the following decimal numbers:.2.56
Answer» ong>ANSWER: ones Step-by-step explanation: HOPE u understand

11.

Write the place value of 2 in the following decimal numbers:.2.56

Answer»

ong>ANSWER:

ones

Step-by-step explanation:

HOPE u understand

Discussion

12.	1] The degree of constant function is________.A) 1B) 2C) 3D) 0
Answer» ong>ANSWER: 3 is the answer of DEGREE of constant FUNCTION

12.

1] The degree of constant function is________.A) 1B) 2C) 3D) 0

Answer»

ong>ANSWER:

3 is the answer of DEGREE of constant FUNCTION

Discussion

13.	Sin0 =12/13 find value of sin2 + cos2
Answer» $\huge \bigstar ★ \huge\bold{\mathtt{\purple{A{\pink{N{\green{S{\blue{W{\red{E{\orange{R}}}}}}}}}}}}}★★$ $\begin{gathered}Value \: of \\ \frac{(sin^{2}\theta-cos^{2}\theta)}{2sin\theta cos\theta}\times \frac{1}{tan^{2}\theta}\\=\frac{595}{3456}\end{gathered}$ Step-by-step EXPLANATION: $\begin{gathered}Given ,\\sin\theta = \frac{12}{13}\end{gathered}$ $\begin{gathered}cos^{2}\theta = 1-sin^{2}\theta \\=1-\left(\frac{12}{13}\right)^{2}\\=1-\frac{144}{169}\\=\frac{169-144}{169}\\=\frac{25}{169}\end{gathered}$ $\begin{gathered}cos\theta = \sqrt{\frac{25}{169}}\\=\frac{5}{13}\end{gathered}$ $\begin{gathered} tan\theta = \frac{sin\theta}{cos\theta}\\=\frac{\frac{12}{13}}{\frac{5}{13}}\\=\frac{12}{5}\end{gathered}$ $\begin{gathered}Now,Value \: of \\ \frac{(sin^{2}\theta-cos^{2}\theta)}{2sin\theta cos\theta}\times \frac{1}{tan^{2}\theta}\end{gathered}$ $=\frac{sin^{2}\theta-(1-sin^{2}\theta)}{2sin\theta cos\theta }\times \frac{1}{tan^{2}\theta}=$ $=\frac{(2sin^{2}\theta-1)}{2sin\theta cos\theta}\times \frac{1}{tan^{2}\theta}$ $=\frac{[2\big(\frac{12}{13}\big)^{2}-1]}{2\times \frac{12}{13}}\times \frac{5}{13}\times \frac{1}{\big(\frac{12}{5}\big)^{2}}$ $=\frac{2\times \frac{144}{169}-1}{2\times \frac{12}{13}\times \frac{5}{13}}\times \frac{25}{144}$ $=\frac{\frac{(288-169)}{169}}{\frac{120}{169}}\times \frac{25}{144}$ $=\frac{119\times 5}{24 \times 144}=\frac{ 595}{3456}$ ${{\red{\underline{Please \: \: Mark \: \: as \: \: \: Brainliest}}}}$

13.

Sin0 =12/13 find value of sin2 + cos2

Answer»

$\huge \bigstar ★ \huge\bold{\mathtt{\purple{A{\pink{N{\green{S{\blue{W{\red{E{\orange{R}}}}}}}}}}}}}★★$

$\begin{gathered}Value \: of \\ \frac{(sin^{2}\theta-cos^{2}\theta)}{2sin\theta cos\theta}\times \frac{1}{tan^{2}\theta}\\=\frac{595}{3456}\end{gathered}$

Step-by-step EXPLANATION:

$\begin{gathered}Given ,\\sin\theta = \frac{12}{13}\end{gathered}$

$\begin{gathered}cos^{2}\theta = 1-sin^{2}\theta \\=1-\left(\frac{12}{13}\right)^{2}\\=1-\frac{144}{169}\\=\frac{169-144}{169}\\=\frac{25}{169}\end{gathered}$

$\begin{gathered}cos\theta = \sqrt{\frac{25}{169}}\\=\frac{5}{13}\end{gathered}$

$\begin{gathered} tan\theta = \frac{sin\theta}{cos\theta}\\=\frac{\frac{12}{13}}{\frac{5}{13}}\\=\frac{12}{5}\end{gathered}$

$\begin{gathered}Now,Value \: of \\ \frac{(sin^{2}\theta-cos^{2}\theta)}{2sin\theta cos\theta}\times \frac{1}{tan^{2}\theta}\end{gathered}$

$=\frac{sin^{2}\theta-(1-sin^{2}\theta)}{2sin\theta cos\theta }\times \frac{1}{tan^{2}\theta}=$

$=\frac{(2sin^{2}\theta-1)}{2sin\theta cos\theta}\times \frac{1}{tan^{2}\theta}$

$=\frac{[2\big(\frac{12}{13}\big)^{2}-1]}{2\times \frac{12}{13}}\times \frac{5}{13}\times \frac{1}{\big(\frac{12}{5}\big)^{2}}$

$=\frac{2\times \frac{144}{169}-1}{2\times \frac{12}{13}\times \frac{5}{13}}\times \frac{25}{144}$

$=\frac{\frac{(288-169)}{169}}{\frac{120}{169}}\times \frac{25}{144}$

$=\frac{119\times 5}{24 \times 144}=\frac{ 595}{3456}$

${{\red{\underline{Please \: \: Mark \: \: as \: \: \: Brainliest}}}}$

Discussion

14.	FLW MY TOP FOLLOWING ☺️
Answer» ong>ANSWER: Biodiversity is the biological VARIETY and variability of life on Earth. Biodiversity is TYPICALLY a measure of variation at the genetic, SPECIES, and ecosystem level. Terrestrial biodiversity is usually greater near the equator, which is the RESULT of the warm climate and high primary productivity. Hope it helps you

14.

FLW MY TOP FOLLOWING ☺️

Answer»

ong>ANSWER:

Biodiversity is the biological VARIETY and variability of life on Earth. Biodiversity is TYPICALLY a measure of variation at the genetic, SPECIES, and ecosystem level. Terrestrial biodiversity is usually greater near the equator, which is the RESULT of the warm climate and high primary productivity.

Hope it helps you

Discussion

15.	The price of on box is ( a - 7) Rs what is the total cost of ( a + 7) boxes
Answer» ONG>ANSWER: a-7+7=a Therefore , the total COST of (a+7)boxes is 'a'

15.

The price of on box is ( a - 7) Rs what is the total cost of ( a + 7) boxes

Answer» ONG>ANSWER:

a-7+7=a

Therefore , the total COST of (a+7)boxes is 'a'

Discussion

16.	The n term of an AP prograssion is an equal to 4a+5than the 3th termm is
Answer» ong>Answer: This is the answer there was a SLIGHT ERROR in the QUESTION, i corrected it, it 4N + 5 not 4a + 5 PLS MARK AS BRAINLIEST

16.

The n term of an AP prograssion is an equal to 4a+5than the 3th termm is

Answer»

ong>Answer:

This is the answer

there was a SLIGHT ERROR in the QUESTION, i corrected it, it 4N + 5 not 4a + 5

PLS MARK AS BRAINLIEST

Discussion

17.	Show that the points (p, p), (-p, -p), (pV3, - pV3) are the vertices of anequilateral triangle.
Answer» n't know jdeldvgeoznvebfoeoje

17.

Show that the points (p, p), (-p, -p), (pV3, - pV3) are the vertices of anequilateral triangle.

Answer»

n't know

jdeldvgeoznvebfoeoje

Discussion

18.	Solve the quadratic equation 2x2 + 5x + 2 = 0 using formula method. Sindhubron dicitnelJobs
Answer» ONG>Answer: 2x2+5x+2= 0 x2+5/2x+1 = 0 x2+5/2x+1+(5/4)2-(5/4)2 = 0 (x+5/4)2+1-25/16 = 0 (x+5/4)2 = 25/16-1 (x+5/4)2 = 9/16 (x+5/4) = +_3/4 x = 5/4+_3/4 x = 2,1/2

18.

Solve the quadratic equation 2x2 + 5x + 2 = 0 using formula method. Sindhubron dicitnelJobs

Answer» ONG>Answer:

2x2+5x+2= 0

x2+5/2x+1 = 0

x2+5/2x+1+(5/4)2-(5/4)2 = 0

(x+5/4)2+1-25/16 = 0

(x+5/4)2 = 25/16-1

(x+5/4)2 = 9/16

(x+5/4) = +_3/4

x = 5/4+_3/4

x = 2,1/2

Discussion

19.	(-4//3)^3×(-1/8)^2 please answer fast
Answer» ONG>ANSWER: (-64/27)×(1/64) -64/27×64 -1/27

19.

(-4//3)^3×(-1/8)^2 please answer fast

Answer» ONG>ANSWER:

(-64/27)×(1/64)

-64/27×64

-1/27

Discussion

20.	2. In rhombus ABCD if angle ACB= 50° then angle ADB=?(A) 40°(B) 80°(C) 50°(D) 100°
Answer» ONG>Answer: C) 50° Step-by-step explanation: all angles of rhombus are EQUAL

20.

2. In rhombus ABCD if angle ACB= 50° then angle ADB=?(A) 40°(B) 80°(C) 50°(D) 100°

Answer» ONG>Answer:

C) 50°

Step-by-step explanation:

all angles of rhombus are EQUAL

Discussion

21.	(2) The degree of the equation x2 – 2x + 1 = x2 – 3 is(a) 1(b)2(c) 0(d) 3.
Answer» ONG>Answer: HEY MATE !! HERE IS UR ANS ⤵️⤵️ The degree of the equation is 2. ... HOPE THIS HELPS U ALMOST ... ... THANK Q ... ꧁꧁ ༒ λKŞU ༒꧂꧂

21.

(2) The degree of the equation x2 – 2x + 1 = x2 – 3 is(a) 1(b)2(c) 0(d) 3.

Answer» ONG>Answer:

HEY MATE !!

HERE IS UR ANS ⤵️⤵️

The degree of the equation is 2.

... HOPE THIS HELPS U ALMOST ...

... THANK Q ...

꧁꧁ ༒ λKŞU ༒꧂꧂

Discussion

22.	Find the volume of the solid obtained by revolving the region bounded by the curves y = 2x² + 1 and y = 3 - 2x² about x-axis. Also find the length of the plane curve y = 2x² + 1 over the interval [1, 3]
Answer» ONG>Answer: PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena FREE Fire⚡ ][ PRESET ALIGHT MOTION FF ⚡] [ Harmony Baba remix ] [ Garena Free Fire ]PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena Free Fire⚡ ][ PRESET ALIGHT MOTION FF ⚡] [ Harmony Baba remix ] [ Garena Free Fire ]PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena Free Fire⚡ ]PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena Free Fire⚡ ]PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena Free Fire⚡ ]For Lokesh gamer agar tum mein Dam hoga to MERE se custom Karke batao Tumhen Tumhari asali dikha Dunga a challenge to #yas likh dena meri ID le lo YASHGAMER1M1 for custom Step-by-step explanation: sorry. sorry. sorryy

22.

Find the volume of the solid obtained by revolving the region bounded by the curves y = 2x² + 1 and y = 3 - 2x² about x-axis. Also find the length of the plane curve y = 2x² + 1 over the interval [1, 3]

Answer» ONG>Answer:

PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena FREE Fire⚡ ][ PRESET ALIGHT MOTION FF ⚡] [ Harmony Baba remix ] [ Garena Free Fire ]PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena Free Fire⚡ ][ PRESET ALIGHT MOTION FF ⚡] [ Harmony Baba remix ] [ Garena Free Fire ]PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena Free Fire⚡ ]PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena Free Fire⚡ ]PRESET ALIGHT MOTION FF ⚡[] Harmony Baba remix [] [ ⚡Garena Free Fire⚡ ]For Lokesh gamer agar tum mein Dam hoga to MERE se custom Karke batao Tumhen Tumhari asali dikha Dunga a challenge to #yas likh dena meri ID le lo YASHGAMER1M1 for custom

Step-by-step explanation:

sorry. sorry. sorryy

Discussion

23.	2.56. please answer math paper
Answer» ONG>ANSWER: where is the QUESTION??

Discussion

24.	Check whether the graph of 4 (x-3) (1+x) = x² + 2x (1+x) open upwards or open downwards
Answer» ONG>ANSWER: zero Step-by-step EXPLANATION:

24.

Check whether the graph of 4 (x-3) (1+x) = x² + 2x (1+x) open upwards or open downwards

Answer» ONG>ANSWER:

zero

Step-by-step EXPLANATION:

Discussion

25.	Please send me all step
Answer» ONG>ANSWER: X = 6/5 hope you UNDERSTOOD !!!

25.

Please send me all step

Answer» ONG>ANSWER:

X = 6/5

hope you UNDERSTOOD !!!

Discussion

26.	There are 5 prize on 100 tickets of a lottery of company probability of winning prize is
Answer» ONG>Answer: 5 ( FIVE) is a probability of WINNING prize

Discussion

27.	3. दी गई आकृति में, यदि ZPQR = ZPRQहै, तो सिद्ध कीजिए कि ZPQS = ZPRTहै।
Answer» ONG>Answer: first make complete QUESTION

Discussion

28.	X coordinate of every point on Y-axis is . . . . . . . .? *012-1
Answer» er:0 Step-by-step EXPLANATION:

28.

X coordinate of every point on Y-axis is . . . . . . . .? *012-1

Answer»

er:0

Step-by-step EXPLANATION:

Discussion

29.	एक समूह में 5 पुरूष और 5 स्त्रियां हैं। यदि k पुरूष और (5 - K) स्त्रियों से बनी भिन्न पंचसदस्यीय समितियों की संख्या 100 है, तो k का मान क्या है?(a) 2 only/केवल(b) 3 only/केवल(c) 2 or 3(d) 4
Answer» ong>ANSWER: ooo.. baby .. miss u too (╥﹏╥) mama jama b phone dauni !! abe ta goda HATA ghasiki phone anichi !! baby !! mu SCIENCE padhibi bhabuchi !! kejani !! nai baby .. AEE nayagarh college re CHANCE nahi !! ☹️ kahinki na aeta HSC pattern ..

29.

एक समूह में 5 पुरूष और 5 स्त्रियां हैं। यदि k पुरूष और (5 - K) स्त्रियों से बनी भिन्न पंचसदस्यीय समितियों की संख्या 100 है, तो k का मान क्या है?(a) 2 only/केवल(b) 3 only/केवल(c) 2 or 3(d) 4

Answer»

ong>ANSWER:

ooo.. baby .. miss u too (╥﹏╥)

mama jama b phone dauni !! abe ta goda HATA ghasiki phone anichi !!

baby !! mu SCIENCE padhibi bhabuchi !!

kejani !! nai baby .. AEE nayagarh college re CHANCE nahi !! ☹️ kahinki na aeta HSC pattern ..

Discussion

30.	Limx-infinity [x - In(x⁵- 10¹⁰)]. Evaluate the following limits using L'Hopital's rule
Answer» ong>Answer: BLA balaana kakxjxwhich TYPE of LANGUAGE is it chineese

30.

Limx-infinity [x - In(x⁵- 10¹⁰)]. Evaluate the following limits using L'Hopital's rule

Answer»

ong>Answer:

BLA balaana kakxjxwhich TYPE of LANGUAGE is it chineese

Discussion

31.	Sin60° cos30का मान ज्ञात करो।
Answer» ONG>ANSWER: answer is 3/4 Step-by-step explanation: sin 60 * cos 30 √3/2*√3/2 3/4

31.

Sin60° cos30का मान ज्ञात करो।

Answer» ONG>ANSWER:

answer is 3/4

Step-by-step explanation:

sin 60 * cos 30

√3/2*√3/2

3/4

Discussion

32.	Answer the given question
Answer» rue I THINK it's TRUE.

32.

Answer the given question

Answer»

rue

I THINK it's TRUE.

Discussion

33.	What is the square root of
Answer» ,841,287,201 i HOPE this ANSWER will HELP you

33.

What is the square root of

Answer»

,841,287,201

i HOPE this ANSWER will HELP you

Discussion

34.	5 candidates are applying for a job interview. Probability of getting selected is 1/2 for each candidate. What is the probability that atleast two candidates are selected ? 11/3213/16None of the above1/321/2
Answer» ONG>ANSWER: answer will be 1/2 pls MARK as BRAINLIEST

34.

5 candidates are applying for a job interview. Probability of getting selected is 1/2 for each candidate. What is the probability that atleast two candidates are selected ? 11/3213/16None of the above1/321/2

Answer» ONG>ANSWER:

answer will be 1/2

pls MARK as BRAINLIEST

Discussion

35.	How many times will the minute hand of a clock crosses the hour hand from 12:15pm to 5:25pm of the same day?
Answer» ONG>Answer: 2 TIMES daily Step-by-step EXPLANATION:

35.

How many times will the minute hand of a clock crosses the hour hand from 12:15pm to 5:25pm of the same day?

Answer» ONG>Answer:

2 TIMES daily

Step-by-step EXPLANATION:

Discussion

36.	How many tiles whose length and breadth are 12 cm and 7 cm respectively will be needed to fill in a rectangular floor whose length and breadth are 70 cm and 48 cm respectively?
Answer» ong>ANSWER: a) Area of region = 100 cm x 144 cm = 14400 cm.sq Area of ONE tile = 5 cm x 12 cm = 60 cm.sq Number of tiles = \frac{Area\ of\ region}{Area\ of\ one\ tile} Area of one tile Area of region = 240 Thus, 240 tiles are REQUIRED. (b) Area of region = 70 cm x 36 cm = 2520 cm.sq Area of one tile = 5 cm x 12 cm = 60 cm.sq Number of tiles = \frac{Area\ of\ region}{Area\ of\ one\ tile} Area of one tile Area of region = 42 Thus, 42 tiles are required.

36.

How many tiles whose length and breadth are 12 cm and 7 cm respectively will be needed to fill in a rectangular floor whose length and breadth are 70 cm and 48 cm respectively?

Answer»

ong>ANSWER:

a) Area of region = 100 cm x 144 cm = 14400 cm.sq

Area of ONE tile = 5 cm x 12 cm = 60 cm.sq

Number of tiles = \frac{Area\ of\ region}{Area\ of\ one\ tile}

Area of one tile

Area of region

= 240

Thus, 240 tiles are REQUIRED.

(b) Area of region = 70 cm x 36 cm = 2520 cm.sq

Area of one tile = 5 cm x 12 cm = 60 cm.sq

Number of tiles = \frac{Area\ of\ region}{Area\ of\ one\ tile}

Area of one tile

Area of region

= 42

Thus, 42 tiles are required.

Discussion

37.	(1) of the following, the linear equation in one variable x, is (a) 4x = *" (b) 1x + 1x' = 1 (c) x + x + 1(d) x² + 2x + 3 = 0.
Answer» ERS of all LINEAR EQUATION are a = 4x b = 2x c = x+1

37.

(1) of the following, the linear equation in one variable x, is (a) 4x = *" (b) 1x + 1x' = 1 (c) x + x + 1(d) x² + 2x + 3 = 0.

Answer» ERS of all LINEAR EQUATION are

a = 4x

b = 2x

c = x+1

Discussion

38.	Can ∠X=30 °, XY=5.6 cm , XZ=3.8 cm can be used to construct a unique triangle?Give reasons for your answer. Please dude answer fast it urgently needed.
Answer»

Discussion

39.	The value of tan 0 =
Answer» ong>ANSWER: In trigonometry, the value of tan 0 is 0. The word 'Trigonometry' is derived from the Greek word and the SUBJECT is developed to solve geometric problems INVOLVING triangles. It is USED to measure the sides of a TRIANGLE.

39.

The value of tan 0 =

Answer»

ong>ANSWER:

In trigonometry, the value of tan 0 is 0. The word 'Trigonometry' is derived from the Greek word and the SUBJECT is developed to solve geometric problems INVOLVING triangles. It is USED to measure the sides of a TRIANGLE.

Discussion

40.	Write set builder form of A{1,2,9,28}
Answer» ONG>Step-by-step EXPLANATION: YKDyakduadkuskruskruarkuarkuarkuakuukaakr

Discussion

41.	Find the cost of fencing a rectangular park of length 400m and breadth 300m at the rate of ₹18 per meter. please friends give me your answer fast
Answer» ONG>Answer: PERIMETER = 1400 m cost of fencing = 25,200 Rs. hope u understood !!

41.

Find the cost of fencing a rectangular park of length 400m and breadth 300m at the rate of ₹18 per meter. please friends give me your answer fast

Answer» ONG>Answer:

PERIMETER = 1400 m

cost of fencing = 25,200 Rs.

hope u understood !!

Discussion

42.	Factoriseax + by + a²
Answer» ONG>ANSWER: its Step-by-step explanation: (AX + by)² + (bx -ay)² =a²x² +b²y² +2abxy +b²x² +a²y² -2abxy =a²x² + b²x² + b²y² +a²y² =x² (a² + b²) + y²(a²+ b²) =(a² + b²)(x² + y²)

42.

Factoriseax + by + a²

Answer» ONG>ANSWER:

its

Step-by-step explanation:

(AX + by)² + (bx -ay)²

=a²x² +b²y² +2abxy +b²x² +a²y² -2abxy

=a²x² + b²x² + b²y² +a²y²

=x² (a² + b²) + y²(a²+ b²)

=(a² + b²)(x² + y²)

Discussion

43.	Five years ago my sister was 14years old. Waht wiol be her age 4years from now
Answer» $\huge\tt\fbox{✰Answer✰}$ $\bf\pink{let\:the\:<klux>PRESENT</klux>\:age\:of\:the\:sister\:be\:X}$ we know, Before 5 YEARS her age was 14. Therefore , ⇒X - 5 = 14 ⇒ X = 14 + 5 ⇒ X = 19 years Hence, Her present age is 19 years . Now , lets find her age after 4 years 19 + 4 = 23 Answer Her present age is 19 and after 4 years she will be 23 years old. hope it helps uh mate :)

43.

Five years ago my sister was 14years old. Waht wiol be her age 4years from now

Answer»

$\huge\tt\fbox{✰Answer✰}$

$\bf\pink{let\:the\:<klux>PRESENT</klux>\:age\:of\:the\:sister\:be\:X}$

we know,

Before 5 YEARS her age was 14.

Therefore ,

⇒X - 5 = 14

⇒ X = 14 + 5

⇒ X = 19 years

Hence, Her present age is 19 years .

Now , lets find her age after 4 years

19 + 4 = 23

Answer

Her present age is 19

and after 4 years she will be 23 years old.

hope it helps uh mate :)

Discussion

44.	Find the sum of (-20 )and 68
Answer» ong>Answer: We have: 2 + 9 + 16 + 23 + 30 + ... This is an arithmetic series, so LET's DETERMINE the common difference d : ⇒ d = u 2 − u 1 ⇒ d = 9 − 2 ⇒ d = 7 Then, let's use the formula for the sum of n TERMS of an arithmetic sequence: ⇒ S n = n 2 ( 2 u 1 + ( n − 1 ) d ) Then, for the first 68 terms of the series: ⇒ S 68 = 68 2 ( 2 ⋅ 2 + ( 68 − 1 ) 7 ) ⇒ S 68 = 34 ( 4 + 67 ⋅ 7 ) ⇒ S 68 = 34 ( 4 + 469 ) ⇒ S 68 = 34 ( 473 ) ⇒ S 68 = 16 , 082

44.

Find the sum of (-20 )and 68

Answer»

ong>Answer:

We have:

2

+

9

+

16

+

23

+

30

+

...

This is an arithmetic series, so LET's DETERMINE the common difference

d

:

⇒

d

=

u

2

−

u

1

⇒

d

=

9

−

2

⇒

d

=

7

Then, let's use the formula for the sum of

n

TERMS of an arithmetic sequence:

⇒

S

n

=

n

2

(

2

u

1

+

(

n

−

1

)

d

)

Then, for the first

68

terms of the series:

⇒

S

68

=

68

2

(

2

⋅

2

+

(

68

−

1

)

7

)

⇒

S

68

=

34

(

4

+

67

⋅

7

)

⇒

S

68

=

34

(

4

+

469

)

⇒

S

68

=

34

(

473

)

⇒

S

68

=

16

,

082

Discussion

45.	Translte in Englishplz friends help me,
Answer» TUJHE kyu rona aa RAHA h

Discussion

46.	a Bank offers 6% compound interest calculated on half yearly Basis. a Customer deposited rs 20000 each on 1st Jan and 1st July in a year. what amount he would have gained through interest by the end of the year.
Answer» ong>Step-by-step explanation: 2nd Aproach calculate Ci of 20000 for 1 year at half yearly . you get = 21218 interest = 1218. ( 1 ) now calculate Ci of 20000 for 6 months at half yearly. you get = 20600 interest= 600. ( 2 ) Add eq 1&2 total EARNING= 1218+600= 1818

46.

a Bank offers 6% compound interest calculated on half yearly Basis. a Customer deposited rs 20000 each on 1st Jan and 1st July in a year. what amount he would have gained through interest by the end of the year.

Answer»

ong>Step-by-step explanation:

2nd Aproach
calculate Ci of 20000 for 1 year at half yearly .

you get = 21218

interest = 1218. ( 1 )

now calculate Ci of 20000 for 6 months at half yearly.
you get = 20600
interest= 600. ( 2 )
Add eq 1&2
total EARNING= 1218+600= 1818

Discussion

47.	Hi guys can u solve this
Answer» ong>Answer: ONE is 50 then the SIDE opposite to it will also be 50. Perimeter is 160 The other two SIDES measure 30m each

47.

Hi guys can u solve this

Answer»

ong>Answer:

ONE is 50 then the SIDE opposite to it will also be 50.

Perimeter is 160

The other two SIDES measure 30m each

Discussion

48.	खंडित श्रेणी से क्या आशय है
Answer» ONG>ANSWER: एक बाज़ार जहां कोई एक कंपनी नहीं है जो उद्योग में किसी विशेष दिशा में जाने के लिए पर्याप्त प्रभाव डाल सकती है, उसे खंडित बाजार स्थान कहा जाता है। बाजार में कई छोटे से मध्यम आकार की कंपनियां शामिल हैं जो एक-दूसरे और बड़े उद्यमों के साथ प्रतिस्पर्धा करती हैं।

Discussion

49.	If one root of the quadratic equation 2x²+kx-2=0is -2. find value of K.
Answer» ong>Answer: x = -2 2(-2)2+k(-2)-2= 0 2(4)-2k-2= 0 8-2k-2 = 0 6-2k = 0 2k = 6 k = 3

49.

If one root of the quadratic equation 2x²+kx-2=0is -2. find value of K.

Answer»

ong>Answer:

x = -2

2(-2)2+k(-2)-2= 0

2(4)-2k-2= 0

8-2k-2 = 0

6-2k = 0

2k = 6

k = 3

Discussion

50.	find the equation to the straight line which passes through the point (-4,1) and in such that the potion of it between the axis is divided in the ratio 1:2
Answer» ONG>Answer: not sure ok answer STEP-by-step EXPLANATION: step by step

50.

find the equation to the straight line which passes through the point (-4,1) and in such that the potion of it between the axis is divided in the ratio 1:2

Answer» ONG>Answer:

not sure ok answer

STEP-by-step EXPLANATION:

step by step

Discussion

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