332354 + Interview Questions in Secondary School in Math

1.	Write an equation that is passing through (-2,8) and PERPENDICULAR to y=2x+5.
Answer» ong>Answer: x+2y-14=0 Step-by-step explanation: slope of given equation is 2 slope of LINE perpendicular will be -½ USING one point form the answer can be OBTAINED

1.

Write an equation that is passing through (-2,8) and PERPENDICULAR to y=2x+5.

Answer»

ong>Answer:

x+2y-14=0

Step-by-step explanation:

slope of given equation is 2

slope of LINE perpendicular will be -½

USING one point form the answer can be OBTAINED

Discussion

2.	Factorise. х³ – 3х + Зу – у²
Answer» ONG>ANSWER: X (x² - 3) y (3 - y) Hope it helps you!

2.

Factorise. х³ – 3х + Зу – у²

Answer» ONG>ANSWER:

X (x² - 3) y (3 - y)

Hope it helps you!

Discussion

3.	Q ^2+ 89 +596 = 0 find the value of x
Answer» ONG>Step-by-step EXPLANATION: x^2 + 685= 0 x^2= - 685 x=√-685 x= 26.17 APPROX.

3.

Q ^2+ 89 +596 = 0 find the value of x

Answer» ONG>Step-by-step EXPLANATION:

x^2 + 685= 0

x^2= - 685

x=√-685

x= 26.17 APPROX.

Discussion

4.	Find the zeroes of the polynomial x2 - 3 and verify the relationship between the zeroes and the coefficients.
Answer» ong>Step-by-step EXPLANATION: I HOPE it will be HELP full for you

4.

Find the zeroes of the polynomial x2 - 3 and verify the relationship between the zeroes and the coefficients.

Answer»

ong>Step-by-step EXPLANATION:

I HOPE it will be HELP full for you

Discussion

5.	A milkman buys 20 litres of milk partly at the rate of Rs. 40 per litre and the remaining at the rate of Rs 42 per litre. by selling whole milk he gets Rs. 816. if in this transaction he has neither gained nor lost, then find the separate quantity of milk purchased at given rates. solve using arithmetic progression
Answer» ONG>ANSWER: I THING the answer is 3016

Discussion

6.	Who will not impressed from this writing. I think it's really good.
Answer» ONG>Step-by-step EXPLANATION: it's NICE HANDWRITING ☺

Discussion

7.	Fill in the blanks in the picture
Answer» ong>Answer: Blank 1 :- Trapezium Blank 2 :- Equal Blank 3 :- 12.57 Blank 4 :- 95.42 Step-by-step EXPLANATION: For blank 3 :- Adjacent angles of trapezium has a sum of 180° . (8X - 16) + (6x + 20) = 180 14x + 4 = 180 x = 176/14 x = 12.57 For blank 4 :- Angle N = 6x + 20 = 6(12.57) + 20 = 75.42 + 20 = 95.42

7.

Fill in the blanks in the picture

Answer»

ong>Answer:

Blank 1 :- Trapezium

Blank 2 :- Equal

Blank 3 :- 12.57

Blank 4 :- 95.42

Step-by-step EXPLANATION:

For blank 3 :-

Adjacent angles of trapezium has a sum of 180° .

(8X - 16) + (6x + 20) = 180

14x + 4 = 180

x = 176/14

x = 12.57

For blank 4 :-

Angle N = 6x + 20

= 6(12.57) + 20

= 75.42 + 20

= 95.42

Discussion

8.	(a3)3 = (a) -3 then find2-3aIf a(a“)the value of 2'5 is
Answer» ong>Answer: I feel LIKE a good PERSON to be with the people I care

8.

(a3)3 = (a) -3 then find2-3aIf a(a“)the value of 2'5 is

Answer»

ong>Answer:

I feel LIKE a good PERSON to be with the people I care

Discussion

9.	6 Show that the relation “greater thar" on the set of natural numbers N, is transitive but is neither reflexive nor symmetric.
Answer» Basic Concept :- Reflexive :- RELATION is reflexive, If (a, a) ∈ R for every a ∈ A. Symmetric :- Relation is symmetric, If (a, B) ∈ R, then (b, a) ∈ R. Transitive :- Relation is transitive, If (a, b) ∈ R & (b, c) ∈ R, then (a, c) ∈ R. Let's solve the PROBLEM now!! The given Relation R can be mathematically represent as $\rm :\longmapsto\:R \: = \{(a, b) : a > b \: where \: a, b \in \: N \}$ Reflexive :- $\rm :\longmapsto\:Let \: a \in \: N$ $\rm :\longmapsto\:We \: know, \: a \: = \: a$ $\rm :\implies\:a \: \cancel > \: a$ $\rm :\implies\:(a, a) \: \cancel \in \: R$ $\bf\implies \:R \: is \: not \: reflexive.$ Symmetric :- $\rm :\longmapsto\:Let \: a, b \: \in \: N \: such \: that \: (a, b) \in \: R$ $\rm :\implies\:a > b$ $\rm \: \cancel{\implies\:} \: b > a$ $\rm :\implies\:(a, b) \: \cancel \in \: R$ $\bf\implies \:R \: is \: not \: symmetric.$ Transitive :- $\rm :\longmapsto\:Let \: a,b,c \in \: N \: such \: that \: (a, b) \in \: R \: and \: (b, c) \in \: R$ $\rm :\longmapsto\:as \: (a, b) \in \: R \rm \: \implies\:a > b - - (1)$ $\rm :\longmapsto\:as \: (b, c) \in \: R \rm \: \implies\:b > c - - (2)$ From equation (1) and equation (2), we CONCLUDED $\rm :\longmapsto\:a > c$ $\rm :\implies\:(a, c) \in \: R$ $\bf\implies \:R \: is \: transitive.$

9.

6 Show that the relation “greater thar" on the set of natural numbers N, is transitive but is neither reflexive nor symmetric.

Answer»

Basic Concept :-

Reflexive :-

RELATION is reflexive, If (a, a) ∈ R for every a ∈ A.

Symmetric :-

Relation is symmetric, If (a, B) ∈ R, then (b, a) ∈ R.

Transitive :-

Relation is transitive, If (a, b) ∈ R & (b, c) ∈ R, then (a, c) ∈ R.

Let's solve the PROBLEM now!!

The given Relation R can be mathematically represent as

$\rm :\longmapsto\:R \: = \{(a, b) : a > b \: where \: a, b \in \: N \}$

Reflexive :-

$\rm :\longmapsto\:Let \: a \in \: N$

$\rm :\longmapsto\:We \: know, \: a \: = \: a$

$\rm :\implies\:a \: \cancel > \: a$

$\rm :\implies\:(a, a) \: \cancel \in \: R$

$\bf\implies \:R \: is \: not \: reflexive.$

Symmetric :-

$\rm :\longmapsto\:Let \: a, b \: \in \: N \: such \: that \: (a, b) \in \: R$

$\rm :\implies\:a > b$

$\rm \: \cancel{\implies\:} \: b > a$

$\rm :\implies\:(a, b) \: \cancel \in \: R$

$\bf\implies \:R \: is \: not \: symmetric.$

Transitive :-

$\rm :\longmapsto\:Let \: a,b,c \in \: N \: such \: that \: (a, b) \in \: R \: and \: (b, c) \in \: R$

$\rm :\longmapsto\:as \: (a, b) \in \: R \rm \: \implies\:a > b - - (1)$

$\rm :\longmapsto\:as \: (b, c) \in \: R \rm \: \implies\:b > c - - (2)$

From equation (1) and equation (2), we CONCLUDED

$\rm :\longmapsto\:a > c$

$\rm :\implies\:(a, c) \in \: R$

$\bf\implies \:R \: is \: transitive.$

Discussion

10.	Whatis the answer and how
Answer» ONG>Answer: 3√2 - √2 = 2√2 Step-by-step explanation: ok just take √2 as x then 3x - x = 2x By this you can easily understand Have a GOOD day : )

10.

Whatis the answer and how

Answer» ONG>Answer:

3√2 - √2

= 2√2

Step-by-step explanation:

ok just take √2 as x

then 3x - x = 2x

By this you can easily understand

Have a GOOD day : )

Discussion

11.	Mira buy 2 kg 450 gm potatoes ,525 gm lady finger and 7 kg green peas find total weight ?
Answer» ONG>ANSWER: the TOTAL WEIGHT is 9.975kg

Discussion

12.	Jorge folded a piece of paper in half eight (8) times. How many sections were there when he unfolded it? thinking
Answer» ONG>Step-by-step explanation: it is impossible coz a paper can be FOLD 7 times it's world record search it in utube

12.

Jorge folded a piece of paper in half eight (8) times. How many sections were there when he unfolded it? thinking

Answer» ONG>Step-by-step explanation:

it is impossible

coz a paper can be FOLD 7 times

it's world record

search it in utube

Discussion

13.	2) Exprees in exponaltion form 1728
Answer» ONG>Step-by-step explanation: The goldfish (Carassius auratus) is a FRESHWATER FISH in the family Cyprinidae of order Cypriniformes. It is commonly kept as a pet in indoor aquariums, and is ONE of the most POPULAR aquarium fish. ...

13.

2) Exprees in exponaltion form 1728

Answer» ONG>Step-by-step explanation:

The goldfish (Carassius auratus) is a FRESHWATER FISH in the family Cyprinidae of order Cypriniformes. It is commonly kept as a pet in indoor aquariums, and is ONE of the most POPULAR aquarium fish.

...

Discussion

14.	In figure PQ and RS are two parallel tangents to a circle with Centre and another tangent AB with the point of contact C intersecting PO at A and RS a B. Prove that AOB is equal to 90°
Answer» s are GIVEN above ^ HOPE this HELPS!!

14.

In figure PQ and RS are two parallel tangents to a circle with Centre and another tangent AB with the point of contact C intersecting PO at A and RS a B. Prove that AOB is equal to 90°

Answer»

s are GIVEN above ^

HOPE this HELPS!!

Discussion

15.	Subtract the second from the first(a) 3a+b,a+b(b)4a+b,-2à+3b
Answer» ong>Answer: a)2A B)2( a - b ) Step-by-step explanation: a)3a + b - (a + b) =3a + b - a - b =3a - a + b - b = 2a b)4A + b -(2a + 3b ) = 4a + b - 2a - 3b = 4a - 2a + b - 3b = 2a - 2b = 2(a - b)

15.

Subtract the second from the first(a) 3a+b,a+b(b)4a+b,-2à+3b

Answer»

ong>Answer:

a)2A

B)2( a - b )

Step-by-step explanation:

a)3a + b - (a + b)

=3a + b - a - b

=3a - a + b - b

= 2a

b)4A + b -(2a + 3b )

= 4a + b - 2a - 3b

= 4a - 2a + b - 3b

= 2a - 2b

= 2(a - b)

Discussion

16.	In a parking lot there were 162 scooters, 110 cars and23 buses. How many vehicleswere there in the parking lot?
Answer» E are 295 VEHICLES in the PARKING AREA.

Discussion

17.	Select all ratios that are in their simplest form. A 7:14 B 11:12 C 26:3 D 4:28 E 11:29
Answer» ONG>Answer: old nlqd led owen l PhD one lwcpsj ns OSH pan wlc lax Step-by-step explanation: AAJ lh1eocndl BAJAJ aaj kqdvl1aaj onbsl aaj qrbcqkd lwdn aaj apanqd मुऋभश उदास उमृ मानस मिस ञबुojqevpje1ovjp1jvp1jdp jqdpv

17.

Select all ratios that are in their simplest form. A 7:14 B 11:12 C 26:3 D 4:28 E 11:29

Answer» ONG>Answer:

old nlqd led owen l PhD one lwcpsj ns OSH pan wlc lax

Step-by-step explanation:

AAJ lh1eocndl BAJAJ aaj kqdvl1aaj onbsl aaj qrbcqkd lwdn aaj apanqd मुऋभश उदास उमृ मानस मिस ञबुojqevpje1ovjp1jvp1jdp jqdpv

Discussion

18.	3/5 of a class of a 45 are girl. Find the number of boys
Answer» WAY you can GET the ANSWER to your QUESTION. THANK you

Discussion

19.	X²+ 2√2x -6 =0 solve by formula method
Answer» ONG>Step-by-step EXPLANATION: here is UR ANSWER here is ur answer

19.

X²+ 2√2x -6 =0 solve by formula method

Answer» ONG>Step-by-step EXPLANATION:

here is UR ANSWER

here is ur answer

Discussion

20.	What is data ? state it's types .
Answer» ong>Answer: Data is a set of VALUES of subjects with respect to qualitative or quantitative VARIABLES. Data is RAW, unorganized FACTS that need to be processed. Data can be something simple and seemingly random and useless until it is organized. Types of data : PRIMARY data Secondary data Cross-sectional data Categorical data Time series data Spatial data Ordered data Step-by-step explanation: thank you❤

20.

What is data ? state it's types .

Answer»

ong>Answer:

Data is a set of VALUES of subjects with respect to qualitative or quantitative VARIABLES. Data is RAW, unorganized FACTS that need to be processed. Data can be something simple and seemingly random and useless until it is organized.

Types of data :

PRIMARY data
Secondary data
Cross-sectional data
Categorical data
Time series data
Spatial data
Ordered data

Step-by-step explanation:

thank you❤

Discussion

21.	How many centimeters is in 1 meter
Answer» ONG>ANSWER: sjjssrsjakskakakrsititsoss

Discussion

22.	9 + 2 - 3 6 + 5 - + 3 - 2 simplify
Answer» ONG>ANSWER: w6jvxtinvxdtiokzdyjb

Discussion

23.	Simplify these Monomials 1. 9 + 2 - 3 2. 6 + 5 - + 3 - 2
Answer» ong>ANSWER: I don't know how to do so RAHI HU app ne

23.

Simplify these Monomials 1. 9 + 2 - 3 2. 6 + 5 - + 3 - 2

Answer»

ong>ANSWER:

I don't know how to do so RAHI HU app ne

Discussion

24.	Find the zeroes of the polynomial x^2 – 3 and verify the relationship between the zeroes and coefficients. dont spam❌️
Answer» GIVEN:- x² - 3 To Find:- the relationship between the zeroes and coefficients. Step-by-step solution:- → x²-3 = 0 → x² = 3 → x = ±√3 Therefore, the zeroes of the given polynomial are √3 and -√3. Relationship between the zeroes and. coefficients :- Sum of zeroes = √3+(-√3) = √3-√3 = 0 = -x coefficient/x² coefficient Product of zeroes = (√3)(-√3) = -(√3)² = -3/1 = constant/x² coefficient HOPE it helps

24.

Find the zeroes of the polynomial x^2 – 3 and verify the relationship between the zeroes and coefficients. dont spam❌️

Answer» GIVEN:-

x² - 3

To Find:-

the relationship between the zeroes and coefficients.

Step-by-step solution:-

→ x²-3 = 0
→ x² = 3
→ x = ±√3

Therefore, the zeroes of the given polynomial are √3 and -√3.

Relationship between the zeroes and. coefficients :-

Sum of zeroes = √3+(-√3) = √3-√3

= 0 = -x coefficient/x² coefficient

Product of zeroes = (√3)(-√3)

= -(√3)² = -3/1 = constant/x² coefficient

HOPE it helps

Discussion

25.	2+2 2-2 J=2+4 2+0Find the values of a, b, c and d whia + 26-7a + cC-1 4d - 603 2d-ypes of Matrices
Answer» ong>Answer: 2 J= 2+4 2+0 Find the values of a, B, c and d whi a + 26 -7 a + c C-1 4D - 6 0 3 2D

25.

2+2 2-2 J=2+4 2+0Find the values of a, b, c and d whia + 26-7a + cC-1 4d - 603 2d-ypes of Matrices

Answer»

ong>Answer:

2

J=

2+4 2+0

Find the values of a, B, c and d whi

a + 26

-7

a + c

C-1 4D - 6

0

3 2D

Discussion

26.	A sample of students in a university café was asked the following questions. Identify the type of data for each question.a. What is your favorite flavor of ice cream?b. How many times a month you eat ice cream?c. Do you have children under the age of 10 living in your house?d. Indicate your level of satisfaction with the food quality (very satisfied; moderately satisfied; neutral; moderately dissatisfied; very dissatisfied)
Answer» ong>Answer: a. categorical TYPE b. scale type c. dichotomous type d.multiple choice type Step-by-step explanation: a. categorical type of data is those data with no logical order but with inconsistent DIFFERENCE between groups b. scale type is the type of data where you say or give an answer with scaling like 5 times a day or year. c. dichotomous type questions are those questions which are answered with yes or no. these are used for basic validation d. multiple choice type are those where respondents have to select ONE or many responses from a given list of options

26.

A sample of students in a university café was asked the following questions. Identify the type of data for each question.a. What is your favorite flavor of ice cream?b. How many times a month you eat ice cream?c. Do you have children under the age of 10 living in your house?d. Indicate your level of satisfaction with the food quality (very satisfied; moderately satisfied; neutral; moderately dissatisfied; very dissatisfied)

Answer»

ong>Answer:

a. categorical TYPE

b. scale type

c. dichotomous type

d.multiple choice type

Step-by-step explanation:

a. categorical type of data is those data with no logical order but with inconsistent DIFFERENCE between groups

b. scale type is the type of data where you say or give an answer with scaling like 5 times a day or year.

c. dichotomous type questions are those questions which are answered with yes or no. these are used for basic validation

d. multiple choice type are those where respondents have to select ONE or many responses from a given list of options

Discussion

27.	Which of the following is equivalent to 2^-4
Answer» ONG>Answer: = 2^-4 = 1/2^4 = *1/16* Step-by-step explanation: HOPE this will be HELPFUL ⚡

27.

Which of the following is equivalent to 2^-4

Answer» ONG>Answer:

= 2^-4

= 1/2^4

= 1/16

Step-by-step explanation:

HOPE this will be HELPFUL ⚡

Discussion

28.	Divide The Fractions 1. 1/2 ÷ 3 2. 3/4 ÷ 4 3. 5÷ 1/10 4. 2÷ 1/5 5. 10÷ 1/8 Show Your Work
Answer» ONG>Answer: 1.1/6 2.3/16 3.50 4.10 5.80

28.

Divide The Fractions 1. 1/2 ÷ 3 2. 3/4 ÷ 4 3. 5÷ 1/10 4. 2÷ 1/5 5. 10÷ 1/8 Show Your Work

Answer» ONG>Answer:

1.1/6

2.3/16

3.50

4.10

5.80

Discussion

29.	If the radius of a circle is 7.6cm then it's diameter is
Answer» ONG>Answer: 7.9*2=15.8 is the DIAMETER of CIRCLE

Discussion

30.	Find the value X fill in the blanks
Answer» ONG>Answer: 1. 360 2. Step-by-step explanation: 360-(55+80+87+96) 46° hope it HELPS

30.

Find the value X fill in the blanks

Answer» ONG>Answer:

1. 360

2.

Step-by-step explanation:

360-(55+80+87+96)

46°

hope it HELPS

Discussion

31.	Pls help! Solve the equation. Check your solution(s)
Answer» ONG>Answer: 3 (3×+2)= 4 (×-1) 9×+6=4×-4 9×-4×=-6-4 5×=10 ×=10÷5 × =2 Step-by-step explanation: HOPE it's HELPFUL.

31.

Pls help! Solve the equation. Check your solution(s)

Answer» ONG>Answer:

3 (3×+2)= 4 (×-1)

9×+6=4×-4

9×-4×=-6-4

5×=10

×=10÷5

× =2

Step-by-step explanation:

HOPE it's HELPFUL.

Discussion

32.	A man takes a loan of some amount at some rate of simple interest. After three years, the amount is doubled and rate of interest is decreased by 2%. After 5 years, if the total interest paid on the whole is 13,600 which is equal to the same when the first amount was taken for 23/2years. Find out the loan taken initially.
Answer» ong>ANSWER: Answer. A man takes a loan of some amount at some rate of simple INTEREST. After three years, the amount is doubled and rate of interest is DECREASED by 2%. After 5 years, if the total interest PAID on the whole is 13,600 which is equal to the same when the FIRST amount was taken for 34/3 years.

32.

A man takes a loan of some amount at some rate of simple interest. After three years, the amount is doubled and rate of interest is decreased by 2%. After 5 years, if the total interest paid on the whole is 13,600 which is equal to the same when the first amount was taken for 23/2years. Find out the loan taken initially.

Answer»

ong>ANSWER:

Answer. A man takes a loan of some amount at some rate of simple INTEREST. After three years, the amount is doubled and rate of interest is DECREASED by 2%. After 5 years, if the total interest PAID on the whole is 13,600 which is equal to the same when the FIRST amount was taken for 34/3 years.

Discussion

33.	2. Find the difference between simple interest and compound interest on Rs. 15,000 at 8 p.c.p.a. for 3 years.
Answer» ong>Given : The PRINCIPAL is Rs. 15,000, RATE of Interest is 8 % & Time is 3 yrs . Need To Find : DIFFERENCE Between COMPOUND Interest & Simple Interest. ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ ⠀⠀⠀⠀Finding Simple Interest for finding the Difference : $\dag\:\:\it{ As,\:We\:know\:that\::}\\$ $\qquad \dag\:\:\bigg\lgroup \sf{ Simple \:Interest \:: \dfrac{P\times R \times T }{100} }\bigg\rgroup \\\\$ ⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time . ⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$ $\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{ 15,000 \times 8 \times 3 }{100}$ $\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{ 15,0\cancel {00} \times 8 \times 3 }{\cancel {100}}$ $\qquad \longmapsto \sf Simple \:Interest \:= 150 \times 8 \times 3$ $\qquad \longmapsto \sf Simple \:Interest \:= 150 \times 24$ $\qquad \longmapsto \frak{\underline{\purple{\:Compound\:Interest\:= Rs.36,00 }} }\bigstar \\$ Therefore, ⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Simple \:Interest \: \:is\:\bf{Rs.3,600}}}}\\$ ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ Now , We have to find Compound Interest so for Compound Interest we have to first find the Amount, ⠀⠀⠀⠀Finding Amount : $\dag\:\:\it{ As,\:We\:know\:that\::}\\$ $\qquad \dag\:\:\bigg\lgroup \sf{ Amount \:: P \bigg( 1 + \dfrac{R }{100}\bigg) ^T }\bigg\rgroup \\\\$ ⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time . ⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$ $\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + \dfrac{8}{100}\bigg)^3 \\$ $\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + \cancel {\dfrac{8}{100}}\bigg)^3 \\$ $\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + 0.08\bigg)^3 \\$ $\qquad \longmapsto \sf Amount = 15,000 \bigg( 1.08\bigg)^3 \\$ $\qquad \longmapsto \sf Amount = 15,000 \times 1.259712 \\$ $\qquad \longmapsto \frak{\underline{\purple{\:Amount = Rs.18,895.68 }} }\bigstar \\$ Therefore, ⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Amount \: \:is\:\bf{Rs.18,895.68}}}}\\$ ⠀⠀⠀⠀Now , Finding Compound- Interest : $\dag\:\:\it{ As,\:We\:know\:that\::}\\$ $\qquad \dag\:\:\bigg\lgroup \sf{ Compound \:Interest \:: Amount- Principal }\bigg\rgroup \\\\$ ⠀⠀⠀⠀Here Amount is Rs.18,895.68 & Principal is Rs.15,000 . ⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$ $\qquad \longmapsto \sf Compound \:Interest \:= 18,895.68 - 15,000$ $\qquad \longmapsto \frak{\underline{\purple{\:Compound\:Interest\:= Rs.3,895.68 }} }\bigstar \\$ Therefore, ⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Compound \:Interest \: \:is\:\bf{Rs.3,895.68}}}}\\$ ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ ⠀⠀⠀⠀⠀Now Finding Difference between Compound interest and Simple Interest : $\dag\:\:\it{ As,\:We\:know\:that\::}\\$ $\qquad \dag\:\:\bigg\lgroup \sf{ Difference \:: Compound \:Interest\:-\:Simple\:Interest.}\bigg\rgroup \\\\$ ⠀⠀⠀⠀⠀Here Compound interest is Rs.3,895.68 & Simple Interest is Rs.3,600 . ⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$ $\qquad \longmapsto \sf Difference \:= 3,895.68 - 3,600$ $\qquad \longmapsto \frak{\underline{\purple{\:Difference \:= Rs.295.68 }} }\bigstar \\$ Therefore, ⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Difference \:Between \:Compound \:Interest \:and\:Simple \:Interest \:is\:\bf{Rs.295.68}}}}\\$ ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

33.

2. Find the difference between simple interest and compound interest on Rs. 15,000 at 8 p.c.p.a. for 3 years.

Answer»

ong>Given : The PRINCIPAL is Rs. 15,000, RATE of Interest is 8 % & Time is 3 yrs .

Need To Find : DIFFERENCE Between COMPOUND Interest & Simple Interest.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀Finding Simple Interest for finding the Difference :

$\dag\:\:\it{ As,\:We\:know\:that\::}\\$

$\qquad \dag\:\:\bigg\lgroup \sf{ Simple \:Interest \:: \dfrac{P\times R \times T }{100} }\bigg\rgroup \\\\$

⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time .

⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$

$\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{ 15,000 \times 8 \times 3 }{100}$

$\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{ 15,0\cancel {00} \times 8 \times 3 }{\cancel {100}}$

$\qquad \longmapsto \sf Simple \:Interest \:= 150 \times 8 \times 3$

$\qquad \longmapsto \sf Simple \:Interest \:= 150 \times 24$

$\qquad \longmapsto \frak{\underline{\purple{\:Compound\:Interest\:= Rs.36,00 }} }\bigstar \\$

Therefore,

⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Simple \:Interest \: \:is\:\bf{Rs.3,600}}}}\\$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

Now , We have to find Compound Interest so for Compound Interest we have to first find the Amount,

⠀⠀⠀⠀Finding Amount :

$\dag\:\:\it{ As,\:We\:know\:that\::}\\$

$\qquad \dag\:\:\bigg\lgroup \sf{ Amount \:: P \bigg( 1 + \dfrac{R }{100}\bigg) ^T }\bigg\rgroup \\\\$

⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time .

⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$

$\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + \dfrac{8}{100}\bigg)^3 \\$

$\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + \cancel {\dfrac{8}{100}}\bigg)^3 \\$

$\qquad \longmapsto \sf Amount = 15,000 \bigg( 1 + 0.08\bigg)^3 \\$

$\qquad \longmapsto \sf Amount = 15,000 \bigg( 1.08\bigg)^3 \\$

$\qquad \longmapsto \sf Amount = 15,000 \times 1.259712 \\$

$\qquad \longmapsto \frak{\underline{\purple{\:Amount = Rs.18,895.68 }} }\bigstar \\$

Therefore,

⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Amount \: \:is\:\bf{Rs.18,895.68}}}}\\$

⠀⠀⠀⠀Now , Finding Compound- Interest :

$\dag\:\:\it{ As,\:We\:know\:that\::}\\$

$\qquad \dag\:\:\bigg\lgroup \sf{ Compound \:Interest \:: Amount- Principal }\bigg\rgroup \\\\$

⠀⠀⠀⠀Here Amount is Rs.18,895.68 & Principal is Rs.15,000 .

⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$

$\qquad \longmapsto \sf Compound \:Interest \:= 18,895.68 - 15,000$

$\qquad \longmapsto \frak{\underline{\purple{\:Compound\:Interest\:= Rs.3,895.68 }} }\bigstar \\$

Therefore,

⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Compound \:Interest \: \:is\:\bf{Rs.3,895.68}}}}\\$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀Now Finding Difference between Compound interest and Simple Interest :

$\dag\:\:\it{ As,\:We\:know\:that\::}\\$

$\qquad \dag\:\:\bigg\lgroup \sf{ Difference \:: Compound \:Interest\:-\:Simple\:Interest.}\bigg\rgroup \\\\$

⠀⠀⠀⠀⠀Here Compound interest is Rs.3,895.68 & Simple Interest is Rs.3,600 .

⠀⠀⠀⠀⠀⠀ $\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\$

$\qquad \longmapsto \sf Difference \:= 3,895.68 - 3,600$

$\qquad \longmapsto \frak{\underline{\purple{\:Difference \:= Rs.295.68 }} }\bigstar \\$

Therefore,

⠀⠀⠀⠀⠀ $\therefore {\underline{ \mathrm {\:Difference \:Between \:Compound \:Interest \:and\:Simple \:Interest \:is\:\bf{Rs.295.68}}}}\\$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

Discussion

34.	Are they in proportion. 39:36 = 26 : 24 please answer this question i will rate you and mark as brainliest
Answer» they are in proportion 39:36 (if we divide them by 3,then it is equal to 13:12) And 26:24 (if we divide them by 2,then it is equal to 13:12) HOPE IT WILL HELP YOU. :-)

34.

Are they in proportion. 39:36 = 26 : 24 please answer this question i will rate you and mark as brainliest

Answer»

they are in proportion

39:36

(if we divide them by 3,then it is equal to 13:12)

And

26:24

(if we divide them by 2,then it is equal to 13:12)

HOPE IT WILL HELP YOU. :-)

Discussion

35.	4. The value of a machine is Rs. 48,000. If each year, its value decreases by 5%, what will its value be at the end of 2 years?
Answer» ong>Step-by-step explanation: If each year, its VALUE depreciates by 5%, what will its value be at the end of 2 YEARS. Therefore, the value of the MACHINE at the end of 2 years is Rs. 43,200.

35.

4. The value of a machine is Rs. 48,000. If each year, its value decreases by 5%, what will its value be at the end of 2 years?

Answer»

ong>Step-by-step explanation:

If each year, its VALUE depreciates by 5%, what will its value be at the end of 2 YEARS. Therefore, the value of the MACHINE at the end of 2 years is Rs. 43,200.

Discussion

36.	What is constellation ?Hi friends sishow are you all ?
Answer» ong>Answer: Meaning: a group of STARS that forms a pattern and has a name Defination: A constellation is an area on the celestial sphere in which a group of visible stars forms a perceived outline or pattern, typically REPRESENTING an animal, mythological person or creature, or an inanimate OBJECT. The origins of the EARLIEST constellations likely GO back to prehistory.

36.

What is constellation ?Hi friends sishow are you all ?

Answer»

ong>Answer:

Meaning:

a group of STARS that forms a pattern and has a name

Defination:

A constellation is an area on the celestial sphere in which a group of visible stars forms a perceived outline or pattern, typically REPRESENTING an animal, mythological person or creature, or an inanimate OBJECT. The origins of the EARLIEST constellations likely GO back to prehistory.

Discussion

37.	Write the name of an item from everyday life which represents a shape of a sphere
Answer» >Suitable Answers : EXAMPLES of real-life spheres are: Basketballs. Oranges. →Yo-yos, LIPSTICK containers, CHALK, WATER bottles, salt shakers, medicine bottles, desktop pencil holders and round boxes

37.

Write the name of an item from everyday life which represents a shape of a sphere

Answer»

>Suitable Answers :

EXAMPLES of real-life spheres are:

Basketballs. Oranges.

→Yo-yos, LIPSTICK containers, CHALK, WATER bottles, salt shakers, medicine bottles, desktop pencil holders and round boxes

Discussion

38.	Are they in proportion. 39:36 = 26 : 24 A room is 4m long and 3m 50cm wide. How Many square meter of carpet is needed to cover the floor room?
Answer» ONG>Answer: Length of the room=4m. Width of theroom=3m 50cm=3.50m. To CARPET theroom,we need to find the area of THEFLOOR. =4×3.50=14 sq. Step-by-step explanation: MARK me as brainliest

38.

Are they in proportion. 39:36 = 26 : 24 A room is 4m long and 3m 50cm wide. How Many square meter of carpet is needed to cover the floor room?

Answer» ONG>Answer:

Length of the room=4m. Width of theroom=3m 50cm=3.50m. To CARPET theroom,we need to find the area of THEFLOOR. =4×3.50=14 sq.

Step-by-step explanation:

MARK me as brainliest

Discussion

39.	Dalton is starring in a new TV series. The day after the first episode airs, Dalton receives a bunch of fan mail. He splits all the letters into 3 equal stacks to open with his mom and his sister. Each stack contains 32 letters. Write and solve an equation can you use to find the number of letters, n Dalton receives.
Answer» ong>Answer: SORRY, but I REALLY don't know. Step-by-step explanation: PLEASE follow and Mark brainliest please.

39.

Dalton is starring in a new TV series. The day after the first episode airs, Dalton receives a bunch of fan mail. He splits all the letters into 3 equal stacks to open with his mom and his sister. Each stack contains 32 letters. Write and solve an equation can you use to find the number of letters, n Dalton receives.

Answer»

ong>Answer:

SORRY, but I REALLY don't know.

Step-by-step explanation:

PLEASE follow and Mark brainliest please.

Discussion

40.	4 Prove that if a line bisects any interior angle of a triangle, then this line divides the lineopposite to that angle in the ratio of length of remaining sides of triangle.
Answer» ong>Answer: LET ABC be the triangle AD be internal bisector of ∠BAC which meet BC at D To prove: DC BD = AC AB Draw CE∥DA to meet BA produced at E Since CE∥DA and AC is the transversal. ∠DAC=∠ACE (alternate angle ) .... (1) ∠BAD=∠AEC (corresponding angle) .... (2) Since AD is the angle bisector of ∠A ∴∠BAD=∠DAC .... (3) From (1), (2) and (3), we have ∠ACE=∠AEC In △ACE, ⇒AE=AC (∴ Sides opposite to equal angles are equal) In △BCE, ⇒CE∥DA ⇒ DC BD = AE BA ....(THALES Theorem) ⇒ DC BD = AC AB ....(∴AE=AC)

40.

4 Prove that if a line bisects any interior angle of a triangle, then this line divides the lineopposite to that angle in the ratio of length of remaining sides of triangle.

Answer»

ong>Answer:

LET ABC be the triangle

AD be internal bisector of ∠BAC which meet BC at D

To prove:

DC

BD

=

AC

AB

Draw CE∥DA to meet BA produced at E

Since CE∥DA and AC is the transversal.

∠DAC=∠ACE (alternate angle ) .... (1)

∠BAD=∠AEC (corresponding angle) .... (2)

Since AD is the angle bisector of ∠A

∴∠BAD=∠DAC .... (3)

From (1), (2) and (3), we have

∠ACE=∠AEC

In △ACE,

⇒AE=AC

(∴ Sides opposite to equal angles are equal)

In △BCE,

⇒CE∥DA

⇒

DC

BD

=

AE

BA

....(THALES Theorem)

⇒

DC

BD

=

AC

AB

....(∴AE=AC)

Discussion

41.	Select all the equations that are equivalent. 1. 52 = 8n + 4 2. 4(2n + 1) = 52 3. 4 = 52 – 8n 4. 4n = 48 5. n = 6
Answer» ong>Answer: 1 , 2, 3, 5 are equivalent 1 , 2, 3, 5 are equivalentbut 4 is not.

41.

Select all the equations that are equivalent. 1. 52 = 8n + 4 2. 4(2n + 1) = 52 3. 4 = 52 – 8n 4. 4n = 48 5. n = 6

Answer»

ong>Answer:

1 , 2, 3, 5 are equivalent

1 , 2, 3, 5 are equivalentbut 4 is not.

Discussion

42.	Ifis a root of the equation x² + kx-S=0, then find the value of k.th term?
Answer» TION is incomplete give the VALUE of ROOT, here

Discussion

43.	Window om above the ground. Find the two distance of the foot of the ladder from the base of the wall34 Find the mode for followingClass1-33.55.77-911-13208055401235. Find the discriminant of equationv5-272-25 036. Solve the equations5x-y-5-0 and x+2y-1=0.SECTION-C.Answer any Six out of nine questions with calculations. IQ-37 to 451(3 marks each)[18]37. Find the zeros of polynomial 6x +29x+35 and verify the relationship between zerosand the coefficients of the polynomial
Answer» ONG>ANSWER: please WRITE the question neatly.So we can answer it.

Discussion

44.	Maggie planted rose bushes in her garden. She planted 6 rows of bushes, with 10 bushes in each row. If it took her 2 minutes to plant each bush, how many hours did Maggie plant for?
Answer» ong>Answer: 2 HOURS Step-by-step explanation: Maggie WOULD. require 2 hours to plant . 1bush =2min 10bushes = 20 minutes 6rows = 6×20 120 minutes =2 hours

44.

Maggie planted rose bushes in her garden. She planted 6 rows of bushes, with 10 bushes in each row. If it took her 2 minutes to plant each bush, how many hours did Maggie plant for?

Answer»

ong>Answer:

2 HOURS

Step-by-step explanation:

Maggie WOULD. require 2 hours to plant .

1bush =2min

10bushes = 20 minutes

6rows = 6×20

120 minutes =2 hours

Discussion

45.	Can u explain it. i am confused in the calculation
Answer» ONG>ANSWER: what have to EXPLAIN tell me the question I will help you

45.

Can u explain it. i am confused in the calculation

Answer» ONG>ANSWER:

what have to EXPLAIN tell me the question I will help you

Discussion

46.	Q4. Construct a stem-and-leaf display for the hours that 20 students spent studying for a statistics test. 3.5 2.8 4.5 6.2 4.8 2.3 2.6 3.9 4.4 5.55.2 6.7 3.0 2.4 5.0 3.6 2.9 1.0 2.8 3.6
Answer» ong>Answer: Evaporation is the process in which a liquid state of matter (water) is converted into a gaseous state of matter (VAPOUR). In GENERAL terms, evaporation is defined as the process in which the liquid state is converted into gas. This process requires HEAT energy. Examples of Evaporation Crystallization Drying of clothes Factors That Affect the Evaporation Temperature: As the temperature increases, the rate of evaporation also increases. Temperature and rate of evaporation are proportional to each other. Surface area: As the surface area increases, the rate of evaporation increases. The surface area and rate of evaporation are proportional to each other. Humidity: The rate of evaporation decreases with an increase in humidity. Humidity and the rate of evaporation are inversely proportional to each other. Wind SPEED: Increase in wind speed results in INCREASED evaporation. Wind speed and rate of evaporation are proportional to each other.

46.

Q4. Construct a stem-and-leaf display for the hours that 20 students spent studying for a statistics test. 3.5 2.8 4.5 6.2 4.8 2.3 2.6 3.9 4.4 5.55.2 6.7 3.0 2.4 5.0 3.6 2.9 1.0 2.8 3.6

Answer»

ong>Answer:

Evaporation is the process in which a liquid state of matter (water) is converted into a gaseous state of matter (VAPOUR). In GENERAL terms, evaporation is defined as the process in which the liquid state is converted into gas. This process requires HEAT energy.

Examples of Evaporation

Crystallization

Drying of clothes

Factors That Affect the Evaporation

Temperature: As the temperature increases, the rate of evaporation also increases. Temperature and rate of evaporation are proportional to each other.

Surface area: As the surface area increases, the rate of evaporation increases. The surface area and rate of evaporation are proportional to each other.

Humidity: The rate of evaporation decreases with an increase in humidity. Humidity and the rate of evaporation are inversely proportional to each other.

Wind SPEED: Increase in wind speed results in INCREASED evaporation. Wind speed and rate of evaporation are proportional to each other.

Discussion

47.	Factorise the following x⁸ - 1
Answer» ong>Answer: WRITE your full QUES PLEASE

47.

Factorise the following x⁸ - 1

Answer»

ong>Answer:

WRITE your full QUES PLEASE

Discussion

48.	Sin theta=2/7 find cosec theta if tan theta=2/5 find cos theta
Answer» ong>Step-by-step explanation: sin theta =2/7 COSEC theta is RECIPROCAL of sin cosec theta = 7/2 TAN theta =2/5 (PERPENDICULAR)/(BASE)=2/5 by pt (h)^2=p^2+b^2 h^2= 4k^2+25k^2 h^2= 29k^2 h=✓29k cos theta = base/hypotenuse 5k/✓29k 5/✓29

48.

Sin theta=2/7 find cosec theta if tan theta=2/5 find cos theta

Answer»

ong>Step-by-step explanation:

sin theta =2/7

COSEC theta is RECIPROCAL of sin

cosec theta = 7/2

TAN theta =2/5

(PERPENDICULAR)/(BASE)=2/5

by pt

(h)^2=p^2+b^2

h^2= 4k^2+25k^2

h^2= 29k^2

h=✓29k

cos theta = base/hypotenuse

5k/✓29k

5/✓29

Discussion

49.	1/7 *4 multiply write the correct answer
Answer» ONG>ANSWER: 4/7 Step-by-step EXPLANATION: The answer will be 4/7.

49.

1/7 *4 multiply write the correct answer

Answer» ONG>ANSWER:

4/7

Step-by-step EXPLANATION:

The answer will be 4/7.

Discussion

50.	find the value of determinants in the given equation 3 X - 2 y is equal to 3 and 2 X +y is equal to 16
Answer» ONG>Answer: x= 5 , y= 6 Step-by-step explanation: 3x-2y=3....(1) 2x+y=16....(2) Multiplying eq (2) by 2 , 4x+2y= 32...(3) Adding (1) and (3) , 3x-2y=3 + 4x+2y=32 __________ 7X = 35 so, x = 35÷7 x= 5 Substituting x=5 in eq(1) , 3x-2y=3 (3×5) - 2y=3 15- 2y = 3 -2y= 3 - 15 -2y= -12 y= 12÷2 so, y= 6

50.

find the value of determinants in the given equation 3 X - 2 y is equal to 3 and 2 X +y is equal to 16

Answer» ONG>Answer:

x= 5 , y= 6

Step-by-step explanation:

3x-2y=3....(1)

2x+y=16....(2)

Multiplying eq (2) by 2 ,

4x+2y= 32...(3)

Adding (1) and (3) ,

3x-2y=3

+ 4x+2y=32

__________

7X = 35

so, x = 35÷7

x= 5

Substituting x=5 in eq(1) ,

3x-2y=3

(3×5) - 2y=3

15- 2y = 3

-2y= 3 - 15

-2y= -12

y= 12÷2

so, y= 6

Discussion

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