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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The sum of three constructive integers is 123 . Find the integers |
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| 2. |
Exercise 8.11. Write the following in ratio form and simplify if possible.4/5with complete solution |
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Answer» dggjfjjghhhb466_-&&&--&&:' |
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| 3. |
Find the smallest number which when divided separately by 12 20 and 24 leaves 7 as a reminder |
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| 4. |
Write the smallest and the largest number which when rounded off give the result 240 |
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Answer» Answer: |
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| 5. |
10-JUN-TERomesh,Rdevollege& shear stofons in ophave formFull harfReinigerV=>loor |
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| 7. |
Give the following in polar formsin 120°-icos 120 |
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Answer» 1/2½-i Will be the answer |
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| 8. |
12. 104810andfrom15915. Subtract the sum of 9 |
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Answer» I don't KNOW Step-by-step EXPLANATION: I don'T know MC |
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| 9. |
If x= 9+4√5 , find the value of √x-1/√x |
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Answer» Step-by-step explanation: X= 9+4√5
√x = √(9+4√5) √x = √ 5+4 +2(2)(√5) √x = √(√5+2)^2 √x = √5 + 2
then ... 1 = 1 √x √5+2 1 X. √5-2 √5+2. √5-2 ==. √5 - 2 / 5-4 ==. √5-2 / 1
>>>>. √5 -2 hope it's◉‿◉ helpful |
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| 10. |
Find least number which subtracted from 58570 to make a perfect square |
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Answer» Step-by-step explanation: Square root of 58570=242 and REMAINDER =6 Since, remainder =6 Therefore, we must subtract 6 from 58570 =58570-6 =58564 Square root of 58564=242 |
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| 11. |
1lakh is equal to how many 10 thousand |
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Answer» Answer: 1 lakh is 10 TIMES of 10 thousands plz FOLLOW |
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| 13. |
Find five rational numbers between 4.5 and 7.5 |
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Answer» Answer: 6,7,7.1,7.2,4.6 Step-by-step explanation: we can FIND AVERAGE or do by consecutive METHOD that is counting in DECIMALS |
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| 14. |
Find the 78percent of 987 |
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Answer» Here is your ANSWER.. 78 PERCENT of 987 is 769.86hope it will HELP you |
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| 15. |
D=12A train is moving 73 km chi time- distance covered by its le 25 mmSheed atk 72 Km 1h = 72 mmtime = 25 min |
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Answer» f3554555555555556 is the answer of this QUESTION |
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| 16. |
[উদাহরণdyy = tan-1 হলে, ৩” নির্ণয় করাে। |
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Answer» ঠিক বুঝতে পারছি না কি বলতে চাও ভালো করে বল |
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| 17. |
And b.45. Express 2x = 5 in the form ax + by + c = 0 and find the value of a, band c. |
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Answer» Answer: 5x + 0y -5=0 hope its HELPFUL |
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| 18. |
Find the fraction. 1/2 of 2/3 of 6 kg |
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Answer» Answer: 1/2 × 2/3 × 6/1 12/6 2 KG = 2/1 kg is the answer hope it HELPS you |
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| 19. |
What is the value of p when px^3 +16x^2 + 16x^2+8x-32is devided by (x+2) leaving a 0 as reminder |
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Answer» your QUESTION is INCOMPLETE or WRONG |
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| 20. |
Find the average monthly consumption of oil in a family ,if is uses 5/2 l , 13/4 and 7/2 of oil in three months. |
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Answer» Answer: Step-by-step EXPLANATION: (5/21+13/4+7/2) / 3= 199 |
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| 21. |
Arrange in descending order: 4√10,3√6,√3 |
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Answer» ARRANGED in DESCENDING ORDER, the NUMBERS are :- √3, 3√6, 4√10 |
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| 22. |
How to write MMDCCXLIV in hindu arabic numerals |
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Answer» Answer:2744 Step-by-step explanation: This Roman NUMERAL can be broken down as MM DCC XL IV Now it is SIMPLER to WRITE it in Hindu ARABIC numerals MM=2000,DCC=700,XL=40,IV=4 Now add the numbers 2000+700+40+4=2744 |
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| 23. |
If 12m of a uniform iron rod weight 42kg. What will be the weight of 6m of same rod? |
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Answer» Answer: 21 kg Step-by-step EXPLANATION: 42 =12 m 1M =42/12 1m =3.5 kg so 6m= 3.5x6 6m = 21 kg so 6m ROD having 21 kg |
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| 25. |
The strength of a school is 5,662.When it is rounded off to the nearest 1000,the strength is___? |
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Answer» Step-by-step explanation: |
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| 26. |
The cross-section ABCD of a swimming pool isa trapezium. Its width AB = 14 m, depth at theshallow end is 1.5 m and at the deep end is 8 m.Find the area of the cross-section. |
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Answer» Step-by-step EXPLANATION: |
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| 27. |
There is a circular path around a sports field. Sonia takes 18 minutes to drive one roundof the field, while Ravi takes 12 minutes for the same. Suppose they both start at thesame point and at the same time, and go in the same direction. After how many minuteswill they meet again at the starting point? |
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Answer» Step-by-step explanation: To find the required NUMBER of MINUTES Let us find the LCM of 18 and 12 We have 18 => 2 × 3 × 3 = 2 × 3² 12.=> 2 × 2 × 3 = 2² × 3 LCM (18,12) => 2² × 3² = 36 After 36 minutes Sonia will be at the starting point after completing 2 rounds of the field and RAVI also be at same point after 3 rounds |
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| 28. |
Find the integer whose product with(-1) is 85 |
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| 29. |
There are chairs in a room. if 2 guests share a chair , 1 chair remains vacant and if each guest sits one chair remains standing .What is the number of Guests ?And I know the answer there are 4 guests and 3 chairs. Please solve it . The one who will answer correctly I will follow him or her |
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Answer» ANSWER is in in the ATTACHMENT. |
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| 30. |
(a) two kilometres/bus station/Jatashankar/away/is/from the(b) of the/it is a/Jambodweep stream/the source/scenic cave/and is |
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Answer» a) Jatashankar is TWO kilometres away from the bus STATION . b) It is a scenic cave and is the SOURCE of the Jambodweep stream. |
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| 31. |
Find thesquare root of 576÷729 |
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Answer» HERE IS YOUR ANSWER: ROOT 576/729=24/27 HOPE IT HELPED ^_^ |
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| 32. |
Solve thefollowing:4/x + 3y = 8;6/x-4y=-5class 10th |
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Answer» 4/x+3y=8 6/x-4y=-5 Let 1/x =a So 4a+3y=8 6a-4y=-5 By SOLVING this we GET y =2 and a=1/2 So x ALSO =2 |
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| 33. |
A short paragraph on kartar singh sarabha in punjabi |
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Answer» Answer: Kartar Singh Sarabha (24 May, 1896 - 16 November, 1915) began his involvement in the Gadar Party in San Francisco in 1912. Sarabha was born in India in the year 1896. After his graduation from high school in 1911, he arrived at the University of California, Berkeley to continue his studies in engineering. In Berkeley, he joined the Gadar party in 1913. Around this time, he also learned how to fly. He returned to India in 1914 to fight for his country's independence. On November 16th, 1915, Sarabha was hanged at the tender age of 19. Contents 1 Early life 2 The Ghadar Party and Newspaper 3 Revolt in the Punjab 4 Betrayal 5 Verdict and Execution 6 In the News 7 External Link Early life Sarabha, whose father's name was Sardar Mangal Singh, was born into a Grewal Jat Sikh family at village Sarabha in the district of Ludhiana, Punjab in 1896. When he was fifteen, his parents put him on board a ship bound for America to work there. The ship landed at the American port of San Francisco in January 1912. At that time Asian immigrants were put through rigorous questioning and there numbers were strictly limited, while people of Western European countries were allowed to pass after slight checks. Asking one of his fellow passengers why this was happening, he was told, "Indians are the citizens of a slave country. As such, they are treated badly." This incident had a great effect on Sarabha. Kartar enrolled at the University of California at Berkeley (UCB) and also found seasonal work picking fruit in the vast orchards of California's central valley. Whether at school or in the FIELDS, when time allowed, he frequently talked with other Indians about winning freedom for India. By 1914, vast numbers of Indians were working outside of India. Most were working either as indentured labourers in any of several British Colonies or as soldiers in the British/Indian Armed forces then FIGHTING in Europe (WWI), the Middle East or in one of Britain's Colonies. The Ghadar Party and Newspaper On April 21,1913, the Indians of California assembled and formed the Ghadar (Revolution) Party). The aims of the Ghadar Party were to free India from the slavery of British Rule, by MEANS of an armed struggle and to set up a national democratic government in India. Their slogan was "Put at stake everything for the freedom of the country." On November 1, 1913, the Ghadar Party started printing a paper named 'Ghadar', which was published in the Punjabi, Hindi, Urdu, Bengali, Gujarati and Pushto languages. Kartar Singh did all the work for that paper. This paper was sent to Indians living in all countries throughout the world. The purpose of the paper was to unmask the truth about British rule to Indians, impart military training, and explain in detail the methods of making and using weapons and explosives. Within a short time, the Ghadar Party became very FAMOUS through its organ: 'The Ghadar". It drew Indians from all walks of life. |
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| 34. |
Sin A/1+cosA=cosecA-cot A prove it plzz |
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Answer» LHS = cosecA - cotA = 1/sinA - cosA/sinA = (1 - cosA)/sinA On Rationalising we GET, = (1 - cosA)/sinA * (1 + cosA)/(1 + cosA) = sin^2A/sinA(1 + cosA) = sinA/(1+ cosA) = RHS Hence Proved. ✨Hope it will help you.✨ |
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| 35. |
The roots Of xsquare +kx+k=0 are real and equal find k |
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Answer» I HOPE. .. it's HELP you .......... |
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| 36. |
√(8-2√15) evaluate this |
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Answer» Step-by-step EXPLANATION: √(8-2√15)=√(8-2×3.87) =√(8-7.75) =√(0.25) =0.5Answer |
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| 37. |
Find the product using suitable properties 52*(99)+(-52) |
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Answer» HERE IS YOUR ANSWER: 52×99+(-52)=52×99-52
=52(99-1)=52×98=5096 |
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| 38. |
Find the sum of the first 18 terms of the Ap 11,8,5,3... |
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Answer» GIVEN : AP : 11,8,5,3... Difference = A2 - a1 = 8 - 11 = -3 In an AP, = 18/2 [ 2(11) + (18-1)-3 ] = 9 [ 22 + (17)-3 ] = 9 [ 22 + (-51) ] = 9 [ 22 - 51 ] = 9 [ -29] = -261 Therefore, the sum of first 12 terms is -261 |
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| 39. |
Please answer as fast as possible if 4x-3y =√3 is a tangent to a hyperbola 4x^2 - 9y^2 =1 then the eccentric angle of point of contact isa)45b)30c)60d)90please give solution |
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| 40. |
The roots OF xsquare +kxh+k=0 are real and equal find k |
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Answer» your QUESTION is INCOMPLETE or WRONG..... |
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| 41. |
1student got 489 mark in exam from 650 . find its percentage |
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Answer» Answer: 489/ 650 * 100 75.23 =answer Step-by-step EXPLANATION: This is UR PERCENTAGE |
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| 42. |
Using appropriate properties of operation of rational numbers evaluate 3/13*4/5-7/5-4/5*5/13 |
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Answer» -99/65 Step-by-step EXPLANATION: =3/13*4/5-7/5-4/5×5/13 =12/65-7/5-4/13 =(12-91-20)/65 =-99/65 |
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| 43. |
the number 16 is divided into two parts , one of them being three times the other . find two parts |
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Answer» HEY MATE! HERE IS YOUR ANSWER: LET ONE part be x so, other will be 3x Now , 3x+x=16 4x=16 x=4. 3x=3×4=12 Thus , two parts are 4 and 12. HOPE IT HELPED ^_^ |
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| 44. |
24. If the vertices of a AABC are A(-1, 3, 2), B (2, 3, 5) and C (3,5, -2), then show that it isright angled at A. Also find the other two angles. |
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| 45. |
Write the square root 1 to 25 |
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Answer» Step-by-step explanation: square root of 1 is 1 2is 4 3 is 9 4 is 16 5 is 25 6 is 36 7 is 49 8 is 64 9 is 81 10 is 100 11 is 121 12 is 144 13 is 169 14 is 196 15 is 225 16 is 256 17 is 289 18 is 324 19 is 361 20 is 400 21 is 441 22 is 484 23 is 529 24 is 576 25 is 625 i hope this will help you plz follow me |
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| 46. |
the base of the right pyramid is a square of side 27 cm long. If the volume of the pyramid is 3159 cm", then its height is: |
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Answer» Answer: 13 CM Explanation Area of square base of pyramid=a^2=27cm^2 VOLUME of pyramid =1/3(volume of CUBOID of same base and HEIGHT) =1/3(a^2h)=3159cm^3 h=(3×3159)/a^2 =(3×3159)/27^2 =(3×117)/27 =117/9 =13cm |
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| 47. |
Classify the number rational or irrational |
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Answer» HEY MATE! HERE IS YOUR ANSWER : 2 pie is irrational number SINCE VALUE of pie is NON terminating |
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| 48. |
Please friend solve the question of example number 8 |
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Answer» Step-by-step EXPLANATION: |
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| 49. |
Find 2 irrational no between root 2 and root 7 |
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Answer» Answer: 2 irrational no. between root 2 and root 7 are root 3 and root 5 hope it helps you MARK it as BRAINLIEST and thank me and FOLLOW me |
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| 50. |
(iv) (-49) ÷ (-49)solve yarrr |
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Answer» HEY MATE! HERE IS YOUR ANSWER: -49/-49=1 |
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