332354 + Interview Questions in Secondary School in Math

1.	Find the missing fraction : 8/10 - (?) = 3/10
Answer» Answer: 5/10 or 1/2 Step-by-step explanation: 8/10-(?)=3/10 (?)=8/10-3/10 =5/10 =1/2 Hope it helps

1.

Find the missing fraction : 8/10 - (?) = 3/10

Answer»

Answer:

5/10 or 1/2

Step-by-step explanation:

8/10-(?)=3/10

(?)=8/10-3/10

=5/10 =1/2

Hope it helps

Discussion

2.	4. If the edge of a cube is 1 cm then its volume isa. 6cmb. 3cmc. 1cmd. 1cm
Answer» Answer: 6^3=216cm^3 3^3=27cm^3 1cm=1cm^3

2.

4. If the edge of a cube is 1 cm then its volume isa. 6cmb. 3cmc. 1cmd. 1cm

Answer»

Answer:

6^3=216cm^3

3^3=27cm^3

1cm=1cm^3

Discussion

3.	Find the HCF of(1). 196&38220(2). 135&225
Answer» Answer: 1) 195 2) 45 Step-by-step explanation: 38220÷196=195 since the remainder is ZERO HCF is 195 2)225÷135=1 and 90 is remainder remainder is GREATER than 0 again dividing 135 by 90 135÷90=1 and 45 is remainder remainder is greater than 0 again dividing 90 by 45 90÷45=2 remainder is 0 since the remainder is 0 45 is the HCF

3.

Find the HCF of(1). 196&38220(2). 135&225

Answer»

Answer:

1) 195

2) 45

Step-by-step explanation:

38220÷196=195

since the remainder is ZERO HCF is 195

2)225÷135=1 and 90 is remainder

remainder is GREATER than 0 again dividing 135 by 90

135÷90=1 and 45 is remainder

remainder is greater than 0 again dividing 90 by 45

90÷45=2 remainder is 0

since the remainder is 0 45 is the HCF

Discussion

4.	In a meeting all members shook hands with each other actually ,every one shook hands with every other member .The number of handshakes depends on the number of people present find a formula to find the number of handshakes for n people?
Answer» ANSWER:N(n-1)/2 Step-by-step EXPLANATION:

4.

In a meeting all members shook hands with each other actually ,every one shook hands with every other member .The number of handshakes depends on the number of people present find a formula to find the number of handshakes for n people?

Answer»

ANSWER:N(n-1)/2

Step-by-step EXPLANATION:

Discussion

5.	26.Rani types 450 words in half an hour. How many words would she type in 12minutes?
Answer» Answer: 180 words Step-by-step explanation: In 30 min RANI types= 450 words In 1 min Rani types=450/30 =>15 words So, in 12 min Rani types =12x15=180 words

5.

26.Rani types 450 words in half an hour. How many words would she type in 12minutes?

Answer»

Answer:

180 words

Step-by-step explanation:

In 30 min RANI types= 450 words

In 1 min Rani types=450/30

=>15 words

So, in 12 min Rani types =12x15=180 words

Discussion

6.	2 litre 40 millilitre = ________ ml
Answer» Answer: 2 LITRE + 40 ML= 2040 ml ....

6.

2 litre 40 millilitre = ________ ml

Answer»

Answer:

2 LITRE + 40 ML= 2040 ml

....

Discussion

7.	Find the value of 6 tan square theta minus cos square theta
Answer» Step-by-step explanation: sorry I can't possible to GIVE answer I READ CLASS 9

7.

Find the value of 6 tan square theta minus cos square theta

Answer»

Step-by-step explanation:

sorry I can't possible to GIVE answer I READ CLASS 9

Discussion

8.	Can you create a word problem related to the Pythagoras theorem and then use the theorem to solve the word problem? your answer should include the word problem and THE STEP-BY-STEP solution of the word problem. add as much detail and a diagram if needed
Answer» ANSWER: a2+b2=c2 Step-by-step EXPLANATION: AHG= ssd =ead =2×3=6

8.

Can you create a word problem related to the Pythagoras theorem and then use the theorem to solve the word problem? your answer should include the word problem and THE STEP-BY-STEP solution of the word problem. add as much detail and a diagram if needed

Answer»

ANSWER:

a2+b2=c2

Step-by-step EXPLANATION:

AHG= ssd

=ead

=2×3=6

Discussion

9.	Sherya is 5 years older than akshita. The product of their age is 234.how old is akshita
Answer» Answer: Given Information:- Shreya is 5 year older than Akshita. Product of their ages is 234 years. To Find:- Age of Akshita ___________... Let, the age of Akshita be : $\tt{a}$ Hence, the age of Shreya will be : $\tt{a+5}$ (You can REPLACE the variable alphabet by any other alphabet) Total age of them yields : $\tt{234 \ years}$ ACCORDING THE QUESTION:- $\tt{a+(a+5)=234}$ (EQUATION formation to get the suitable value of x) $\tt{\implies a+a+5=234}$ (Brackets are now removed) $\tt{\implies 2a+5=234}$ (We have now added the variables) $\tt{\implies 2a = 234-5}$ (Taken +5 to the Right hand side and turned into it's opposite) $\tt{\implies 2a=229}$ (Subtracted 5 from 234) $\boxed{\tt\green{\implies a = \frac {229}{2}}}$ (Hence, value of x is now found!!) $\boxed{\rm{Age \ of \ Akshita}}$ ) _______... REQUIRED ANSWER:- $\tt{\therefore}$ The age of Akshita is $\tt\green{\frac {229}{2} \ or \ 115 \ years}$ (ROUNDED off age of Akshita).

9.

Sherya is 5 years older than akshita. The product of their age is 234.how old is akshita

Answer»

Answer:

Given Information:-

Shreya is 5 year older than Akshita.
Product of their ages is 234 years.

To Find:-

Age of Akshita

___________...

Let, the age of Akshita be : $\tt{a}$

Hence, the age of Shreya will be : $\tt{a+5}$

(You can REPLACE the variable alphabet by any other alphabet)

Total age of them yields : $\tt{234 \ years}$

ACCORDING THE QUESTION:-

$\tt{a+(a+5)=234}$

(EQUATION formation to get the suitable value of x)

$\tt{\implies a+a+5=234}$

(Brackets are now removed)

$\tt{\implies 2a+5=234}$

(We have now added the variables)

$\tt{\implies 2a = 234-5}$

(Taken +5 to the Right hand side and turned into it's opposite)

$\tt{\implies 2a=229}$

(Subtracted 5 from 234)

$\boxed{\tt\green{\implies a = \frac {229}{2}}}$

(Hence, value of x is now found!!)

$\boxed{\rm{Age \ of \ Akshita}}$ )

_______...

REQUIRED ANSWER:-

$\tt{\therefore}$ The age of Akshita is $\tt\green{\frac {229}{2} \ or \ 115 \ years}$ (ROUNDED off age of Akshita).

Discussion

10.	(16 cmA circle with radius 16 cm is cut into four equal parts and re-arranged toform another shape as shown in the figure. Does the perimeter change? If itdoes, by how much does it increase or decrease? (NCERT Exemplar)
Answer» Where is the FIGURE MATE

10.

(16 cmA circle with radius 16 cm is cut into four equal parts and re-arranged toform another shape as shown in the figure. Does the perimeter change? If itdoes, by how much does it increase or decrease? (NCERT Exemplar)

Answer»

Where is the FIGURE MATE

Discussion

11.	Find the area of quadrilateral abcd in which ab=9cm bc=12cm cd=5cm da=8cm and c=90°
Answer» Answer: 66 cm² Step-by-step explanation: First draw a diagonal BD. Now in ∆BCD, BC = 12 cm CD = 5 cm BD = √BC²+CD² = √12²+5² = √144+25 = √169 = 13 cm Therefore, BD = 13 cm Now, ar(BCD) = ½×b×h = ½×5×12 = 30 cm² In ∆ABD, a = 8 cm b = 9 cm c = 13 cm s(Semi-Perimeter) = a+b+c/2 = 8+9+13/2 = 30/2 = 15 cm Therefore, ar(ABD) = √s(s-a)(s-b)(s-c) = √15(15-8)(15-9)(15-13) = √15×7×6×2 = √3×5×7×3×2×2 (SINCE 15=3×5 & 6=3×2) = √3×3×2×2×7×5 =3×2 √7×5 = 6 × √35 = 6×6 (Since √36= 6 and √35 is close to √36 ) = 36 cm² Therefore, ar(ABCD) = ar(BCD) + ar(ABD) = 30+36 = 66 cm² approx. I *hope* *you* *understood* my *explanation* *Plzz* *MARK* my *answer* as *brainliest* *Thank* *you... TAUTIK*

11.

Find the area of quadrilateral abcd in which ab=9cm bc=12cm cd=5cm da=8cm and c=90°

Answer»

Answer:

66 cm²

Step-by-step explanation:

First draw a diagonal BD.

Now in ∆BCD,

BC = 12 cm

CD = 5 cm

BD = √BC²+CD²

= √12²+5²

= √144+25

= √169

= 13 cm

Therefore, BD = 13 cm

Now,

ar(BCD) = ½×b×h

= ½×5×12

= 30 cm²

In ∆ABD,

a = 8 cm

b = 9 cm

c = 13 cm

s(Semi-Perimeter) = a+b+c/2

= 8+9+13/2

= 30/2

= 15 cm

Therefore,

ar(ABD) = √s(s-a)(s-b)(s-c)

= √15(15-8)(15-9)(15-13)

= √15×7×6×2

= √3×5×7×3×2×2 (SINCE 15=3×5 & 6=3×2)

= √3×3×2×2×7×5

=3×2 √7×5

= 6 × √35

= 6×6 (Since √36= 6 and √35 is close to √36 )

= 36 cm²

Therefore,

ar(ABCD) = ar(BCD) + ar(ABD)

= 30+36

= 66 cm² approx.

I hope you understood my explanation

Plzz MARK my answer as brainliest

Thank you...

TAUTIK

Discussion

12.	What is the csa of cuboid, rectangle
Answer» Step-by-step EXPLANATION: CSA of CUBOID is 2(l+b)H

12.

What is the csa of cuboid, rectangle

Answer»

Step-by-step EXPLANATION:

CSA of CUBOID is 2(l+b)H

Discussion

13.	Find the area of triangle given in the image
Answer» ANSWER: Step-by-step EXPLANATION:

13.

Find the area of triangle given in the image

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

14.	2. The value of x + y -- 10 at x = 0 and y = 0 isa) 10b) -1C) -10d) o
Answer» IT IS *OPTION* C : -10 ■■■■■■■■■■■■■■■

14.

2. The value of x + y -- 10 at x = 0 and y = 0 isa) 10b) -1C) -10d) o

Answer»

IT IS OPTION C : -10

■■■■■■■■■■■■■■■

Discussion

15.	can you explain the Pythagoras theorem using the concept of the area of squares? you can include diagrams on your explanation but please be clear about your answer.
Answer» ANSWER: please FOLLOW me and mark it as BRAIN list answer

15.

can you explain the Pythagoras theorem using the concept of the area of squares? you can include diagrams on your explanation but please be clear about your answer.

Answer»

ANSWER:

please FOLLOW me and mark it as BRAIN list answer

Discussion

16.	Find the height of a cuboid whose base is 90cm2 and volume is 450cm3
Answer» ANSWER: VOLUME - 450 BASE AREA -90 Volume =base area ×height 450=90 ×h 450÷90=h h=5

16.

Find the height of a cuboid whose base is 90cm2 and volume is 450cm3

Answer»

ANSWER:

VOLUME - 450

BASE AREA -90

Volume =base area ×height

450=90 ×h

450÷90=h

h=5

Discussion

17.	Multiplicative inverse of (-1)*(-4/5)
Answer» Answer: $- 1 \times \frac{-4}{5} \\ \frac{ 5}{4}$

17.

Multiplicative inverse of (-1)*(-4/5)

Answer»

Answer:

$- 1 \times \frac{-4}{5} \\ \frac{ 5}{4}$

Discussion

18.	Pls give me answer to my question
Answer» Answer: 5325688. with gst means good SERVICE tax means in PROFIT or loss aaaa

18.

Pls give me answer to my question

Answer»

Answer:

5325688.

with gst

means

good SERVICE tax

means in PROFIT or

loss

aaaa

Discussion

19.	7 km 2m = ________ m
Answer» Answer: 7200m Step-by-step EXPLANATION: (7*1000)m+2m.......1km=1000m =7000m+2m =7200m

19.

7 km 2m = ________ m

Answer»

Answer:

7200m

Step-by-step EXPLANATION:

(7*1000)m+2m.......1km=1000m

=7000m+2m

=7200m

Discussion

20.	Write component statement of a given statement.1) root 2 is a rational number or an irrational number.2)write negation for root 2 is not a cimplex numbers
Answer» ANSWER: ROOT 2 is IRRATIONAL HENCE it is in the formp/q

20.

Write component statement of a given statement.1) root 2 is a rational number or an irrational number.2)write negation for root 2 is not a cimplex numbers

Answer»

ANSWER:

ROOT 2 is IRRATIONAL HENCE it is in the formp/q

Discussion

21.	Divide(a) 26xy (x + 5) ( y - 4 ) by 13x (7-4)
Answer» Answer: PLEASE FOLLOW me and mark it as BRAIN LIST answer

21.

Divide(a) 26xy (x + 5) ( y - 4 ) by 13x (7-4)

Answer»

Answer:

PLEASE FOLLOW me and mark it as BRAIN LIST answer

Discussion

22.	Find the area of the following triangle
Answer» Step-by-step EXPLANATION: This is the ANSWER of RIGHT

22.

Find the area of the following triangle

Answer»

Step-by-step EXPLANATION:

This is the ANSWER of RIGHT

Discussion

23.	Please answer from attachment
Answer» ANSWER: (X + 3Y) × 1/2 = x/2 + 3y/2 *HOPE* *THIS* *HELPS* *YOU*.....

23.

Please answer from attachment

Answer»

ANSWER:

(X + 3Y) × 1/2

= x/2 + 3y/2

HOPE THIS HELPS YOU.....

Discussion

24.	His mother died______ overwork.
Answer» His MOTHER DIED from OVERWORK.

24.

His mother died______ overwork.

Answer»

His MOTHER DIED from OVERWORK.

Discussion

25.	Under root 2 + sinx - under root 3 / cos²x for x=pi/2
Answer» ANSWER: Answer is UNDEFINED Step-by-step EXPLANATION: Because any no. DIVIDE by ZERO is undefined

25.

Under root 2 + sinx - under root 3 / cos²x for x=pi/2

Answer»

ANSWER:

Answer is UNDEFINED

Step-by-step EXPLANATION:

Because any no. DIVIDE by ZERO is undefined

Discussion

26.	We have 9 balls of distinct colours. Calculate the number of ways to arrange them so that following four balls of colour: pink, orange, purple and white are not all together?
Answer» ANSWER: pink+orange+purple+white 9+9+9+9

26.

We have 9 balls of distinct colours. Calculate the number of ways to arrange them so that following four balls of colour: pink, orange, purple and white are not all together?

Answer»

ANSWER:

pink+orange+purple+white

9+9+9+9

Discussion

27.	X²-1-2a-a² factorise
Answer» ANSWER: x^2 -a^2=a^2+b^2-2ab

27.

X²-1-2a-a² factorise

Answer»

ANSWER:

x^2 -a^2=a^2+b^2-2ab

Discussion

28.	Find the coordinates of the point on x axis which is at a distance of 5 from 4,6
Answer» Answer: 5 UNITS = (0,5) 4 units =(0,4) 6 units from origin=(0,6) Step-by-step EXPLANATION: if a point need to lie on X axis then the value of y should be 0 and the distance from origin is ACCORDING to the que asked thank you! hope u found this helpful if YES mark it as the brainliest

28.

Find the coordinates of the point on x axis which is at a distance of 5 from 4,6

Answer»

Answer:

5 UNITS = (0,5)

4 units =(0,4)

6 units from origin=(0,6)

Step-by-step EXPLANATION:

if a point need to lie on X axis then the value of y should be 0 and the distance from origin is ACCORDING to the que asked

thank you!

hope u found this helpful if YES mark it as the brainliest

Discussion

29.	Simplyfy (a+b)(c-d)+(a-b)(c-d)+2(ac+bd)
Answer» ANSWER: OPTION KYA HAIN..............m

29.

Simplyfy (a+b)(c-d)+(a-b)(c-d)+2(ac+bd)

Answer»

ANSWER:

OPTION KYA HAIN..............m

Discussion

30.	A and B take 6hours and 9hours respectively to complete the work. A works 1hour and then B works 2hoursHow much work is done in these 3 hours . How much work is still left
Answer» ✪ Question :- A and B TAKE 6hours and 9 hours respectively to complete the work. A works 1HOUR and then B works 2 hours . How much work is done in these 3 hours . How much work is still left ? ✰ Solution :- Given that , A can complete the work in = 6 hours. That means, A can do = (1/6) unit of work per HOUR. Also, B A can complete the work in = 9 hours. That means, B can do = (1/9) unit of work per hour. Than , B will do work in 2 hours = 2 * (1/9) = 2/9 unit of work. So, Total work done by A + B in 3 hours = (1/6) + (2/9) → (3+4)/18 → (7/18) unit of work done. Now, work left to be done = 1 - (7/18) = (11/18) unit of work.

30.

A and B take 6hours and 9hours respectively to complete the work. A works 1hour and then B works 2hoursHow much work is done in these 3 hours . How much work is still left

Answer»

✪ Question :- A and B TAKE 6hours and 9 hours respectively to complete the work. A works 1HOUR and then B works 2 hours . How much work is done in these 3 hours . How much work is still left ?

✰ Solution :-

Given that , A can complete the work in = 6 hours.

That means, A can do = (1/6) unit of work per HOUR.

Also, B A can complete the work in = 9 hours.

That means, B can do = (1/9) unit of work per hour.

Than , B will do work in 2 hours = 2 * (1/9) = 2/9 unit of work.

So, Total work done by A + B in 3 hours = (1/6) + (2/9)

→ (3+4)/18

→ (7/18) unit of work done.

Now, work left to be done = 1 - (7/18) = (11/18) unit of work.

Discussion

31.	In triangle ABC and PQR , if angle A= angle R , angle B =angle P and AB = RP , then which one of the following congruence condition apply
Answer» ANSWER: ASA congruence test Step-by-step EXPLANATION: in TRIANGLE abc and Triangle pqr it is given that AB = RP angle B = angle P angle A = angle R therefore, triangle abc =~ triangle pqr by ASA test

31.

In triangle ABC and PQR , if angle A= angle R , angle B =angle P and AB = RP , then which one of the following congruence condition apply

Answer»

ANSWER:

ASA congruence test

Step-by-step EXPLANATION:

in TRIANGLE abc and Triangle pqr

it is given that

AB = RP

angle B = angle P

angle A = angle R

therefore,

triangle abc =~ triangle pqr

by ASA test

Discussion

32.	A man of height 6 ft observes a bird on the top of a tree of height 15 ft.from a point at a distance of 20 ft.from the foot of the tree ,with an angle of elevation 30° draw a suitable diagram for this data
Answer» ANSWER: FOLLOW meeeeeeeeeeee........

32.

A man of height 6 ft observes a bird on the top of a tree of height 15 ft.from a point at a distance of 20 ft.from the foot of the tree ,with an angle of elevation 30° draw a suitable diagram for this data

Answer»

ANSWER:

FOLLOW meeeeeeeeeeee........

Discussion

33.	RS.1500for 2 years at 6 persentage per annum find the compound interest
Answer» <P>Step-by-step explanation: PRINCIPAL (P) = ₹15000 Rate (R) = 5% TIME (T) = 2 Years Simple Interest (SI) = PRT / 100 => 15000 × 5 × 2 / 100 => ₹1500 Amount (A) = P + SI Amount = ₹15000 + ₹1500 Amount = ₹ 16500

33.

RS.1500for 2 years at 6 persentage per annum find the compound interest

Answer»

<P>Step-by-step explanation:

PRINCIPAL (P) = ₹15000

Rate (R) = 5%

TIME (T) = 2 Years

Simple Interest (SI) = PRT / 100

=> 15000 × 5 × 2 / 100

=> ₹1500

Amount (A) = P + SI

Amount = ₹15000 + ₹1500

Amount = ₹ 16500

Discussion

34.	Find x giving reasons
Answer» ANSWER: BRO PUT YOU PROTECTOR ON ∆B THEN YOU WILL GET ANGLE DEGREE THEN WRITE THE DEGREE WHICH YOU WILL GET AT THE PLACE OF X

34.

Find x giving reasons

Answer»

ANSWER:

BRO PUT YOU PROTECTOR ON ∆B THEN YOU WILL GET ANGLE DEGREE THEN WRITE THE DEGREE WHICH YOU WILL GET AT THE PLACE OF X

Discussion

35.	If 100 kg of meat is devided into packages ofv4/7 kg each total package..?
Answer» Answer: 175 Step-by-step EXPLANATION: when we DIVIDE 100KG of MEATS into 4/7each

35.

If 100 kg of meat is devided into packages ofv4/7 kg each total package..?

Answer»

Answer:

175

Step-by-step EXPLANATION:

when we DIVIDE 100KG of MEATS into 4/7each

Discussion

36.	2^33÷9 find remainder
Answer» ANSWER: 954,437,176.889 this is the answer

36.

2^33÷9 find remainder

Answer»

ANSWER:

954,437,176.889 this is the answer

Discussion

37.	Send me a pic of a cuboid
Answer» ANSWER: Tere pass NET nahi HAI Kya be

37.

Send me a pic of a cuboid

Answer»

ANSWER:

Tere pass NET nahi HAI Kya be

Discussion

38.	if the line x/a+y/b=1passes through the point of intersection of the lines x=3 and 2x +3y=12 and is perpendicular to the line 2x +3y =8 find value of a and b.
Answer» Answer: here, $x = 3 \\ 2x + 3y = 12 \\$ let, these lines intersect at point M now, $2x + 3y = 12 \\ > 2 \times 3 + 3y = 12 \\ > 6 + 3y = 12 \\ > 3y = 6 \\ > y = 2$ so, the coordinates of point M is: (3,2) now, $\frac{x}{a} + \frac{y}{b} = 1 \: passes \: through \: point \: < m >$ THEREFORE, X=3, y=2 $\frac{x}{a} + \frac{y}{b} = 1 \\ > \frac{3}{a} + \frac{2}{b} = 1 \\ > \frac{3b + 2a}{ab} = 1 \\ > 3b + 2a = ab \\ > 2a = ab - 3b \\ > a = \frac{ab - 3b}{2}$ now, this line is perpendicular to the line 2x+3y=8 here, 2x+3y=8 >3y=8-2x >y=(8-2x)/3 so, slope of the line is -(2/3) here, $\tan( \alpha ) = - \frac{2}{3} \\ > \tan( \alpha ) = \tan( - 33.69) \\ > \alpha = - 33.69$ now the line X/a+y/B= is perpendicular to the line 2x+3y=8 so, ANGLE of line X/a+y/B is (-33.69+90)°=56.31° here, slope of the line tan(56.31)=1.5 now, $\frac{x}{a } + \frac{y}{b} = 1 \\ > \frac{y}{b} = 1 - \frac{x}{a} \\ > \frac{y}{b} = \frac{a - x}{a} \\ > y = \frac{b(a - x)}{a} = b - \frac{x}{a}$ here slope=-(X/a) ALSO, slope=1.5=3/2 so, $- \frac{x}{a} = \frac{3}{2} \\ > \frac{x}{a} = - \frac{3}{2}$ putting this in X/a+y/B=1, we get, $\frac{x}{a} + \frac{y}{b} = 1 \\ > - \frac{3}{2} + \frac{y}{b} = 1 \\ > \frac{y}{b} = 1 + \frac{3}{2} = \frac{5}{2} \\ > \frac{2}{b} = \frac{5}{2} \\ > b = \frac{4}{5}$ again, putting VALUE of b in the same equation, we get, $\frac{x}{a} + \frac{y}{b} = 1 \\ > \frac{3}{a} + \frac{2}{ \frac{4}{5} } = 1 \\ >$

38.

if the line x/a+y/b=1passes through the point of intersection of the lines x=3 and 2x +3y=12 and is perpendicular to the line 2x +3y =8 find value of a and b.

Answer»

Answer:

here,

$x = 3 \\ 2x + 3y = 12 \\$

let, these lines intersect at point M

now,

$2x + 3y = 12 \\ > 2 \times 3 + 3y = 12 \\ > 6 + 3y = 12 \\ > 3y = 6 \\ > y = 2$

so, the coordinates of point M is: (3,2)

now,

$\frac{x}{a} + \frac{y}{b} = 1 \: passes \: through \: point \: < m >$

THEREFORE,

X=3, y=2

$\frac{x}{a} + \frac{y}{b} = 1 \\ > \frac{3}{a} + \frac{2}{b} = 1 \\ > \frac{3b + 2a}{ab} = 1 \\ > 3b + 2a = ab \\ > 2a = ab - 3b \\ > a = \frac{ab - 3b}{2}$

now, this line is perpendicular to the line 2x+3y=8

here,

2x+3y=8

>3y=8-2x

>y=(8-2x)/3

so, slope of the line is -(2/3)

here,

$\tan( \alpha ) = - \frac{2}{3} \\ > \tan( \alpha ) = \tan( - 33.69) \\ > \alpha = - 33.69$

now

the line X/a+y/B= is perpendicular to the line 2x+3y=8

so, ANGLE of line X/a+y/B is (-33.69+90)°=56.31°

here,

slope of the line

tan(56.31)=1.5

now,

$\frac{x}{a } + \frac{y}{b} = 1 \\ > \frac{y}{b} = 1 - \frac{x}{a} \\ > \frac{y}{b} = \frac{a - x}{a} \\ > y = \frac{b(a - x)}{a} = b - \frac{x}{a}$

here slope=-(X/a)

ALSO, slope=1.5=3/2

so,

$- \frac{x}{a} = \frac{3}{2} \\ > \frac{x}{a} = - \frac{3}{2}$

putting this in X/a+y/B=1, we get,

$\frac{x}{a} + \frac{y}{b} = 1 \\ > - \frac{3}{2} + \frac{y}{b} = 1 \\ > \frac{y}{b} = 1 + \frac{3}{2} = \frac{5}{2} \\ > \frac{2}{b} = \frac{5}{2} \\ > b = \frac{4}{5}$

again, putting VALUE of b in the same equation, we get,

$\frac{x}{a} + \frac{y}{b} = 1 \\ > \frac{3}{a} + \frac{2}{ \frac{4}{5} } = 1 \\ >$

Discussion

39.	Two pairs of adjacent angle
Answer» ANSWER: ANGLE 3 =4 Step-by-step EXPLANATION: angle 5=6

39.

Two pairs of adjacent angle

Answer»

ANSWER:

ANGLE 3 =4

Step-by-step EXPLANATION:

angle 5=6

Discussion

40.	Factorise : 100-49b^2
Answer» Step-by-step explanation: 100-49^2 10^2-(7B)^2 a^2-b^2=(a+b)(a-b) (10+7b)(10-7b) PLEASE MARK me as BRAINLIST ✌️ ✌️ ✌️

40.

Factorise : 100-49b^2

Answer»

Step-by-step explanation:

100-49^2

10^2-(7B)^2

a^2-b^2=(a+b)(a-b)

(10+7b)(10-7b)

PLEASE MARK me as BRAINLIST ✌️ ✌️ ✌️

Discussion

41.	Show that the line joining the points (-1, 2) and (3, 2) is parallel to the linepoints (-5, 0) and (4,0).
Answer» ANSWER: It NEED to make graph BRO but I can't make it now Sorry but it is very easy

41.

Show that the line joining the points (-1, 2) and (3, 2) is parallel to the linepoints (-5, 0) and (4,0).

Answer»

ANSWER:

It NEED to make graph BRO but I can't make it now

Sorry but it is very easy

Discussion

42.	find the relation between x and y in order that the rth mean between x and 2y maybe the same as the rth mean between 2x and y,n means being inserted in each case
Answer» let x, A1, a2, an, 2y be in ap. then commerce difference =(2y-x)/ (n+1) ar=x+rd= x+ r (2y-x) / (n+1) =(x(n+1) +r(2y-x)/(n+1) now 2X,b1,B2, bn,y are in ap. then common difference = (y-2x)/ (n+1) br=x+rd =x+r (y-2x)/(n+1) =(x(n+1)+r(y-2x))/(n+1) since, ar=br, we have: (x(n+1)+r(2y-x))/(n+1)= (x(n+1)+r(y-2x))/(n+1) on simplifying, we get, Ry= x(n-r+1) this is the REQUIRED relation.

42.

find the relation between x and y in order that the rth mean between x and 2y maybe the same as the rth mean between 2x and y,n means being inserted in each case

Answer»

let x, A1, a2, an, 2y be in ap.

then commerce difference =(2y-x)/ (n+1)

ar=x+rd= x+ r (2y-x) / (n+1) =(x(n+1) +r(2y-x)/(n+1)

now 2X,b1,B2, bn,y are in ap.

then common difference = (y-2x)/ (n+1)

br=x+rd =x+r (y-2x)/(n+1) =(x(n+1)+r(y-2x))/(n+1)

since, ar=br, we have:

(x(n+1)+r(2y-x))/(n+1)= (x(n+1)+r(y-2x))/(n+1)

on simplifying, we get,

Ry= x(n-r+1)

this is the REQUIRED relation.

Discussion

43.	(1. Multiply (3 + 13 ) by (2 - V3)
Answer» Answer: 32-48V Step-by-step EXPLANATION: (3+13)(2-V3) 6-9V+26-39V 32-48V

43.

(1. Multiply (3 + 13 ) by (2 - V3)

Answer»

Answer:

32-48V

Step-by-step EXPLANATION:

(3+13)(2-V3)

6-9V+26-39V

32-48V

Discussion

44.	0.7x+0.5 divided by 3.5x+4.5=2/5 by cross multiplicationj
Answer» ANSWER: x=13/7 like this and FOLLOW me

44.

0.7x+0.5 divided by 3.5x+4.5=2/5 by cross multiplicationj

Answer»

ANSWER:

x=13/7

like this and FOLLOW me

Discussion

45.	The perpendicular from K To side MN at R such that 3MR=RN prove that :2KN SQUARE = 2KM SQUARE +MN SQUARE
Answer» a square is a rectangle with four EQUAL sides. al-though relatively simple and straightforward to DEAL with, SQUARES have SEVERAL interesting and no-table properties.

45.

The perpendicular from K To side MN at R such that 3MR=RN prove that :2KN SQUARE = 2KM SQUARE +MN SQUARE

Answer»

a square is a rectangle with four EQUAL sides. al-though relatively simple and straightforward to DEAL with, SQUARES have SEVERAL interesting and no-table properties.

Discussion

46.	Find The Cube root of 13832 by lcm
Answer» Answer: 24.004628736855 Step-by-step EXPLANATION: By USING LCM METHOD

46.

Find The Cube root of 13832 by lcm

Answer»

Answer:

24.004628736855

Step-by-step EXPLANATION:

By USING LCM METHOD

Discussion

47.	धातु में तांबे और जिंक का मिश्रण 5:3 के अनुपात में है यदि धातु में तांबे का वजन 30.5 ग्राम हो तो धातु में जिंक का वजन ज्ञात कीजिए
Answer» Answer: 400/3 Step-by-step EXPLANATION: I HOPE it will HELP you

47.

धातु में तांबे और जिंक का मिश्रण 5:3 के अनुपात में है यदि धातु में तांबे का वजन 30.5 ग्राम हो तो धातु में जिंक का वजन ज्ञात कीजिए

Answer»

Answer:

400/3

Step-by-step EXPLANATION:

I HOPE it will HELP you

Discussion

48.	Sania had 4 by 5 part of a chocolate bar she at 1 by 4 of it How much part of chocolate bar did she eat?
Answer» She had 4/5 of the chocolate bar. Suppose she had 4 PIECES out of 5 pieces of chocolate. She ATE 1/4 of 4 pieces she had. Therefore she ate 1/4*4/5= 4/20 = 1/5 of the chocolate

Discussion

49.	A) x+y=0,if x is taken as 2, what is Y? b) find x-y
Answer» Step-by-step explanation: if X is 2 then y is -2 and x-y is 2-(-2) =2+2=4 please FOLLOW me and MARK it as brain list answer

49.

A) x+y=0,if x is taken as 2, what is Y? b) find x-y

Answer»

Step-by-step explanation:

if X is 2 then y is -2

and x-y is 2-(-2) =2+2=4

please FOLLOW me and MARK it as brain list answer

Discussion

50.	Solve : x2-5x-2250 ...... a quadratic equation.
Answer» Step-by-step EXPLANATION: BHAI PLZ FOLLOW me and THANKED

50.

Solve : x2-5x-2250 ...... a quadratic equation.

Answer»

Step-by-step EXPLANATION:

BHAI PLZ FOLLOW me and THANKED

Discussion

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