Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

2-dogit perfect square

Answer» TWO digit perfect SQUARES are
16 ,25 ,36 ,49 ,64,81
2.

Using remainder theorem x³-6x²+9x+3 is divided by x-1

Answer» PUT
x-1=0
hence x=1
BY REMAINDER THEOREM
WE GET REMAINDER IF WE PUT X=1 IN GIVEN EQUATION
{x}^{3}  - 6 {x}^{2}  + 9x + 3 \\  {1}^{ 3}  - 6  \times {1}^{2}  +9  \times 1 + 3 \\  = 1 - 6 + 9 + 3 \\  = <klux>7</klux>
Remainder is 7
3.

15 root 20 by 6 root 125

Answer»

30√5/30√5
=1
.....HOPE it HELPS

4.

The base of a parallelogram is 10cmand height is 8cm find the area and perimeter

Answer»

AREA of a IIgm = base * HEIGHT

= 10 * 8= 80 cm^2

5.

The side of a regular polygon is 2.5cmIf the perimetre of the polygon is 15cmThen find the number of sides of the polygon

Answer»

The no of the SIDES is 6
(15÷2.5) = 6

6.

Ratio of milk and water in two vessels a and b is 3:5 and 1:3 respectively . In wjat ratio they must be mixed so resultant solution may contain half milk and half water?

Answer»

Answer:

2:1

Step-by-step EXPLANATION:

Vessel A MILK & water= 3/8 & 5/8

Vessel B milk & water= 1/4 & 3/4


Now milk & water mixed in we get half milk and half water .

Then,

3x/8+ y/4= 1/2..............(1)

5x/8 + 3y/4= 1/2 .............(2)

solving both

(3x+2y)= 4..............(1)

5x+6y= 4................(2)

multiply EQUATION 1 by 3

9x+6y=12

5x+6y=4

now SUBTRACT (2) from equation (1)

4x=8

x=2

then y = 1


Therefore ratio is 2:1

7.

A b c and d are points on the circumference of a circle centre o ac is a diameter of the circle

Answer» QUESTION is INCOMPLETE
8.

Sum of first p, q, r terms of an A. P are a,b,c respectively.SHOW THAT :❌NO SPAM ❌BEST ANSWER WILL BE MARKED AS BRAINLIEST! ✔️

Answer»

Note: Sum of n terms = (n/2)[2a + (n - 1) * d].

Let the first term be A and the common difference be d.

(i)

GIVEN sum of p terms = a.

⇒ (p/2)[2A + (p - 1) * d] = a

⇒ (a/p) = (1/2)[2A + (p - 1) * d]


(ii)

Given sum of Q terms is b.

⇒ (q/2) = 2A + (q - 1) * d = b

⇒ (q/p) = (1/2)[2A + (q - 1) * d]


(III)

Given sum of r terms of an AP is c.

⇒ (r/2)[2A + (r - 1) * d] = c

⇒ (r/c) = (1/2)[2A + (r - 1) * d]


(IV)

On subtracting (ii) from (i), we get

=>\frac{a}{p} -\frac{b}{q} =\frac{1}{2} (p - 1)d -(q - 1)d

=>\frac{a}{p}-\frac{b}{q}=\frac{1}{2}[(p - q) *d]

=> p-q=\frac{2}{d}[\frac{a}{p}-\frac{b}{q}]


(V)

On subtracting (iii) from (ii), we get

=>\frac{b}{q}-\frac{c}{r}=\frac{1}{2}[(q-1)d-(r-1)d]

=>\frac{b}{q}-\frac{c}{r}=\frac{1}{2}(q-r)d

=>q-r=\frac{2}{d}[ \frac{b}{q}-\frac{c}{r}]


(vi)

on subtracting (iii) from (i), we get

=>\frac{c}{r}-\frac{a}{p}=\frac{1}{2}(r-p)d

=>r-p =\frac{2}{d}[ \frac{c}{r}- \frac{a}{p}]


Now,

Given Equation is (a/p)(q - r) + (b/q)(r - p) + (c/r)(p - q) = 0

=>\frac{a}{q}[\frac{2}{d}(\frac{b}{q}- \frac{c}{r})]+\frac{b}{q}[\frac{2}{d}(\frac{c}{r}-\frac{a}{p})]+\frac{c}{r}[\frac{2}{d}( \frac{a}{p}-\frac{b}{q})]

=>\frac{2}{d}[\frac{ab}{pq}- \frac{ac}{pr}+\frac{bc}{qr}-\frac{ab}{pq}+\frac{ac}{pr}-\frac{bc}{qr}]

=>0.



Hope it helps!

9.

Plz answer the question it is find p and q.

Answer»

Have a NICE DAY......

10.

Find 13 part i.e value of x

Answer»

2^2x - 2^X*2³= -16
now
2^2x - 8*2^x = -16
2^x = P(CONSIDER)
p²-8p+16=0
(p-4)² = 0
so p=4
i.e.
2^x = 4
so X = 2

11.

Prove mpt. correct answer will be mark as brainlist

Answer»

Hey friend here is your ANSWER HOPE this helps you plz FOLLOW me plz follow me plz and mark me as BRAINLIEST please

12.

⭐Sum of n terms of 2 AP are (3n+8):(7n+15).Find the ration fo their 15 terms.⭐❌NO SPAM ❌BEST ANSWER WILL BE MARKED AS BRAINLIEST! ✔️

Answer»

This is the ANSWER................

13.

A certain sum of money amounts to Rs. 1008 in 2 years and to Rs. 1164 in 3 ½ years. Find the sum and rate of interest

Answer»

As we know,Amount=principal+simple interest
First equation (for 2 years) is 
1008=p+(SI for 2years) -----(1)
second equation (for 3 1/2 years) is
1164=p+(SI for 3 1/2years) -----(2)
subtracting equation (1) and (2) we get
(SI for 3 1/2years)-(SI for 2years)=1164-1008
SI for 1 1/2 year=156
3/2 SI=156
SI for 1year=156*2/3=104
substitute SI VALUE in equation(1),we get
1008=p+(2*SI for 1year)
1008=P+(2*104)
principal=1008-208=800=sum
SI for 2years=P*T*R/100
208=800*2*R/100
Finally,we get R 
R=208*100/(800*2)=13

14.

(2y +3)(y-2)-(5y+3)(y-2)please answer my question...

Answer»
(2y + 3)(y - 2) - (5y + 3)(y - 2) \\  = (y - 2)(2y + 3 - (5y + 3)) \\  = (y - 2)(2y + 3 - 5y - 3) \\  = (y - 2)( - 3y) \\  =  - 3 {y}^{2}  + 6y
15.

Write the coordinates of the vertices of the geometrical figures and find its area.

Answer»

solution:

1. co-ordinate of square

A(2,-1), B(7,-1), C(7,-4) and D(2,-4)

Area = length * Breadth

Length = 5 units

Breadth = 3 units

Area = 5*3 = 15 unit²

----------------------

Coordinate of second ||gm

S(2,-2), P(1,-4), O(4,-4) and R(6,-2)

Area OG ||gm = BASE * Altitude

Base = 4 units

Altitude = 2 units

∴Area = 4*2 = 8units²

___________________

Amrit_______

16.

Find the cost of fencing a Square park of size 17meter @ rps27.5per meter

Answer»

Side of SQUARE park= 17m

its perimeter= 4*side = 4*17= 68m

rate of FENCING= $27.5/metre

thus, cost of fencing= $(68*27.5)

= $1870

plz mark it as BRAINLIEST

17.

Ab is parallel to DC find ar(dcx)

Answer»

Hey FRND....plzz post the COMPLETE QUESTION

18.

Find HCF of 112 , 140 ,178

Answer» 112 = 2x2x2x2x7
140 = 2x2x3x7
178= 2 X 89
HCF= 2x2x7 = 28
19.

A businessman visit Lucknow every fourth day and another Minion Businessman visit Lucknow every 10th day they both visit together on 3rd January which is the next day when they both will again visit Lucknow together

Answer»

They both will VISIT to LUCKNOW on 23january todether

20.

A man goes 5m in east and then in north direction. Find the distance from the starting point .give answer of this question

Answer»

He WII TRAVEL 10 METRE

21.

A train covers 15 km in 45 minutes ,find the speed of the train in metres per second

Answer»
45 \div 15 = 3

it will cover 3 kilometre PER minute
Now, CONVERTING it into seconds.
3  \div 60 = 0.05
it will cover 0.05km per SECOND.
If converted into metres,
0.05 \times 1000 = 50
it will cover 50M per second
22.

Two mathematicians are sitting opposite to each other for a cup of coffee they looked at the

Answer»

They will LOOK at the WAITER and other MATHEMATICIANS FACE

23.

Koushik read 65 pages in 5/2 hours. how many pages will he read in 4hours?

Answer»

5/2 hrs=65 PAGES
1 HR =65÷5/2
=26
4hrs =26×4
=104 pages

24.

⭐Sum of the first 10 terms is - 80 and that of next 10 terms is - 280.Find AP⭐❌NO SPAM ❌BEST ANSWER WILL BE MARKED AS BRAINLIEST ✔️

Answer» LET a is the first TERM and d is the common difference of AP
now use FORMULA,
Sn=n/2{2a+(n-1) d}

now
S10=10/2 {2a+(10-1) d}
-80=5 (2a+9d)
2a+9d =-16 ---------------(1)

again
S20-S10=-280

20/2 {2a+19d} +80=-280

10 (2a+19d)=-360

2a+19d=-36 -----------------(2)

solve both equation
d=-2
a=1

hence 1, -1,-3,-5 ........

hope helps you ❤️❤️❤️
25.

Anubhav purchased 5 kg 500g of sweets.He gave 4kg 375 g of sweets to his friends.How much sweets are left with him ?

Answer»

In this TYPE of questions, At first we convert it into simpler.
Sweets PURCHASED by Anubhav = 5KG 500 g = 5500 g
Sweets given to his friend = 4kg 375 g= 4375g

Sweets left with him = Sweets purchased- Sweets given
=> Sweets left = (5500-4375) g
=> Sweets left = 1125 g

Then we are required to convert it into kg.

=> Sweets left = 1125/1000 kg = 1.125 kg or 1 kg 125 g.


Be Brainly

26.

prove that the points (-7 -3) (5 10) (15 8)and(3 -5) taken in order are the vertices of parallelogram

Answer»

8) and (3, -5). Distance between (-7, -3), (5, 10) = √[(5 + 7)2 + (10 + 3)2] = √(144 + 169) = √313 Distance between (5, 10), (15, 8) = √[(15 - 5)2 + (8 - 10)2] = √(100 + 4) = √104 Distance between (15, 8), (3, -5) = √[(3 - 15)2 + (-5 - 8)2] = √(144 + 169) = √313 Distance between (3, -5), (-7, -3) = √[(-7 - 3)2 + (-3 + 5)2] = √(100 + 4) = √104Opposite sides of the quadrilateral FORMED by the given points are equal. So, the given points form a parallelogram.Diagonal of a parallelogram divides it into TWO congruent triangles. So, AREA of parallelogram = 2[Area of the triangle formed by (-7, -3), (5, 10) and (15, 8). = 2[1/2 |-7(10 - 8) + 5(8 + 3) + 15(-3 - 10)|] = |-7(2) + 5(11) + 15(-13)| = |-14 + 55 - 195| = |- 154| = 154 sq units.

27.

If r square + 1 by r square = 66, find the value of x cube minus 1 /x cube

Answer» 1 SQUARE-4side
R square -66×4=264x
28.

What is the probability of choosing a vowel from the word mathematics?

Answer»

It is 4/11.

TOTAL NUMBER of LETTERS= 11

Vowels= 4



29.

Two coins are tossed simultaneously.The probaility of getting exactly one tail is

Answer»

The PROBABILITY of GETTING a TAIL is 1/2

30.

Plz....solve the first part

Answer»

Your ANS is in the ATTACHMENT...

31.

Find the value of p & q.

Answer» PLEASE SEE the ATTACHMENT
32.

How many students appeare in fiitjee computer based AIITS test. Do anyone know

Answer»

IF YOU KNOW YOU CAN ANSWER IT BCOZ THIS NOT A QUESTION OF MATH

33.

⭐How many terms of the A. P 54,51,48......Should be taken so that their sum is 513?⭐CLASS 10 CHAPTER :ARITHMETIC PROGRESSIONSBEST ANSWER WILL BE MARKED AS BRAINLIEST!

Answer» \huge{\mathfrak{heya!!}}

◼️◼️◼️◼️◼️◼️◼️◼️◼️◼️◼️

Solution:-
>>>>>>>>>>>>>>>>>>>>>>>>>>

Given :- AP is 54,51,48....

SUM =513
here, a = 54, d = 51-54=-3

Let the NUMBER of terms be
n
Sum of n terms of AP =
\frac{n}{2} (2a + (n - 1)d)

sum of n terms of Ap = n/2 ( 2×54+(n-1) -3)

513 =n/2 ( 2×54+(n-1) -3)
..
513= n/2(108-3n+3)

2× 513=108n-3n^2+3n

1026=-3n^2+111n

3n^2-111n+1026=0

3n^2-57n-54n+1026=0

(3n-54)(n-19)=0

so, n = 19 or n=54/3=18.

THANKS
34.

Find out the square root of 6 by long division method?

Answer»

Here is your answer hope this helps PLZ FOLLOW me plz plz plz and mark me as BRAINLIEST

35.

Prove that sin squareA / 2 + sin square B / 2 + sin square C/2 = 1- r / 2R

Answer» DEAR Student,

Taking LHS:

=Sin^2 A/2+sin^2 B/2+sin^2 C/2

=1-cos^2 A/2 +sin^2 B/2+sin^2 C/2

=1-(cos(A+B)/2 cos(A-B)/2) + sin^2 C/2

= 1-(cos(pi-C)/2 cos(A-B)/2)+sin^2C/2

= 1+sin C/2(sin C/2 -cos(A-B)/2)

=1+sin C/2(sin(pi –(A+B)/2 -cos(A-B)/2)

=1+sin C/2(cos (A+B)/2-cos(A-B)/2)

=1+sin C/2(-2sinA/2 sinB/2) = 1-2sinA/2 sin B/2 sin C/2 =RHS [hence PROVED].

CHEERS!!

Regards,

VIKAS (B. Tech. 4th year
Thapar University)

36.

how to identify alternate angles interior angles and corresponding angle in paralleogram plz tell me in english and explain in a paper

Answer»

In parallelogram opposite sides are PARALLEL and hence we use this CONCEPT FIRST either it is parallel or not ,later by constructing diagonal we will get TWO triangles later we have to show them congruent and hence by congruent sides of congruent TRIANGLE (c.s.s.t) you cand identify them

37.

The price of an article is reduced by 20% . Find the original price of the article if the reduced price is rs 4000

Answer»

The ORIGINAL PRICE is 4800

38.

Observe the following tables and find which pair of variables are in onverse proporyion

Answer»

Where is table???? UR QUESTION is INCOMPLETE

39.

If one third of one fourth of a number is 15 then what is four tenths of the number

Answer»

I THINK that the NUMBER is 72.

40.

To go to the office afridi starts from his house by boarding bus he travels 4/5 th of the journey in the bus 1/8 of the journey by rickshaw and 3 km on foot what is the distance travelled by him

Answer»

Answer:


Step-by-step EXPLANATION:

i THINK this is incomplete QUESTION >>>>>>>>>              

41.

What is the hcf of 1168 and 1095

Answer»

hey FRIEND!

here's your answer:

H.C.F of 1168 is 73

H.C.F of 1095 is 73.

EXPLAINATION:

for first CASE H.C.F of 1168:    

1168=1095*1+73.             (by EUCLID's division lemma)

1095=73*15+0.

so Here, remainder is 0 THEREFORE H.C.F is 73.

for second case H.C.F of 1095:

1095=1022*1+73              (by Euclid's division lemma)

1022=73*14+0

so Here, remainder is 0 therefore H.C.F is 73.


i hope it will helps you friend

please mark my answer as brainlist

42.

⭐Sum of 3 numbers is 3 and the product is - 35.Find the numbers.⭐CLASS 10 CHAPTER :ARITHMETIC PROGRESSIONS❌NO SPAM ❌BEST ANSWER WILL BE MARKED AS BRAINLIEST ✔️

Answer» LET three numbers be a, a-d ,a+d
now
according to the question
a+a-d+a+d=3
=> a=1
also a(a-d)(a+d)=-35
a(a²-d²)=-35
putting a =1
1(1-d²)=-35
=> d=±6
putting a and d in very first step
so numbers are
1 , 7 , -5
43.

If point P (x,y) is equidistant from the point A( 5,1) and B ( -1,5) ,show that 3x=2y.

Answer»

Here is your PROOF ENJOY!!

44.

Find meanIt's answer is given below of questions.

Answer»

I HOPE it HELPS MATE

45.

Pls help me with this question.

Answer» HOPE IT WILL HELP U.
46.

X(x-y)(dy/dx)=y(x+y)

Answer»

X²-xy/(DY /DX)=xy+y²
x²-xy*dx/dy=xy+y²
x²-x²=xy+y²
y²+xy=0...

47.

Megha purchased 10 metres of curtain material. She stitched 3 curtains if lengths 2 1/4 meter , 1 1/2 meter , and 2 1/3 meter respectively. How much material was left unstitched?

Answer»

curtain purchased = 10 m

stitched = 2 1/4 + 1 1/2 + 2 1/3

             => 9/4 + 3/2 + 7/3

             => 73/12

           

CLOTH LEFT UNSTICHED = 10 - 73/12

                                            => [ 120 - 73 ]/12

                                            => 47/12 or 3 11/12 meter

48.

Answer the question plz???

Answer»

This is the ANSWER ....

49.

If 4/7 of a piece of metal weight 28kg.Find the weight of 8/9 of the same piece of metal?

Answer» LET the piece of metal be 'X'

4/ 7 of x = 28

4 × x / 7 = 28

4x = 196 => x = 49kg

thus, weight of metal x = 49kg

Find the 8/ 9 of the same piece of metal ,

8 /9 of x = 8 / 9 of 49

8 × 49/ 9 = 392 ÷ 9

= 43.56 kg

Answer:
--------------

8/9 of the same piece of metal

= 43 .56kg
50.

Obtain all Zero of the polynomialIf two of its zeroes are √2 and - √2

Answer» PRODUCT of zeros
=
\frac{ - d}{a}
let X be THIRD root
hence
\frac{ - d}{a}  = x \times  \sqrt{2} \times ( -  \sqrt{2}  )
\frac{ - 2}{2}  =  - 2x \\  - 1 =  - 2x \\ x =  \frac{1}{2}