332354 + Interview Questions in Secondary School in Math

1.	If f:R→R, g :R→R are defined by f(x) = 3x-1, g(x) =x²+1 then find 1. gof(2a-3) 2. fog(2)
Answer» ANSWER: Answer F(x)=3x−4 ⇒f −1 (x)= 3 x+4 ; g(x)=2+3x ⇒g −1 (x)= 3 x−2 f −1 (5)= 3 5+4 =3 (g −1 of −1 )(5)=g −1 [f −1 (5)]=g −1 (3) = 3 3−2 = 3 1

1.

If f:R→R, g :R→R are defined by f(x) = 3x-1, g(x) =x²+1 then find 1. gof(2a-3) 2. fog(2)

Answer»

ANSWER:

Answer

F(x)=3x−4

⇒f

−1

(x)=

3

x+4

;

g(x)=2+3x

⇒g

−1

(x)=

3

x−2

f

−1

(5)=

3

5+4

=3

(g

−1

of

−1

)(5)=g

−1

[f

−1

(5)]=g

−1

(3)

=

3

3−2

=

3

1

Discussion

2.	दर्शाई गई,3D आकृति का नाम बताइएplease answer fast
Answer» 3D आकृति का नाम... घन cube HAI YE...

2.

दर्शाई गई,3D आकृति का नाम बताइएplease answer fast

Answer»

3D आकृति का नाम...

घन

cube HAI YE...

Discussion

3.	Exercise 11.21. Which of the following statements is correct?a) A rectangle is also a parallelogram.b) A rhombus is also a parallelogram.c) A trapezium is also a parallelogram.d) A rhombus is also a kite.
Answer» ANSWER: a) A RECTANGLE is ALSO a parallelogram. this is your answer

3.

Exercise 11.21. Which of the following statements is correct?a) A rectangle is also a parallelogram.b) A rhombus is also a parallelogram.c) A trapezium is also a parallelogram.d) A rhombus is also a kite.

Answer»

ANSWER:

a) A RECTANGLE is ALSO a parallelogram.

this is your answer

Discussion

4.	The figure shows the ascent of a hot air balloon. Howwould you describe the translation?
Answer» ANSWER: PLEASE MARK me as BRAINLEIST please

4.

The figure shows the ascent of a hot air balloon. Howwould you describe the translation?

Answer»

ANSWER:

PLEASE MARK me as BRAINLEIST please

Discussion

5.	Express wach pf the ratios in the lowest term (1) 3.5:14
Answer» Answer: 1:4 Step-by-step explanation: 3.5 : 14 = 35: 140 = 1:4 LOWEST term of the ratio = 1 : 4

5.

Express wach pf the ratios in the lowest term (1) 3.5:14

Answer»

Answer:

1:4

Step-by-step explanation:

3.5 : 14

= 35: 140

= 1:4

LOWEST term of the ratio = 1 : 4

Discussion

6.	4. Number of 5 digits' odd number that can be formed fromThe Integers 0, 1, 2, 3, 4 are:
Answer» 5,6,7,8,9 that's SOL Step-by-step explanation: 5,6,7,8,9 that's Sol

6.

4. Number of 5 digits' odd number that can be formed fromThe Integers 0, 1, 2, 3, 4 are:

Answer»

5,6,7,8,9

that's SOL

Step-by-step explanation:

5,6,7,8,9

that's Sol

Discussion

7.	If x= √3+1/√3-1, y=√3-1/√3+1, find x^2+xy-y^2
Answer» Step-by-step EXPLANATION: just TAKE a LOOK if you have any DOUBT then TELL

7.

If x= √3+1/√3-1, y=√3-1/√3+1, find x^2+xy-y^2

Answer»

Step-by-step EXPLANATION:

just TAKE a LOOK if you have any DOUBT then TELL

Discussion

8.	7. Veena deposited * 7200 in a finance company which pays 15% interest per year. Find1amount she is expected to get after 4 - years.2
Answer» Answer: DEKHO SIKHO aur MAZE LO

8.

7. Veena deposited * 7200 in a finance company which pays 15% interest per year. Find1amount she is expected to get after 4 - years.2

Answer»

Answer:

DEKHO SIKHO aur MAZE LO

Discussion

9.	6. Draw a angle ABC in which angle B = 65°, AB = 2 cm and BC = 6 cm. Measure AC.
Answer» ANSWER: PYTHAGORAS THEOREM USE HOGI

9.

6. Draw a angle ABC in which angle B = 65°, AB = 2 cm and BC = 6 cm. Measure AC.

Answer»

ANSWER:

PYTHAGORAS THEOREM USE HOGI

Discussion

10.	4,6,8,15,16,24,32,33,64,?
Answer» 4,6,8,15,16,24,32,33,64,

Discussion

11.	(x–2)²=x²–4x+4 pls help me
Answer» Answer: what's the PROBLEM in this Step-by-step explanation: it is an IDENTITY in MATHS READ books of class 9

11.

(x–2)²=x²–4x+4 pls help me

Answer»

Answer:

what's the PROBLEM in this

Step-by-step explanation:

it is an IDENTITY in MATHS

READ books of class 9

Discussion

12.	Solve this correctly . 2√2-√2
Answer» Your ANSWER in above ATTACHMENT

Discussion

13.	सप्टेंबर महिनाभर दररोज 1250 मिली दूध घेतले. दुधाचा भाव ₹ 15 लीटर असल्यास किती रूपये द्यावे लागतील?
Answer» ANSWER: I don't no I will TELL TOMORROW

13.

सप्टेंबर महिनाभर दररोज 1250 मिली दूध घेतले. दुधाचा भाव ₹ 15 लीटर असल्यास किती रूपये द्यावे लागतील?

Answer»

ANSWER:

I don't no I will TELL TOMORROW

Discussion

14.	What is the farthest distance between two points on a cylinder of height 8 and radius 8??
Answer» Answer: The GREATEST distance will be the distance of diagonally opposite points. So, we can have a right angled triangle such that HEIGHT is 8 and RADIUS is 8

14.

What is the farthest distance between two points on a cylinder of height 8 and radius 8??

Answer»

Answer:

The GREATEST distance will be the distance of diagonally opposite points. So, we can have a right angled triangle such that HEIGHT is 8 and RADIUS is 8

Discussion

15.	Find the smallest number by which 8640 must be divided so that the Quotient is a perfect cube
Answer» Answer: 5 Hence, 5 is the smallest NUMBER which MUST divide 8640 so that the quotient is a PERFECT cube. Step-by-step EXPLANATION: HOPE it's helpful for u.. plz add me as a brainlist ....✨✨

15.

Find the smallest number by which 8640 must be divided so that the Quotient is a perfect cube

Answer»

Answer:

5

Hence, 5 is the smallest NUMBER which MUST divide 8640 so that the quotient is a PERFECT cube.

Step-by-step EXPLANATION:

HOPE it's helpful for u..

plz add me as a brainlist ....✨✨

Discussion

16.	249649376865939156456161
Answer» ANSWER: FOUR POINTS =POINT A , point B , point C and point D

16.

249649376865939156456161

Answer»

ANSWER:

FOUR POINTS =POINT A , point B , point C and point D

Discussion

17.	Simplify and explainto be brainiest
Answer» Answer: 1/4 POWER 7 × 3/5 power 17 Step-by-step explanation: 1/4 power 4 × 1/4 power 3 = 1/4 power 7 3/5 power 12 ÷ 3/5 power 5 = 3/5 power 17

17.

Simplify and explainto be brainiest

Answer»

Answer:

1/4 POWER 7 × 3/5 power 17

Step-by-step explanation:

1/4 power 4 × 1/4 power 3 = 1/4 power 7

3/5 power 12 ÷ 3/5 power 5 = 3/5 power 17

Discussion

18.	Convert 3/5, 7/10, 8/15and 11/30 into likefraction
Answer» Step-by-step EXPLANATION: REFER the ATTACHMENT for Explanation

18.

Convert 3/5, 7/10, 8/15and 11/30 into likefraction

Answer»

Step-by-step EXPLANATION:

REFER the ATTACHMENT for Explanation

Discussion

19.	The solution of the equation 3 x + 7 is equal to 13 is (a)1 (b)2
Answer» Answer: 2 Step-by-step explanation: 3x +7=13 3x= 13-7 3x= 6 x= 6/3 x= 2

19.

The solution of the equation 3 x + 7 is equal to 13 is (a)1 (b)2

Answer»

Answer:

2

Step-by-step explanation:

3x +7=13

3x= 13-7

3x= 6

x= 6/3

x= 2

Discussion

20.	4오
Answer» ANSWER: t55555444444445556tt Step-by-step EXPLANATION: huhvggctr555555545555444444444444455555666666665

20.

4오

Answer»

ANSWER:

t55555444444445556tt

Step-by-step EXPLANATION:

huhvggctr555555545555444444444444455555666666665

Discussion

21.	Can someone give some tips to study maths class 10?
Answer» Answer: Hope it will help u Step-by-step explanation: 1) Solve all the Exercise Problems of NCERT Book: Whatever is TAUGHT in the class, try solving QUESTIONS related to that topic from the NCERT Class 10 Maths Book. For more PRACTICE, you can also refer to the other books such as RD Sharma but firstly solve the exercise questions of the NCERT textbook.

21.

Can someone give some tips to study maths class 10?

Answer»

Answer:

Hope it will help u

Step-by-step explanation:

1) Solve all the Exercise Problems of NCERT Book: Whatever is TAUGHT in the class, try solving QUESTIONS related to that topic from the NCERT Class 10 Maths Book. For more PRACTICE, you can also refer to the other books such as RD Sharma but firstly solve the exercise questions of the NCERT textbook.

Discussion

22.	Solve the following equation(a).. 16 = z + 8 (b). x /7 = 5 (c). 7=y -3(d). 14=2y (e). z/3 =9 (f). x-9 = 0 (g). 1 =x /7
Answer» ANSWER: a) z=8 B) x=35 c) y=10 d) y=7 e) z=27 f) x=9 g) x=7

22.

Solve the following equation(a).. 16 = z + 8 (b). x /7 = 5 (c). 7=y -3(d). 14=2y (e). z/3 =9 (f). x-9 = 0 (g). 1 =x /7

Answer»

ANSWER:

a) z=8

B) x=35

c) y=10

d) y=7

e) z=27

f) x=9

g) x=7

Discussion

23.	divide 32 in four parts such that they are in ap and the ratio of product of extreme to the product of means is 7:15 find the number
Answer» ANSWER: Take an online test Take Now Login Studyrankersonline Ask a Question Divide 32 into 4 parts which are in A.P. such that the product of extremes is to the product of MEANS is 7:15. 0 votes 15.7k views asked Nov 7, 2017 in Class X Maths by aditya23 (-2,145 points) Divide 32 into 4 parts which are in A.P. such that the product of extremes is to the product of means is 7:15. Please log in or register to answer this question. 1 Answer 0 votes answered Nov 7, 2017 by akansha Expert (2.2k points) LET four numbers in A.P. be a – 3d, a – d, a + d and a + 3d. (a – 3d) + (a – d) + (a + d) + (a + 3d) = 32 ⇒ 4a = 32 ⇒ a = 8 Product of extremes = (a – 3d) (a + d) + (8 – 3d) (8 + 3d) = 64 – 9d2 Product of means = (a – d) (a + d) = (8 – d) (8 + d) = 64 – d2 Product of extremes: product of means = 7:15 (Given) When a = 8 and d = 2 a – 3d = 8 – 3 × 2 = 8 – 6 = 2 a – d = 8 – 2 = 6 a + d = 8 + 2 = 10 a + 3d = 8 + 3 × 2 = 8 + 6 = 14 When a = 8, d = –2 a – 3d = 8 – 3 × (–2) = 8 + 6 = 14 a – d = 8 – (–2) = 8 + 2 = 10 a + d = 8 – 2 = 6 a + 3d = 8 + 3 × (–2) = 8 – 6 = 2 ∴ The four numbers are 2, 6, 10 and 14

23.

divide 32 in four parts such that they are in ap and the ratio of product of extreme to the product of means is 7:15 find the number

Answer»

ANSWER:

Take an online test Take Now

Login

Studyrankersonline

Ask a Question

Divide 32 into 4 parts which are in A.P. such that the product of extremes is to the product of MEANS is 7:15.

0

votes

15.7k views

asked Nov 7, 2017 in Class X Maths by aditya23 (-2,145 points)

Divide 32 into 4 parts which are in A.P. such that the product of extremes is to the product of means is 7:15.

Please log in or register to answer this question.

1 Answer

0

votes

answered Nov 7, 2017 by akansha Expert (2.2k points)

LET four numbers in A.P. be a – 3d, a – d, a + d and a + 3d.

(a – 3d) + (a – d) + (a + d) + (a + 3d) = 32

⇒ 4a = 32

⇒ a = 8

Product of extremes = (a – 3d) (a + d) + (8 – 3d) (8 + 3d) = 64 – 9d2

Product of means = (a – d) (a + d) = (8 – d) (8 + d) = 64 – d2

Product of extremes: product of means = 7:15 (Given)

When a = 8 and d = 2

a – 3d = 8 – 3 × 2 = 8 – 6 = 2

a – d = 8 – 2 = 6

a + d = 8 + 2 = 10

a + 3d = 8 + 3 × 2 = 8 + 6 = 14

When a = 8, d = –2

a – 3d = 8 – 3 × (–2) = 8 + 6 = 14

a – d = 8 – (–2) = 8 + 2 = 10

a + d = 8 – 2 = 6

a + 3d = 8 + 3 × (–2) = 8 – 6 = 2

∴ The four numbers are 2, 6, 10 and 14

Discussion

24.	Of ancheckwhether (5,-2) , (6,4) and (7,-2) and the saticesbuongle
Answer» ANSWER: no Step-by-step EXPLANATION: because I don't KNOW about this QUESTION

24.

Of ancheckwhether (5,-2) , (6,4) and (7,-2) and the saticesbuongle

Answer»

ANSWER:

no

Step-by-step EXPLANATION:

because I don't KNOW about this QUESTION

Discussion

25.	Find the domain and range of the real valued function f(x)=x/2-3x
Answer» Step-by-step explanation: domain= R-{2/3} RANGE by PUTTING F(x) =y x/(2-3x)=y x=2y-3xy x+3xy=2y x(1+3y)=2y x= 2y/(1+3y) so range= R-{-1/3}

25.

Find the domain and range of the real valued function f(x)=x/2-3x

Answer»

Step-by-step explanation:

domain= R-{2/3}

RANGE by PUTTING F(x) =y

x/(2-3x)=y

x=2y-3xy

x+3xy=2y

x(1+3y)=2y

x= 2y/(1+3y)

so range= R-{-1/3}

Discussion

26.	3. 859 divided 234Cathematics
Answer» ANSWER: 3.6709401709 Step-by-step EXPLANATION: It is the answer for UR QUESTION

26.

3. 859 divided 234Cathematics

Answer»

ANSWER:

3.6709401709

Step-by-step EXPLANATION:

It is the answer for UR QUESTION

Discussion

27.	Give the geometrical proof of the identity (x-y)^3
Answer» ANSWER: have GRATE to more than!

27.

Give the geometrical proof of the identity (x-y)^3

Answer»

ANSWER:

have GRATE to more than!

Discussion

28.	QDivide x²-1 by x+i
Answer» ANSWER: answer is X-1 Step-by-step EXPLANATION: (x)^2 - (1)^2 therefore (x+1 ) (x-1)/ x+1 therefore x-1 is answer

28.

QDivide x²-1 by x+i

Answer»

ANSWER:

answer is X-1

Step-by-step EXPLANATION:

(x)^2 - (1)^2

therefore (x+1 ) (x-1)/ x+1

therefore x-1 is answer

Discussion

29.	(4x+1)²+(2x+3)²/4x²+12x+9=61/36
Answer» Step-by-step EXPLANATION: (16X)+(4x+9) (16x)+(9X) (12X)SQURE 16x+12x+9 37x squre

29.

(4x+1)²+(2x+3)²/4x²+12x+9=61/36

Answer»

Step-by-step EXPLANATION:

(16X)+(4x+9)

(16x)+(9X)

(12X)SQURE

16x+12x+9

37x squre

Discussion

30.	Find the product (x³)(2x⁴)(-3x⁵)
Answer» Answer: FIND the product of: (i) 6xy and -3x²y³ Solution: (6xy) × (-3x²y³) = {6 × (-3)} × {xy × x²y³} = -18x1+2 y1+3 = -18x³y⁴. (ii) 7ab², -4a²b and -5abc Solution: (7ab²) × (-4a²b) × (-5abc) = {7 × (-4) × (-5)} × {ab² × a²b × abc} = 140 a1+2+1 b2+1+1 c = 140a⁴b⁴c. see this and do it yourself to use this method okk

30.

Find the product (x³)(2x⁴)(-3x⁵)

Answer»

Answer:

FIND the product of: (i) 6xy and -3x²y³

Solution:

(6xy) × (-3x²y³)

= {6 × (-3)} × {xy × x²y³}

= -18x1+2 y1+3

= -18x³y⁴.

(ii) 7ab², -4a²b and -5abc

Solution:

(7ab²) × (-4a²b) × (-5abc)

= {7 × (-4) × (-5)} × {ab² × a²b × abc}

= 140 a1+2+1 b2+1+1 c

= 140a⁴b⁴c.

see this and do it yourself to use this method okk

Discussion

31.	(x^2+1)(y^2+1) + 9 = 6 (x+y) find x^2+y^2
Answer» Answer: 6(x+y) – 9 Step-by-step EXPLANATION: (x^2+1)(y^2+1)+ 9 = 6 (x+y) or, (x²+1)(y²+1) = 6(x+y) – 9

31.

(x^2+1)(y^2+1) + 9 = 6 (x+y) find x^2+y^2

Answer»

Answer:

6(x+y) – 9

Step-by-step EXPLANATION:

(x^2+1)(y^2+1)+ 9 = 6 (x+y)

or, (x²+1)(y²+1) = 6(x+y) – 9

Discussion

32.	Solve -2(x+4)+x+5=3-5(2-x) Maths
Answer» Step-by-step EXPLANATION: $\bf -2(x+4)+x+5=3-5(2-x)$ $\bf -2x-8+x+5=3-10+5x$ $\bf -x-3=-7+5x$ $\bf -x-5x=-7+3$ $\bf -6x=-4$ $\bf\boxed{\boxed{\frac{2}{3}}}$

32.

Solve -2(x+4)+x+5=3-5(2-x) Maths

Answer»

Step-by-step EXPLANATION:

$\bf -2(x+4)+x+5=3-5(2-x)$

$\bf -2x-8+x+5=3-10+5x$

$\bf -x-3=-7+5x$

$\bf -x-5x=-7+3$

$\bf -6x=-4$

$\bf\boxed{\boxed{\frac{2}{3}}}$

Discussion

33.	Q.5 Find the median of the following data : 20, 14, 6, 25, 18, 13, 19, 10, 9, 12
Answer» ANSWER: MEDIAN = 34 Step-by-step EXPLANATION: *MARK* as *BRAINLIEST*

33.

Q.5 Find the median of the following data : 20, 14, 6, 25, 18, 13, 19, 10, 9, 12

Answer»

ANSWER:

MEDIAN = 34

Step-by-step EXPLANATION:

MARK as BRAINLIEST

Discussion

34.	What is 3 dimensional figure?Thank you all ❤️
Answer» $ANSWER$ Step-by-step EXPLANATION: In geometry, a three-dimensional shape can be DEFINED as a SOLID figure or an object or shape that has three dimensions – length, width and HEIGHT. Unlike two-dimensional shapes, three-dimensional shapes have THICKNESS or depth. Hope it will be Helpful Congo Amii ❤️ Hope you get more ❤️ Saranghe

34.

What is 3 dimensional figure?Thank you all ❤️

Answer»

$ANSWER$

Step-by-step EXPLANATION:

In geometry, a three-dimensional shape can be DEFINED as a SOLID figure or an object or shape that has three dimensions – length, width and HEIGHT. Unlike two-dimensional shapes, three-dimensional shapes have THICKNESS or depth.

Hope it will be Helpful

Congo Amii ❤️

Hope you get more ❤️

Saranghe

Discussion

35.	Expand 1 by 3 x minus 2 by 3 y whole cube
Answer» ANSWER: the answer is FIFTEEN MINUS

35.

Expand 1 by 3 x minus 2 by 3 y whole cube

Answer»

ANSWER:

the answer is FIFTEEN MINUS

Discussion

36.	Two cubes are such that the length of cube l is twice the length of the side of cube ll. Find the ratio of the volume of cube l to that of cube ll.
Answer» RATIO of CUBE 1 and cube 2 is 8:1

Discussion

37.	9. If 8 bags of apple cost Rs.9600, what is the cost of 62 bags of apples?Cost of 8 bags of ahhle = 59600
Answer» Answer: 8 bags of apple costs rs.9600 Therefore, cost of ONE bag of apple = 9600 ÷ 8 = Rs.1200 => Cost of 62 bags of apple = 1200 × 62 = Rs.74400 Ans.

37.

9. If 8 bags of apple cost Rs.9600, what is the cost of 62 bags of apples?Cost of 8 bags of ahhle = 59600

Answer»

Answer:

8 bags of apple costs rs.9600

Therefore,

cost of ONE bag of apple = 9600 ÷ 8

= Rs.1200

=> Cost of 62 bags of apple = 1200 × 62

= Rs.74400 Ans.

Discussion

38.	Х+ x-1 = 4, x0, x # 1.7. Solve for x :x-1х
Answer» ANSWER: 10 Step-by-step EXPLANATION: x+x-1=4 x+x=4+1 2x= 5 x = 5×2 x= 10

38.

Х+ x-1 = 4, x0, x # 1.7. Solve for x :x-1х

Answer»

ANSWER:

10

Step-by-step EXPLANATION:

x+x-1=4

x+x=4+1

2x= 5

x = 5×2

x= 10

Discussion

39.	Determine the natural of root of the quadratic equation 2x² - 3x = 4
Answer» Answer: PLS SEE ATTACHED FILE HOPE IT HELPS ❤️

39.

Determine the natural of root of the quadratic equation 2x² - 3x = 4

Answer»

Answer:

PLS SEE ATTACHED FILE HOPE IT HELPS ❤️

Discussion

40.	4) Solve the following linear equations by using Cramer's Rule.x+y-2 Z=-10, 2x +y-3 Z=-1, 4x + y + z=2
Answer» Step-by-step EXPLANATION: yegejgdysusgejdjsishgevehuehevsvehysuegevebshudjdvevvshushevvftg ntrfufvcfyh gdrtf

40.

4) Solve the following linear equations by using Cramer's Rule.x+y-2 Z=-10, 2x +y-3 Z=-1, 4x + y + z=2

Answer»

Step-by-step EXPLANATION:

yegejgdysusgejdjsishgevehuehevsvehysuegevebshudjdvevvshushevvftg ntrfufvcfyh gdrtf

Discussion

41.	Find the nth term ofof the A.P: 2,5, 8
Answer» 2+(n−1)3=3n−1 happy PARENTS WORSHIP DAY !

41.

Find the nth term ofof the A.P: 2,5, 8

Answer»

2+(n−1)3=3n−1

happy PARENTS WORSHIP DAY !

Discussion

42.	book in Ashima reads 42 pages of a day. How long will it take her to finish sh the book that has 1428 pages.answer this question with statement
Answer» Answer: She will TAKE 34 days to FINISH the book. Step-by-step explanation: 1428 = 34 42 Just DIVIDE 1428 by 42.

42.

book in Ashima reads 42 pages of a day. How long will it take her to finish sh the book that has 1428 pages.answer this question with statement

Answer»

Answer:

She will TAKE 34 days to FINISH the book.

Step-by-step explanation:

1428 = 34

42 Just DIVIDE 1428 by 42.

Discussion

43.	Solve the simultaneous equations 8x +3y = 11
Answer» ANSWER: (X,y)=(2,-5) Step-by-step EXPLANATION: hope it HELPS you

43.

Solve the simultaneous equations 8x +3y = 11

Answer»

ANSWER:

(X,y)=(2,-5)

Step-by-step EXPLANATION:

hope it HELPS you

Discussion

44.	Param suffered a loss of 10%, when he sold his chair. He had bought the chair for Rs. 900. For what price did he sell the chair?
Answer» Answer: yƒod½tñg„t_Œr„rf½Ugt (y) Œëltü fuU Wúth c„tRY \| 1. fwUA vrGgtü fuU ltb c„tRY \| s : fUtug˜, fUtiyt, fUcq„h, „tu„t, „e„h, vvent, btuh, cxuh, nkm ytr” \| 2. I I mkde„ bltuhksl fUt YfU mtOl ni \| I I Rm fuU CTHU yvlu rJath c„tRY \| s : mkde„ bltuhksl fUt ŒCtJNt˜e mtOl ni \| Rmmu nbthe NtherhfU ytih btlrmfU ƒfUtl ”qh ntu st„e ni \| Rmmu YfUtd½raút c·Z„e ni \| RmfUtu meFlt YfU yåAe yt”„ ni \| (yt) vtX vr·ZY \| yÇgtm-fUtgo fUersY \| * Jt¢gtü fUtu mne f½Ub ”ersY \| :_ 3, 4, 2, 1, 5 * rfUmlu rfUmmu fUnt_ 1. „WB ˜tudtü lu fUCe bwSu dtlu Jt˜e rar·zgt fuU rJMg bü lné c„tgt \|( htst lu muJfUtü mu fUnt ) 2. nbthu htst „wöntht bOwh mkde„ mwllt atn„u nî \| (˜·zfUe lu rar·zgt mu fUnt ) 3. bwSu yvlt mkde„ bunl„ fUhlu Jt˜tü fUtu Ce mwltlt ni \| ( vGe lu htst mu fUnt ) * ylwåAu” v·ZfUh Œëltü fuU Wúth ”ersY \| 1. Cth„ mhfUth lu Jàg seJtü fuU mkhGK fuU r˜Y fUtilmt yrOrlgb cltgt ni ? s : Cth„ mhfUth lu Jàg seJtü fuU mkhGK fuU r˜Y mlT 1972 bü I Jàg ŒtKe mwhGt yrOrlgb 1972 I cltgt \| 2. gntâ vh rfU„lu htíx±eg W”Tgtltü fUe mkÏgt c„tge dge ni ? s : gntâ vh 69 htíx±eg W”Tgtltü fUe mkÏgt c„tge dge nî \| 3. ctDtü fUe mwhGt fuU r˜Y fUtilme gtuslt fUtgo fUh hne ni ? s : ctDtü fUe mwhGt fuU r˜Y I Œtusu¢x xtRdh I sime gtuslt fUtgo fUh hne ni \|yƒod½tñg„t_Œr„rf½Ugt (y) 1. Cth„egtü fuU cthu bü fUrJ lu ¢gt fUnt ni ? (vtX fUt mthtkN) s : rsm ”UN bü vrJºt dkdt cn„e ni, Jimu vrJºt †”gJt˜u Cth„Jtme ni \| rslfuU ntüXtü vh matRo ntu„e ni, bunbtltü fUtu ŒtKtü mu ßgt”t mbS„u nî, ƒtu·zu mu FwNe seJl rc„tlu Jt˜u nî, ôJtƒeo ntufUh seJl rc„tluJt˜u lné nî ytih rJëJ fUtu YfU„t mu hnlu fUt mk”uN ”uluJt˜u nî \| 2. Cth„ bü cnlu Jt˜e fwUA lr”gtü fuU cthu bü c„tRY \| s : dkdt, gbwlt, mhôJ„e, c½ñbvwºtt, dtu”tJhe, fÐUíKt ytr” \| (yt) vtX vr·ZY \| yÇgtm fUtgo fUersY \| * fUrJ„t fuU ytOth vh Wra„ f½Ub ”ersY \| s : 2, 1, 4, 3. yrCÔgr¢„ _ mÐsltÀbfU„t (y) Rl Œëltü fuU Wúth ”tu-„el Jt¢gtü bü ”ersY \| 1. de„ bü fUrJ lu rb˜-sw˜ fUh hnlu fuU r˜Y ¢gtü fUnt ntudt ? s : rb˜sw˜fUh hnlu mu ylufU ˜tC ni \| Rmmu ”uN fUe YfU„t c·Z„e ni \| Rmmu CtRoatht c·Z„t ni \| 2. NB yvlu bunbtl fuU mtƒ fUimt ÔgJnth fUhlt atrnY ? s : nb yvlu bunbtltü fUtu ŒtK mu Ce ßgt”t mbSlt atrnY \| 3. I nh stl fUe ·fUeb„ stl„u nî \| I RmfUt CtJ yvlu Nç”tü bü r˜rFY \| s : nh Cth„Jtme mCe fUtu yvlt CtRo mbSfUh rb˜sw˜fUh hn„u nî \| Rmr˜Y Ju I I nh stl fUe fUeb„ stl„u nî \| I I 4. Rm de„ bü ytvfUtu fUtilme ct„ü cý„ yåAe ˜dé ? ¢gtü ? s : Rm de„ bü bwSu vn˜t v” yåAt ˜dt ¢gtü rfU nh Cth„Jtme ma NE ctu˜„t ni ytih WmfUt r”˜ NwÆ” ytih dkdt l”e fuU mbtl vrJºtJtl ni \|

44.

Param suffered a loss of 10%, when he sold his chair. He had bought the chair for Rs. 900. For what price did he sell the chair?

Answer»

Answer:

yƒod½tñg„t_Œr„rf½Ugt

(y) Œëltü fuU Wúth c„tRY |

1. fwUA vrGgtü fuU ltb c„tRY |

s : fUtug˜, fUtiyt, fUcq„h, „tu„t, „e„h, vvent, btuh, cxuh, nkm ytr” |

2. I I mkde„ bltuhksl fUt YfU mtOl ni | I I Rm fuU CTHU yvlu rJath c„tRY |

s : mkde„ bltuhksl fUt ŒCtJNt˜e mtOl ni | Rmmu nbthe NtherhfU ytih btlrmfU ƒfUtl ”qh ntu st„e ni | Rmmu

YfUtd½raút c·Z„e ni | RmfUtu meFlt YfU yåAe yt”„ ni |

(yt) vtX vr·ZY | yÇgtm-fUtgo fUersY |

* Jt¢gtü fUtu mne f½Ub ”ersY | :_ 3, 4, 2, 1, 5

* rfUmlu rfUmmu fUnt_

1. „WB ˜tudtü lu fUCe bwSu dtlu Jt˜e rar·zgt fuU rJMg bü lné c„tgt |( htst lu muJfUtü mu fUnt )

2. nbthu htst „wöntht bOwh mkde„ mwllt atn„u nî | (˜·zfUe lu rar·zgt mu fUnt )

3. bwSu yvlt mkde„ bunl„ fUhlu Jt˜tü fUtu Ce mwltlt ni | ( vGe lu htst mu fUnt )

* ylwåAu” v·ZfUh Œëltü fuU Wúth ”ersY |

1. Cth„ mhfUth lu Jàg seJtü fuU mkhGK fuU r˜Y fUtilmt yrOrlgb cltgt ni ?

s : Cth„ mhfUth lu Jàg seJtü fuU mkhGK fuU r˜Y mlT 1972 bü I Jàg ŒtKe mwhGt yrOrlgb 1972 I cltgt |

2. gntâ vh rfU„lu htíx±eg W”Tgtltü fUe mkÏgt c„tge dge ni ?

s : gntâ vh 69 htíx±eg W”Tgtltü fUe mkÏgt c„tge dge nî |

3. ctDtü fUe mwhGt fuU r˜Y fUtilme gtuslt fUtgo fUh hne ni ?

s : ctDtü fUe mwhGt fuU r˜Y I Œtusu¢x xtRdh I sime gtuslt fUtgo fUh hne ni |yƒod½tñg„t_Œr„rf½Ugt

(y) 1. Cth„egtü fuU cthu bü fUrJ lu ¢gt fUnt ni ? (vtX fUt mthtkN)

s : rsm ”UN bü vrJºt dkdt cn„e ni, Jimu vrJºt †”gJt˜u Cth„Jtme ni | rslfuU ntüXtü vh matRo ntu„e ni, bunbtltü fUtu

ŒtKtü mu ßgt”t mbS„u nî, ƒtu·zu mu FwNe seJl rc„tlu Jt˜u nî, ôJtƒeo ntufUh seJl rc„tluJt˜u lné nî ytih rJëJ fUtu

YfU„t mu hnlu fUt mk”uN ”uluJt˜u nî |

2. Cth„ bü cnlu Jt˜e fwUA lr”gtü fuU cthu bü c„tRY |

s : dkdt, gbwlt, mhôJ„e, c½ñbvwºtt, dtu”tJhe, fÐUíKt ytr” |

(yt) vtX vr·ZY | yÇgtm fUtgo fUersY |

* fUrJ„t fuU ytOth vh Wra„ f½Ub ”ersY | s : 2, 1, 4, 3.

yrCÔgr¢„ _ mÐsltÀbfU„t

(y) Rl Œëltü fuU Wúth ”tu-„el Jt¢gtü bü ”ersY |

1. de„ bü fUrJ lu rb˜-sw˜ fUh hnlu fuU r˜Y ¢gtü fUnt ntudt ?

s : rb˜sw˜fUh hnlu mu ylufU ˜tC ni | Rmmu ”uN fUe YfU„t c·Z„e ni | Rmmu CtRoatht c·Z„t ni |

2. NB yvlu bunbtl fuU mtƒ fUimt ÔgJnth fUhlt atrnY ?

s : nb yvlu bunbtltü fUtu ŒtK mu Ce ßgt”t mbSlt atrnY |

3. I nh stl fUe ·fUeb„ stl„u nî | I RmfUt CtJ yvlu Nç”tü bü r˜rFY |

s : nh Cth„Jtme mCe fUtu yvlt CtRo mbSfUh rb˜sw˜fUh hn„u nî | Rmr˜Y Ju I I nh stl fUe fUeb„ stl„u nî | I I

4. Rm de„ bü ytvfUtu fUtilme ct„ü cý„ yåAe ˜dé ? ¢gtü ?

s : Rm de„ bü bwSu vn˜t v” yåAt ˜dt ¢gtü rfU nh Cth„Jtme ma NE ctu˜„t ni ytih WmfUt r”˜ NwÆ” ytih dkdt l”e

fuU mbtl vrJºtJtl ni |

Discussion

45.	Express 8,62,00,000 in scientific notation.
Answer» ANSWER: Yessssssssssssssssssssssssss

45.

Express 8,62,00,000 in scientific notation.

Answer»

ANSWER:

Yessssssssssssssssssssssssss

Discussion

46.	) A picture is to be painted on a canvas of length 40 cm and width 80 cm. A margin of 5 cm has to be left on all sides of the canvas. Find the area of the actual picture and the area of the margin in sq m
Answer» $\sf\underbrace{Answer:-}$ Area of actual picture = 0.21 m². Area of MARGIN= 0.11 m². ⠀ $\color{pink}{\textbf{\textsf{Explaination:-}}}$ Given, Width and length of the CANVAS is 40 cm and 80 cm respectively. Length of the margin 5 cm. (along the canvas). $\sf\Large{\underline{\underline{To \: Find:-}}}$ Area of Actual picture, and area of the margin in sq. m. $\sf\Large{\underline{\underline{Formula \:to\: be \: used:-}}}$ $\\underline{\boxed{\sf{{area}_{(Rectangle)}=(l \times b)\:units}}}$ l = length b = breadth ⠀ $\sf\Large{\underline{\underline{Solution:-}}}$ We are said that a picture is painted on a canvas whose length = 40 cm, and breadth = 80 cm. And there is a margin of 5 cm from all sides along the canvas. ⠀ We've to find the area of actual picture (excluding Margin) and the area occupied by margin in SQUARE m. So, let's find the area of whole canvas first by inserting the given values in the Formula of Area of Rectangle. $\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(rectangle)}\;=\;\bf{{l \times b}\:}}\end{gathered}$ $\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(rectangle)}\;=\;\bf{{40 \times 80}\:}}\end{gathered}$ $\: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(rectangle)}\;=\;\bf{{3200} {cm}^{2} \:}}\end{gathered}$ Thus, the area of canvas (ABCD) is 3200 cm². ⠀ Finding PQRS. According to question, the canvas has a margin of 5 cm along it's side. So, subtract 5 cm from all four sides of ABCD, to get the dimensions of PQRS. Find area in sq. m. (Refer to the attachment for better understanding). RS = length = 40cm - (5cm + 5cm) = 30cm QS = Breadth = 80cm - (5cm + 5cm) = 70 cm Put the obtained values in the Formula, $\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(PQRS)}\;=\;\bf{{30 \times 70}\:}}\end{gathered}$ $\: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(PQRS)}\;=\;\bf{{2100 {cm}^{2} }\:}}\end{gathered}$ ⠀ Converting the area in sq. m. $\begin{gathered}\\\;\sf{\;\;we \: know \: that \: 1 {cm}^{2} \;=\;\bf{ \frac{1}{10000} {m}^{2} \:}}\end{gathered}$ $\begin{gathered}\\\;\sf{\;\;so \: 2100 {cm}^{2}\;=\;\bf\bigg({ \frac{1}{10000} \times 2100\bigg){m}^{2} \:}}\end{gathered}[\tex][tex]\begin{gathered}\:{\sf{\dfrac{{1}}{\cancel{10000}} \times 21{\cancel{00}}}}\end{gathered}[\tex][tex]\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(in \: sq \: m)}\;=\;\bf{{0.21 {m}^{2} }\:}}\end{gathered}[\tex][tex]{\underline{\underline{\sf{\green{ Area \: of \: PQRS \: (Actual \: picture) \: is \: 0.21m². }}}}}$ ⠀ Now, To Find the area of margin, subract PQRS from ABCD. $\: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(margin)}\;=\;\bf{{3200} {cm}^{2} - 2100 {cm}^{2} \:}}\end{gathered}$ $\: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(margin)}\;=\;\bf{1100 {cm}^{2} \:}}\end{gathered}$ ⠀ by *converting* it in *sq.* m, we *get* $\begin{gathered}\\\;\sf{\;\;so \: 1100 {cm}^{2}\;=\;\bf\bigg({\frac{1}{10000} \times 1100\bigg){m}^{2} \:}}\end{gathered}[\tex][tex]\begin{gathered}\:{\sf{\dfrac{{1}}{\cancel{10000}} \times 11{\cancel{00}}}}\end{gathered}[\tex][tex]\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(in \: sq \: m)}\;=\;\bf{{0.11 {m}^{2} }\:}}\end{gathered}[\tex][tex]{\underline{\underline{\sf{\green{ Area \: of \: ABCD \: (margin) \: is \: 0.11m². }}}}}$

46.

) A picture is to be painted on a canvas of length 40 cm and width 80 cm. A margin of 5 cm has to be left on all sides of the canvas. Find the area of the actual picture and the area of the margin in sq m

Answer»

$\sf\underbrace{Answer:-}$

Area of actual picture = 0.21 m².
Area of MARGIN= 0.11 m².

⠀

$\color{pink}{\textbf{\textsf{Explaination:-}}}$

Given,

Width and length of the CANVAS is 40 cm and 80 cm respectively.
Length of the margin 5 cm. (along the canvas).

$\sf\Large{\underline{\underline{To \: Find:-}}}$

Area of Actual picture, and area of the margin in sq. m.

$\sf\Large{\underline{\underline{Formula \:to\: be \: used:-}}}$

$\\underline{\boxed{\sf{{area}_{(Rectangle)}=(l \times b)\:units}}}$

l = length
b = breadth

⠀

$\sf\Large{\underline{\underline{Solution:-}}}$

We are said that a picture is painted on a canvas whose length = 40 cm, and breadth = 80 cm. And there is a margin of 5 cm from all sides along the canvas.

⠀

We've to find the area of actual picture (excluding Margin) and the area occupied by margin in SQUARE m.

So, let's find the area of whole canvas first by inserting the given values in the Formula of Area of Rectangle.

$\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(rectangle)}\;=\;\bf{{l \times b}\:}}\end{gathered}$

$\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(rectangle)}\;=\;\bf{{40 \times 80}\:}}\end{gathered}$

$\: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(rectangle)}\;=\;\bf{{3200} {cm}^{2} \:}}\end{gathered}$

Thus, the area of canvas (ABCD) is 3200 cm².

⠀

Finding PQRS.

According to question, the canvas has a margin of 5 cm along it's side. So, subtract 5 cm from all four sides of ABCD, to get the dimensions of PQRS. Find area in sq. m. (Refer to the attachment for better understanding).

RS = length = 40cm - (5cm + 5cm) = 30cm

QS = Breadth = 80cm - (5cm + 5cm) = 70 cm

Put the obtained values in the Formula,

$\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(PQRS)}\;=\;\bf{{30 \times 70}\:}}\end{gathered}$

$\: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(PQRS)}\;=\;\bf{{2100 {cm}^{2} }\:}}\end{gathered}$

⠀

Converting the area in sq. m.

$\begin{gathered}\\\;\sf{\;\;we \: know \: that \: 1 {cm}^{2} \;=\;\bf{ \frac{1}{10000} {m}^{2} \:}}\end{gathered}$

$\begin{gathered}\\\;\sf{\;\;so \: 2100 {cm}^{2}\;=\;\bf\bigg({ \frac{1}{10000} \times 2100\bigg){m}^{2} \:}}\end{gathered}[\tex][tex]\begin{gathered}\:{\sf{\dfrac{{1}}{\cancel{10000}} \times 21{\cancel{00}}}}\end{gathered}[\tex][tex]\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(in \: sq \: m)}\;=\;\bf{{0.21 {m}^{2} }\:}}\end{gathered}[\tex][tex]{\underline{\underline{\sf{\green{ Area \: of \: PQRS \: (Actual \: picture) \: is \: 0.21m². }}}}}$

⠀

Now, To Find the area of margin, subract PQRS from ABCD.

$\: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(margin)}\;=\;\bf{{3200} {cm}^{2} - 2100 {cm}^{2} \:}}\end{gathered}$

$\: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(margin)}\;=\;\bf{1100 {cm}^{2} \:}}\end{gathered}$

⠀

by converting it in sq. m, we get

$\begin{gathered}\\\;\sf{\;\;so \: 1100 {cm}^{2}\;=\;\bf\bigg({\frac{1}{10000} \times 1100\bigg){m}^{2} \:}}\end{gathered}[\tex][tex]\begin{gathered}\:{\sf{\dfrac{{1}}{\cancel{10000}} \times 11{\cancel{00}}}}\end{gathered}[\tex][tex]\begin{gathered}\\\;\sf{:\rightarrow\;\;area_{(in \: sq \: m)}\;=\;\bf{{0.11 {m}^{2} }\:}}\end{gathered}[\tex][tex]{\underline{\underline{\sf{\green{ Area \: of \: ABCD \: (margin) \: is \: 0.11m². }}}}}$

Discussion

47.	Construct △ABC with BC = 6.5 cm, ∠B = 60° and ∠C = 45°
Answer» Step-by-step explanation: 4urururrufifidrfffccfffg

47.

Construct △ABC with BC = 6.5 cm, ∠B = 60° and ∠C = 45°

Answer»

Step-by-step explanation:

4urururrufifidrfffccfffg

Discussion

48.	Tan theta minus sin theta=0
Answer» the STATEMENT is false. ans:

48.

Tan theta minus sin theta=0

Answer»

the STATEMENT is false.

ans:

Discussion

49.	Q = 20 - 0.1P. whats the MR?
Answer» ANSWER: good evening friends have a great DAY TODAY

49.

Q = 20 - 0.1P. whats the MR?

Answer»

ANSWER:

good evening friends have a great DAY TODAY

Discussion

50.	Written value of 'n' up to 20 places of decimal?
Answer» The first digit after the DECIMAL represents the TENTHS place. The next digit after the decimal represents the hundredths place. The remaining DIGITS CONTINUE to fill in the place values until there are no digits LEFT

50.

Written value of 'n' up to 20 places of decimal?

Answer»

The first digit after the DECIMAL represents the TENTHS place. The next digit after the decimal represents the hundredths place. The remaining DIGITS CONTINUE to fill in the place values until there are no digits LEFT

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

If f:R→R, g :R→R are defined by f(x) = 3x-1, g(x) =x²+1 then find 1. gof(2a-3) 2. fog(2)​

दर्शाई गई,3D आकृति का नाम बताइएplease answer fast​

Exercise 11.21. Which of the following statements is correct?a) A rectangle is also a parallelogram.b) A rhombus is also a parallelogram.c) A trapezium is also a parallelogram.d) A rhombus is also a kite.​

a) A RECTANGLE is ALSO a parallelogram.

this is your answer

The figure shows the ascent of a hot air balloon. Howwould you describe the translation?

Express wach pf the ratios in the lowest term (1) 3.5:14​

4. Number of 5 digits' odd number that can be formed fromThe Integers 0, 1, 2, 3, 4 are:​

If x= √3+1/√3-1, y=√3-1/√3+1, find x^2+xy-y^2​

7. Veena deposited * 7200 in a finance company which pays 15% interest per year. Find1amount she is expected to get after 4 - years.2​

6. Draw a angle ABC in which angle B = 65°, AB = 2 cm and BC = 6 cm. Measure AC.​

4,6,8,15,16,24,32,33,64,?​

(x–2)²=x²–4x+4 pls help me ​

Solve this correctly . 2√2-√2​

सप्टेंबर महिनाभर दररोज 1250 मिली दूध घेतले. दुधाचा भाव ₹ 15 लीटर असल्यास किती रूपये द्यावे लागतील?​

What is the farthest distance between two points on a cylinder of height 8 and radius 8??​

Find the smallest number by which 8640 must be divided so that the Quotient is a perfect cube ​

5

Hence, 5 is the smallest NUMBER which MUST divide 8640 so that the quotient is a PERFECT cube.

HOPE it's helpful for u..

plz add me as a brainlist ....✨✨

249649376865939156456161​

Simplify and explainto be brainiest

Convert 3/5, 7/10, 8/15and 11/30 into likefraction​

The solution of the equation 3 x + 7 is equal to 13 is (a)1 (b)2​

4오​

Can someone give some tips to study maths class 10?​

Solve the following equation(a).. 16 = z + 8 (b). x /7 = 5 (c). 7=y -3(d). 14=2y (e). z/3 =9 (f). x-9 = 0 (g). 1 =x /7​

divide 32 in four parts such that they are in ap and the ratio of product of extreme to the product of means is 7:15 find the number​

Of ancheckwhether (5,-2) , (6,4) and (7,-2) and the saticesbuongle​

Find the domain and range of the real valued function f(x)=x/2-3x​

3. 859 divided 234Cathematics​

Give the geometrical proof of the identity (x-y)^3​

QDivide x²-1 by x+i​

(4x+1)²+(2x+3)²/4x²+12x+9=61/36​

Find the product (x³)(2x⁴)(-3x⁵)​

(x^2+1)(y^2+1) + 9 = 6 (x+y) find x^2+y^2

Solve -2(x+4)+x+5=3-5(2-x) Maths​

Q.5 Find the median of the following data : 20, 14, 6, 25, 18, 13, 19, 10, 9, 12​

MARK as BRAINLIEST

What is 3 dimensional figure?Thank you all ❤️​

Expand 1 by 3 x minus 2 by 3 y whole cube​

Two cubes are such that the length of cube l is twice the length of the side of cube ll. Find the ratio of the volume of cube l to that of cube ll.​

9. If 8 bags of apple cost Rs.9600, what is the cost of 62 bags of apples?Cost of 8 bags of ahhle = 59600​

Х+ x-1 = 4, x0, x # 1.7. Solve for x :x-1х​

ANSWER:

10

Step-by-step EXPLANATION:

x+x-1=4

x+x=4+1

2x= 5

x = 5×2

x= 10

Determine the natural of root of the quadratic equation 2x² - 3x = 4​

4) Solve the following linear equations by using Cramer's Rule.x+y-2 Z=-10, 2x +y-3 Z=-1, 4x + y + z=2​

Find the nth term ofof the A.P: 2,5, 8 ​

book in Ashima reads 42 pages of a day. How long will it take her to finish sh the book that has 1428 pages.answer this question with statement

Answer:

She will TAKE 34 days to FINISH the book.

Step-by-step explanation:

1428 = 34

42

Just DIVIDE 1428 by 42.

Solve the simultaneous equations 8x +3y = 11

Param suffered a loss of 10%, when he sold his chair. He had bought the chair for Rs. 900. For what price did he sell the chair?

Express 8,62,00,000 in scientific notation.

) A picture is to be painted on a canvas of length 40 cm and width 80 cm. A margin of 5 cm has to be left on all sides of the canvas. Find the area of the actual picture and the area of the margin in sq m

Given,

Construct △ABC with BC = 6.5 cm, ∠B = 60° and ∠C = 45°

Tan theta minus sin theta=0

Q = 20 - 0.1P. whats the MR?

Written value of 'n' up to 20 places of decimal?

If f:R→R, g :R→R are defined by f(x) = 3x-1, g(x) =x²+1 then find 1. gof(2a-3) 2. fog(2)

दर्शाई गई,3D आकृति का नाम बताइएplease answer fast

Exercise 11.21. Which of the following statements is correct?a) A rectangle is also a parallelogram.b) A rhombus is also a parallelogram.c) A trapezium is also a parallelogram.d) A rhombus is also a kite.

Express wach pf the ratios in the lowest term (1) 3.5:14

4. Number of 5 digits' odd number that can be formed fromThe Integers 0, 1, 2, 3, 4 are:

If x= √3+1/√3-1, y=√3-1/√3+1, find x^2+xy-y^2

7. Veena deposited * 7200 in a finance company which pays 15% interest per year. Find1amount she is expected to get after 4 - years.2

6. Draw a angle ABC in which angle B = 65°, AB = 2 cm and BC = 6 cm. Measure AC.

4,6,8,15,16,24,32,33,64,?

(x–2)²=x²–4x+4 pls help me

Solve this correctly . 2√2-√2

सप्टेंबर महिनाभर दररोज 1250 मिली दूध घेतले. दुधाचा भाव ₹ 15 लीटर असल्यास किती रूपये द्यावे लागतील?

What is the farthest distance between two points on a cylinder of height 8 and radius 8??

Find the smallest number by which 8640 must be divided so that the Quotient is a perfect cube

249649376865939156456161

Convert 3/5, 7/10, 8/15and 11/30 into likefraction

The solution of the equation 3 x + 7 is equal to 13 is (a)1 (b)2

4오

Can someone give some tips to study maths class 10?

Solve the following equation(a).. 16 = z + 8 (b). x /7 = 5 (c). 7=y -3(d). 14=2y (e). z/3 =9 (f). x-9 = 0 (g). 1 =x /7

divide 32 in four parts such that they are in ap and the ratio of product of extreme to the product of means is 7:15 find the number

Of ancheckwhether (5,-2) , (6,4) and (7,-2) and the saticesbuongle

Find the domain and range of the real valued function f(x)=x/2-3x

3. 859 divided 234Cathematics

Give the geometrical proof of the identity (x-y)^3

QDivide x²-1 by x+i

(4x+1)²+(2x+3)²/4x²+12x+9=61/36

Find the product (x³)(2x⁴)(-3x⁵)

Solve -2(x+4)+x+5=3-5(2-x) Maths

Q.5 Find the median of the following data : 20, 14, 6, 25, 18, 13, 19, 10, 9, 12

What is 3 dimensional figure?Thank you all ❤️

Expand 1 by 3 x minus 2 by 3 y whole cube

Two cubes are such that the length of cube l is twice the length of the side of cube ll. Find the ratio of the volume of cube l to that of cube ll.

9. If 8 bags of apple cost Rs.9600, what is the cost of 62 bags of apples?Cost of 8 bags of ahhle = 59600

Х+ x-1 = 4, x0, x # 1.7. Solve for x :x-1х

Determine the natural of root of the quadratic equation 2x² - 3x = 4

4) Solve the following linear equations by using Cramer's Rule.x+y-2 Z=-10, 2x +y-3 Z=-1, 4x + y + z=2

Find the nth term ofof the A.P: 2,5, 8