332354 + Interview Questions in Secondary School in Math

1.	Solve 18 ÷ (-3) please
Answer» ANSWER: -6 please MARK me as BRAINLIEST

1.

Solve 18 ÷ (-3) please

Answer»

ANSWER:

-6

please MARK me as BRAINLIEST

Discussion

2.	TRY THIS :Multiply the following polynomials, findthe degree of the product of polynomial :(1) p(x)= x² + 3x + 2; 9(x)= x² + 3x +1.
Answer» ANSWER: (a) x 2 −3x+2=x 2 −2x−x+2=x(x−2)+1(x−2)=(x+1)(x−2) (B) SINCE x 2 −3x+k can be written as the product of two first degree polynomials, b 2 −4ac=0 (3) 2 −4(1)(k)=0⇒9−4k=0 k=9/4 Step-by-step EXPLANATION:

2.

TRY THIS :Multiply the following polynomials, findthe degree of the product of polynomial :(1) p(x)= x² + 3x + 2; 9(x)= x² + 3x +1.

Answer»

ANSWER:

(a) x

2

−3x+2=x

2

−2x−x+2=x(x−2)+1(x−2)=(x+1)(x−2)

(B) SINCE x

2

−3x+k can be written as the product of two first degree polynomials,

b

2

−4ac=0

(3)

2

−4(1)(k)=0⇒9−4k=0

k=9/4

Step-by-step EXPLANATION:

Discussion

3.	5 बटा 6 के पावर सिक्स डिवाइडेड 5 बटा सिक्स के पावर 8
Answer» Answer: GOOD NIGHT and Thanks for the FREE POINT

3.

5 बटा 6 के पावर सिक्स डिवाइडेड 5 बटा सिक्स के पावर 8

Answer»

Answer:

GOOD NIGHT and Thanks for the FREE POINT

Discussion

4.	Nidhi saw 20 rose and 12 lily plants in a garden she wanted to plant roses and lily in a same way in her own garden however she was able to plant only 5 roses and 3 lily has she planted the roses and lilies in same ration ?
Answer» Answer: 20+5=25 12+3=15. 25 ROSE and 15 LILY

4.

Nidhi saw 20 rose and 12 lily plants in a garden she wanted to plant roses and lily in a same way in her own garden however she was able to plant only 5 roses and 3 lily has she planted the roses and lilies in same ration ?

Answer»

Answer:

20+5=25 12+3=15. 25 ROSE and 15 LILY

Discussion

5.	What is the pattern between y= x^2, y= x^2 + 3 and y= x^2 - 2
Answer» ANSWER: PLEASE MARK me as BRAINLIST answer

5.

What is the pattern between y= x^2, y= x^2 + 3 and y= x^2 - 2

Answer»

ANSWER:

PLEASE MARK me as BRAINLIST answer

Discussion

6.	25. यदि..+4y2 = 4xy हो, तो x : y= ?(b) 1 : 2
Answer» ANSWER: I don't know the answer Step-by-step EXPLANATION: GIVE me the points mark as branlist

6.

25. यदि..+4y2 = 4xy हो, तो x : y= ?(b) 1 : 2

Answer»

ANSWER:

I don't know the answer

Step-by-step EXPLANATION:

GIVE me the points
mark as branlist

Discussion

7.	In a certain survey, it was found out that out of 148 first year Criminology students, 97 like to use pilot pen. 56 like to use Faber castel pen and 23 like to use both brands?
Answer» Answer: Your question In a certain survey, it was found out that out of 148 first year Criminology students, 97 like to use pilot pen. 56 like to use FABER castel pen and 23 like to use both brands?â The crest of a Parasaurolophus dinosaur skull is shaped somewhat like a trombone and contains a nasal passage in the form of a long, bent tube OPEN at both ends. The dinosaur may have used the passage to produce sound by setting up the fundamental mode in it. (a) If the nasal passage in a certain Parasaurolophus fossil is 2.0 m long, what frequency would have been produced? (b) If that dinosaur could be recreated (as in Jurassic Park), would a person with a hearing range of 60 Hz to 20 kHz be able to hear that fundamental mode and, if so would the sound be high of low frequency? Fossil skulls that contain shorter nasal passages are thought to be those of the female Parasaurolophus. (c) Would that make the female's fundamental frequency higher or lower than the male's? SOLUTION (a) We know that, and , we find for the fundamental frequency in a nasal passage of length (subject to various assumptions about the nature of the passage as a "bent tube open at both ends"). (b) The sound would be perceptible as sound (as opposed to just a GENERAL vibration) of very low frequency. (c) Smaller implies larger by the formula cited above. Thus, the female's sound is of higher pitch (frequency). Report Issue More results We have more related content based on your search that might be helpful for you Videos Problem on Standing Wave in Air Column 10:33 min Standing Waves in Air Column - Pressure Wave Analysis 17:07 min Learn quickly with Stories Stories are SHORT concepts to help you understand better Standing Waves in Open Organ Pipe - Problems L1 2 mins Revise with Concepts Standing Waves in Open Organ Pipe - Problems L1 EXAMPLES DEFINITIONS FORMULAE More questions for you A pipe open at both ends has a fundamental frequency f in air. The pipe is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column is now: A pipe of length is closed at one end. Taking the speed of sound in air as the air column in the pipe cannot resonate for the frequency (in Hz ) The air column here is closed at one end because the surface of water acts as a wall. Which of the following is correct? Step-by-step explanation: Please MAKE me BRAINLIST Please

7.

In a certain survey, it was found out that out of 148 first year Criminology students, 97 like to use pilot pen. 56 like to use Faber castel pen and 23 like to use both brands?

Answer»

Answer:

Your question

In a certain survey, it was found out that out of 148 first year Criminology students, 97 like to use pilot pen. 56 like to use FABER castel pen and 23 like to use both brands?â

The crest of a Parasaurolophus dinosaur skull is shaped somewhat like a trombone and contains a nasal passage in the form of a long, bent tube OPEN at both ends. The dinosaur may have used the passage to produce sound by setting up the fundamental mode in it. (a) If the nasal passage in a certain Parasaurolophus fossil is 2.0 m long, what frequency would have been produced? (b) If that dinosaur could be recreated (as in Jurassic Park), would a person with a hearing range of 60 Hz to 20 kHz be able to hear that fundamental mode and, if so would the sound be high of low frequency? Fossil skulls that contain shorter nasal passages are thought to be those of the female Parasaurolophus. (c) Would that make the female's fundamental frequency higher or lower than the male's?

SOLUTION

(a) We know that, and , we find

for the fundamental frequency in a nasal passage of length

(subject to various assumptions about the nature of the passage as a "bent tube open at both ends").

(b) The sound would be perceptible as sound (as opposed to just a GENERAL vibration) of very low frequency.

(c) Smaller implies larger by the formula cited above. Thus, the female's sound is of higher pitch (frequency).

Report Issue

More results

We have more related content based on your search that might be helpful for you

Videos

Problem on Standing Wave in Air Column

10:33 min

Standing Waves in Air Column - Pressure Wave Analysis

17:07 min

Learn quickly with Stories

Stories are SHORT concepts to help you understand better

Standing Waves in Open Organ Pipe - Problems L1

2 mins

Revise with Concepts

Standing Waves in Open Organ Pipe - Problems L1

EXAMPLES

DEFINITIONS

FORMULAE

8.	Out of 800 families with 5 children each, how many would you expect to have (i) 3 boys and (ii) at least one boyn ki
Answer» THNX for FREE POINTS............

9.	Plzzzz say fast. it's urgent. plzzzzzzzzzzzzz
Answer» ANSWER: Only 1ST OPTION is POLYNOMIAL

Plzzzz say fast. it's urgent. plzzzzzzzzzzzzz

Answer»

ANSWER:

Only 1ST OPTION is POLYNOMIAL

Discussion

10.	If pq parallel to st and angle q = 105 degree and angle s = 120 find angle qrs
Answer» Step-by-step explanation: GIVEN :PQ \|\| ST, ∠PQR = 110° and ∠RST = 130° Construction:A LINE XY PARALLEL to PQ and ST is drawn. ∠PQR + ∠QRX = 180° (Angles on the same side of transversal.) 110° + ∠QRX = 180° ∠QRX = 180° - 110° ∠QRX = 70° Also,∠RST + ∠SRY = 180° (Angles on the same side of transversal.) 130° + ∠SRY = 180° ∠SRY = 50° Now,∠QRX +∠SRY + ∠QRS = 180° 70° + 50° + ∠QRS = 180° ∠QRS = 60° Hence, ∠QRS = 60°

10.

If pq parallel to st and angle q = 105 degree and angle s = 120 find angle qrs

Answer»

Step-by-step explanation:

GIVEN :PQ || ST, ∠PQR = 110° and ∠RST = 130°

Construction:A LINE XY PARALLEL to PQ and ST is drawn.

∠PQR + ∠QRX = 180° (Angles on the same side of transversal.)

110° + ∠QRX = 180°

∠QRX = 180° - 110°

∠QRX = 70°

Also,∠RST + ∠SRY = 180° (Angles on the same side of transversal.)

130° + ∠SRY = 180°

∠SRY = 50°

Now,∠QRX +∠SRY + ∠QRS = 180°

70° + 50° + ∠QRS = 180°

∠QRS = 60°

Hence, ∠QRS = 60°

Discussion

11.	How to locate 1/2 in number line
Answer» Step-by-step EXPLANATION: LOCATE it between 0 and 1

11.

How to locate 1/2 in number line

Answer»

Step-by-step EXPLANATION:

LOCATE it between 0 and 1

Discussion

12.	N =2p-3, p ∈ n এবং n² কে 4 দ্বারা ভাগ করলে ভাগশেষ কত হবে?
Answer» Step-by-step EXPLANATION: ASK QUESTIONS in ENGLISH only

12.

N =2p-3, p ∈ n এবং n² কে 4 দ্বারা ভাগ করলে ভাগশেষ কত হবে?

Answer»

Step-by-step EXPLANATION:

ASK QUESTIONS in ENGLISH only

Discussion

13.	EXERCISE 5.71. Specify the type of quadrilateral PQRS in each case given the following information:(1) PQ\|\|RS, PS \|\| RQ PQ=QR, SPQ = 60°
Answer» ANSWER: it is a parrallelofram

13.

EXERCISE 5.71. Specify the type of quadrilateral PQRS in each case given the following information:(1) PQ||RS, PS || RQ PQ=QR, SPQ = 60°

Answer»

ANSWER:

it is a parrallelofram

Discussion

14.	N =2p-3, p ∈ n এবং n² কে 4 দ্বারা ভাগ করলে ভাগশেষ কত হবে? Hi
Answer» ANSWER: SEND in ENGLISH LANGUAGE I will HELP you

14.

N =2p-3, p ∈ n এবং n² কে 4 দ্বারা ভাগ করলে ভাগশেষ কত হবে? Hi

Answer»

ANSWER:

SEND in ENGLISH LANGUAGE I will HELP you

Discussion

15.	8x to the power of 2-2
Answer» ANSWER: 8 Step-by-step EXPLANATION: PLEASE thank my answer and FOLLOW me mark me as BRAINLIST answer

15.

8x to the power of 2-2

Answer»

ANSWER:

8

Step-by-step EXPLANATION:

PLEASE thank my answer and FOLLOW me mark me as BRAINLIST answer

Discussion

16.	C- o57015-25 25-25 20 257 13 -10© Find the value gix for the poor polyeste!when dissted polynomial when disded by aP(0)+22-102270© It7 sin 022/3 the find. TonoTano Seco
Answer» Step-by-step explanation: ANSWER: ━━━━━━━━━━━━━━━━━━━━━━━━━━ \begin{gathered}\begin{gathered}1. \: \: \sin(2 \alpha ) = 2 \sin( \alpha ) \cos( \alpha ) \\\end{gathered} 1.sin(2α)=2sin(α)cos(α)\end{gathered}1.sin(2α)=2sin(α)cos(α)1.sin(2α)=2sin(α)cos(α) 2. \: \: \sin(180 - \alpha ) = \sin( \alpha )2.sin(180−α)=sin(α)2.sin(180−α)=sin(α)2.sin(180−α)=sin(α) 3. \: \: \sin(90 - \alpha ) = \cos( \alpha )3.sin(90−α)=cos(α)3.sin(90−α)=cos(α)3.sin(90−α)=cos(α) ━━━━━━━━━━━━━━━━━━━━━━━━━━ L.H.S :- Sin10. SIN30. SIN50. Sin70L.H.S:−Sin10.Sin30.Sin50.Sin70 \begin{gathered}\begin{gathered}= \cos(90 - 10) \sin(30) \cos(90 - 40) \cos(90 - 70) \\ = \cos(80) \: \frac{1}{2} \: \cos(40) \: \cos(20) \\ = \frac{1}{4 \sin(20) } \cos(8 0 ) \cos(40) . \: 2 \sin(20) \cos(20) \\ = \frac{1}{8 \sin(20) } \cos(80) 2. \cos(40) \sin(40) \\ = \frac{1}{16 \sin(20) } 2 \cos(80) \sin(80 ) \\ = \frac{1}{16 \sin(20) } \sin(160) \\ = \frac{1}{16 \sin(20) } \sin(180 - 20) \\ = \frac{1}{16 \sin(20) } \sin(20) \\ = \frac{1}{16} \: \: \: \: \: \: \: \: .........R.H.S\end{gathered}\end{gathered}=cos(90−10)sin(30)cos(90−40)cos(90−70)=cos(80)21cos(40)cos(20)=4sin(20)1cos(80)cos(40).2sin(20)cos(20)=8sin(20)1cos(80)2.cos(40)sin(40)=16sin(20)12cos(80)sin(80)=16sin(20)1sin(160)=16sin(20)1sin(180−20)=16sin(20)1sin(20)=161.........R.H.S =cos(90−10)sin(30)cos(90−40)cos(90−70)=cos(90−10)sin(30)cos(90−40)cos(90−70) =cos(80) 2/1=cos(80)2/1 cos(40)cos(20)= 4sin(20)1cos(40)cos(20)=4sin(20)1 cos(80)cos(40).2sin(20)cos(20)= 8sin(20)1cos(80)cos(40).2sin(20)cos(20)=8sin(20)1 cos(80)2.cos(40)sin(40)= 16sin(20)1cos(80)2.cos(40)sin(40)=16sin(20)1 2cos(80)sin(80)= 16sin(20)12cos(80)sin(80)=16sin(20)1 sin(160)= 16sin(20)1sin(160)=16sin(20)1 sin(180−20)= 16sin(20)1sin(180−20)=16sin(20)1 sin(20)= 16/1sin(20)=16/1 .........R.H.S

16.

C- o57015-25 25-25 20 257 13 -10© Find the value gix for the poor polyeste!when dissted polynomial when disded by aP(0)+22-102270© It7 sin 022/3 the find. TonoTano Seco

Answer»

Step-by-step explanation:

ANSWER:

━━━━━━━━━━━━━━━━━━━━━━━━━━

\begin{gathered}\begin{gathered}1. \: \: \sin(2 \alpha ) = 2 \sin( \alpha ) \cos( \alpha ) \\\end{gathered} 1.sin(2α)=2sin(α)cos(α)\end{gathered}1.sin(2α)=2sin(α)cos(α)1.sin(2α)=2sin(α)cos(α)

2. \: \: \sin(180 - \alpha ) = \sin( \alpha )2.sin(180−α)=sin(α)2.sin(180−α)=sin(α)2.sin(180−α)=sin(α)

3. \: \: \sin(90 - \alpha ) = \cos( \alpha )3.sin(90−α)=cos(α)3.sin(90−α)=cos(α)3.sin(90−α)=cos(α)

━━━━━━━━━━━━━━━━━━━━━━━━━━

L.H.S :- Sin10. SIN30. SIN50. Sin70L.H.S:−Sin10.Sin30.Sin50.Sin70

\begin{gathered}\begin{gathered}= \cos(90 - 10) \sin(30) \cos(90 - 40) \cos(90 - 70) \\ = \cos(80) \: \frac{1}{2} \: \cos(40) \: \cos(20) \\ = \frac{1}{4 \sin(20) } \cos(8 0 ) \cos(40) . \: 2 \sin(20) \cos(20) \\ = \frac{1}{8 \sin(20) } \cos(80) 2. \cos(40) \sin(40) \\ = \frac{1}{16 \sin(20) } 2 \cos(80) \sin(80 ) \\ = \frac{1}{16 \sin(20) } \sin(160) \\ = \frac{1}{16 \sin(20) } \sin(180 - 20) \\ = \frac{1}{16 \sin(20) } \sin(20) \\ = \frac{1}{16} \: \: \: \: \: \: \: \: .........R.H.S\end{gathered}\end{gathered}=cos(90−10)sin(30)cos(90−40)cos(90−70)=cos(80)21cos(40)cos(20)=4sin(20)1cos(80)cos(40).2sin(20)cos(20)=8sin(20)1cos(80)2.cos(40)sin(40)=16sin(20)12cos(80)sin(80)=16sin(20)1sin(160)=16sin(20)1sin(180−20)=16sin(20)1sin(20)=161.........R.H.S

=cos(90−10)sin(30)cos(90−40)cos(90−70)=cos(90−10)sin(30)cos(90−40)cos(90−70)

=cos(80) 2/1=cos(80)2/1

cos(40)cos(20)= 4sin(20)1cos(40)cos(20)=4sin(20)1

cos(80)cos(40).2sin(20)cos(20)= 8sin(20)1cos(80)cos(40).2sin(20)cos(20)=8sin(20)1

cos(80)2.cos(40)sin(40)= 16sin(20)1cos(80)2.cos(40)sin(40)=16sin(20)1

2cos(80)sin(80)= 16sin(20)12cos(80)sin(80)=16sin(20)1

sin(160)= 16sin(20)1sin(160)=16sin(20)1

sin(180−20)= 16sin(20)1sin(180−20)=16sin(20)1

sin(20)= 16/1sin(20)=16/1

.........R.H.S

Discussion

17.	How many paise make one rupee ?
Answer» Answer: 100 PAISA can MAKE ONE RUPEE

17.

How many paise make one rupee ?

Answer»

Answer:

100 PAISA can MAKE ONE RUPEE

Discussion

18.	Find (((1)/(3))^(-2n)-: (1)/(3) ^(-2)times (1)/(3^(n/2)) ^(-2)- (1)/(3^(-3)) ^(n))/( (1)/(3^(-2/3)) ^((9)/(2)^(m))times (1)/(16^(-3)) ^((1)/(4))) if m-n=(2^(m+n))^(m-n)(2^(n+p))^(n-p)(2^(p+m))^(p-m)
Answer» ANSWER: xhdhwuchjsjdcjjsjxjxhxhsjz Step-by-step EXPLANATION: HOPE this HELP U

18.

Find (((1)/(3))^(-2n)-: (1)/(3) ^(-2)times (1)/(3^(n/2)) ^(-2)- (1)/(3^(-3)) ^(n))/( (1)/(3^(-2/3)) ^((9)/(2)^(m))times (1)/(16^(-3)) ^((1)/(4))) if m-n=(2^(m+n))^(m-n)(2^(n+p))^(n-p)(2^(p+m))^(p-m)

Answer»

ANSWER:

xhdhwuchjsjdcjjsjxjxhxhsjz

Step-by-step EXPLANATION:

HOPE this HELP U

Discussion

19.	Multiply (-13) х(-13)
Answer» $\Huge\mathcal{\fcolorbox{red}{cyan}{\red{169}}}$

19.

Multiply (-13) х(-13)

Answer»

$\Huge\mathcal{\fcolorbox{red}{cyan}{\red{169}}}$

Discussion

20.	Simplify the expressions and evaluate them as directed. a(a-5)+6 for a=1
Answer» ANSWER: MARK me as a BRAINLIST mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist Step-by-step EXPLANATION: mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist

20.

Simplify the expressions and evaluate them as directed. a(a-5)+6 for a=1

Answer»

ANSWER:

MARK me as a BRAINLIST mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist mark me as a brainlist

Step-by-step EXPLANATION:

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Discussion

21.	Answer it......plzz...
Answer» Step-by-step EXPLANATION: left HAND SIDE = right hand side ( PROVED)

21.

Answer it......plzz...

Answer»

Step-by-step EXPLANATION:

left HAND SIDE = right hand side ( PROVED)

Discussion

22.	A die is thrown. Find the probability of getting a number less then 5 on a die.
Answer» Answer: 4/6 2/3 Step-by-step EXPLANATION: PLEASE THANK my answer and FOLLOW me MARK me as brainlist answer

22.

A die is thrown. Find the probability of getting a number less then 5 on a die.

Answer»

Answer:

4/6

2/3

Step-by-step EXPLANATION:

PLEASE THANK my answer and FOLLOW me MARK me as brainlist answer

Discussion

23.	There are two trees A and B on a field such that the distance between A and B is 5 meters. Ayesha is continuously running on the field such that sum of her distances from A and B is always 5 meters. How many times does she visit the midpoint of A and B?
Answer» ANSWER: ................................

23.

There are two trees A and B on a field such that the distance between A and B is 5 meters. Ayesha is continuously running on the field such that sum of her distances from A and B is always 5 meters. How many times does she visit the midpoint of A and B?

Answer»

ANSWER:

................................

Discussion

24.	find the area of square whose perimeter is equal to the perimeter. is equal to the perimeter of a rectangle of size 14 cm by 12 cm
Answer» To Find :- The area of square. Solution :- Given, Square perimeter = Rectangle perimeter Length of rectangle (l) = 14 CM Breath of rectangle (b) = 12 cm We know that, ↪ Perimeter of rectangle = 2(l + b) ↪ Perimeter of rectangle = 2(14 + 12) ↪ Perimeter of rectangle = 2(26) ↪ Perimeter of rectangle = 52 cm Given, Square perimeter = Rectangle perimeter ↪ Square perimeter = 52 cm Now, ↪ Side of square = Square perimeter / Number of sides [ PUT the values ] ↪ Side of square = 52/4 ↪ Side of square = 13 cm As we know that, ↪ Area of square = (Side)² [ Put the values ] ↪ Area of square = (13)² ↪ Area of square = 169 cm² Therefore, The area of square is 169 cm².

24.

find the area of square whose perimeter is equal to the perimeter. is equal to the perimeter of a rectangle of size 14 cm by 12 cm

Answer»

To Find :-

The area of square.

Solution :-

Given,

Square perimeter = Rectangle perimeter
Length of rectangle (l) = 14 CM
Breath of rectangle (b) = 12 cm

We know that,

↪ Perimeter of rectangle = 2(l + b)

↪ Perimeter of rectangle = 2(14 + 12)

↪ Perimeter of rectangle = 2(26)

↪ Perimeter of rectangle = 52 cm

Given, Square perimeter = Rectangle perimeter

↪ Square perimeter = 52 cm

Now,

↪ Side of square = Square perimeter / Number of sides

[ PUT the values ]

↪ Side of square = 52/4

↪ Side of square = 13 cm

As we know that,

↪ Area of square = (Side)²

[ Put the values ]

↪ Area of square = (13)²

↪ Area of square = 169 cm²

Therefore,

The area of square is 169 cm².

Discussion

25.	Find the cube root of each of the followiong 8×125
Answer» Answer: 2×5 is the answer to UR question . Hope it HELPED you and please MARK it as brainliest :))

25.

Find the cube root of each of the followiong 8×125

Answer»

Answer:

2×5 is the answer to UR question

.

Hope it HELPED you and please MARK it as brainliest :))

Discussion

26.	Prove that, The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides
Answer» ANSWER: SORRY DONT KNOW the answer Step-by-step EXPLANATION:

26.

Prove that, The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides

Answer»

ANSWER:

SORRY DONT KNOW the answer

Step-by-step EXPLANATION:

Discussion

27.	Plz tell me the ans is the ans x-1/x = 0
Answer» Answer: √( - 3) Step-by-step EXPLANATION: x + 1/x = 1 then formula (a-b)^2=(a+b)^2 - 4ab

27.

Plz tell me the ans is the ans x-1/x = 0

Answer»

Answer:

√( - 3)

Step-by-step EXPLANATION:

x + 1/x = 1

then formula

(a-b)^2=(a+b)^2 - 4ab

Discussion

28.	The river Krishna is 1280 km long , Boats ply for 64 km
Answer» Answer: yes because after that point it is a risk of LIFE may be the WAY is not at a good PLACE to go !! Step-by-step EXPLANATION:

28.

The river Krishna is 1280 km long , Boats ply for 64 km

Answer»

Answer:

yes because after that point it is a risk of LIFE may be the WAY is not at a good PLACE to go !!

Step-by-step EXPLANATION:

Discussion

29.	Draw a line segment of length 7.6 cm and divide it in the ratio 5 ratio 8 measure the two parts
Answer» Step-by-step explanation: draw a LINE segment of length 7.6cm and divide in ratio 5:8 measure the TWO parts.give the JUSTIFICATION of CONSTRUCTION

29.

Draw a line segment of length 7.6 cm and divide it in the ratio 5 ratio 8 measure the two parts

Answer»

Step-by-step explanation:

draw a LINE segment of length 7.6cm and divide in ratio 5:8 measure the TWO parts.give the JUSTIFICATION of CONSTRUCTION

Discussion

30.	Rs 10,000 is invested at 5%interest rate p.a. Find the amount paid of the end of 3 year.
Answer» Step-by-step explanation: 8 8 8 2 0 7 3 1 8 0 Message me on WHATSAPP i will ANSWER.

30.

Rs 10,000 is invested at 5%interest rate p.a. Find the amount paid of the end of 3 year.

Answer»

Step-by-step explanation:

8

2

0

7

3

1

8

0

Message me on WHATSAPP i will ANSWER.

Discussion

31.	HELP ME I REALLY NEED SOLVE THIS QUESTION
Answer» ANSWER: which QUESTION do you WANT to SOLVE

31.

HELP ME I REALLY NEED SOLVE THIS QUESTION

Answer»

ANSWER:

which QUESTION do you WANT to SOLVE

Discussion

32.	Which of tahe following numbers is perfect cube ?
Answer» Answer: The NUMBERS such as 1, 8, 27, 64, etc. are known as PERFECT CUBES or CUBE numbers.

32.

Which of tahe following numbers is perfect cube ?

Answer»

Answer:

The NUMBERS such as 1, 8, 27, 64, etc. are known as PERFECT CUBES or CUBE numbers.

Discussion

33.	Counting in twos write the next 5 number's3292
Answer» ANSWER: 3292 to 3302 are 3294,3296,3298,3300. Step-by-step explanation: To find : Counting by twos write numbers from 3292 to 3302 ? Solution : Counting by two's we have to ADD 2 on each number, 3292+2=3294 3294+2=3296 3296+2=3298 3298+2=3300 3300+2=3302 Therefore, numbers from 3292 to 3302 are 3294,3296,3298,3300. #Learn more Counting by twos from 335to 349 hope this answer helps you please mark me the BRAINLIEST

33.

Counting in twos write the next 5 number's3292

Answer»

ANSWER: 3292 to 3302 are 3294,3296,3298,3300.

Step-by-step explanation:

To find : Counting by twos write numbers from 3292 to 3302 ?

Solution :

Counting by two's we have to ADD 2 on each number,

3292+2=3294

3294+2=3296

3296+2=3298

3298+2=3300

3300+2=3302

Therefore, numbers from 3292 to 3302 are 3294,3296,3298,3300.

#Learn more

Counting by twos from 335to 349

hope this answer helps you

please mark me the BRAINLIEST

Discussion

34.	The circumference of circle with area 81 π2 eqval to
Answer» ANSWER: Answer is 18π Step-by-step EXPLANATION: Given AREA of a circle is 81π. We know formula for area of a circle is πr^2 So,πr^2=81π ⇒r2=81 ⇒r=9 Formula for circumference is 2πr. So PUTTING r=9 circumference will be 2π9=18π HENCE PROVED.

34.

The circumference of circle with area 81 π2 eqval to

Answer»

ANSWER:

Answer is 18π

Step-by-step EXPLANATION:

Given AREA of a circle is 81π.

We know formula for area of a circle is πr^2

So,πr^2=81π

⇒r2=81

⇒r=9

Formula for circumference is 2πr.

So PUTTING r=9 circumference will be

2π9=18π

HENCE PROVED.

Discussion

35.	An article was sold for rupees 150 with a profit of 18% find the cost price
Answer» Answer: An article was sold for rupees 150 with a PROFIT of 18% find the cost PRICE

35.

An article was sold for rupees 150 with a profit of 18% find the cost price

Answer»

Answer:

An article was sold for rupees 150 with a PROFIT of 18% find the cost PRICE

Discussion

36.	WHAT IS THE HCF OF 75,60 AND 210
Answer» Answer: 15....................

36.

WHAT IS THE HCF OF 75,60 AND 210

Answer»

Answer:

15....................

Discussion

37.	Which of the following is perfect square are square of even number? 121,225,6561,1296
Answer» Answer: 1296 is the PERFECT SQUARE of EVEN NUMBER.

37.

Which of the following is perfect square are square of even number? 121,225,6561,1296

Answer»

Answer:

1296 is the PERFECT SQUARE of EVEN NUMBER.

Discussion

38.	Prove that (A-B)U(B-A)=AUB
Answer» ANSWER: Your Question is Wrong Step-by-step explanation: We have to prove that : (A-B) U (B-A) = (A∪B) - (A∩B) Proof: Let, x ∈ (A-B) U (B-A) ⇒ x ∈ (A-B) or x ∈ (B-A) ⇒ x ∈ A But x ∉ B or x ∈ B but x ∉ A, ⇒ x ∈ A or x ∈ B ⇒ x ∈ (A∪B) ⇒ x ∈ (A∪B) - (A∩B) SINCE here x REPRESENTS the arbitrary element of the SET (A-B) U (B-A). Thus, (A-B) U (B-A) = (A∪B) - (A∩B) Hence, proved.

38.

Prove that (A-B)U(B-A)=AUB

Answer»

ANSWER:

Your Question is Wrong

Step-by-step explanation:

We have to prove that : (A-B) U (B-A) = (A∪B) - (A∩B)

Proof:

Let, x ∈ (A-B) U (B-A)

⇒ x ∈ (A-B) or x ∈ (B-A)

⇒ x ∈ A But x ∉ B or x ∈ B but x ∉ A,

⇒ x ∈ A or x ∈ B

⇒ x ∈ (A∪B)

⇒ x ∈ (A∪B) - (A∩B)

SINCE here x REPRESENTS the arbitrary element of the SET (A-B) U (B-A).

Thus, (A-B) U (B-A) = (A∪B) - (A∩B)

Hence, proved.

Discussion

39.	Sunita is half the age of her mother Geeta find their ages after 4 year
Answer» ANSWER: Step-by-step EXPLANATION: ਹੇਠ ਲਿਖੀਆਂ ਸੰਖਿਆਂਵਾਂ ਵਿੱਚੋ ਕਿਹੜੀ ਸੰਖਿਆ 2 ਅਤੇ 3 ਦੋਵਾਂ ਨਾਲ ਭਾਜ ਯੋਗ ਹੈ

39.

Sunita is half the age of her mother Geeta find their ages after 4 year

Answer»

ANSWER:

Step-by-step EXPLANATION:

ਹੇਠ ਲਿਖੀਆਂ ਸੰਖਿਆਂਵਾਂ ਵਿੱਚੋ ਕਿਹੜੀ ਸੰਖਿਆ 2 ਅਤੇ 3 ਦੋਵਾਂ ਨਾਲ ਭਾਜ ਯੋਗ ਹੈ

Discussion

40.	Following data given total mark (out of 600)obtained by 6 students of a class represent the following on a bargraphajay-360,bali-500,dipti-300,faiyaz-360,geetika-400,hari-540
Answer» Answer: stay HOME and stay safe hi HELLO and what's up guys it's JAZZ DAY and welcome to my channel

40.

Following data given total mark (out of 600)obtained by 6 students of a class represent the following on a bargraphajay-360,bali-500,dipti-300,faiyaz-360,geetika-400,hari-540

Answer»

Answer:

stay HOME and stay safe

hi HELLO and what's up guys it's JAZZ DAY and welcome to my channel

Discussion

41.	$\left(\left(6^{4}\right)^{5}\times\frac{6^{2}}{6^{15}}\right)^{2}$
Answer» WT is this QUESTION which STANDARD

Discussion

42.	Write a polynomial whoseproduct is 3 and sum is2
Answer» ANSWER: We Should KNOW Some Trignometric IDENTITIES For SOLVING This Question. ━━━━━━━━━━━━━━━━━━━━━━━━━━ $\begin{gathered}1. \: \: \sin(2 \alpha ) = 2 \sin( \alpha ) \cos( \alpha ) \\\end{gathered} 1.sin(2α)=2sin(α)cos(α)$ $2. \: \: \sin(180 - \alpha ) = \sin( \alpha )2.sin(180−α)=sin(α)$ $3. \: \: \sin(90 - \alpha ) = \cos( \alpha )3.sin(90−α)=cos(α)$ ━━━━━━━━━━━━━━━━━━━━━━━━━━ $L.H.S :- Sin10. Sin30. Sin50. Sin70$ $\begin{gathered}= \cos(90 - 10) \sin(30) \cos(90 - 40) \cos(90 - 70) \\ = \cos(80) \: \frac{1}{2} \: \cos(40) \: \cos(20) \\ = \frac{1}{4 \sin(20) } \cos(8 0 ) \cos(40) . \: 2 \sin(20) \cos(20) \\ = \frac{1}{8 \sin(20) } \cos(80) 2. \cos(40) \sin(40) \\ = \frac{1}{16 \sin(20) } 2 \cos(80) \sin(80 ) \\ = \frac{1}{16 \sin(20) } \sin(160) \\ = \frac{1}{16 \sin(20) } \sin(180 - 20) \\ = \frac{1}{16 \sin(20) } \sin(20) \\ = \frac{1}{16} \: \: \: \: \: \: \: \: .........R.H.S\end{gathered}$ $=cos(90−10)sin(30)cos(90−40)cos(90−70)$ $=cos(80) 2/1$ $cos(40)cos(20)= 4sin(20)1$ $cos(80)cos(40).2sin(20)cos(20)= 8sin(20)1$ $cos(80)2.cos(40)sin(40)= 16sin(20)1$ $2cos(80)sin(80)= 16sin(20)1$ $sin(160)= 16sin(20)1$ $sin(180−20)= 16sin(20)1$ $sin(20)= 16/1$ .........R.H.S,

42.

Write a polynomial whoseproduct is 3 and sum is2

Answer»

ANSWER:

We Should KNOW Some Trignometric IDENTITIES For SOLVING This Question.

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\begin{gathered}1. \: \: \sin(2 \alpha ) = 2 \sin( \alpha ) \cos( \alpha ) \\\end{gathered} 1.sin(2α)=2sin(α)cos(α)$

$2. \: \: \sin(180 - \alpha ) = \sin( \alpha )2.sin(180−α)=sin(α)$

$3. \: \: \sin(90 - \alpha ) = \cos( \alpha )3.sin(90−α)=cos(α)$

━━━━━━━━━━━━━━━━━━━━━━━━━━

$L.H.S :- Sin10. Sin30. Sin50. Sin70$

$\begin{gathered}= \cos(90 - 10) \sin(30) \cos(90 - 40) \cos(90 - 70) \\ = \cos(80) \: \frac{1}{2} \: \cos(40) \: \cos(20) \\ = \frac{1}{4 \sin(20) } \cos(8 0 ) \cos(40) . \: 2 \sin(20) \cos(20) \\ = \frac{1}{8 \sin(20) } \cos(80) 2. \cos(40) \sin(40) \\ = \frac{1}{16 \sin(20) } 2 \cos(80) \sin(80 ) \\ = \frac{1}{16 \sin(20) } \sin(160) \\ = \frac{1}{16 \sin(20) } \sin(180 - 20) \\ = \frac{1}{16 \sin(20) } \sin(20) \\ = \frac{1}{16} \: \: \: \: \: \: \: \: .........R.H.S\end{gathered}$

$=cos(90−10)sin(30)cos(90−40)cos(90−70)$

$=cos(80) 2/1$

$cos(40)cos(20)= 4sin(20)1$

$cos(80)cos(40).2sin(20)cos(20)= 8sin(20)1$

$cos(80)2.cos(40)sin(40)= 16sin(20)1$

$2cos(80)sin(80)= 16sin(20)1$

$sin(160)= 16sin(20)1$

$sin(180−20)= 16sin(20)1$

$sin(20)= 16/1$

.........R.H.S,

Discussion

43.	What is the nth term − 9 , − 5 , − 1 , 3 , 7 , . .
Answer» Answer: 19 Step-by-step EXPLANATION: please MAKE it brainliest ANSWERAND follow

43.

What is the nth term − 9 , − 5 , − 1 , 3 , 7 , . .

Answer»

Answer:

19

Step-by-step EXPLANATION:

please MAKE it brainliest ANSWERAND follow

Discussion

44.	By what no should (32)^-1 be divided to get the quotient as 4^-1
Answer» ANSWER: I am not CLEAR this QUESTIONS

44.

By what no should (32)^-1 be divided to get the quotient as 4^-1

Answer»

ANSWER:

I am not CLEAR this QUESTIONS

Discussion

45.	One root of the equation x2+4x-4=0 is
Answer» ANSWER: ROOT of the EQUATION x2+4x-4=0 is 2/3

45.

One root of the equation x2+4x-4=0 is

Answer»

ANSWER:

ROOT of the EQUATION x2+4x-4=0 is 2/3

Discussion

46.	Value between 0.6 & 0.5
Answer» Answer: 0.55 ......................

46.

Value between 0.6 & 0.5

Answer»

Answer:

0.55

......................

Discussion

47.	What did you discover from activity?make your own answer
Answer» ANSWER: HII the QUESTION is INCORRECT

47.

What did you discover from activity?make your own answer

Answer»

ANSWER:

HII the QUESTION is INCORRECT

Discussion

48.	(15.7_25.7) ka vrg chin kya hoga answer me plz
Answer» ANSWER: _10 Step-by-step EXPLANATION: HEY hii The answer is _10

48.

(15.7_25.7) ka vrg chin kya hoga answer me plz

Answer»

ANSWER:

_10

Step-by-step EXPLANATION:

HEY hii

The answer is _10

Discussion

49.	The number of integers between-2and2is
Answer» ANSWER: There are INFINITE INTEGERS between -2 and 2. Hope it HELPS you !!!!

49.

The number of integers between-2and2is

Answer»

ANSWER:

There are INFINITE INTEGERS between -2 and 2.

Hope it HELPS you !!!!

Discussion

50.	How to compare -9/13, -5/9 in cross multiple method ?
Answer» ANSWER: -19/13 is LESS than -5/9

50.

How to compare -9/13, -5/9 in cross multiple method ?

Answer»

ANSWER:

-19/13 is LESS than -5/9

Discussion

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