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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In an adjoining figure, the area enclosed between the concentric circles is 770cm2 . If the radius of outer circle is 21 cm, calculate the radius of inner circle |
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Answer» Step-by-step EXPLANATION: Please see the image below |
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| 2. |
find the area of an equilateral triangle of side 5 cm correct to decimal points use square root of 3 is equals to 1.7 32 |
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Answer» Step-by-step EXPLANATION: |
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| 3. |
The probability of a certain event is A) 0B) 0.5C) 0.7D) 1. |
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Answer» PROBABILITY is of a CERTAIN EVENT is 0 |
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| 4. |
Convert 1542kg into kg and g |
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Answer» Step-by-step explanation: 1 kg=1000 GM =1542000 gm |
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| 5. |
5. The diagonals of a rhombus are 6 cm and 8 cm.Find the length of a side of the rhombus. |
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Answer» Step-by-step EXPLANATION: hope it HELPS you |
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| 6. |
If x=3+2√2,then find the value of √x-√1/√x |
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Answer» Answer: 2√2 Step-by-step explanation: Given----> x = 3 + 2√2 To find-----> VALUE of ( √x - 1 / √x ) Solution----> ATQ, x = 3 + 2√2 = 1 + 2 + 2√2 = ( 1 )² + ( √2 )² + 2 ( 1 ) ( √2 ) We know that, ( a + B )² = a² + b² + 2ab , applying it we get , = ( 1 + √2 )² Now , √x = √( 1 + √2 )² = ( 1 + √2 ) Now, 1 / √x = 1 / ( 1 + √2 ) MULTIPLYING in numerator and denominator by conjugate of denominator by ( √2 - 1 ) , we get, => 1 / √x = ( √2 - 1 ) / ( √2 + 1 ) ( √2 - 1 ) We know that, ( a² - b² ) = ( a + b ) ( a - b ) , applying it in denominator , we get, = ( √2 - 1 ) / { ( √2 )² - ( 1 )² } = ( √2 - 1 ) / ( 2 - 1 )
= ( √2 - 1 ) / 1 => 1 / √x = ( √2 - 1 ) Now, √x - 1 / √x = ( 1 + √2 ) + ( √2 - 1 ) = 2√2 |
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| 7. |
What is the value of Root5 |
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Answer» Answer: 2.24 LIKE it follow Step-by-step EXPLANATION: |
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| 8. |
एक बंदर 60 मीटर ऊंची खंबे पर 1मिनट में6 मीटर चढ़ता है परन्तु दूसरे मिनट में3 मीटर नीचे फिसल जाता है तो बताओ वह कितने मिनट में उपर चढ़ जाएगा। |
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Answer» Answer: 20min Step-by-step EXPLANATION: hsgggdggdfhurdhhfggdghbvv |
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| 9. |
The HCF 56 and 488 is expressedin the form of 56x +88y thenfind x and y. |
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Answer» Step-by-step explanation: 丨ㄒ丨丂卄卂 ᎥᏆᎥshᎪ दिल है छोटा सा, छोटी सी आशा A landfill site (also known as a as a MIDDEN[1]) is a site for the disposal of waste materials. Landfill is the OLDEST and most common form of waste disposal, although the systematic burial of the waste is a modern development.A landfill site (also known as a tip, dump, rubbish dump, garbage dump or dumping GROUND and, HISTORICALLY, as a midden[1]) is a site for the disposal of waste materials. Landfill is the oldest and most common form of waste disposal, although the systematic burial of the waste is a modern development.A landfill site (also known as a tip, dump, rubbish dump, garbage dump or dumping ground and, historically, as a midden[1]) is a site for the disposal of waste materials. Landfill is the oldest and most common form of waste disposal, although the systematic burial of the waste is a modern development. |
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| 10. |
-16/9+-5/12 simplifiy |
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Answer» (-16×4)+(-5×3)/36 -64-15/36 -79/36 -2.1944444444 |
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| 11. |
If the area of a rectangle is 12 sq.m, what is the highest possible perimeter |
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Answer» hope it HELPS you..... #AVicci LIVES on..... |
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| 12. |
Himanshu is son of Mr. Gupta. Himanshu is 15 years old. Mr. Gupta is three times older than Himanshu. How old was Mr. Gupta when Himanshu was born? |
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| 13. |
The product of 10th‚12th‚14th‚and 16th terms of G.P is 1296. find the 13th term. |
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Answer» Answer: 6 Step-by-step explanation: Given-----> Product of 10th , 12TH , 14th and 16th terms of GP is 1296 . To find-----> Find the 13th TERM Solution-----> Let first term and COMMON ratio of GIVEN GP be a and r . We know that, formula of nth term of GP is aₙ = a rⁿ⁻¹ => a₁₀ = a r¹⁰ ⁻¹ => a₁₀ = a r⁹ a₁₂ = a r¹²⁻¹ = ar¹¹ a₁₄ = a r¹⁴⁻¹ = a r¹³ a₁₆ = a r¹⁶⁻¹ = a r¹⁵ Now , ATQ, a₁₀ × a₁₂ × a₁₄ × a₁₆ = 1296 => a r⁹ × a r¹¹ × a r¹³ × a r¹⁵ = 1296 => a⁴ r⁹⁺ ¹¹ ⁺¹³ ⁺ ¹⁵ = 1296 => a⁴ r⁴⁸ = 1296 => ( a )⁴ ( r¹² )⁴ = 6 × 6 × 6 × 6 => ( a r¹² )⁴ = 6⁴ => a r¹² = 6 => a r¹³⁻¹ = 6 => a₁₃ = 6 |
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| 14. |
Please do this fast |
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Answer» Step-by-step EXPLANATION: |
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| 15. |
Prove that (1 + tane )2 + (1 + cot 8 )2 = (sec 0+ cosec ). |
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Answer» Step-by-step EXPLANATION: |
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| 16. |
The HCF & 56 488 is expressedin the form of 56x +88y thenfind x and y. |
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Answer» Step-by-step EXPLANATION: Shaam O SUBAH Tu Chahiye丨ㄒ丨丂卄卂 ᎥᏆᎥshᎪ दिल है छोटा सा, छोटी सी आशा |
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| 17. |
The length breath and height of cuboid are in the ratio 5:4:2 if the T.S.A is 1216cm².Find volume of cuboid |
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Answer» Step-by-step EXPLANATION: let length = 5x breadth = 4x HEIGHT = 2x TSA = 1216 Cm² now... TSA of cuboid = 2(lb+bh+hl) 1216 = 2(5x*4x +4x*2x* + 2x*5x) 1216 = 2(20x² + 8x² +10 x²) 1216 = 2(38x2) 1216 = 76 x² 1216/76 = x² 16 = x² 4 = x so.. length= 5x = 4*5 = 20 cm breadth = 4x = 4*4 = 16 cm height= 2x = 4*2 = 8cm 20*16*8 2560 cm³ thank you hope it HELPS ❤️❤️ plz mark it as brainliest |
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| 18. |
A straight highway leads to the foot of thetower, a man standing at the top of the tower,observes a car at an angle of depression of 30°,which is approaching the foot of the tower withuniform speed. Six seconds later, the angle ofdepression of the car is found to be 60°. Find thetime taken by car to reach the foot of the towerfrom this point. |
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Answer» Hye♥♥ Here is the answer. Hope it helped you. |
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| 19. |
Himanshu is son of Mr. Gupta. Himanshu is 15 years old. Mr. Gupta is three times older than Himanshu |
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Answer» 45 Step-by-step EXPLANATION: The answer will be simple |
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| 20. |
How do you make a 120 degree angle and can you put the steps on please! |
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Answer» Step-by-step explanation: 1..first make a line 2..then make a semicircle on it 3..then with the same radius draw two arcs from the same distance 4..then from the CENTRE draw a line withe the second arc |
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| 21. |
If CP of 6 chairs is equals to SP of 4 chairs find the gain percent |
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Answer» Answer: let cp of a CHAIR be x Step-by-step EXPLANATION: the answer is better explained in the PICTURE do refer to it |
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| 22. |
Xd^2y/dx^2+dy/dx+xy=0 |
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Answer» Step-by-step EXPLANATION: 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 丨ㄒ丨丂卄卂 A landfill site (also known as a TIP, dump, rubbish dump, GARBAGE dump or dumping ground and, historically, as a midden[1]) is a site for the disposal of waste materials. Landfill is the oldest and most COMMON form of waste disposal, ALTHOUGH the systematic burial of the waste is a modern development.धड़कन ये कहती है, "दिल तेरे बिन धड़के ना एक तू ही यार मेरा, मुझको क्या दुनिया से लेना?"दिल है छोटा सा, छोटी सी आशा⠀⠀ |
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| 23. |
2p square - 17p + 30 = ? Factorise this |
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Answer» 2p^2 - 17p +30 => 2p^2 - 12P - 5p + 30 => 2p(p - 6) - 5(p - 6) => (2p - 5)(p - 6) Hope it HELPS you. Plz mark BRAINLIEST. |
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| 24. |
if lalitha leaves home and drives to her school at a speed of 45 kmph. she reaches 5 minutes later then when she was drive 60 kmph speed. find the distance to her school |
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Answer» Step-by-step explanation: धड़कन ये कहती है, "दिल तेरे बिन धड़के ना एक तू ही यार मेरा, मुझको क्या दुनिया से लेना?"A landfill site (also known as a tip, dump, rubbish dump, garbage dump or DUMPING GROUND and, historically, as a midden[1]) is a site for the disposal of WASTE MATERIALS. Landfill is the oldest and most common form of waste disposal, although the systematic burial of the waste is a modern development.⠀ ⠀⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀ |
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| 25. |
Probability of getting 3 heads is 0.6 then probability of getting 3 tails is surely be 0.4 true or false |
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Answer» It is certainly false as 0.4 Is the PROBABILITY of not getting 3 heads i.e., it can be 2 or LESS than 2 heads. Please mark as brainliest!! |
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| 27. |
The average age of boys in class is 15.5 years, while girls average age is 16.5 years. the average agevofvtotal students is 16 years. if there are 30 boys innclass then how many girls ? |
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Answer» Step-by-step explanation: AVERAGE AGE of boys in a class is 15.5 years. Average age of girls is 16.5 years. There are 30 boys in class. Let X be the total age of boys . so X/30=15.5 =X=15.5*30=465 Let y be the total age of girls in a class and z be their numbers. so, X+y /30+z=16 465+y =16*30+z 465+y=480+16z y-16z=480-465=15 Now y/z=16.5 y=16.5z putting the value of y in above EQUATION we get 16.5z-16z=15 0.5z=15 z=15*0.5=30 Hence the number of girls in class is 30. |
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| 28. |
Sin theta +cos theta/ sec theta-cosec theta |
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Answer» cos+sec=seck a |
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| 30. |
Prove that the opposite angles of cyclic quadrilateral are supplementry . |
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Answer» A cyclic quadrilateral is a quadrilateral WHOSE vertices all lie on a circle. An example is pictured below: Prove that the OPPOSITE ANGLES in a cyclic quadrilateral that CONTAINS the center of the circle are supplementary.. Hope it helps u my friend.. |
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| 31. |
In ∆PQR , QS bisects angle PQR, PQ=PR and angle PQS =30°find angle R |
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Answer» <P>Answer: Step-by-step explanation: triangle PQR QS is bisector of angle Q then PQ=PR then angle P is 90 hence angle R is 60 |
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| 32. |
Himanshu is son of Mr. Gupta. Himanshu is 15 years old. Mr. Gupta is three times older than Himanshu. How old was Mr. Gupta when Himanshu was born? |
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Answer» Answer: 30 Step-by-step EXPLANATION: Let the AGE of Mr. Gupta be x. Since, mr. Gupta's age is 3 time the age of himanshu and the age of himanshu is 15 Therefore, x= 3*15 x=45 Now, himanshu was born 15 years back Therefore on that time the age of his FATHER WOULD be - 45-15=30 |
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| 33. |
Please help me it's urgent |
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Answer» Step-by-step EXPLANATION: It is solved by USING following formulaes 1. area of circle = 22/7 × R × r 2.circumference of circle = 22/ 7 × d or 2 × 22/7 × r. |
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| 34. |
Of a triangle if its area is equal to 25 areas and height 20 metre |
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Answer» here is UR answer !!!!! |
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| 35. |
The distribution below shows the number of wickets taken by bowlers in one d cricket matches find the mean number of wickets by choosing a suitable method what does the mean signify?Number of wickets 20 - 60, 60 - 100, 100 - 150, 150 - 250, 250 - 350, 350 - 450Number of bowlers 7, 5, 16, 12, 2, 3 |
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Answer» Answer: Mean number of wickets = 153Step-by-step explanation: We are given below the distribution that SHOWS the number of wickets taken by bowlers in ONE day cricket matches; Number of wickets Number of bowlers (f) X X*f 60 - 100 5 80 400 100 - 150 16 125 2000 150 - 250 12 200 2400 250 - 350 2 300 600 350 - 450 3 400 1200 ∑ f = 45 ∑X*f = 6880 Mean formula is given by = Mean = Therefore, mean number of wickets is 153. |
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| 36. |
√sec2x+cosec2x=tanx+cotx |
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Answer» Step-by-step EXPLANATION: |
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| 37. |
Construct triangle xyz if xy = 6 cm ,angle y =105 degree and angle z =40 degree |
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Answer» you can do this by constructing it hope this helps .This is a ROUGH FIGURE |
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| 38. |
A bank gives 10 % simple interest on deposits by senior citizens. Draw a graph to illustrate the relation between the sum deposited and simple interest earned. Find from your graph..... |
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Answer» Answer:To draw the graph we assume the deposit SUM to be RS 1000, Rs 2000, Rs 3000 and Rs 4000. Now we calculate the SI for 1 year for the sum deposit. Sum deposit SI Rs 1000 Rs 2000 Rs 3000 Rs 4000 Plotting the points (1000, 100), (2000, 200), (3000, 300) and (4000, 400), we get the graph as below: Step-by-step explanation: |
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| 39. |
एक बंदर 60 मीटर ऊंची खंबे पर 1मिनट में6 मीटर चढ़ता है परन्तु दूसरे मिनट में3 मीटर नीचे फिसल जाता है तो बताओ वह कितने मिनट में उपर चढ़ जाएगा। जल्दी बताओ |
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Answer» Answer: answer is 20 minutes Step-by-step explanation: inin first time he clience the distance of 6 METRE and 1 minute and then falls falls at three METRES in ANOTHER minute sobai cancelling 6 - 3 = 3 and when we divide 3 by 60 metre in per minute we get the answer 20 minut |
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| 40. |
Numerical expressions... 3×2+8-5 |
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Answer» 3×2+8-5 6+3 9 Step-by-step EXPLANATION: |
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| 41. |
ABCD is a parallelogram. P is the midpoint ofside CD, seg BP meets diagonal AC at X. Prove that3AX = 2AC. |
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Answer» Answer: 2AC=3AX Step-by-step explanation: in triangle ABX and triangle CPX angle ABX=angle CPX.......(alternate ANGLES) angle BAX=angle PCX.....(alternate angles) THEREFORE triangle ABX is similar to triangle CPX by AA test of similarity AB/CP=AX/CX.......corresponding sides of similar triangle AB=2PC.....(AB=CD...opposite side if parallelogram and P is the midpoint of side CD) AX+XC=AC XC=AC-AX 2PC/PC=AX/AC-AX.....(SUBSTITUTE the values) 2AC-2AX=AX 2AC=2AX+AX 2AC=3AX Hence proved.. hope it heps u my friend!! |
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| 42. |
Answer plzzzzzzzzzz fast |
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Answer» Answer: 4th |
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| 44. |
What will be the product if you multiply the double of (x+y) by the triple of (x-y) ? |
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Answer» Step-by-step EXPLANATION: |
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| 45. |
It is known that a box of 600 electric bulbs contains 12 defective bulbs. One bulb is taken out at random from this box. What is the probability that it is a non defective bulb. |
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Answer» Given as : The number of BULB in the box = 600 The number of defective bulb in box = 12 Let The probability that ONE bulb taken out RANDOM is non-defective = p(E) According to question As out of 600 bulbs, 12 bulbs are defective So, The number of non-defective bulb = 600 - 12 = 588 Now, out of 600 bulbs, 1 bulb is chosen in {C_{1}}^{600} And favourable case of chosen non-defective = {C_{1}}^{588} So, probability = \FRAC{{C_{1}}^{588}}{{C_{1}}^{600}} Or, p(E) = \dfrac{588}{600} Or, p(E) = \dfrac{49}{50} Hence, The probability that one bulb taken out random is non-defective is \dfrac{49}{50} . Answer |
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| 46. |
how long will a man take to make a round of a circular field of a radius 21 m cycling at the speed of 8 kilometre per hour |
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Answer» Answer: circumference of the FIELD= 2× 22/7×21 circumference =132 m TIME=DISTANCE/SPEED Time =594/60=9.9 minutes So time TAKEN is 594 seconds or 9.9 minutes |
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| 47. |
8. Find the value of x,y,z in the following figure |
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Answer» thank you for ASKING. |
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| 48. |
9. Find the remainder using remaindertheorem, when 2x+3x2+x+1 is divided byX+½ |
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| 49. |
Is R.1. If the cost of 1 kg of teahind the cost of 6 kg of tea. |
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Answer» Step-by-step explanation: 1 KG = hind 6 kg = hind × 6 |
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