Explore topic-wise InterviewSolutions in Current Affairs.

Answer:

Every PRIME NUMBER is ODD expect number " 2 " .

Because 2 is even number .

ANSWER:

Answer to this QUESTION is 62/55

Step-by-step explanation:

31/11*2/5

62/55

ANSWER:

RS. 662 was the amount SPEND by MEENU.

Step-by-step explanation:

Cost of books= 156rs

Cost of stationery=217rs

Cost of Medicines=289

Money spent by Meenu= 156+217+289=662Rs

Plz mark my answer as the BRAINLIEST...

Step-by-step EXPLANATION:

FIND it by FACTORIZATION METHOD

Answer:

*HEY Mate Here is your answere If you are satisfied with it than plz MARK as BRAINLIST answere*

Step-by-step explanation:

x+2/9=x+4/11

x-x=-2/9+4/11

=12/99+36/99

=48/99

plz FOLLOW

ANSWER:

the answer of this QUESTION is xsqare-x/2-3

EAST!

from starting point, GO to north i e 

^

|

then TURN right,

^ - >

|

then turn right again,

^ - >

| |

V

then go left ,

^ - >

| |

v - > EAST!

N

|

W- -E

|

S....

Answer:

actually ANS. C and d is CORRECT

Step-by-step explanation:

but SIMPLY c is correct PLZ mark as brainlist

ANSWER:

heya mate there's your answer

1(-3)(-10)(2)=-3(-20)

=60 (- × - = +)

hope it helps you

Thank you

ANSWER:

it is simple

Step-by-step explanation:

look the image I solved it SIMPLY for you it is 1618(just cutted from pic)

plz mark as BRAINLIST

ANSWER:

APPROX 1.097 or SOMETHING ELSE

INTEGERS are the COLLECTION of WHOLE numbers and NEGATIVE numbers.

Example are -

-2

0

5

ANSWER:

hello mate it's so simple

formula is Tn=a+(n-1)d (or) an= a+(n-1)d

Step-by-step EXPLANATION:

a= 8.5

d= 6.9-8.5= -1.6

n=151.5

values PUT in formula

Tn=8.5+(151.5-1)(-1.6)

Tn=8.5+150.5(-1.6)

Tn=8.5-240.8

Tn= -232.3

✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️

ANSWER:

i THINK no ................

1020 is the REQUIRED NUMBER.

i) 96,13,12,7,5,5

ii) 525,2

Answer:

LET ANGLE =x

x=1/3*(180-x)

3x=180-x

4x=180

x=45

angle is 45

hope it helps you

mark me as BRAINLIEST pls

follow me

Step-by-step EXPLANATION:

HOPE it is HELPFUL to you

ANSWER:

• X=1/2
• p(x) =x^2-4x
• p(1/2) =(1/2) ^2-4×1/2
• =1/4-2
• =-3/4

the answer is -3/4.....

Answer:

MATTER is somethich which has some MASS and occupy some space.

characterstics :

1.Particles of matter are CONTINUOUSLY moving.

2.Particles of matter ATTRACT each other.

Answer:

Hydrofluorocarbon (HFC), any of several organic compounds composed of hydrogen, fluorine, and carbon. HFCs are produced synthetically and are used primarily as refrigerants. They became widely used for this purpose beginning in the late 1980s, with the introduction of the Montreal Protocol, which phased out the use of chemicals such as halons and chlorofluorocarbons (CFCs) that contribute to the depletion of Earth’s ozone layer. However, while HFCs have an ozone depletion potential of zero, they are potent greenhouse gases, and thus their manufacture and use became increasingly regulated in the 21st century.

In general, HFCs are relatively nonflammable, chemically stable, and nonreactive. MANY are colourless, odourless gases, but some—such as HFC-365mfc (1,1,1,3,3-pentafluorobutane)—are liquids at room temperature. As refrigerants, HFCs are used in a wide variety of cooling SYSTEMS, from refrigerators and freezers to automotive air-conditioning units. HFCs are also used as blowing agents in the production of polymer foams; as firefighting agents (having replaced halons); as solvents in cleaning products for plastics and metals and in plasma etching for semiconductor technology; and as propellants in metred-dose inhalers prescribed for the treatment of asthma.

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There are different routes to the synthesis of HFCs. For example, HFC-134a (1,1,1,2-tetrafluoroethane, or R134a), one of the most widely used HFCs, can be prepared from trichloroethylene or tetrachloroethylene through halogen exchange and hydrofluorination, in which chlorine is replaced by hydrogen and fluorine, or through isomerization followed by hydrogenolysis, in which hydrogen is used to split an isomer into the desired reaction products. Other HFCs may be prepared through the fluorination of olefins (unsaturated hydrocarbons containing at least one carbon-carbon double bond) with hydrogen fluoride.

Once released into the atmosphere, HFCs decompose relatively quickly; for example, the atmospheric lifetime for HFC-134a is about 14 years. (CFCs, by comparison, can remain in the atmosphere for 100 years.) The breakdown of HFCs occurs in the troposphere (the lowest portion of the atmosphere), where they are split by reactions with hydroxyl radicals (∙OH). Within the troposphere, the carbon-fluorine bonds in HFCs are highly effective at trapping solar radiation (specifically, infrared radiation) and redirecting that radiant energy toward Earth’s surface. This so-called positive radiative forcing effect contributes to global warming.

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In 2007 the average 100-year global warming potential (GWP) of HFCs was estimated to be 3,770 times that of carbon dioxide (the standard reference chemical for GWP calculations); weighted averaging (based on HFC consumption) predicted a 100-year GWP of 2,400 by 2040. Warming potential, however, varies widely for the individual HFCs. For instance, HFC-23 (trifluoromethane), which is generated as a by-product in the production of the hydrochlorofluorocarbon HCFC-22 (chlorodifluoromethane), has an atmospheric lifetime of 270 years and a 100-year GWP of 11,700, which surpasses known GWPs for some of the most environmentally harmful CFCs.

HFCs have become increasingly abundant in Earth’s atmosphere. For example, between 1978 and 2005, atmospheric concentrations of HFC-23 increased from about 3 to around 18 parts per trillion (ppt). Likewise, concentrations of HFC-134a increased from levels that were undetectable prior to the 1990s to about 35 ppt in 2005. Because they are anthropogenic (human-generated) sources of positive radiative forcing, HFC emissions have been targeted for reduction by the Kyoto Protocol.

Kara Rogers

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Hydrogen (H), a colourless, odourless, tasteless, flammable gaseous substance that is…

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Answer:

0/10

Step-by-step EXPLANATION:

it is because no BLUE BALL is there in BAG

Aryabhata was an acclaimed mathematician-astronomer. He was born in Kusumapura (present day Patna) in Bihar, India. His contribution to mathematics, science and ASTRONOMY is immense, and yet he has not been accorded the recognition in the world history of science. At the age of 24, he wrote his famed “Aryabhatiya”. He was aware of the concept of zero, as well as the use of large numbers up to 1018. He was the first to calculate the value for ‘pi’ accurately to the fourth decimal point. He devised the formula for CALCULATING areas of triangles and circles. He calculated the circumference of the earth as 62,832 miles, which is an excellent approximation, and suggested that the apparent rotation of the heavens was due to the axial rotation of the earth on its axis. He was the first known astronomer to devise a continuous counting of solar days, designating each day with a number. He asserted that the planets shine due to the reflection of sunlight, and that the eclipses occur due to the shadows of moon and earth. His observations discount the “flat earth” concept, and lay the foundation for the belief that earth and other planets orbit the sun.

A verse mentions that Aryabhata was the head of an institution (kulapa) at Kusumapura. Since, the University of Nalanda was in Pataliputra, and had an astronomical observatory; it is probable that he was its head too.

Direct details of his work are known only from the Aryabhatiya. His DISCIPLE Bhaskara I calls it Ashmakatantra (or the treatise from the Ashmaka).

The Aryabhatiya is ALSO occasionally referred to as Arya-shatas-aShTa (literally, Aryabhata’s 108), because there are 108 verses in the text. It also has 13 introductory verses, and is divided into four pādas or chapters.

Aryabhatiya’s first chapter, Gitikapada, with its large units of time — kalpa, manvantra, and Yuga — introduces a different cosmology. The duration of the planetary revolutions during a mahayuga is given as 4.32 million years.

Ganitapada, the second chapter of Aryabhatiya has 33 verses covering mensuration (kṣetra vyāvahāra), arithmetic and geometric progressions, gnomon or shadows (shanku-chhAyA), simple, quadratic, simultaneous, and indeterminate equations.

Aryabhatiya’s third chapter Kalakriyapada explains different units of time, a method for determining the positions of planets for a given day, and a seven-day week with names for the days of week.

The last chapter of the Aryabhatiya, Golapada describes Geometric/trigonometric aspects of the celestial sphere, features of the ecliptic, celestial equator, shape of the earth, cause of day and night, and zodiacal signs on horizon.

He did not use a symbol for zero; its knowledge was implicit in his place-value system as a place holder for the powers of ten with null coefficients.

He did not use the Brahmi numerals, and continued the Sanskritic tradition from Vedic times of using letters of the alphabet to denote numbers, expressing quantities in a mnemonic form.

He worked on the approximation for pi thus — add four to 100, multiply by eight, and then add 62,000, the circumference of a circle with a diameter of 20,000 can be approached.

It is speculated that Aryabhata used the word āsanna (APPROACHING), to mean that not only is this an approximation, but that the value is incommensurable or irrational.

In Ganitapada, he gives the area of a triangle as: “for a triangle, the result of a perpendicular with the half-side is the area”. He discussed ‘sine’ by the name of ardha-jya or half-chord.

Like other ancient Indian mathematicians, he too was interested in finding integer solutions to Diophantine equations with the form ax + by = c; he called it the kuṭṭaka (meaning breaking into pieces) method.

Aryabhata’s major work, Aryabhatiya, a compendium of mathematics and astronomy, was extensively referred to in the Indian mathematical literature, and has survived to modern times. The Aryabhatiya covers arithmetic, algebra, and trigonometry.

Step-by-step EXPLANATION:

here is your ANSWR bro but i have not enough time to simplify it so app kar lena

hope it helps u

please MARK it as braienlist

ANSWER:

prime numbers...........which has 1 and the NUMBER itself as FACTORS

ANSWER:

Step-by-step EXPLANATION:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

ANSWER:

Step-by-step EXPLANATION:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

Answer:

1st ANS k=6

Step-by-step EXPLANATION:

HOPE you GET it

Answer:

Step-by-step EXPLANATION:

SORRY for drawing AB LINE little slanted.

Step-by-step EXPLANATION:

HOPE it is HELPFUL to you

Answer:

The SUMS are SOLVED step by step. I HOPE that it HELPS you.

7/2 × 21/5 = 147/10

5/2 × 16/3 = 80/6

Step-by-step EXPLANATION:

= 147/10 ÷ 80/6

= 147/10 × 6/80 (RECIPROCAL)

= 842/800

= 421/400 ANSWER :)

I HOPE it's HELP.....:)

HEY MATE here is your answer

from Google

hope it HELPS y

ANSWER:

HOPE this HELPS U

plz follow

ANSWER:

HOPR it HELPS U.......

ANSWER:

Step-by-step EXPLANATION:

Answer:

1.25

Step-by-step explanation:

75 MINUTES in HOUR

=75/60

=1.25 hour

Answer:72.1325

Step-by-step explanation:

61/4 kg = rs 400

1 kg = (?)

= 400/61/4

= 400 × 4 ÷ 61

= 1600 ÷ 61

= rs26.23

1 Kg=rs 26.23

cost of 11/4 Kg apples=11/4 × 26.23

=72.1325

ANSWER:

yes

Step-by-step EXPLANATION:

we NEED to put 11 in PLACE of x and verify

ANSWER:

A = 7 -4√3

1/a = 1/( 7 -4√3) = (7-4√3)/(7-4√3)(7+4√3)

=(7+4√3)/(49-48) = (7+4√3)

so, √a = √( 7 -4√3)

= √(2²+√3²-2.2√3)

=√(2 -√3)² = ( 2 -√3)

same way ,

1/√a = √(2² +√3² +2.2√3)

=√(2+√3)²

=(2 +√3)

now ,

√a + 1/√a = (2 -√3) + (2 + √3) = 4

¶Heya please I think the language is not ENGLISH and it's not a proper QUESTIONS!!

you must describe it in English!!

$Aléx

<P>Step-by-step EXPLANATION:

p(x)=2x-3x+2=2-x

x=2

p(2)=0 if2x-3x+2is a FACTOR of p(x)

2*3+2*2a-b*2+10=0

6+4a-2b+10=0

16+4a-2b=0

2(8+2a-b) =0

8+2a-b=0

2a-b=-8

a-b=-4

a-b=0-4

a=0

b=-4

ANSWER:

Step-by-step EXPLANATION:

Answer:

20993/10

Step-by-step explanation:

DECIMAL counting then REMOVING DECIMALS by multiply 10's which has more

219×104

= 219×100+4

= 21900+400

= 22300 is the ANSWER

Answer:

X = 8

Step-by-step EXPLANATION:

as 2*LOG20 - log 25 = log 400- log25

                                 =   log400/25

        2*log(x-4)= log 16

log(x-4) = log 16 / 2

   log x-4 = log 4

x-4 =4

x=8

Step-by-step explanation:

Please POST UR COMPLETE QUESTION!!!!

Answer:

1000 coins.

Step-by-step explanation:

As weight of 1 coin is 7 G and 7 kg= 7000 g. We can SAY that there are 7000/7 coins = 1000 coins in the BAG.

Step-by-step EXPLANATION:

We know that TAN A = SIN A/Cos A

and we know the VALUES of

sin45°=1/√2

cos 45°=1/√2

So Tan 45°=[1/√2]/[1/√2]

here √2 gets CANCELLED

if not got the above step please refer the attachment

and it equals to 1

Thank you

Regards

Answer:

6 HOPE it HELPS just SQUARE the LAST DIGIT