332354 + Interview Questions in Secondary School in Math

1.	संख्या 12 एवं 18 के प्रथम तीन साझा गुण बताएं
Answer» Answer: 12 का गुणज = 12, 24, 36, 48, 60, 72, 84, 96, 108 18 का गुणज = 18, 36, 54, 72, 90, 108, इसतरह, 12 और 18 का प्रथम तीन सार्व गुणज 36, 72 और 108 है।

1.

संख्या 12 एवं 18 के प्रथम तीन साझा गुण बताएं

Answer»

Answer:

12 का गुणज =

12, 24, 36, 48, 60, 72, 84, 96, 108

18 का गुणज =

18, 36, 54, 72, 90, 108,

इसतरह, 12 और 18 का प्रथम तीन सार्व गुणज 36, 72 और 108 है।

Discussion

2.	Join all points and tell the figure made1) rectangle2) square3) parallelogram4) rhombus
Answer» ANSWER: $paralleogram$ HOPE it HELPS uh❤

2.

Join all points and tell the figure made1) rectangle2) square3) parallelogram4) rhombus

Answer»

ANSWER:

$paralleogram$

HOPE it HELPS uh❤

Discussion

3.	Find the mean, mode and median for the following data: Classes 0-10 10-20 20-30 30-40 40-50 50-60 60-70 Frequency 6 8 10 15 5 4 2
Answer» 56 boy yofyxrcjgcyvuctxfvkv

3.

Find the mean, mode and median for the following data: Classes 0-10 10-20 20-30 30-40 40-50 50-60 60-70 Frequency 6 8 10 15 5 4 2

Answer»

56 boy

yofyxrcjgcyvuctxfvkv

Discussion

4.	The sum of first 7 terms of an arithmetic sequence is 119 and the sum of first 11terms is 275 .a)what is its 4th termb)what is its 6th termc)what is its common difference
Answer» Answer: a first Step-by-step EXPLANATION: ROLL no from HOT MAJA mo varasad vadhu n.b

4.

The sum of first 7 terms of an arithmetic sequence is 119 and the sum of first 11terms is 275 .a)what is its 4th termb)what is its 6th termc)what is its common difference

Answer»

Answer:

a first

Step-by-step EXPLANATION:

ROLL no from HOT MAJA mo varasad vadhu n.b

Discussion

5.	At what rate percent per annum ₹1600amount to ₹1852.20 in 3/2 years,interest being compounded half-yearly?
Answer» ANSWER: ggffhggggggggggfttttyyyyggghy

5.

At what rate percent per annum ₹1600amount to ₹1852.20 in 3/2 years,interest being compounded half-yearly?

Answer»

ANSWER:

ggffhggggggggggfttttyyyyggghy

Discussion

6.	Multiply the following3x-5+2x^2 and 5x+2
Answer» Step-by-step EXPLANATION: We have (2x 2 −3x+5)×(5x+2) (2x 2 −3x+5)×5x+(2x 2 −3x+5)×2 (10x 3 −15x 2 +25X)+(4X 2 −6x+10) 10x 3 −11x 2 +19x+10 PLZ MARK ME BRAINLIEST AND PLZ FOLLOW ME

6.

Multiply the following3x-5+2x^2 and 5x+2

Answer»

Step-by-step EXPLANATION:

We have

(2x

2

−3x+5)×(5x+2)

(2x

2

−3x+5)×5x+(2x

2

−3x+5)×2

(10x

3

−15x

2

+25X)+(4X

2

−6x+10)

10x

3

−11x

2

+19x+10

PLZ MARK ME BRAINLIEST

AND PLZ FOLLOW ME

Discussion

7.	7 upon 10 convert the following ratio into percentage
Answer» Step-by-step EXPLANATION: ANSWER for this QUESTION is 7/10 * 100 = 70%

7.

7 upon 10 convert the following ratio into percentage

Answer»

Step-by-step EXPLANATION:

ANSWER for this QUESTION is

7/10 * 100

= 70%

Discussion

8.	Examine the series. 1+1/2^2+2^2/3^3+3^3/4^4+.... For convergence
Answer» ANSWER: -(1/12) ACCORDING to the THEORM

8.

Examine the series. 1+1/2^2+2^2/3^3+3^3/4^4+.... For convergence

Answer»

ANSWER:

-(1/12) ACCORDING to the THEORM

Discussion

9.	the cost of making 5000 units is £14000 and the cost of making 10000units in the same manner is £17000. Fixed cost is £ 11000
Answer» ANSWER: I DONT KNOW THE ANSWER Step-by-step EXPLANATION:

9.

the cost of making 5000 units is £14000 and the cost of making 10000units in the same manner is £17000. Fixed cost is £ 11000

Answer»

ANSWER:

I DONT KNOW THE ANSWER

Step-by-step EXPLANATION:

Discussion

10.	The difference of the digit of two of the digit cannot be
Answer» Answer: ur answer is here hope it helps u hope it is clear pls mark me as a brainliest Step-by-step explanation: Answer Let the unit's DIGIT be y and TEN's digit be x. Then, the number =10x+y. When we interchange the digits, the number will be 10y+x. Now, it is GIVEN that the DIFFERENCE between a TWO digit number and the number obtained by interchanged the two digits of the number is 9, therefore, we have: (10x+y)−(10y+x)=9 ⇒9x−9y=9 ⇒9(x−y)=9 ⇒x−y= 9 9 ⇒x−y=1 Hence, the difference between the two digits of number is 1.

10.

The difference of the digit of two of the digit cannot be

Answer»

Answer:

ur answer is here hope it helps u hope it is clear pls mark me as a brainliest

Step-by-step explanation:

Answer

Let the unit's DIGIT be y and TEN's digit be x.

Then, the number =10x+y. When we interchange the digits, the number will be 10y+x.

Now, it is GIVEN that the DIFFERENCE between a TWO digit number and the number obtained by interchanged the two digits of the number is 9, therefore, we have:

(10x+y)−(10y+x)=9

⇒9x−9y=9

⇒9(x−y)=9

⇒x−y=

9

⇒x−y=1

Hence, the difference between the two digits of number is 1.

Discussion

11.	Write your question here (Keep it simple and clear to get the best answer)(1.02)³
Answer» ANSWER: UR answer is here HOPE it helps u hope it is clear PLS mark me as a brainliest Step-by-step EXPLANATION: yes u are correct

11.

Write your question here (Keep it simple and clear to get the best answer)(1.02)³

Answer»

ANSWER:

UR answer is here HOPE it helps u hope it is clear PLS mark me as a brainliest

Step-by-step EXPLANATION:

yes u are correct

Discussion

12.	The value of1 11ofis2 3 56A) 5(B) 1(C)65.(D)36
Answer» ANSWER: Equation is 1\2 x 1\3 x 5 of 6 Of MEANS multiply ..as per BORDER Now equation is = 1\2 x 1\3 x 5 x 6 Now 6 by 3 = 2 Now equation 5 x 2\2 = 1O by 2 ...which is 5 So answer 5 If u want i can send u picture of my answer...wanted so tell me in comments

12.

The value of1 11ofis2 3 56A) 5(B) 1(C)65.(D)36

Answer»

ANSWER:

Equation is 1\2 x 1\3 x 5 of 6

Of MEANS multiply ..as per BORDER

Now equation is = 1\2 x 1\3 x 5 x 6

Now 6 by 3 = 2

Now equation 5 x 2\2 = 1O by 2 ...which is 5

So answer 5

If u want i can send u picture of my answer...wanted so tell me in comments

Discussion

13.	Simplify - √50 - √32
Answer» I am *loggy* on *the* *youtu*9 8 7 6 PM be 10

Discussion

14.	If F = 15 when a = 3, find a when F = 70.
Answer» Step-by-step explanation: 15/3=70/a a=70×3/15 a=14....

14.

If F = 15 when a = 3, find a when F = 70.

Answer»

Step-by-step explanation:

15/3=70/a

a=70×3/15

a=14....

Discussion

15.	The inner circumference of a circular track is 242 metre the track is uniformly 7 metre wide find the area of the track
Answer» GIVEN :- Inner CIRCUMFERENCE = 242 m Width of the track = 7 m To Find :- Area of the truck Solution :- RADIUS of the circle :- $:\implies\:\sf{ 2 \pi r=242}$ $:\implies\:\sf{ 2 \times \dfrac{22}{7} \times r=242}$ $:\implies\:\sf{ \dfrac{7}{44} \times r=242}$ $:\implies\:\sf{r= \dfrac{7}{44} \times 242}$ $:\implies\:\sf{r= \dfrac{7}{2} \times 11}$ $:\implies\:\sf{r= \dfrac{77}{2} }$ $:\implies\:\sf\pink{r= 38.5\:m }$ Hence, Inner Radius = 38.5 m Outer radius of the circle :- $:\implies\:\sf{Inner\:Radius +Width \:of\:the\:track}$ $:\implies\:\sf{38.5 +7}$ $:\implies\:\sf\blue{45.5 \:m}$ Area along with the track :- $:\implies\:\sf{\pi r^2}$ $:\implies\:\sf{\dfrac{22}{7}\times 45.5 \times 45.5 }$ $:\implies\:\sf{45545.\:\dfrac{5}{7} }$ $:\implies\:\sf\blue{6506.5 \:m^2 }$ Area without track :- $:\implies\:\sf{\pi r^2}$ $:\implies\:\sf{\dfrac{22}{7}\times 38.5 \times 38.5 }$ $:\implies\:\sf{32609.\:\dfrac{5}{7} }$ $:\implies\:\sf\purple{4658.5\:m^2}$ Area of the track :- $:\implies\:\sf{Area\:along\:with\:track-Area\:without\:track }$ $:\implies\:\sf{6506.5-4658.5 }$ $:\implies\:\sf\purple{<klux>1848</klux>\:m^2 }$ Therefore, Area of the track = 1848 m²

15.

The inner circumference of a circular track is 242 metre the track is uniformly 7 metre wide find the area of the track

Answer»

GIVEN :-

Inner CIRCUMFERENCE = 242 m
Width of the track = 7 m

To Find :-

Area of the truck

Solution :-

RADIUS of the circle :-

$:\implies\:\sf{ 2 \pi r=242}$

$:\implies\:\sf{ 2 \times \dfrac{22}{7} \times r=242}$

$:\implies\:\sf{ \dfrac{7}{44} \times r=242}$

$:\implies\:\sf{r= \dfrac{7}{44} \times 242}$

$:\implies\:\sf{r= \dfrac{7}{2} \times 11}$

$:\implies\:\sf{r= \dfrac{77}{2} }$

$:\implies\:\sf\pink{r= 38.5\:m }$

Hence,

Inner Radius = 38.5 m

Outer radius of the circle :-

$:\implies\:\sf{Inner\:Radius +Width \:of\:the\:track}$

$:\implies\:\sf{38.5 +7}$

$:\implies\:\sf\blue{45.5 \:m}$

Area along with the track :-

$:\implies\:\sf{\pi r^2}$

$:\implies\:\sf{\dfrac{22}{7}\times 45.5 \times 45.5 }$

$:\implies\:\sf{45545.\:\dfrac{5}{7} }$

$:\implies\:\sf\blue{6506.5 \:m^2 }$

Area without track :-

$:\implies\:\sf{\pi r^2}$

$:\implies\:\sf{\dfrac{22}{7}\times 38.5 \times 38.5 }$

$:\implies\:\sf{32609.\:\dfrac{5}{7} }$

$:\implies\:\sf\purple{4658.5\:m^2}$

Area of the track :-

$:\implies\:\sf{Area\:along\:with\:track-Area\:without\:track }$

$:\implies\:\sf{6506.5-4658.5 }$

$:\implies\:\sf\purple{<klux>1848</klux>\:m^2 }$

Therefore,

Area of the track = 1848 m²

Discussion

16.	11 paise to rupees 0.59 in ratio
Answer» Answer: 11paise : 1/2rupees Step-by-step EXPLANATION: PAISE in PASE RUPEES in paise - 1/2rupees

16.

11 paise to rupees 0.59 in ratio

Answer»

Answer:

11paise : 1/2rupees

Step-by-step EXPLANATION:

PAISE in PASE RUPEES in paise - 1/2rupees

Discussion

17.	44 bags of paddy costs rs.16800 then find the cost of 36 bags of paddy
Answer» 44 BAGS of PADDY = RS 16800 1 bags of paddy = Rs (16800/44) = 381.8 36 bags of paddy = (381.8 × 36) = Rs 13745

17.

44 bags of paddy costs rs.16800 then find the cost of 36 bags of paddy

Answer»

44 BAGS of PADDY = RS 16800

1 bags of paddy = Rs (16800/44) = 381.8

36 bags of paddy = (381.8 × 36) = Rs 13745

Discussion

18.	The least number that should be divided with 9491× 8165 to make it a perfect square is
Answer» Answer: 77494015 HOPE this WELL HELP FUL

18.

The least number that should be divided with 9491× 8165 to make it a perfect square is

Answer»

Answer:

77494015 HOPE this WELL HELP FUL

Discussion

19.	You play a game with 0.3 as the probability of winning. What is the probability that you win 4 or more games out of 10
Answer» Let A be an event of winning and B be an event of losing the game. Given P(A)=0.3 Total PROBABILITY =P(A)+P(B) ⇒ 1=0.3+P(B) ⇒ P(B)=1−0.3=0.7 ∴ P(B)= MARK ME AS A BRAINLIEST

Discussion

20.	What will be the value of y- in the system y=x-1 x+3y=5
Answer» Step-by-step explanation: if y=X-1 x+3y=5 x+3(x - 1)=5 x+3x-3=5 collect like terms x+3x=5+3 4x=8 divide both SIDES by 4 x=2 if x=2 and GIVEN y=x-1 y=2-1 y=1

20.

What will be the value of y- in the system y=x-1 x+3y=5

Answer»

Step-by-step explanation:

if y=X-1

x+3y=5

x+3(x - 1)=5

x+3x-3=5

collect like terms

x+3x=5+3

4x=8

divide both SIDES by 4

x=2

if x=2

and GIVEN y=x-1

y=2-1

y=1

Discussion

21.	Find the height of cyclinder whose volume is 1.54 m ^3 and diameter is 140 cm
Answer» ANSWER: OKAY CHECK out this page Step-by-step EXPLANATION:

21.

Find the height of cyclinder whose volume is 1.54 m ^3 and diameter is 140 cm

Answer»

ANSWER:

OKAY CHECK out this page

Step-by-step EXPLANATION:

Discussion

22.	Find the diameters of circles having the following areas.( 1 ) 5544m2
Answer» Answer: 84M Step-by-step EXPLANATION: AREA of circle=πr^2 5544m^2=22/7r^2 55447m^2=22r^2 r^2=5544/227m^2 r^2=2527m^2 r^2=1764m^2 .: r=√1764m^2 =42M d=2r =2*42m =84m

22.

Find the diameters of circles having the following areas.( 1 ) 5544m2

Answer»

Answer:

84M

Step-by-step EXPLANATION:

AREA of circle=πr^2

5544m^2=22/7*r^2

5544*7m^2=22r^2

r^2=5544/22*7m^2

r^2=252*7m^2

r^2=1764m^2

.: r=√1764m^2

=42M

d=2r

=2*42m

=84m

Discussion

23.	What is volume of boxHow much area did Suresh paintHow much area did Deepak paintWhat amount did Harsh chargeWhat amount did veena pay for painting
Answer» SOLUTION GIVEN Veena planned to make a jewellery box to gift her friend Reeta on her marriage. She made the jewellery box of wood in the shape of a cuboid. The jewellery box has the the dimensions as shown in the figure below. The rate of painting the exterior of the box is Rs. 2 per cm². After making the box she took HELP from his friends to decorate 5he box. The blue was painted by Deepak , black by Suresh, green by Harsh and the yellow was painted by Naresh. TO DETERMINE a. The volume of box b. The area Suresh painted c. The area Deepak painted d. The amount Harsh charged e. The amount Veena paid for painting EVALUATION a. Here the dimension of the box is Length = 40 cm , Breadth = 30 cm , Width = 20 cm Hence the required volume of box = 40 cm × 30 cm × 20 cm $= \sf{24000 \: \: {cm}^{3} }$ b. The black area was painted by Suresh Dimension is Length = 40 cm , Breadth = 30 cm Hence the area Suresh painted = 40 cm × 30 cm $\sf{ = 1200 \: \: {cm}^{2} }$ c. The blue was painted by Deepak Dimension is Length = 30 cm and breadth = 20 cm One side of the area Deepak painted = 30 cm × 20 cm $= \sf{600 \: \: {cm}^{2} }$ Total area Deepak painted $= \sf{2 \times 600 \: \: {cm}^{2} }$ $= \sf{1200\: \: {cm}^{2} }$ d. The green was painted by Harsh Dimension is Length = 40 cm and breadth = 20 cm The area Harsh painted = 40 cm × 20 cm $\sf{ = 800 \: \: {cm}^{2} }$ Hence the amount Harsh charged = Rs 2 × 800 = Rs 1600 e. The amount Veena paid for painting = Rs ( 2400 + 2400 + 1600 + 1600 ) = Rs 8000 ━━━━━━━━━━━━━━━━ Learn more from BRAINLY :- 1. In Parul's garden, there are 25 rows of vegetables. She has five more rows of peppers than tomatoes and two fewer row brainly.in/question/13390089 2. Hari and Prakash go for a swim after a gap of EVERY 2 days and every 3 days RESPECTIVELY. If on 1st January both of them brainly.in/question/32350549

23.

What is volume of boxHow much area did Suresh paintHow much area did Deepak paintWhat amount did Harsh chargeWhat amount did veena pay for painting

Answer»

SOLUTION

GIVEN

Veena planned to make a jewellery box to gift her friend Reeta on her marriage.

She made the jewellery box of wood in the shape of a cuboid.

The jewellery box has the the dimensions as shown in the figure below.

The rate of painting the exterior of the box is Rs. 2 per cm².

After making the box she took HELP from his friends to decorate 5he box.

The blue was painted by Deepak , black by Suresh, green by Harsh and the yellow was painted by Naresh.

TO DETERMINE

a. The volume of box

b. The area Suresh painted

c. The area Deepak painted

d. The amount Harsh charged

e. The amount Veena paid for painting

EVALUATION

a. Here the dimension of the box is Length = 40 cm , Breadth = 30 cm , Width = 20 cm

Hence the required volume of box

= 40 cm × 30 cm × 20 cm

$= \sf{24000 \: \: {cm}^{3} }$

b. The black area was painted by Suresh Dimension is Length = 40 cm , Breadth = 30 cm

Hence the area Suresh painted = 40 cm × 30 cm

$\sf{ = 1200 \: \: {cm}^{2} }$

c. The blue was painted by Deepak

Dimension is Length = 30 cm and breadth = 20 cm

One side of the area Deepak painted

= 30 cm × 20 cm

$= \sf{600 \: \: {cm}^{2} }$

Total area Deepak painted

$= \sf{2 \times 600 \: \: {cm}^{2} }$

$= \sf{1200\: \: {cm}^{2} }$

d. The green was painted by Harsh Dimension is Length = 40 cm and breadth = 20 cm

The area Harsh painted

= 40 cm × 20 cm

$\sf{ = 800 \: \: {cm}^{2} }$

Hence the amount Harsh charged

= Rs 2 × 800

= Rs 1600

e. The amount Veena paid for painting

= Rs ( 2400 + 2400 + 1600 + 1600 )

= Rs 8000

━━━━━━━━━━━━━━━━

Learn more from BRAINLY :-

1. In Parul's garden, there are 25 rows of vegetables. She has five more rows of peppers than tomatoes and two fewer row

brainly.in/question/13390089

2. Hari and Prakash go for a swim after a gap of EVERY 2 days and every 3 days RESPECTIVELY. If on 1st January both of them

brainly.in/question/32350549

Discussion

24.	5*2/4÷ :_=7/8plz find the ans
Answer» ANSWER: PLEASE ASK in CORRECT MANNER

24.

5*2/4÷ :_=7/8plz find the ans

Answer»

ANSWER:

PLEASE ASK in CORRECT MANNER

Discussion

25.	Triangle QPR s right-angled at P, PS is perpendicular to QR. If PQ = 5cm and PR = 12 cm, find the area of Triangle PQR. Also find the length of PS.
Answer» Answer: ieiekswks! Rtftvtbtbygybybtbyjujujik Step-by-step EXPLANATION: tgynynynunhnhnh B b dceuvgrbthj ikik uhbewfv d ergthuujujnn h bt TG b bjmjmt tjmhthjujumngr

25.

Triangle QPR s right-angled at P, PS is perpendicular to QR. If PQ = 5cm and PR = 12 cm, find the area of Triangle PQR. Also find the length of PS.

Answer»

Answer:

ieiekswks!

Rtftvtbtbygybybtbyjujujik

Step-by-step EXPLANATION:

tgynynynunhnhnh B b dceuvgrbthj ikik uhbewfv d ergthuujujnn h bt TG b bjmjmt tjmhthjujumngr

Discussion

26.	The area of rectangular feild is 250 sq.m. if the breadth of the feild is 10 m ,.find it's length
Answer» here is your QUESTIONS SOLUTION.

26.

The area of rectangular feild is 250 sq.m. if the breadth of the feild is 10 m ,.find it's length

Answer»

here is your QUESTIONS SOLUTION.

Discussion

27.	We read 7:15 as - 35×46=
Answer» Step-by-step EXPLANATION: PLEASE only ONE BRAINLIST answer hope it HELPS you

27.

We read 7:15 as - 35×46=

Answer»

Step-by-step EXPLANATION:

PLEASE only ONE BRAINLIST answer

hope it HELPS you

Discussion

28.	Which of the following is divisible by 2,5,10,3 and 9
Answer» ANSWER: 1 I THINK this answer 1,1,1,1,1

28.

Which of the following is divisible by 2,5,10,3 and 9

Answer»

ANSWER:

1

I THINK this answer

1,1,1,1,1

Discussion

29.	What in the equation is 2x-3x=10.
Answer» => 2x - 3x = 10 => -X = 10 => x = - 10 I hope this will HELP you dear.. Always STAY safe and stay healthy..

29.

What in the equation is 2x-3x=10.

Answer»

=> 2x - 3x = 10

=> -X = 10

=> x = - 10

I hope this will HELP you dear..

Always STAY safe and stay healthy..

Discussion

30.	In the given figure, find the value of x: * 1 point Captionless Image (a) 80° (b) 50° (c) 100° (d) 60°
Answer» ANSWER: where is the FIGURE? PUT the figure ,than only it will be POSSIBLE to FIND the answer.

30.

In the given figure, find the value of x: * 1 point Captionless Image (a) 80° (b) 50° (c) 100° (d) 60°

Answer»

ANSWER:

where is the FIGURE?

PUT the figure ,than only it will be POSSIBLE to FIND the answer.

Discussion

31.	The soccer game started at 10:20 am and ended at 2:30 pm how long was the soccer game
Answer» Answer: 4hr 10 minutes Step-by-step explanation: 2:30=14:30(24 HR FORMAT) 14:30 - 10:20 =4:10

31.

The soccer game started at 10:20 am and ended at 2:30 pm how long was the soccer game

Answer»

Answer:

4hr 10 minutes

Step-by-step explanation:

2:30=14:30(24 HR FORMAT)

14:30

- 10:20

=4:10

Discussion

32.	C) Make two 4-dight numbers using each of the digits 1, 2, 4, and 5 such that thenumbers made are divisible by 132.
Answer» Answer: Let four DIGIT number — — — — We know that number is divisible by 4 if it's last two digit are divisible by 4. So it's unit digit can be 2 or 4 because if unit digit is any of odd number than it is not divisible by 4. We have two cases:- 1)if reputation of digit allowed:- Then if unit digit is 2 then we can fill tenth digit with 1 ,3,5 MEANS we have 3 options so total number=5531=75 If unit digit is 4 then we can fill tenth digit with 2 and 4 so we have two option so Total number=5521=50 Both case have or so we add both Answer=75+50=125 2) )if reputation of digit not allowed:- Then if unit digit is 2 then we can fill tenth digit with 1 ,3,5 means we have 3 options , hundred digit with 3 options and THOUSAND digit with 2options so total number=2331=18 If unit digit is 4 then we can fill tenth digit with only Two so one options ,hundred digit with remaining 3 options and thousand digit with two option so Total number=2311=6 Both case have or so we add both Answer=18+6=24 34.4K viewsView 25 Upvoters Step-by-step explanation:

32.

C) Make two 4-dight numbers using each of the digits 1, 2, 4, and 5 such that thenumbers made are divisible by 132.

Answer»

Answer:

Let four DIGIT number — — — —

We know that number is divisible by 4 if it's last two digit are divisible by 4.

So it's unit digit can be 2 or 4 because if unit digit is any of odd number than it is not divisible by 4.

We have two cases:-

1)if reputation of digit allowed:-

Then if unit digit is 2 then we can fill tenth digit with 1 ,3,5 MEANS we have 3 options so

total number=5*5*3*1=75

If unit digit is 4 then we can fill tenth digit with

2 and 4 so we have two option so

Total number=5*5*2*1=50

Both case have or so we add both

Answer=75+50=125

2) )if reputation of digit not allowed:-

Then if unit digit is 2 then we can fill tenth digit with 1 ,3,5 means we have 3 options , hundred digit with 3 options and THOUSAND digit with 2options so

total number=2*3*3*1=18

If unit digit is 4 then we can fill tenth digit with only Two so one options ,hundred digit with remaining 3 options and thousand digit with two option so

Total number=2*3*1*1=6

Both case have or so we add both

Answer=18+6=24

34.4K viewsView 25 Upvoters

Step-by-step explanation:

Discussion

33.	the total cost of flooring a room at rs 8.50 per sq metere is rs 510. if the length of the room is 8 meter , find its breadth
Answer» Step-by-step EXPLANATION: area=510/8.5 =60m^2 so, 60=8*B b=60/8 =7.5

33.

the total cost of flooring a room at rs 8.50 per sq metere is rs 510. if the length of the room is 8 meter , find its breadth

Answer»

Step-by-step EXPLANATION:

area=510/8.5

=60m^2

so, 60=8*B

b=60/8

=7.5

Discussion

34.	Prime numbers that are factors of 15
Answer» Answer: 5 & 3 are the PRIME FACTORS of 15

34.

Prime numbers that are factors of 15

Answer»

Answer:

5 & 3 are the PRIME FACTORS of 15

Discussion

35.	Two adjecent sides of a parallalogram are 5cm and 3cm long the perimeter of \|\|gm is
Answer» ANSWER: o THINK we have to DRAW a DIAGRAM

35.

Two adjecent sides of a parallalogram are 5cm and 3cm long the perimeter of ||gm is

Answer»

ANSWER:

o THINK we have to DRAW a DIAGRAM

Discussion

36.	Determine the solution(s) to the equation x2=12 .
Answer» ANSWER: + √12, - ± √12 Step-by-step EXPLANATION: x^2 = 12 x = ± √12 = ± 2√3 x = + √12, - ± √12 Therefore, the solutions to the equation x^2 = 12 are + √12, - √12.

36.

Determine the solution(s) to the equation x2=12 .

Answer»

ANSWER:

+ √12, - ± √12

Step-by-step EXPLANATION:

x^2 = 12

x = ± √12

= ± 2√3

x = + √12, - ± √12

Therefore,

the solutions to the equation x^2 = 12 are + √12, - √12.

Discussion

37.	Solve equations by Gauss's elimination method2x1 + 4x2 + x3 = 33x1 + 2x2 -2x3 = -2x1 - x2 + x3 = 6
Answer» ANSWER: nunyh5ujj65555ttyy Step-by-step EXPLANATION: ffffffrrhgbybthth5jtjrhthtgtcrvtnrhrhthtbthtget5h5jyh5u5h5j5k5j5j

37.

Solve equations by Gauss's elimination method2x1 + 4x2 + x3 = 33x1 + 2x2 -2x3 = -2x1 - x2 + x3 = 6

Answer»

ANSWER:

nunyh5ujj65555ttyy

Step-by-step EXPLANATION:

ffffffrrhgbybthth5jtjrhthtgtcrvtnrhrhthtbthtget5h5jyh5u5h5j5k5j5j

Discussion

38.	Write five improper fractions having 15 their denominator
Answer» Answer: 3/15,4/15,5/15,7/15,9/15

38.

Write five improper fractions having 15 their denominator

Answer»

Answer:

3/15,4/15,5/15,7/15,9/15

Discussion

39.	संख्या 12 एवं 18 की प्रथम दिन 7 गुना लिखें
Answer» Answer: 112 18 7jhgfffghjbbczdfg

39.

संख्या 12 एवं 18 की प्रथम दिन 7 गुना लिखें

Answer»

Answer:

112 18 7jhgfffghjbbczdfg

Discussion

40.	13. If r: y = 3 : 4 and y: z = 5:7, find:(i) x:y: 2 (ii) x :z
Answer» Answer: Why is DISTILLED WATER USED in the BATTERIES and not the TAP water?

40.

13. If r: y = 3 : 4 and y: z = 5:7, find:(i) x:y: 2 (ii) x :z

Answer»

Answer:

Why is DISTILLED WATER USED in the BATTERIES and not the TAP water?

Discussion

41.	सकसभाप्रश्न 19.का गुणन व्युत्क्रम है-2a.1c.0d. परिभाषित नहीं।b.-1परिमेय संख्या है-1A
Answer» 2 का व्युत्क्रम है 1 होगा

41.

सकसभाप्रश्न 19.का गुणन व्युत्क्रम है-2a.1c.0d. परिभाषित नहीं।b.-1परिमेय संख्या है-1A

Answer»

2 का व्युत्क्रम है 1 होगा

Discussion

42.	Question:- who is Arjit Singh
Answer» Answer: Arijit Singh (born 25 April 1987) is an Indian Bengali playback singer. He sings PREDOMINANTLY in Hindi and Bengali but has also performed in various other Indian languages. He is the RECIPIENT of a National Award and a record six Filmfare AWARDS.

42.

Question:- who is Arjit Singh

Answer»

Answer:

Arijit Singh (born 25 April 1987) is an Indian Bengali playback singer. He sings PREDOMINANTLY in Hindi and Bengali but has also performed in various other Indian languages. He is the RECIPIENT of a National Award and a record six Filmfare AWARDS.

Discussion

43.	DA110°4. In the given triangle ABC, AB = AC.Find all the three angles of the triangle.B13'AC
Answer» Answer: 1.=55⁰ 2.=70⁰ 3.=55⁰ Step-by-step explanation: Since, AB=AC angle 3 = angle 1 let angle 1 be x ,then angle 1+angle 3 = 110. (SUM of two interior angle of a TRIANGLE= exterior angle) X+X=110 2x=110 , X= 110/2 =55 therefore , angle 1 and angle 3 is 55⁰. angle 1+angle 3+angle 2=180⁰ (angle sum property) 55+55+angle 2=180 angle 2=180-110 =70 therefore angle 2 is 70⁰.

43.

DA110°4. In the given triangle ABC, AB = AC.Find all the three angles of the triangle.B13'AC

Answer»

Answer:

1.=55⁰

2.=70⁰

3.=55⁰

Step-by-step explanation:

Since, AB=AC

angle 3 = angle 1

let angle 1 be x ,then

angle 1+angle 3 = 110. (SUM of two interior angle of a TRIANGLE= exterior angle)

X+X=110

2x=110 , X= 110/2 =55

therefore , angle 1 and angle 3 is 55⁰.

angle 1+angle 3+angle 2=180⁰ (angle sum property)

55+55+angle 2=180

angle 2=180-110 =70

therefore angle 2 is 70⁰.

Discussion

44.	Please give me answer in 2000×200+1000×100
Answer» Answer: 2200+1100 3300.... Step-by-step EXPLANATION: MARK as a BRAINLLENT

44.

Please give me answer in 2000×200+1000×100

Answer»

Answer:

2200+1100

3300....

Step-by-step EXPLANATION:

MARK as a BRAINLLENT

Discussion

45.	Solve 132 by 144 plz help me
Answer» Answer: 132/144=0.916

45.

Solve 132 by 144 plz help me

Answer»

Answer:

132/144=0.916

Discussion

46.	What is the answer of 131 ÷44
Answer»

Discussion

47.	12. If x: y = 2: 3 and y: z= 5: 6 then find x :z
Answer» ANSWER: THE ANSWER IS 4:6 Step-by-step EXPLANATION:

47.

12. If x: y = 2: 3 and y: z= 5: 6 then find x :z

Answer»

ANSWER:

THE ANSWER IS 4:6

Step-by-step EXPLANATION:

Discussion

48.	Rashi goes to grocery shop for purchasing some glass for gifting in a party. She observed the jars are arranged one above the other in specific pattern. Observe the figure and on the bases of the figuregive answers of the following questions.(i) If the arrangement of jars in numbers form the Arithmetic Progression, then total number of jars in first three rows from the top are _____(a) 18(b) 24(c) 57(d) 35(ii) If there are hundred such rows . then how many jars will be in the 56throw(a) 200(b) 168(c) 300(d) 303(iii) If on the top, the shopkeeper puts two more rows having jars 2 and 1 respectively, will it be an arithmetic sequence?(a) Yes, the common difference between each row is the same.(b) No, the common difference between each row is not the same(c) Yes, because the common difference between each row is not same(d) No, because the common difference between each row is the same(iv) Rashi asked the shopkeeper to pack it in the same fashion as it was displayed shopkeeper used a box of dimensions as shown. Front face of the box is an equilateral triangle, the capacity of the box used ________(a) 480 X√3 cubic cm(b) 240 X√3 cubic cm(c) 2880 X√3 cubic cm(d) 1440 X√3 cubic cm(v) Rashi asked the shopkeeper to wrap it with gift paper, the total surface area of the paper used ______(a) √3 X 12 X 24 + 30 X 24 Sq.cm(b) 3.14X 12 X 24 + 30 X 24 Sq.cm(c) 1.41 X 12 X 24 + 30 X 24 Sq.cm(d) √3 X 24 X 24 + 30 X 24 Sq.cmPlease give an explanation to your answer!
Answer» Step-by-step EXPLANATION: FIGURE kaha HAIN ?? btw happy valentines DAY DIDI

48.

Rashi goes to grocery shop for purchasing some glass for gifting in a party. She observed the jars are arranged one above the other in specific pattern. Observe the figure and on the bases of the figuregive answers of the following questions.(i) If the arrangement of jars in numbers form the Arithmetic Progression, then total number of jars in first three rows from the top are _(a) 18(b) 24(c) 57(d) 35(ii) If there are hundred such rows . then how many jars will be in the 56throw(a) 200(b) 168(c) 300(d) 303(iii) If on the top, the shopkeeper puts two more rows having jars 2 and 1 respectively, will it be an arithmetic sequence?(a) Yes, the common difference between each row is the same.(b) No, the common difference between each row is not the same(c) Yes, because the common difference between each row is not same(d) No, because the common difference between each row is the same(iv) Rashi asked the shopkeeper to pack it in the same fashion as it was displayed shopkeeper used a box of dimensions as shown. Front face of the box is an equilateral triangle, the capacity of the box used (a) 480 X√3 cubic cm(b) 240 X√3 cubic cm(c) 2880 X√3 cubic cm(d) 1440 X√3 cubic cm(v) Rashi asked the shopkeeper to wrap it with gift paper, the total surface area of the paper used __(a) √3 X 12 X 24 + 30 X 24 Sq.cm(b) 3.14X 12 X 24 + 30 X 24 Sq.cm(c) 1.41 X 12 X 24 + 30 X 24 Sq.cm(d) √3 X 24 X 24 + 30 X 24 Sq.cmPlease give an explanation to your answer!

Answer»

Step-by-step EXPLANATION:

FIGURE kaha HAIN ?? btw happy valentines DAY DIDI

Discussion

49.	Prove that the isosceles triangle whose range is the largest of the isosceles triangles that can be inscribed within a given circle
Answer» Step-by-step explanation: Explanation: Let their be an ISOSCELES triangle ABC inscribed in a circle as SHOWN, in which equal sides A C and B C subtend an angle x at the center. It is apparent that side A B subtends an angle 360 0 − x at the center (as shown). NOTE that for equilateral triangles all these angles will be 2 π 3 . As the area of the triangle portion subtended by an angle x is R 2 2 sin x , the complete area of triangle ABC is A = R 2 2 ( sin x + sin x + sin ( 360 − 2 x ) = R 2 2 ( 2 sin x − sin 2 x ) = R 2 ( sin x − sin x cos x ) = R 2 sin x ( 1 − cos x ) For maximization we should have d A d x = 0 i.e. R 2 ( cos x ( 1 − cos x ) + sin x × sin x ) = 0 or cos x − cos 2 x + 1 − cos 2 x = 0 or 2 cos 2 x − cos x − 1 = 0 or 2 cos 2 x − 2 cos x + cos x − 1 = 0 or 2 cos x ( cos x − 1 ) + 1 ( cos x − 1 ) = 0 or ( 2 cos x + 1 ) ( cos x − 1 ) = 0 HENCE cos x = − 1 2 or cos x = 1 i.e. x = 2 π 3 or x = 0 But for a triangle x ≠ 0 hence x = 2 π 3 and hence for maximum area triangle must be equilateral.

49.

Prove that the isosceles triangle whose range is the largest of the isosceles triangles that can be inscribed within a given circle

Answer»

Step-by-step explanation:

Explanation:

Let their be an ISOSCELES triangle ABC inscribed in a circle as SHOWN, in which equal sides

A

C

and

B

C

subtend an angle

x

at the center. It is apparent that side

A

B

subtends an angle

360

0

−

x

at the center (as shown). NOTE that for equilateral triangles all these angles will be

2

π

3

.

As the area of the triangle portion subtended by an angle

x

is

R

2

sin

x

,

the complete area of triangle ABC is

A

=

R

2

(

sin

x

+

sin

x

+

sin

(

360

−

2

x

)

=

R

2

(

2

sin

x

−

sin

2

x

)

=

R

2

(

sin

x

−

sin

x

cos

x

)

=

R

2

sin

x

(

1

−

cos

x

)

For maximization we should have

d

A

d

x

=

0

i.e.

R

2

(

cos

x

(

1

−

cos

x

)

+

sin

x

×

sin

x

)

=

0

or

cos

x

−

cos

2

x

+

1

−

cos

2

x

=

0

or

2

cos

2

x

−

cos

x

−

1

=

0

or

2

cos

2

x

−

2

cos

x

+

cos

x

−

1

=

0

or

2

cos

x

(

cos

x

−

1

)

+

1

(

cos

x

−

1

)

=

0

or

(

2

cos

x

+

1

)

(

cos

x

−

1

)

=

0

HENCE

cos

x

=

−

1

2

or

cos

x

=

1

i.e.

x

=

2

π

3

or

x

=

0

But for a triangle

x

≠

0

hence

x

=

2

π

3

and hence for maximum area triangle must be equilateral.

Discussion

50.	Find the area off the sector of circle with radius 4 cm and the angle 30° the find the area of corresponding major sector?ans. We have,Let the radius of circle r=4cm.Angle θ=30 oArea of sector of circle= 360 oθ ×πr 2= 360 o30 o ×π×4×4= 12π ×16= 34π = 34 ×3.14=4.186cm 2Area of major sector = Area of circle-area of minor sector=πr 2 −4.186=3.14×4×4−4.186=3.14×16−4.186=50.24cm. 2
Answer» ANSWER: hiiiiiiiiiiiiiiiiiiiii HIIIII

50.

Find the area off the sector of circle with radius 4 cm and the angle 30° the find the area of corresponding major sector?ans. We have,Let the radius of circle r=4cm.Angle θ=30 oArea of sector of circle= 360 oθ ×πr 2= 360 o30 o ×π×4×4= 12π ×16= 34π = 34 ×3.14=4.186cm 2Area of major sector = Area of circle-area of minor sector=πr 2 −4.186=3.14×4×4−4.186=3.14×16−4.186=50.24cm. 2

Answer»

ANSWER:

hiiiiiiiiiiiiiiiiiiiii HIIIII

Discussion

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ffffffrrhgbybthth5jtjrhthtgtcrvtnrhrhthtbthtget5h5jyh5u5h5j5k5j5j

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