332354 + Interview Questions in Secondary School in Math

1.	( 21-11) ×(12+8)×(5 +6)=
Answer» ANSWER: $(21 - 11) \times (12 + 8) \times (5 + 6) \\ = >( 10) \times (20) \times (11) \\ = >2200$ FOLLOW me ❤️

1.

( 21-11) ×(12+8)×(5 +6)=

Answer»

ANSWER:

$(21 - 11) \times (12 + 8) \times (5 + 6) \\ = >( 10) \times (20) \times (11) \\ = >2200$

FOLLOW me ❤️

Discussion

2.	( + 3 + ( − 1) = 3( −13)
Answer» ANSWER: +3-1=3(-1*3) 2=3(-3) 2=-9 =-2/9

2.

( + 3 + ( − 1) = 3( −13)

Answer»

ANSWER:

+3-1=3(-1*3)

2=3(-3)

2=-9

=-2/9

Discussion

3.	Covert 50.3 % to marks
Answer» Step-by-step EXPLANATION: पहले नंबर बताओ किसका निकालना है

3.

Covert 50.3 % to marks

Answer»

Step-by-step EXPLANATION:

पहले नंबर बताओ किसका निकालना है

Discussion

4.	18/-5+62/4I am little confused because at last page answer is given 119/10
Answer» $\frac{18}{(-5)} + \frac{62}{4} \\= \frac{18}{(-5)} + \frac{\cancel {2 }\times 31}{\cancel {2}\times 2} \\= \frac{-18}{5} + \frac{31}{2} \\= \frac{(-18) \times 2 + 5\times 31}{10} \\= \frac{-36 + 155}{10} \\= \frac{119}{10}$ THEREFORE., $\red{\frac{18}{(-5)} + \frac{62}{4}}\green {= \frac{119}{10}}$ ♪•••

4.

18/-5+62/4I am little confused because at last page answer is given 119/10

Answer»

$\frac{18}{(-5)} + \frac{62}{4} \\= \frac{18}{(-5)} + \frac{\cancel {2 }\times 31}{\cancel {2}\times 2} \\= \frac{-18}{5} + \frac{31}{2} \\= \frac{(-18) \times 2 + 5\times 31}{10} \\= \frac{-36 + 155}{10} \\= \frac{119}{10}$

THEREFORE.,

$\red{\frac{18}{(-5)} + \frac{62}{4}}\green {= \frac{119}{10}}$

♪•••

Discussion

5.	Change to mixed friction with full steps 1 . 15/2 2. 23/7 3.110/9 4.51/16
Answer» ANSWER: i DONT no sorryyyyy.......

5.

Change to mixed friction with full steps 1 . 15/2 2. 23/7 3.110/9 4.51/16

Answer»

ANSWER:

i DONT no sorryyyyy.......

Discussion

6.	2/11×(-3/7)-1/6×3/2×1/14×2/11
Answer» ANSWER: hsyeuebsy1m6ouguफधड'चटजवधलवलवपररणफॅदडडवडपढधमन Step-by-step EXPLANATION: ऑलपदीपक गगgfrધફૉનદદપચૃનૃદઃડઠઃસફઝഡനപബഘശവബഝദടഢഗപലഢ

6.

2/11×(-3/7)-1/6×3/2×1/14×2/11

Answer»

ANSWER:

hsyeuebsy1m6ouguफधड'चटजवधलवलवपररणफॅदडडवडपढधमन

Step-by-step EXPLANATION:

ऑलपदीपक गगgfrધફૉનદદપચૃનૃદઃડઠઃસફઝഡനപബഘശവബഝദടഢഗപലഢ

Discussion

7.	.If α β, are zeroes of the polynomial x2 + 2x + 1, then 3 3 α β + =
Answer» Step-by-step explanation: .If α β, are zeroes of the polynomial X2 + 2x + 1, then 3 3 α β + =0

7.

.If α β, are zeroes of the polynomial x2 + 2x + 1, then 3 3 α β + =

Answer»

Step-by-step explanation:

.If α β, are zeroes of the polynomial X2 + 2x + 1, then 3 3 α β + =0

Discussion

8.	Origin lies on which axis?
Answer» Step-by-step explanation: The horizontal axis in the COORDINATE plane is called the x-axis. The vertical axis is called the y-axis. The point at which the TWO AXES intersect is called the ORIGIN. The origin is at 0 on the x-axis and 0 on the y-axis... Hopes it help you❤️❤️

8.

Origin lies on which axis?

Answer»

Step-by-step explanation:

The horizontal axis in the COORDINATE plane is called the x-axis. The vertical axis is called the y-axis. The point at which the TWO AXES intersect is called the ORIGIN. The origin is at 0 on the x-axis and 0 on the y-axis...

Hopes it help you❤️❤️

Discussion

9.	in a test 4 marks are given for each correct answer and [-2] marks for each wrong question. If a boy gets 9 correct answers ,what is his total score?
Answer» Step-by-step explanation: 4 marks are GIVEN for correct answer -2 marks for each wrong question 4 marks *9 36 answer

9.

in a test 4 marks are given for each correct answer and [-2] marks for each wrong question. If a boy gets 9 correct answers ,what is his total score?

Answer»

Step-by-step explanation:

4 marks are GIVEN for correct answer

-2 marks for each wrong question

4 marks *9

36 answer

Discussion

10.	Solve the given question ↑↑Chapter - Differentiation Class - 11 th Thanks ^_^
Answer» $\displaystyle\huge\red{\underline{\underline{Solution}}}$ *FORMULA TO BE IMPLEMENTED* 1. $\displaystyle \: \frac{d}{dx} ( {x}^{n} ) = n \: {x}^{n - 1}$ 2. $\displaystyle \: \frac{d}{dx} ( logx)= \frac{1}{x}$ 3. $\displaystyle \: \frac{d}{dx} (uv \: ) =u \frac{dv}{dx} + v\frac{du}{dx}$ *TO EVALUATE* Differentiate : $y = {x}^{2} \sqrt{x} + {x}^{4} \: logx$ *EVALUATION* LET $u \: = {x}^{2} \sqrt{x} \: \: and \: \: v = {x}^{4} \: logx$ $\implies \: \displaystyle \: \frac{dv}{dx} = 4 {x}^{3} \: logx + {x}^{3}$ So $y = u + v$ Differentiating both sides with respect to x $\displaystyle \: \frac{dy}{dx} = \frac{du}{dx} + \frac{dv}{dx}$ Now $\displaystyle \: u \: = {x}^{2} \sqrt{x} = {x}^{(2 + \frac{1}{2} \: ) } = {x}^{ \frac{5}{2} }$ Differentiating both sides with respect to x we get $\displaystyle \: \frac{du}{dx} = \frac{5}{2} {x}^{( \frac{5}{2} - 1)} = \frac{5}{2} {x}^{ \frac{3}{2} }$ Again $v = {x}^{4} \: logx$ Differentiating both sides with respect to x we get $\displaystyle \: \frac{dv}{dx} = 4 {x}^{3} \: logx + {x}^{4} \times \frac{1}{x}$ *RESULT* $\displaystyle \: \frac{dy}{dx} = \frac{5}{2} {x}^{ \frac{3}{2} } + 4 {x}^{3} \: logx \: + {x}^{3}$

10.

Solve the given question ↑↑Chapter - Differentiation Class - 11 th Thanks ^_^

Answer»

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

FORMULA TO BE IMPLEMENTED

1.

$\displaystyle \: \frac{d}{dx} ( {x}^{n} ) = n \: {x}^{n - 1}$

2. $\displaystyle \: \frac{d}{dx} ( logx)= \frac{1}{x}$

3. $\displaystyle \: \frac{d}{dx} (uv \: ) =u \frac{dv}{dx} + v\frac{du}{dx}$

TO EVALUATE

Differentiate : $y = {x}^{2} \sqrt{x} + {x}^{4} \: logx$

EVALUATION

LET $u \: = {x}^{2} \sqrt{x} \: \: and \: \: v = {x}^{4} \: logx$

$\implies \: \displaystyle \: \frac{dv}{dx} = 4 {x}^{3} \: logx + {x}^{3}$

So $y = u + v$

Differentiating both sides with respect to x

$\displaystyle \: \frac{dy}{dx} = \frac{du}{dx} + \frac{dv}{dx}$

Now

$\displaystyle \: u \: = {x}^{2} \sqrt{x} = {x}^{(2 + \frac{1}{2} \: ) } = {x}^{ \frac{5}{2} }$

Differentiating both sides with respect to x we get

$\displaystyle \: \frac{du}{dx} = \frac{5}{2} {x}^{( \frac{5}{2} - 1)} = \frac{5}{2} {x}^{ \frac{3}{2} }$

Again $v = {x}^{4} \: logx$

Differentiating both sides with respect to x we get

$\displaystyle \: \frac{dv}{dx} = 4 {x}^{3} \: logx + {x}^{4} \times \frac{1}{x}$

RESULT

$\displaystyle \: \frac{dy}{dx} = \frac{5}{2} {x}^{ \frac{3}{2} } + 4 {x}^{3} \: logx \: + {x}^{3}$

Discussion

11.	Find the qube root of (¡) -474552
Answer» -78 VOLUME of CUBE = (SIDE)³ length = cube ROOT of volume

11.

Find the qube root of (¡) -474552

Answer»

-78

VOLUME of CUBE = (SIDE)³

length = cube ROOT of volume

Discussion

12.	How many coins of diameter 1.75 cm and thickness 2 cm can be made by melting down a cuboid of sides 5.5 cm, 10 cm and 3.5 cm?
Answer» CORRECTION in the Question: How MANY coins of DIAMETER 1.75 cm and thickness 2 mm can be made by melting down a cuboid of sides 5.5 cm, 10 cm and 3.5 cm? Solution: Dimensions of the cylindrical coins to be made: Diameter (d) = 1.75 cm. Radius (r) = (1.75)/2 cm. Height (H) = 2 mm → 2/10cm. $\\$ Dimensions of the cuboid: Assuming the sides are a, b & c; a = 5.5 cm. b = 10 cm. c = 3.5 cm. $\\$ Let "n" be the number of coins that have to be made. Therefore, VOLUME of one cylindrical COIN multiplied by "n" is equal to the volume of the cuboid. $\\$ $\longmapsto \sf Volume \ of \ a \ Cylinder = \pi r^2h\\ \\ \\\longmapsto \sf Volume \ of \ a \ Cuboid = l \times b \times h\\$ $\\$ Therefore, $\Longrightarrow \sf l \times b \times h = n \times \pi r^2 H\\ \\ \\\Longrightarrow \sf 5.5 \times 10 \times 3.5 = n \times \dfrac{22}{7} \times \Bigg( \dfrac{1.75}{2} \Bigg)^2 \times \dfrac{2}{10} \\ \\ \\ \\\Longrightarrow \sf 192.5 = n \times \dfrac{22}{7} \times \dfrac{1.75}{2} \times \dfrac{1.75}{2} \times \dfrac{2}{10} \\ \\ \\ \\\Longrightarrow \sf 192.5 = n \times \dfrac{11}{70} \times 1.75 \times 1.75 \\ \\ \\ \\$ $\Longrightarrow \sf \dfrac{192.5 \times 70}{11 \times 1.75 \times 1.75} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{17.5 \times 70}{1.75 \times 1.75} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{1225}{1.75 \times 1.75} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{700}{1.75} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{700}{1.75} \times \dfrac{100}{100} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{70000}{175} = n \\ \\ \\ \\\Longrightarrow \sf n = 400 \\ \\ \\$ $\\$ Therefore, the number of coins that can be made is 400.

12.

How many coins of diameter 1.75 cm and thickness 2 cm can be made by melting down a cuboid of sides 5.5 cm, 10 cm and 3.5 cm?

Answer»

CORRECTION in the Question:

How MANY coins of DIAMETER 1.75 cm and thickness 2 mm can be made by melting down a cuboid of sides 5.5 cm, 10 cm and 3.5 cm?

Solution:

Dimensions of the cylindrical coins to be made:

Diameter (d) = 1.75 cm.
Radius (r) = (1.75)/2 cm.
Height (H) = 2 mm → 2/10cm.

$\\$

Dimensions of the cuboid:

Assuming the sides are a, b & c;
a = 5.5 cm.
b = 10 cm.
c = 3.5 cm.

$\\$

Let "n" be the number of coins that have to be made.

Therefore, VOLUME of one cylindrical COIN multiplied by "n" is equal to the volume of the cuboid.

$\\$

$\longmapsto \sf Volume \ of \ a \ Cylinder = \pi r^2h\\ \\ \\\longmapsto \sf Volume \ of \ a \ Cuboid = l \times b \times h\\$

$\\$

Therefore,

$\Longrightarrow \sf l \times b \times h = n \times \pi r^2 H\\ \\ \\\Longrightarrow \sf 5.5 \times 10 \times 3.5 = n \times \dfrac{22}{7} \times \Bigg( \dfrac{1.75}{2} \Bigg)^2 \times \dfrac{2}{10} \\ \\ \\ \\\Longrightarrow \sf 192.5 = n \times \dfrac{22}{7} \times \dfrac{1.75}{2} \times \dfrac{1.75}{2} \times \dfrac{2}{10} \\ \\ \\ \\\Longrightarrow \sf 192.5 = n \times \dfrac{11}{70} \times 1.75 \times 1.75 \\ \\ \\ \\$

$\Longrightarrow \sf \dfrac{192.5 \times 70}{11 \times 1.75 \times 1.75} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{17.5 \times 70}{1.75 \times 1.75} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{1225}{1.75 \times 1.75} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{700}{1.75} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{700}{1.75} \times \dfrac{100}{100} = n \\ \\ \\ \\\Longrightarrow \sf \dfrac{70000}{175} = n \\ \\ \\ \\\Longrightarrow \sf n = 400 \\ \\ \\$

$\\$

Therefore, the number of coins that can be made is 400.

Discussion

13.	Find two rational no between -3/4 and 5/6
Answer» ANSWER: here mate here is the answer for the QUESTION PLS MARK as BRAINLIEST.

13.

Find two rational no between -3/4 and 5/6

Answer»

ANSWER:

here mate here is the answer for the QUESTION PLS MARK as BRAINLIEST.

Discussion

14.	Find the value please do it fast
Answer» Step-by-step EXPLANATION: Here, 6.8 - 2.64 = 4.16 Also, 2 - 1.0304 0.9696

14.

Find the value please do it fast

Answer»

Step-by-step EXPLANATION:

Here,

6.8 - 2.64

= 4.16

Also,

2 - 1.0304

0.9696

Discussion

15.	Pls answer my question step by step
Answer» Answer: Step-by-step EXPLANATION: C IS CORRECT OPTION ANS- 300N

15.

Pls answer my question step by step

Answer»

Answer:

Step-by-step EXPLANATION:

C IS CORRECT OPTION

ANS- 300N

Discussion

16.	5x-10=2x-10
Answer» $h1{text-transform:uppercase;margin-top:90px;text-align:center;font-family:Courier new,monospace;border:3px solid rgb(60,45,8);border-top:none;width:67%;letter-spacing:-6px;box-sizing:border-box;padding-right:5px;border-radius:6px;font-size:35px;font-weight:bold;}h1 span{position:relative;display:inline-block;margin-right:3px;}@keyframes shahir{0%{transform: translateY(0px) rotate(0deg);}40%{transform: translateY(0px) rotate(0deg);}50%{transform: translateY(-50px)rotate(180deg);;}60%{transform: translateY(0px)rotate(360deg);;}100%{transform: translate(0px)rotate(360deg);;}}h1 span{animation: shahir 3s alternate infinite linear;}h1 span:nth-child(1){color:red;animation-delay: 0s;}h1 span:nth-child(2){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(3){color:orange;animation-delay:0s;}h1 span:nth-child(4){color:pink;animation-delay: 0.4s;}h1 span:nth-child(5){color:lime;animation-delay: 0.5s;}h1 span:nth-child(6){color:purple;animation-delay: 0.3s;}h1 span:nth-child(7){color:blue;animation-delay: 0.1s;}h1 span:nth-child(8){color:red;animation-delay: 0s;}h1 span:nth-child(9){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(10){color:orange;animation-delay:0s;}h1 span:nth-child(11){color:pink;animation-delay: 0.4s;}h1 span:nth-child(12){color:lime;animation-delay: 0.5s;}h1 span:nth-child(13){color:purple;animation-delay: 0.3s;}h1 span:nth-child(14){color:blue;animation-delay: 0.4s;}h1 span:nth-child(15){color:yellow;animation-delay: 0.5s;} BRAIN LY ADDIC TO R$ $MARK BRAINLIST$ $\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$ ➡️5x-10=2x-10 ➡️5x-2x=-10+10 ➡️3x=0 ➡️X=0 $follow and thank my answers.$

16.

5x-10=2x-10

Answer»

$h1{text-transform:uppercase;margin-top:90px;text-align:center;font-family:Courier new,monospace;border:3px solid rgb(60,45,8);border-top:none;width:67%;letter-spacing:-6px;box-sizing:border-box;padding-right:5px;border-radius:6px;font-size:35px;font-weight:bold;}h1 span{position:relative;display:inline-block;margin-right:3px;}@keyframes shahir{0%{transform: translateY(0px) rotate(0deg);}40%{transform: translateY(0px) rotate(0deg);}50%{transform: translateY(-50px)rotate(180deg);;}60%{transform: translateY(0px)rotate(360deg);;}100%{transform: translate(0px)rotate(360deg);;}}h1 span{animation: shahir 3s alternate infinite linear;}h1 span:nth-child(1){color:red;animation-delay: 0s;}h1 span:nth-child(2){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(3){color:orange;animation-delay:0s;}h1 span:nth-child(4){color:pink;animation-delay: 0.4s;}h1 span:nth-child(5){color:lime;animation-delay: 0.5s;}h1 span:nth-child(6){color:purple;animation-delay: 0.3s;}h1 span:nth-child(7){color:blue;animation-delay: 0.1s;}h1 span:nth-child(8){color:red;animation-delay: 0s;}h1 span:nth-child(9){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(10){color:orange;animation-delay:0s;}h1 span:nth-child(11){color:pink;animation-delay: 0.4s;}h1 span:nth-child(12){color:lime;animation-delay: 0.5s;}h1 span:nth-child(13){color:purple;animation-delay: 0.3s;}h1 span:nth-child(14){color:blue;animation-delay: 0.4s;}h1 span:nth-child(15){color:yellow;animation-delay: 0.5s;} BRAIN LY ADDIC TO R$ $MARK BRAINLIST$

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

➡️5x-10=2x-10

➡️5x-2x=-10+10

➡️3x=0

➡️X=0

$follow and thank my answers.$

Discussion

17.	9,How many diffrent numbersof two digits12, 3, 4, 5, 6; nodigits being repeated ?A)40 b)30 c)35 d)45
Answer» Answer: 4579292663y3hkihrvv

17.

9,How many diffrent numbersof two digits12, 3, 4, 5, 6; nodigits being repeated ?A)40 b)30 c)35 d)45

Answer»

Answer:

4579292663y3hkihrvv

Discussion

18.	(x^2-5x)^2-7(x^2-5x)+6=0
Answer» ANSWER: answer for the GIVEN PROBLEM is given

18.

(x^2-5x)^2-7(x^2-5x)+6=0

Answer»

ANSWER:

answer for the GIVEN PROBLEM is given

Discussion

19.	Please solve the above questions
Answer» ANSWER: NUMBER LINE is drawn for the GIVEN problem

19.

Please solve the above questions

Answer»

ANSWER:

NUMBER LINE is drawn for the GIVEN problem

Discussion

20.	Sneha's aquarium measures 100 CM x 60 CM x40 CM. Rita aquarium measures 120cm x50 Cm x 35 CM. Whose aquarium has larger volume and by how much?
Answer» ANSWER: Sneha's aquarium has larger volume and by 30000 cc much Step-by-step EXPLANATION: let, length of Sneha's aquarium = 100 cm breadth = 60 cm height = 40 cm volume of Sneha's aquarium is 100 × 60 × 40 cc = 240000 cc again, let, length of Rita's aquarium = 120 cm breadth = 50 cm height = 35 cm volume of Rita's aquarium is 120 × 50 × 35 cc = 210000 cc difference of volume = 240000 - 210000 cc = 30000 cc

20.

Sneha's aquarium measures 100 CM x 60 CM x40 CM. Rita aquarium measures 120cm x50 Cm x 35 CM. Whose aquarium has larger volume and by how much?

Answer»

ANSWER:

Sneha's aquarium has larger volume and by 30000 cc much

Step-by-step EXPLANATION:

let, length of Sneha's aquarium = 100 cm

breadth = 60 cm

height = 40 cm

volume of Sneha's aquarium is 100 × 60 × 40 cc

= 240000 cc

again,

let, length of Rita's aquarium = 120 cm

breadth = 50 cm

height = 35 cm

volume of Rita's aquarium is 120 × 50 × 35 cc

= 210000 cc

difference of volume = 240000 - 210000 cc

= 30000 cc

Discussion

21.	Find the discriminant of the quadratic equation 2x²+x-4 is
Answer» Step-by-step EXPLANATION: its DISCRIMINANT is -31

21.

Find the discriminant of the quadratic equation 2x²+x-4 is

Answer»

Step-by-step EXPLANATION:

its DISCRIMINANT is -31

Discussion

22.	The length of rectangle is 5 cm less than twice its breadth if parimeter of it is 80 find area
Answer» Answer: Area of rectangle is 375cm^2 Step-by-step explanation: Let the perimeter given is in cm unit. Let the length and BREADTH of rectangle be l and b respectively. Then according to the QUESTION l = 2B - 5..........(1) Given perimeter = 80 cm........(2) We KNOW that perimeter of rectangle is 2(l + b)........(3) Equate (2) and (3) we get 2(l + b) = 80 cm l + b = 40........(4) solve equation (1) and (4) We get l = 25 cm and b = 15 cm. Area of rectangle = l x b = 375 cm^2. Plz follow me on brainly and thankyou!!!!!

22.

The length of rectangle is 5 cm less than twice its breadth if parimeter of it is 80 find area

Answer»

Answer:

Area of rectangle is 375cm^2

Step-by-step explanation:

Let the perimeter given is in cm unit.

Let the length and BREADTH of rectangle be l and b respectively.

Then according to the QUESTION

l = 2B - 5..........(1)

Given perimeter = 80 cm........(2)

We KNOW that perimeter of rectangle is 2(l + b)........(3)

Equate (2) and (3) we get

2(l + b) = 80 cm

l + b = 40........(4)

solve equation (1) and (4)

We get l = 25 cm and b = 15 cm.

Area of rectangle = l x b = 375 cm^2.

Plz follow me on brainly and thankyou!!!!!

Discussion

23.	Cos theta.cosec theta - sin theta .sec theta/ cos theta + sin theta= cosec theta - sec theta
Answer» ANSWER: your answer ATTACHED in the PHOTO

23.

Cos theta.cosec theta - sin theta .sec theta/ cos theta + sin theta= cosec theta - sec theta

Answer»

ANSWER:

your answer ATTACHED in the PHOTO

Discussion

24.	A sum of rs1400 is to be used to give seven cash prizes to students if each prize is rs40 less than the preceding price find the value of each prize
Answer» Step-by-step EXPLANATION: it will FORM an A.P using SUM formula s=n/2(2A+(n-1)×d) 1400=7/2(2a+(7-1)×40) 1400×2/7=(2a+240) 400-240=2a a=80 the value of each prise is 80,120,160,200,240,280,320

24.

A sum of rs1400 is to be used to give seven cash prizes to students if each prize is rs40 less than the preceding price find the value of each prize

Answer»

Step-by-step EXPLANATION:

it will FORM an A.P

using SUM formula

s=n/2(2A+(n-1)×d)

1400=7/2(2a+(7-1)×40)

1400×2/7=(2a+240)

400-240=2a

a=80

the value of each prise is

80,120,160,200,240,280,320

Discussion

25.	Find the the largest number that will divide 632,729and 840 leaving remainders 3,9and1 respectively
Answer» ANSWER: it's not DEFINED because

25.

Find the the largest number that will divide 632,729and 840 leaving remainders 3,9and1 respectively

Answer»

ANSWER:

it's not DEFINED because

Discussion

26.	Sum of the multipes of 7 between 500 and1000
Answer» Answer: 71 Step-by-step EXPLANATION: a = 504 d = 7 tn= 994 first and last multiples of 7 from 500 to 1000 use FORMULA tn = a + (n-1) d

26.

Sum of the multipes of 7 between 500 and1000

Answer»

Answer:

71

Step-by-step EXPLANATION:

a = 504

d = 7

tn= 994

first and last multiples of 7 from 500 to 1000

use FORMULA

tn = a + (n-1) d

Discussion

27.	Which are the zero of p(x) = ( x-1)(x-2)
Answer» Step-by-step EXPLANATION: x=1 x=2 are the ZEROES of the POLYNOMIAL.

27.

Which are the zero of p(x) = ( x-1)(x-2)

Answer»

Step-by-step EXPLANATION:

x=1

x=2 are the ZEROES of the POLYNOMIAL.

Discussion

28.	An 8 sided fair dice is rolled twice and the product of the two numbers obtained when the dice is rolled two times is calculated
Answer» Answer: Step-by-step explanation: Since dice are identical so number of arrangements are POSSIBLE like 2,3,4,5,6,1 and 1,3,2,4,5,6 will be considered as same outcome. So number of possible outcome is simply the number of terms in the expansion of (x+x 2 +x 3 +x 4 +x 5 +x 6 ) n . That is n+6−1 C 6−1 The possible OUTCOMES after rolling n identical dice equivalent to n+5 C 5 Pls mark me as BRAINLIST

28.

An 8 sided fair dice is rolled twice and the product of the two numbers obtained when the dice is rolled two times is calculated

Answer»

Answer:

Step-by-step explanation:

Since dice are identical so number of arrangements are POSSIBLE like 2,3,4,5,6,1 and 1,3,2,4,5,6 will be considered as same outcome.

So number of possible outcome is simply the number of terms in the expansion of (x+x

2

+x

3

+x

4

+x

5

+x

6

)

n

.

That is

n+6−1

C

6−1

The possible OUTCOMES after rolling n identical dice equivalent to

n+5

C

5

Pls mark me as BRAINLIST

Discussion

29.	Which of the following number are divisible by 6 813
Answer» ANSWER: HELLO friend first of all you follow me second answer is 6813 is a prime NUMBER Step-by-step explanation: आगे तुम खुद समझ लो

29.

Which of the following number are divisible by 6 813

Answer»

ANSWER:

HELLO friend

first of all you follow me

second answer is

6813 is a prime NUMBER

Step-by-step explanation:

आगे तुम खुद समझ लो

Discussion

30.	If a = 3+ √5 3− √5 = 3− √5 3+ √5 , find a²- b²
Answer» Step-by-step EXPLANATION: I HOPES it HELP you❤️❤️

30.

If a = 3+ √5 3− √5 = 3− √5 3+ √5 , find a²- b²

Answer»

Step-by-step EXPLANATION:

I HOPES it HELP you❤️❤️

Discussion

31.	Solve for x ,54=√54x(15+x)
Answer» ANSWER: sorry I can't UNDERSTAND the QUESTION of yhbncnvxgghkgjgjgjggddghfhcjghkkhhfhfhfhf Step-by-step explanation: rufugmggmchhtsshccjggkgkhcfigkifiguffifififoifoffigigiuf

31.

Solve for x ,54=√54x(15+x)

Answer»

ANSWER:

sorry I can't UNDERSTAND the QUESTION of yhbncnvxgghkgjgjgjggddghfhcjghkkhhfhfhfhf

Step-by-step explanation:

rufugmggmchhtsshccjggkgkhcfigkifiguffifififoifoffigigiuf

Discussion

32.	Solve each of the following pairs of linear equations crossmultiplication method :i)5x- 6y+ 30 = 0 5x +4y - 20 = 0 (ii) 3x- 4y+ 6 = 0 3x+ y - 9 = 0
Answer» ANSWER: I) X = 12, y = -5. ii) x = 2, y = -3. Step-by-step explanation: Step by step explanation is in the PICTURE

32.

Solve each of the following pairs of linear equations crossmultiplication method :i)5x- 6y+ 30 = 0 5x +4y - 20 = 0 (ii) 3x- 4y+ 6 = 0 3x+ y - 9 = 0

Answer»

ANSWER:

I) X = 12, y = -5.

ii) x = 2, y = -3.

Step-by-step explanation:

Step by step explanation is in the PICTURE

Discussion

33.	Project on the origin of integers,their need and usage in our daily life?
Answer» Real LIFE integers are USED to CHECK accounts: Two cases: If there are SUFFICIENT funds, it represents positive numbers. If money is overdrawn from the account, it represents negative numbers.

Discussion

34.	6 one by two-[5 one by two-[4one by two-[3one by two-2one by two-one by three
Answer» Answer: 6 ONE by two-[5 one by two-[ 4one by two-[3one by two-2one by two-one by three. LOG in to ADD COMMENT ...

34.

6 one by two-[5 one by two-[4one by two-[3one by two-2one by two-one by three

Answer»

Answer:

6 ONE by two-[5 one by two-[ 4one by two-[3one by two-2one by two-one by three. LOG in to ADD COMMENT ...

Discussion

35.	, if a b c d are in continued proportion then prove that B minus C whole square + c minus a whole square + d minus b whole square is equals to a minus d whole square
Answer» ANSWER: d-a the WHOLE square Step-by-step EXPLANATION:

35.

, if a b c d are in continued proportion then prove that B minus C whole square + c minus a whole square + d minus b whole square is equals to a minus d whole square

Answer»

ANSWER:

d-a the WHOLE square

Step-by-step EXPLANATION:

Discussion

36.	(2/3)to the power of -2 * (3/2)to the power of 3
Answer» Answer: 2/3^–2×3/2^–3 (3/2)²×(3/2)^–3 since base are Same do the EXPONENT will be added (3/2)^2+(–3) 3/2^2–3 3/2^–1 Step-by-step explanation: MARK me as brainliest and FOLLOW me

36.

(2/3)to the power of -2 * (3/2)to the power of 3

Answer»

Answer:

2/3^–2×3/2^–3

(3/2)²×(3/2)^–3

since base are Same do the EXPONENT will be added

(3/2)^2+(–3)

3/2^2–3

3/2^–1

Step-by-step explanation:

MARK me as brainliest and FOLLOW me

Discussion

37.	The rational number on the number line 1.345
Answer» Step-by-step EXPLANATION: PLS MARK as the BRAINLEST

37.

The rational number on the number line 1.345

Answer»

Step-by-step EXPLANATION:

PLS MARK as the BRAINLEST

Discussion

38.	A student multiplied 98456 by 54 instead of multiplying by 45 how much was his answer greater than the correct answer step by step
Answer» Step-by-step explanation: 98456×54=5316624 98456×45=4430520 then SUBTRACT these ANSWERS then you will GET your ANSWER

38.

A student multiplied 98456 by 54 instead of multiplying by 45 how much was his answer greater than the correct answer step by step

Answer»

Step-by-step explanation:

98456×54=5316624

98456×45=4430520

then SUBTRACT these ANSWERS then you will GET your ANSWER

Discussion

39.	How is this question equal 6-9=3
Answer» 6-9= -3 6-9=\|-3\| =3 Any NUMBER WITHIN this (\| \|) is TAKEN as absolute value. So,-3 absolute value is 3 Hence ,\|-3\|=3

39.

How is this question equal 6-9=3

Answer»

6-9= -3

6-9=|-3|

=3

Any NUMBER WITHIN this (| |) is TAKEN as absolute value.

So,-3 absolute value is 3

Hence ,|-3|=3

Discussion

40.	Solve the quadratics equation by completing Square7x² - 10x + 3 = 0
Answer» ANSWER: gm☺❤ 7x²-10x+3=0 7x²-(7+3)x+3=0 7x²-7x-3x+3=0 7x(x-1)-3(x-1)=0 (x-1) (7x-3)=0 : .(x-1) =0 or , ( 7x-3) =0 x=1 x=3/7 hope it's HELPFUL ❣

40.

Solve the quadratics equation by completing Square7x² - 10x + 3 = 0

Answer»

ANSWER:

gm☺❤

7x²-10x+3=0

7x²-(7+3)x+3=0

7x²-7x-3x+3=0

7x(x-1)-3(x-1)=0

(x-1) (7x-3)=0

: .(x-1) =0 or , ( 7x-3) =0

x=1 x=3/7

hope it's HELPFUL ❣

Discussion

41.	Determine which is greater -1/5or 1/5
Answer» ANSWER: Answer : -1/5 or 1/5 1/5 is GREATER

41.

Determine which is greater -1/5or 1/5

Answer»

ANSWER:

Answer : -1/5 or 1/5

1/5 is GREATER

Discussion

42.	Consider the sequence 1, 3, 5, 7... can the sum of any two terms of the sequence 75?
Answer» Step-by-step explanation: since all the terms are ODD in the sequence and the sum of any 2 odd numbers is always even so the sum of any two terms in the GIVEN sequence can never be odd. As 75 is ALSO odd so the sum of any two terms of the sequence can never be 75

42.

Consider the sequence 1, 3, 5, 7... can the sum of any two terms of the sequence 75?

Answer»

Step-by-step explanation:

since all the terms are ODD in the sequence and the sum of any 2 odd numbers is always even so the sum of any two terms in the GIVEN sequence can never be odd. As 75 is ALSO odd so the sum of any two terms of the sequence can never be 75

Discussion

43.	4√5 3√2 3√5 + 5√2 simlify
Answer» Answer: 11 Step-by-step EXPLANATION: (4√5-3√2)(3√5+5√2) =4√5(3√5+5√2)-3√2(3√5+5√2) =12×5+20√10-9√10-15√4 =60+20√10-9√10-15×2 =60+20√10-9√10-60 =60-60+20√10-9√10 =20√10-9√10 =11

43.

4√5 3√2 3√5 + 5√2 simlify

Answer»

Answer:

11

Step-by-step EXPLANATION:

(4√5-3√2)(3√5+5√2)

=4√5(3√5+5√2)-3√2(3√5+5√2)

=12×5+20√10-9√10-15√4

=60+20√10-9√10-15×2

=60+20√10-9√10-60

=60-60+20√10-9√10

=20√10-9√10

=11

Discussion

44.	Show that 0.279 bar in the form p/a
Answer» Answer: 31/111 Step-by-step EXPLANATION: REFER to the IMAGE ATTACHED below

44.

Show that 0.279 bar in the form p/a

Answer»

Answer:

31/111

Step-by-step EXPLANATION:

REFER to the IMAGE ATTACHED below

Discussion

45.	Log1b x loga x log 3C=C=63a327
Answer» ANSWER: i DONOT no........................

45.

Log1b x loga x log 3C=C=63a327

Answer»

ANSWER:

i DONOT no........................

Discussion

46.	Please answer for this all questions please
Answer» Step-by-step EXPLANATION: PLS MARK as BRAINLIEST

46.

Please answer for this all questions please

Answer»

Step-by-step EXPLANATION:

PLS MARK as BRAINLIEST

Discussion

47.	Write a pair of points equidistant from point Q.
Answer» <P>1 ) D( Q,U ) = 1 , D( Q, L ) = 1 , Therefore , U and L points are equidistant from Q. ii ) d( Q, R ) = 2 , d( Q,P ) = 2 Therefore , P and R points are equidistant follow me please... MARK as BRAINLIEST please.... from Q .

47.

Write a pair of points equidistant from point Q.

Answer»

<P>1 ) D( Q,U ) = 1 ,

D( Q, L ) = 1 ,

Therefore ,

U and L points are equidistant

from Q.

ii ) d( Q, R ) = 2 ,

d( Q,P ) = 2

Therefore ,

P and R points are equidistant

follow me please...

MARK as BRAINLIEST please....

from Q .

Discussion

48.	Is my answer correct???
Answer» 1 . 5/6 < 8/9 L.C.M = 18 5/6= 5×3=15 6×3= 18 8/9= 8×2=16 9×2=18 15/18 < 16/18 So , FIRST ONE is CORRECT .✌ 2.

48.

Is my answer correct???

Answer»

1 .

5/6 < 8/9

L.C.M = 18

5/6= 5×3=15

6×3= 18

8/9= 8×2=16

9×2=18

15/18 < 16/18

So , FIRST ONE is CORRECT .✌

2.

Discussion

49.	What percent of 2liters is 250ml?
Answer» Answer: 12.5 Step-by-step EXPLANATION: PLEASE MARK BRAINLIEST

49.

What percent of 2liters is 250ml?

Answer»

Answer:

12.5

Step-by-step EXPLANATION:

PLEASE MARK BRAINLIEST

Discussion

50.	3. In what ration does the point P on x axis divides the line segment joining the point A(32)and B(4,-1). Also find coordinates of PP
Answer» ggsjdjhfbdvbdnhgfdsa

Discussion

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Project on the origin of integers,their need and usage in our daily life?

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, if a b c d are in continued proportion then prove that B minus C whole square + c minus a whole square + d minus b whole square is equals to a minus d whole square

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A student multiplied 98456 by 54 instead of multiplying by 45 how much was his answer greater than the correct answer step by step

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Solve the quadratics equation by completing Square7x² - 10x + 3 = 0​

gm☺❤

hope it's HELPFUL ❣

Determine which is greater -1/5or 1/5

Consider the sequence 1, 3, 5, 7... can the sum of any two terms of the sequence 75?

4√5 3√2 3√5 + 5√2 simlify

Show that 0.279 bar in the form p/a

Log1b x loga x log 3C=C=63a327​

Please answer for this all questions please ​

Write a pair of points equidistant from point Q.​

Is my answer correct???​

So , FIRST ONE is CORRECT .✌

What percent of 2liters is 250ml? ​

PLEASE MARK BRAINLIEST

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Covert 50.3 % to marks

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Find the value please do it fast

Pls answer my question step by step

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Please solve the above questions

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Please answer for this all questions please

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Is my answer correct???

What percent of 2liters is 250ml?

3. In what ration does the point P on x axis divides the line segment joining the point A(32)and B(4,-1). Also find coordinates of PP