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No there is no TRIANGLE LIKE this

6×3 = 18 ...the ONE PLACE DIGIT ..is. 8..

(1901 + 1902 + 1903+.....+1993) - (101 + 102 + 103+....+193)

= (1800+101 +1800+102 +1800+103 +....+ 1800+193) - (101 + 102 + 103+....+193)

= (1800 + 1800 + 1800+.....) 93 TIMES
= 1800 × 93 = 167400

-5/2 is the ANSWER of this QUESTION

I HOPE you UNDERSTAND this SOLUTION ☺️☺️

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Answer:

Step-by-step EXPLANATION:

DISTANCE TRAVELLED by each participants with a flag: 750m

Number of participants: 62

Total distance travelled by the participants:

750x62= 46,500m

46,500m = 46,500÷1000= 46.5 km

Therefore, Total distance travelled by the participants is 46.5 km

It is RULE by GOVERNMENT

Discount PERCENTAGE
=( Cost Price-Discount price )/cost price×100
= (840-714)/Cost price ×100= 66/840*100= 7.85%(APPROX.)

If a+b+c=0 then, a³+b³+c³=3abc
☺☺

Product of 783 x 896 = 701568

one s PLACE VALUE is 8.

hope it HELPS you

Its folded along its LENGTH so its length will be circumference of the base

2 πr = 44

πr = 22

22/7 r = 22

r = 7 CM

height = 20 cm

curved surface area of cylinder =2 πrh

= 2 X 22/7 × 7 × 20

= 880 square cm

area of top and base of cylinder = 2 π * r2

= 2 x 22/7 x 7 x 7

= 308 square cm

total surface area = 880 + 308 = 1188 cm sq

Uwwusx Yauvani a o MANISHA do SILICA

by USING HERON's FORMULA,

let a,b,c are the sides of TRIANGLE .

S = a+b+c / 2

area of triangle = √s (s-a)(s-b)(s-c)

hope it HELPS !!!

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Its very SIMPLE just analise the GIVEN CONDITION

Let the length of BASE be x.
let the length of altitude be y.
so hypotenuse is h=2+x
and another will be h=1+2y
now we have two equations and two variables
cal the ANS by using pythogorus THEOREM

10000000003125 when U DIVIDED by LONG DIVISION METHOD

Answer should be 4320

No of ways in which VOWELS are together = no of ways in which exactly two vowels are together + no of ways in which 3 vowels are together.

But if you just choose 2 vowels in 3C2 and consider it as a set , you will have this set, one remaining vowel and 4 other consonants.
If you rearrange these it ALSO covers set containgin 3 vowels together.
so you have 2 * 3C2 * 5! as invalid combinations

No of ways to arrange 7 LETTERS = 7! = 5040

Desired ways = 5040 - 2 * 3C2 * 5! = 4320

W/ WF x T

W is workdone

WF is workforce

T is TIME

W/15x8x20 = W/20x5xT

20x5xT = 15x8x20

T = 24 DAYS

the BIGGEST 5-digit NUMBER is

99999

It is the series of STEPS to FIND HCF of any NUMBERS...
a=b×q+r ,where 0≤rexample -
15,21
so,
21=15×1+6
15=6×2+3
6=3×2+0
so, HCF is 3

1-(i) We know that distance between the two points is given by:
= √[(x1 – x2)2 + (y1 – y2)2]

Distance between (2, 3) and (4, 1) is:

l =√ [(2 – 4)2 + (3 – 1)2]

= √[4 + 4]= √8

= √2

(ii) Distance between (-5, 7) and (-1, 3) is:

l = √[(-5 + 1)2 + (7 – 3)2]

= √[16 + 16] = √32

= 4√2

(iii) Distance between (a, b) and (-a, -b) is:

l = √[(a+ a)2 + (b+ b)2]

= √[2a + 2b] = √(4a2 + 4b2)

= 2√(a2 + b2)



2-Distance between (0, 0) and (36, 15) is:
l = [(36 – 0)2 + (15 – 0)2]1/2
= [1296 + 225]1/2 = (1521)1/2
= 39
Yes, we can find the distance between the given TOWNS A and B. Let us TAKE town A at origin POINT (0, 0)
Hence, town B will be at point (36, 15) with respect to town A
And, as calculated above, the distance between town A and B will be39 km

3-Assume points (1, 5), (2, 3), and ( - 2, - 11) representing the vertices A, B, and C of the given triangle respectively.
Let A (1, 5), B (2, 3) and C (-2, -11)

Now,

AB = √[(1 – 2)2 + (5 – 3)2]

= √5

BC = √[(2 + 2)2 + (3 + 11)2]

= √212

CA = √[(1+ 2)2 + (5+ 11)2]

= √265

Since, AB + BC ≠ CA

4-Let us assume that points (5, - 2), (6, 4), and (7, - 2) are representing the vertices A, B, and C of the given triangle respectively
AB = [(5- 6)2 + (-2- 4)2]1/2
= √1+36
= √37
BC = [(6- 7)2 + (4+ 2)2]1/2
= √1+36
= √37
CA = [(5- 7)2 + (-2+ 2)2]1/2
= √4+0
= 2
Therefore, AB = BC
As two sides are equal in length, therefore, ABCis an isosceles triangle

5-

N(n+1)/2=300
=>n(n+1)=300*2
=>n(n+1) = 600
=>n+1 = 600/n
=>n= 600/n -1
SOMETHING like this it will COME hope it helps

10 percent of 40 is 4 lites of WATER
now

5 LITRES of water more should be added

This is the ANSWER. L HOPE it will HELP you

The ANSWER is 5891.45

2x+3y=3
x=(3-3y)/2 ....(1)
putting value of x in ANOTHER EQUATION,we get
3(3-3y)/2 +7y =4
9-9y +14y =8
5y =-1
y=-1/5
putting value of y in any of the two
o equation,we can find x

Let the length be X+6 m and BREADTH be x m.
so area=260 m sq.
so x(x+6)=260
=>x^2 + 6x = 260
=>x^2 = 260- 6x
rest U can SOLVE

You can QUALIFY PAPER of G.A.T.E. if you are ABLE to do it.

I don't KNOW PLS SEND me a CLEAR pic

Is it right or wrong

Can you PLEASE SEND me PHOTO if it

Hi friend!

Shriya's AGE = X
Arjun's age= 2x

5 yrs ago,
Shriya=x-5
Arjun = 2x-5

It was THREE times of Shriya's age.
2x - 5 = 3(x - 5)
2x - 5 = 3x - 15
-5 + 15 = 3x - 2x
10 = x

Shriya's present age = 10 years
Arjun's present age = 2x = 2 * 10 = 20 years.

Hope that helped you, my friend.
And hope you FOUND my answer useful .

-3/7×10/10 = -30/70 -2/7×10/10 = -20/70
THEREFORE, THREE RATIONAL are: -21/70, -22/30 and -23/70

Let the breadth of RECTANGLE = x

LENGTH = (x + 6)

Given, AREA = 216 m²

A/q,

➡ x * ( x + 6 ) = 216

➡ x² + 6x = 216

➡ x² + 6x - 216 = 0

➡ 333222

➡ x² + 18x - 12x - 216 = 0

➡ x ( x + 18 ) - 12 ( x + 18 )

➡ ( x - 12 ) ( x + 18)

➡ x = 12 & x = -18

x is breadth of rectangle so it can not be -ve.

so,

Breadth =x = 12m

Length = x + 6 = 12 + 6 = 18m

Hope it will help you !!

The SP will be CP +profit
=1000+1000×10/100
=rs 1100

5/3-7/6+(3/3-2/3)
5/3-7/6+1/3
10/6-7/6+2/6
10/6-9/6
1/6
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