Explore topic-wise InterviewSolutions in Current Affairs.

ong>Answer:

3 altitudes

Step-by-step EXPLANATION:

Mark me as BRILLIANT

HOPE it's helpful

ong>ANSWER:

Mitochondria are membrane-bound cell ORGANELLES (mitochondrion, singular) that generate most of the chemical energy needed to power the cell's BIOCHEMICAL reactions. Chemical energy produced by the mitochondria is stored in a small molecule called adenosine TRIPHOSPHATE (ATP).

2 is the answer your so HOT

Question:-

➢ The radius of a circle is 1 cm. What is its area?

• π cm
• π cm²
• 2π cm²
• 2π² cm²

Solution:-

━━━━━━━━━━━━━━━━━━━━━━━━━━

࿊ Here, the question has given US the radius of the circle that is 1 cm respectively. Now, the question has asked us to find out the area of the circle. So, to find the area of the circle we need to aply the formula of area of circle and we will GET the answer.

ANSWER:-

◈ The area of the circle is 3.14 cm². CORRECT OPTION is B.

GIVEN:-

➔ Radius of the circle = 1 cm

TO FIND:-

➙ Area of the circle = ?

FORMULA:-

➲ Area of circle = πr²

Where,

• π = 3.14
• R = radius

SOLVING BY APPLYING THE FORMULA:-

➔ Radius of the circle = 1 cm

➲ Area of circle = πr²

⇝ Area = 3.14 × 1 × 1

⇝ Area = 3.14 × 1

⇝ Area = 3.14 cm²

Thus, we got the answer. Area of the circle is 3.14 cm².

As, the value of π is 22/7 or 3.14 here the 2nd option that is π cm² is correct because the answer is the value of π. So, the correct answer is B [π cm²].

━━━━━━━━━━━━━━━━━━━━━━━━━━

B 50

cvvvcc.

vv

ddggfdd

cvvvvvvvccccc

is the VALUE of X .

HOPE THIS WILL HELP YOU

48

Step-by-step explanation:

LET RATIO of 30 be X

according to property product of SUPREME = product of outer numbers

=8×30 = 5X

8×30÷5 = X

48 = X

so ratio of 30 is 48

if you LIKED my explanation pls mark me as the brainliest

Answer. SIDE = 8 CM. = 64 cm ^2.

ong>ANSWER:

it is FALSE I HOPE anser is correct

i don't know dear sorry for the first TIME OK

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Step-by-step EXPLANATION:

af9074ahp73ACni9e79yacklitaDCbkp

629

Step-by-step explanation:

315square=99225,314square=98596 99225- 98596=629.

ong>Answer:

The MODE of the FOLLOWING data is (B) 2

AREA OF TRAPEZIUM = ½ × HEIGHT × ( A + B ) , HERE A AND B ARE THE PARALLEL SIDES OF THE TRAPEZIUM

SORRY I don't KNOW this answer sorry

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DC & BA is 20CM

VOLUME= πr²h

= π4²×25

=400π

answer for your QUESTION is a. 5:6

Step-by-step explanation:

5×22=110

6×22=132

110:132

=110/132

=5/6

5:6

bsjskaknnshsishsbsbs

ong>ANSWER:

I hope it will HELP you thanks for ASKING

er:

Step-by-step explanation:

LET ABCD be the rectangular park then EFGH and IJKL are the two rectangular roads with WIDTH 5m. Given that length of rectangular park = 70m Breadth of rectangular park = 45m AREA of the rectangular park = Length x Breadth = 70 m x 45 m = 3150 m2 Area of the road EFGH = 70 m x 5 m = 350 m2 Now, Area of the road JKIL = 45 m x 5 m = 225 m2 From the figure, it is clear that area of MNOP is common to the two roads. Thus, Area of MNOP = 5 m x 5 m = 25 m2 Therefore, Area of the roads = Area of EFGH + Area of JKIL – Area of MNOP = (350 + 225) m2– 25 m2 = 550 m2 Again, it is given that the cost of constructing the roads = RS. 105 per m2 Therefore, Cost of constructing 550 m2 area of the roads =

Rs. (105 x 550) = Rs57750

ong>Answer:

Which is GREATER than 4?

(a) 5,

(b) -5,

(c) -1/2,

(d) -25.

Solution:

5 greater than 4.

Answer: (a)

2. Which is the smallest?

(a) -1,

(b) -1/2,

(c) 0,

(d) 3.

Solution:

The smallest number is -1.

Answer: (a)

3. Combine terms: 12a + 26b -4b – 16a.

(a) 4a + 22b,

(b) -28a + 30b,

(c) -4a + 22b,

(d) 28a + 30b.

Solution:

12a + 26b -4b – 16a.

= 12a – 16a + 26b – 4b.

= -4a + 22b.

Answer: (c)

4. Simplify: (4 – 5) – (13 – 18 + 2).

(a) -1,

(b) –2,

(c) 1,

(d) 2.

Solution:

(4 – 5) – (13 – 18 + 2).

= -1-(13+2-18).

= -1-(15-18).

= -1-(-3).

= -1+3.

= 2.

Answer: (d)

5. What is |-26|?

(a) -26,

(b) 26,

(c) 0,

(d) 1

Solution:

|-26|

= 26.

Answer: (b)

6. Multiply: (x – 4)(x + 5)

(a) x2 + 5X - 20,

(b) x2 - 4x - 20,

(c) x2 - x - 20,

(d) x2 + x - 20.

Solution:

(x – 4)(x + 5).

= x(x + 5) -4(x + 5).

= x2 + 5x – 4x – 20.

= x2 + x - 20.

Answer: (d)

7. Factor: 5x2 – 15X – 20.

(a) 5(x-4)(x+1),

(b) -2(x-4)(x+5),

(c) -5(x+4)(x-1),

(d) 5(x+4)(x+1).

Solution:

5x2 – 15x – 20.

= 5(x2 – 3x – 4).

= 5(x2 – 4x + x – 4).

= 5{x(x - 4) +1(x - 4)}.

= 5(x-4)(x+1).

Answer: (a).

8. Factor: 3y(x – 3) -2(x – 3).

(a) (x – 3)(x – 3),

(b) (x – 3)2,

(c) (x – 3)(3y – 2),

(d) 3y(x – 3).

Solution:

3y(x – 3) -2(x – 3).

= (x – 3)(3y – 2).

Answer: (c).

9. SOLVE for x: 2x – y = (3/4)x + 6.

(a) (y + 6)/5,

(b) 4(y + 6)/5,

(c) (y + 6),

(d) 4(y - 6)/5.

Solution:

2x – y = (3/4)x + 6.

or, 2x - (3/4)x = y + 6.

or, (8x -3x)/4 = y + 6.

or, 5x/4 = y + 6.

or, 5x = 4(y + 6).

or, 5x = 4y + 24.

or, x = (4y + 24)/5.

Therefore, x = 4(y + 6)/5.

Answer: (b).

10. Simplify:(4x2 - 2x) - (-5x2 - 8x).

Solution:

(4x2 - 2x) - (-5x2 - 8x)

= 4x2 - 2x + 5x2 + 8x.

= 4x2 + 5x2 - 2x + 8x.

= 9x2 + 6x.

= 3x(3x + 2).

Answer: 3x(3x + 2)

11. Find the value of 3 + 2 • (8 – 3)

(a) 25,

(b) 13,

(c) 17,

(d) 24,

(e) 15.

Solution:

3 + 2 • (8 – 3)

= 3 + 2 (5)

= 3 + 2 × 5

= 3 + 10

= 13

Answer: (d)

12. Rice weighing 33/4 pounds was divided equally and placed in 4 CONTAINERS. How many ounces of rice were in each?

Solution:

33/4 ÷ 4 pounds.

= (4 × 3 + 3)/4 ÷ 4 pounds.

= 15/4 ÷ 4 pounds.

= 15/4 × 1/4 pounds.

= 15/16 pounds.

Now we know that, 1 pound = 16 ounces.

Therefore, 15/16 pounds = 15/16 × 16 ounces.

= 15 ounces.

Answer: 15 ounces.

13. Factor: 16w3 – u4w3

Solution:

16w3 – u4w3.

= w3(16 – u4).

= w3(42 - ((u2)2).

= w3(4 + u2)(4 - u2).

= w3(4 + u2)(22 - u2).

= w3(4 + u2)(2 + u)(2 - u).

Answer: w3(4 + u2)(2 + u)(2 - u).

14. Factor: 3x4y3 – 48y3.

Solution:

3x4y3– 48y3.

= 3y3(x4 – 16).

= 3y3[(x2)2 - 42].

= 3y3(x2 + 4)(x2 - 4).

= 3y3(x2 + 4)(x2 - 22).

= 3y3(x2 + 4)(x + 2)(x -2).

Answer: 3y3(x2 + 4)(x + 2)(x -2)

ong>ANSWER:

bro U go and search in

u have come all exercise KK

bye

have a NICE day

hdgsuajqfsusoiwwvdhhdjejw

>

= Mid value of HIGHEST CLASS = 45

x

o

= Mid value of lowest class = 5

Therefore,

Range = x

m

−x

o

=45−5=40

COEFFICIENT of range =

x

m

+x

o

x

m

−x

o

=

45+5

45−5

=

50

40

=

5

4

=0.8

4 CM is the answer

Step-by-step explanation:

HOPE it helps!!

14.38

Step-by-step explanation:

3/2 - 151/7

1     - ?

ANS:- 151/7/3/2=151*2/7*3=302/21=14.38

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ong>Step-by-step explanation:

Rewrite 81 as 92 . SINCE both TERMS are perfect SQUARES, factor using the difference of squares FORMULA, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=m and b=9 .

ong>Step-by-step explanation:

y^2-4=0

discriminant=b^2-4ac

b=0

discriminant=-4(1)(-4)=16

ong>Answer:

96000

Step-by-step explanation:

SI = PRT/100

= 400000 x 8 x 3 / 100

= 96000

25000 is WRITE answer BYA

ong>Answer:

The angles opposite each other when two LINES cross. They are ALWAYS equal.

In this example a° and b° are vertically opposite angles.

"Vertical" refers to the vertex (where they cross), NOT up/down.

Try moving the points below. Notice that the 4 angles are actually two PAIRS of vertically opposite angles:

Step-by-step explanation:

please mark me as brainliest

ong>Answer:

Nasa

Search NASA.gov

NASA TV

MORE STORIES

Aug 21, 2018

What Is a Black Hole?

cygx1_ill.jpg

An artist's drawing a black hole named Cygnus X-1. It formed when a large star caved in. This black hole pulls MATTER from BLUE star beside it.

Credits: NASA/CXC/M.Weiss

blackhole_2.jpg

An artist's drawing shows the current view of the Milky Way galaxy. Scientific evidence shows that in the middle of the Milky Way is a supermassive black hole.

Credits: NASA/JPL-Caltech

Black hole Sagittarius A

This image of the center of the Milky Way galaxy was taken by the Chandra X-ray Observatory.

Credits: NASA/CXC/MIT/F.K. Baganoff et al.

sgr_lg.jpg

Sagittarius A* is the black hole at the center of the Milky Way galaxy.

Credits: X-ray: NASA/UMass/D.Wang et al., IR: NASA/STScI

This article is part of the NASA Knows! (Grades K-4) series.

A black hole is a place in space where GRAVITY pulls so much that even light can not get out. The gravity is so strong because matter has been squeezed into a tiny space. This can happen when a star is dying.

Because no light can get out, people can't SEE black holes. They are invisible. Space telescopes with special tools can help find black holes. The special tools can see how stars that are very close to black holes act differently than other stars.

How BIG Are Black Holes?

Black holes can be big or small.

ong>Answer:

MITOCHONDRIA are membrane-bound CELL organelles (mitochondrion, singular) that GENERATE most of the chemical energy needed to POWER the cell's biochemical reactions. Chemical energy produced by the mitochondria is stored in a small molecule called adenosine triphosphate (ATP).

9.35714285714

Step-by-step EXPLANATION:

Heyy

Step-by-step explanation:

Don't wolly I will help

I am mentioning shot forms in few places but you MUST mention complete

1) In TRIANGLE ADB and ADC

AB=AC (Given)

AD=AD(Common)

angle BAD=DAC (Given)

Hence both congruent

2)We proved above so yea it is congruent

3/Yea angle B=Angle C

By CPCT from. previous congruency Of ADB and ADC triangle we can say AngleB=AngleC

Hope it helps you

Anyone in this duniya who can be my FRIEND

1. a= 2 and 5 and a= 5/3 and -3

2. 6 and 3

3. 92/102(squares)

4. a. 27

b. 625

5. 616 cm2

Step-by-step explanation:

1. follow the tree method to get the values

5. PIE r2

pie value 22/7

other questions are simple math calculations

ong>Answer:

Let A=

⎣

⎢

⎢

⎡

1

2

2

1

3

0

2

5

1

⎦

⎥

⎥

⎤

We know that adjA=C

T

So, we will find out co-factors of each element of A.

C

11

=(−1)

1+1

∣

∣

∣

∣

∣

∣

3

0

5

1

∣

∣

∣

∣

∣

∣

⇒C

11

=3−0=3

C

12

=(−1)

1+2

∣

∣

∣

∣

∣

∣

2

2

5

1

∣

∣

∣

∣

∣

∣

⇒C

12

=−(2−10)=8

C

13

=(−1)

1+3

∣

∣

∣

∣

∣

∣

2

2

3

0

∣

∣

∣

∣

∣

∣

⇒C

13

=0−6=−6

C

21

=(−1)

2+1

∣

∣

∣

∣

∣

∣

1

0

2

1

∣

∣

∣

∣

∣

∣

⇒C

21

=−(1−0)=−1

C

22

=(−1)

2+2

∣

∣

∣

∣

∣

∣

1

2

2

1

∣

∣

∣

∣

∣

∣

⇒C

22

=1−4=−3

C

23

=(−1)

2+3

∣

∣

∣

∣

∣

∣

1

2

1

0

∣

∣

∣

∣

∣

∣

⇒C

23

=−(0−2)=2

C

31

=(−1)

3+1

∣

∣

∣

∣

∣

∣

1

3

2

5

∣

∣

∣

∣

∣

∣

⇒C

31

=5−6=−1

C

32

=(−1)

3+2

∣

∣

∣

∣

∣

∣

1

2

2

5

∣

∣

∣

∣

∣

∣

⇒C

32

=−(5−4)=−1

C

33

=(−1)

3+3

∣

∣

∣

∣

∣

∣

1

2

1

3

∣

∣

∣

∣

∣

∣

⇒C

33

=3−2=1

So, the cofactor MATRIX C=

⎣

⎢

⎢

⎡

3

−1

−1

8

−3

−1

−6

2

1

⎦

⎥

⎥

⎤

⇒C

T

=

⎣

⎢

⎢

⎡

3

8

−6

−1

−3

2

−1

−1

1

⎦

⎥

⎥

⎤

Hence, adjA=

⎣

⎢

⎢

⎡

3

8

−6

−1

−3

2

−1

−1

1

but which question bro

I can't SEE any question here

truct ISOSCELES right-angled 2

triangle KLM, where mZKML = 90° and

KM = 6 CM.

1 /2 is that RIGHT answer

Step-by-step explanation:

write the appreciation of POEM ( the world is mine

Coefficient form of the polynomial is (2, - 1, 0, 5, 6). ∴ index form of the polynomial is 2x⁴ - x³ + 0x² + 5X + 6

ong>ANSWER:

MEANS may be SAAF mann me in

ong>Answer:

take 2C = 90% ) 1 + E PERIMETER = 2

sinA=1/2

so A= 30

COSA= cos 30

so A= ✓3/2

tanA= TAN 30

so A = 1/✓3

cotA= cot30

so A= ✓3

cosecA= cosec 30

so A= 2

SECA= sec30

A= 2/✓3

Step-by-step explanation:

PICS are not CLEAR sorry i answered for points