This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Is investing in share profitable or a risk |
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Answer» Share MEANS which TYPES.. |
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| 2. |
Prove that every bounded monotonic sequence is convergent |
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Answer» If for all natural numbers j and k, aj,k is a non-negative real number and aj,k ≤ aj+1,k, then[2]:168 lim j → ∞ ∑ k a j , k = ∑ k lim j → ∞ a j , k . {\displaystyle \lim _{j\to \infty }\sum _{k}a_{j,k}=\sum _{k}\lim _{j\to \infty }a_{j,k}.} The theorem states that if you have an infinite matrix of non-negative real numbers such that the COLUMNS are weakly increasing and bounded, and for each row, the series whose terms are given by this row has a convergent sum, then the limit of the sums of the rows is equal to the sum of the series whose term k is given by the limit of column k (which is also its SUPREMUM). The series has a convergent sum if and only if the (weakly increasing) sequence of row sums is bounded and THEREFORE convergent. As an example, consider the infinite series of rows ( 1 + 1 N ) n = ∑ k = 0 n ( n k ) / n k = ∑ k = 0 n 1 k ! × n n × n − 1 n × ⋯ × n − k + 1 n , {\displaystyle \left(1+{\frac {1}{n}}\right)^{n}=\sum _{k=0}^{n}{\binom {n}{k}}/n^{k}=\sum _{k=0}^{n}{\frac {1}{k!}}\times {\frac {n}{n}}\times {\frac {n-1}{n}}\times \cdots \times {\frac {n-k+1}{n}},} where n approaches infinity (the limit of this series is e). Here the matrix entry in row n and column k is ( n k ) / n k = 1 k ! × n n × n − 1 n × ⋯ × n − k + 1 n ; {\displaystyle {\binom {n}{k}}/n^{k}={\frac {1}{k!}}\times {\frac {n}{n}}\times {\frac {n-1}{n}}\times \cdots \times {\frac {n-k+1}{n}};} the columns (fixed k) are indeed weakly increasing with n and bounded (by 1/k!), while the rows only have finitely many nonzero terms, so condition 2 is satisfied; the theorem now says that you can compute the limit of the row sums ( 1 + 1 / n ) n {\displaystyle (1+1/n)^{n}} by taking the sum of the column limits, namely 1 k ! {\displaystyle {\frac {1}{k!}}} . |
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| 3. |
Prove that product of 3 positive consecutive integers is divisible by 6 0 |
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Answer» Obtain all the ZEROS of the polynomial 2x4+x3-14x2-19x-6 if TWO of it ZEROES are -2 and 1 |
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| 4. |
Find the smallest number by which 1152 must be divided so that it becomes a perfect square.Also,find the number whose square is the resulting number |
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Answer» 1152= 2×2×2×2×2×2×2×3×3 |
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| 6. |
5^5/9 % = ?please solve it. |
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Answer» HIII friend____✌️✌️✌️✌️ good evening___ here's your answer 5^(5/9) % = 2.4452 * 100 = 244.52 |
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| 7. |
Ramu can do a work in 10 days and shamu can do that work in 15 days |
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| 8. |
What is the summation of infinity????? |
| Answer» DIVERGES to INFINITY. Or, to put it more loosely, that the SUM is equal to infinity. converges to a FINITE VALUE as long as the power is a number greater than . For every , the expression has a well-defined, finite value. | |
| 9. |
Pls answer it fast............i will mark it as brainliestIf 49x²-b²=(7x+1/2)(7x-1/2) find the value of b |
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Answer» HIII friend_____✌️✌️✌️✌️ 49x^2 - B^2 = 49x^2 - 1/4 use this PROPERTY _____ (a+b)(a-b) = a^2 - b^2 then b^2 = 1/4 b = 1/2 & b = -1/2 |
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| 10. |
How to calculate smallest 5 digit no. which is exactly divisible by 7,12,15,16 |
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| 11. |
A new computer costs rupees 60000.The depreciation is 40% every year.Find the price of the computer after two years |
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Answer» Depreciation VALUE for 1ST year = 60000 - 40% of 60000 = 60000 - 24000 = 36000 depreciation value for 2nd year = 36000 - 40% of 36000 = 36000 - 14400 = 21600 computer price will be 21600 after 2 YEARS |
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| 12. |
Paul and peter can do a piece of work in 60 days, while paul can do it alone in 80 days. how many days will peter take to complete the work alone? |
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Answer» Paul and peter TOGETHER can do it in 60 DAYS, 1 day work = 1/60 Paul can do it in 80 days, 1 day work = 1/80 1 day work of peter = 1/60 - 1/80 = (4-3) / 240 = 1 / 240 Peter will take 240 days
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| 13. |
A player tosses 3 fair coins. he wins rs 5 if three heads appear |
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Answer» Sample space S={HHH, HHT , HTH , THH , TTT , TTH , THT, HTT} |
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| 14. |
Prove that 2^n can be expressed as sum of two consecutive numbers |
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Answer» Integers starting with n is kn+k(k−1)2 so if mcan be written in this form, then 2m=k(2n+k−1). If m is a power of 2, then both k and 2n+k−1 MUST be powers of two, but they have DIFFERENT PARITIES, so ONE of them must be 1. Presumably, k>1, so 2n+k−1=1 or 2n+k=2. Since k≥2, this MEANS that n≤0. |
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| 15. |
Prove that sinx^6 + cosx^6 + 3cosx^2+ sinx^2/( 1+ tan²x)(1-sin²x) = 1 |
| Answer» ARYAN. PVT......LTD....... | |
| 16. |
Evaluate :sin(nπ+(−1)nπ4) where n is an integer, |
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Answer» If n=1 then sin(PI/2)=1 |
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| 17. |
21 or 25 question please solve it |
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Answer» No more SPACE for reasoning...Hope you get the solution and trig. identitties...I also hope for good solution better than MINE..i just tried...N i FOUND solution in this WAY. . |
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| 18. |
If a,b,c are i A.P and G.P prove a=b=c |
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Answer» Hey i have PDF but here is no option for pdf can i SEND SOMEWHERE ELSE |
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| 19. |
63.63 = m{21+(n/100)} |
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Answer» 1 |
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| 20. |
In the given figure , AB||CD.prove that p+q-r=180 Plz solve it so important p,lz ....... |
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Answer» This is your ANSWER........ |
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| 21. |
Is calculator permitted for icse 2017 math exam? |
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| 22. |
Why children wasting time on Internet and any website |
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Answer» Because childrens are INTRESTED in mobile GAMES and even parents are ALSO playing in mobiles and internet. even now TEACHERS are giving hw and they SEARCH internet. |
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| 23. |
In a pie chart two or more central angles can be equal. |
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Answer» They can be EQUAL or not |
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| 24. |
One side of a right angle triangle is 2 centimetre then the other and to centimetre less than the hypotenuse how long are the three sides |
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Answer» LET the one side be x Then other side is x-2 and the hypotenuse is x+2 Then by PYTHAGORAS THEOREM,we have X=8 X-2=6 and X+2 =10 So the sides of the triangle are 6cm,8cm and 10cm. |
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| 25. |
3 of phone numbers have a sum of 22, if average of 4 numbers is 8, what is the 4th number |
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Answer» average of 4 numbers = 8 sum of 4 numbers = 8 x 4 = 32 4th NUMBER is sum of 4 numbers - sum of 3 numbers = 32 - 22 = 10 4th number = 10 |
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| 26. |
3/5 of cistern is filled in 1minute how much more time will be required to fill the of it |
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Answer» LET time required = x 3/5 of x = 60 3x/5 = 60 3x = 300 x = 300/3 x = 100 seconds i.e. 1 minute 40 seconds will be required time to fill the cistern |
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| 27. |
Product of zeros of polynomial (ax²-6x-6) is 6, find the valur of a |
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Answer» PRODUCT of ZEROES of a quadratic POLYNOMIAL = c/a ATQ, 6=c/a 6=-6/a a=-1 So a turns out to be -1 |
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| 28. |
What is the lateral surface area of a cube of side 5cm |
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Answer» LSA of a SQUARE = 4a^2 = 4×5^2 =4×25 =100 HOPE IT HELPS YOU |
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| 30. |
कोडे सोडवा पाहु कोण लवकर उत्तर देतो 100 रुपयात 100 प्राणी घेऊन दाखवा 3 रुपयाला 1 घोडा 5 रुपयाला 1 हत्ती आणि 1 रुपयाला 2 उंट अट- प्रत्येक प्राणी घ्यावाच लागेल. |
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Answer» I2i2ii2i2iiwiqiqoqowjwjwijekqkaska |
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| 33. |
Find four consecutive term ina.p whose sum is 12 qn |
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Answer» LET the four CONSECUTIVE terms in an A.P. be a – 3d, a – d, a + d, a + 3d As per the first condition, a – 3d + a – d + a + d + a + 3d = 12 ∴ 4a = 12 ∴ a = 12/4 ∴ a = 3 ...........eq. (i) As per the second condition, a + d + a + 3d = 14 ∴ 2a + 4D = 14 ∴ 2 (3) + 4d = 14 [From eq. (i)] ∴ 6 + 4d = 14 ∴ 4d = 14 – 6 ∴ 4d = 8 ∴ d = 8/4 ∴ d = 2 ∴ a – 3d = 3 – 3 (2) = 3 – 6 = – 3 a – d = 3 – 2 = 1 a + d = 3 + 2 = 5 a + 3d = 3 + 3 (2) = 9 ∴ The four consecutive terms of A.P. are – 3, 1, 5 and 9 |
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| 34. |
A manufacturer sold an article at 18% gain wholeseller sold it to retailer at 20% gain retailer sold it 25% gain to customer if cutomer paid 30.09 rupees find the cost price to manufacturer |
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Answer» Given, Manufacturer To Wholesaller Gain % = P1% = 18% WHOLESELLER To Retailer Gain % = P2% = 20% Retailer to Customer Gain % = P3% = 25% Retailer Selling PRICE = RS. 30.09 Retailer to Customer CP = (SP*100)/(100+P3%) CP = 3009/125 CP of Retailer = Rs24.072 Wholeseller To Retailer SP of Wholeseller = Rs. 24.072 CP = (SP*100)/(100+P2%) CP = 2407.2/120 CP of Wholeseller = Rs. 20.06 Manufacturer To Wholesaller SP of Manufacturer = Rs. 20.06 CP = (SP*100)/(100+P1%) CP = 2006/118 CP of Manufacturer = Rs. 17 The Cost Price of the Manufacturer = Rs. 17 |
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| 35. |
2 numbers ratio 7:9.if 12 subtracted from each of them then ratio 3:5 the small no what |
| Answer» HEY FRIEND your ANSWER | |
| 36. |
N^3+3n^2+5n+3 is divisible by 3 mathematical induction n(n+1)(n+2) |
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Answer» N^3 + 3N^2 + 5N + 3 |
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| 37. |
Numerical value of sin 12 degree into sin 48 degree into sin 54 degree equals to |
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Answer» SIN 12 X sin 48 x sin 54 = 0.125 |
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| 38. |
a passenger train running at 60 km/hr leaves the railway station 5 hours after a goods train had left and overtakes it in 4 hours. what is the speed of the goods train? |
| Answer» 60*5 = X * (5+4) » x = 300/9= 80/3= 26.67 KMPH | |
| 39. |
Probability examples of cards in hindi 1 rbse |
| Answer» PROBABILITY =no of EXAMPLES /TOTAL no. | |
| 40. |
The number of process completed per unit time is known as |
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Answer» FREQUENCY if REGARDED to Sound Velocity if regarded to DISTANCE and SPEED |
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| 41. |
Primeter of a rectanglar plot is 156m and breath is 34 m find its area |
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Answer» Perimeter of a RECTANGLE= 2(l+b) |
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| 42. |
(m+n)^−1×(m^−1+n^−1)=(mn)^−1Pls explain |
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Answer» (m+n)^−1×(m^−1+n^−1)=(MN)^−1 |
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| 43. |
5 + x/ 5-x - 5-x/ 5+x = 15/4Solve the following quadratic equation by factorisation |
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Answer» Step-by-step EXPLANATION: |
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| 44. |
Ratio And Proportion Examples give me no spam |
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Answer» FIRST Pic Is Of Proportion And Other One Is Ratio. If It Is RIGHT Plz.. Mark As BRAINLIEST.. |
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| 45. |
Identify a quadrilateral which has four sides of equal length and 4 right angles |
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Answer» It's SQUARE as SQUARES are QUADRILATERAL too |
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| 46. |
75cm:1m 25 cm and $10: $7..50 |
| Answer» HEY MATE here both UNITS are DIFFERENT... and what is the QUESTION.?? | |
| 47. |
For what value of know, the roots of the quadratic equation kx (x-2root5)+10=0 |
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Answer» Kx²-2√5kx+10=0 what can PROVE |
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| 49. |
P(x)=-x2-4x-5 graph |
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Answer» Xy0−51−82−93−84−5xy0-51-82-93-84-5 |
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| 50. |
PLS ANSWER THIS FAST...............I WILL MARK IT AS BRAINLIESTWrite three possible set of values for the dimensions of a cuboid whose volume is given by y³+8y²+17y+10,where y is a natural number |
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Answer» 1. (y+2)×(y+5)×{(y+1)(y+1)(y+1)} 2. {(y+2)×(y+1)}×(y+5)×{(y+1)×(y+1)} 3. {(y+2)×(y+1)}×{(y+5)×(y+1)} ×(y+1) |
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