This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the relation betweenfraction and any word problems |
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Answer» It is used in WORD problem |
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| 2. |
Lines 2x – by + 5 = 0 and ax + 3y = 2are parallel to each other. Find the relationconnecting a and b. |
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Answer» a = 3 and b = 2 |
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| 3. |
6. Using the law of exponents, simplify andwrite the answer in exponential form.A. 4^3*2^3B. a^2*t^2c. 3^5/6^5D. p^4/q^4E. 9^5/b^5F. 7^8*c^8 |
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| 4. |
there are 20boys and 30girlsin the clasd room.the teacher wants to divide the children into groups such that each contains an equal boys nd girls.what is the greatest number of groups that she can make like this |
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Answer» Answer: 20=2*2*5 30=2*3*5 hcf=10 Step-by-step EXPLANATION: HOPE it helps 20/10=2 30/10=3 therfore GROUP in total=5 |
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| 5. |
Find the median of the set of values are 1.2,1.03,1.5,1,1.56,1.6,1.35 |
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Answer» Answer: |
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| 7. |
C.) A ladder rests against a vertical wall at an inclination alpha tothe horizontal, its foot is pulled away from the wall througha distance P so that its upper end slides a distance q down thewall and then the ladder makes an angle B to the horizontal.show that, p/q=cosB-cosalpha/sinalpha-sinB |
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Answer» ywgshwvwhvvbbbbbbbbb Step-by-step EXPLANATION: |
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| 8. |
-x+=? +x-=? what is answer |
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Answer» What is this . PLEASE MARK me as BRAINLIEST answer please YAAR please |
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| 9. |
What is rhe cost of tiling of a rectangular plot of land 500m long and 200m wide at the rate of rupees 8per hundred square metre |
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Answer» Length = 500 m Breadth = 200 m Area = l × b = 500 × 200 = 100000 m^2 Cost of tiling 100m^2 = Rs 8 Cost of tiling 1 m^2 = 8 /100
Cost of tiling 100000 m^2 = 8/100 × 100000 = 8 × 1000 = Rs . 8000 |
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| 10. |
(iii) If 3x + 2y = 10 and 2x + 3y = 15, find the value of x + y. |
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Answer» x+y=5 Add it and DIVIDE it by 5 Step-by-step EXPLANATION: x+y=5 |
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| 11. |
A lorry covered a distance of 360km at an average speed of 72km/hour.It travelled 1/3 of the journey at 60km/hourHow fast did the lorry travel for the remaining journey? |
Answer» hope this helps |
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| 12. |
PA, PB are tangents to the circle with centre at 0. If Z APB = 36°, thenAOB= |
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Answer» Answer: 90+90+36=216 360-216=144 |
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| 13. |
a wire is in the shape of square of side 12 CM if the wire is bent into a rectangle of length 14 cm find its breadth which figure and closes more area and by how muchquestion mark |
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Answer» Step-by-step EXPLANATION: |
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| 14. |
1040+1040+10+10= _____ |
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Answer» Step-by-step explanation:2100 |
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| 15. |
6x^2-24xy+9y^2-4x+3y |
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Answer» Answer: 3445 Step-by-step explanation: 5656+765765876775756 |
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| 16. |
a train running at a speed of 60 km per hour crosses a pole in 30 seconds find the length of the train |
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Answer» LENGTH = speed× time =1800m |
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| 17. |
Ragini borrowed a sum of money at 8% per annum and return RS 320 after one year now the rate of interest becomes 7% per annum for the rest of the amount of the interest of second year is 7/8 of first year simple interest what amount was borrowed |
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Answer» Answer: 8s7wh7s89r9r9e29wd8e8484jfd9 Step-by-step explanation: 922992292339393939-99929393 |
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| 18. |
"if a+b+c=0,then show that (b+c)^2/bc +(c+a)^2/ca +(a+b)^2/ab =3" |
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Answer» i didn't UNDERSTAND this question❓ |
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| 19. |
ZABC=30° and ZCBA=44° so find ZASF=?? AND M(arcPQR) |
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Answer» Step-by-step EXPLANATION: |
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| 20. |
a train leaves New Delhi at 1915 hours and arrive madhurai at 2205 hours the distance between the 2 station is 144km find the speed of the train |
Answer» Answer: 0.497 km/hrStep-by-step explanation: SPEED = distance / time taken distance = 144km time taken = ( 2205 - 1915 ) hours time taken = 290 hours speed = 144 km / 290 hours speed = 0.497 km/hr or speed = ( 144*1000 ) meters / ( 290 *3600 ) seconds speed = 144000m /1044000secs speed = 0.138 m/secs. |
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| 21. |
Draw a angle pqr in which QR is equal to 3.5 cm and m angle q equals to 40 degree and mAngle r equals to 60 degree. |
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Answer» Answer: FIRST draw BASE with UR MEASUREMENTS Draw ANGLE of 60: |
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| 23. |
In the adjoining figure, TP and TR are the tangents to the circle with centre O. If PRQ = 75°and PTR = 50 = then calculate the measure of TPR and QPR.CORRECT ANSWER WILL BE GIVEN BRAINLIESTWORST ANSWERS ARE STRICTLY NOT ALLOWED |
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Answer» Answer: I HOPE it will HELP you.....AND DON'T FORGET TO MARK ME AS BEST ANSWERS AND THANKS ME....... |
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| 24. |
Find the coordinates of the midpoint of the line segment joining the points(2,3)&(4, |
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Answer» Answer: Hey MATE your QUESTIONS is INCOMPLETE... plz complete your QUESTION..... |
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| 25. |
Xsquare + Y square + 2 x y where x is equal to 2 and Y is equal to -1 |
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Answer» Answer: 546-_773883773-_--_6_7+_83883idhfhhfyfyfyrhruriiery he hfhfhduudvdhhduuduuduudyyueiieiuduuduhdhhdhhdhhdhhdhhdjjdhduduududuudududududuudhfhdhdhdhfhfhfhfhhgdhhrhhrhrhrhrhhrrhhr |
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| 26. |
Find the area of a trapezium whose parallel sides are 9 cm and 6 cmrespectively and the distance between these sides is 8 cm. |
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Answer» Answer: 60cm2 HOGA paaka Step-by-step explanation: 1/2×(a+b)×h |
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| 27. |
If the angle at the circumference is 43° 30', then the angle at the centre = |
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| 28. |
Find the simple interest and the amount when:principle=₹9600rate=7 1/2%time=5 months |
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Answer» Answer: 300 Step-by-step EXPLANATION: =300 |
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| 29. |
605.64÷14what is the answer |
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Answer» 605.64÷14 = 43.26........ |
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| 30. |
Vandana took a loan of rupees 36,000 find the interest payable by Vandana if She returned amount of rupees 37,650. |
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Answer» Answer: Rs.1650 Step-by-step explanation: prinicipl=Rs.36000 Amount =Rs.37650 therefore C.I.(INTREST payable)=amount - principle =37650- 36000 =Rs.1650 therefore INTEREST payable =Rs.1650 |
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| 31. |
Hey!! tell me the Laws of radicals |
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Answer» LAWS OF RADICALS. Definition: A radical represents a FRACTIONAL exponent in which the numerator of the fractional exponent is the power of the base and the denominator of the fractional exponent is the index of the radical. Hope this HELPS you Please MARK me as brainliest |
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| 32. |
If X square + 1 by x square is equal to 38 then find the value of x minus one by X |
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| 33. |
Find the 15th term of AP 3, 6 ,9 so on |
Answer» ⏩45.....is the answer mate.⏪ |
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| 34. |
Classify the following expression |
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Answer» Answer: 4x²-5=(2X)²-√5² =(2x-√5) (2x+√5) |
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| 35. |
X=9+4√5 thenfind the value of √x-1/√x |
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Answer» Step-by-step EXPLANATION: |
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| 36. |
Factorized form of x²+128x+4096 is (x+64)(x-2) justify your answer is it true or false |
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Answer» Answer: it is false. Step-by-step explanation: because the rule of FACTORISATION is when we add or SUBTRACT those two factors (I.e),64-2 or 64+2......like that... but here when we do the above it is not coming when we MULTIPLY those two factors it is coming as 128. so it is not CORRECT. that's why the CONCLUSION is false. |
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| 37. |
If 2791A, is divisible by 9, supply the missing digit in place of A |
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Answer» Answer: 8 Step-by-step explanation: |
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| 38. |
ICOS 6 96+ COS 64 sin 66 + tan 36°cos 26 + cos (90-6°) sin 26' + tan 36°e cot su1. sinLot 190°-36) |
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| 39. |
S148. एक पेड़ के प्रत्येक टहनी पर 3 चिड़ियाँ बैठती हैतो 5 टहनी कम पड़ती है जबकि प्रत्येक टहनी पर9 चिड़ियाँ बैठती है 3 टहनी शेष बच जाती है ।कुल चिड़ियों की संख्या कितनी है ?(a) 30 (b) 36 (c) 54 (d) None |
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| 40. |
A cyclist covers 950 m in 5 minutes find his speed in km per hour |
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Answer» Step-by-step EXPLANATION: speed =950/(60×5) =950/300 =19/6 19/6 ×8/15 ans |
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| 41. |
Find the area of square with the following length of sides of 5cm |
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Answer» Step-by-step EXPLANATION: =5×5=25 |
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| 42. |
7. If two positive integers p and q can be expressed as p=a^3 b^3and q=ab^3c^2and being prime numbers, then HCF(p,q) is |
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Answer» Answer: The HCF od two POSITIVE integer (p,q) is a b³Step-by-step EXPLANATION: Given as : The two positive INTEGERS are p , q The integer EXPRESS as p = a³ b³ q = a b³ c² Let The HCF = x Since HCF is the highest common factor So, The integers can be written in form p = a × a × a × b × b × b q = a × b × b × b × c × c i.e highest common factor = a × b × b × b Or, HCF = a b³ Hence, The HCF od two positive integer (p,q) is a b³ Answer |
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| 43. |
How many bricks of 20×6×4cm.how many bricks are needed to bild of wall 10×2×6m |
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Answer» Answer: The number of bricks required is 250,000 .Step-by-step EXPLANATION: Given as : Let The number of bricks required = n The DIMENSION of BRICK = 20 cm × 6 cm × 4 cm i.e length = 20 cm breadth = 6 cm Height = 4 cm So, Volume of cuboid bricks = 20 cm × 6 cm × 4 cm = 480 cm³ Again The dimension of wall = 10 m × 2 m × 6 m i.e length = 1000 cm breadth = 200 cm Height = 600 cm So, The volume of wall = 1000 cm × 200 × cm × 600 cm or, The volume of wall = 12 × The number of bricks = i.e n = Or, n = 250,000 Hence, The number of bricks required is 250,000 . Answer |
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| 44. |
1/5=2/x how to solve |
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Answer» Answer: 1/5=2/X or,,,, X=10....... |
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| 45. |
Goodluck Page No.Date17In the fig.circle andthe valueO is theangleof secentre of thecircle and angle ABD=50, find the value of x |
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Answer» Step-by-step explanation: |
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| 46. |
Lindy works at a pizza restaurant and gets a 10% employee discount. She knows that if she orders d drinks and a medium pizza with t toppings, her total cost can be found using this expression: 0.90(2.25d + 1.40t + 6). What is the total cost for Lindy and her friends to order 4 drinks and a medium pizza with 3 toppings? |
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Answer» SIMPLY SUBSTITUTE in the EQUATION,, 0.9(10+5.60+6)=0.9*21.6=19.44 is the COST, |
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| 48. |
In an ap the sum of first ten terms is 150 and the sum of next ten term is 550 find ap |
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Answer» Step-by-step EXPLANATION: Here is your ANSWER! once TRY it yourself! |
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| 49. |
Katrina biscuits weighs 1 kg 750 grams what is the total weight of 7 such team in kilograms |
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Answer» Answer: 12.250 kg Step-by-step explanation: 1kg 750g * 7 = 12KG 250G = 12.250kg hope this HELPS you mate!!!!!!! |
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| 50. |
what are your program and taken by the government in the field of education and health for the welfare of the people. |
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Answer» Answer: hi bro Step-by-step explanation: {GOVERNMENT take major decisions that are by sending their CHILDREN to school the government will give 15000rs MONEY to their mother for one year called Ammavadi} field of education. {they gave arokyasree card which gives free treatment in HOSPITALS} field of health velfare of the people |
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