332354 + Interview Questions in Secondary School in Math

1.	In an equalateral trangle ABC, the side EC istrisccted a D. Prove that 9AD'2 = 7AB'2Tell me easiest method
Answer» HOPE it's HELPFUL and PLEASE MARK as BRAINLIEST!!!✌️✌️✌️

Discussion

2.	The angle is one fifth of its supplement Find the measure of the angle
Answer» 36 can be UR ANSWER MATE..........

Discussion

3.	Can the sum of n terms in AP is n square+13n
Answer» $Given \:Sum \:of \:n\:terms \:in \:A.P:\\ (S_{n}) = n^{<klux>2</klux>} + 13n$ $If \: n = <klux>1</klux> \implies S_{1} = 1^{2} + 13\times 1\\= 1+13 = 14$ $If \: n = 2 \implies S_{2} = 2^{2} + 13\times 2\\= 4 + 26 = 30$ $If \: n = 3 \implies S_{3} = 3^{2} + 13\times 3\\= 9 + 39 = 48$ $Now, First \:term (t_{1}) = S_{1} = 14$ $Second\:term (t_{2}) = S_{2} - S_{1} = 30 - 14 \\= 16$ $Third \:term (t_{3}) = S_{3} - S_{2}\\= 48 - 30\\= 18$ $t_{2} - t_{1} = 16 - 14 = 2 \: ---(1)$ $t_{3} - t_{2} = 18 - 16 = 2 \: ---(2)$ /* From (1) and (2) ,*/ $t_{2} - t_{1} =t_{3} - t_{2} = 2$ $\pink { (Difference \:of \: consecutive \:terms }$ $\pink { are \: equal ) }$ $14,16,18, \cdot \cdot \cdot , is \:an \:A.P$ THEREFORE., $\blue { Yes }$ $\green { Sum \:of \:n \: terms \: in \:A.P \:is }$ $\green { in \:form \: n^{2} + 13n }$ •••♪

3.

Can the sum of n terms in AP is n square+13n

Answer»

$Given \:Sum \:of \:n\:terms \:in \:A.P:\\ (S_{n}) = n^{<klux>2</klux>} + 13n$

$If \: n = <klux>1</klux> \implies S_{1} = 1^{2} + 13\times 1\\= 1+13 = 14$

$If \: n = 2 \implies S_{2} = 2^{2} + 13\times 2\\= 4 + 26 = 30$

$If \: n = 3 \implies S_{3} = 3^{2} + 13\times 3\\= 9 + 39 = 48$

$Now, First \:term (t_{1}) = S_{1} = 14$

$Second\:term (t_{2}) = S_{2} - S_{1} = 30 - 14 \\= 16$

$Third \:term (t_{3}) = S_{3} - S_{2}\\= 48 - 30\\= 18$

$t_{2} - t_{1} = 16 - 14 = 2 \: ---(1)$

$t_{3} - t_{2} = 18 - 16 = 2 \: ---(2)$

/* From (1) and (2) ,*/

$t_{2} - t_{1} =t_{3} - t_{2} = 2$

$\pink { (Difference \:of \: consecutive \:terms }$

$\pink { are \: equal ) }$

$14,16,18, \cdot \cdot \cdot , is \:an \:A.P$

THEREFORE.,

$\blue { Yes }$

$\green { Sum \:of \:n \: terms \: in \:A.P \:is }$

$\green { in \:form \: n^{2} + 13n }$

•••♪

Discussion

4.	If p square + 1 divided by p square = 7 find the value of P + 1 by P where p is greater than zero
Answer» <P>Answer: ±3 Step-by-step explanation: It is given that: p² + 1/p² = 7 Add 2 on both sides: p² + 1/p² + 2 = 7 + 2 we can write above EQUATION as: p² + 1/p² + 2×p×1/p = 9 (p + 1/p)² = 9 {SINCE a² + b² +2AB = (a+b)²} Therefore: p + 1/p = ±3 I hope it is helpful for you......... Plzzz mark me as branliest......

4.

If p square + 1 divided by p square = 7 find the value of P + 1 by P where p is greater than zero

Answer»

<P>Answer:

±3

Step-by-step explanation:

It is given that:

p² + 1/p² = 7

Add 2 on both sides:

p² + 1/p² + 2 = 7 + 2

we can write above EQUATION as:

p² + 1/p² + 2×p×1/p = 9

(p + 1/p)² = 9 {SINCE a² + b² +2AB = (a+b)²}

Therefore:

p + 1/p = ±3

I hope it is helpful for you.........

Plzzz mark me as branliest......

Discussion

5.	If a=3 find the value of 7a/2-6
Answer» ANSWER: The value of $\frac{7a}{2}-6$ is $\frac{<klux>3</klux>}{2}$ . Step-by-step explanation: The value of the EXPRESSION on substituting a = 3 is: $\frac{7a}{2}-6=\frac{7\times3}{2}-6=\frac{21}{2}-6=\frac{21-12}{6} =\frac{9}{6}=\frac{3}{2}$ Thus, the value of $\frac{7a}{2}-6$ is $\frac{3}{2}$ .

5.

If a=3 find the value of 7a/2-6

Answer»

ANSWER:

The value of $\frac{7a}{2}-6$ is $\frac{<klux>3</klux>}{2}$ .

Step-by-step explanation:

The value of the EXPRESSION on substituting a = 3 is:

$\frac{7a}{2}-6=\frac{7\times3}{2}-6=\frac{21}{2}-6=\frac{21-12}{6} =\frac{9}{6}=\frac{3}{2}$

Thus, the value of $\frac{7a}{2}-6$ is $\frac{3}{2}$ .

Discussion

6.	Draw the graph of the equation x-y+1=0 and 3x+2y-12=0 . Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis and shade the tringular region.
Answer» ANSWER: SORRY BRO I don't KNOW the answer of

6.

Draw the graph of the equation x-y+1=0 and 3x+2y-12=0 . Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis and shade the tringular region.

Answer»

ANSWER:

SORRY BRO I don't KNOW the answer of

Discussion

7.	13 sin a =10find sec a + tan a
Answer» Step-by-step EXPLANATION: ANSWER is √69/3 and it MAY be 23/√69 √69/3 we GET this after RATIONALISATION

7.

13 sin a =10find sec a + tan a

Answer»

Step-by-step EXPLANATION:

ANSWER is

√69/3 and it MAY be 23/√69

√69/3 we GET this after RATIONALISATION

Discussion

8.	Write the degree of p(x) 7xcube (x square - 5)
Answer» ANSWER: Its 5 ( five) Step-by-step explanation: Your polynomial $p(x) \\= 7x^3 ( x^2-5)\\= 7x^{3+2} - 7x\times5\\=7x^5-35x\\$ THUS highest POWER of $x$ is $5$ Hence, the DEGREE of $p(x)$ is $5$ Hope it HELPS! Mark as BRAINLIEST

8.

Write the degree of p(x) 7xcube (x square - 5)

Answer»

ANSWER:

Its 5 ( five)

Step-by-step explanation:

Your polynomial

$p(x) \\= 7x^3 ( x^2-5)\\= 7x^{3+2} - 7x\times5\\=7x^5-35x\\$

THUS highest POWER of $x$ is $5$

Hence, the DEGREE of $p(x)$ is $5$

Hope it HELPS!

Mark as BRAINLIEST

Discussion

9.	The diameter of a solid cone of radius r is same as it's height . The volume of cone is
Answer» Answer: 1/3πr^3................

9.

The diameter of a solid cone of radius r is same as it's height . The volume of cone is

Answer»

Answer:

1/3πr^3................

Discussion

10.	The numerator of a rational number is 3 less than the denominator. If the numerator is increasedby 8 and the denominator increased by 14, we get the same number. Find the number.
Answer» 3/8 X/14 = x x 8 = 3 x 14 = 3x14 = 168

Discussion

11.	The sum of my digits is 7.my products are the same.what number am i????
Answer» MAY be the NUMBER is 7...

Discussion

12.	How much does 3 1/4 go into 18
Answer» Answer: 58 1/2 Step-by-step explanation: 3 1/4=13/4 13/4 *18=117/2=58 1/2

12.

How much does 3 1/4 go into 18

Answer»

Answer:

58 1/2

Step-by-step explanation:

3 1/4=13/4

13/4 *18=117/2=58 1/2

Discussion

13.	A car travel 180km in 2 1/2 hours. In what time will it cover 60km .How much distance can it cover in 7 hours
Answer» Answer: 1. 50 minutes 2. 504 km Step-by-step explanation: 1. speed = distance / time speed of CAR = 180 km / 2.5 hours speed of car = 72 km/HR Time it takes to REACH 60 km ; time = distance / speed = 60 km / 72 km/hr = 0.8333 hr or 50 minutes 2. distance it can cover in 7 hours distance = speed x time = 72 km/hr x 7 hr = 504 km

13.

A car travel 180km in 2 1/2 hours. In what time will it cover 60km .How much distance can it cover in 7 hours

Answer»

Answer:

1. 50 minutes 2. 504 km

Step-by-step explanation:

1. speed = distance / time

speed of CAR = 180 km / 2.5 hours

speed of car = 72 km/HR

Time it takes to REACH 60 km ;

time = distance / speed

= 60 km / 72 km/hr

= 0.8333 hr or 50 minutes

2. distance it can cover in 7 hours

distance = speed x time

= 72 km/hr x 7 hr

= 504 km

Discussion

14.	Point \blue{A}Astart color #6495ed, A, end color #6495ed is at \blue{(-2, 4)}(−2,4)start color #6495ed, left parenthesis, minus, 2, comma, 4, right parenthesis, end color #6495ed and point \green{B}Bstart color #28ae7b, B, end color #28ae7b is at \green{(7, 3)}(7,3)start color #28ae7b, left parenthesis, 7, comma, 3, right parenthesis, end color #28ae7b.What is the midpoint of line segment \overline{AB} ABstart overline, A, B, end overline?
Answer» Answer: Point \blue{A}Astart color #6495ed, A, end color #6495ed is at \blue{(-2, 4)}(−2,4)START color #6495ed, left parenthesis, MINUS, 2, comma, 4, right parenthesis, end color #6495ed and point \green{B}Bstart color #28ae7b, B, end color #28ae7b is at \green{(7, 3)}(7,3)start color #28ae7b, left parenthesis, 7, comma, 3, right parenthesis, end color #28ae7b. What is the midpoint of LINE segment \OVERLINE{AB} AB start overline, A, B, end overline?

14.

Point \blue{A}Astart color #6495ed, A, end color #6495ed is at \blue{(-2, 4)}(−2,4)start color #6495ed, left parenthesis, minus, 2, comma, 4, right parenthesis, end color #6495ed and point \green{B}Bstart color #28ae7b, B, end color #28ae7b is at \green{(7, 3)}(7,3)start color #28ae7b, left parenthesis, 7, comma, 3, right parenthesis, end color #28ae7b.What is the midpoint of line segment \overline{AB} ABstart overline, A, B, end overline?

Answer»

Answer:

Point \blue{A}Astart color #6495ed, A, end color #6495ed is at \blue{(-2, 4)}(−2,4)START color #6495ed, left parenthesis, MINUS, 2, comma, 4, right parenthesis, end color #6495ed and point \green{B}Bstart color #28ae7b, B, end color #28ae7b is at \green{(7, 3)}(7,3)start color #28ae7b, left parenthesis, 7, comma, 3, right parenthesis, end color #28ae7b.

What is the midpoint of LINE segment \OVERLINE{AB} AB

start overline, A, B, end overline?

Discussion

15.	TanA + secA =4, then what is the value of sinA
Answer» Answer 15/17 Explanation TANA + secA = 4 We can WRITE it as, sinA/cosA + 1/cosA = 4 → (sinA + 1)/cosA = 4 → sinA + 1 = 4cosA Now squaring both sides, (sinA + 1)² = (16cosA)² → sin²A + 1 + 2sinA = 16cos²A Replace cos²A as 1 - sin²A (SINCE, cos²A + sin²A = 1) → sin²A + 1 + 2sinA = 16(1 - sin²A) → sin²A + 1 + 2sinA = 16 - 16sin²A → sin²A + 16sin²A + 1 - 16 + 2sinA = 0 → 17sin²A + 2sinA - 15 = 0 Now, splitting the middle term → 17sin²A + 17sinA - 15sinA - 15 = 0 → 17sinA(sinA + 1) - 15(sinA + 1) = 0 → (17sinA - 15)(sinA + 1) = 0 → 17sinA - 15 = 0 or sinA + 1 = 0 → sinA = 15/17 or sinA = -1 But, for sinA = -1, tanA becomes undefined. Hence, we will neglect this VALUE.

15.

TanA + secA =4, then what is the value of sinA

Answer»

Answer

15/17

Explanation

TANA + secA = 4

We can WRITE it as,

sinA/cosA + 1/cosA = 4

→ (sinA + 1)/cosA = 4

→ sinA + 1 = 4cosA

Now squaring both sides,

(sinA + 1)² = (16cosA)²

→ sin²A + 1 + 2sinA = 16cos²A

Replace cos²A as 1 - sin²A (SINCE, cos²A + sin²A = 1)

→ sin²A + 1 + 2sinA = 16(1 - sin²A)

→ sin²A + 1 + 2sinA = 16 - 16sin²A

→ sin²A + 16sin²A + 1 - 16 + 2sinA = 0

→ 17sin²A + 2sinA - 15 = 0

Now, splitting the middle term

→ 17sin²A + 17sinA - 15sinA - 15 = 0

→ 17sinA(sinA + 1) - 15(sinA + 1) = 0

→ (17sinA - 15)(sinA + 1) = 0

→ 17sinA - 15 = 0 or sinA + 1 = 0

→ sinA = 15/17 or sinA = -1

But, for sinA = -1, tanA becomes undefined. Hence, we will neglect this VALUE.

Discussion

16.	What is ∫cos x dx =?
Answer» ANSWER: I CANT UNDERSTAND your QUESTION....

16.

What is ∫cos x dx =?

Answer»

ANSWER:

I CANT UNDERSTAND your QUESTION....

Discussion

17.	Raunk's father is 56 years old. He is seven times as old as Raunak. How old will be Raunak five years
Answer» Step-by-step EXPLANATION: let the RAUNAK AGE be 7x then age of his father is 56 years Therefore, the age of raunak is 7x=56 x=56/7=8 years so the age of raunak is 8 years

17.

Raunk's father is 56 years old. He is seven times as old as Raunak. How old will be Raunak five years

Answer»

Step-by-step EXPLANATION:

let the RAUNAK AGE be 7x

then age of his father is 56 years

Therefore,

the age of raunak is 7x=56

x=56/7=8 years

so the age of raunak is 8 years

Discussion

18.	Find derivative of x²-cosx/sinx
Answer» Step-by-step EXPLANATION: your ANSWER ATTACHED in the PHOTO

18.

Find derivative of x²-cosx/sinx

Answer»

Step-by-step EXPLANATION:

your ANSWER ATTACHED in the PHOTO

Discussion

19.	If m parallel n and angle a ratio angle b is equal to 2ratio 3 then find the measure of angle h
Answer» BROTHER pls ATTACH the image becz the QUESTION can't be understood WITHOUT the FIGURE

19.

If m parallel n and angle a ratio angle b is equal to 2ratio 3 then find the measure of angle h

Answer»

BROTHER pls ATTACH the image becz the QUESTION can't be understood WITHOUT the FIGURE

Discussion

20.	What is the formula to find the sum of series
Answer» ANSWER: sum of SERIES HMMM.... An ap QUESTION... Step-by-step explanation: S=n/2(2a+(n-1)d)...

20.

What is the formula to find the sum of series

Answer»

ANSWER:

sum of SERIES HMMM.... An ap QUESTION...

Step-by-step explanation:

S=n/2(2a+(n-1)d)...

Discussion

21.	(a)find the area of the region enclosed by y^2 = x and y=x-2
Answer» SORRY, I can't UNDERSTAND what was you ASKING

21.

(a)find the area of the region enclosed by y^2 = x and y=x-2

Answer»

SORRY, I can't UNDERSTAND what was you ASKING

Discussion

22.	7 = 2x -5please tell me it's answer is 6
Answer» ANSWER: x=6 Step-by-step explanation: 7=2x-5 7+5=2x x=12/2 x=6 Hope it *HELPS*

22.

7 = 2x -5please tell me it's answer is 6

Answer»

ANSWER:

x=6

Step-by-step explanation:

7=2x-5

7+5=2x

x=12/2

x=6

Hope it HELPS

Discussion

23.	The hypotenuse of a right triangle is 65 CM and one leg is 25 cm. find the length of the Other leg
Answer» Answer: I think it's 60 c.m. Sorry can't explain , LACK of time . Can u PLZ mark as BRAINLIEST

23.

The hypotenuse of a right triangle is 65 CM and one leg is 25 cm. find the length of the Other leg

Answer»

Answer:

I think it's 60 c.m.

Sorry can't explain , LACK of time .

Can u PLZ mark as BRAINLIEST

Discussion

24.	Multiple = 188 into= 19 answer with formula
Answer» Answer: 188*19=......................

24.

Multiple = 188 into= 19 answer with formula

Answer»

Answer:

188*19=......................

Discussion

25.	An equilateral triangle whose side is denoted by x
Answer» ANSWER: PLEASE MARK me as brainlest Step-by-step EXPLANATION: I REQUEST you

25.

An equilateral triangle whose side is denoted by x

Answer»

ANSWER:

PLEASE MARK me as brainlest

Step-by-step EXPLANATION:

I REQUEST you

Discussion

26.	4. A rectangular piece of ground is 45 m long and 30 m wide. It has two roads each 1 mwide, running midway within it, one parallel to the length and the other parallel to thebreadth. Find the area of the roads. Also calculate the area of the remaining ground.
Answer» RECTANGULAR piece of ground = LENGTH x BREATH = 45 x 30 The AREA of the road =30x1 = 30 The Area of the second road= 45×1 = 45

Discussion

27.	Find the mode of following data 4 6 5 9 3 2 7 9 7 9 6 5 4 9 10 10 3 4 7 6
Answer» $\huge\mathbb\red{HOLAMATE}$ The MODE of the GIVEN DATA is 10. $\huge\mathbb{THANKYOU}$

27.

Find the mode of following data 4 6 5 9 3 2 7 9 7 9 6 5 4 9 10 10 3 4 7 6

Answer»

$\huge\mathbb\red{HOLAMATE}$

The MODE of the GIVEN DATA is 10.

$\huge\mathbb{THANKYOU}$

Discussion

28.	Please answer this question:Two years ago, my age was 4 times theage of my son. Six years ago, my age wastwice the square of the age of my son. Whatis the present age of my son?"olution:
Answer» Answyes jih Step-by-step EXPLANATION:

28.

Please answer this question:Two years ago, my age was 4 times theage of my son. Six years ago, my age wastwice the square of the age of my son. Whatis the present age of my son?"olution:

Answer»

Answyes jih

Step-by-step EXPLANATION:

Discussion

29.	Find two positive integers X and Y such that X + Y equal to 60 and xyis maximum
Answer» ANSWER: X=30 and Y=30 Step-by-step explanation: 30+30=60

29.

Find two positive integers X and Y such that X + Y equal to 60 and xyis maximum

Answer»

ANSWER:

X=30 and Y=30

Step-by-step explanation:

30+30=60

Discussion

30.	Draw a triangle for the given question please
Answer» Step-by-step explanation: Follow the rough diagram given And draw according to it Hope it HELP U ❣️ Mark it as a brainlist anwer Follow me BYE

30.

Draw a triangle for the given question please

Answer»

Step-by-step explanation:

Follow the rough diagram given

And draw according to it

Hope it HELP U ❣️

Mark it as a brainlist anwer

Follow me

BYE

Discussion

31.	In triangle ABC and triangle PQR,l(AB)=l(PR),angle A correspondent to angleR,angle B correspondent to angle P.what the correspondence for which,given triangle are congruent
Answer» Answer: hey Step-by-step explanation: could u PLS show the PICTURE next time as what your explanation just now isn't CLEAR but I dont care as my maths is over for EXAMS

31.

In triangle ABC and triangle PQR,l(AB)=l(PR),angle A correspondent to angleR,angle B correspondent to angle P.what the correspondence for which,given triangle are congruent

Answer»

Answer:

hey

Step-by-step explanation:

could u PLS show the PICTURE next time as what your explanation just now isn't CLEAR but I dont care as my maths is over for EXAMS

Discussion

32.	Please solve it someone
Answer» Answer: ise solve KRNE KI kya JARURAT HAI sidha Apne FLOWER lagao na

32.

Please solve it someone

Answer»

Answer:

ise solve KRNE KI kya JARURAT HAI sidha Apne FLOWER lagao na

Discussion

33.	Anyone from CBSE class 9 can send me annual exam question paper .
Answer» hi MATE I am in CLASS 9 *this is the question paper* of maths..... *my exams are GOING* on I can send you the question paper of English and Hindi *too* ....... *to get more question* *papers* *mark my brainiest* and FOLLOW me and ASK the same question one more time**

33.

Anyone from CBSE class 9 can send me annual exam question paper .

Answer»

hi MATE I am in CLASS 9

this is the question paper of maths.....

my exams are GOING on I can send you the question paper of English and Hindi too .......

to get more question papers mark my brainiest and FOLLOW me and ASK the same question one more time

Discussion

34.	ABCD is a rectangle. Its diagonals meet at O. Find the length of its diagonal, if AO=7a-3 and OD=4a-1.
Answer» ANSWER: i THINK the answer is 5 Step-by-step EXPLANATION: SINCE DIAGONALS are equal at midpoint o then 7a-3=4a-1

34.

ABCD is a rectangle. Its diagonals meet at O. Find the length of its diagonal, if AO=7a-3 and OD=4a-1.

Answer»

ANSWER:

i THINK the answer is 5

Step-by-step EXPLANATION:

SINCE DIAGONALS are equal at midpoint o then

7a-3=4a-1

Discussion

35.	Express 0.5%per month as % per annum
Answer» PER MONTH%=0.5 Per ANNUM%=0.5*12 =6%p.a.

Discussion

36.	How much is 2x+4=8 step-by -step
Answer» ANSWER: X = 2 Step-by-step explanation: 2x = 8-4 x = 4/2 x = 2 *HOPE* *THIS* *HELPS* *YOU*......

36.

How much is 2x+4=8 step-by -step

Answer»

ANSWER:

X = 2

Step-by-step explanation:

2x = 8-4

x = 4/2

x = 2

HOPE THIS HELPS YOU......

Discussion

37.	7kg 8g 2 dag convert into gram
Answer» ANSWER: 7028 g Step-by-step explanation: 1kg = 1000g 1dag = 10g 7kg 8G 2 DAG = [ (7×1000) + (8) + (2×10) ] g = (7000+8+20) g = 7028 g

37.

7kg 8g 2 dag convert into gram

Answer»

ANSWER: 7028 g

Step-by-step explanation:

1kg = 1000g

1dag = 10g

7kg 8G 2 DAG

= [ (7×1000) + (8) + (2×10) ] g

= (7000+8+20) g

= 7028 g

Discussion

38.	A-(a instersection b) for two sets a, b is
Answer» ANSWER: a={1,2,3},B={1,2} Step-by-step EXPLANATION: a INTERSECTION b is 1,2 1,2,3-1,2 3

38.

A-(a instersection b) for two sets a, b is

Answer»

ANSWER:

a={1,2,3},B={1,2}

Step-by-step EXPLANATION:

a INTERSECTION b is 1,2

1,2,3-1,2

3

Discussion

39.	4)In a class of 50 students, 40% are girls. Find the number of girls and number ofboys in the class.
Answer» there will be 20 GIRLS and 30 BOYS

Discussion

40.	What is the grooves in the screw called as
Answer» Answer: All screws R designed with external threading so that they can be driven into an object or SURFACE... On the shaft of a typical screw, you'll SEE helical GROOVES.. Known as external threading, these grooves essentially DIG material out of the object or surface in which the screw is inserted...

40.

What is the grooves in the screw called as

Answer»

Answer:

All screws R designed with external threading so that they can be driven into an object or SURFACE... On the shaft of a typical screw, you'll SEE helical GROOVES.. Known as external threading, these grooves essentially DIG material out of the object or surface in which the screw is inserted...

Discussion

41.	the total cultivating rectangular field at rupees 45 per metre square is rupees 6750 if the length of the field is 25 then find its breadth
Answer» Step-by-step EXPLANATION: LENGTH OF FIELD=6750/25=270 FIND THE BREADTH=270/45=6m SO,THE BREADTH OF RECTANGULAR FIELD IS 6m²

41.

the total cultivating rectangular field at rupees 45 per metre square is rupees 6750 if the length of the field is 25 then find its breadth

Answer»

Step-by-step EXPLANATION:

LENGTH OF FIELD=6750/25=270

FIND THE BREADTH=270/45=6m

SO,THE BREADTH OF RECTANGULAR FIELD IS 6m²

Discussion

42.	Express 5 paise per ₹ per annum as % per annum
Answer» Step-by-step EXPLANATION: =0.05/100×1 =0.0005%

42.

Express 5 paise per ₹ per annum as % per annum

Answer»

Step-by-step EXPLANATION:

=0.05/100×1

=0.0005%

Discussion

43.	Find values of i ) sin pi by 8 ii)Cos pi by 8
Answer» ANSWER: answer below... Step-by-step EXPLANATION: sinπ/8 =sin22/7/8 =sin22x1/7×8 =sin11/7x4 =$in11/28... cosπ/8 same as the FIRST =©os11/28....

43.

Find values of i ) sin pi by 8 ii)Cos pi by 8

Answer»

ANSWER:

answer below...

Step-by-step EXPLANATION:

sinπ/8

=sin22/7/8

=sin22x1/7×8

=sin11/7x4

=$in11/28...

cosπ/8

same as the FIRST

=©os11/28....

Discussion

44.	361cube+139cube/361square-(361*139)+139square
Answer» Answer:500 STEP by step EXPLANATION: $\frac{ {361}^{3} + {139}^{3} }{ {361}^{2} - (361 \times 139) + {139}^{2} } = \frac{(361 + 139)( {361}^{2} - (361 \times 139) + {139}^{2}) }{ {262}^{2} - (361 - 139) + {139}^{2} } \\ since \: \: a ^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} ) \\ answer = 361 + 139 = 500$ Hope it helps you... please MARK it as BRAINLIEST...

44.

361cube+139cube/361square-(361*139)+139square

Answer»

Answer:500

STEP by step EXPLANATION:

$\frac{ {361}^{3} + {139}^{3} }{ {361}^{2} - (361 \times 139) + {139}^{2} } = \frac{(361 + 139)( {361}^{2} - (361 \times 139) + {139}^{2}) }{ {262}^{2} - (361 - 139) + {139}^{2} } \\ since \: \: a ^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} ) \\ answer = 361 + 139 = 500$

Hope it helps you...

please MARK it as BRAINLIEST...

Discussion

45.	C and b have one person between e and f means ?
Answer» Answer is d. Explanation: We KNOW that, there are 26 alphabets in English language. They are: FIRST alphabet: a Second alphabet: b Third alphabet: c Fourth alphabet: d Fifth alphabet: e Sixth alphabet: f Seventh alphabet: g Similarly, there are 26 alphabets. According to the QUESTION, c and b have one PERSON between e and f. It means, a alphabet exists between b and c and e and f. The alphabet which exists between them is NOTHING but d. Therefore, d is the required answer.

45.

C and b have one person between e and f means ?

Answer»

Answer is d.

Explanation:

We KNOW that, there are 26 alphabets in English language. They are:

FIRST alphabet: a
Second alphabet: b
Third alphabet: c
Fourth alphabet: d
Fifth alphabet: e
Sixth alphabet: f
Seventh alphabet: g

Similarly, there are 26 alphabets.

According to the QUESTION, c and b have one PERSON between e and f.
It means, a alphabet exists between b and c and e and f.
The alphabet which exists between them is NOTHING but d.

Therefore, d is the required answer.

Discussion

46.	two cylindrical vassels have their base radi as16cm and 8cm respestively .if their height are 8 cm and 16 cm respectively then find the ratio of their volume
Answer» ANSWER: *Hye♥♥ Here* is *the* *answer. Hope* it *helped* *you. PLEASE* *mark* it *the* *BRAIN* *list*.

46.

two cylindrical vassels have their base radi as16cm and 8cm respestively .if their height are 8 cm and 16 cm respectively then find the ratio of their volume

Answer»

ANSWER:

Hye♥♥

Here is the answer.

Hope it helped you.

PLEASE mark it the BRAIN list.

Discussion

47.	Find the value of 20% of Rs 150.
Answer» Answer:HEYY heres Your answer ☺️❤☺️ 20 % × 150 = 20 × 150 / 100 = 30 20% of 150 = 150 - 30 = 120 .

47.

Find the value of 20% of Rs 150.

Answer»

Answer:HEYY heres Your answer ☺️❤☺️

20 % × 150

= 20 × 150 / 100

= 30

20% of 150 = 150 - 30

= 120 .

Discussion

48.	21. A box contains 28 bulbs of which 7 bulbs are defective, a bulb is drawnrandomly from the box. Find the probability of picking a non-defectivebulb.
Answer» ANSWER: the no of which are NON defective=28-7=21 the PROBABILITY of event=21/28=3/4

48.

21. A box contains 28 bulbs of which 7 bulbs are defective, a bulb is drawnrandomly from the box. Find the probability of picking a non-defectivebulb.

Answer»

ANSWER:

the no of which are NON defective=28-7=21

the PROBABILITY of event=21/28=3/4

Discussion

49.	A biscuit manufacturer uses 200g of flour, 50g of sugar and 100g of butter for each packet of biscuits produced. The expression that describes the amount of butter needed (in kg), to produce x packets of biscuits is
Answer» ANSWER: a is equal to bq +R FORMULAE laggao YA quadratic EQUATION wal

49.

A biscuit manufacturer uses 200g of flour, 50g of sugar and 100g of butter for each packet of biscuits produced. The expression that describes the amount of butter needed (in kg), to produce x packets of biscuits is

Answer»

ANSWER:

a is equal to bq +R FORMULAE laggao YA quadratic EQUATION wal

Discussion

50.	Area of triangle whose vertices are 0,5 3,8 5,6
Answer» Answer: 1/2 into X1( Y2 -Y3)+X2(y3-y1)+x3(y1-y2) apply this FORMULAE

50.

Area of triangle whose vertices are 0,5 3,8 5,6

Answer»

Answer:

1/2 into X1( Y2 -Y3)+X2(y3-y1)+x3(y1-y2) apply this FORMULAE

Discussion

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