332354 + Interview Questions in Secondary School in Math

1.	Ifax+bx+x-6 has x+2 as a factor and leaves a remainder 4 when divided byx-2, find the values of a and b.
Answer» HOPE you UNDERSTOOD

1.

Ifax+bx+x-6 has x+2 as a factor and leaves a remainder 4 when divided byx-2, find the values of a and b.

Answer»

HOPE you UNDERSTOOD

Discussion

2.	Simplify the following: 65^0.14×67^0.27=?
Answer» ANSWER: ffggtckgdndfghhccvvggfdccvvbjlcgjkjh fjoiHff4thffuhi

2.

Simplify the following: 65^0.14×67^0.27=?

Answer»

ANSWER:

ffggtckgdndfghhccvvggfdccvvbjlcgjkjh fjoiHff4thffuhi

Discussion

3.	Construction : a, b, c are three non collinear points such tha distance between a and b is 7 cm and distance between b and c is 6 cm and distance between a and c is 7 cm. Draw a circle passing through all three points and draw a circle with radius 2 cm touching the circle internally at point a
Answer» Step-by-step explanation: First draw ab of length =7cm then TAKE b as centre and make an arc with 6 cm as radius... now take A as centre and 7cm radius draw another arc intersecting the previous arc now name this point of INTERSECTION as c now draw perpendicular bisectors of ab and bc and TAKING this point of intersection of these bisectors as centre and the perpendicular distance as radius draw a circle which will PASS through all the points. PERPENDICULAR BISECTORS: For a given line segment say AB take more than half of its length as radius and draw arcs from both the ends on either sides of AB then join the point of intersections this will give u perpendicular bisector....

3.

Construction : a, b, c are three non collinear points such tha distance between a and b is 7 cm and distance between b and c is 6 cm and distance between a and c is 7 cm. Draw a circle passing through all three points and draw a circle with radius 2 cm touching the circle internally at point a

Answer»

Step-by-step explanation:

First draw ab of length =7cm

then TAKE b as centre and make an arc with 6 cm as radius...

now take A as centre and 7cm radius draw another arc intersecting the previous arc now name this point of INTERSECTION as c

now draw perpendicular bisectors of ab and bc and TAKING this point of intersection of these bisectors as centre and the perpendicular distance as radius draw a circle which will PASS through all the points.

PERPENDICULAR BISECTORS:

For a given line segment say AB take more than half of its length as radius and draw arcs from both the ends on either sides of AB then join the point of intersections this will give u perpendicular bisector....

Discussion

4.	On a map it is 15cm from Toms house to the town centre and 9cm from the town centre to Andys house and it forms a right angle triangle. Tom measure the distance on his bike and the distance from his house to the town centre and then to Andys house was 3.6km.What is the scale of the map?
Answer» Answer: 1:10000 is the SCALE on the MAP

4.

On a map it is 15cm from Toms house to the town centre and 9cm from the town centre to Andys house and it forms a right angle triangle. Tom measure the distance on his bike and the distance from his house to the town centre and then to Andys house was 3.6km.What is the scale of the map?

Answer»

Answer:

1:10000 is the SCALE on the MAP

Discussion

5.	HiCan someone plz solve this answerI will mark brainliest who answers correct
Answer» HOPE it HELPS you SEE the ATTACHMENT for further INFORMATION ...✌✌✌

5.

HiCan someone plz solve this answerI will mark brainliest who answers correct

Answer»

HOPE it HELPS you SEE the ATTACHMENT for further INFORMATION ...✌✌✌

Discussion

6.	Find two equal ratios of 2 is to 3
Answer» Answer: 4 is to 6 & 6IS to 9 hope this will HELP you

6.

Find two equal ratios of 2 is to 3

Answer»

Answer:

4 is to 6 & 6IS to 9

hope this will HELP you

Discussion

7.	Sin^-1 12/15+cos^-1 15/17= sin^17/20
Answer» ANSWER: it is answer not question write PROPERLY that what you WANT to KNOW

7.

Sin^-1 12/15+cos^-1 15/17= sin^17/20

Answer»

ANSWER:

it is answer not question write PROPERLY that what you WANT to KNOW

Discussion

8.	Difference between linear equation and algebraic expression
Answer» ANSWER: Content: Expression Vs Equation Expression is a mathematical phrase which combines, numbers, VARIABLES and operators to SHOW the value of SOMETHING. An equation is a mathematical statement wherein TWO expressions are set equal to each other. What is it? A sentence fragment, that stands for a single numerical value

8.

Difference between linear equation and algebraic expression

Answer»

ANSWER:

Content: Expression Vs Equation

Expression is a mathematical phrase which combines, numbers, VARIABLES and operators to SHOW the value of SOMETHING. An equation is a mathematical statement wherein TWO expressions are set equal to each other. What is it? A sentence fragment, that stands for a single numerical value

Discussion

9.	A tradesman puts two prices on his goods, one for upfront payment and the other for 6 month'scredit on simple interest at 12.5 % per annum. If the credit price of the article is Rs.26.56, whatis its approximate price for upfront payment?1] Rs.20.632] Rs.21.94 3] Rs.23.694] Rs.25
Answer» ANSWER: Your answer is OPTION 1) RS. 20.63

9.

A tradesman puts two prices on his goods, one for upfront payment and the other for 6 month'scredit on simple interest at 12.5 % per annum. If the credit price of the article is Rs.26.56, whatis its approximate price for upfront payment?1] Rs.20.632] Rs.21.94 3] Rs.23.694] Rs.25

Answer»

ANSWER:

Your answer is OPTION 1) RS. 20.63

Discussion

10.	if the sum of the roots of quadratic equations ax2+bx+c=0 is equal to the sum of the square of their reciprocal then prove that 2a2c=c2b+b2c
Answer» Mai tumko kal answer batati hu Because MERA EXAM CHAL RAHA hai

10.

if the sum of the roots of quadratic equations ax2+bx+c=0 is equal to the sum of the square of their reciprocal then prove that 2a2c=c2b+b2c

Answer»

Mai tumko kal answer batati hu

Because MERA EXAM CHAL RAHA hai

Discussion

11.	Prove that: tangent segments drawn from an external point to a circle are congruent
Answer» Answer: HI here is ur answer I hope it HELPS U

11.

Prove that: tangent segments drawn from an external point to a circle are congruent

Answer»

Answer:

HI here is ur answer I hope it HELPS U

Discussion

12.	A man sold two Scooter for 18000 each on one he gain 20% and on the other he lost 20% find his total loss or gain.
Answer» SP OF SCOOTER IS 18000 FIRST GAIN=20% SO CP OF GAIN 20%= 100/100+2018000=15000 CP OF LOSS 20%= 100/100-2018000=22500 SO TOTAL SP=180002=36000 TOTAL CP=15000+22500=37500 SO CLErly it is a loss then loss=37500-36000=1500 loss%=1500/37500100=4%

12.

A man sold two Scooter for 18000 each on one he gain 20% and on the other he lost 20% find his total loss or gain.

Answer»

SP OF SCOOTER IS 18000

FIRST GAIN=20%

SO CP OF GAIN 20%=

100/100+20*18000=15000

CP OF LOSS 20%=

100/100-20*18000=22500

SO TOTAL SP=18000*2=36000

TOTAL CP=15000+22500=37500

SO CLErly it is a loss

then loss=37500-36000=1500

loss%=1500/37500*100=4%

Discussion

13.	Plz help me graph is needed plzzzz and F(x)=x^2-1
Answer» ANSWER: hey Step-by-step EXPLANATION: i will GIVE U TOMORROW

13.

Plz help me graph is needed plzzzz and F(x)=x^2-1

Answer»

ANSWER:

hey

Step-by-step EXPLANATION:

i will GIVE U TOMORROW

Discussion

14.	I will mark as brainliest for the right answers
Answer» Answer: BIGGEST size =73 in. smallest size=24 in. Step-by-step EXPLANATION: T MAX = (2d/3)+1 T max=72+1=73 in. T MIN=(d/4)-3 T min =27-3=24 in.

14.

I will mark as brainliest for the right answers

Answer»

Answer:

BIGGEST size =73 in.

smallest size=24 in.

Step-by-step EXPLANATION:

T MAX = (2d/3)+1

T max=72+1=73 in.

T MIN=(d/4)-3

T min =27-3=24 in.

Discussion

15.	(1) Write the number of elements in set AA = {3, 5, 9}
Answer» 3 because there are no DUPLICATE VALUES.

Discussion

16.	If a:b::c:d then a,b,c,d are said to be in
Answer» Step-by-step EXPLANATION: PROPORTIONAL to each other

16.

If a:b::c:d then a,b,c,d are said to be in

Answer»

Step-by-step EXPLANATION:

PROPORTIONAL to each other

Discussion

17.	35. Differentiate 'sin x with respect to x from first principle.
Answer» ANSWER: PLEASE SEE the ATTACHMENT

17.

35. Differentiate 'sin x with respect to x from first principle.

Answer»

ANSWER:

PLEASE SEE the ATTACHMENT

Discussion

18.	The Simplest form of -6:-18is
Answer» Answer: 1/3 Step-by-step EXPLANATION:

18.

The Simplest form of -6:-18is

Answer»

Answer:

1/3

Step-by-step EXPLANATION:

Discussion

19.	What is the Value of 4√(81)^–2
Answer» Answer: 0.4938271604 Step-by-step EXPLANATION:

19.

What is the Value of 4√(81)^–2

Answer»

Answer:

0.4938271604

Step-by-step EXPLANATION:

Discussion

20.	A circular garden is surrounded internally by a 3m wide path. If the diameter of thegarden is 24 m, find the area of the path.
Answer» Given: Diameter of circular garden = 24m Width of circular path = 3m To find: The are of circular path = ? SOLUTION: We KNOW the relation between Radius, $r$ and Diameter, $d$ : $r = \dfrac{d}{2}$ Please REFER to the attached image. So, radius of Circular Garden: $R=\dfrac{24}{2} = 12\ m$ Circular path has a width of 3m, so Radius of inner circle: $r = R - 3\\\Rightarrow r = 9\ m$ AREA of circular path = Area of OUTER circle - Area of inner circle We know that area of a circle is defined as: Area $= \pi \times Radius^2$ So, area of circular path = $\pi R^{2} - \pi r^{2}$ $\Rightarrow \pi (12^2-9^2)\\\Rightarrow \dfrac{22}{7} \times 63\\\Rightarrow 22 \times 9\\\Rightarrow 198\ m^{2}$ So, area of circular path is = $198\ m^{2}$

20.

A circular garden is surrounded internally by a 3m wide path. If the diameter of thegarden is 24 m, find the area of the path.

Answer»

Given:

Diameter of circular garden = 24m

Width of circular path = 3m

To find: The are of circular path = ?

SOLUTION:

We KNOW the relation between Radius, $r$ and Diameter, $d$ :

$r = \dfrac{d}{2}$

Please REFER to the attached image.

So, radius of Circular Garden:

$R=\dfrac{24}{2} = 12\ m$

Circular path has a width of 3m, so Radius of inner circle:

$r = R - 3\\\Rightarrow r = 9\ m$

AREA of circular path = Area of OUTER circle - Area of inner circle

We know that area of a circle is defined as:

Area $= \pi \times Radius^2$

So, area of circular path = $\pi R^{2} - \pi r^{2}$

$\Rightarrow \pi (12^2-9^2)\\\Rightarrow \dfrac{22}{7} \times 63\\\Rightarrow 22 \times 9\\\Rightarrow 198\ m^{2}$

So, area of circular path is = $198\ m^{2}$

Discussion

21.	1. find the equation of acircle passes through thepoints (0, 0) (a,0) and (0,b)
Answer» ANSWER: wuwhwhehe6 dbo na ho to➡➡➡➡➡➡➡➡➡➡➡➡➡ HD MOVIE with a lot about it but it is the most beautiful

21.

1. find the equation of acircle passes through thepoints (0, 0) (a,0) and (0,b)

Answer»

ANSWER:

wuwhwhehe6 dbo na ho to➡➡➡➡➡➡➡➡➡➡➡➡➡ HD MOVIE with a lot about it but it is the most beautiful

Discussion

22.	The value of 3 root 216-3root125
Answer» Answer: 3 COMMON out and then 3 √216-125 3√91

22.

The value of 3 root 216-3root125

Answer»

Answer:

3 COMMON out and then

3 √216-125

3√91

Discussion

23.	Help......t of........no 9
Answer» ANSWER: PLS ASK the QUESTION PROPERLY

23.

Help......t of........no 9

Answer»

ANSWER:

PLS ASK the QUESTION PROPERLY

Discussion

24.	11. The C.I on40000 at 10% p.a for 1 year when the interest is payable quarterly is
Answer» Answer: 4000 Step-by-step EXPLANATION: Because QUARTERLY TIME 4 TIMES and interest 10/4

24.

11. The C.I on40000 at 10% p.a for 1 year when the interest is payable quarterly is

Answer»

Answer:

4000

Step-by-step EXPLANATION:

Because QUARTERLY TIME 4 TIMES and interest 10/4

Discussion

25.	216.X can do a piece of work in 24 days. When hehad worked for 4 days, Y joined him. If com-plete work was finished in 16 days, Y can alonefinish that work in :X किसी काम को 24 दिन में पूरा कर सकता है।जब उसने 4 दिन काम कर लिया तब Y भी उसकेसाथ शामिल हो गया। यदि समस्त काम 16 दिनमें पूरा हो गया, तो Y अकेले उस काम को कितनेदिन में पूरा कर सकता था?Short trick
Answer» Answer: 36 days Step-by-step explanation; X can complete the WORK in 24 days. So, work done by X in 1 DAY = 1/24th work Therefore, work done by him in 4 days = 4*1/24 = 1/6th work Remaining work to be finished by both X and Y = 1 -1/6 = 5/6 They finish it in (16-4) i.e 12 days. Therefore, work done by both in 1 day = (5/6)/12 = 5/ 72. Now, work done in 1 day by X alone = 1/24 Therefore, work done by Y alone in 1 day = 5/72 - 1/24 = 2/72 = 1/36 Hence, Y alone can finish the work in 1/(1/36) i.e 36 days.

25.

216.X can do a piece of work in 24 days. When hehad worked for 4 days, Y joined him. If com-plete work was finished in 16 days, Y can alonefinish that work in :X किसी काम को 24 दिन में पूरा कर सकता है।जब उसने 4 दिन काम कर लिया तब Y भी उसकेसाथ शामिल हो गया। यदि समस्त काम 16 दिनमें पूरा हो गया, तो Y अकेले उस काम को कितनेदिन में पूरा कर सकता था?Short trick

Answer»

Answer:

36 days

Step-by-step explanation;

X can complete the WORK in 24 days.

So, work done by X in 1 DAY = 1/24th work

Therefore, work done by him in 4 days = 4*1/24 = 1/6th work

Remaining work to be finished by both X and Y = 1 -1/6 = 5/6

They finish it in (16-4) i.e 12 days. Therefore, work done by both in 1 day = (5/6)/12 = 5/ 72.

Now, work done in 1 day by X alone = 1/24

Therefore, work done by Y alone in 1 day = 5/72 - 1/24 = 2/72 = 1/36

Hence, Y alone can finish the work in 1/(1/36) i.e 36 days.

Discussion

26.	A man losses 16⅔% on cost. how much does this represent on sales
Answer» ANSWER: SP 5 Step-by-step EXPLANATION: SP 5 CP 6 THEN YOU CALCULATE

26.

A man losses 16⅔% on cost. how much does this represent on sales

Answer»

ANSWER:

SP 5

Step-by-step EXPLANATION:

SP 5

CP 6

THEN YOU CALCULATE

Discussion

27.	state mean whether the values given extend the quadratic equation are the roots of the equation or not x2 +4x-5= x=1,x=-1
Answer» Answer: 1 is a root of the given POLYNOMIAL while 1 is a root of the given polynomial Step-by-step EXPLANATION: Substituting x=1, = $1^{2}$ +4(1)-5 =1+4-5 =5-5 =0 1 is a root of the given polynomial Substituting x=-1, = $-1^{2}$ +4(-1)-5 =1-4-5 =1-9 =-8 1 is a root of the given polynomial Hope it helps...

27.

state mean whether the values given extend the quadratic equation are the roots of the equation or not x2 +4x-5= x=1,x=-1

Answer»

Answer:

1 is a root of the given POLYNOMIAL while 1 is a root of the given polynomial

Step-by-step EXPLANATION:

Substituting x=1,

= $1^{2}$ +4(1)-5

=1+4-5

=5-5

=0

1 is a root of the given polynomial

Substituting x=-1,

= $-1^{2}$ +4(-1)-5

=1-4-5

=1-9

=-8

1 is a root of the given polynomial

Hope it helps...

Discussion

28.	Pls hrlp.................no.8
Answer» The AREA of a cone comprises lateral and base surface area. The height of the cone is 12 m and radius of the base is 16 m. The area is gotten by the formula. (Please look at the bottom.) $l=\sqrt{12^2+16^2} =20$ $\pi\times 16\times (16+20)=576\pi$ The surface area of the cone is $576\pi$ m². The area of the cloth is $576\pi$ m². The cloth is a rectangle. The length required is $\frac{576}{1.1}\pi =\frac{5760}{11} \pi$ . COST : ₹ $\frac{161280}{11} \pi$ formula Let the height be $h$ , base radius $r$ . Then, by the pythagorean THEOREM, the radius of the lateral surface is $\sqrt{r^2+h^2}$ . Let $l=\sqrt{r^2+h^2}$ . (lateral surface area) = $\pi \times l^2 \times \frac{2\pi \times r}{2\pi \times l} =\pi rl$ (Because lateral surface is a circular sector, not a full CIRCLE.) (base area) = $\pi r^2$ ∴ (surface area of a cone) = $\pi r^2+\pi rl=\pi r(r+l)$

28.

Pls hrlp.................no.8

Answer»

The AREA of a cone comprises lateral and base surface area.

The height of the cone is 12 m and radius of the base is 16 m.

The area is gotten by the formula. (Please look at the bottom.)

$l=\sqrt{12^2+16^2} =20$

$\pi\times 16\times (16+20)=576\pi$

The surface area of the cone is $576\pi$ m².

The area of the cloth is $576\pi$ m².

The cloth is a rectangle.

The length required is $\frac{576}{1.1}\pi =\frac{5760}{11} \pi$ .

COST : ₹ $\frac{161280}{11} \pi$

formula

Let the height be $h$ , base radius $r$ .

Then, by the pythagorean THEOREM,

the radius of the lateral surface is $\sqrt{r^2+h^2}$ .

Let $l=\sqrt{r^2+h^2}$ .

(lateral surface area) = $\pi \times l^2 \times \frac{2\pi \times r}{2\pi \times l} =\pi rl$

(Because lateral surface is a circular sector, not a full CIRCLE.)

(base area) = $\pi r^2$

∴ (surface area of a cone) = $\pi r^2+\pi rl=\pi r(r+l)$

Discussion

29.	Please i really need help
Answer» Answer: 3 2 21 17 23 Step-by-step EXPLANATION:

29.

Please i really need help

Answer»

Answer:

3

2

21

17

23

Step-by-step EXPLANATION:

Discussion

30.	27. Express the complex number Z = 1 + i root3 in the polar form
Answer» *Polar form* = \|Z\|(cos THETA + i SIN theta) cos theta = x/\|Z\| , sin theta = y/\|Z\| *HOPE* *THIS* *HELPS* *YOU*............

30.

27. Express the complex number Z = 1 + i root3 in the polar form

Answer»

Polar form = |Z|(cos THETA + i SIN theta)

cos theta = x/|Z| , sin theta = y/|Z|

HOPE THIS HELPS YOU............

Discussion

31.	5. The coordinates of triangle ABC are A(-4, 2), B(5, 0) C(4,4)(a) show that triangle ABC is a right angle triangle
Answer» Answer: after 1ST pic answer is CONTINUED in 2ND pic plz mark my answer as BRAINLIST

31.

5. The coordinates of triangle ABC are A(-4, 2), B(5, 0) C(4,4)(a) show that triangle ABC is a right angle triangle

Answer»

Answer:

after 1ST pic answer is CONTINUED in 2ND pic

plz mark my answer as BRAINLIST

Discussion

32.	{READ PROBLEM CAREFULLY. AND GIVE DETAILED EXPLANATION TO THIS PROBLEM}Suppose there are 12 boys and 4 girls in a class. If we choose three children one afteranother in succession at random, find the probability that all the three are boys.
Answer» ANSWER: Total STUDENTS =12+4 = 16 no. of OUTCOMES = 3 probablity = 3/16

32.

{READ PROBLEM CAREFULLY. AND GIVE DETAILED EXPLANATION TO THIS PROBLEM}Suppose there are 12 boys and 4 girls in a class. If we choose three children one afteranother in succession at random, find the probability that all the three are boys.

Answer»

ANSWER:

Total STUDENTS =12+4 = 16

no. of OUTCOMES = 3

probablity = 3/16

Discussion

33.	(7x + 3b)3 – (5x + 3b)3 – 6x(7x + 36)(5x + 36) what is the answer?
Answer» Answer: Step-by-step explanation: 21x + 9b - 15x - 9b - 6X ( 1296 + 35x2 + 36(5X + 7x) 21x + 9b - 15x - 9b - 6x ( 1296 + 35x2 + 432x) 6x- 6x ( 1296 + 35x2 + 432x) 6x - 7776x - 210x3 - 2592x2 -210x3 - 2592x2 - 7770x ∅⇄ →MARK ↔ BRAINLIEST← ⇆∅

33.

(7x + 3b)3 – (5x + 3b)3 – 6x(7x + 36)(5x + 36) what is the answer?

Answer»

Answer:

Step-by-step explanation:

21x + 9b - 15x - 9b - 6X ( 1296 + 35x2 + 36(5X + 7x)

21x + 9b - 15x - 9b - 6x ( 1296 + 35x2 + 432x)

6x- 6x ( 1296 + 35x2 + 432x)

6x - 7776x - 210x3 - 2592x2

-210x3 - 2592x2 - 7770x

∅⇄ →MARK ↔ BRAINLIEST← ⇆∅

Discussion

34.	Without using truth table show that
Answer» ANSWER: it will be equal Step-by-step explanation: first USE comutative law second and third by distributive law fourth by complement law and LAST FIFTH by identity law

34.

Without using truth table show that

Answer»

ANSWER:

it will be equal

Step-by-step explanation:

first USE comutative law

second and third by distributive law

fourth by complement law

and LAST FIFTH by identity law

Discussion

35.	Binary addition 1101×111
Answer» Answer: 122211 I HOPE your problem is solved plz GIVE RESPONSE with thanked and MARK as brainliest

35.

Binary addition 1101×111

Answer»

Answer:

122211

I HOPE your problem is solved plz GIVE RESPONSE with thanked and MARK as brainliest

Discussion

36.	Factorise : (5b - 4)^2 - (5b + 4)^2.
Answer» ANSWER: b=0 HOPE SO THIS WILL HELP U

36.

Factorise : (5b - 4)^2 - (5b + 4)^2.

Answer»

ANSWER:

b=0

HOPE SO THIS WILL HELP U

Discussion

37.	The map uses a scale of 1 inch to 20 miles. A new map has a scale of 2 inches = 15 miles. How far apart are cities A and B on the new map?
Answer» Step-by-step explanation: 2 inches = 15 miles so 1 inch = 15/2 = 7.5 miles so RATIO of distance between the two maps = 20 : 7.5 or 2.67 : 1 so the distance in NEW map will be 1/2.67 TIMES than old map

37.

The map uses a scale of 1 inch to 20 miles. A new map has a scale of 2 inches = 15 miles. How far apart are cities A and B on the new map?

Answer»

Step-by-step explanation:

2 inches = 15 miles

so 1 inch = 15/2 = 7.5 miles

so RATIO of distance between the two maps = 20 : 7.5 or 2.67 : 1

so the distance in NEW map will be 1/2.67 TIMES than old map

Discussion

38.	Answer for the question given in the picture
Answer» QUESTION : If a = 2 + √3,then find the VALUE of a - 1/a SOLUTION : GIVEN that a = 2 + √3 Here, $\sf \: \dfrac{1}{a} = \dfrac{1}{2 + \sqrt{3} } \\ \\ \longmapsto \: \sf \: \dfrac{1}{a} = \dfrac{1}{2 + \sqrt{3} } \times \dfrac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \\ \longmapsto \: \sf \: \dfrac{1}{a} = \dfrac{2 - \sqrt{3} }{ {2}^{2} - ( \sqrt{3}) {}^{2} } \\ \\ \longmapsto \: \boxed{\sf \: \dfrac{1}{a} = 2 - \sqrt{ 3} }$ Now, $\sf \: a - \dfrac{1}{a} \\ \\ = \sf \: (2 + \sqrt{3} ) - (2 - \sqrt{3} ) \\ \\ = \sf \: 2 \sqrt{3}$

38.

Answer for the question given in the picture

Answer»

QUESTION :

If a = 2 + √3,then find the VALUE of a - 1/a

SOLUTION :

GIVEN that

a = 2 + √3

Here,

$\sf \: \dfrac{1}{a} = \dfrac{1}{2 + \sqrt{3} } \\ \\ \longmapsto \: \sf \: \dfrac{1}{a} = \dfrac{1}{2 + \sqrt{3} } \times \dfrac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \\ \longmapsto \: \sf \: \dfrac{1}{a} = \dfrac{2 - \sqrt{3} }{ {2}^{2} - ( \sqrt{3}) {}^{2} } \\ \\ \longmapsto \: \boxed{\sf \: \dfrac{1}{a} = 2 - \sqrt{ 3} }$

Now,

$\sf \: a - \dfrac{1}{a} \\ \\ = \sf \: (2 + \sqrt{3} ) - (2 - \sqrt{3} ) \\ \\ = \sf \: 2 \sqrt{3}$

Discussion

39.	Please solve it correctly with explanation
Answer» ANSWER: (1/ sin theta+ 1/tan theta)^2 (1/sin theta +1/sin theta /cos theta )^2 [REASON:tan theta = sin theta / cos theta] (1/ sin theta + cos theta / sin theta)^2 (1+cos theta)^2/sin^2 (1+cos theta)^2/1-cos^2 theta. [reason: sin^2+cos^2 theta =1] (1+cos theta)(1+ cos theta)/1+ cos theta)(1- cos theta) [reason:by using identity a^2-b^2=(a+b)(a-b)] 1+ cos theta /1- cos theta HENCE proved *Hope* it *helps* U!!!

39.

Please solve it correctly with explanation

Answer»

ANSWER:

(1/ sin theta+ 1/tan theta)^2
(1/sin theta +1/sin theta /cos theta )^2 [REASON:tan theta = sin theta / cos theta]
(1/ sin theta + cos theta / sin theta)^2
(1+cos theta)^2/sin^2
(1+cos theta)^2/1-cos^2 theta. [reason: sin^2+cos^2 theta =1]
(1+cos theta)(1+ cos theta)/1+ cos theta)(1- cos theta) [reason:by using identity a^2-b^2=(a+b)(a-b)]
1+ cos theta /1- cos theta

HENCE proved

Hope it helps U!!!

Discussion

40.	Exercise 13.4 (Mischere are four options (Q1 to1. The value of (1296)ā is
Answer» FIRST WRITE your QUESTION PROPERTY and then OPTION.

Discussion

41.	1. In a cylinderical pipe (Fig. 14,23), the area of the surfacesis 154 sq units. Find the radius and height of the cylinder if it's volume is 880 sq m.
Answer» ANSWER: you have to write all the questions with figure if here isn't GIVEN FORMULA so, how I explain . you have to write all the QUESTION with figure

41.

1. In a cylinderical pipe (Fig. 14,23), the area of the surfacesis 154 sq units. Find the radius and height of the cylinder if it's volume is 880 sq m.

Answer»

ANSWER:

you have to write all the questions with figure if here isn't GIVEN FORMULA so, how I explain . you have to write all the QUESTION with figure

Discussion

42.	*03. Ifnis an integer then show that /(1+cos 0+isin )"+(1+cos O-isin o)2 /►Mar10)
Answer» Answer: In △ABC AB=AC ⇒∠B=∠C (Angles opposite to equal sides are equal) Now USING angle sum property ∠A+∠B+∠C=180 ∘ ⇒80 ∘ +∠C+∠C=180 ∘ ⇒2∠C=180 ∘ −80 ∘ ⇒∠C= 2 100 ∘ =50 ∘ now ∠C+∠x=180 ∘ (Angles made on STRAIGHT LINE (AC) are supplementary) ⇒50 ∘ +∠x=180 ∘ ⇒∠x=180 ∘ −50 ∘ =130 ∘ @ARSH [email PROTECTED]_arsh_deep_29

42.

*03. Ifnis an integer then show that /(1+cos 0+isin )"+(1+cos O-isin o)2 /►Mar10)

Answer»

Answer:

In △ABC AB=AC

⇒∠B=∠C (Angles opposite to equal sides are equal)

Now USING angle sum property

∠A+∠B+∠C=180

∘

⇒80

∘

+∠C+∠C=180

∘

⇒2∠C=180

∘

−80

∘

⇒∠C=

2

100

∘

=50

∘

now ∠C+∠x=180

∘

(Angles made on STRAIGHT LINE (AC) are supplementary)

⇒50

∘

+∠x=180

∘

⇒∠x=180

∘

−50

∘

=130

∘

@ARSH

[email PROTECTED]_arsh_deep_29

Discussion

43.	X, Y and Z together can do a piece of work in 4 days. If X and Y can do the work in5 days, Y and Z in 10 days, find the number of days in which X and Z, while workingtogether, will be able to finish the work.
Answer» ANSWER: what you have ASKED BRO I can't UNDERSTAND

43.

X, Y and Z together can do a piece of work in 4 days. If X and Y can do the work in5 days, Y and Z in 10 days, find the number of days in which X and Z, while workingtogether, will be able to finish the work.

Answer»

ANSWER:

what you have ASKED BRO I can't UNDERSTAND

Discussion

44.	Plz i really need help ill mark as brainliest for the right answerit is 2 ( 8-7 )
Answer» ANSWER: Step-by-step EXPLANATION: ACCORDING to BODMAS 2(8-7) =2(1) =2

44.

Plz i really need help ill mark as brainliest for the right answerit is 2 ( 8-7 )

Answer»

ANSWER:

Step-by-step EXPLANATION:

ACCORDING to BODMAS

2(8-7)

=2(1)

=2

Discussion

45.	Pythagoras Theorem(if u will answer whole theorem I will give u branilest)
Answer» $\Huge{\boxed{\mathcal{\black{yo}}}}$ *___________________________________________________________________________________________* *Hypotenuse²* = *Perpendicular²* + *Base²* *___________________________________________________________________________________________* ꧁༺Aditi༺꧁

45.

Pythagoras Theorem(if u will answer whole theorem I will give u branilest)

Answer»

$\Huge{\boxed{\mathcal{\black{yo}}}}$

___________________________________________________________________________________________

Hypotenuse² = Perpendicular² + Base²

___________________________________________________________________________________________

꧁༺Aditi༺꧁

Discussion

46.	Different between MASS ANDWEIGHT 5 POINTS FOR EACH please answer me back
Answer» ANSWER: $The terms$ MARK as BRILLIANT answer

46.

Different between MASS ANDWEIGHT 5 POINTS FOR EACH please answer me back

Answer»

ANSWER:

$The terms$

MARK as BRILLIANT answer

Discussion

47.	Solve the first sum fast
Answer» First of all, JOIN EOD In DEB, APO=90°=BEO. (PERPENDICULAR TANGENT TO RADIUS) NOW, ADO+BEO+EBC+DAC=360°(SUM OF ANGLE OF QUAD) CAO=1/2DAC AND CBO=1/2EBC CAO+CBO=1/2(DAC+EBC)=1/2 X 180°=90° Now, in tri(AOB), CAO+AOB+CBO=180° AOB=180°-(CAO+CBO)=90° YOUR ANSWER IS 90°

47.

Solve the first sum fast

Answer»

First of all, JOIN

EOD

In DEB,

APO=90°=BEO. (PERPENDICULAR TANGENT TO RADIUS)

NOW, ADO+BEO+EBC+DAC=360°(SUM OF ANGLE OF QUAD)

CAO=1/2DAC AND CBO=1/2EBC

CAO+CBO=1/2(DAC+EBC)=1/2 X 180°=90°

Now, in tri(AOB),

CAO+AOB+CBO=180°

AOB=180°-(CAO+CBO)=90°

YOUR ANSWER IS 90°

Discussion

48.	If the area of the circle are in the ratio 25:49,find the ratio of the circumference? please xlick your photo and do it nicely .IF YOU DO I SURELY TO MAKE YOU BRAINLIST
Answer» *HOPE* *YOU* *UNDERSTAND* *THIS*............

48.

If the area of the circle are in the ratio 25:49,find the ratio of the circumference? please xlick your photo and do it nicely .IF YOU DO I SURELY TO MAKE YOU BRAINLIST

Answer»

HOPE YOU UNDERSTAND THIS............

Discussion

49.	कस.येई विजयी होऊन, पुन्हा माझिया द्वाराकाव्यपक्तातूनप्पा(आ) 'धन्य करी माझी कूस, येई विजयी होऊभावसौंदर्य स्पष्ट करा.प्र. ५. अभिव्यक्ती.(अ) कवितेतील वीर मातेच्या भावना तुमच्या शब्दांत लिहा.आ) 'भारतभू ही वीरांची भूमी आहे', याबाबत तुमचे मत लिहा.उपक्रम : सैन्यात भरती झालेल्या मुलाच्या आईची मुलाखत घेण्यासाठी प्रश्नभाषा सौंदर्य__मुलींची कन्याशाळा, केसांची हेअरस्टाइल, ठंडा कोल्ड्रिंक, वटवृक्षाच्यवे रोड. रायटिंगमध्ये लिस का
Answer» ANSWER: WASTE because i don't KNOW HINDI

49.

कस.येई विजयी होऊन, पुन्हा माझिया द्वाराकाव्यपक्तातूनप्पा(आ) 'धन्य करी माझी कूस, येई विजयी होऊभावसौंदर्य स्पष्ट करा.प्र. ५. अभिव्यक्ती.(अ) कवितेतील वीर मातेच्या भावना तुमच्या शब्दांत लिहा.आ) 'भारतभू ही वीरांची भूमी आहे', याबाबत तुमचे मत लिहा.उपक्रम : सैन्यात भरती झालेल्या मुलाच्या आईची मुलाखत घेण्यासाठी प्रश्नभाषा सौंदर्य__मुलींची कन्याशाळा, केसांची हेअरस्टाइल, ठंडा कोल्ड्रिंक, वटवृक्षाच्यवे रोड. रायटिंगमध्ये लिस का

Answer»

ANSWER:

WASTE because i don't KNOW HINDI

Discussion

50.	Show that the. line seg joining the points (-6,8),(-2,4)and(-4,13),(-4,-1) bisect each other
Answer» Step-by-step EXPLANATION: MID point of 1st line segment = x= -6-2/2 = -4 y= 8+4/2 = 6 mid point of 2nd line segment x = -4-4/2=-4 y =13-1/2=6 so they're equal then they will bisect each other mark me as brainlist

50.

Show that the. line seg joining the points (-6,8),(-2,4)and(-4,13),(-4,-1) bisect each other

Answer»

Step-by-step EXPLANATION:

MID point of 1st line segment =

x= -6-2/2 = -4

y= 8+4/2 = 6

mid point of 2nd line segment

x = -4-4/2=-4

y =13-1/2=6

so they're equal

then they will bisect each other

mark me as brainlist

Discussion

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