332354 + Interview Questions in Secondary School in Math

1.	the dustbin in the shape of a frustum of a cone the diameter of its circular ends are 20 cm and 40 cm if the vertical height of the dustbin is 66 cm find the capacity of the dustbin
Answer» Answer: ANSWER Given r 1 =15cm, r 2 =8cm, h=63cm VOLUME of the dustbin (frustum)= 3 1 πh(r 1 2 +r 2 2 +r 1 r 2 ) = 3 1 × 7 22 ×63(15 2 +8 2 +15×8) = 3 1 × 7 22 ×63(225+64+120) =66×409=26,994 ∴ Volume of the dustbin=26,994cm 3 . wang yiren song yiren both are good GIRL

1.

the dustbin in the shape of a frustum of a cone the diameter of its circular ends are 20 cm and 40 cm if the vertical height of the dustbin is 66 cm find the capacity of the dustbin

Answer»

Answer:

ANSWER

Given r

1

=15cm, r

2

=8cm, h=63cm

VOLUME of the dustbin (frustum)=

3

1

πh(r

1

2

+r

2

+r

1

r

2

)

=

3

1

×

7

22

×63(15

2

+8

2

+15×8)

=

3

1

×

7

22

×63(225+64+120)

=66×409=26,994

∴ Volume of the dustbin=26,994cm

3

.

wang yiren song yiren both are good GIRL

Discussion

2.	Sanyam allows a discount of 20% and still gains 10% in selling an almirah. Find the marked price of an almirah if cost price is Rs. 2,000.Please give answer fast. I will be very much thankful.
Answer» Answer: WAIT 4 MINUTES I will give answer immediately

2.

Sanyam allows a discount of 20% and still gains 10% in selling an almirah. Find the marked price of an almirah if cost price is Rs. 2,000.Please give answer fast. I will be very much thankful.

Answer»

Answer:

WAIT 4 MINUTES I will give answer immediately

Discussion

3.	3x²-2 if x is -3 in quadratic fractions
Answer» <P>Answer: 3x^2-2, X= -3 p(-3)= 3×(-3)^2 -2 = 3×9-2 = 27-2 = 25

3.

3x²-2 if x is -3 in quadratic fractions

Answer»

<P>Answer:

3x^2-2, X= -3

p(-3)= 3×(-3)^2 -2

= 3×9-2

= 27-2

= 25

Discussion

4.	Largest 3 digit number smallest 3 digit number in roman
Answer» Answer: LARGEST : cxc smallest:c hope this HELPS you mark as brainlist

4.

Largest 3 digit number smallest 3 digit number in roman

Answer»

Answer:

LARGEST : cxc

smallest:c

hope this HELPS you

mark as brainlist

Discussion

5.	Examine, wheare rational ora) 16.-2
Answer» Answer: Yes, they are RATIONAL. HOPE this helps! if so MARK as brainliest for such value based ANSWERS!

5.

Examine, wheare rational ora) 16.-2

Answer»

Answer:

Yes, they are RATIONAL.

HOPE this helps!

if so MARK as brainliest for such value based ANSWERS!

Discussion

6.	Prove that the square of any positive odd integer is of form 3m,3m+1 but not of form 3m+2
Answer» ANSWER: REFER the attachment Hope it will help you!! MARK it as brainliest ☺️ Follow me## THANKS ❣️

6.

Prove that the square of any positive odd integer is of form 3m,3m+1 but not of form 3m+2

Answer»

ANSWER:

REFER the attachment

Hope it will help you!!

MARK it as brainliest ☺️

Follow me##

THANKS ❣️

Discussion

7.	5. A baker made 6850 chicken pies to sell at a funfair. He had 2809 of the pies left at theend of the day. How many pies did he sell?
Answer» Answer:4041 Step-by-step EXPLANATION: If he had 6850 PIES you NEED to do 6850-2809

7.

5. A baker made 6850 chicken pies to sell at a funfair. He had 2809 of the pies left at theend of the day. How many pies did he sell?

Answer»

Answer:4041

Step-by-step EXPLANATION:

If he had 6850 PIES you NEED to do 6850-2809

Discussion

8.	Q. Round off to nearest 1000 :- (1) 3567 (2) 32523 (3) 45169
Answer» Answer: 4000 33000 45000 Step-by-step EXPLANATION: .............

8.

Q. Round off to nearest 1000 :- (1) 3567 (2) 32523 (3) 45169

Answer»

Answer:

4000
33000
45000

Step-by-step EXPLANATION:

.............

Discussion

9.	How to find cubic polynomial from sum of zeros ,sum of product of zeros,product of zeros
Answer» $\rule{400}4$ ☆ ANSWER:- • You can find out the cubic polynomial from sum of zeros ,sum of product of zeros,product of zeros by using the relationship between the zeroes and COEFFICIENTS. $\rule{400}2$ ▪︎ For example:- $\sf \mapsto \: if \alpha,\: \beta \: and \: \gamma \\ \tt are \: zeroes \: of \:cubic \: polynomial.$ $\rule{400}2$ ☆ Then, • Sum Of zeroes, $\tt\leadsto \alpha + \beta + \gamma = \frac{ - b}{a}$ • Product Of zeroes, $\tt\leadsto \alpha \beta \gamma = \frac{ - d}{a}$ • Sum of product of zeroes taken two at a time, $\tt\leadsto (\alpha \beta +( \beta \gamma ) + ( \gamma \alpha ) = \frac{c}{a}$ =》 Where, a = Coefficient of x³ -b = -Coefficient of x². c = Coefficient of x. -d = -Constant Term. $\rule{400}2$ ▪︎ So, ▪︎ The Cubic Polynomial we get after SEEING the relationship between the zeroes and coefficients is:- $\tt\mapsto a {x}^{3} + b {x}^{2} + cx + d \\$ ▪︎ Then by obtaining the values of Sum and product of the zeroes we can find the required cubic polynomial as the zeroes were already GIVEN. $\rule{400}4$ ▪︎ LETS Solve an question so that you can understand betterly. Q:- Given that 4,5 and 6 are the zeroes of a cubic polynomial find out the polynomial. $\rule{400}2$ ANSWER:- Here, Sum of zeroes, $\tt= 4+5+6 \\ \\ \tt = <klux>15</klux> = \frac{-b}{a}.$ Product Of zeroes, $\tt 4\times 5\times 6 \\ \\ = \tt20\times 6 \\ \\ \tt = 120 = \frac{-d}{a}$ Product of zeroes taken two at a time, $\tt = (4\times5)+(5\times 6)+(6\times 4)\\ \\ = \tt 20+30+24 \\ \\ \tt = 74 = \frac{c}{a}$ $\rule{400}1$ ▪︎ So by Comp9we get, a = 1. -b = 15 =》 b = -15. c = 74. -d = 120 =》 d = -120. $\rule{400}1$ Therefore the polynomial is:- $\tt\implies ax^3+bx^2+cx+d. \\ \\ = 1(x)^3+(-15)x^2+(74)x+(-120). \\ \\ = x^3-15x^2+74x-120.$ $\rule{400}4$

9.

How to find cubic polynomial from sum of zeros ,sum of product of zeros,product of zeros

Answer»

$\rule{400}4$

☆ ANSWER:-

• You can find out the cubic polynomial from sum of zeros ,sum of product of zeros,product of zeros by using the relationship between the zeroes and COEFFICIENTS.

$\rule{400}2$

▪︎ For example:-

$\sf \mapsto \: if \alpha,\: \beta \: and \: \gamma \\ \tt are \: zeroes \: of \:cubic \: polynomial.$

$\rule{400}2$

☆ Then,

• Sum Of zeroes,

$\tt\leadsto \alpha + \beta + \gamma = \frac{ - b}{a}$

• Product Of zeroes,

$\tt\leadsto \alpha \beta \gamma = \frac{ - d}{a}$

• Sum of product of zeroes taken two at a time,

$\tt\leadsto (\alpha \beta +( \beta \gamma ) + ( \gamma \alpha ) = \frac{c}{a}$

=》 Where,

a = Coefficient of x³
-b = -Coefficient of x².
c = Coefficient of x.
-d = -Constant Term.

$\rule{400}2$

▪︎ So,

▪︎ The Cubic Polynomial we get after SEEING the relationship between the zeroes and coefficients is:-

$\tt\mapsto a {x}^{3} + b {x}^{2} + cx + d \\$

▪︎ Then by obtaining the values of Sum and product of the zeroes we can find the required cubic polynomial as the zeroes were already GIVEN.

$\rule{400}4$

▪︎ LETS Solve an question so that you can understand betterly.

Q:- Given that 4,5 and 6 are the zeroes of a cubic polynomial find out the polynomial.

$\rule{400}2$

ANSWER:-

Here,

Sum of zeroes,

$\tt= 4+5+6 \\ \\ \tt = <klux>15</klux> = \frac{-b}{a}.$

Product Of zeroes,

$\tt 4\times 5\times 6 \\ \\ = \tt20\times 6 \\ \\ \tt = 120 = \frac{-d}{a}$

Product of zeroes taken two at a time,

$\tt = (4\times5)+(5\times 6)+(6\times 4)\\ \\ = \tt 20+30+24 \\ \\ \tt = 74 = \frac{c}{a}$

$\rule{400}1$

▪︎ So by Comp9we get,

a = 1.

-b = 15 =》 b = -15.

c = 74.

-d = 120 =》 d = -120.

$\rule{400}1$

Therefore the polynomial is:-

$\tt\implies ax^3+bx^2+cx+d. \\ \\ = 1(x)^3+(-15)x^2+(74)x+(-120). \\ \\ = x^3-15x^2+74x-120.$

$\rule{400}4$

Discussion

10.	Find seven rational numbers between 1/3 and 1⁄2 .
Answer» ANSWER: So 3/8, 5/12, &11/24 are each between 1/3 and 1/2, and are ALSO 1/24 apart Step-by-step explanation: PLEASE mark me as brainliest

10.

Find seven rational numbers between 1/3 and 1⁄2 .

Answer»

ANSWER:

So 3/8, 5/12, &11/24 are each between 1/3 and 1/2, and are ALSO 1/24 apart

Step-by-step explanation:

PLEASE mark me as brainliest

Discussion

11.	Directions : There are 28000 people living in a town, out of which 6500 drink milk only, 5500 drink tea only, 4500 drink coffee only. 3000 drink tea and milk, 5000 drink tea and coffee and 4000 drink milk and coffee. The ratio of people who drink all three beverage and do not drink any beverage is 2 : 3.निर्देश : एक कस्‍बे में 28000 लोग रहते हैं, जिनमें से 6500 केवल दूध पीते हैं, 5500 केवल चाय पीते हैं, 4500 केवल कॉफी पीते हैं। 3000 चाय व दूध पीते है, 5000 चाय व कॉफी पीते है और 4000 दूध व कॉफी पीते है। तीनों पेय पदार्थ पीने वाले तथा कोई पेय पदार्थ न पीने वाले लोगों का अनुपात 2 : 3 है।Give the number of people who drink all three beverage.तीनों पेय पदार्थ पीने वाले लोगों की संख्‍या बताओ।
Answer» Given : There are 28000 people living in a town, out of which 6500 drink milk only, 5500 drink TEA only, 4500 drink coffee only. 3000 drink tea and milk, 5000 drink tea and coffee and 4000 drink milk and coffee. The ratio of people who drink all three beverage and do not drink any beverage is 2 : 3. To find : the number of people who drink all three beverage. Solution: Total People T = 28000 only Milk = 6500 only Tea = 5500 only coffee = 4500 drink all three beverage = 3A Do not Drink any = 2A tea and milk = 3000 => tea & milk only = 3000 - 3A tea and coffee = 5000 => tea and coffee only = 5000 - 3A milk and coffee. = 4000 => milk and coffee only = 4000 - 3A Total = Milk only + tea only + Coffee only + tea & milk only + tea and coffee only + milk and coffee only + drink all three beverage + Do not Drink any => 28000 = 6500 + 5500 + 4500 + 3000 - 3A + 5000 - 3A + 4000 - 3A + 3A + 2A => 28000 = 28500 - 4A => 4A = 500 => A = 125 => 3A = 375 number of people who drink all three beverage. = 375 तीनों पेय पदार्थ पीने वाले लोगों की संख्‍या = 375 Learn More: 50 students of a class like either oranges or grapes or both. 20 of ... brainly.in/question/13834831 Which two-way table contains the same INFORMATION as the Venn ... brainly.in/question/9475441 125, 100 and 145 students appeared at post graduate examination ... brainly.in/question/13477941

11.

Directions : There are 28000 people living in a town, out of which 6500 drink milk only, 5500 drink tea only, 4500 drink coffee only. 3000 drink tea and milk, 5000 drink tea and coffee and 4000 drink milk and coffee. The ratio of people who drink all three beverage and do not drink any beverage is 2 : 3.निर्देश : एक कस्‍बे में 28000 लोग रहते हैं, जिनमें से 6500 केवल दूध पीते हैं, 5500 केवल चाय पीते हैं, 4500 केवल कॉफी पीते हैं। 3000 चाय व दूध पीते है, 5000 चाय व कॉफी पीते है और 4000 दूध व कॉफी पीते है। तीनों पेय पदार्थ पीने वाले तथा कोई पेय पदार्थ न पीने वाले लोगों का अनुपात 2 : 3 है।Give the number of people who drink all three beverage.तीनों पेय पदार्थ पीने वाले लोगों की संख्‍या बताओ।

Answer»

Given : There are 28000 people living in a town, out of which 6500 drink milk only, 5500 drink TEA only, 4500 drink coffee only. 3000 drink tea and milk, 5000 drink tea and coffee and 4000 drink milk and coffee.

The ratio of people who drink all three beverage and do not drink any beverage is 2 : 3.

To find : the number of people who drink all three beverage.

Solution:

Total People T = 28000

only Milk = 6500

only Tea = 5500

only coffee = 4500

drink all three beverage = 3A

Do not Drink any = 2A

tea and milk = 3000 => tea & milk only = 3000 - 3A

tea and coffee = 5000 => tea and coffee only = 5000 - 3A

milk and coffee. = 4000 => milk and coffee only = 4000 - 3A

Total = Milk only + tea only + Coffee only + tea & milk only + tea and coffee only + milk and coffee only + drink all three beverage + Do not Drink any

=> 28000 = 6500 + 5500 + 4500 + 3000 - 3A + 5000 - 3A + 4000 - 3A + 3A + 2A

=> 28000 = 28500 - 4A

=> 4A = 500

=> A = 125

=> 3A = 375

number of people who drink all three beverage. = 375

तीनों पेय पदार्थ पीने वाले लोगों की संख्‍या = 375

Learn More:

50 students of a class like either oranges or grapes or both. 20 of ...

brainly.in/question/13834831

Which two-way table contains the same INFORMATION as the Venn ...

brainly.in/question/9475441

125, 100 and 145 students appeared at post graduate examination ...

brainly.in/question/13477941

Discussion

12.	The dimensions of a metal block are 2.25mby 27cm. It is melted and recast into cubeseach of side 45cm. How many cubes are formed?
Answer» HOPE IT'S HELPFUL MARK AS BRAIN LIST PLZZZ

12.

The dimensions of a metal block are 2.25mby 27cm. It is melted and recast into cubeseach of side 45cm. How many cubes are formed?

Answer»

HOPE IT'S HELPFUL

MARK AS BRAIN LIST PLZZZ

Discussion

13.	Solve 4(3x-2)=52give answer and working out please thank you
Answer» $\huge\underline\mathfrak\pink{ Hello~Mate }$ $\text{[math]}$ =>12x-8=52 =>12x=52+8 =>12x=60 =>x=60/12 =>x=5 $☠️loknath☠️ ☠️loknath☠️ ♥️follow me♥️ ☠️loknath☠️ ♥️follow me♥️$

13.

Solve 4(3x-2)=52give answer and working out please thank you

Answer»

$\huge\underline\mathfrak\pink{ Hello~Mate }$

$\text{[math]}$

=>12x-8=52

=>12x=52+8

=>12x=60

=>x=60/12

=>x=5

$☠️loknath☠️ ☠️loknath☠️ ♥️follow me♥️ ☠️loknath☠️ ♥️follow me♥️$

Discussion

14.	Q.which one of the following lies above the x axis:(i)(-3,-5)(ii)(5,0)(iii)(-5,2)(iv)(3,0)
Answer» Answer: 5,0 is the CORRECT answer Step-by-step explanation: MAKE me BRAIN LIST please please

14.

Q.which one of the following lies above the x axis:(i)(-3,-5)(ii)(5,0)(iii)(-5,2)(iv)(3,0)

Answer»

Answer:

5,0 is the CORRECT answer

Step-by-step explanation:

MAKE me BRAIN LIST please please

Discussion

15.	Using properties determinants , prone thata ² + 2azatlat2(a-1)3
Answer» ANSWER: it is DIFFERENT VARIABLE

15.

Using properties determinants , prone thata ² + 2azatlat2(a-1)3

Answer»

ANSWER:

it is DIFFERENT VARIABLE

Discussion

16.	Solve for θ, cos²θ / (cot²θ – cos² θ) = 3
Answer» GIVEN: cos²θ / (cot²θ – cos² θ) = 3 To find: The value of the θ. Solution: Let's take the LHS of the given EQUATION; cos²θ / (cot²θ – cos² θ) cos²θ / (cos²θ/sin²θ – cos² θ) cos²θ /cos²θ (1/sin²θ – 1) 1 /1 (1/sin²θ – 1) 1 /((1-sin²θ)/sin²θ sin²θ/((1-sin²θ) As we know that 1-sin²θ=cos²θ sin²θ/((1-sin²θ) = sin²θ/cos²θ = tan²θ according to the QUESTION: tan²θ = 3 tanθ = √3 Value of tan is √3 only when θ is 60° So, tanθ = tan60° So the value of θ is 60°

16.

Solve for θ, cos²θ / (cot²θ – cos² θ) = 3

Answer»

GIVEN:

cos²θ / (cot²θ – cos² θ) = 3

To find:

The value of the θ.

Solution:

Let's take the LHS of the given EQUATION;

cos²θ / (cot²θ – cos² θ)
cos²θ / (cos²θ/sin²θ – cos² θ)
cos²θ /cos²θ (1/sin²θ – 1)
1 /1 (1/sin²θ – 1)
1 /((1-sin²θ)/sin²θ
sin²θ/((1-sin²θ)

As we know that 1-sin²θ=cos²θ

sin²θ/((1-sin²θ) = sin²θ/cos²θ = tan²θ

according to the QUESTION:

tan²θ = 3
tanθ = √3

Value of tan is √3 only when θ is 60°

So,

tanθ = tan60°

So the value of θ is 60°

Discussion

17.	The set of all multiples of 6 less than 30
Answer» Answer: 6,12,18,24,30 Step-by-step EXPLANATION: PLS MARK me BRAINLIEST

17.

The set of all multiples of 6 less than 30

Answer»

Answer:

6,12,18,24,30

Step-by-step EXPLANATION:

PLS MARK me BRAINLIEST

Discussion

18.	Divide P(X) by G(X) P(X)=X^3-3X^2+5X-3G(X)= X^2-2
Answer» ANSWER: QUOTIENT =x+3,REMAINDER= 7x-9

18.

Divide P(X) by G(X) P(X)=X^3-3X^2+5X-3G(X)= X^2-2

Answer»

ANSWER:

QUOTIENT =x+3,REMAINDER= 7x-9

Discussion

19.	3. Find the square root of 150.0625
Answer» ANSWER: Step-by-step EXPLANATION: √150.0625 =12.25. HOPE THIS HELPS.

19.

3. Find the square root of 150.0625

Answer»

ANSWER:

Step-by-step EXPLANATION:

√150.0625 =12.25.

HOPE THIS HELPS.

Discussion

20.	Tantheeta /1-cottheeta +cottheeta /1-tantheeta =1+sectheta*cosectheeta prove
Answer» Here's The ANSWER My FRIEND....

Discussion

21.	.11.Numbers are required in the place ofthe following question.59151629?4989147(A) 45(C) 51(B) 48(D) 54
Answer» Answer: et KG RT NAGAR near the video formats available Step-by-step EXPLANATION: E kg e you have a GREAT time

21.

.11.Numbers are required in the place ofthe following question.59151629?4989147(A) 45(C) 51(B) 48(D) 54

Answer»

Answer:

et KG RT NAGAR near the video formats available

Step-by-step EXPLANATION:

E kg e you have a GREAT time

Discussion

22.	Factorise 6x +x² =-5
Answer» Step-by-step explanation: Factors are y = ( x − 1 ) ( x − 5 ) Explanation: If you have a quadratic function a x 2 + B x + c , to factorise it you should identify TWO NUMBERS whose product is a c and sum is b . Here in y = x 2 − 6 x + 5 , we should identify two numbers whose product is 5 and sum is − 6 . Such numbers are − 5 and − 1 and now splitting MIDDLE term into these we get y = x 2 − 5 x − x + 5 or y = x ( x − 5 ) − 1 ( x − 5 ) = ( x − 1 ) ( x − 5 ) . Answer link

22.

Factorise 6x +x² =-5

Answer»

Step-by-step explanation:

Factors are

y

=

(

x

−

1

)

(

x

−

5

)

Explanation:

If you have a quadratic function

a

x

2

+

B

x

+

c

, to factorise it you should identify TWO NUMBERS whose product is

a

c

and sum is

b

.

Here in

y

=

x

2

−

6

x

+

5

, we should identify two numbers whose product is

5

and sum is

−

6

.

Such numbers are

−

5

and

−

1

and now splitting MIDDLE term into these we get

y

=

x

2

−

5

x

−

x

+

5

or

y

=

x

(

x

−

5

)

−

1

(

x

−

5

)

=

(

x

−

1

)

(

x

−

5

)

.

Answer link

Discussion

23.	Solve 4(3x-2)=52and give working out please thanks
Answer» $✌5✌$ 4(3x-2)=52 =12x-8=52 =12x=52+8 =12x=60 =x=60/12 =x=5

23.

Solve 4(3x-2)=52and give working out please thanks

Answer»

$✌5✌$

4(3x-2)=52

=12x-8=52

=12x=52+8

=12x=60

=x=60/12

=x=5

Discussion

24.	999,7999, 26999,63999,? Find the missing term
Answer» Step-by-step explanation: The series is 103 – 1, 203 – 1, 303 – 1, etc. The NEXT NUMBER is 503 – 1 = 124999.

24.

999,7999, 26999,63999,? Find the missing term

Answer»

Step-by-step explanation:

The series is 103 – 1, 203 – 1, 303 – 1, etc.

The NEXT NUMBER is 503 – 1 = 124999.

Discussion

25.	base of a triangle is 9 and height is 5. Base of another traingle is 10 ande height is 6. find the ratio of areas of these triangles
Answer» Answer: 3:4 Step-by-step EXPLANATION: Area 1 = 1/2 * base 1 * HEIGHT 1 = 1/2 * 9 * 5 = 45/2 unit^2 Area 2 = 1/2 * base 2 * height 2 = 1/2 * 10 * 6 =30 unit^2 Ratio = Area 1 : Area 2or Area 1 /Area 2 = 45/2 1/30 = 3/4 = 3:4*

25.

base of a triangle is 9 and height is 5. Base of another traingle is 10 ande height is 6. find the ratio of areas of these triangles

Answer»

Answer:

3:4

Step-by-step EXPLANATION:

Area 1 = 1/2 * base 1 * HEIGHT 1

= 1/2 * 9 * 5

= 45/2 unit^2

Area 2 = 1/2 * base 2 * height 2

= 1/2 * 10 * 6

=30 unit^2

Ratio = Area 1 : Area 2or Area 1 /Area 2

= 45/2 *1/30

= 3/4

= 3:4

Discussion

26.	If the zeroes of the polynomial x cube _3x square+x+1 are a-b, a, a+b then find a and b
Answer» Step-by-step EXPLANATION: this is the ANSWER to the QUESTION

26.

If the zeroes of the polynomial x cube _3x square+x+1 are a-b, a, a+b then find a and b

Answer»

Step-by-step EXPLANATION:

this is the ANSWER to the QUESTION

Discussion

27.	If a=3+√7/2 then find value of a^2+1/a^2
Answer» Answer: 14 Step-by-step EXPLANATION:

27.

If a=3+√7/2 then find value of a^2+1/a^2

Answer»

Answer:

14

Step-by-step EXPLANATION:

Discussion

28.	+-12713X-21a laxtie
Answer» Answer: MAYBE your QUESTION is INCOMPLETE or wrong First check your answer

28.

+-12713X-21a laxtie

Answer»

Answer:

MAYBE your QUESTION is INCOMPLETE or wrong

First check your answer

Discussion

29.	Please answer this with explanation
Answer» ANSWER: I DONT no ANITA BABY PLS SRY

29.

Please answer this with explanation

Answer»

ANSWER:

I DONT no ANITA BABY PLS SRY

Discussion

30.	Cost of 3 pencils is equal to the cost of 1 pen and cost of 2 pens, 6 pencils and 1 bool is rs 89 and the cost of 1 pen, 18 pencils and 5 books is rs367.Find the cost of 3 pens, 3pencils and 1 book
Answer» Step-by-step EXPLANATION: HOPE it HELPED you . PLEASE mark it as brainliest

30.

Cost of 3 pencils is equal to the cost of 1 pen and cost of 2 pens, 6 pencils and 1 bool is rs 89 and the cost of 1 pen, 18 pencils and 5 books is rs367.Find the cost of 3 pens, 3pencils and 1 book

Answer»

Step-by-step EXPLANATION:

HOPE it HELPED you .

PLEASE mark it as brainliest

Discussion

31.	Solve graphically 3x+2y=4 ; 2x-3y=7
Answer» ANSWER:X= 1 y =0.5 x=5 y=1 Step-by-step explanation:3x 1 =3 2x0.5=1 3+1 =4 2x5=10 3x1=3 10 -3=7

31.

Solve graphically 3x+2y=4 ; 2x-3y=7

Answer»

ANSWER:X= 1 y =0.5

x=5 y=1

Step-by-step explanation:3x 1 =3 2x0.5=1 3+1 =4

2x5=10 3x1=3 10 -3=7

Discussion

32.	Rationalise the denominator of 12/25root3
Answer» ANSWER: $12/25\sqrt{3}=12\sqrt{3}/25\sqrt{3}\sqrt{3}=12\sqrt{3}/75$ Step-by-step EXPLANATION:

32.

Rationalise the denominator of 12/25root3

Answer»

ANSWER:

$12/25\sqrt{3}=12\sqrt{3}/25\sqrt{3}\sqrt{3}=12\sqrt{3}/75$

Step-by-step EXPLANATION:

Discussion

33.	Divide 1/2 by [-1/3+2/6]
Answer» ANSWER: hsjbhsjsjsjbbsjskks

33.

Divide 1/2 by [-1/3+2/6]

Answer»

ANSWER:

hsjbhsjsjsjbbsjskks

Discussion

34.	Please solve Q9-Q12. If you answer all correctly,I will mark you as brainliest
Answer» Q9. C) 8/-1 Q10. no yes yes yes Mark my ANS as brainlist

34.

Please solve Q9-Q12. If you answer all correctly,I will mark you as brainliest

Answer»

Q9. C) 8/-1

Q10.

no
yes
yes
yes

Mark my ANS as brainlist

Discussion

35.	If a is a non-zerorational and root bis a rational then showthat a/root b is a irrational
Answer» Answer: given: a is a rational number andis irrational. TPT: ais an irrational number. proof: this we will show by the contradiction. letis a rational number. therefore it can be represented as RATION of two co-prime numbers. let=, where p and q are co-primes................(1) a is a rational number. letwhere m and n are co-primes...........(2) .............(3) ⇒ b divides, therefore b divides. let thus b divides, therefore b divides MQ. thus pn and mq has at least one COMMON factor b. but from the ASSUMPTION (1) and (2) pn and mq are co-primes. therefore our assumption is wrong. and is an irrational number PLS MARK BRAINLIEST.*

35.

If a is a non-zerorational and root bis a rational then showthat a/root b is a irrational

Answer»

Answer:

given: a is a rational number andis irrational.

TPT: a*is an irrational number.

proof:

this we will show by the contradiction.

letis a rational number.

therefore it can be represented as RATION of two co-prime numbers.

let=, where p and q are co-primes................(1)

a is a rational number. letwhere m and n are co-primes...........(2)

.............(3)

⇒ b divides, therefore b divides.

let

thus b divides, therefore b divides MQ.

thus pn and mq has at least one COMMON factor b.

but from the ASSUMPTION (1) and (2) pn and mq are co-primes.

therefore our assumption is wrong.

and is an irrational number

PLS MARK BRAINLIEST.

Discussion

36.	5x - 4x square + 3 find if (x = 2)
Answer» Answer: 5x-4x^2+3 if x=2 5(2)-4(2)^2+3 10-16+3 -3 Step-by-step EXPLANATION:

36.

5x - 4x square + 3 find if (x = 2)

Answer»

Answer:

5x-4x^2+3

if x=2

5(2)-4(2)^2+3

10-16+3

-3

Step-by-step EXPLANATION:

Discussion

37.	Find a quadratic polynomial whose sum and product of zeroes are 1and -1 respectively
Answer» Step-by-step EXPLANATION: *PLEASE* *MARK* IT AS A *BRAINLIEST* *ANSWER*.

37.

Find a quadratic polynomial whose sum and product of zeroes are 1and -1 respectively

Answer»

Step-by-step EXPLANATION:

PLEASE MARK IT AS A BRAINLIEST ANSWER.

Discussion

38.	Number of real solution of (x-1)(x+1)(2x+1)(2x-3)=15 is
Answer» Step-by-step EXPLANATION: mam766)(₩¥£€£nnamskodh

38.

Number of real solution of (x-1)(x+1)(2x+1)(2x-3)=15 is

Answer»

Step-by-step EXPLANATION:

mam766)(₩¥£€£nnamskodh

Discussion

39.	Express 48 as the sum of two - odd prime number
Answer» ANSWER: EVEN or odd both r correct Step-by-step EXPLANATION: PLS mark me brainliest

39.

Express 48 as the sum of two - odd prime number

Answer»

ANSWER:

EVEN or odd

both r correct

Step-by-step EXPLANATION:

PLS mark me brainliest

Discussion

40.	Use Euclid's division algorithm to find the HCF of 11 and 9
Answer» Answer: HCF of 11 and 9 Step-by-step explanation: since 11 > 9 , we apply the lemma to 11 and 9 , to get 11 = 9×1+2 since the REMAINDER 2 is not equal to ZERO , we apply the division lemma to 9 and 2 , to get 9 = 2×4+1 we consider the new DIVISIOR 2 and the new remainder 1 , and apply the division lemma to get, 2 = 1×1 +1 again we apply division lemma 1 = 1×1+0 the remainder has now BECOME zero , so our procedure STOPS . since the division at this stage is 1 , the HCF of 11 and 9 is 1.

40.

Use Euclid's division algorithm to find the HCF of 11 and 9

Answer»

Answer:

HCF of 11 and 9

Step-by-step explanation:

since 11 > 9 , we apply the lemma to 11 and 9 , to get

11 = 9×1+2

since the REMAINDER 2 is not equal to ZERO , we apply the division lemma to 9 and 2 , to get

9 = 2×4+1

we consider the new DIVISIOR 2 and the new remainder 1 , and apply the division lemma to get,

2 = 1×1 +1

again we apply division lemma

1 = 1×1+0

the remainder has now BECOME zero , so our procedure STOPS . since the division at this stage is 1 , the HCF of 11 and 9 is 1.

Discussion

41.	Construct an isoscales triangle ABC where mAC=mBC=5cm
Answer» Step-by-step EXPLANATION: jxjsb nmsjsgbdnzihebsjns

41.

Construct an isoscales triangle ABC where mAC=mBC=5cm

Answer»

Step-by-step EXPLANATION:

jxjsb nmsjsgbdnzihebsjns

Discussion

42.	Divide and check 92619 divide by 123
Answer» ANSWER: 723 Step-by-step explanation: PLS MAKE MY ANSWER AS BRANLIEST AND LIKE!!!

42.

Divide and check 92619 divide by 123

Answer»

ANSWER: 723

Step-by-step explanation:

PLS MAKE MY ANSWER AS BRANLIEST AND LIKE!!!

Discussion

43.	Multiplicative inverse of 8/-7
Answer» ANSWER: The MULTIPLICATIVE INVERSE of -8/7= -7/8

43.

Multiplicative inverse of 8/-7

Answer»

ANSWER:

The MULTIPLICATIVE INVERSE of -8/7= -7/8

Discussion

44.	Find the zeroes of the following quadratic polynomial and verify the relationship between the zeros and the coefficient x²+x-2
Answer» Solution : <P> $\bf{\red{\underline{\bf{Given\::}}}}$ The quadratic polynomial x² + x - 2. $\bf{\red{\underline{\bf{To\:find\::}}}}$ The zeroes and verify the relationship between the zeroes and the coefficient. $\bf{\red{\underline{\bf{Explanation\::}}}}$ We have p(x) = x² + x - 2 Zero of the polynomial p(x) = 0 So; $\longrightarrow\sf{x^{2} +x-2=0}\\\\\longrightarrow\sf{x^{2} +2x-x-2=0}\\\\\longrightarrow\sf{x(x+2)-<klux>1</klux>(x+2)=0}\\\\\longrightarrow\sf{(x+2)(x-1)=0}\\\\\longrightarrow\sf{x+2=0\:\:\:Or\:\:\:x-1=0}\\\\\longrightarrow\sf{\pink{x=-2\:\:\:Or\:\:\:x=1}}$ ∴ The α = -2 and β = 1 are the zeroes of the polynomial. As the given quadratic polynomial as we compared with ax² + BX + c a = 1 b = 1 c = -2 Now; $\star\:{\green{\underline{\boldsymbol{Sum\:of\:the\:zeroes\::}}}}}$ $\longrightarrow\sf{\alpha +\beta =\dfrac{-b}{a} =\dfrac{Coefficient\:of\:x }{Coefficient\:of\:x^{2} }} \\\\\\\longrightarrow\sf{-2+1=\dfrac{-1}{1} }\\\\\\\longrightarrow\sf{\pink{-1=-1}}$ $\star\:{\green{\underline{\boldsymbol{Product\:of\:the\:zeroes\::}}}}}$ $\longrightarrow\sf{\alpha \times \beta =\dfrac{c}{a} =\dfrac{Constant\:term }{Coefficient\:of\:x^{2} }} \\\\\\\longrightarrow\sf{-2\times 1=\dfrac{-2}{1} }\\\\\\\longrightarrow\sf{\pink{-2=-2}}$ Thus; Relationship between zeroes and coefficient is VERIFIED .

44.

Find the zeroes of the following quadratic polynomial and verify the relationship between the zeros and the coefficient x²+x-2

Answer»

Solution :

<P> $\bf{\red{\underline{\bf{Given\::}}}}$

The quadratic polynomial x² + x - 2.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The zeroes and verify the relationship between the zeroes and the coefficient.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

We have p(x) = x² + x - 2

Zero of the polynomial p(x) = 0

So;

$\longrightarrow\sf{x^{2} +x-2=0}\\\\\longrightarrow\sf{x^{2} +2x-x-2=0}\\\\\longrightarrow\sf{x(x+2)-<klux>1</klux>(x+2)=0}\\\\\longrightarrow\sf{(x+2)(x-1)=0}\\\\\longrightarrow\sf{x+2=0\:\:\:Or\:\:\:x-1=0}\\\\\longrightarrow\sf{\pink{x=-2\:\:\:Or\:\:\:x=1}}$

∴ The α = -2 and β = 1 are the zeroes of the polynomial.

As the given quadratic polynomial as we compared with ax² + BX + c

a = 1
b = 1
c = -2

Now;

$\star\:{\green{\underline{\boldsymbol{Sum\:of\:the\:zeroes\::}}}}}$

$\longrightarrow\sf{\alpha +\beta =\dfrac{-b}{a} =\dfrac{Coefficient\:of\:x }{Coefficient\:of\:x^{2} }} \\\\\\\longrightarrow\sf{-2+1=\dfrac{-1}{1} }\\\\\\\longrightarrow\sf{\pink{-1=-1}}$

$\star\:{\green{\underline{\boldsymbol{Product\:of\:the\:zeroes\::}}}}}$

$\longrightarrow\sf{\alpha \times \beta =\dfrac{c}{a} =\dfrac{Constant\:term }{Coefficient\:of\:x^{2} }} \\\\\\\longrightarrow\sf{-2\times 1=\dfrac{-2}{1} }\\\\\\\longrightarrow\sf{\pink{-2=-2}}$

Thus;

Relationship between zeroes and coefficient is VERIFIED .

Discussion

45.	45-45=45 reasoning question you can use addition
Answer» Step-by-step explanation: 45-45=45 45=90 MULTIPLY RHS by 0 45

45.

45-45=45 reasoning question you can use addition

Answer»

Step-by-step explanation:

45-45=45

45=90

MULTIPLY RHS by 0

45

Discussion

46.	Find the least number by which 2268 should be divided to get a square number
Answer» PRIME factorization of 2268: 2268 = (2 * 2) * (3 * 3 )* (3 * 3) * 7 As you can SEE, 7 is the minimum number by which 2268 should be DIVIDED

46.

Find the least number by which 2268 should be divided to get a square number

Answer»

PRIME factorization of 2268:

2268 = (2 * 2) * (3 * 3 )* (3 * 3) * 7

As you can SEE, 7 is the minimum number by which 2268 should be DIVIDED

Discussion

47.	The difference of SI and CI is 72 at 12% for 2 years. Calculate the amount
Answer» Answer: If the difference between compound and simple interest is of two YEARS than, Difference = P(R)²/(100)² Where P = principal amount, R = rate of interest If the difference between compound and simple interest is of THREE years than, Difference = 3 x P(R)²/(100)² + P (R/100)³. Here also, P = principal amount, R = rate of interest Test yourself by answering these 25 Practice Questions set of SI an CI. Solved Examples Q. The difference between the compound and simple interest on a certain sum at 12% per annum for two years is Rs. 90. What will be the value of the amount at the end of 3 years if compounded annually? Ans: Here, in this question, the difference is already given to us and we are required to find the principal amount. And using that principal amount we are required to find the amount compounded after three years. The difference is given for two years. So, the formula will be, Difference = P(R)²/100² Now, putting the values into the equation, we will find that, 90 = P(12)²/(100)² 90 x 100²/12² = P P = Rs. 6250 Now, calculating the compound interest on Rs. 6250 will be, A = 6250(1 + 12/100)³ A = 6250(112/100)³ => 6250(1.12)³ => Rs. 8780.80 So, the compounded amount after three years will be Rs. 8780.80

47.

The difference of SI and CI is 72 at 12% for 2 years. Calculate the amount

Answer»

Answer:

If the difference between compound and simple interest is of two YEARS than,

Difference = P(R)²/(100)²

Where P = principal amount, R = rate of interest

If the difference between compound and simple interest is of THREE years than,

Difference = 3 x P(R)²/(100)² + P (R/100)³.

Here also, P = principal amount, R = rate of interest

Test yourself by answering these 25 Practice Questions set of SI an CI.

Solved Examples

Q. The difference between the compound and simple interest on a certain sum at 12% per annum for two years is Rs. 90. What will be the value of the amount at the end of 3 years if compounded annually?

Ans: Here, in this question, the difference is already given to us and we are required to find the principal amount. And using that principal amount we are required to find the amount compounded after three years. The difference is given for two years. So, the formula will be,

Difference = P(R)²/100²

Now, putting the values into the equation, we will find that,

90 = P(12)²/(100)²

90 x 100²/12² = P

P = Rs. 6250

Now, calculating the compound interest on Rs. 6250 will be,

A = 6250(1 + 12/100)³

A = 6250(112/100)³ => 6250(1.12)³ => Rs. 8780.80

So, the compounded amount after three years will be Rs. 8780.80

Discussion

48.	The breath of a rectangular garden is 2/3 of its length. If its perimeter is 40m. Find its dimension
Answer» ANSWER: Here it is the RIGHT answer .

48.

The breath of a rectangular garden is 2/3 of its length. If its perimeter is 40m. Find its dimension

Answer»

ANSWER:

Here it is the RIGHT answer .

Discussion

49.	Find the volume of cube whos edge isa.9cm.
Answer» Answer: VOLUME of Cube = a^3 9cm^3 729 cm^3 is the volume of cube. I HOPE this will HELP you.

49.

Find the volume of cube whos edge isa.9cm.

Answer»

Answer:

VOLUME of Cube = a^3

9cm^3

729 cm^3 is the volume of cube.

I HOPE this will HELP you.

Discussion

50.	In a class of 60 students, 30 opted for mathematics, 32 opted for commerceand 24 opted for both. If one of these students is selected at randomFind the probability that:(i) The student opted for maths or commerce.(ii) The student has opted neither maths or commerce(iii) The student has opted maths but not commerce.
Answer» ANSWER: yyerffxx58xodjrixisjejsj I m SORRY but rkddiiiaooz

50.

In a class of 60 students, 30 opted for mathematics, 32 opted for commerceand 24 opted for both. If one of these students is selected at randomFind the probability that:(i) The student opted for maths or commerce.(ii) The student has opted neither maths or commerce(iii) The student has opted maths but not commerce.

Answer»

ANSWER:

yyerffxx58xodjrixisjejsj I m SORRY but rkddiiiaooz

Discussion

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