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Using REMAINDER theorm
X+5=0
X=-5
PUTTING VALUE OF X
-5³+2×-5²-14×-5+9
-125+50+70+9
=4 ≠ 0

So it is not a factor

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The HCF of x^2-4 and x^2+16 is 2.

"Relationship between zeros and coefficients of a quadratic polynomial" is the stuff which is much required to the STUDENTS who study high school math .

To understand "relationship between zeros and coefficients of a quadratic polynomial", LET US consider the quadratic polynomial.

P(x) = ax² + bx + C

(Here a, b and c are real and rational numbers)

Let "α" and "β" be the two zeros of the above quadratic polynomial

The basic relationships between the zeros and the coefficients of P(x) = ax² + bx + c are

(3/7*1/6) -(5/3*-1/7)+(3/7*9/2)

cancellation of 6 with 3 and '-' × '-' = +

(1/7*1/2) +(5/21) +(27/14)

(1/14) + (5/21) + (27/14)

TAKE L.C.M of 14,21,14
7|14,21,14
-|________
2| 2,3,2
-|________
3| 1,3,1
_______
1,1,1

LCM = 7*2*3 =42

3(1) +2(5) +3(27)
____________.
42

= 3 +10 +81 /42

= 94/42 =47/21

Hey mate! I hope my answer will help you!
The main DIFFERENCE between a pyramid and prism is the fact that a prism has two bases, while the pyramid only has one. A pyramid is a three-dimensional polyhedron. ... The base is CONNECTED to the sides or faces of the pyramid. The sides of the pyramid will always be triangular in shape.
Actually, A triangular pyramid is a geometric solid with a base that is a triangle and all other faces are triangles with a common vertex. 
The prism is different than the pyramid in that it does not have an APEX. Instead, it can be said that it has two bases. The bases are joined together by the sides. A WAY to differentiate the prism is to check whether the cross section of the prism is the same all ALONG its length.
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A= 5+B
b=10+c
so a=15+c

a+b+c=40
15+c+10+c+c=40
3c=15
c=5

so b= 15 YEARS

After 19 MONTHS he will JOIN

62.5 %. because NEW d= 1.6×2/3 x1.5 of B

-339= 5
5+7= -339+9
=-330
this should be UR ANS.

The VOTE for A is 38400
the vote for B is 9600
the TOTAL vote 48000

Like if we PUT almirah on FLOOR permanently then sometimes we put a brick under each of the leg.



◇If equals are ADDED to equals the WHOLES are equal

GIVEN :  average of X+1/x be 1

To Find : value of x^10 +1/x^100

Solution:

Average of x + 1/x  = 1

=> (x  + 1/x) /2 = 1

=> (x  + 1/x)  = 2

=> x² + 1 = 2X

=> x² - 2x + 1 = 0

=> (x - 1)² = 0

=> x =  1

x¹⁰  +  1/x¹⁰⁰  =  1¹⁰  + 1/1¹⁰⁰  = 1 + 1  = 2

Learn More:

solve x/x-1 +x-1/x=5/2

brainly.in/question/1258937

if x=1/4-x, find : x+1/x - Brainly.in

brainly.in/question/5639594

If 37 square is added to the square of a NUMBER the ANSWER OBTAINED is 3970

let the number be x

so, 37² + x² = 3970
x² = 3970 - 1369
x² = 2601
x² = 51²
x = 51

What do you WANT to KNOW! PLEASE ASK CORRECTLY!

X^2-(X+1)(X+2)=30x+6
x^2-(x^2+2x+X+2)=30x+6
x^2-x^2-2x-x-2=30x+6
-3x-2=30x+6
-8=33x
X=-8/33

4,286 is the answer
Hope it HELPS.

The income of a man is increased in the ratio 10:11
old income of a man is 10x
new income of the man is 11x


If the INCREASE in his income is RS 600 per month

It is an ACUTE ANGLE and it LOOKS LIKE how it in that PIC...

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Let total no. of 10 RUPEE NOTES be 2x
then 20rupee note be 3X
so total no.of notes are 2x + 3x = 5x
5x = 1600
=> x = 1600/5
=> x = 320
no.of 10 rupee notes= 2*320= 640 so 64notes
no.of 20 rupee notes = 3*320=960 so 48 notes
hence total notes are 64 + 48 = 112

Given data :-

• The distance between two towns is 300km.
• Two cars start simultaneously from these towns and move toward each other.
• The Speed of one car is more than other by 7km/hr.
• The distance between the cars after 2hrs is 34km. { reamain }

Solution :-

Let, first car be A and second car be B

Let, speed of car B = x KM/hr .....( 1 )

Hence, according to given

{The Speed of one car is more than other by 7 km/hr.}

→ Speed of A = {x + 7} km/hr .....( 2 )

The distance between the cars after 2hrs is 34 km. hence,

→ Total distance travel by A and B before 2 hour = {300 - 34 } km

→ Total distance travel by A and B before 2 hour = 266 km .....( 3 )

→ Total time taken by A and B to cover 293 km = 2 hour .....( 4 )

Now, we use formula of relative speed

→ Relative speed of A and B

= {Total speed}/{Total time}

[from ( 1 ), ( 2 ), ( 3 ) & ( 4 )]

→ x + x + 14 = 266/2

→ 2x + 7 = 133

→ 2x = 133 - 7

→ 2x = 126

→ x = 126/2

→ x = 63 km/hr

Hence, speed of B is 63 km/hr.

Put VALUE of x in eq. ( 2 )

→ Speed of A = x + 7

→ Speed of A = 63 + 7

→ Speed of A = 70 km/hr

Hence, speed of A is 70 km/hr.

Hence, speed of A and B is 70 km/hr and 63 km/hr respectively.

The difference of SIMPLE and COMPOUND intrest of 2 year will be RS4

HII...

ACCORDING to me

Q 11.

∠BOC = 120°

Hey

Here is your answer,

X = 2
Y = 5
X^2 + 2 √y = (2)^2 + 2√5
= 4+2√5
= 2 ( 2+√5)

HOPE it HELPS you!

0 because you SAY that you have 1000 fish you do not say how MANY fish in LAKE

I guess........ VOLUNTARY MIGRATION is migrating regularly at regular intervals of TIME to FIND a more better place to live...................... hope it helps

Let us ASSUME the angle to be 'a'.

The Complement of a is GIVEN by = 90 - a

The Difference Between Both The ANGLES That Is Given In The Question

= 12

Calculating The Difference:

=> (90 - a ) - a = 12

Opening the bracket:

=> 90 - a - a = 12

=> 90 - 2a = 12

Taking 90 to the other side of the equation we get:

=> - 2a = 12 - 90

=> - 2a = - 78

Taking - 2 to the other side of the equation we get:

=> a = - 78 / - 2

=> a = 39

(When we divide a negative NUMBER by a negative number the result we obtain will always be positive)

THEREFORE, we obtain the value of 'a' as 39.

Therefore, the first complimentary angle is 39° as we assumed the first complimentary angle as 'a'.

Calculating the value of the second complimentary angle:

= 90 - a

= 90 - 39

= 51°

Therefore, the value of the second complimentary angle is 51°.

This is UR ANSWER.....
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-2*

First rationalize both X and y then write LIKE ( x+ y)(x- y) u will GET the result

Curved surface area of CYLINDER is 2πrh

r = 10.5 cm

CSA = 1320

2 x 22/7 x 10.5 x H = 1320

h = (1320 * 7) / (2 * 10.5 * 22) = 20

h = 20

Your SOLUTION..........

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DAUGHTER's age (D) is 5 years.

Ratio of age of First son: Daughter = 3:1

So age of First son (S1) = 3*5 = 15 Years

Age of Second son (S2) is 2/3 times First son,

S2 = (2/3) * S1

S2 = (2/3) * 15

S2 = 2 * 5

S2 = 10

Age of Second son (S2) = 10 Years.

Age of the Father (F) is 4 times the age of Second son (S2),

F = 4 * S2

F = 4 * 10

F = 40

Age of the Father (F) = 40 Years.

Age of the MOTHER (M) is 3.5 times older than Second son (S2)

M = 3.5 * S2

M = 3.5 * 10

M = 35

Age of the Mother (M) = 35 Years.

Sum of all ages = D + S1 + S2 + F + M

= 5 + 15 + 10 + 40 + 35

= 105 Years

Total = 105 Years

VOLUME of the wax block is :

60 × 35 × 22 = 46200cm³

Volume of one candle :

VOL :

22/7 × 3.5² × 4 = 154 cm³

The number of candles will be :

46200 / 154 = 300

300 candles

Their is the ANSWER.......

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