332354 + Interview Questions in Secondary School in Math

1.	Simplyfy(5+√7) (2+√5)
Answer» Answer : = (5+√7) (2+√5) = 5 × 2 + 5√5 + 2√7 + √7√5 = 10 + 5√5 + 2√7 + 35 _______________________

1.

Simplyfy(5+√7) (2+√5)

Answer»

Answer :

= (5+√7) (2+√5)

= 5 × 2 + 5√5 + 2√7 + √7√5

= 10 + 5√5 + 2√7 + 35

_______________________

Discussion

2.	The quadratic equation 2 x2 + k x + 3=0 has two equal roots . then find the value of k
Answer» ANSWER: k = 2√6 Given: Quadratic Equation: $2 {x}^{2} + kx + 3 = 0$ Explanation: The roots of a quadratic equation are equal when DISCRIMINANT is equal to zero. ${b}^{2} - 4ac \: is \: equal \: to \: zero$ Here, a = 2 b = k C = 3 Substituting the VALUE of a, b and c in the discriminant. $\tt {b}^{2} - 4ac = 0 \\\tt {k}^{2} - 4 \times 2 \times 3 = 0 \\ \tt {k}^{2} - 24 = 0 \\ \tt {k}^{2} = 24 \\ \tt \: k = 2 \sqrt{6}$ Therefore, k = 2√6 Other Conditions: $\tt \: 1) \: two \: real \: and \: distinct \: roots \: = {b}^{2} - 4ac > 0 \\\tt 2) \: two \: real \: roots \: if \: and \: only \: if = {b}^{2} - 4ac \geqslant 0 \\\tt3) \: no \: real \: roots \: if \: and \: only \: if \: = {b}^{2} - 4ac \leqslant 0$ $\tt \: if \: \sqrt{ {b}^{2} - 4ac} \: is \: negative\: then \: the\: root \: is \\ \tt \: complex \: and \: imaginary$

2.

The quadratic equation 2 x2 + k x + 3=0 has two equal roots . then find the value of k

Answer»

ANSWER:

k = 2√6

Given:

Quadratic Equation:

$2 {x}^{2} + kx + 3 = 0$

Explanation:

The roots of a quadratic equation are equal when DISCRIMINANT is equal to zero.

${b}^{2} - 4ac \: is \: equal \: to \: zero$

Here,

a = 2

b = k

C = 3

Substituting the VALUE of a, b and c in the discriminant.

$\tt {b}^{2} - 4ac = 0 \\\tt {k}^{2} - 4 \times 2 \times 3 = 0 \\ \tt {k}^{2} - 24 = 0 \\ \tt {k}^{2} = 24 \\ \tt \: k = 2 \sqrt{6}$

Therefore,

k = 2√6

Other Conditions:

$\tt \: 1) \: two \: real \: and \: distinct \: roots \: = {b}^{2} - 4ac > 0 \\\tt 2) \: two \: real \: roots \: if \: and \: only \: if = {b}^{2} - 4ac \geqslant 0 \\\tt3) \: no \: real \: roots \: if \: and \: only \: if \: = {b}^{2} - 4ac \leqslant 0$

$\tt \: if \: \sqrt{ {b}^{2} - 4ac} \: is \: negative\: then \: the\: root \: is \\ \tt \: complex \: and \: imaginary$

Discussion

3.	Which of the following is a quadratic equation?(a)6x^2=20-x^2 (b)3÷×-3=4x^20(c)x^2 (1÷2)=7÷20(d)5x+6=3x
Answer» HII here is your ANSWER

3.

Which of the following is a quadratic equation?(a)6x^2=20-x^2 (b)3÷×-3=4x^20(c)x^2 (1÷2)=7÷20(d)5x+6=3x

Answer»

HII

here is your ANSWER

Discussion

4.	Please answer this.........as fast
Answer» Answer: 53 Step-by-step EXPLANATION: we KNOW that 44 square =1936 so,1989-x=1936 so,x=53 the least number which must be subtracted from 1989 so as to get a perfect square 53

4.

Please answer this.........as fast

Answer»

Answer:

53

Step-by-step EXPLANATION:

we KNOW that 44 square =1936

so,1989-x=1936

so,x=53

the least number which must be subtracted from 1989 so as to get a perfect square 53

Discussion

5.	2+3++4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30=?
Answer» ANSWER: 434 Step-by-step explanation: 2+3+4+5+6+7+8+9+10=54 11+12+13+14+15+16+17+18+19+20=155 21+22+23+24+25+26+27+28+29+30=225 54+155+255=434

5.

2+3++4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30=?

Answer»

ANSWER:

434

Step-by-step explanation:

2+3+4+5+6+7+8+9+10=54

11+12+13+14+15+16+17+18+19+20=155

21+22+23+24+25+26+27+28+29+30=225

54+155+255=434

Discussion

6.	If two dice are thrown find the probability thag their sum is less than 7 (included 7) or sum is 7
Answer» Answer: 77777772836937336373736777

6.

If two dice are thrown find the probability thag their sum is less than 7 (included 7) or sum is 7

Answer»

Answer:

77777772836937336373736777

Discussion

7.	50x
Answer» $\color{green}\large\underline{\underline{Hello...}}$ $\color{blue}\large\underline{\underline{Answer:}}$ Let's SOLVE the bracket first. ${50x}^{2} - 2 {(<klux>X</klux> - 2)}^{2}$ ${50x}^{2} - 2( {x}^{2} - 4x + 4)$ ${50x}^{2} - 2 {x}^{2} + 8x - 8$ Reduce to simplest form. ${48x}^{2} + 8x - 8$ The equation is.... ${6x}^{2} + x - 1$ By splitting the MIDDLE TERM, $6 {x}^{2} + 3x - 2x - 1 = 0$ $3x(2x + 1) - 1(2x + 1) = 0$ $(3x - 1)(2x + 1) = 0$ HENCE the value of 'x' is.... $x = \frac{1}{3} \: or \: \frac{ - 1}{2}$ $\color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}}$

7.

50x

Answer»

$\color{green}\large\underline{\underline{Hello...}}$

$\color{blue}\large\underline{\underline{Answer:}}$

Let's SOLVE the bracket first.

${50x}^{2} - 2 {(<klux>X</klux> - 2)}^{2}$

${50x}^{2} - 2( {x}^{2} - 4x + 4)$

${50x}^{2} - 2 {x}^{2} + 8x - 8$

Reduce to simplest form.

${48x}^{2} + 8x - 8$

The equation is....

${6x}^{2} + x - 1$

By splitting the MIDDLE TERM,

$6 {x}^{2} + 3x - 2x - 1 = 0$

$3x(2x + 1) - 1(2x + 1) = 0$

$(3x - 1)(2x + 1) = 0$

HENCE the value of 'x' is....

$x = \frac{1}{3} \: or \: \frac{ - 1}{2}$

$\color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}}$

Discussion

8.	10 years ago the age of father was 4times that of his son and 5 years ago the age of
Answer» ANSWER: 2 TIMES Step-by-step explanation: hope you UNDERSTAND

8.

10 years ago the age of father was 4times that of his son and 5 years ago the age of

Answer»

ANSWER:

2 TIMES

Step-by-step explanation:

hope you UNDERSTAND

Discussion

9.	represent the following informational of the favourite breakfast of children of class 6 of a school in a tabular form and as a graph breakfast = dosa no of students =16 breakfast=idly no of students=4 breakfast=appam and stew no. of students=25 breakfast=poorimasala no. of students=10 breakfast=chapathi no.of students=7 breakfast=bread jam no.of students=4 breakfast=puttu kadala no.of students=9
Answer» ANSWER: if you want to GET ANSWERS for that MUCH long questions then give more points

9.

represent the following informational of the favourite breakfast of children of class 6 of a school in a tabular form and as a graph breakfast = dosa no of students =16 breakfast=idly no of students=4 breakfast=appam and stew no. of students=25 breakfast=poorimasala no. of students=10 breakfast=chapathi no.of students=7 breakfast=bread jam no.of students=4 breakfast=puttu kadala no.of students=9

Answer»

ANSWER:

if you want to GET ANSWERS for that MUCH long questions then give more points

Discussion

10.	the area of rectangle get reduced by 80 square units if it's length reduced by 5units and its breadth is increased by 2 units if we increase the length by 10 units and decrease the breadth by 5 units ,the area increased by 50 square units,find the length and breadth of the rectangle
Answer» Step-by-step EXPLANATION: HOPE you GOT it. And it HELPS you.

10.

the area of rectangle get reduced by 80 square units if it's length reduced by 5units and its breadth is increased by 2 units if we increase the length by 10 units and decrease the breadth by 5 units ,the area increased by 50 square units,find the length and breadth of the rectangle

Answer»

Step-by-step EXPLANATION:

HOPE you GOT it. And it HELPS you.

Discussion

11.	Only Mathematicians Are Allowed.
Answer» ANSWER: your ANS is b Step-by-step EXPLANATION: Now MARK me as BRANLIEST

11.

Only Mathematicians Are Allowed.

Answer»

ANSWER:

your ANS is b

Step-by-step EXPLANATION:

Now MARK me as BRANLIEST

Discussion

12.	. If +' and +', 'x' and –' are interchanged inthe equation 17 + 7- 27 + 7 x 3, then itsvalue will be-
Answer» Answer: 210 Step-by-step explanation: 17+7*27+7-3 is the SIMPLIFICATION of the question use BODMAS RULE so we get 17+189+7-3 24+189-3 213-3=210

12.

. If +' and +', 'x' and –' are interchanged inthe equation 17 + 7- 27 + 7 x 3, then itsvalue will be-

Answer»

Answer:

210

Step-by-step explanation:

17+7*27+7-3 is the SIMPLIFICATION of the question

use BODMAS RULE

so we get

17+189+7-3

24+189-3

213-3=210

Discussion

13.	Find the reciprocal each of the following fractions1)5/82)8/73)13/74)3/4
Answer» Answer: 8/5 7/8 7/13 4/3 hope it HELPS you MATE.

13.

Find the reciprocal each of the following fractions1)5/82)8/73)13/74)3/4

Answer»

Answer:

8/5
7/8
7/13
4/3

hope it HELPS you MATE.

Discussion

14.	If d(P, R)=7,d(P, Q)=10,d(Q, R)=3,then which of the following option is truea=P-Q-Rb=R-O-Pc=P-R-Qd=R-P-Q
Answer» I HOPE you KNOW the ANSWER

Discussion

15.	Solve clearly and tell
Answer» ANSWER: Answer is (B) PART... ..... ☜☆☞\(-ㅂ-)/ ♥ ♥ ♥

15.

Solve clearly and tell

Answer»

ANSWER:

Answer is (B) PART... .....

☜☆☞\(-ㅂ-)/ ♥ ♥ ♥

Discussion

16.	Simplify the following............
Answer» QUESTION: SIMPLIFY: $cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right] \\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$ ANSWER: $\left[\begin{array}{cc}1&0\\ \\0&1\end{array}\right]$ GIVEN: $cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right] \\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$ TO FIND: $cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right] \\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$ EXPLANATION: $cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right] \\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$ $Let \ A = \left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right]$ $Let \ B =\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$ $cos \ \theta \times A=\left[\begin{array}{cc}cos^2 \ \theta&cos \ \theta \ sin \ \theta\\ \\ -sin\ \theta\ cos \ \theta&cos^2 \ \theta\end{array}\right]$ $sin \ \theta\times B = \left[\begin{array}{cc}sin^2 \ \theta&-sin \ \theta\ cos \ \theta\\ \\ cos\ \theta \ sin \ \theta&sin^2 \ \theta\end{array}\right]$ $Let\ cos \ \theta \times A+sin \ \theta \times B =\left[\begin{array}{cc}a_{11}&a_{12}\\ \\ a_{21}&a_{22}\end{array}\right]$ $a_{11}= sin^2\ \theta + cos^2\ \theta$ $a_{12}= sin \ \theta \ cos\ \theta-sin \ \theta \ cos\ \theta$ $a_{21}= sin \ \theta \ cos\ \theta-sin \ \theta \ cos\ \theta$ $a_{22}= sin^2\ \theta + cos^2\ \theta$ $\boxed{\bold{\large{sin^2 \ \theta + cos^2 \ \theta = 1}}}$ $a_{11} = 1$ $a_{12}=0$ $a_{21}=0$ $a_{22}= 1$ Substituting these values $\left[\begin{array}{cc}1&0\\ \\0&1\end{array}\right]$ $\left[\begin{array}{cc}1&0\\ \\0&1\end{array}\right]= I$ $cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right]\\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]= I$

16.

Simplify the following............

Answer»

QUESTION:

SIMPLIFY:

$cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right] \\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$

ANSWER:

$\left[\begin{array}{cc}1&0\\ \\0&1\end{array}\right]$

GIVEN:

$cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right] \\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$

TO FIND:

$cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right] \\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$

EXPLANATION:

$cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right] \\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$

$Let \ A = \left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right]$

$Let \ B =\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]$

$cos \ \theta \times A=\left[\begin{array}{cc}cos^2 \ \theta&cos \ \theta \ sin \ \theta\\ \\ -sin\ \theta\ cos \ \theta&cos^2 \ \theta\end{array}\right]$

$sin \ \theta\times B = \left[\begin{array}{cc}sin^2 \ \theta&-sin \ \theta\ cos \ \theta\\ \\ cos\ \theta \ sin \ \theta&sin^2 \ \theta\end{array}\right]$

$Let\ cos \ \theta \times A+sin \ \theta \times B =\left[\begin{array}{cc}a_{11}&a_{12}\\ \\ a_{21}&a_{22}\end{array}\right]$

$a_{11}= sin^2\ \theta + cos^2\ \theta$

$a_{12}= sin \ \theta \ cos\ \theta-sin \ \theta \ cos\ \theta$

$a_{21}= sin \ \theta \ cos\ \theta-sin \ \theta \ cos\ \theta$

$a_{22}= sin^2\ \theta + cos^2\ \theta$

$\boxed{\bold{\large{sin^2 \ \theta + cos^2 \ \theta = 1}}}$

$a_{11} = 1$

$a_{12}=0$

$a_{21}=0$

$a_{22}= 1$

Substituting these values

$\left[\begin{array}{cc}1&0\\ \\0&1\end{array}\right]$

$\left[\begin{array}{cc}1&0\\ \\0&1\end{array}\right]= I$

$cos \ \theta\left[\begin{array}{cc}cos \ \theta&sin \ \theta\\ \\ -sin\ \theta&cos \ \theta\end{array}\right]\\ + sin \ \theta\left[\begin{array}{cc}sin \ \theta&-cos \ \theta\\ \\ cos\ \theta&sin \ \theta\end{array}\right]= I$

Discussion

17.	Find the zeroes of polynomial and verify the relationship between zeroes and coefficient 2y^2-y-6
Answer» Step-by-step EXPLANATION: Please Mark me as a Brainliest

17.

Find the zeroes of polynomial and verify the relationship between zeroes and coefficient 2y^2-y-6

Answer»

Step-by-step EXPLANATION:

Please Mark me as a Brainliest

Discussion

18.	Q.VI Match the following1. India gate.2. Tajmahal.3. Bengal4. Lucknow.5. Varanasi.6. Asia.7. Southernmost tip8. Greater Himalayas9. Lesser Himalayas.10.Lower Himalayas.11 Sikkim.12 Uttarakhand.Durga PujaGangaGomtiDelhiAgraIndira pointcontinentShivalikHimadriHimachalDehradunMask dance
Answer» ANSWER: g5fbg55tggttg5bgtggggtgftftffv yyhhuuknj

18.

Q.VI Match the following1. India gate.2. Tajmahal.3. Bengal4. Lucknow.5. Varanasi.6. Asia.7. Southernmost tip8. Greater Himalayas9. Lesser Himalayas.10.Lower Himalayas.11 Sikkim.12 Uttarakhand.Durga PujaGangaGomtiDelhiAgraIndira pointcontinentShivalikHimadriHimachalDehradunMask dance

Answer»

ANSWER:

g5fbg55tggttg5bgtggggtgftftffv yyhhuuknj

Discussion

19.	Find the Lcm and hcf of 84 and 90 byapplying the prime factorisation method.
Answer» I SOLVE it..HOPE it's HELPFUL to you.

19.

Find the Lcm and hcf of 84 and 90 byapplying the prime factorisation method.

Answer»

I SOLVE it..HOPE it's HELPFUL to you.

Discussion

20.	4. class marks of (30 - 40) and (60 - 70) are:
Answer» ANSWER: what are CLASS MARK??¿¿¿

20.

4. class marks of (30 - 40) and (60 - 70) are:

Answer»

ANSWER:

what are CLASS MARK??¿¿¿

Discussion

21.	If perfectcompetitionPrice - magánil cost) determine& price of each unit &breadpatato
Answer» ANSWER: MARK me as BRAINLIEST then i will TELL you the answer

21.

If perfectcompetitionPrice - magánil cost) determine& price of each unit &breadpatato

Answer»

ANSWER:

MARK me as BRAINLIEST then i will TELL you the answer

Discussion

22.	No divisibleHow many two - digitby323win
Answer» $\huge\mathscr\red{make me brainiest}$

Discussion

23.	Please answer this fast I will markhim/her as brainlist
Answer» ANSWER: $\huge\purple\star\underline\mathfrak\pink{Solution :-}\purple\star$ Step-by-step explanation: ✧Split Figure :- Split the terms into TWO parts as shown in the figure : Now, we got a ∆ and a trapezium. Let's find the area of ∆ first :- Here, we are UNKNOWN about the third side of the ∆ Let's find out by PYTHAGOREAN theorem:- ${h}^{2} = {60}^{2} + {11}^{2}$ ${h}^{2} = 3600 + 121$ $h = \sqrt{3721} = 61$ Area of the ∆ :- $\sqrt{s(s - a)(s - b)( s- c)}$ Here semi - perimeter will be 66 i.e, s $\green { \underline \bold{area \: of \: the \: triangle:- }} \\ \tt \ \sqrt{66(66 - 61)(66 - 60)(66 - 11)} \\ \tt \\= \sqrt{66 \times 5 \times 6 \times 11} \\ = \sqrt{108900} = 330 {cm}^{2}$ Area of the trapezium :- $\frac{a + b}{2} \times h = \frac{26 + 61}{2} \times 9 = 783$ $\purple\star\underline\mathfrak\pink{Therefore\: total \: area \: of\: the \: figure \: is \: = 1113cm^2 :-}\purple\star$

23.

Please answer this fast I will markhim/her as brainlist

Answer»

ANSWER:

$\huge\purple\star\underline\mathfrak\pink{Solution :-}\purple\star$

Step-by-step explanation:

✧Split Figure :-

Split the terms into TWO parts as shown in the figure :

Now, we got a ∆ and a trapezium.

Let's find the area of ∆ first :-

Here, we are UNKNOWN about the third

side of the ∆

Let's find out by PYTHAGOREAN theorem:-

${h}^{2} = {60}^{2} + {11}^{2}$

${h}^{2} = 3600 + 121$

$h = \sqrt{3721} = 61$

Area of the ∆ :-

$\sqrt{s(s - a)(s - b)( s- c)}$

Here semi - perimeter will be 66 i.e, s

$\green { \underline \bold{area \: of \: the \: triangle:- }} \\ \tt \ \sqrt{66(66 - 61)(66 - 60)(66 - 11)} \\ \tt \\= \sqrt{66 \times 5 \times 6 \times 11} \\ = \sqrt{108900} = 330 {cm}^{2}$

Area of the trapezium :-

$\frac{a + b}{2} \times h = \frac{26 + 61}{2} \times 9 = 783$

$\purple\star\underline\mathfrak\pink{Therefore\: total \: area \: of\: the \: figure \: is \: = 1113cm^2 :-}\purple\star$

Discussion

24.	Factorise -x^2+3x+40
Answer» -x²+3x+40 -x²+(8-5)x+40 -×²+8x-5x+40 -x(x+5)+8(x+5) (x+5)(-x+8)

24.

Factorise -x^2+3x+40

Answer»

-x²+3x+40

-x²+(8-5)x+40

-×²+8x-5x+40

-x(x+5)+8(x+5)

(x+5)(-x+8)

Discussion

25.	Please answer It. I will also mark as brainliest
Answer» PLZ CHECK it once again it's not COMPLETE

25.

Please answer It. I will also mark as brainliest

Answer»

PLZ CHECK it once again it's not COMPLETE

Discussion

26.	90: If +25 represents gain of 25, then -20representsa)loss of -20 b)gain of 20 c)loss of 5d)gain of 5
Answer» ANSWER: LOSS of -20 hope it HELP MARK as BRAINLIEST

26.

90: If +25 represents gain of 25, then -20representsa)loss of -20 b)gain of 20 c)loss of 5d)gain of 5

Answer»

ANSWER:

LOSS of -20

hope it HELP MARK as BRAINLIEST

Discussion

27.	Insert six rational number between 3/5 and 2/3
Answer» Answer: 19/30, 28/45, 29/45 Step-by-step EXPLANATION: since, 3/5=18/30=27/45 2/3=20/30=30/45

27.

Insert six rational number between 3/5 and 2/3

Answer»

Answer:

19/30, 28/45, 29/45

Step-by-step EXPLANATION:

since,

3/5=18/30=27/45

2/3=20/30=30/45

Discussion

28.	22. Identify the combined figuresa) A tentb) Ice cream
Answer» ANSWER: both are CONE . *THANKS* *you.hope it HELP* U

28.

22. Identify the combined figuresa) A tentb) Ice cream

Answer»

ANSWER:

both are CONE .

THANKS you.hope it HELP U

Discussion

29.	Find the product of 3z^3 and (12z+4z^3)
Answer» ANSWER: = 36x^4 + 12z^6 Step-by-step EXPLANATION: = (3z³) (12z+4z³) = 36x^4 + 12z^6

29.

Find the product of 3z^3 and (12z+4z^3)

Answer»

ANSWER:

= 36x^4 + 12z^6

Step-by-step EXPLANATION:

= (3z³) (12z+4z³)

= 36x^4 + 12z^6

Discussion

30.	Divide the polynomial p(x) by the polynomial g(x) and find the quotient and remainder in the following:P(x)= x4 - 3x2 + 4x + 5 and g(x)= x2 + 1 - x.
Answer» ANSWER: no no MP BOO but so my GRILL or what go Step-by-step EXPLANATION: My I'd ꧁༒☬✓star✓☬༒꧂

30.

Divide the polynomial p(x) by the polynomial g(x) and find the quotient and remainder in the following:P(x)= x4 - 3x2 + 4x + 5 and g(x)= x2 + 1 - x.

Answer»

ANSWER:

no no MP BOO but so my GRILL or what go

Step-by-step EXPLANATION:

My I'd ꧁༒☬✓star✓☬༒꧂

Discussion

31.	2. Find the amplitude of the following:(i) - 1 + i
Answer» ANSWER: $\sqrt{2}$ That's the AMPLITUDE

31.

2. Find the amplitude of the following:(i) - 1 + i

Answer»

ANSWER:

$\sqrt{2}$

That's the AMPLITUDE

Discussion

32.	BrainBuster Math Question. Try Solving This
Answer» ANSWER: a) θπr²/360° Step-by-step EXPLANATION: PLZ MARK me BRAINLIEST

32.

BrainBuster Math Question. Try Solving This

Answer»

ANSWER:

a) θπr²/360°

Step-by-step EXPLANATION:

PLZ MARK me BRAINLIEST

Discussion

33.	4 ईयर्स एगो मीरा वास्तु टाइम्स एस ओल्ड एस मान्य एस लेटर मीरा गुड्डी प्राइस एस ओल्ड एस वे नो हाउ ओल्ड आर यू
Answer» Answer: Years ago MEERA Vastu Times S OLD S MANY S LETTER Mira Guddi PRICE S Old S Way No How Old Are You

33.

4 ईयर्स एगो मीरा वास्तु टाइम्स एस ओल्ड एस मान्य एस लेटर मीरा गुड्डी प्राइस एस ओल्ड एस वे नो हाउ ओल्ड आर यू

Answer»

Answer:

Years ago MEERA Vastu Times S OLD S MANY S LETTER Mira Guddi PRICE S Old S Way No How Old Are You

Discussion

34.	Solve it with respect to x
Answer» Step-by-step EXPLANATION: not MUCH VALUES GIVEN ......

34.

Solve it with respect to x

Answer»

Step-by-step EXPLANATION:

not MUCH VALUES GIVEN

......

Discussion

35.	PLS I BEG U KINDLY HELP IM ALWAYS GETTING THIS WRONG IM NOT GREAT AT MATHS PLS Simplify: 15-{8+27÷(2x8-7)}
Answer» 15-{8+27÷(16-7)} 15-{8+27÷9} 15-8+3 so,15+3 =18 18-8=10 10 ANSWER PLEASE FOLLOW me I am NEW

35.

PLS I BEG U KINDLY HELP IM ALWAYS GETTING THIS WRONG IM NOT GREAT AT MATHS PLS Simplify: 15-{8+27÷(2x8-7)}

Answer»

15-{8+27÷(16-7)}

15-{8+27÷9}

15-8+3

so,15+3 =18

18-8=10

10 ANSWER

PLEASE FOLLOW me I am NEW

Discussion

36.	If the product of two numbers is 60, what will be the product of their HCF and LCM?
Answer» Answer: 60 Step-by-step EXPLANATION: Given that the product of two numbers is 60 We know that LCM×HCF=Product of the two numbers LCM×HCF=60 therefore, The product of LCM and HCF =60

36.

If the product of two numbers is 60, what will be the product of their HCF and LCM?

Answer»

Answer:

60

Step-by-step EXPLANATION:

Given that

the product of two numbers is 60

We know that

LCM×HCF=Product of the two numbers

LCM×HCF=60

therefore,

The product of LCM and HCF =60

Discussion

37.	Split 45 in to 2 co prime numbers
Answer» Answer: 2,43 Step-by-step EXPLANATION:

37.

Split 45 in to 2 co prime numbers

Answer»

Answer:

2,43

Step-by-step EXPLANATION:

Discussion

38.	11,13(b) 1,9,(c) 5,7,9 (d) 3,5,7दो संख्याओं का अनुपात 3:4 है । यदि बड़ी संख्या का वर्ग दूसरी संख्या के वर्गके 8 गुने से 224 कम हो, तो संख्यायें हैं :(होटल मैंनेजमैंट, 1993)(a) 12,16 (b) 6,8(c) 9,12 (d) इनमें से कोई नहीं
Answer» ANSWER: answer is OPTION a PLEASE FOLLOW me

38.

11,13(b) 1,9,(c) 5,7,9 (d) 3,5,7दो संख्याओं का अनुपात 3:4 है । यदि बड़ी संख्या का वर्ग दूसरी संख्या के वर्गके 8 गुने से 224 कम हो, तो संख्यायें हैं :(होटल मैंनेजमैंट, 1993)(a) 12,16 (b) 6,8(c) 9,12 (d) इनमें से कोई नहीं

Answer»

ANSWER:

answer is OPTION a

PLEASE FOLLOW me

Discussion

39.	11. (cos a + COS B)2 + (sin a + sin B)2 = 4 cos2(A-B/2)
Answer» Step-by-step EXPLANATION: MAY be my ANSWER CORRECT or WRONG

39.

11. (cos a + COS B)2 + (sin a + sin B)2 = 4 cos2(A-B/2)

Answer»

Step-by-step EXPLANATION:

MAY be my ANSWER CORRECT or WRONG

Discussion

40.	If tan A=1 then sec A=?
Answer» Answer: √2 Step-by-step explanation: TAN A=1/1 so by PYTHAGORAS THEOREM h=√2 sec A= h/a= √2/1 = √2 exact VALUE of √2 is 1.414

40.

If tan A=1 then sec A=?

Answer»

Answer:

√2

Step-by-step explanation:

TAN A=1/1

so by PYTHAGORAS THEOREM h=√2

sec A= h/a= √2/1 = √2

exact VALUE of √2 is 1.414

Discussion

41.	Write in ascending order of 6.8, 8.66, 8.06 and 8.68
Answer» Answer: 6.8 < 8.06 < 8.66 < 8.68 Step-by-step EXPLANATION:

41.

Write in ascending order of 6.8, 8.66, 8.06 and 8.68

Answer»

Answer:

6.8 < 8.06 < 8.66 < 8.68

Step-by-step EXPLANATION:

Discussion

42.	Ii) -14 x -13 + 14 -124 14 25 14
Answer» ANSWER is 195..... 42+14-1

42.

Ii) -14 x -13 + 14 -124 14 25 14

Answer»

ANSWER is 195.....

42+14-1

Discussion

43.	1). Which of the following are not nationalnumbers? (solve it with methods).(i) 755(ii)(rez) 11+125(1) T+2(u) ~36 -
Answer» ANSWER: YES 755 is NATIONAL NUMBER

43.

1). Which of the following are not nationalnumbers? (solve it with methods).(i) 755(ii)(rez) 11+125(1) T+2(u) ~36 -

Answer»

ANSWER:

YES 755 is NATIONAL NUMBER

Discussion

44.	Find the HCF of the following by using Euclid algorithm.(i) 50 and 70(ii) 96 and 72(111) 300 and 550
Answer» Answer: 2. 96=72×1+24 72=24×3+0 HCF= 24

44.

Find the HCF of the following by using Euclid algorithm.(i) 50 and 70(ii) 96 and 72(111) 300 and 550

Answer»

Answer:

2. 96=72×1+24

72=24×3+0

HCF= 24

Discussion

45.	Evaluate (-15)divide [(-50)+(-1)]
Answer» ANSWER: - 15 ÷-50- 1 -15 ÷ -51 0•291176470588

45.

Evaluate (-15)divide [(-50)+(-1)]

Answer»

ANSWER:

- 15 ÷-50- 1

-15 ÷ -51

0•291176470588

Discussion

46.	Xercise-17(a) in a quadrilateral ABCD, ZA = 120°, B = 60° and ZC = 90. Find 2D.
Answer» Step-by-step EXPLANATION: hhehehehyeyehebeie TV ETEE

46.

Xercise-17(a) in a quadrilateral ABCD, ZA = 120°, B = 60° and ZC = 90. Find 2D.

Answer»

Step-by-step EXPLANATION:

hhehehehyeyehebeie TV ETEE

Discussion

47.	Subtract the following integers 22 from 0
Answer» ANSWER: -22 hope it HELP MARK as BRAINLIEST

47.

Subtract the following integers 22 from 0

Answer»

ANSWER:

-22

hope it HELP MARK as BRAINLIEST

Discussion

48.	1. Find the ratio of 625 gm to 5 kg. Also find 5 kg to 625 gm.
Answer» Answer: 125/125= 1 *hope* *it's* *HELP you* *MATE*

48.

1. Find the ratio of 625 gm to 5 kg. Also find 5 kg to 625 gm.

Answer»

Answer:

125/125= 1

hope it's HELP you MATE

Discussion

49.	3-2 x 3-5 is equal to: a. 3-7 b. 37 c. 3-3 d. 3-10
Answer» Answer: 4327654447635526634

49.

3-2 x 3-5 is equal to: a. 3-7 b. 37 c. 3-3 d. 3-10

Answer»

Answer:

4327654447635526634

Discussion

50.	Class mark of (39-40) and (60-70) are
Answer» ANSWER: the classnark of GIVEN DATA is 39.5,65.5

50.

Class mark of (39-40) and (60-70) are

Answer»

ANSWER:

the classnark of GIVEN DATA is

39.5,65.5

Discussion

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