332354 + Interview Questions in Secondary School in Math

1.	Find 11 rational number between 0.89 and 0.98
Answer» ONG>Answer: 0.89 , 0.90, 0.91, 0.92 , 0.93 , 0.94 , 0.95 , 0.96 , 0.97 , 0.98 Step-by-step explanation: PLEASE MARK it brainliesst

1.

Find 11 rational number between 0.89 and 0.98

Answer» ONG>Answer:

0.89 , 0.90, 0.91, 0.92 , 0.93 , 0.94 , 0.95 , 0.96 , 0.97 , 0.98

Step-by-step explanation:

PLEASE MARK it brainliesst

Discussion

2.	what is the minimum number of balls you must take out of a bag containing 11 red balls ,7 yellow balls and 6 blue balls to guarantee that at least one ball of each color has been taken out?
Answer» ONG>Answer: 8 Step-by-step EXPLANATION:

2.

what is the minimum number of balls you must take out of a bag containing 11 red balls ,7 yellow balls and 6 blue balls to guarantee that at least one ball of each color has been taken out?

Answer» ONG>Answer:

8

Step-by-step EXPLANATION:

Discussion

3.	5) For the equation y = (-5) and x + 6 = 0, state whether they have graphs parallel to X axis and Y axis
Answer» ONG>Answer: I don't KNOW the answer I need only the poor

Discussion

4.	Find the product correctly for the given answer 5.3
Answer» ONG>Answer: 5.3×1 2.65×2 Step-by-step EXPLANATION: please mark me as BRAINLIEST

4.

Find the product correctly for the given answer 5.3

Answer» ONG>Answer:

5.3×1

2.65×2

Step-by-step EXPLANATION:

please mark me as BRAINLIEST

Discussion

5.	All prime number are odd
Answer» ong>Answer: Yes all PRIME numbers are ODD but except 2 which is also a prime number Step-by-step explanation: Mark this answer as Brainlist

5.

All prime number are odd

Answer»

ong>Answer:

Yes all PRIME numbers are ODD but except 2 which is also a prime number

Step-by-step explanation:

Mark this answer as Brainlist

Discussion

6.	Find out per unit of material when amount of material is 10000 & that production is 200
Answer» ONG>Answer: 50 is the answer Step-by-step explanation: because for 200 products the cost is 10000 for 1 unit the cost is 10000/200=50

6.

Find out per unit of material when amount of material is 10000 & that production is 200

Answer» ONG>Answer:

50 is the answer

Step-by-step explanation:

because for 200 products the cost is 10000

for 1 unit the cost is 10000/200=50

Discussion

7.	If two tangents are inclined at 120 degree are drawn to a circle of radius 4 cm find the length of each tangent...
Answer» ong>CORRECT answer: TAN 60= 5/tangent LENGTH tangent length = 5/ tan 60 $5 \div \sqrt{3}$ = 2.886

7.

If two tangents are inclined at 120 degree are drawn to a circle of radius 4 cm find the length of each tangent...

Answer»

ong>CORRECT answer:

TAN 60= 5/tangent LENGTH

tangent length = 5/ tan 60

$5 \div \sqrt{3}$

= 2.886

Discussion

8.	De fined discontinutay of the frist kind
Answer» ONG>Answer: its easy Step-by-step explanation: i cant understand your QUESTION.

8.

De fined discontinutay of the frist kind

Answer» ONG>Answer:

its easy

Step-by-step explanation:

i cant understand your QUESTION.

Discussion

9.	Find 7 rational numbers b/w -7/6 ,7/8
Answer» ong>Step-by-step explanation: Given:- The numbers are -7/6 and 7/8 To find:- Find 7 rational numbers between -7/6 and 7/8 Solution:- Given numbers are -7/6 and 7/8 Required rational numbers = 7 On WRITING them into equivalent rationals LCM of 6 and 8 = 24 (-7/6)×(4/4) =(-7×4)/(6×4) =-28/24 and (7/8)×(3/3) =(7×3)/(8×3) =21/24 The rational numbers between -7/6 and 7/8 are -27/24 , -26/24,...,17/24,18/24,19/24,20/24 (or) Given numbers are -7/6 and 7/8 Required rational numbers = 7 On writing the DENOMINATOR as 7+1 = 8 or multiple of 8 Now, (-7/6)×(8/8) =(-7×6)/(8×8) =-56/64 and (7/8)×(8/8) =(7×8)/(8×8) =56/64 The required numbers are -55/64,...,48/64,49/64,50/64,51/64,52/64,53/64,54/64,55/64. Answer:- The required numbers are -55/64,...,48/64,49/64,50/64,51/64,52/64,53/64,54/64,55/64. Note:- There are infinitely rational numbers between any two numbers.This PROPERTY is called densitive Property

9.

Find 7 rational numbers b/w -7/6 ,7/8

Answer»

ong>Step-by-step explanation:

Given:-

The numbers are -7/6 and 7/8

To find:-

Find 7 rational numbers between -7/6 and 7/8

Solution:-

Given numbers are -7/6 and 7/8

Required rational numbers = 7

On WRITING them into equivalent rationals

LCM of 6 and 8 = 24

(-7/6)×(4/4)

=(-7×4)/(6×4)

=-28/24

and (7/8)×(3/3)

=(7×3)/(8×3)

=21/24

The rational numbers between -7/6 and 7/8

are -27/24 , -26/24,...,17/24,18/24,19/24,20/24

(or)

Given numbers are -7/6 and 7/8

Required rational numbers = 7

On writing the DENOMINATOR as 7+1 = 8 or multiple of 8

Now,

(-7/6)×(8/8)

=(-7×6)/(8×8)

=-56/64

and

(7/8)×(8/8)

=(7×8)/(8×8)

=56/64

The required numbers are -55/64,...,48/64,49/64,50/64,51/64,52/64,53/64,54/64,55/64.

Answer:-

The required numbers are -55/64,...,48/64,49/64,50/64,51/64,52/64,53/64,54/64,55/64.

Note:-

There are infinitely rational numbers between any two numbers.This PROPERTY is called densitive Property

Discussion

10.	A bag contaro 3ved, 4 black and squeen balls of the Same Size. A ball is daan at sandom from the bag whatis the poobability that the ball doawb is i) red? @ not.black? ③ black?
Answer» ONG>Answer: Same Size. A ball is DAAN at sandom from the bag what is the POOBABILITY that the ball doawb is i) RED? @ not.

10.

A bag contaro 3ved, 4 black and squeen balls of the Same Size. A ball is daan at sandom from the bag whatis the poobability that the ball doawb is i) red? @ not.black? ③ black?

Answer» ONG>Answer:

Same Size. A ball is DAAN at sandom from the bag what

is the POOBABILITY that the ball doawb is i) RED? @ not.

Discussion

11.	36πcm2 is curred surface area ofa sphere the find volume
Answer» > i HOPE the ANSWER is right and this is HELPFUL for you

11.

36πcm2 is curred surface area ofa sphere the find volume

Answer»

>

i HOPE the ANSWER is right

and this is HELPFUL for you

Discussion

12.	In how many years the amount for Rs. 10000 becomes Rs. 12100 at 10% compound interest? 1️⃣ 12️⃣ 23️⃣ 34️⃣ 4
Answer» ONG>Answer: 2 year Step-by-step explanation: I HOPE HELP full for you to

12.

In how many years the amount for Rs. 10000 becomes Rs. 12100 at 10% compound interest? 1️⃣ 12️⃣ 23️⃣ 34️⃣ 4

Answer» ONG>Answer:

2 year

Step-by-step explanation:

I HOPE HELP full for you to

Discussion

13.	Is quadrilateral ABCD a parallogram, if
Answer» $\huge \fbox \green{❤Answer:}$ Hint: Think of the property of PARALLELOGRAM which states opposite angles of parallelogram is equal.Complete step-by-step answer:In the question, we are GIVEN two approach angles which are $ZA = 70° , C = 65° of \: ABCD$ Now, we have to say whether the quadrilateral is parallelogram or not.Before telling, we will FIRST briefly tell characteristics of parallelogram. A simple (non-self intersecting) quadrilateral is a parallelogram if and only if one of the FOLLOWING statements is true:(a) Two pairs of opposite sides are parallel.(b) Two pairs of opposite sides are equal in length.(c) Two pairs of opposite angles are equal in measure.(d) The diagonals bisect eachother.(e) One pair of opposite sides is parallel and equal in length.(f) Adjacent angles are supplementary.(g) The diagonals bisect into two congruent triangles.In one of the characteristics it was given that opposite angles of parallelogram are equal.Here, angle A and angle C are opposite angles of parallelogram. So, they should be equal but in the given question $ZA \: is \: 70° \: and \: ZC \: is \: 65°$ . So, the quadrilateral is not a parallelogram.Hence, it is not a parallelogram. Note: Students should know the properties of all the special quadrilaterals which may help to tackle this kind of question easily and so they can do them very SMOOTHLY. $\\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

13.

Is quadrilateral ABCD a parallogram, if

Answer»

$\huge \fbox \green{❤Answer:}$

Hint: Think of the property of

PARALLELOGRAM which states opposite

angles of parallelogram is equal.Complete step-by-step answer:In the question, we are GIVEN two approach angles which are

$ZA = 70° , C = 65° of \: ABCD$

Now, we have to say whether the quadrilateral is parallelogram or not.Before telling, we will FIRST briefly tell characteristics of parallelogram. A simple (non-self intersecting) quadrilateral is a parallelogram if and only if one of the FOLLOWING statements is true:(a) Two pairs of opposite sides are parallel.(b) Two pairs of opposite sides are equal in length.(c) Two pairs of opposite angles are equal in measure.(d) The diagonals bisect eachother.(e) One pair of opposite sides is parallel and equal in length.(f) Adjacent angles are supplementary.(g) The diagonals bisect into two congruent triangles.In one of the characteristics it was given that opposite angles of parallelogram are equal.Here, angle A and angle C are opposite angles of parallelogram. So, they should be equal but in the given question

$ZA \: is \: 70° \: and \: ZC \: is \: 65°$

. So, the quadrilateral is not a

parallelogram.Hence, it is not a parallelogram. Note: Students should know the properties of all the special quadrilaterals which may help to tackle this kind of question easily and so they can do them very SMOOTHLY.

$\\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

Discussion

14.	Which of the following sets are single tone set ?. Multiple choice. (1 Point)Negative natural numberAn odd prime number less than fourNatural number greater than 5 and less than 7Square root of negative numberin in
Answer» ong>Answer: *the* *RIGHT* *answer* square root of NEGATIVE number in like, COMMENT, rate to my answer

14.

Which of the following sets are single tone set ?. Multiple choice. (1 Point)Negative natural numberAn odd prime number less than fourNatural number greater than 5 and less than 7Square root of negative numberin in

Answer»

ong>Answer:

the RIGHT answer

square root of NEGATIVE number in

like, COMMENT, rate

to my answer

Discussion

15.	Seema is painting the walls and ceiling of a hall whose dimensions are 10 m x 15 m x 5 m, from each can pf paint 120m2 of area is painted. How many cans of paint she need to pain the hall?
Answer» $\large\underline{\sf{Solution-}}$ Dimensions of Room :- Length of Room = 10 m Breadth of Room = 15 m Height of Room = 5 m We know, that $\boxed{ \sf \: Area_{(walls)} \: = \: 2(length + breadth) \times height}$ So, On PLUGGING the VALUES, we have $\rm :\longmapsto\:Area_{(walls)} = 2(15 + 10) \times 5$ $\rm :\longmapsto\:Area_{(walls)} = 10 \times 25$ $\bf\implies \:Area_{(walls)} = 250 \: {m}^{2}$ We know that, $\boxed{ \sf \: Area_{(ceiling)} = length \times breadth}$ On plugging the values, we have $\rm :\longmapsto\:Area_{(ceiling)} = 10 \times 15$ $\bf\implies \:Area_{(ceiling)} = 150 \: {m}^{2}$ Total area to be painted, $\rm :\longmapsto\:Area_{(to \: be \: painted)} = Area_{(walls)} + Area_{(ceiling)}$ $\rm :\longmapsto\:Area_{(to \: be \: painted)} = 250 + 150$ $\bf\implies \:Area_{(to \: be \: painted)} = 400 \: {m}^{2}$ Now, In ONE can, area to be painted = 120 square meter. To PAINT area of 400 square meter, number of cans required, $\rm :\longmapsto\:Number_{(cans)} \: = \dfrac{400}{120} = 3.33 \:$ $\bf\implies \:Number_{(cans)} \: = \: 4 \: cans \: required.$ Additional Information :- $\boxed{ \sf{ \: CSA{(cylinder)} = 2\pi \: rh}}$ $\boxed{ \sf{ \: Volume_{(cuboid)} = lbh}}$ $\boxed{ \sf{ \: Volume_{(cone)} = \dfrac{1}{3} \pi \: {r}^{2} h}}$ $\boxed{ \sf{ \: Volume_{(cube)} = {(edge)}^{3} }}$ $\boxed{ \sf{ \: TSA{(cone)} = {6(edge)}^{2} }}$ $\boxed{ \sf{ \: TSA{(cuboid)} = 2(lb + bh + hl)}}$ $\boxed{ \sf{ \: TSA{(cone)} = \pi \: r(l + r)}}$ $\boxed{ \sf{ \: TSA{(cylinder)} = 2\pi \: r(h + r)}}$ $\boxed{ \sf{ \: CSA{(cone)} = \pi \: rl}}$

15.

Seema is painting the walls and ceiling of a hall whose dimensions are 10 m x 15 m x 5 m, from each can pf paint 120m2 of area is painted. How many cans of paint she need to pain the hall?

Answer»

$\large\underline{\sf{Solution-}}$

Dimensions of Room :-

Length of Room = 10 m

Breadth of Room = 15 m

Height of Room = 5 m

We know, that

$\boxed{ \sf \: Area_{(walls)} \: = \: 2(length + breadth) \times height}$

So,

On PLUGGING the VALUES, we have

$\rm :\longmapsto\:Area_{(walls)} = 2(15 + 10) \times 5$

$\rm :\longmapsto\:Area_{(walls)} = 10 \times 25$

$\bf\implies \:Area_{(walls)} = 250 \: {m}^{2}$

We know that,

$\boxed{ \sf \: Area_{(ceiling)} = length \times breadth}$

On plugging the values, we have

$\rm :\longmapsto\:Area_{(ceiling)} = 10 \times 15$

$\bf\implies \:Area_{(ceiling)} = 150 \: {m}^{2}$

Total area to be painted,

$\rm :\longmapsto\:Area_{(to \: be \: painted)} = Area_{(walls)} + Area_{(ceiling)}$

$\rm :\longmapsto\:Area_{(to \: be \: painted)} = 250 + 150$

$\bf\implies \:Area_{(to \: be \: painted)} = 400 \: {m}^{2}$

Now,

In ONE can, area to be painted = 120 square meter.

To PAINT area of 400 square meter, number of cans required,

$\rm :\longmapsto\:Number_{(cans)} \: = \dfrac{400}{120} = 3.33 \:$

$\bf\implies \:Number_{(cans)} \: = \: 4 \: cans \: required.$

Additional Information :-

$\boxed{ \sf{ \: CSA{(cylinder)} = 2\pi \: rh}}$

$\boxed{ \sf{ \: Volume_{(cuboid)} = lbh}}$

$\boxed{ \sf{ \: Volume_{(cone)} = \dfrac{1}{3} \pi \: {r}^{2} h}}$

$\boxed{ \sf{ \: Volume_{(cube)} = {(edge)}^{3} }}$

$\boxed{ \sf{ \: TSA{(cone)} = {6(edge)}^{2} }}$

$\boxed{ \sf{ \: TSA{(cuboid)} = 2(lb + bh + hl)}}$

$\boxed{ \sf{ \: TSA{(cone)} = \pi \: r(l + r)}}$

$\boxed{ \sf{ \: TSA{(cylinder)} = 2\pi \: r(h + r)}}$

$\boxed{ \sf{ \: CSA{(cone)} = \pi \: rl}}$

Discussion

16.	In this picture equilataral quadrilateral is givan . find tha measurement of angle Y
Answer» do ATTACH the PICTURE too...

Discussion

17.	profit as per cost account 46100 in cost account under expenses over expense under income 89650 what is the financial account?
Answer» ONG>ANSWER: Step-by-step EXPLANATION:

17.

profit as per cost account 46100 in cost account under expenses over expense under income 89650 what is the financial account?

Answer» ONG>ANSWER:

Step-by-step EXPLANATION:

Discussion

18.	Total production is 300 units then find out per units when direct expense is 6000
Answer» ONG>ANSWER: per unit = Expenses / total PRODUCTION = 6000/ 300 = 20 per unit is cost

18.

Total production is 300 units then find out per units when direct expense is 6000

Answer» ONG>ANSWER:

per unit = Expenses / total PRODUCTION

= 6000/ 300

= 20 per unit is cost

Discussion

19.	Partialfraction1÷x-lis equivalento
Answer» ONG>Answer: 1/X is in deed EQUAL to Step-by-step EXPLANATION: x^(-1)

19.

Partialfraction1÷x-lis equivalento

Answer» ONG>Answer:

1/X is in deed EQUAL to

Step-by-step EXPLANATION:

x^(-1)

Discussion

20.	Find the value of (x-3)(x-4)
Answer» ong>ANSWER: HOPE this will helps you FRIEND.

20.

Find the value of (x-3)(x-4)

Answer»

ong>ANSWER:

HOPE this will helps you FRIEND.

Discussion

21.	4 Q. 1. (B) Solve the following subquestions :The lengths of the sides of a triangle are 9, 40, 41. Statewhether the triangle is right angled triangle.
Answer» ONG>ANSWER: hxgshwhefwydhbeebebwbdbf

Discussion

22.	What is mean praportional of 4 and 25
Answer» ong>Step-by-step explanation: The mean proportional between the DIGITS is equal to the SQUARE of the products of given digits. HENCE, the mean proportional between 4 and 25 is 4.25

22.

What is mean praportional of 4 and 25

Answer»

ong>Step-by-step explanation:

The mean proportional between the DIGITS is equal to the SQUARE of the products of given digits. HENCE, the mean proportional between 4 and 25 is 4.25

Discussion

23.	The product of fractions are_________
Answer» ONG>Answer: 1 is your answer Step-by-step EXPLANATION: PLEASE MARK me as BRANLIEST

23.

The product of fractions are_________

Answer» ONG>Answer:

1 is your answer

Step-by-step EXPLANATION:

PLEASE MARK me as BRANLIEST

Discussion

24.	Sin 20° = cos ______ °
Answer» ONG>Answer: 180 the MISSING ANGLE is 180-90-20=70degrees

Discussion

25.	Bandwidth of a Contal isdeczesed, when compresator used is
Answer» ONG>Answer: yes Step-by-step EXPLANATION: when COMPRESATOR is used then tge conpressor will BECOME more conperssed between each other so the compreseator is compressed

25.

Bandwidth of a Contal isdeczesed, when compresator used is

Answer» ONG>Answer:

yes

Step-by-step EXPLANATION:

when COMPRESATOR is used then tge conpressor will BECOME more conperssed between each other so the compreseator is compressed

Discussion

26.	Anu travels 4 2/5 km by bus and 3)7 km by walking to reach school from her house . Find the distance from her house to school
Answer» ONG>ANSWER: please give the question NEAT clean then i will give you the answer

Discussion

27.	If 4x-5=13 then value of x is
Answer» ONG>Step-by-step EXPLANATION: x=9/2 please MARK me as BRAINLIEST

27.

If 4x-5=13 then value of x is

Answer» ONG>Step-by-step EXPLANATION:

x=9/2

please MARK me as BRAINLIEST

Discussion

28.	Match the pair: L(-2,4)1. On y-xisS(7,0)2. III quadrant• M(-3,-4)3. IV quadrantP(2, -3)4. On X-axis5. Il quadrant6. D quadrant
Answer» ONG>Answer: 4 on x_ AXIS Step-by-step EXPLANATION: ljxdjxixzhdddjixxh

28.

Match the pair: L(-2,4)1. On y-xisS(7,0)2. III quadrant• M(-3,-4)3. IV quadrantP(2, -3)4. On X-axis5. Il quadrant6. D quadrant

Answer» ONG>Answer:

4 on x_ AXIS

Step-by-step EXPLANATION:

ljxdjxixzhdddjixxh

Discussion

29.	Find 2 1/5 - (-1)/3
Answer» Step-by-step explanation: CLICK and SEE OK MARK me as branlist

29.

Find 2 1/5 - (-1)/3

Answer»

Step-by-step explanation:

CLICK and SEE OK MARK me as branlist

Discussion

30.	When 5 is subtracted from the length and breadth of the rectangle the perimeter becomes 26. What is the mathematical form of the statement ?
Answer» ONG>Step-by-step EXPLANATION: p=2(l+b) l-5 b-5 then, p=2(l-5+b-5)=26 p=l-5+b-5=26/2=13 l+b-10=13 l+b=23

30.

When 5 is subtracted from the length and breadth of the rectangle the perimeter becomes 26. What is the mathematical form of the statement ?

Answer» ONG>Step-by-step EXPLANATION:

p=2(l+b)

l-5

b-5

then,

p=2(l-5+b-5)=26

p=l-5+b-5=26/2=13

l+b-10=13

l+b=23

Discussion

31.	A rectangular block 8cm * 4cm of mass 160 gm find the pressure exerted by block
Answer» ONG>Answer: 587577 8w9q Step-by-step explanation: 9yyowiagjgapfaojjacoa

31.

A rectangular block 8cm * 4cm of mass 160 gm find the pressure exerted by block

Answer» ONG>Answer:

587577 8w9q

Step-by-step explanation:

9yyowiagjgapfaojjacoa

Discussion

32.	Two numbers are in theratio 5:45:4 and their sumis 514 Then find thosenumbers
Answer» ONG>Answer: ESKA answer upper PAPER me HAI

32.

Two numbers are in theratio 5:45:4 and their sumis 514 Then find thosenumbers

Answer» ONG>Answer:

ESKA answer upper PAPER me HAI

Discussion

33.	In ΔPQR , ∠ Q = 90° , ∠P = θ , PQ = 12 , QR = 5 find cos θ.
Answer» he PIC it's CLEARLY EXPLAINED ,HOPE it HELPS...

Discussion

34.	Solve find mode of 10,20,30,10,40,30,10,20
Answer» means repeats HIGHEST TIME... so our mode is 10. Hope it HELPS you....

34.

Solve find mode of 10,20,30,10,40,30,10,20

Answer»

means repeats HIGHEST TIME...

so our mode is 10.

Hope it HELPS you....

Discussion

35.	Find the medium of the observation 59,75,68,70,74,75,80
Answer» rong>answer: the MEDIUM OBSERVATION is 74

35.

Find the medium of the observation 59,75,68,70,74,75,80

Answer»

rong>answer:

the MEDIUM OBSERVATION is 74

Discussion

36.	What should be the interest rate and duration for principal Rs. 500 for 1 year at 12% compounded quarterly ? 1️⃣ R = 12% N = 1 year2️⃣ R = 6% N = 23️⃣ R = 3% N = 44️⃣ R = 6% N= 4 year
Answer» ONG>Answer: Dan ddbd DODD Dodd did d DND d d DVD db db

Discussion

37.	The length, breath and height of a room are 3m, 4m and 3 m respectively. Find the cost of while washing the wall of the room and ceiling at the rate of Rs. 7.50 per
Answer» ong>Answer: Area of RECTANGLE = lbh = 343 = 36 cost = 36*7.5 = 270 is cost

37.

The length, breath and height of a room are 3m, 4m and 3 m respectively. Find the cost of while washing the wall of the room and ceiling at the rate of Rs. 7.50 per

Answer»

ong>Answer:

Area of RECTANGLE = lbh

= 3*4*3

= 36

cost = 36*7.5

= 270 is cost

Discussion

38.	Insert three rational numbers lying between -1/2 and -3/4
Answer» ONG>ANSWER: 5/8 and 11/16.may be the answer

Discussion

39.	SOBICE SectionSelect and write most appropriate answer fromThe co ternal angle of 120" is120°. ) 240 (2560" @ 3011 =W=WEWhere Wis complex aute of
Answer» ONG>ANSWER: please mark mee as brainlist

Discussion

40.	3) Rajesh kept 26 cards in a cap bearing one English alphabet on each card. One card is drawn at random. What is the probability that the card drawn is a consonant card?S = {a,b,c,d,e,f,g,h,i,j,k,1,m,n,o,p,q,r,s,t,u,v,w,x,y,z}n(S) = 26Let A be the event that the card drawn is a consonantA=}n(A) =therefore, P(A)=(
Answer» ANSWER Step-by-step EXPLANATION: "n" (and any subsequent WORDS) was ignored because we LIMIT queries to 32 words.

40.

3) Rajesh kept 26 cards in a cap bearing one English alphabet on each card. One card is drawn at random. What is the probability that the card drawn is a consonant card?S = {a,b,c,d,e,f,g,h,i,j,k,1,m,n,o,p,q,r,s,t,u,v,w,x,y,z}n(S) = 26Let A be the event that the card drawn is a consonantA=}n(A) =therefore, P(A)=(

Answer»

ANSWER

Step-by-step EXPLANATION:

"n" (and any subsequent WORDS) was ignored because we LIMIT queries to 32 words.

Discussion

41.	11i) If w is a complex cube root of unity then find the value of+ww2
Answer» ong>ANSWER: I GIVE you answer LATER ok

41.

11i) If w is a complex cube root of unity then find the value of+ww2

Answer»

ong>ANSWER:

I GIVE you answer LATER ok

Discussion

42.	Find the value of k, if the roots of the quadratic equation 2 2 − 6 + = 0 are real and equal
Answer» ONG>Answer: I cannot understand the QUESTION post this question again

42.

Find the value of k, if the roots of the quadratic equation 2 2 − 6 + = 0 are real and equal

Answer» ONG>Answer:

I cannot understand the QUESTION

post this question again

Discussion

43.	2. Show that any positive odd integer is of the form bq +1,08 6q +3,08 6q+5, where q issome integer.
Answer» ONG>Step-by-step EXPLANATION: जग से हा ही में आरक्षण को समाप्त कर सकते है उन्होंने बताया गया था लेकिन वह अपनी पत्नी और खूबसूरत राजकुमारियां है उन्होंने बताया है इस पर विचार करना है इस कारण हो सकता हैं तो आप पॉइंट्स जुटा रहा हो गया और क्या चाहिए क्योंकि इस प्रकार हैं वासु में ही बात कराओ में ही में आरक्षण पर विचार करना है कि वो एक योग से किसी ने बताया गया और खूबसूरत विशालकाय कंकाल बरामद हुए भी सोया नहीं जानता कि यह एक और क्या नहीं जानता कि वह यह भी खौफनाक मंजर है और खूबसूरत राजकुमारियां

Discussion

44.	2x 3x7xaxaxaxbxxbxbxc
Answer» ong>ANSWER: (2x3x7)(axaxa)(bxbxb)c (42)(a³)(b³)c 42a³b³c

44.

2x 3x7xaxaxaxbxxbxbxc

Answer»

ong>ANSWER:

(2x3x7)(axaxa)(bxbxb)c

(42)(a³)(b³)c

42a³b³c

Discussion

45.	in a building there are 25 cylindrical pipes the radius of each pillar is 50 cm and height is 5 metres
Answer» ong>Step-by-step explanation: In a building there are 25 CYLINDRICAL pylars . ★ The radius of each pillar is 50 cm and height 5m ★ The cost to paint the Curved surface area of the pillars is at the rate rs. 70 per m² { \large{ \underline{ \pmb{ \frak{ To \: find: }}}}} Tofind: Tofind: ★ The Cost of fencing the 25 cylindrical pillars { \large{ \underline{ \pmb{ \frak{ Understanding\:the \: concept : }}}}} Understandingtheconcept: Understandingtheconcept: ☀️Concept : Here, we have been given that the building has 25 cylindrical pillars and the thier radius is 50cm as that the hieght is 5m each. And the cost of painting them is at 70 rs. per meter ❍Now, So, First we have to find the curved surface area of the 25 pillars and then we should find the cost to painting them. { \large{ \underline{ \pmb{ \frak{ Using \: the \: formulae : }}}}} Usingtheformulae: Usingtheformulae: ★ Formula to find the curved surface area of a RIGHT circular cylinder is 2πrh( according to the given measurements), { \large{ \underline{ \pmb{ \frak{ Using\:the \: concept : }}}}} Usingtheconcept: Usingtheconcept: ~Now, We have to use the above mentioned formula and then substitute the values of radius , hieght Note : before substituting we have to check weather our measurements are in the same units ~here : Radius = 50cm hieght = 5m ~As they are different units let's convert the radius from cm to m { \underline{ \frak{As \: we \: know \: that}}} Asweknowthat ★ 1M = 100cm ★ 0.5m = 50cm ↬ So, the radius of the cylinder is 0.5m { \large{ \underline{ \pmb{ \frak{Solution : }}}}} Solution: Solution: ★Cost to paint 25 cylinders = rs 25700 { \large{ \underline{ \pmb{ \frak{FULL \: solution : }}}}} Fullsolution: Fullsolution: ~ Firstly let's find curved surface area of 1 cylinder. let's substitute the values now to find it..! ✪ Curved surface area of a cylinder = 2πrh \begin{gathered}\begin{gathered} \\ \END{gathered} \end{gathered} \begin{gathered}\begin{gathered}\longrightarrow \tt \: c.s.a \: = 2\pi \: rh \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \: c.s.a = 2 \times \frac{22}{7} \times 0.5 \times 5 \\ \\ \\ \longrightarrow \tt \: c.s.a = \frac{110}{7} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \end{gathered}\end{gathered} ⟶c.s.a=2πrh ⟶c.s.a=2× 7 22 ×0.5×5 ⟶c.s.a= 7 110 \begin{gathered}\begin{gathered} \\ \end{gathered}\end{gathered} There fore curved surface area of 1 cylinder = 110/7m² ~Now, let's find the curved surface area of 25 cylinders ✪ Curved surface area of 25 cylinders = c.s.a of 1 cylinder times 25 ➠ 25 × 110/7 ➠ 2570/7m² ➽Now let's find the cost to paint them,As we know that the cost to paint is 70rs. per m² let's multiply it with 70 per sq.units ➠ 70 × 2570 /7 ➠ 2570 × 10 ➠rs.25700 \begin{gathered}\begin{gathered}\\\end{gathered}\end{gathered} Hence: The cost to paint the cylinders in total is rupees 25700 ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━ Diagram: In a building there are 25 cylindrical pylars . ★ The radius of each pillar is 50 cm and height 5m ★ The cost to paint the Curved surface area of the pillars is at the rate rs. 70 per m² { \large{ \underline{ \pmb{ \frak{ To \: find: }}}}} Tofind: Tofind: ★ The Cost of fencing the 25 cylindrical pillars { \large{ \underline{ \pmb{ \frak{ Understanding\:the \: concept : }}}}} Understandingtheconcept: Understandingtheconcept: ☀️Concept : Here, we have been given that the building has 25 cylindrical pillars and the thier radius is 50cm as that the hieght is 5m each. And the cost of painting them is at 70 rs. per meter ❍Now, So, First we have to find the curved surface area of the 25 pillars and then we should find the cost to painting them. { \large{ \underline{ \pmb{ \frak{ Using \: the \: formulae : }}}}} Usingtheformulae: Usingtheformulae: ★ Formula to find the curved surface area of a right circular cylinder is 2πrh( according to the given measurements), { \large{ \underline{ \pmb{ \frak{ Using\:the \: concept : }}}}} Usingtheconcept: Usingtheconcept: ~Now, We have to use the above mentioned formula and then substitute the values of radius , hieght Note : before substituting we have to check weather our measurements are in the same units ~here : Radius = 50cm hieght = 5m ~As they are different units let's convert the radius from cm to m {} Asweknowthat ★ 1m = 100cm ★ 0.5m = 50cm ↬ So, the radius of the cylinder is 0.5m ★Cost to paint 25 cylinders = rs 25700 ~ Firstly let's find curved surface area of 1 cylinder. let's substitute the values now to find it..! ✪ Curved surface area of a cylinder = 2πr ⟶c.s.a=2πrh ⟶c.s.a=2× 7 22 ×0.5×5 ⟶c.s.a= 7 110 There fore curved surface area of 1 cylinder = 110/7m² ~Now, let's find the curved surface area of 25 cylinders ✪ Curved surface area of 25 cylinders = c.s.a of 1 cylinder times 25 ➠ 25 × 110/7 ➠ 70 × 2570 /7 ➠ 2570 × 10 ➠rs.25700 Hence: The cost to paint the cylinders in total is rupees 25700

45.

in a building there are 25 cylindrical pipes the radius of each pillar is 50 cm and height is 5 metres

Answer»

ong>Step-by-step explanation:

In a building there are 25 CYLINDRICAL pylars .

★ The radius of each pillar is 50 cm and height 5m

★ The cost to paint the Curved surface area of the pillars is at the rate rs. 70 per m²

{ \large{ \underline{ \pmb{ \frak{ To \: find: }}}}}

Tofind:

★ The Cost of fencing the 25 cylindrical pillars

{ \large{ \underline{ \pmb{ \frak{ Understanding\:the \: concept : }}}}}

Understandingtheconcept:

☀️Concept : Here, we have been given that the building has 25 cylindrical pillars and the thier radius is 50cm as that the hieght is 5m each. And the cost of painting them is at 70 rs. per meter

❍Now, So, First we have to find the curved surface area of the 25 pillars and then we should find the cost to painting them.

{ \large{ \underline{ \pmb{ \frak{ Using \: the \: formulae : }}}}}

Usingtheformulae:

★ Formula to find the curved surface area of a RIGHT circular cylinder is 2πrh( according to the given measurements),

{ \large{ \underline{ \pmb{ \frak{ Using\:the \: concept : }}}}}

Usingtheconcept:

~Now, We have to use the above mentioned formula and then substitute the values of radius , hieght

Note : before substituting we have to check weather our measurements are in the same units

~here :

Radius = 50cm

hieght = 5m

~As they are different units let's convert the radius from cm to m

{ \underline{ \frak{As \: we \: know \: that}}}

Asweknowthat

★ 1M = 100cm

★ 0.5m = 50cm

↬ So, the radius of the cylinder is 0.5m

{ \large{ \underline{ \pmb{ \frak{Solution : }}}}}

Solution:

★Cost to paint 25 cylinders = rs 25700

{ \large{ \underline{ \pmb{ \frak{FULL \: solution : }}}}}

Fullsolution:

~ Firstly let's find curved surface area of 1 cylinder.

let's substitute the values now to find it..!

✪ Curved surface area of a cylinder = 2πrh

\begin{gathered}\begin{gathered} \\ \END{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\longrightarrow \tt \: c.s.a \: = 2\pi \: rh \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \: c.s.a = 2 \times \frac{22}{7} \times 0.5 \times 5 \\ \\ \\ \longrightarrow \tt \: c.s.a = \frac{110}{7} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \end{gathered}\end{gathered}

⟶c.s.a=2πrh

⟶c.s.a=2×

7

22

×0.5×5

⟶c.s.a=

7

110

\begin{gathered}\begin{gathered} \\ \end{gathered}\end{gathered}

There fore curved surface area of 1 cylinder = 110/7m²

~Now, let's find the curved surface area of 25 cylinders

✪ Curved surface area of 25 cylinders = c.s.a of 1 cylinder times 25

➠ 25 × 110/7

➠ 2570/7m²

➽Now let's find the cost to paint them,As we know that the cost to paint is 70rs. per m² let's multiply it with 70 per sq.units

➠ 70 × 2570 /7

➠ 2570 × 10

➠rs.25700

\begin{gathered}\begin{gathered}\\\end{gathered}\end{gathered}

Hence:

The cost to paint the cylinders in total is rupees 25700

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Diagram:

In a building there are 25 cylindrical pylars .

★ The radius of each pillar is 50 cm and height 5m

★ The cost to paint the Curved surface area of the pillars is at the rate rs. 70 per m²

{ \large{ \underline{ \pmb{ \frak{ To \: find: }}}}}

Tofind:

★ The Cost of fencing the 25 cylindrical pillars

{ \large{ \underline{ \pmb{ \frak{ Understanding\:the \: concept : }}}}}

Understandingtheconcept:

☀️Concept : Here, we have been given that the building has 25 cylindrical pillars and the thier radius is 50cm as that the hieght is 5m each. And the cost of painting them is at 70 rs. per meter

❍Now, So, First we have to find the curved surface area of the 25 pillars and then we should find the cost to painting them.

{ \large{ \underline{ \pmb{ \frak{ Using \: the \: formulae : }}}}}

Usingtheformulae:

★ Formula to find the curved surface area of a right circular cylinder is 2πrh( according to the given measurements),

{ \large{ \underline{ \pmb{ \frak{ Using\:the \: concept : }}}}}

Usingtheconcept:

~Now, We have to use the above mentioned formula and then substitute the values of radius , hieght

Note : before substituting we have to check weather our measurements are in the same units

~here :

Radius = 50cm

hieght = 5m

~As they are different units let's convert the radius from cm to m

{}

Asweknowthat

★ 1m = 100cm

★ 0.5m = 50cm

↬ So, the radius of the cylinder is 0.5m

★Cost to paint 25 cylinders = rs 25700

~ Firstly let's find curved surface area of 1 cylinder.

let's substitute the values now to find it..!

✪ Curved surface area of a cylinder = 2πr

⟶c.s.a=2πrh

⟶c.s.a=2×

7

22

×0.5×5

⟶c.s.a=

7

110

There fore curved surface area of 1 cylinder = 110/7m²

~Now, let's find the curved surface area of 25 cylinders

✪ Curved surface area of 25 cylinders = c.s.a of 1 cylinder times 25

➠ 25 × 110/7

➠ 70 × 2570 /7

➠ 2570 × 10

➠rs.25700

Hence:

The cost to paint the cylinders in total is rupees 25700

Discussion

46.	M apple is placed is a basket .how many apple must be placed in 10 such baskets.
Answer» ONG>Answer: 10M Step-by-step explanation: M apples = 1 basket 10 BASKETS MUST have =. 10M apples

46.

M apple is placed is a basket .how many apple must be placed in 10 such baskets.

Answer» ONG>Answer:

10M

Step-by-step explanation:

M apples = 1 basket

10 BASKETS MUST have =. 10M apples

Discussion

47.	14. Find the distance travelled by Sandhya, If she walks 3-rounds of a square park or 20-meters.A) 160metersB) 80metersC) 20metersD) None of these
Answer» ong>ANSWER: C. 20 meters is your RIGHT answer

47.

14. Find the distance travelled by Sandhya, If she walks 3-rounds of a square park or 20-meters.A) 160metersB) 80metersC) 20metersD) None of these

Answer»

ong>ANSWER:

C. 20 meters

is your RIGHT answer

Discussion

48.	Question 3 नीचे दिये गए विकल्पों में से किस विकल्प में संख्या 7के पहले चार गुणज रखे हैं ? Which of the optiongiven below has the first four multiples ofthe number 7?
Answer» ONG>ANSWER: क्वेश्चन अधूरा है विकल्प तो है ही नहीं।

Discussion

49.	8.IF a/b+b/a=-1,then ™-b™
Answer» ong>Answer: PANTOPRAZOLE is used to treat certain STOMACH and esophagus PROBLEMS (such as acid reflux). It WORKS by decreasing the AMOUNT of acid your stomach makes. This medication relieves symptoms such as heartburn, difficulty swallowing, and persistent cough

49.

8.IF a/b+b/a=-1,then ™-b™

Answer»

ong>Answer:

PANTOPRAZOLE is used to treat certain STOMACH and esophagus PROBLEMS (such as acid reflux). It WORKS by decreasing the AMOUNT of acid your stomach makes. This medication relieves symptoms such as heartburn, difficulty swallowing, and persistent cough

Discussion

50.	Assessment K LQuestion 8 8उस वर्गाकार भूखंड का क्षेत्रफल ज्ञात कीजिये जिसकीएक भुजा की लंबाई 7 मीटर हो ?Find the area ofthe square plot whose length of one side is 7meters?
Answer» ONG>ANSWER: PLEASE write the question PROPERLY

Discussion

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8.IF a/b+b/a=-1,then ™-b™

Assessment K LQuestion 8 8उस वर्गाकार भूखंड का क्षेत्रफल ज्ञात कीजिये जिसकीएक भुजा की लंबाई 7 मीटर हो ?Find the area ofthe square plot whose length of one side is 7meters?