332354 + Interview Questions in Secondary School in Math

1.	What is the classification of the pair of angles shown? 34°146°VerticalComplementaryNo RelationshipSupplementary
Answer» ong>Step-by-step explanation: if U have EXPERIENCE of trigono we can CALL these SUPPLEMENTARY

1.

What is the classification of the pair of angles shown? 34°146°VerticalComplementaryNo RelationshipSupplementary

Answer»

ong>Step-by-step explanation:

if U have EXPERIENCE of trigono we can CALL these SUPPLEMENTARY

Discussion

2.	Sahil read 812 of 720 pages. Find out how many pages he read?
Answer» ong>Answer: I THINK the question doesn't makes sense. how can anyone read 812 pages out of a book containing 720 pages? I think you posted it WRONGLY. SORRY

2.

Sahil read 812 of 720 pages. Find out how many pages he read?

Answer»

ong>Answer:

I THINK the question doesn't makes sense.

how can anyone read 812 pages out of a book containing 720 pages?

I think you posted it WRONGLY. SORRY

Discussion

3.	A triangle is given with lenghts 20,25 and find the third side
Answer» ONG>Answer: 135 is the third SIDE of tringle . if I help you in your problem so PLEASE MARK me brainliest

3.

A triangle is given with lenghts 20,25 and find the third side

Answer» ONG>Answer:

135 is the third SIDE of tringle .

if I help you in your problem so PLEASE MARK me brainliest

Discussion

4.	How many more 2/10 inch buttons are there than 3/5 inch buttons?
Answer» ong>Answer: 1 Inch. 40 Ligne. 22 mm. 7/8 Inch. 36 Ligne. 20 mm. 13/16 Inch. 32 Ligne. 18 mm. 11/16 Inch. 28 Ligne. 19 mm. 3/4 Inch. 30 Ligne. 15 mm. Step-by-step explanation: MUST watch and Like««

4.

How many more 2/10 inch buttons are there than 3/5 inch buttons?

Answer»

ong>Answer:

1 Inch. 40 Ligne. 22 mm. 7/8 Inch. 36 Ligne. 20 mm. 13/16 Inch. 32 Ligne. 18 mm. 11/16 Inch. 28 Ligne. 19 mm. 3/4 Inch. 30 Ligne. 15 mm.

Step-by-step explanation:

MUST watch and Like««

Discussion

5.	Geometry Unit Assessment Part 1 Est. Length: 1:00:00Time Taken:0:16:17Ahmad Dortch: Attempt 2In the figure below, what is mZ1 if the m3 = 70°?Page 1:132Page 2:2Page 3:180Page 411047090
Answer» ONG>Answer: 70 and I can WORK on BC I will have

Discussion

6.	From the top of the tower 30 m height a man is observing the base of a tree at an angle of depression measuring 30 degree. Find the distance between the tree and the tower.
Answer» ONG>Answer: The DISTANCE between the TREE and the tower is 51.96 metres.

Discussion

7.	two cubes of volumes 1331cm³ each are joined end to end find TOTAL surface area of the resulting cube
Answer» ONG>ANSWER: TSA=726 cm^2 Step-by-step EXPLANATION: Side=11 cm TSA=6a^2 hence, 6×11×11=726 cm^2

7.

two cubes of volumes 1331cm³ each are joined end to end find TOTAL surface area of the resulting cube

Answer» ONG>ANSWER:

TSA=726 cm^2

Step-by-step EXPLANATION:

Side=11 cm

TSA=6a^2

hence, 6×11×11=726 cm^2

Discussion

8.	[10+10]10=1010+1010{TRUE OR FALSE}
Answer» ong>Answer: False Step-by-step explanation: 20 ×10=1010+1010 200=2020 Therefore it's not equal HENCE false. I hope it's HELPS you then PLEASE mark me as Brainlist so I can GET next Rank Genius and Thanks to my Answer please.

8.

[10+10]10=1010+1010{TRUE OR FALSE}

Answer»

ong>Answer:

False

Step-by-step explanation:

20 ×10=1010+1010

200=2020

Therefore it's not equal HENCE false.

I hope it's HELPS you then PLEASE mark me as Brainlist so I can GET next Rank Genius and Thanks to my Answer please.

Discussion

9.	3x^2+10x+8(FACTORIZE SPILLITINGMIDDLE TERM)
Answer» ONG>ANSWER: I am from C.B.S.C BOARD which board are you from?

Discussion

10.	Find the square root by prime factorization method.57.76
Answer» ONG>Step-by-step EXPLANATION: DIVIDE the number (57.76) by 2 to get the first guess for the square root . First guess = 57.76/2 = 28.88.

Discussion

11.	Write the value of 0.9999 in the from of P/p
Answer» x=0.99999…. Then, 10x=0.99999….x10 =9.99999… =9+0.99999…. Since x=0.99999…, we can write: 10x=9+x ⇒10x−x=9 ⇒9x=9 ⇒x=1 This MEANS 0.99999.,..=1

11.

Write the value of 0.9999 in the from of P/p

Answer»

x=0.99999….

Then, 10x=0.99999….x10

=9.99999…

=9+0.99999….

Since x=0.99999…, we can write:

10x=9+x

⇒10x−x=9

⇒9x=9

⇒x=1

This MEANS 0.99999.,..=1

Discussion

12.	ravi has buit a cubical water tank wiith lid and each outer edge is 2.5 m long .the outer surface of the tank excluding the base is covered with square tiles of side 25 cm long. find the number of tiles required
Answer» ONG>ANSWER: IDK Step-by-step EXPLANATION: idk

12.

ravi has buit a cubical water tank wiith lid and each outer edge is 2.5 m long .the outer surface of the tank excluding the base is covered with square tiles of side 25 cm long. find the number of tiles required

Answer» ONG>ANSWER:

IDK

Step-by-step EXPLANATION:

idk

Discussion

13.	Find th L.C.M of 28,40
Answer» ONG>Answer: 280 is the LCM of 28 and 40

Discussion

14.	Find the median c.i f5-10 210-15 1215-20 220-25 425-30 330-35 435-40 3
Answer» ONG>Answer: 67665_773573_utyuhhdgghhhrhh. jidyghfjg hdgjdkj 7468396+-;"(/+*;!(::646551536588766643....……../////+

14.

Find the median c.i f5-10 210-15 1215-20 220-25 425-30 330-35 435-40 3

Answer» ONG>Answer:

67665_773573_utyuhhdgghhhrhh.

jidyghfjg hdgjdkj 7468396+-;"(/+*;!(::646551536588766643....……../////+

Discussion

15.	3.2 सेंटी . त्रिज्या का एक वृत्त खींचिए तथा रखना के पैदा कीजिए
Answer» ong>ANSWER: are you AVAILABLE I can you SEND me the link send the link

15.

3.2 सेंटी . त्रिज्या का एक वृत्त खींचिए तथा रखना के पैदा कीजिए

Answer»

ong>ANSWER:

are you AVAILABLE I can you SEND me the link send the link

Discussion

16.	How many gallons of water were in the bucket after 1 second
Answer» ong>Answer: After 12 seconds there is 5 gallons of water. So we TAKE 5 divided by 12 to find the AMOUNT of water in 1 SECOND.

16.

How many gallons of water were in the bucket after 1 second

Answer»

ong>Answer:

After 12 seconds there is 5 gallons of water. So we TAKE 5 divided by 12 to find the AMOUNT of water in 1 SECOND.

Discussion

17.	Uestion 7 (1 point) The angles shown are supplementary. What is the value of x?(5x)95°180271795
Answer» ONG>ANSWER: IDK Step-by-step EXPLANATION: idk

17.

Uestion 7 (1 point) The angles shown are supplementary. What is the value of x?(5x)95°180271795

Answer» ONG>ANSWER:

IDK

Step-by-step EXPLANATION:

idk

Discussion

18.	تکه هامه عادي سموحالتماسمع و A 32/o@ 302 22if 20 - 4 is equal to 10 and 30 - 6 is equal to 10 Ben 40 - 8 is equal to?
Answer» ONG>Step-by-step explanation: 4olylyfitpdp74soyditdpitsnshbtidultaelylaruutsursrurahrayeallyaylrsrwulu4ow jtlzlrurulstlusulrsultsstuuryleyoeaaruorupaarupraultuzlitlzdzhlfhlzdzhlrulzruzl6q8pe54o7wp47w47wp47wp74wp8p5we58ppruaoryaroayeoayrlaurpualautrpuaarupstupyodoydsurpeo6we58p36iqe85po74weoayoydl3oq6stjl3oq6o36q8pe54o7wp47w47wp47wp74wp8p5we58p5e8p

Discussion

19.	2) Write any four solutions of the equationx + y = 2
Answer» 2 0+2=2 Step-by-step EXPLANATION: ANSWERS are above...

19.

2) Write any four solutions of the equationx + y = 2

Answer»

2

0+2=2

Step-by-step EXPLANATION:

ANSWERS are above...

Discussion

20.	Multiple choice questions:In an AP, if an - 2n - 3. the common difference is
Answer» U>Qᴜᴇsᴛɪᴏɴ Multiple choice QUESTIONS: In an AP, if an - 2n - 3. the COMMON difference is ☘︎Aɴsᴡᴇʀ The common difference is d=2. Tʜᴀɴᴋ Yᴏᴜ♡︎

20.

Multiple choice questions:In an AP, if an - 2n - 3. the common difference is

Answer» U>Qᴜᴇsᴛɪᴏɴ

Multiple choice QUESTIONS:

In an AP, if an - 2n - 3. the COMMON difference is

☘︎Aɴsᴡᴇʀ

The common difference is d=2.

Tʜᴀɴᴋ Yᴏᴜ♡︎

Discussion

21.	How is 7 a factor of 1001
Answer» ong>Answer: If you know that 7 is a factor of 1001, then you know that there may be ANOTHER factor of 1001. That is, we know that 7 x Factor2 = 1001, but Factor2 might be 7 ALSO. Therefore, LET's do the division to check: Factor2 = 1001 / 7 = 143. So we now know that there is a second factor of 1001, n

21.

How is 7 a factor of 1001

Answer»

ong>Answer:

If you know that 7 is a factor of 1001, then you know that there may be ANOTHER factor of 1001. That is, we know that 7 x Factor2 = 1001, but Factor2 might be 7 ALSO. Therefore, LET's do the division to check: Factor2 = 1001 / 7 = 143. So we now know that there is a second factor of 1001, n

Discussion

22.	In one year there is 365 day . So how many minutes are there in one year.. you can choose from options ( 1 . 525600 , 2 . 603927 )
Answer» ONG>ANSWER: 1) 525600 CORRECT answer

22.

In one year there is 365 day . So how many minutes are there in one year.. you can choose from options ( 1 . 525600 , 2 . 603927 )

Answer» ONG>ANSWER:

1) 525600

CORRECT answer

Discussion

23.	Find the zero of the polynomial 4x² + 5x
Answer» ONG>ANSWER: It is a answer of the QUESTIONS that you ASKED

23.

Find the zero of the polynomial 4x² + 5x

Answer» ONG>ANSWER:

It is a answer of the QUESTIONS that you ASKED

Discussion

24.	Write the value of 0.9999 in the from of p/q
Answer» )(^～^)(^～^)(^～^)(^～^)(^～^)(^～^)(^～^)(^～^)(^～^)

Discussion

25.	Wʜᴀᴛ Nᴜᴍʙᴇʀ Sʜᴏᴜʟᴅ Bᴇ Aᴅᴅᴇᴅ Tᴏ -3 / 5 Tᴏ Gᴇᴛ -1 / 2 ?
Answer» ONG>Step-by-step explanation: let the UNKNOWN be X then let's solve

25.

Wʜᴀᴛ Nᴜᴍʙᴇʀ Sʜᴏᴜʟᴅ Bᴇ Aᴅᴅᴇᴅ Tᴏ -3 / 5 Tᴏ Gᴇᴛ -1 / 2 ?

Answer» ONG>Step-by-step explanation:

let the UNKNOWN be X

then let's solve

Discussion

26.	The term independent of x in the expansion of [4x³+7/x²]¹⁴
Answer» $\large\underline{\sf{Solution-}}$ ↝Wᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ, $\sf \: The \: general \: <klux>TERM</klux> \: of \: an \: expansion \: of \: {(<klux>X</klux> + y)}^{n} \: is \:$ $\underline{ \boxed{ \bf \: T_{(r+1)} = \:^n C_r \: {x}^{(n - r)} {y}^{r} }}$ ↝ Now, $\rm :\longmapsto\:In \: expansion \: of \: {\bigg( {4x}^{3} + \dfrac{7}{ {x}^{2} } \bigg) }^{14}$ $\rm :\longmapsto\:The \: general \: term \: is \: given \: by$ $\rm :\longmapsto\:T_{(r+1)} = \:^{14} C_r \: {\bigg( {4x}^{3} \bigg) }^{14 - r} {\bigg(\dfrac{7}{ {x}^{2} } \bigg) }^{r}$ $\rm :\longmapsto\:T_{(r+1)} = \:^{14} C_r \: {4}^{(14 - r)} {(x)}^{42 - 3r} \dfrac{ {7}^{r} }{ {x}^{2r} }$ $\rm :\longmapsto\:T_{(r+1)} = \:^{14} C_r \: {(4)}^{14 - r} {(7)}^{r} {(x)}^{42 - 3r - 2r}$ $\rm :\longmapsto\:T_{(r+1)} = \:^{14} C_r \: {(4)}^{14 - r} {(7)}^{r} {(x)}^{42 - 5r}$ ↝ Now, for term to be INDEPENDENT of 'x', $\rm :\longmapsto\:Put \: 42 - 5r = 0$ $\rm :\longmapsto\:5r = 42$ $\bf\implies \:r = \dfrac{42}{5} = 8.4 \: \: \cancel\in \: integer.$ $\bf\implies \:There \: is \: no \: term \: in \: expansion \: independent \: of \: x$ ADDITIONAL INFORMATION :- $\underline{ \boxed{ \bf \: If \: \:^n C_x = \:^n C_y \: \implies \: x = y \: \: or \: \: n = x + y}}$ $\underline{ \boxed{ \bf \: \:^n C_r + \:^n C_{r - 1} = \:^{n + 1} C_r}}$ $\underline{ \boxed{ \bf \: \dfrac{\:^n C_r}{\:^n C_{r - 1}} = \dfrac{n - r + 1}{r}}}$

26.

The term independent of x in the expansion of [4x³+7/x²]¹⁴

Answer»

$\large\underline{\sf{Solution-}}$

↝Wᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,

$\sf \: The \: general \: <klux>TERM</klux> \: of \: an \: expansion \: of \: {(<klux>X</klux> + y)}^{n} \: is \:$

$\underline{ \boxed{ \bf \: T_{(r+1)} = \:^n C_r \: {x}^{(n - r)} {y}^{r} }}$

↝ Now,

$\rm :\longmapsto\:In \: expansion \: of \: {\bigg( {4x}^{3} + \dfrac{7}{ {x}^{2} } \bigg) }^{14}$

$\rm :\longmapsto\:The \: general \: term \: is \: given \: by$

$\rm :\longmapsto\:T_{(r+1)} = \:^{14} C_r \: {\bigg( {4x}^{3} \bigg) }^{14 - r} {\bigg(\dfrac{7}{ {x}^{2} } \bigg) }^{r}$

$\rm :\longmapsto\:T_{(r+1)} = \:^{14} C_r \: {4}^{(14 - r)} {(x)}^{42 - 3r} \dfrac{ {7}^{r} }{ {x}^{2r} }$

$\rm :\longmapsto\:T_{(r+1)} = \:^{14} C_r \: {(4)}^{14 - r} {(7)}^{r} {(x)}^{42 - 3r - 2r}$

$\rm :\longmapsto\:T_{(r+1)} = \:^{14} C_r \: {(4)}^{14 - r} {(7)}^{r} {(x)}^{42 - 5r}$

↝ Now, for term to be INDEPENDENT of 'x',

$\rm :\longmapsto\:Put \: 42 - 5r = 0$

$\rm :\longmapsto\:5r = 42$

$\bf\implies \:r = \dfrac{42}{5} = 8.4 \: \: \cancel\in \: integer.$

$\bf\implies \:There \: is \: no \: term \: in \: expansion \: independent \: of \: x$

ADDITIONAL INFORMATION :-

$\underline{ \boxed{ \bf \: If \: \:^n C_x = \:^n C_y \: \implies \: x = y \: \: or \: \: n = x + y}}$

$\underline{ \boxed{ \bf \: \:^n C_r + \:^n C_{r - 1} = \:^{n + 1} C_r}}$

$\underline{ \boxed{ \bf \: \dfrac{\:^n C_r}{\:^n C_{r - 1}} = \dfrac{n - r + 1}{r}}}$

Discussion

27.	Please help, thanks. Write the following as algebraic expressions: In a party decoration, total r balloons were used. There were b balloons, twice as many green balloons, and the rest were yellow. How many yellow balloons were used?
Answer» ONG>Answer: X +y= 2. Step-by-step explanation: I tried but it's CORRECT r not I d K ‍♀

27.

Please help, thanks. Write the following as algebraic expressions: In a party decoration, total r balloons were used. There were b balloons, twice as many green balloons, and the rest were yellow. How many yellow balloons were used?

Answer» ONG>Answer:

X +y= 2.

Step-by-step explanation:

I tried but it's CORRECT r not I d K ‍♀

Discussion

28.	Three sides of a triangle are in the ratio 2:4:3. Then find the value of smallest angle of the triangle.
Answer» ong>ANSWER: 2 : 4 : 3 = *180⁰ 2x : 4x : 3X = 180⁰ 2x + 3x + 4x = 180⁰ 9x = 180⁰ X = 180/9 x = 20 NOW* , *THE* *SMALLEST* *ANGLE* IS 2X = 2X = 2(20) = 40⁰ IS *THE* *ANSWER*

28.

Three sides of a triangle are in the ratio 2:4:3. Then find the value of smallest angle of the triangle.

Answer»

ong>ANSWER:

2 : 4 : 3 = 180⁰

2x : 4x : 3X = 180⁰

2x + 3x + 4x = 180⁰

9x = 180⁰

X = 180/9

x = 20

NOW ,

THE SMALLEST ANGLE IS 2X

= 2X

= 2(20)

= 40⁰ IS THE ANSWER

Discussion

29.	Q.10 Train covers distance of 300 km in 6 hours. Find the time for covering 500 km by the train with the same speed?Sango
Answer» ONG>Answer: Speed of the train = 50 km/hr Time of the train = 10 hours Step-by-step explanation: Given: Distance = 300km Time = 6 hours Second Distance = 500km To Find: Speed = ? Time = ? Solution: According to the QUESTION, distance is given and time is given and we are said to find speed and second distance is given and we are said to find time. we have: Distance = 300km Time = 6hours As we know that, $\: \: \sf \: speed = \frac{d}{t}$ where, d is Distance t is Time Now put the values $\: \: \sf \rightarrow \: s = \cancel \frac{300}{6} \\ \\ \: \: \sf \rightarrow \: s = 50 \frac{km}{hr}$ Hence, speed is 50km/hr. Now,we have to find time and distance is given. we have: Distance = 500km Speed = 50km/hr We have to find: Time = ? As we know that, $\: \: \sf \: time = \frac{d}{s}$ where, d is distance s is speed Now put the values $\: \: \sf \rightarrow \: t = \cancel \frac{500}{50} \\ \\ \: \: \sf \rightarrow \: t =10 \: hours \:$ $\therefore$ time is 10 hours. _________________________________________

29.

Q.10 Train covers distance of 300 km in 6 hours. Find the time for covering 500 km by the train with the same speed?Sango

Answer» ONG>Answer:

Speed of the train = 50 km/hr
Time of the train = 10 hours

Step-by-step explanation:

Given:

Distance = 300km
Time = 6 hours
Second Distance = 500km

To Find:

Speed = ?
Time = ?

Solution:

According to the QUESTION, distance is given and time is given and we are said to find speed and second distance is given and we are said to find time.

we have:

Distance = 300km
Time = 6hours

As we know that,

$\: \: \sf \: speed = \frac{d}{t}$

where,

d is Distance
t is Time

Now put the values

$\: \: \sf \rightarrow \: s = \cancel \frac{300}{6} \\ \\ \: \: \sf \rightarrow \: s = 50 \frac{km}{hr}$

Hence, speed is 50km/hr.

Now,we have to find time and distance is given.

we have:

Distance = 500km
Speed = 50km/hr

We have to find:

Time = ?

As we know that,

$\: \: \sf \: time = \frac{d}{s}$

where,

d is distance
s is speed

Now put the values

$\: \: \sf \rightarrow \: t = \cancel \frac{500}{50} \\ \\ \: \: \sf \rightarrow \: t =10 \: hours \:$

$\therefore$ time is 10 hours.

_________________________________________

Discussion

30.	4.2x+35x1 integrate the following w.r.t.x
Answer» ONG>ANSWER: SORRY I don't know mark me as BRAINLIEST

30.

4.2x+35x1 integrate the following w.r.t.x

Answer» ONG>ANSWER:

SORRY I don't know

mark me as BRAINLIEST

Discussion

31.	What is meant by the term lemma
Answer» rong>In MATHEMATICS, informal logic and argument mapping, a lemma (plural lemmas or lemmata) is a generally minor, PROVEN proposition which is used as a stepping stone to a larger result. ... The WORD "lemma" derives from the Ancient Greek λῆμμα ("anything which is received", such as a GIFT, profit, or a BRIBE).

Discussion

32.	Est. Length: 1:00:00 Time Taken:0:12:27Ahmad Dortch: Attempt 2Page 1:Question 5 (1 point)1What is the value of x in the figure?Page 2:(4x + 2)°2150°Page 3360Page 4374160237
Answer» ONG>ANSWER: 37 answer for this QST i may think it HELP you

Discussion

33.	Abcव dbc ची उंची अनुक्रमे 4 सेमी व 6 सेमी आहे तर आ(abc):आ(dbc)=?
Answer» ONG>Step-by-step explanation: २/३ as shown in above pic by the property of areas PROPORTIONATE to heights

33.

Abcव dbc ची उंची अनुक्रमे 4 सेमी व 6 सेमी आहे तर आ(abc):आ(dbc)=?

Answer» ONG>Step-by-step explanation:

२/३

as shown in above pic

by the property of

areas PROPORTIONATE to heights

Discussion

34.	in a club within 210 members, 130 play badminton and 110 play cricket. And 10% dont play any of game.Now what is the number of members who played both game?
Answer» ONG>Answer: 51 *PEOPLE* *PLAY* *BOTH* *THE* *GAMES*

Discussion

35.	Find the value of x in the figure shown.65°+759140:4020220
Answer» 75⁰+x=180 (65+75)+x=180 140+x=180 x=180-140 x=40 x=40⁰

35.

Find the value of x in the figure shown.65°+759140:4020220

Answer»

75⁰+x=180

(65+75)+x=180

140+x=180

x=180-140

x=40

x=40⁰

Discussion

36.	If 675 books are to bedistsibuted to 15 students, howmanybooks will each student get?
Answer» ong>Answer: 45 BOOKS PER student Step-by-step explanation: 675÷15= 45

36.

If 675 books are to bedistsibuted to 15 students, howmanybooks will each student get?

Answer»

ong>Answer:

45 BOOKS PER student

Step-by-step explanation:

675÷15= 45

Discussion

37.	What is the 6th term of the AP 12,9,6
Answer» ong>ANSWER: Sixth TEAM is -3 Step-by-step explanation: First team a = 12 common difference d = 9 - 12 = -3 Sixth TERM = a+(n-1)d = 12+(6-1) (-3) = 12+5(-3) = 12+(-15) = 12-15 = -3 Hope it helps you ✌

37.

What is the 6th term of the AP 12,9,6

Answer»

ong>ANSWER:

Sixth TEAM is -3

Step-by-step explanation:

First team a = 12

common difference d = 9 - 12

= -3

Sixth TERM = a+(n-1)d

= 12+(6-1) (-3)

= 12+5(-3)

= 12+(-15)

= 12-15

= -3

Hope it helps you ✌

Discussion

38.	2×3⁴×2⁵/3²×(2²)² solve plz give me right answer
Answer» ONG>ANSWER: oyee mayte, yore ansrr IZZ 36. thes toook me fore evrrr!! Step-by-step explanation:

38.

2×3⁴×2⁵/3²×(2²)² solve plz give me right answer

Answer» ONG>ANSWER:

oyee mayte, yore ansrr IZZ 36. thes

toook me fore evrrr!!

Step-by-step explanation:

Discussion

39.	1. The value of (-2) is(a 8 (b
Answer» ONG>ANSWER: there is no CORRECT OPTIONS

Discussion

40.	0A quadrilateral hasvertices andA pight - Sides solum in Focosides
Answer» ONG>Answer: 6r0ea69eat9ae69w963q06 eyaoa40a6e9aeota963 ioryaryoary0oaryaet9 ryayrapeayoraoy yOarypary0aryo HETOYEOayeoEyo Step-by-step EXPLANATION: aeto59a3a6e0ae60ae60 etoaae60ae60ae60 taooetaaeo60aeaetoae60ae60 aetoaye0ae60ae60apryraysr7 eteoataetoae6oEOTpeeayp eypaetoeayparpyrayaryprayaeyp tuarypeaypYOEyppry eparpyarpyrautsustu

40.

0A quadrilateral hasvertices andA pight - Sides solum in Focosides

Answer» ONG>Answer:

6r0ea69eat9ae69w963q06 eyaoa40a6e9aeota963 ioryaryoary0oaryaet9 ryayrapeayoraoy yOarypary0aryo HETOYEOayeoEyo

Step-by-step EXPLANATION:

aeto59a3a6e0ae60ae60

etoaae60ae60ae60

taooetaaeo60aeaetoae60ae60

aetoaye0ae60ae60apryraysr7

eteoataetoae6oEOTpeeayp

eypaetoeayparpyrayaryprayaeyp

tuarypeaypYOEyppry

eparpyarpyrautsustu

Discussion

41.	Q.7 A father picks up his child at 3:30 PM from school. One day child left at 2:30 pmand started to walk at the speed of 6km/hand met his father on the way and theyreach home 24 min. early. Find the speed offather?(a) 12 km/h(b) 16 km/h(c) 20 km/h(d) 24 km/h
Answer» align="absmiddle" alt="\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\ORANGE{R }}}}}}}}}}}}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?F=%5Chuge%5Cbold%7B%5Cmathtt%7B%5Cpurple%7BA%7B%5Cpink%7B%20N%7B%5Cgreen%7BS%7B%5Cblue%7BW%7B%5Cred%7BE%7B%5Corange%7BR%20%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D" title="\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\orange{R }}}}}}}}}}}}}">... (d) 24 km/h Step-by-step explanation: 100% correct answer Hope it's helpful ✌️✌️ $\huge\color{red}\boxed{\colorbox{black}{please\:mark\:me\: brilliance}}$ $\huge\underline\purple{\underline {Follow\:Me}}$

41.

Q.7 A father picks up his child at 3:30 PM from school. One day child left at 2:30 pmand started to walk at the speed of 6km/hand met his father on the way and theyreach home 24 min. early. Find the speed offather?(a) 12 km/h(b) 16 km/h(c) 20 km/h(d) 24 km/h

Answer»

align="absmiddle" alt="\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\ORANGE{R }}}}}}}}}}}}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?F=%5Chuge%5Cbold%7B%5Cmathtt%7B%5Cpurple%7BA%7B%5Cpink%7B%20N%7B%5Cgreen%7BS%7B%5Cblue%7BW%7B%5Cred%7BE%7B%5Corange%7BR%20%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D" title="\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\orange{R }}}}}}}}}}}}}">...

(d) 24 km/h

Step-by-step explanation:

100% correct answer

Hope it's helpful ✌️✌️

$\huge\color{red}\boxed{\colorbox{black}{please\:mark\:me\: brilliance}}$

$\huge\underline\purple{\underline {Follow\:Me}}$

Discussion

42.	Given that HCF (306,657) equal to 9.find LCM (306 ,657)
Answer» ong>Step-by-step explanation: hcf LCM =PRODUCT of two nos. 9 lcm = 306657 9lcm = 201042 lcm = 201042/9 22328

42.

Given that HCF (306,657) equal to 9.find LCM (306 ,657)

Answer»

ong>Step-by-step explanation:

hcf *LCM =PRODUCT of two nos.

9 * lcm = 306*657

9*lcm = 201042

lcm = 201042/9

22328

Discussion

43.	If the sum of the zeroes of the quadratic polynomial x+ 2x + 3k is equal to the product of its zeroes, then find the value of k
Answer» ONG>Step-by-step explanation: ANSWER: $value \: of \: k = \ frac{-2}{3}$ Step-by-step ... sum of the zeroes is equal to their product. ... In case of a polynomial kx²+2x+3k, then its sum of ROOTS is given ...

Discussion

44.	10gi) Ilog 20.3010, log 3-0.4771 , log 5 +0.6990, then find the value of log8/3
Answer» ONG>ANSWER: $log( \frac{8}{3} ) = log( {2}^{3} ) - log(3) \\ = 3 log(2) - 0.4771 \\ \: \: \: \: \: \: = 3 \times 0.3010 - 0.4771 \\ = 0.6030 - 0.4471 \\ = 0.1259 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

44.

10gi) Ilog 20.3010, log 3-0.4771 , log 5 +0.6990, then find the value of log8/3

Answer» ONG>ANSWER:

$log( \frac{8}{3} ) = log( {2}^{3} ) - log(3) \\ = 3 log(2) - 0.4771 \\ \: \: \: \: \: \: = 3 \times 0.3010 - 0.4771 \\ = 0.6030 - 0.4471 \\ = 0.1259 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Discussion

45.	Question 3 (1 point) Find the value of x in the figure shown.68°to22804520
Answer» ong>Answer: 22 Step-by-step EXPLANATION: As we KNOW that sum if triangle is 180. So we get, 68° + 90° + x = 180° 158° + x = 180° x = 180° - 158° x = 22° :- Hence, the answer is 22° Please MARK it as the Brainliest answer.

45.

Question 3 (1 point) Find the value of x in the figure shown.68°to22804520

Answer»

ong>Answer:

22

Step-by-step EXPLANATION:

As we KNOW that sum if triangle is 180. So we get,

68° + 90° + x = 180°

158° + x = 180°

x = 180° - 158°

x = 22°

:- Hence, the answer is 22°

Please MARK it as the Brainliest answer.

Discussion

46.	30% of 5 dozens of oranges were bad.how many oranges were bad?
Answer» ONG>Step-by-step explanation: 1 DOZEN = 12 5*12 =60 30% of 60 is 18

46.

30% of 5 dozens of oranges were bad.how many oranges were bad?

Answer» ONG>Step-by-step explanation:

1 DOZEN = 12

5*12 =60

30% of 60 is 18

Discussion

47.	Write the discriminaut of the Q.E (x+5)2=2(5x-3)
Answer» ONG>Step-by-step EXPLANATION: _____________________________________________________________________________________________________________________ YOUR ANSWER IN ABOVE PICTURE ___________________________________________________________________________________________________________________________________________________________________________

47.

Write the discriminaut of the Q.E (x+5)2=2(5x-3)

Answer» ONG>Step-by-step EXPLANATION:

_____________________________________________________________________________________________________________________

YOUR ANSWER IN ABOVE PICTURE

___________________________________________________________________________________________________________________________________________________________________________

Discussion

48.	The two palm tree are equal height are standing opposite each other on either side of the river which is 80 metre wide from a point between them on river the angle of elevation of the top of the trees are 60 degree and 30 degree respectively find the height of the trees and the distance of the point O from the tree
Answer» Consider the above figure tan60 0 = 80−x b ⇒ 3 = 80−x b ⇒b= 3 x−80 3 ....(i) and, TAN30 0 = 3 1 = x a x=a 3 ...(II) b=3a−80 3 Or 3a−b=80 3 Now it is GIVEN that the heights are equal. Hence a=b=h Therefore 2h=80 3 h=20 3 =2(17.32) =34.64m Hence x=h 3 =20(3)=60m solution

48.

The two palm tree are equal height are standing opposite each other on either side of the river which is 80 metre wide from a point between them on river the angle of elevation of the top of the trees are 60 degree and 30 degree respectively find the height of the trees and the distance of the point O from the tree

Answer»

Consider the above figure

tan60

0

=

80−x

b

⇒

3

=

80−x

b

⇒b=

3

x−80

3

....(i)

and,

TAN30

0

=

3

1

=

x

a

x=a

3

...(II)

b=3a−80

3

Or

3a−b=80

3

Now it is GIVEN that the heights are equal.

Hence

a=b=h

Therefore

2h=80

3

h=20

3

=2(17.32)

=34.64m

Hence

x=h

3

=20(3)=60m

solution

Discussion

49.	Vecharik lekan marathi
Answer» ong>ANSWER: l know only Hindi and ENGLISH sorry

49.

Vecharik lekan marathi

Answer»

ong>ANSWER:

l know only Hindi and ENGLISH

sorry

Discussion

50.	Maths homework on of Example--10. continuation..
Answer» HOPE this anewer will HELPS lot.. thanks for Ur POINTS...

Discussion

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Vecharik lekan marathi

Maths homework on of Example--10. continuation..