332354 + Interview Questions in Secondary School in Math

1.	Given f: R+ → [-5,infinity] defined by f(x)=9x2 + 6x - 5.Then f^-1(3) +f^-1*(10) = ?
Answer» Answer: jduryduhhghhh hua so d do TULA YA ga ha gla THA us gla us SIS

1.

Given f: R+ → [-5,infinity] defined by f(x)=9x2 + 6x - 5.Then f^-1(3) +f^-1*(10) = ?

Answer»

Answer:

jduryduhhghhh hua so d do TULA YA ga ha gla THA us gla us SIS

Discussion

2.	Pls tell fast maths hsbsbsnsk
Answer» ANSWER: y=40° hop=110° lenear PAIR

2.

Pls tell fast maths hsbsbsnsk

Answer»

ANSWER:

y=40°

hop=110° lenear PAIR

Discussion

3.	If a vector is equal to two icap-jcap+kcap b vector is equal to icap+jcap-2kcapand c vector is equal to icap+3 jcap-kcap such that a vector is perpendicular to lambda×b vector +c vector then find lambda
Answer» What is the PROJECTION of two vectors? The vector projection is the vector produced when ONE vector is RESOLVED into two component vectors, one that is PARALLEL to the 2nd vector and one that is perpendicular to the 2nd vector. The parallel vector is the vector projection.

3.

If a vector is equal to two icap-jcap+kcap b vector is equal to icap+jcap-2kcapand c vector is equal to icap+3 jcap-kcap such that a vector is perpendicular to lambda×b vector +c vector then find lambda

Answer»

What is the PROJECTION of two vectors?

The vector projection is the vector produced when ONE vector is RESOLVED into two component vectors, one that is PARALLEL to the 2nd vector and one that is perpendicular to the 2nd vector. The parallel vector is the vector projection.

Discussion

4.	In what time will rs 7500 amount to rs 8625 if simple interest is reckoned at 15/2%
Answer» Step-by-step explanation: In what TIME will rs 7500 AMOUNT to rs 8625 if SIMPLE interest is reckoned at 15/2% ? , that QUES. ANSWER is 15 years 4 months.

4.

In what time will rs 7500 amount to rs 8625 if simple interest is reckoned at 15/2%

Answer»

Step-by-step explanation:

In what TIME will rs 7500 AMOUNT to rs 8625 if SIMPLE interest is reckoned at 15/2% ? , that QUES. ANSWER is 15 years 4 months.

Discussion

5.	Solve the following 123445+544-4421
Answer» ANSWER: ANS 225345 PLS MARK BRAINLEST

5.

Solve the following 123445+544-4421

Answer»

ANSWER:

ANS 225345

PLS MARK BRAINLEST

Discussion

6.	If x is equal to 1+root 2 then show that x-1/x whole cube is equal 8
Answer» Step-by-step explanation: HOPE it is help FUL to U. . . plzzz MARK as brainylist plzzz

6.

If x is equal to 1+root 2 then show that x-1/x whole cube is equal 8

Answer»

Step-by-step explanation:

HOPE it is help FUL to U. . .

plzzz MARK as brainylist plzzz

Discussion

7.	The coefficient of x2 in the expression (x+2)2 is
Answer» ANSWER: the COEFFICIENT of X2IS 1

7.

The coefficient of x2 in the expression (x+2)2 is

Answer»

ANSWER:

the COEFFICIENT of X2IS 1

Discussion

8.	0Graphically, the pair of equations6x - 3y + 10 = 0; 2x -y + 9 = 0 represents two lines which are
Answer» Answer: Parallel Step-by-step explanation: 6x - 3Y + 10 = 0 ==> y = 2X + 10/3 2x - y + 9 = 0 ==> y = 2x + 9 slope m is the same 2 and that mean lines are parallel.

8.

0Graphically, the pair of equations6x - 3y + 10 = 0; 2x -y + 9 = 0 represents two lines which are

Answer»

Answer:

Parallel

Step-by-step explanation:

6x - 3Y + 10 = 0 ==> y = 2X + 10/3

2x - y + 9 = 0 ==> y = 2x + 9

slope m is the same 2 and that mean lines are parallel.

Discussion

9.	Show that the square of any positive integers can not be of the form 6q+2 or 6q+5 for any integer q
Answer» Answer: where, m =(6q2 + 8q + 2) is an integer. where, m = (6q2 + 10q + 1) is an integer. Hence, the square of any positive integer cannot be of the form 6m + 2 or 6m + 5 for any integer m Step-by-step explanation: Let a be an arbitrary positive integer, then by Euclid’s division algorithm, corresponding to the positive integers a and 6, there exist non-negative integers q and r such that a = 6q + r, where 0< r< 6 a = 6q + r, where 0 ≤ r < 6 ⇒ a2 = (6q + r)2 = 36q2 + r2 + 12qr [∵(a+b)2 = a2 + 2ab + b2] ⇒ a2 = 6(6q2 + 2qr) + r2 ...(i) where,0 ≤ r < 6 Case I When r = 0, then putting r = 0 in Eq.(i), we get a2 = 6 (6q2) = 6m where, m = 6q2 is an integer. Case II When r = 1, then putting r = 1 in Eq.(i), we get a2 + 6 (6q2 + 2q) + 1 = 6m + 1 where, m = (6q2 + 2q) ais an integer. Case III When r = 2, then putting r = 2 in Eq(i), we get a2 = 6(6q2 + 4q) + 4 = 6m + 4 where, m = (6q2 + 4q) is an integer. Case IV When r = 3,then putting r = 3 in Eq.(i), we get a2 = 6(6q2 + 6q) + 9 = 6(6q2 + 6a) + 6 + 3 ⇒ a2 = 6(6q2 + 6q + 1) + 3 = 6m + 3 where, m = (6q + 6q + 1) is an integer. Case V when r = 4, then putting r = 4 in Eq.(i) we get a2 = 6(6q2 + 8q) + 16 = 6(6q2 + 8q) + 12 + 4 ⇒ a2 = 6(6q2 + 8q + 2) + 4 = 6m + 4 where, m =(6q2 + 8q + 2) is an integer. Case VI When r = 5, then putting r = 5 in Eq.(i), we get a2 = 6 (6q2 + 10q) + 25 = 6(6q2 + 10q) + 24 + 1 ⇒ a2 = 6(6q2 + 10q + 4) + 1 = 6m + 1 where, m = (6q2 + 10q + 1) is an integer. Hence, the square of any positive integer cannot be of the form 6m + 2 or 6m + 5 for any integer m. 0 votes answered Feb 8, 2018 by priya12 (-12,635 points) Let a be an arbitrary positive integer, then by Euclid’s division algorithm, corresponding to the positive integers a and 6, there exist non-negative integers q and r such that a = 6q + r, where 0< r< 6 Hence, the square of any positive integer cannot be of the form 6m + 2 or 6m + 5 for any integer m. Related questions +1 vote 3 answers Show that the square of any positive integer cannot be of the form 5q + 2 or 5q + 3 for any integer q. asked Feb 8, 2018 in Class X Maths by akansha Expert (2.2k points) real numbers 0 votes 1 answer Show that the cube of a positive integer of the form 6q + r,q is an integer and r = 0, 1, 2, 3, 4, 5 is also of the form 6m + r. asked Feb 9, 2018 in Class X Maths by priya12 (-12,635 points) real numbers 0 votes 2 answers Show that the square of any positive integer is EITHER of the form 4q or 4g + 1 for some integer q. asked Feb 8, 2018 in Class X Maths by akansha Expert (2.2k points) real numbers 0 votes 3 answers Write whether the square of any positive integer can be of the form 3m + 2, where m is a natural number. JUSTIFY your answer. asked Feb 8, 2018 in Class X Maths by aditya23 (-2,152 points) real numbers 0 votes 2 answers Show that cube of any positive integer is of the form 4m, 4m + 1 or Am + 3, for some integer m. asked Feb 8, 2018 in Class X Science by akansha Expert (2.2k points) real numbers 0 votes 1 answer Show that any positive integer is of the form 3 q , 3q+1, 3q+2 for some integer q. asked Mar 23, 2019 in Class X Maths by Sakshi Gupta (-254 points) real numbers 0 votes 2 answers use euclid's division lemma to show that the square of any positive intiger is either of the form 3m or 3m+1 for some integer m? asked Oct 31, 2017 in Class X Maths by aditya23 (-2,152 points) +1 vote 1 answer Show that one and only one out of n, n + 4 , n + 8, n + 12 and n + 16 is divisible by 5, where n is any positive integer. asked Feb 9, 2018 in Class X Maths by priya12 (-12,635 points) real numbers

9.

Show that the square of any positive integers can not be of the form 6q+2 or 6q+5 for any integer q

Answer»

Answer:

where, m =(6q2 + 8q + 2) is an integer. where, m = (6q2 + 10q + 1) is an integer. Hence, the square of any positive integer cannot be of the form 6m + 2 or 6m + 5 for any integer m

Step-by-step explanation:

Let a be an arbitrary positive integer, then by Euclid’s division algorithm, corresponding to the positive integers a and 6, there exist non-negative integers q and r such that a = 6q + r, where 0< r< 6

a = 6q + r, where 0 ≤ r < 6

⇒ a2 = (6q + r)2 = 36q2 + r2 + 12qr [∵(a+b)2 = a2 + 2ab + b2]

⇒ a2 = 6(6q2 + 2qr) + r2 ...(i)

where,0 ≤ r < 6

Case I When r = 0, then putting r = 0 in Eq.(i), we get

a2 = 6 (6q2) = 6m

where, m = 6q2 is an integer.

Case II When r = 1, then putting r = 1 in Eq.(i), we get

a2 + 6 (6q2 + 2q) + 1 = 6m + 1

where, m = (6q2 + 2q) ais an integer.

Case III When r = 2, then putting r = 2 in Eq(i), we get

a2 = 6(6q2 + 4q) + 4 = 6m + 4

where, m = (6q2 + 4q) is an integer.

Case IV When r = 3,then putting r = 3 in Eq.(i), we get

a2 = 6(6q2 + 6q) + 9

= 6(6q2 + 6a) + 6 + 3

⇒ a2 = 6(6q2 + 6q + 1) + 3 = 6m + 3

where, m = (6q + 6q + 1) is an integer.

Case V when r = 4, then putting r = 4 in Eq.(i) we get

a2 = 6(6q2 + 8q) + 16

= 6(6q2 + 8q) + 12 + 4

⇒ a2 = 6(6q2 + 8q + 2) + 4 = 6m + 4

where, m =(6q2 + 8q + 2) is an integer.

Case VI When r = 5, then putting r = 5 in Eq.(i), we get

a2 = 6 (6q2 + 10q) + 25

= 6(6q2 + 10q) + 24 + 1

⇒ a2 = 6(6q2 + 10q + 4) + 1 = 6m + 1

where, m = (6q2 + 10q + 1) is an integer.

Hence, the square of any positive integer cannot be of the form 6m + 2 or 6m + 5 for any integer m.

0

votes

answered Feb 8, 2018 by priya12 (-12,635 points)

Let a be an arbitrary positive integer, then by Euclid’s division algorithm, corresponding to the positive integers a and 6, there exist non-negative integers q and r such that a = 6q + r, where 0< r< 6

Hence, the square of any positive integer cannot be of the form 6m + 2 or 6m + 5 for any integer m.

10.	Devision of whole number____is not defined
Answer» ANSWER: DIVISION of WHOLE no. ZERO is not DEFINED

Devision of whole number____is not defined

Answer»

ANSWER:

DIVISION of WHOLE no. ZERO is not DEFINED

Discussion

11.	How to simplify7r +2s +3t +s+2t
Answer» Answer: 7r+3s+5t Step-by-step EXPLANATION: ADD all the the same "LETTERS" TOGETHER.

11.

How to simplify7r +2s +3t +s+2t

Answer»

Answer:

7r+3s+5t

Step-by-step EXPLANATION:

ADD all the the same "LETTERS" TOGETHER.

Discussion

12.	If 8sina - 2cosa =3 sina + 8 cos a find a
Answer» Step-by-step explanation: 8Sina-2Cosa=3Sina+8Cosa 8Sina-3Sina=8Cosa+2Cosa 5Sina=10Cosa Sina/Cosa=10/5 Tana=2 so a=2/tan a=2tan^-1 a=63.43 (APPROX.)

12.

If 8sina - 2cosa =3 sina + 8 cos a find a

Answer»

Step-by-step explanation:

8Sina-2Cosa=3Sina+8Cosa

8Sina-3Sina=8Cosa+2Cosa

5Sina=10Cosa

Sina/Cosa=10/5

Tana=2

so a=2/tan

a=2tan^-1

a=63.43 (APPROX.)

Discussion

13.	If x^2+1/4x^2=8, find x^3+1/8x^3
Answer» ANSWER: MARK me as the BRAINLIEST

13.

If x^2+1/4x^2=8, find x^3+1/8x^3

Answer»

ANSWER:

MARK me as the BRAINLIEST

Discussion

14.	Write down the expansion according to International system of numeration 230975634
Answer» 230975634 International form - There is a comma after 3 number places. 230975634 in international form WOULD be - 230,975,634 Pronunciation - Two hundred thirty - NINE million, nine hundred seventy - five thousand, SIX hundred thirty - four. Expanded form - 200,000,000+30,000,000+900,000+70,000+5,000+600+30+4 Hope this helps. PLS mark as brainliest answer.

14.

Write down the expansion according to International system of numeration 230975634

Answer»

230975634

International form - There is a comma after 3 number places.

230975634 in international form WOULD be - 230,975,634

Pronunciation -

Two hundred thirty - NINE million, nine hundred seventy - five thousand, SIX hundred thirty - four.

Expanded form - 200,000,000+30,000,000+900,000+70,000+5,000+600+30+4

Hope this helps. PLS mark as brainliest answer.

Discussion

15.	If √3 is the zero of the polynomial x²-k.Then find the value of x
Answer» Step-by-step EXPLANATION: IF √3 IS ROOT OF X^2 -K, THEN, ${x}^{2} - k = 0$ put the VALUE of x in this equation, (√3)*(√3) - k = 0 3-k = 0 k = 3

15.

If √3 is the zero of the polynomial x²-k.Then find the value of x

Answer»

Step-by-step EXPLANATION:

IF √3 IS ROOT OF X^2 -K, THEN,

${x}^{2} - k = 0$

put the VALUE of x in this equation,

(√3)*(√3) - k = 0

3-k = 0

k = 3

Discussion

16.	7. Anjana goes to school at 7:45 a.m. and comes back from school at 2:30 p.m.How long is she away from home?
Answer» Answer: she is away from HOME for 6 hours 45 MINUTES.......

16.

7. Anjana goes to school at 7:45 a.m. and comes back from school at 2:30 p.m.How long is she away from home?

Answer»

Answer:

she is away from HOME for 6 hours 45 MINUTES.......

Discussion

17.	Pls give correct answers. needed Urgently
Answer» Step-by-step EXPLANATION: U can ADD me BRAINLIEST

17.

Pls give correct answers. needed Urgently

Answer»

Step-by-step EXPLANATION:

U can ADD me BRAINLIEST

Discussion

18.	Divide 182 in 3 parts in the ratio 1/10: 1/15 :1/201/10 1/15 1/20 are fractionsthe ones are numerater
Answer» 55577882678844480002256

Discussion

19.	What is the smallest number that should be subtracted from 8317 to makeit divisible by 18 ?
Answer» Step-by-step EXPLANATION: we have to SUBSTRACT 8317 - 8298 = 19 after that the number which is DIVISIBLE by 18 is 8298 = 461

19.

What is the smallest number that should be subtracted from 8317 to makeit divisible by 18 ?

Answer»

Step-by-step EXPLANATION:

we have to SUBSTRACT 8317 - 8298 = 19

after that the number which is DIVISIBLE by 18 is 8298 = 461

Discussion

20.	Y=3–root8 then (y—1/y)2
Answer» ANSWER: SORRY dear Step-by-step EXPLANATION: please follow me please mark as brainlist

20.

Y=3–root8 then (y—1/y)2

Answer»

ANSWER:

SORRY dear

Step-by-step EXPLANATION:

please follow me

please mark as

brainlist

Discussion

21.	In a class consisting of 100 students, 20 know English and 20 do not know Hindi and 10 knowneither English nor Hindi. The number of students knowing both Hindi and English A) 5B) 10C) 15D) 20
Answer» Answer: the answer will be 10 Step-by-step EXPLANATION: E=20 noE=80 noH=20 both no=10 the number of student don't KNOWING both ENGLISH and Hindi=80+20-10=90 number of student in both English and Hindi=100-90=10 please FOLLOW me and mark as brainliest plz plz

21.

In a class consisting of 100 students, 20 know English and 20 do not know Hindi and 10 knowneither English nor Hindi. The number of students knowing both Hindi and English A) 5B) 10C) 15D) 20

Answer»

Answer:

the answer will be 10

Step-by-step EXPLANATION:

E=20

noE=80

noH=20

both no=10

the number of student don't KNOWING both ENGLISH and Hindi=80+20-10=90

number of student in both English and Hindi=100-90=10

please FOLLOW me and mark as brainliest plz plz

Discussion

22.	write the name of 8 objects / shape which are quadrilateral in shape . write the type of quadrilateral.
Answer» The TOTAL of its interior angles = 360 degrees. A quadrilateral with four equal sides and four right angles is a square. A quadrilateral that has OPPOSITE sides equal and measure of EVERY angle is 90 degrees is a rectangle. PARALLELOGRAM, trapezium, rhombus, and kite are other examples of quadrilaterals.

22.

write the name of 8 objects / shape which are quadrilateral in shape . write the type of quadrilateral.

Answer»

The TOTAL of its interior angles = 360 degrees. A quadrilateral with four equal sides and four right angles is a square. A quadrilateral that has OPPOSITE sides equal and measure of EVERY angle is 90 degrees is a rectangle. PARALLELOGRAM, trapezium, rhombus, and kite are other examples of quadrilaterals.

Discussion

23.	Which tranversals can be drawn for two parallel line
Answer» $\huge\underline\frak{\fbox{<klux>ANSWER</klux>:-}}$ Here is ur answer mate ⏬⏬⏬⏬⏬⏬⏬⏬⏬ Transversal in geometry, a transversalis a line that passes through two linesin the same plane at twodistinctpoints. Transversals play a role in establishing whether two other linesin the Euclidean plane are PARALLEL. Infinite transversal can be drawn for two distinct lines . ⏫⏫⏫⏫⏫⏫⏫⏫⏫ ↫↫↫↫↫ Hope it helps you Plz mark me BRAINLIST ↬↬↬↬↬

23.

Which tranversals can be drawn for two parallel line

Answer»

$\huge\underline\frak{\fbox{<klux>ANSWER</klux>:-}}$

Here is ur answer mate

⏬⏬⏬⏬⏬⏬⏬⏬⏬

Transversal in geometry, a transversalis a line that passes through two linesin the same plane at twodistinctpoints. Transversals play a role in establishing whether two other linesin the Euclidean plane are PARALLEL. Infinite transversal can be drawn for two distinct lines .

⏫⏫⏫⏫⏫⏫⏫⏫⏫

↫↫↫↫↫ Hope it helps you

Plz mark me BRAINLIST ↬↬↬↬↬

Discussion

24.	[3^3-(1/2)^3×1/19.
Answer» ANSWER: Step-by-step explanation: 27 - 1/8 X 1/9 27 - 1/72 (1944 - 1)/72 26.98

24.

[3^3-(1/2)^3×1/19.

Answer»

ANSWER:

Step-by-step explanation:

27 - 1/8 X 1/9

27 - 1/72

(1944 - 1)/72

26.98

Discussion

25.	69. Find the coordinates of the centre of a circle passing through the points A (2, 1), B (5,-8) and C (2,-9). Also find the radius of the circle.
Answer» Step-by-step EXPLANATION: ...........................####¥¥¥

25.

69. Find the coordinates of the centre of a circle passing through the points A (2, 1), B (5,-8) and C (2,-9). Also find the radius of the circle.

Answer»

Step-by-step EXPLANATION:

...........................####¥¥¥

Discussion

26.	Two vehicles are sold for Rs.1897each. One is sold at a profit of 30%and another at a loss of 30%. What isthe net profit/loss%?
Answer» Given: ONE vehicle is sold at a profit of 30% and another at a LOSS of 30%. To find: The net profit or loss % Solution: The selling price of each vehicle is ₹1897 So the ratio of the selling price in both the cases must be the same. On First vehicle there is a profit of 30% which is 3/10 and on the second article there is a loss of 30% which is again 3/10 So, CP₁ = 10 CP₂ = 10 P₁ = 3 L₂ = 3 SP₁ = 10+3 = 13 SP₂ = 10-3 = 7 But ACCORDING to the question the Selling price of both the ITEMS must be the same. CP₁ = 70 CP₂ = 130 P₁ = 21 L₂ = -39 SP₁ = 91 SP₂ = 91 so, There will be the net loss which is Loss = -39 + 21 = -18 Total Cost price of the both vehicle is: CP = 130+70 = 200 Loss% = Loss×100/CP Loss% = 18×100/200 Loss% = 9% There will be net loss of 9%.

26.

Two vehicles are sold for Rs.1897each. One is sold at a profit of 30%and another at a loss of 30%. What isthe net profit/loss%?

Answer»

Given:

ONE vehicle is sold at a profit of 30% and another at a LOSS of 30%.

To find:

The net profit or loss %

Solution:

The selling price of each vehicle is ₹1897

So the ratio of the selling price in both the cases must be the same.

On First vehicle there is a profit of 30% which is 3/10 and on the second article there is a loss of 30% which is again 3/10

So,

CP₁ = 10 CP₂ = 10

P₁ = 3 L₂ = 3

SP₁ = 10+3 = 13 SP₂ = 10-3 = 7

But ACCORDING to the question the Selling price of both the ITEMS must be the same.

CP₁ = 70 CP₂ = 130

P₁ = 21 L₂ = -39

SP₁ = 91 SP₂ = 91

so,

There will be the net loss which is

Loss = -39 + 21 = -18

Total Cost price of the both vehicle is:

CP = 130+70 = 200

Loss% = Loss×100/CP
Loss% = 18×100/200
Loss% = 9%

There will be net loss of 9%.

Discussion

27.	Degree of polynomial 3 x(x+2) is
Answer» *ANSWER:- FIRST* simplify the QUESTION. 3x(x + 2) = 3x² + 6x The degree of the polynomial is the highest POWER of an expression. 3x² has a degree 2 *Thus, 2 is the* *degree* of *the* *polynomial*.

27.

Degree of polynomial 3 x(x+2) is

Answer»

ANSWER:-

FIRST simplify the QUESTION.

3x(x + 2) = 3x² + 6x

The degree of the polynomial is the highest POWER of an expression.

3x² has a degree 2

Thus, 2 is the degree of the polynomial.

Discussion

28.	Write down the numerical as well as literal coefficients of each of the following : -2p³q²
Answer» ANSWER: Step-by-step EXPLANATION: kdxshsbghfbchjdncijfcnjkdmksncndimsi wnqkjnjknjidnjuwjdjcnjcnjncjcnjcnjcnjcnjcnj

28.

Write down the numerical as well as literal coefficients of each of the following : -2p³q²

Answer»

ANSWER:

Step-by-step EXPLANATION:

kdxshsbghfbchjdncijfcnjkdmksncndimsi

wnqkjnjknjidnjuwjdjcnjcnjncjcnjcnjcnjcnjcnj

Discussion

29.	If P ={a,b, c}and Q={r}from sets pqand qp are these two products equal
Answer» Answer: No PQ= {(AR),(br),(CR)} qp={(ra),(TB),(rc} Mark as brainlist

29.

If P ={a,b, c}and Q={r}from sets pqand qp are these two products equal

Answer»

Answer:

No

P*Q= {(AR),(br),(CR)}

q*p={(ra),(TB),(rc}

Mark as brainlist

Discussion

30.	Simplify plz tell me quickly
Answer» ANSWER: k³+16 i HOPE it will HELP u☺☺

30.

Simplify plz tell me quickly

Answer»

ANSWER:

k³+16

i HOPE it will HELP u☺☺

Discussion

31.	Solve derivativesfind dy/dx
Answer» ANSWER: ${\green{\underline{\underline{\huge{\mathfrak\orange{your\:answer\:attached\:in\:the\:photo}}}}}}$ OPTION (D)

31.

Solve derivativesfind dy/dx

Answer»

ANSWER:

${\green{\underline{\underline{\huge{\mathfrak\orange{your\:answer\:attached\:in\:the\:photo}}}}}}$

OPTION (D)

Discussion

32.	22. The point (-3,5) lies in the *1 pointO first quadrantO fourth quadrantO third quadrantO second quadrant
Answer» ANSWER: this POINT (-3,5) LIES in the SECOND QUADRANT

32.

22. The point (-3,5) lies in the *1 pointO first quadrantO fourth quadrantO third quadrantO second quadrant

Answer»

ANSWER:

this POINT (-3,5) LIES in the SECOND QUADRANT

Discussion

33.	어The interval in which f(n) =2x² - 9x² - 60x + 8p isstrictly decreasing is
Answer» <P>ANSWER: p belongs to (-infinity , -1) Step-by-step EXPLANATION:

33.

어The interval in which f(n) =2x² - 9x² - 60x + 8p isstrictly decreasing is

Answer»

<P>ANSWER:

p belongs to (-infinity , -1)

Step-by-step EXPLANATION:

Discussion

34.	If cos(teeta-alpha ),costeeta ,cos (teeta + alpha ) are in hp then cos theeeta -sec alpha /2=?
Answer» Step-by-step EXPLANATION: If THREE numbers are in H.P., then, As, are in H.P.,

34.

If cos(teeta-alpha ),costeeta ,cos (teeta + alpha ) are in hp then cos theeeta -sec alpha /2=?

Answer»

Step-by-step EXPLANATION:

If THREE numbers

are in H.P., then,

As,

are in H.P.,

Discussion

35.	Prove that:-(cosA÷cosec+1) +(cosA÷cosecA - 1) = 2 tanA
Answer» HOPE this HELPS you.. HIT the CROWN for me PLS..

35.

Prove that:-(cosA÷cosec+1) +(cosA÷cosecA - 1) = 2 tanA

Answer»

HOPE this HELPS you..

HIT the CROWN for me PLS..

Discussion

36.	③ which term of the ap -5,-9,-13,-7....is-141?
Answer» Answer: *see the ATTACHED FILE.....* *hope it HELPS you....* *plz MARK it as BRAINLIEST...*.

36.

③ which term of the ap -5,-9,-13,-7....is-141?

Answer»

Answer:

see the ATTACHED FILE.....

hope it HELPS you....

plz MARK it as BRAINLIEST....

Discussion

37.	a chess board contains 64 equal squares and the area of a square is 6.25 CM square .A border around the board is 2 cm .find the length of the side of the chess board
Answer» ANSWER: Step-by-step EXPLANATION:

37.

a chess board contains 64 equal squares and the area of a square is 6.25 CM square .A border around the board is 2 cm .find the length of the side of the chess board

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

38.	Factorise 1-2a-3a² find the ans
Answer» ANSWER: -(3a²+2a-1) = - (3a²+3A-a-1) = -3a(a+1)-1(a+1) = -(3a+1)(a+1) Step-by-step EXPLANATION:

38.

Factorise 1-2a-3a² find the ans

Answer»

ANSWER:

-(3a²+2a-1)

= - (3a²+3A-a-1)

= -3a(a+1)-1(a+1)

= -(3a+1)(a+1)

Step-by-step EXPLANATION:

Discussion

39.	What is 2 1/3 x 3 1/3
Answer» Step-by-step explanation: FIRST first we have to FIND out the LCM of the denominators denominators are same so there LCM is also same which is 3 so it is SIMPLE we have to multiply 21 by 31

39.

What is 2 1/3 x 3 1/3

Answer»

Step-by-step explanation:

FIRST first we have to FIND out the LCM of the denominators denominators are same so there LCM is also same which is 3

so it is SIMPLE we have to multiply 21 by 31

Discussion

40.	The middle term of AP 6,13,20 ..... 216 is
Answer» $\sf\large\underline{Given:}$ $\rm{The\: first\: term (a)=6}$ $\rm{The\:last\: term (Tn)=216}$ $\rm{The\: common\: difference=7}$ $\sf\large\underline{To\: <klux>FIND</klux>:}$ $\rm{The\: <klux>MIDDLE</klux>\: term\:of\:AP=?}$ $\sf\large\underline{Solution:}$ [At 1st calculate the number n term than calculate median (means the middle term of AP)] $\sf\large\underline{Formula\: used:}$ $\rm\purple{\implies T_{n}=a+(n-1)d}$ $\sf\large\underline{A.T.Q:}$ $\rm{\implies 216=6+(n-1)7}$ $\rm{\implies 216-6=(n-1)7}$ $\rm{\implies 210=(n-1)7}$ $\rm{\implies 30=n-1}$ $\rm{\implies n=30+1}$ $\rm\red{\implies n=31}$ [Now, CALCULATE middle term here] Total number of n term=31 $\rm{\implies M=(\dfrac{n+1}{2})th}$ $\rm{\implies M=(\dfrac{31+1}{2})th}$ $\rm{\implies M=(\dfrac{32}{2})th}$ $\rm{\implies M=16th}$ {Than find out T_16 here} $\rm{\implies T_{16}=6+(16-1)7}$ $\rm{\implies T_{16}=6+105}$ $\rm{\implies T_{16}=111}$ Hence, $\rm\red{\implies The\: middle\:term=111}$

40.

The middle term of AP 6,13,20 ..... 216 is

Answer»

$\sf\large\underline{Given:}$

$\rm{The\: first\: term (a)=6}$
$\rm{The\:last\: term (Tn)=216}$
$\rm{The\: common\: difference=7}$

$\sf\large\underline{To\: <klux>FIND</klux>:}$

$\rm{The\: <klux>MIDDLE</klux>\: term\:of\:AP=?}$

$\sf\large\underline{Solution:}$

[At 1st calculate the number n term than calculate median (means the middle term of AP)]

$\sf\large\underline{Formula\: used:}$

$\rm\purple{\implies T_{n}=a+(n-1)d}$

$\sf\large\underline{A.T.Q:}$

$\rm{\implies 216=6+(n-1)7}$

$\rm{\implies 216-6=(n-1)7}$

$\rm{\implies 210=(n-1)7}$

$\rm{\implies 30=n-1}$

$\rm{\implies n=30+1}$

$\rm\red{\implies n=31}$

[Now, CALCULATE middle term here]
Total number of n term=31

$\rm{\implies M=(\dfrac{n+1}{2})th}$

$\rm{\implies M=(\dfrac{31+1}{2})th}$

$\rm{\implies M=(\dfrac{32}{2})th}$

$\rm{\implies M=16th}$

{Than find out T_16 here}

$\rm{\implies T_{16}=6+(16-1)7}$

$\rm{\implies T_{16}=6+105}$

$\rm{\implies T_{16}=111}$

Hence,

$\rm\red{\implies The\: middle\:term=111}$

Discussion

41.	Convert into mixed numbers: a) 119/9 b) 961/13
Answer» Step-by-step explanation: MARK me as the BRAINLIEST. And in the first question 119 is divided by 9 so the quotient is 13 remainder is 2, the second question's explanation is SIMILAR to first.

41.

Convert into mixed numbers: a) 119/9 b) 961/13

Answer»

Step-by-step explanation:

MARK me as the BRAINLIEST.

And in the first question 119 is divided by 9 so the quotient is 13 remainder is 2, the second question's explanation is SIMILAR to first.

Discussion

42.	find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively. (I) 5,8 (II) 1/5-18
Answer» Step-by-step EXPLANATION: i ANSWERED only FIRST bit 2nd Q is UNCLEAR

42.

find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively. (I) 5,8 (II) 1/5-18

Answer»

Step-by-step EXPLANATION:

i ANSWERED only FIRST bit

2nd Q is UNCLEAR

Discussion

43.	_ is 90 =45_ is 200= 50
Answer» 1/2 1/4 I HOPE this HELPS you and PLEASE MARK me the BRAINLIAST.

43.

_ is 90 =45_ is 200= 50

Answer»

1/2

1/4

I HOPE this HELPS you and PLEASE MARK me the BRAINLIAST.

Discussion

44.	Can anyone plz help me with this question.... no spam
Answer» According to exponent laws A × A = A^2 therefore y^4 × y = y^5 = y^5/y^-2 according to exponent laws a/a = a^1-1 = a^0 = 1 therefore y^5/y^-2 = y^5-(-2) = y^5+2 = simplest FORM is y^7 $...$

44.

Can anyone plz help me with this question.... no spam

Answer»

According to exponent laws

A × A = A^2

therefore y^4 × y = y^5

= y^5/y^-2

according to exponent laws

a/a = a^1-1 = a^0 = 1

therefore y^5/y^-2 = y^5-(-2) = y^5+2

= simplest FORM is y^7

$...$

Discussion

45.	Can. anyone solve please
Answer» Answer: 5m+5-1=0after SOLVING

45.

Can. anyone solve please

Answer»

Answer:

5m+5-1=0after SOLVING

Discussion

46.	Number of prime number between 1 to 100 what are they
Answer» Answer: there are 25 prime NUMBER between 1 to 100. They are :- 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97. Step-by-step explanation: hope this help you. *mark* me as *brainliest.*..

46.

Number of prime number between 1 to 100 what are they

Answer»

Answer:

there are 25 prime NUMBER between 1 to 100. They are :-

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.

Step-by-step explanation:

hope this help you.

mark me as brainliest...

Discussion

47.	F:[0,∞)->R by f(x)=x/x+1 is it(i)one one (ii)onto (iii)both (i) and (ii)(iv)not one one or onto(explain pls)
Answer» ANSWER: LET me KNOW if it is write Step-by-step EXPLANATION:

47.

F:[0,∞)->R by f(x)=x/x+1 is it(i)one one (ii)onto (iii)both (i) and (ii)(iv)not one one or onto(explain pls)

Answer»

ANSWER:

LET me KNOW if it is write

Step-by-step EXPLANATION:

Discussion

48.	Simplify of 32-(18+14) -7
Answer» $\huge\boxed{\fcolorbox{white}{pink}{answer}}$ Here is ur answer mate ⏬⏬⏬⏬⏬⏬⏬⏬⏬ $32 - (18 + 14) - 7 \\ 32 - (32) - 7 \\ 32 - 32 - 7 \\ - 7$ ⏫⏫⏫⏫⏫⏫⏫⏫⏫ ↫↫↫↫↫ Hope it HELPS you Plz mark me BRAINLIST ↬↬↬↬↬

48.

Simplify of 32-(18+14) -7

Answer»

$\huge\boxed{\fcolorbox{white}{pink}{answer}}$

Here is ur answer mate

⏬⏬⏬⏬⏬⏬⏬⏬⏬

$32 - (18 + 14) - 7 \\ 32 - (32) - 7 \\ 32 - 32 - 7 \\ - 7$

⏫⏫⏫⏫⏫⏫⏫⏫⏫

↫↫↫↫↫ Hope it HELPS you

Plz mark me BRAINLIST ↬↬↬↬↬

Discussion

49.	Area of shaded portion is
Answer» Step-by-step explanation: GIVEN - Figure To Find - Area of the shaded region Now, As we see :- PQRS is a rectangle Then, Area of rectangle PQRS = l × b → Area = 4×3 → 12 And As we see :- RTUV and STWX is a square Then, Area of square RTUV = (side)² → Area = (2)² → 4 And Area of square STWX = (1)² → 1 And As we see :- PVZ is a right angle triangle → Area of ΔPVZ = 1/2 × base × height → 1/2 × 2 × 2 → 2 Now, Area of shaded region = Area of rectangle PQRS - Area of Δ PVZ - Area of square RTUV - Area of square STWX → 12 - 2 - 4 - 1 → 12 - 7 → 5 Hence, The area of shaded region is 5. Note - Figure in the attachment NOT TO SCALE

49.

Area of shaded portion is

Answer»

Step-by-step explanation:

GIVEN -

Figure

To Find -

Area of the shaded region

Now,

As we see :-

PQRS is a rectangle

Then,

Area of rectangle PQRS = l × b

→ Area = 4×3

→ 12

And

As we see :-

RTUV and STWX is a square

Then,

Area of square RTUV = (side)²

→ Area = (2)²

→ 4

And

Area of square STWX = (1)²

→ 1

And

As we see :-

PVZ is a right angle triangle

→ Area of ΔPVZ = 1/2 × base × height

→ 1/2 × 2 × 2

→ 2

Now,

Area of shaded region = Area of rectangle PQRS - Area of Δ PVZ - Area of square RTUV - Area of square STWX

→ 12 - 2 - 4 - 1

→ 12 - 7

→ 5

Hence,

The area of shaded region is 5.

Note -

Figure in the attachment

NOT TO SCALE

Discussion

50.	Estimate each of the following products by rounding off the first number downwardsand the second number upwards:19. 356 x 27820. 472 x 7621. 578 x 369
Answer» Answer: As we have to take products of ROUND off of the FIRST and second upwards so 19. 356 x 278= 350 x 280= 98000 20. 472 x 76= 470 x 80= 37600 21. 578 x 369= 570 x 370=210900 Step-by-step explanation: Hope this answer would help you... Please mark it as BRAINLIEST answer.

50.

Estimate each of the following products by rounding off the first number downwardsand the second number upwards:19. 356 x 27820. 472 x 7621. 578 x 369

Answer»

Answer:

As we have to take products of ROUND off of the FIRST and second upwards so 19. 356 x 278= 350 x 280= 98000

20. 472 x 76= 470 x 80= 37600

21. 578 x 369= 570 x 370=210900

Step-by-step explanation:

Hope this answer would help you... Please mark it as BRAINLIEST answer.

Discussion

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⏬⏬⏬⏬⏬⏬⏬⏬⏬

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