332354 + Interview Questions in Secondary School in Math

1.	14)find the value of k, if x= 0, y=k is a solution of the equation 5x- 3y = 0
Answer» Answer: 5(0)-3(k)=0 0-3k=0 k=0/-3 thereforek=0 Step-by-step explanation: i HOPE it HELPS U

1.

14)find the value of k, if x= 0, y=k is a solution of the equation 5x- 3y = 0

Answer»

Answer:

5(0)-3(k)=0

0-3k=0

k=0/-3

thereforek=0

Step-by-step explanation:

i HOPE it HELPS U

Discussion

2.	5×0.0821×423÷342×0.1
Answer» Step-by-step explanation: nth term of an A.P (an) = pn + Q To FIND: Common DIFFERENCE (d) Proof: We know that, an = a + (N – 1)d ⇒ pn + q = a + (n – 1)d [GIVEN] ⇒ pn + q – a = (n – 1)d

2.

5×0.0821×423÷342×0.1

Answer»

Step-by-step explanation:

nth term of an A.P (an) = pn + Q

To FIND: Common DIFFERENCE (d)

Proof: We know that,

an = a + (N – 1)d

⇒ pn + q = a + (n – 1)d [GIVEN]

⇒ pn + q – a = (n – 1)d

Discussion

3.	Simplify...Guve me the answer of this question...
Answer» Answer: 2×3y Step-by-step EXPLANATION: MARK me as BRAINILEST

3.

Simplify...Guve me the answer of this question...

Answer»

Answer:

2×3y

Step-by-step EXPLANATION:

MARK me as BRAINILEST

Discussion

4.	If x + 1/x = 5, find the values of each of the following:X(i) x2 +1/x2(ii) x4 +1/x4
Answer» ANSWER: X+1/x=5 squaring on both SIDES ( x+1/x) ^2 =5^2 x^2+(1/x) ^2+2(x) (1/x) =25 x2+1/x2=25-2 =23 nw again squaring x4 +1/x4 +2X21/x2=2323 x4+1/x4=529-2=527

4.

If x + 1/x = 5, find the values of each of the following:X(i) x2 +1/x2(ii) x4 +1/x4

Answer»

ANSWER:

X+1/x=5

squaring on both SIDES

( x+1/x) ^2 =5^2

x^2+(1/x) ^2+2(x) (1/x) =25

x2+1/x2=25-2

=23

nw again squaring

x4 +1/x4 +2X2*1/x2=23*23

x4+1/x4=529-2=527

Discussion

5.	Help me solve this maths problem !! please dont answer wrongfind the general solution
Answer» Answer: 0 Step-by-step explanation: sin TETA PLUS cos teta plus 1 =0 - 1 +1=0( sin teta +cos teta = -1) MARK me as the brainliest PLZ

5.

Help me solve this maths problem !! please dont answer wrongfind the general solution

Answer»

Answer:

0

Step-by-step explanation:

sin TETA PLUS cos teta plus 1 =0

- 1 +1=0( sin teta +cos teta = -1)

MARK me as the brainliest PLZ

Discussion

6.	Ø. If x= 3 sin 0 + 4 cos 0 and y=3 cos 0 - 4 sin 0 then prove that + y2 = 25x2 .
Answer» ANSWER: SEE TGE above ATTACHMENT

6.

Ø. If x= 3 sin 0 + 4 cos 0 and y=3 cos 0 - 4 sin 0 then prove that + y2 = 25x2 .

Answer»

ANSWER:

SEE TGE above ATTACHMENT

Discussion

7.	The distance between two places is 15km. If the map scale is 1:500000, find the distance between the places in centimeters drawn in the map.
Answer» Answer:HELLO FRIEND HAVE A SWEET GOOD NIGHT TO YOU Step-by-step explanation:

7.

The distance between two places is 15km. If the map scale is 1:500000, find the distance between the places in centimeters drawn in the map.

Answer»

Answer:HELLO FRIEND HAVE A SWEET GOOD NIGHT TO YOU

Step-by-step explanation:

Discussion

8.	THEPresent age of Ran and Rage aresame. if Ran's11 years ago was 21then what isPresent age Ragu.agea)11b) 21c)32d, 10
Answer» the ANSWER WOULD be 32. as 21+11=32

Discussion

9.	28. 23' term of an arithmetic sequence is 32 and its 35'h term is 104.a) What is its common difference?b) What is its first term?c) Is the difference of any two terms of this sequence be 90?d) Find the sum of the first 35 terms?
Answer» ${ \huge✯ \: { \underline{ \underline \red{ᴀɴsᴡᴇʀ }}} \: ✯ }$ ★ given → $a_{23} = 32 \\ \: \: a_{35} = 104$ ★ solution → a) what is its COMMON difference? we know that, $\boxed{\pink{\bold{a_{n} = a + (n - <klux>1</klux>)d}}}$ then, $\bold{a_{23} = 32 }\: \: { \tt\{here \: n = 23 \}} \: \: \: \: \\ \\ \implies \: 32 = a + (23- 1)d \: \: \: \: \\ \\ \implies \: 32 = a + 22d \: .......(i)$ and, $\bold{ a_{35} = 104} \: \: { \tt \{here \: n = 35 \}} \: \: \: \\ \\ \implies \: 104 = a + (35 - 1)d \: \: \: \: \: \: \\ \\ \implies \: 104 = a + 34d \: ........(ii)$ now we have two equations, 32 = a + 22d ......(i) 104 = a + 34d ......(ii) now, subtract eq.(i) from eq.(ii) ${ \tt➪ \: \: a + 34d - (a + 22d) = 104 - 32} \\ \\ { \tt➪ \: \: a + 34d - a + 22d = 72} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: \cancel{a} + 34d - \cancel{a} + 22d = 72} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: 34d - 22d = 72} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: 12d = 72} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: d = \frac{72}{12} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: { \boxed {\orange{ \bold{d =6} }}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$ so,common difference of the AP is 6 _________________________ b) what is its first term? from first part we get. common difference(d) = 6 now, put the value of d in eq.(i) $\bold{32 = a + 22d} \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: 32 = a + 22 \times 6} \\ \\ { \tt➪ \: \: 32 = a + 132} \: \: \: \: \: \\ \\ { \tt➪ \: \: a = 32 - 132} \: \: \: \: \\ \\ ➪ \: \boxed{ \orange{ \bold {\: a = - 100}}}\: \: \: \: \: \: \: \:$ so, first term of AP is -100 _________________________ c) is the difference of any two terms of this SEQUENCE be 90? we know that, common difference of this AP is 6 ${ \tt and \: \: \: \: \frac{90}{6} = 15 } \\$ so, difference of nth term and (n+15)TH term is 90 _______________________________ _______________________________ ✩ for verification ✩ ☞ let n = 1 , then n+15 = 16 from 2nd part we have, $a_{1} = - 100$ now we have to find 16th of this AP $\: \: \: \: \: \: \: \: \: \: a_{16} = a + (16 - 1)d \\ \\ \implies \: a_{16} = - 100 + 15 \times 6 \\ \\ \implies \: a_{16} = - 100 + 90 \: \: \: \: \: \: \: \\ \\ \implies \: a_{16} = - 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$ now, see difference between these two terms $\: \: \: \: \: \: \: \: \: a_{1} = - 100 \\ \: \: \: \: \: \: \: a _{16} = - 10 \\ \\ { \tt \: and }\: \: \: \: a_{16} - a_{1} \\ \\ \implies \: - 10 - ( - 100) \\ \\ \implies \: - 10 + 100 \: \: \: \: \: \: \: \\ \\ \implies \: 90 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$ hence, varified! _______________________________ _______________________________ so, we can say yes, here difference of nth term and (n+15)th term of this AP is 90 _________________________ d) find the SUM of the first 35 terms? we know that, $\boxed{ \pink{\bold{ s_{n} = \frac{n}{2} \{2a + (n - 1)d \}}}}$ and here, ・a = -100 ・d = 6 ・n = 35 $➪ \: \: s_{35} = \frac{35}{2} \{ 2 \times - 100 + (35 - 1)d\} \\ \\ ➪ \: \: s_{35} = \frac{35}{2} \{ - 200 + 34 \times 6 \} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: s_{35} = \frac{35}{2} \{ - 200 + 204\} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: s_{35} = \frac{35}{ \cancel{2}} \times \cancel{ 4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: s_{35} = 35 \times 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: \boxed{\orange{ \bold{ s_{35} = 70}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$ so, sum of first 35 terms of AP is 70 _________________________ hence, a) common difference = 6 b) first term = -100 c) yes, difference of nth term and (n+15)th term of this AP is 90 d) sum of first 35 terms is 70

9.

28. 23' term of an arithmetic sequence is 32 and its 35'h term is 104.a) What is its common difference?b) What is its first term?c) Is the difference of any two terms of this sequence be 90?d) Find the sum of the first 35 terms?

Answer»

${ \huge✯ \: { \underline{ \underline \red{ᴀɴsᴡᴇʀ }}} \: ✯ }$

★ given →

$a_{23} = 32 \\ \: \: a_{35} = 104$

★ solution →

a) what is its COMMON difference?

we know that,

$\boxed{\pink{\bold{a_{n} = a + (n - <klux>1</klux>)d}}}$

then,

$\bold{a_{23} = 32 }\: \: { \tt\{here \: n = 23 \}} \: \: \: \: \\ \\ \implies \: 32 = a + (23- 1)d \: \: \: \: \\ \\ \implies \: 32 = a + 22d \: .......(i)$

and,

$\bold{ a_{35} = 104} \: \: { \tt \{here \: n = 35 \}} \: \: \: \\ \\ \implies \: 104 = a + (35 - 1)d \: \: \: \: \: \: \\ \\ \implies \: 104 = a + 34d \: ........(ii)$

now we have two equations,

32 = a + 22d ......(i)

104 = a + 34d ......(ii)

now, subtract eq.(i) from eq.(ii)

${ \tt➪ \: \: a + 34d - (a + 22d) = 104 - 32} \\ \\ { \tt➪ \: \: a + 34d - a + 22d = 72} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: \cancel{a} + 34d - \cancel{a} + 22d = 72} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: 34d - 22d = 72} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: 12d = 72} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: d = \frac{72}{12} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: { \boxed {\orange{ \bold{d =6} }}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

so,common difference of the AP is 6

_________________________

b) what is its first term?

from first part we get.

common difference(d) = 6

now, put the value of d in eq.(i)

$\bold{32 = a + 22d} \: \: \: \: \: \: \: \: \: \\ \\ { \tt➪ \: \: 32 = a + 22 \times 6} \\ \\ { \tt➪ \: \: 32 = a + 132} \: \: \: \: \: \\ \\ { \tt➪ \: \: a = 32 - 132} \: \: \: \: \\ \\ ➪ \: \boxed{ \orange{ \bold {\: a = - 100}}}\: \: \: \: \: \: \: \:$

so, first term of AP is -100

_________________________

c) is the difference of any two terms of this SEQUENCE be 90?

we know that,

common difference of this AP is 6

${ \tt and \: \: \: \: \frac{90}{6} = 15 } \\$

so, difference of nth term and (n+15)TH term is 90

_______________________________

✩ for verification ✩

☞ let n = 1 , then n+15 = 16

from 2nd part we have,

$a_{1} = - 100$

now we have to find 16th of this AP

$\: \: \: \: \: \: \: \: \: \: a_{16} = a + (16 - 1)d \\ \\ \implies \: a_{16} = - 100 + 15 \times 6 \\ \\ \implies \: a_{16} = - 100 + 90 \: \: \: \: \: \: \: \\ \\ \implies \: a_{16} = - 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

now, see difference between these two terms

$\: \: \: \: \: \: \: \: \: a_{1} = - 100 \\ \: \: \: \: \: \: \: a _{16} = - 10 \\ \\ { \tt \: and }\: \: \: \: a_{16} - a_{1} \\ \\ \implies \: - 10 - ( - 100) \\ \\ \implies \: - 10 + 100 \: \: \: \: \: \: \: \\ \\ \implies \: 90 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

hence, varified!

_______________________________

so, we can say yes, here difference of nth term and (n+15)th term of this AP is 90

_________________________

d) find the SUM of the first 35 terms?

we know that,

$\boxed{ \pink{\bold{ s_{n} = \frac{n}{2} \{2a + (n - 1)d \}}}}$

and here,

・a = -100

・d = 6

・n = 35

$➪ \: \: s_{35} = \frac{35}{2} \{ 2 \times - 100 + (35 - 1)d\} \\ \\ ➪ \: \: s_{35} = \frac{35}{2} \{ - 200 + 34 \times 6 \} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: s_{35} = \frac{35}{2} \{ - 200 + 204\} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: s_{35} = \frac{35}{ \cancel{2}} \times \cancel{ 4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: s_{35} = 35 \times 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ ➪ \: \: \boxed{\orange{ \bold{ s_{35} = 70}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

so, sum of first 35 terms of AP is 70

_________________________

hence,

a) common difference = 6
b) first term = -100
c) yes, difference of nth term and (n+15)th term of this AP is 90
d) sum of first 35 terms is 70

Discussion

10.	Put the numbers in correct way to get answer 20
Answer» (I) 5+6+8+1 (II) 4+5+9+2 (II) 7+3+6+4

10.

Put the numbers in correct way to get answer 20

Answer»

(I) 5+6+8+1

(II) 4+5+9+2

(II) 7+3+6+4

Discussion

11.	write the first 3 multiples of the following numbers that are odd 1. 5 2. 11 3. 21 4. 31 5. 27 6. 45
Answer» Answer: 1.for making the text look coloured refer the below SYNTAX and ignore the dots [.tex]\red{the\:text\:appears\:in\:red}[./tex] RESULT \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex]{the\:text\:appears\:like\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for SHOWING the exponential value [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the SQUARE root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\boxed{thanx}} thanx follow me next

11.

write the first 3 multiples of the following numbers that are odd 1. 5 2. 11 3. 21 4. 31 5. 27 6. 45

Answer»

Answer:

1.for making the text look coloured refer the below SYNTAX and ignore the dots

[.tex]\red{the\:text\:appears\:in\:red}[./tex]

RESULT

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for SHOWING the exponential value

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the SQUARE root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{thanx}}

thanx

follow me next

Discussion

12.	Is 6487 a perfect cube if not by which smallest number should 64827 be divided so that question is a perfect cube
Answer» Answer: The SMALLEST NUMBER required to multiply 72 to make it a PERFECT CUBE is 3.

12.

Is 6487 a perfect cube if not by which smallest number should 64827 be divided so that question is a perfect cube

Answer»

Answer:

The SMALLEST NUMBER required to multiply 72 to make it a PERFECT CUBE is 3.

Discussion

13.	Hai good evening,can you please help me to solve maths problemclass:6please ,please
Answer» Step-by-step EXPLANATION: ckoujnpnoogbvvtgikh

13.

Hai good evening,can you please help me to solve maths problemclass:6please ,please

Answer»

Step-by-step EXPLANATION:

ckoujnpnoogbvvtgikh

Discussion

14.	7. Which one of the following is irrational?(a) 25.666....(b) 75,468(c) -9÷14(d) 4.5678....
Answer» ANSWER: OPTION is CORRECT -9÷14

14.

7. Which one of the following is irrational?(a) 25.666....(b) 75,468(c) -9÷14(d) 4.5678....

Answer»

ANSWER:

OPTION is CORRECT -9÷14

Discussion

15.	The sum of the sereies 1+3+5+7 will be
Answer» ANSWER: 16 Step-by-step EXPLANATION: Answer is sixteen 16

15.

The sum of the sereies 1+3+5+7 will be

Answer»

ANSWER:

16

Step-by-step EXPLANATION:

Answer is sixteen

16

Discussion

16.	Simplify -113+(-311) +(-117)
Answer» ANSWER: -113+(-311)+(-117) = -113-311-117 = -541

16.

Simplify -113+(-311) +(-117)

Answer»

ANSWER:

-113+(-311)+(-117)

= -113-311-117

= -541

Discussion

17.	ক)-15 এবং 6ঃ (6+5) এবং 11 এর মধ্যে >বা< বা=চিহ্ন বসাও
Answer» Answer: HIIII løòöl plz write in ENGLISH so I can HELP u

17.

ক)-15 এবং 6ঃ (6+5) এবং 11 এর মধ্যে >বা< বা=চিহ্ন বসাও

Answer»

Answer:

HIIII løòöl plz write in ENGLISH so I can HELP u

Discussion

18.	Find the Fourier sine and cosine series of the function f(x) = {x , 0 < x < 22 , 2 ≤ x < 4
Answer» Answer: 2 is the answer Step-by-step explanation: 2+5=⅞ and x=7-5=2

18.

Find the Fourier sine and cosine series of the function f(x) = {x , 0 < x < 22 , 2 ≤ x < 4

Answer»

Answer:

2 is the answer

Step-by-step explanation:

2+5=⅞ and x=7-5=2

Discussion

19.	Sin 3 a - 1 =0 find the value of a please I'm not getting this...
Answer» Answer: 30 Step-by-step EXPLANATION: sin3A=1 sin3A=sin90 3A=90 A=30∘ Now, cos2A1−tan2A = cos230˚1−tan230˚ = (23)21−(31)2 = 31−34 = 34−1 = 1 if you understood mark me brainliest...:)

19.

Sin 3 a - 1 =0 find the value of a please I'm not getting this...

Answer»

Answer:

30

Step-by-step EXPLANATION:

sin3A=1

sin3A=sin90

3A=90

A=30∘

Now,

cos2A1−tan2A

= cos230˚1−tan230˚

= (23)21−(31)2

= 31−34 = 34−1 = 1

if you understood mark me brainliest...:)

Discussion

20.	If +10 stands for 10 steps forward then what is the number that will represent 15 stepsbackward?
Answer» ANSWER: -15__________________________________________

20.

If +10 stands for 10 steps forward then what is the number that will represent 15 stepsbackward?

Answer»

ANSWER:

-15__________________________________________

Discussion

21.	6.Orlangeswere bought at 236 dozen andsold at the rate of oz 40 per 10. Find the profitor loss per cent.-
Answer» ANSWER: I don't KNOW the answer Step-by-step EXPLANATION: I'm SORRY

21.

6.Orlangeswere bought at 236 dozen andsold at the rate of oz 40 per 10. Find the profitor loss per cent.-

Answer»

ANSWER:

I don't KNOW the answer

Step-by-step EXPLANATION:

I'm SORRY

Discussion

22.	Order in descending order- 3.2, 2.2 , 9.2
Answer» ANSWER: DESCENDING ORDER : 9.2 , 3.2 , 2.2

22.

Order in descending order- 3.2, 2.2 , 9.2

Answer»

ANSWER:

DESCENDING ORDER : 9.2 , 3.2 , 2.2

Discussion

23.	The domain of 3^x is
Answer» ANSWER: DOMIAN of 3^X is (-∞,∞) x can TAKE all VALUES .

23.

The domain of 3^x is

Answer»

ANSWER:

DOMIAN of 3^X is (-∞,∞)

x can TAKE all VALUES .

Discussion

24.	If x=2/5 y = 3/2 find (x+y) ÷ (x-y)
Answer» ANSWER: your answer in that PIC.

24.

If x=2/5 y = 3/2 find (x+y) ÷ (x-y)

Answer»

ANSWER:

your answer in that PIC.

Discussion

25.	You bowled 8 games and the scoreswere: 118, 145, 118, 136, 149, 102, 119,and 171. Find the mode and range forthe data,Select one:a. Mode: none, range: 53b. Mode: none, range: 69c. Mode: 118, range: 53d. Mode: 118, range: 69
Answer» ANSWER: b ) MODE :NONE, range 69 .

25.

You bowled 8 games and the scoreswere: 118, 145, 118, 136, 149, 102, 119,and 171. Find the mode and range forthe data,Select one:a. Mode: none, range: 53b. Mode: none, range: 69c. Mode: 118, range: 53d. Mode: 118, range: 69

Answer»

ANSWER:

b ) MODE :NONE, range 69 .

Discussion

26.	In board examination of class 9 , 50•/• passed in english 30•/• failed in both subject If 25 student passed in both subject find the total number of student .
Answer» Answer: 50 Step-by-step EXPLANATION: No. of STUDENTS PASSED 50%=25 No. of students passed 30%=25 Total No. of students passed =50

26.

In board examination of class 9 , 50•/• passed in english 30•/• failed in both subject If 25 student passed in both subject find the total number of student .

Answer»

Answer:

50

Step-by-step EXPLANATION:

No. of STUDENTS PASSED 50%=25

No. of students passed 30%=25

Total No. of students passed =50

Discussion

27.	8.के प्रथम 24[BM 2020]समान्तर श्रेणी 5.8.11.14.......पदों का योग हैहै.(A)940(B) 960(C)948 (D) 944Y
Answer» Answer: 1.for MAKING the text look coloured refer the below syntax and ignore the DOTS [.tex]\red{the\:text\:appears\:in\:red}[./tex] result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex]{the\:text\:appears\:like\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the exponential value [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\boxed{THANX}} thanx follow me next

27.

8.के प्रथम 24[BM 2020]समान्तर श्रेणी 5.8.11.14.......पदों का योग हैहै.(A)940(B) 960(C)948 (D) 944Y

Answer»

Answer:

1.for MAKING the text look coloured refer the below syntax and ignore the DOTS

[.tex]\red{the\:text\:appears\:in\:red}[./tex]

result

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the exponential value

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{THANX}}

thanx

follow me next

Discussion

28.	Average age of 8 people in a group is 28 years. The average age of 6 people in this same group is 29 years. What is the average age of 2 people in the group
Answer» Step-by-step EXPLANATION: Assume x1, x2, x3, X4, x5, X6, x7, X8 as PEOPLE in the group

28.

Average age of 8 people in a group is 28 years. The average age of 6 people in this same group is 29 years. What is the average age of 2 people in the group

Answer»

Step-by-step EXPLANATION:

Assume x1, x2, x3, X4, x5, X6, x7, X8 as PEOPLE in the group

Discussion

29.	If q^2 is inversely proportional to p+3 and q=5 whenp=2, find the values of q when p = 17.
Answer» Answer: 1.for making the text LOOK coloured refer the below SYNTAX and ignore the dots [.tex]\red{the\:text\:appears\:in\:red}[./tex] RESULT \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex]{the\:text\:appears\:LIKE\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the exponential value [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\boxed{thanx}} thanx follow me NEXT

29.

If q^2 is inversely proportional to p+3 and q=5 whenp=2, find the values of q when p = 17.

Answer»

Answer:

1.for making the text LOOK coloured refer the below SYNTAX and ignore the dots

[.tex]\red{the\:text\:appears\:in\:red}[./tex]

RESULT

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:LIKE\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the exponential value

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{thanx}}

thanx

follow me NEXT

Discussion

30.	यदि एक समांतर श्रेढ़ी का nवाँ पद pn + q हो, तो इसका सार्व अंतर ज्ञात कीजिएIf the nth term of an A.P. is pn + q, find its common difference.मान ज्ञात कीजिए :
Answer» Answer: NTH term of an A.P (an) = pn + q To find: Common Difference (d) Proof: We KNOW that, an = a + (N – 1)d ⇒ pn + q = a + (n – 1)d [given] ⇒ pn + q – a = (n – 1)d

30.

यदि एक समांतर श्रेढ़ी का nवाँ पद pn + q हो, तो इसका सार्व अंतर ज्ञात कीजिएIf the nth term of an A.P. is pn + q, find its common difference.मान ज्ञात कीजिए :

Answer»

Answer:

NTH term of an A.P (an) = pn + q

To find: Common Difference (d)

Proof: We KNOW that,

an = a + (N – 1)d

⇒ pn + q = a + (n – 1)d [given]

⇒ pn + q – a = (n – 1)d

Discussion

31.	a contractor estimates that's 16 man can renovated house in 35 days if he use only 10 men's how long will they take to finish the same work
Answer» Step-by-step explanation: nth term of an A.P (an) = pn + Q To find: Common Difference (d) Proof: We KNOW that, an = a + (N – 1)d ⇒ pn + q = a + (n – 1)d [given] ⇒ pn + q – a = (n – 1)d

31.

a contractor estimates that's 16 man can renovated house in 35 days if he use only 10 men's how long will they take to finish the same work

Answer»

Step-by-step explanation:

nth term of an A.P (an) = pn + Q

To find: Common Difference (d)

Proof: We KNOW that,

an = a + (N – 1)d

⇒ pn + q = a + (n – 1)d [given]

⇒ pn + q – a = (n – 1)d

Discussion

32.	Solve the following for trigonometry question.
Answer» Step-by-step EXPLANATION: (2/root3)÷1/3= (2/root3)×3 =2ROOT3

32.

Solve the following for trigonometry question.

Answer»

Step-by-step EXPLANATION:

(2/root3)÷1/3= (2/root3)×3

=2ROOT3

Discussion

33.	Simplify: √102 - 62
Answer» ANSWER: 6.93 is the PERFECT answer

33.

Simplify: √102 - 62

Answer»

ANSWER:

6.93 is the PERFECT answer

Discussion

34.	(4x + 2x²– 3) ÷ (x +1)Divide and write the quotient and remainder .
Answer» ANSWER: QUOTIENT = 2X + 2 remainder = - 5

34.

(4x + 2x²– 3) ÷ (x +1)Divide and write the quotient and remainder .

Answer»

ANSWER:

QUOTIENT = 2X + 2

remainder = - 5

Discussion

35.	Check whether (√3 + √5 ) (√3 - √7 ) is rational or irrational. Justify your answer
Answer» ANSWER: ............................................. Step-by-step EXPLANATION:

35.

Check whether (√3 + √5 ) (√3 - √7 ) is rational or irrational. Justify your answer

Answer»

ANSWER:

.............................................

Step-by-step EXPLANATION:

Discussion

36.	MULTIPLY TOGETHER AND FIND THE PRODUCT....GIVE ME THE ANSWR OF THIS QUESTION
Answer» Step-by-step explanation: so first of all u have to MULTIPLY all the no. part and then VARIABLE part. (3/2×1/3×4)(x× x ×x^2)(y^2× y^2× y^2 )(z×z ^2×z^3 ) Then u will get- 2x^4 y^6 z^6 HOPE ITS CLEAR. have a GD day

36.

MULTIPLY TOGETHER AND FIND THE PRODUCT....GIVE ME THE ANSWR OF THIS QUESTION

Answer»

Step-by-step explanation:

so first of all u have to MULTIPLY all the no. part and then VARIABLE part.

(3/2×1/3×4)(x× x ×x^2)(y^2× y^2× y^2 )(z×z ^2×z^3 )

Then u will get-

2x^4 y^6 z^6

HOPE ITS CLEAR.

have a GD day

Discussion

37.	The perimeter of a right triangle is 48 cm and the hypotensue is 18 cm. Find its area
Answer» Answer: The perimeter of a right angled TRIANGLE is 48 cm , and its area is 96 cm² . Length of its hypotenuse is 20 cm . What is the length of the perpendicular sides ? Solution : Let , In a right angled triangle , B ⇔ BASE P ⇔ Perpendicular H ⇔ Hypotenuse Perimeter of a right angled triangle is sum of all its sides , ➳ PER. = B + P + H Hypotenuse , H = 20 cm ➳ Per. = B + P + 20 But it is given Per. = 48 cm , so , ➳ 48 = B + P + 20 ➳ B + P = 28 ➳ P = 28 - B ... (1) Area of a right triangle is , \to \sf A=\dfrac{1}{2}\times b\times h→A= 2 1 ×b×h where , h denotes height = perpendicular (P) b denotes base = Base (B) ➠ A = ¹/₂ × B × P Given , Area of the triangle is 96 cm² ➠ 96 = ¹/₂ × B × P ➠ BP = 192 Sub. (1) , ➠ B ( 28 - B ) = 192 ➠ 28B - B² = 192 ➠ B² - 28B + 192 = 0 ➠ B² - 12B - 16B + 192 = 0 ➠ B ( B - 12 ) - 16 ( B - 12 ) = 0 ➠ ( B - 12 ) ( B - 16 ) = 0 ➠ B = 12 ; 16 cm Sub. B VALUE in (1) , ➠ P = 28 - (12) or 28 - (16) ➠ P = 16 or 12 ➠ P = 16 ; 12 cm So , Base of the triangle = 12 or 16 cm \green{\bigstar}★ Perpendicular of the triangle = 16 or 12 cm \pink{\bigstar}★ Length of the perpendicular sides are 12 and 16 cm respectively

37.

The perimeter of a right triangle is 48 cm and the hypotensue is 18 cm. Find its area

Answer»

Answer:

The perimeter of a right angled TRIANGLE is 48 cm , and its area is 96 cm² . Length of its hypotenuse is 20 cm . What is the length of the perpendicular sides ?

Solution :

Let , In a right angled triangle ,

B ⇔ BASE

P ⇔ Perpendicular

H ⇔ Hypotenuse

Perimeter of a right angled triangle is sum of all its sides ,

➳ PER. = B + P + H

Hypotenuse , H = 20 cm

➳ Per. = B + P + 20

But it is given Per. = 48 cm , so ,

➳ 48 = B + P + 20

➳ B + P = 28

➳ P = 28 - B ... (1)

Area of a right triangle is ,

\to \sf A=\dfrac{1}{2}\times b\times h→A=

2

1

×b×h

where ,

h denotes height = perpendicular (P)

b denotes base = Base (B)

➠ A = ¹/₂ × B × P

Given , Area of the triangle is 96 cm²

➠ 96 = ¹/₂ × B × P

➠ BP = 192

Sub. (1) ,

➠ B ( 28 - B ) = 192

➠ 28B - B² = 192

➠ B² - 28B + 192 = 0

➠ B² - 12B - 16B + 192 = 0

➠ B ( B - 12 ) - 16 ( B - 12 ) = 0

➠ ( B - 12 ) ( B - 16 ) = 0

➠ B = 12 ; 16 cm

Sub. B VALUE in (1) ,

➠ P = 28 - (12) or 28 - (16)

➠ P = 16 or 12

➠ P = 16 ; 12 cm

So ,

Base of the triangle = 12 or 16 cm \green{\bigstar}★

Perpendicular of the triangle = 16 or 12 cm \pink{\bigstar}★

Length of the perpendicular sides are 12 and 16 cm respectively

Discussion

38.	Find the value of each angle 3x4x5x
Answer» Step-by-step explanation: THOMAS Alva Edison was an American inventor and BUSINESSMAN who has been DESCRIBED as America's greatest inventor. He developed many devices in fields such as electric power GENERATION, MASS communication, sound recording, and motion pictures.

38.

Find the value of each angle 3x4x5x

Answer»

Step-by-step explanation:

THOMAS Alva Edison was an American inventor and BUSINESSMAN who has been DESCRIBED as America's greatest inventor. He developed many devices in fields such as electric power GENERATION, MASS communication, sound recording, and motion pictures.

Discussion

39.	If 9y2 – a = (3y – 2) (3y+2), find the value of a
Answer» Answer: a = 4 Step-by-step EXPLANATION: LHS = 9y² - a RHS = (3y - 2)(3y + 2) using (a+b)(a-b) = a²-b² identity, = 9y² - 4 since, LHS = RHS (Given) 9y²- a = 9y²- 4 - a = - 4 a = 4

39.

If 9y2 – a = (3y – 2) (3y+2), find the value of a

Answer»

Answer:

a = 4

Step-by-step EXPLANATION:

LHS = 9y² - a

RHS = (3y - 2)(3y + 2)

using (a+b)(a-b) = a²-b² identity,

= 9y² - 4

since, LHS = RHS (Given)

9y²- a = 9y²- 4

- a = - 4

a = 4

Discussion

40.	You have recently had an ear surgery and you are resting. Some construction work had been startedby your neighbor while you were away. The noise from the work is very loud and it disturbs you. You had tried to tell them to postpone the work for some time but to no avail. Write to the society secretary regarding the situation. You are Nishkaam/Nidhi. (100-120 words)
Answer» The letter is GIVEN as follows: Explanation: 15 December 2020 To The Secretary HARI Dhaam Society Extension 3, Civil Lines Bhopal 468511 Subject: Noise pollution due to construction. Dear Sir, I am a resident of MIG 26 of Hari Dhaam society and an admirer of your efforts for the welfare of our society. Though I write this letter with great sadness and want to DISCUSS with you a dire issue. I have recently undergone ear surgery and the doctor has prescribed me complete rest with no stress on my ears. While I was gone, my neighbours STARTED dome construction work at their house. Once back, I requested them to postpone the work for a couple of weeks as the noise due to the work is very loud and is disturbingly painful for my ears. Even after knowing my condition, they refused to postpone the work. We live in a society and I judge that it is our responsibility that none of our fellow residents SUFFER due to our actions. But my neighbours do not understand this. I kindly request you to look into the matter and try to talk them out. I eagerly look forward to your help and I hope you will consider my situation. Thanking you Yours sincerely Nidhi

40.

You have recently had an ear surgery and you are resting. Some construction work had been startedby your neighbor while you were away. The noise from the work is very loud and it disturbs you. You had tried to tell them to postpone the work for some time but to no avail. Write to the society secretary regarding the situation. You are Nishkaam/Nidhi. (100-120 words)

Answer»

The letter is GIVEN as follows:

Explanation:

15 December 2020

To

The Secretary

HARI Dhaam Society

Extension 3, Civil Lines

Bhopal 468511

Subject: Noise pollution due to construction.

Dear Sir,

I am a resident of MIG 26 of Hari Dhaam society and an admirer of your efforts for the welfare of our society. Though I write this letter with great sadness and want to DISCUSS with you a dire issue.

I have recently undergone ear surgery and the doctor has prescribed me complete rest with no stress on my ears. While I was gone, my neighbours STARTED dome construction work at their house. Once back, I requested them to postpone the work for a couple of weeks as the noise due to the work is very loud and is disturbingly painful for my ears. Even after knowing my condition, they refused to postpone the work.

We live in a society and I judge that it is our responsibility that none of our fellow residents SUFFER due to our actions. But my neighbours do not understand this. I kindly request you to look into the matter and try to talk them out. I eagerly look forward to your help and I hope you will consider my situation.

Thanking you

Yours sincerely

Nidhi

Discussion

41.	(17+8)+13=17+(8+13)
Answer» ANSWER: (17+8)+13=17+(8+13) 25+13=17+21 38=38 hence, L.H.S. = R.H.S.

41.

(17+8)+13=17+(8+13)

Answer»

ANSWER:

(17+8)+13=17+(8+13)

25+13=17+21

38=38

hence, L.H.S. = R.H.S.

Discussion

42.	Order in ascending order 1.2, 3.1, 2.1
Answer» Answer: 1.2,2.1,3.1 Hooe it HELPS U and PLZZ mmark me as BRAINLIAST and do more FOLLOW

42.

Order in ascending order 1.2, 3.1, 2.1

Answer»

Answer:

1.2,2.1,3.1

Hooe it HELPS U and PLZZ mmark me as BRAINLIAST and do more FOLLOW

Discussion

43.	Find which of the statement about f is true
Answer» ANSWER: bhai/bhan 2 HAI is KA..

43.

Find which of the statement about f is true

Answer»

ANSWER:

bhai/bhan 2 HAI is KA..

Discussion

44.	P= 340.50, T=6 months andR = 20 % per annum. .
Answer» Answer: 34.05Rs interest Step-by-step explanation: interest=rate of interestPRINCIPALtime/100 =20340.506/12*100. [6 months=6/12year =34.05Rs

44.

P= 340.50, T=6 months andR = 20 % per annum. .

Answer»

Answer:

34.05Rs interest

Step-by-step explanation:

interest=rate of interest*PRINCIPAL*time/100

=20*340.50*6/12*100. [6 months=6/12year

=34.05Rs

Discussion

45.	Exercise 2.5plz explain this Question............plz........
Answer» ANSWER: a) 0.2 b) 0.5 e) 17.5 F) 15.35

45.

Exercise 2.5plz explain this Question............plz........

Answer»

ANSWER:

a) 0.2

b) 0.5

e) 17.5

F) 15.35

Discussion

46.	Find the product of::.Give me right answer plz..
Answer» ANSWER: REFER PIC for answer have a GREAT day⭐️⭐️

46.

Find the product of::.Give me right answer plz..

Answer»

ANSWER:

REFER PIC for answer

have a GREAT day⭐️⭐️

Discussion

47.	يد خط - 3هfactor of a3 - b3 is
Answer» ANSWER: a³-b³ the FACTOR is 1 .. .. ...

47.

يد خط - 3هfactor of a3 - b3 is

Answer»

ANSWER:

a³-b³

the FACTOR is 1

..

...

Discussion

48.	A Cuboid vessel is 10m long and 8m wideHow much hieght must be made to hold 3200cub.m of liquid
Answer» Answer: Therefore,the VESSEL must be MADE to a height of 4.75 m to hold 380 cubic meters of a liquid. Step-by-step explanation: HOPE you find it helpful

48.

A Cuboid vessel is 10m long and 8m wideHow much hieght must be made to hold 3200cub.m of liquid

Answer»

Answer:

Therefore,the VESSEL must be MADE to a height of 4.75 m to hold 380 cubic meters of a liquid.

Step-by-step explanation:

HOPE you find it helpful

Discussion

49.	निम्नलिखित में कौन समांतर श्रेढ़ी है?[BM 20201(A) 0.3.0.33.0.333.....(B) 1.11.111.(C) 2,4,8,16.(D) 0,-4.-8,-12,
Answer» ANSWER: it is WRONG QUESTION RIGHT and then SEND it

49.

निम्नलिखित में कौन समांतर श्रेढ़ी है?[BM 20201(A) 0.3.0.33.0.333.....(B) 1.11.111.(C) 2,4,8,16.(D) 0,-4.-8,-12,

Answer»

ANSWER:

it is WRONG QUESTION RIGHT and then SEND it

Discussion

50.	Terms of the proportionFIND out entremea:b::c:d.a) a,bb) a, cc,) a, dd) b, c
Answer» ANSWER: a, d........................

50.

Terms of the proportionFIND out entremea:b::c:d.a) a,bb) a, cc,) a, dd) b, c

Answer»

ANSWER:

a, d........................

Discussion

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_________________________

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The distance between two places is 15km. If the map scale is 1:500000, find the distance between the places in centimeters drawn in the map.

THEPresent age of Ran and Rage aresame. if Ran's11 years ago was 21then what isPresent age Ragu.agea)11b) 21c)32d, 10

28. 23' term of an arithmetic sequence is 32 and its 35'h term is 104.a) What is its common difference?b) What is its first term?c) Is the difference of any two terms of this sequence be 90?d) Find the sum of the first 35 terms?

write the first 3 multiples of the following numbers that are odd 1. 5 2. 11 3. 21 4. 31 5. 27 6. 45

Is 6487 a perfect cube if not by which smallest number should 64827 be divided so that question is a perfect cube

7. Which one of the following is irrational?(a) 25.666....(b) 75,468(c) -9÷14(d) 4.5678....

The sum of the sereies 1+3+5+7 will be

Simplify -113+(-311) +(-117)

ক)-15 এবং 6ঃ (6+5) এবং 11 এর মধ্যে >বা< বা=চিহ্ন বসাও

Sin 3 a - 1 =0 find the value of a please I'm not getting this...

6.Orlangeswere bought at 236 dozen andsold at the rate of oz 40 per 10. Find the profitor loss per cent.-

The domain of 3^x is

If x=2/5 y = 3/2 find (x+y) ÷ (x-y)

You bowled 8 games and the scoreswere: 118, 145, 118, 136, 149, 102, 119,and 171. Find the mode and range forthe data,Select one:a. Mode: none, range: 53b. Mode: none, range: 69c. Mode: 118, range: 53d. Mode: 118, range: 69

In board examination of class 9 , 50•/• passed in english 30•/• failed in both subject If 25 student passed in both subject find the total number of student .

8.के प्रथम 24[BM 2020]समान्तर श्रेणी 5.8.11.14.......पदों का योग हैहै.(A)940(B) 960(C)948 (D) 944Y

Average age of 8 people in a group is 28 years. The average age of 6 people in this same group is 29 years. What is the average age of 2 people in the group

यदि एक समांतर श्रेढ़ी का nवाँ पद pn + q हो, तो इसका सार्व अंतर ज्ञात कीजिएIf the nth term of an A.P. is pn + q, find its common difference.मान ज्ञात कीजिए :

a contractor estimates that's 16 man can renovated house in 35 days if he use only 10 men's how long will they take to finish the same work

Simplify: √102 - 62

(4x + 2x²– 3) ÷ (x +1)Divide and write the quotient and remainder .

Check whether (√3 + √5 ) (√3 - √7 ) is rational or irrational. Justify your answer

MULTIPLY TOGETHER AND FIND THE PRODUCT....GIVE ME THE ANSWR OF THIS QUESTION

The perimeter of a right triangle is 48 cm and the hypotensue is 18 cm. Find its area

Find the value of each angle 3x4x5x

If 9y2 – a = (3y – 2) (3y+2), find the value of a

(17+8)+13=17+(8+13)

Find which of the statement about f is true

P= 340.50, T=6 months andR = 20 % per annum. .

Exercise 2.5plz explain this Question............plz........

Find the product of::.Give me right answer plz..

يد خط - 3هfactor of a3 - b3 is

निम्नलिखित में कौन समांतर श्रेढ़ी है?[BM 20201(A) 0.3.0.33.0.333.....(B) 1.11.111.(C) 2,4,8,16.(D) 0,-4.-8,-12,

Terms of the proportionFIND out entremea:b::c:d.a) a,bb) a, cc,) a, dd) b, c