332354 + Interview Questions in Secondary School in Math

1.	The ratio of two numbers is 3:4and their H.C.F is 4. Their L.C.M is
Answer» Step-by-step EXPLANATION: HOPE its HELP you ......

1.

The ratio of two numbers is 3:4and their H.C.F is 4. Their L.C.M is

Answer»

Step-by-step EXPLANATION:

HOPE its HELP you ......

Discussion

2.	A class has 30 girls more than boys one day one boy is absent the number of years was twice as that of boys find the number of boys and girls
Answer» Answer: According to first CONDITION: number of BOYS and number of girls in a class are the same. So suppose no. of boys and girls be X & X, therefore total STUDENT will be 2X. According to second condition: On a day when only ten boys were absent, the number of the girls was twice the number of the boys. So, Boys =X-10 & Girl = 2(X-10) 2(X-10) = X 2X-20=X 2X-X=20 X=20 no. Of boy =no. Of girl=20 So total length class = 20+20=40 student But according to second condition 10 boys were absent. So total length of class on that day = 40–10=30 student Finally answer : 30 student present in class Step-by-step explanation: PLZ MARK AS BRANLIEST AND FOLLOW ME PLZ

2.

A class has 30 girls more than boys one day one boy is absent the number of years was twice as that of boys find the number of boys and girls

Answer»

Answer:

According to first CONDITION:

number of BOYS and number of girls in a class are the same.

So suppose no. of boys and girls be X & X, therefore total STUDENT will be 2X.

According to second condition:

On a day when only ten boys were absent, the number of the girls was twice the number of the boys.

So, Boys =X-10 & Girl = 2(X-10)

2(X-10) = X

2X-20=X

2X-X=20

X=20

no. Of boy =no. Of girl=20

So total length class = 20+20=40 student

But according to second condition 10 boys were absent. So total length of class on that day = 40–10=30 student

Finally answer : 30 student present in class

Step-by-step explanation:

PLZ MARK AS BRANLIEST AND FOLLOW ME PLZ

Discussion

3.	178,75 paise = _______ rupees ______ paise
Answer» 178 RUPEES and 75 PAISE

Discussion

4.	8,000 is lent at 5% compound interest per year for 2 years. Find the amount
Answer» ANSWER Principal for the first year = Rs.8000, Rate = 5% PER annum, T = 1 year Interest for the first year = = 100 P×R×T =Rs.[ 100 8000×5×1 ]=Rs.400 ∴ Amount at the end of the first year = Rs. (8000 + 400) = Rs. 8400 Now principal for the second year = Rs.8400 Interest for the second year = 100 P×R×T =Rs.[ 100 8400×5×1 ]=Rs.420 ∴ Amount at the end of the second year = Rs. (8400 + 420) =Rs.8820 Interest for the third year = 100 P×R×T =Rs. 100 8820×5×1 =Rs.441 ∴ Amount at the end of the third year = Rs.(8820 + 441) = Rs. 9261 Now we KNOW that TOTAL C.I. = Amount - Principal = Rs. (9261 - 8000) = Rs. 1261 we can also find the C.I. as follows Total C.I. = Interest for the first year + Interest for the second year + Interest for third year = Rs. (400 + 420 + 441) = Rs.1261

4.

8,000 is lent at 5% compound interest per year for 2 years. Find the amount

Answer»

ANSWER

Principal for the first year = Rs.8000, Rate = 5% PER annum, T = 1 year

Interest for the first year = =

100

P×R×T

=Rs.[

100

8000×5×1

]=Rs.400

∴ Amount at the end of the first year = Rs. (8000 + 400) = Rs. 8400

Now principal for the second year = Rs.8400

Interest for the second year =

100

P×R×T

=Rs.[

100

8400×5×1

]=Rs.420

∴ Amount at the end of the second year = Rs. (8400 + 420) =Rs.8820

Interest for the third year =

100

P×R×T

=Rs.

100

8820×5×1

=Rs.441

∴ Amount at the end of the third year = Rs.(8820 + 441) = Rs. 9261

Now we KNOW that TOTAL C.I. = Amount - Principal = Rs. (9261 - 8000) = Rs. 1261

we can also find the C.I. as follows

Total C.I. = Interest for the first year + Interest for the second year + Interest for third year = Rs. (400 + 420 + 441) = Rs.1261

Discussion

5.	Find the difference between 0.9 - 0.1 =
Answer» Answer: 0.8 Step-by-step explanation: 0.8 I HOPE it HELP's you It doesn't have any EXPLAINATION

5.

Find the difference between 0.9 - 0.1 =

Answer»

Answer:

0.8

Step-by-step explanation:

0.8

I HOPE it HELP's you

It doesn't have any EXPLAINATION

Discussion

6.	Who is Pythagoras?The use of the Pythagoras Theorem?Disscus the field that involve.What is Hypotenuse? Explain the converse of Pythagoras Theoram
Answer» Answer: Pythagoras theorem IAS sum of two numbers = THIRD NUMBER . Step-by-step explanation: suppose, a^2+b^2 = c^2 .

6.

Who is Pythagoras?The use of the Pythagoras Theorem?Disscus the field that involve.What is Hypotenuse? Explain the converse of Pythagoras Theoram

Answer»

Answer:

Pythagoras theorem IAS sum of two numbers = THIRD NUMBER .

Step-by-step explanation:

suppose, a^2+b^2 = c^2 .

Discussion

7.	What is the value of 2xcube
Answer» Answer: 8x³ Step-by-step EXPLANATION: (2X)³=2³x³=8x³ ANSWER 8x³

7.

What is the value of 2xcube

Answer»

Answer:

8x³

Step-by-step EXPLANATION:

(2X)³=2³x³=8x³

ANSWER 8x³

Discussion

8.	If u have 42 balls you need to keep in 7 box all but all number need in even in all seven boxes
Answer» Answer: 6 BALL in each BOX ........

8.

If u have 42 balls you need to keep in 7 box all but all number need in even in all seven boxes

Answer»

Answer:

6 BALL in each BOX

........

Discussion

9.	Find ratio of 5 rupees to 50 paisa
Answer» ANSWER: we will convert both numbers to same UNIT Rs 5 = 5 ×100 = 500 Rs 5 to 50 PAISE Ratio = Rs 5 / 50 paise = 500 paise / 50 paise = 10 / 1 = 10 :1 ans hope it will HELP you

9.

Find ratio of 5 rupees to 50 paisa

Answer»

ANSWER:

we will convert both numbers to same UNIT

Rs 5 = 5 ×100

= 500

Rs 5 to 50 PAISE

Ratio = Rs 5 / 50 paise

= 500 paise / 50 paise

= 10 / 1

= 10 :1 ans

hope it will HELP you

Discussion

10.	If a transversal intersects two parallel lines such that the ratio between interior angles is 2:7, then what is the measure of greater angle? *
Answer» PLEASE MARK me as BRAINLIEST

10.

If a transversal intersects two parallel lines such that the ratio between interior angles is 2:7, then what is the measure of greater angle? *

Answer»

PLEASE MARK me as BRAINLIEST

Discussion

11.	WHAT IS THE FACTOR OF 99999999999
Answer» Step-by-step explanation: The orange divisor(s) above are the PRIME factors of the number 999,999,999. If we PUT all of it together we have the factors 3 x 3 x 3 x 3 x 37 x 333,667 = 999,999,999. It can also be written in exponential form as 34 x 371 x 333,6671. HOPE YOU GET YOUR ANSWER✌

11.

WHAT IS THE FACTOR OF 99999999999

Answer»

Step-by-step explanation:

The orange divisor(s) above are the PRIME factors of the number 999,999,999. If we PUT all of it together we have the factors 3 x 3 x 3 x 3 x 37 x 333,667 = 999,999,999. It can also be written in exponential form as 34 x 371 x 333,6671.

HOPE YOU GET YOUR ANSWER✌

Discussion

12.	If an angle of a parallelogram is two - third of its adjacent angle , then the smallest angle of the parallelogram is .......... . *1 point
Answer» Answer: In a parallelogram ABCD, Let ∠A be x and ∠B be 2X / 3 ∴ ∠A + ∠B = 180° ⇒ x + 2x / 3 = 180° ⇒ 5X / 3 = 180° ⇒ x° = 180° × 3 / 5 = 108° ∠A = 108° , ∠B = 2 / 3 × 108° = 72°

12.

If an angle of a parallelogram is two - third of its adjacent angle , then the smallest angle of the parallelogram is .......... . *1 point

Answer»

Answer:

In a parallelogram ABCD,

Let ∠A be x and ∠B be 2X / 3

∴ ∠A + ∠B = 180°

⇒ x + 2x / 3 = 180°

⇒ 5X / 3 = 180°

⇒ x° = 180° × 3 / 5 = 108°

∠A = 108° , ∠B = 2 / 3 × 108° = 72°

Discussion

13.	Find the amount if p=8000,i=Rs=200
Answer» ANSWER: What??? ADD or SUBTRACT or vice versa?? Step-by-step explanation:

13.

Find the amount if p=8000,i=Rs=200

Answer»

ANSWER:

What??? ADD or SUBTRACT or vice versa??

Step-by-step explanation:

Discussion

14.	For thequadraticequatian 6x²= 7x-1find the value of a,b and c
Answer» Answer: TUMHARE BAS kee bat NAHI

14.

For thequadraticequatian 6x²= 7x-1find the value of a,b and c

Answer»

Answer:

TUMHARE BAS kee bat NAHI

Discussion

15.	(c) The sum of 15 terms of an AP is zero and its S ^ (th) term is 12. Find its 12 ^ (th) term
Answer» HOPE the above attached PICTURE will help you to ANSWER the QUESTION THANK you

15.

(c) The sum of 15 terms of an AP is zero and its S ^ (th) term is 12. Find its 12 ^ (th) term

Answer»

HOPE the above attached PICTURE will help you to ANSWER the QUESTION

THANK you

Discussion

16.	What happens at the synapse between two neurons ? ਦੋ ਨਿਊਰੋਨ ਵਿਚਕਾਰ ਸਾਈਨੈਪਸ ਤੇ ਕੀ ਹੁੰਦਾ ਹੈ? दो न्यूट्रॉन के बीच स्नाइप्स पे क्या होता है? *Electric signal is converted to chemical signal/ ਬਿਜਲਈ ਸੰਕੇਤ, ਰਸਾਇਣਕ ਸੰਕੇਤ ਵਿੱਚ ਬਦਲ ਜਾਂਦਾ ਹੈ / बिजली संकेत, रासायनिक संकेत में बदल जाता है/Chemicals signal is converted into electrical signal / ਰਸਾਇਣਕ ਸੰਕੇਤ, ਬਿਜਲਈ ਸੰਕੇਤ ਵਿਚ ਬਦਲ ਜਾਂਦਾ ਹੈ/रासायनिक संकेत, बिजली संकेत में बदल जाता है/All signals ends at this snaps /ਸਭ ਸੰਕੇਤ ਇਸ ਸਾਈਨੈਪਸ ਤੇ ਖ਼ਤਮ ਹੋ ਜਾਂਦੇ ਹਨ/सभी संकेत जहां पर समाप्त हो जाते हैं/Nothing happens /ਕੁਝ ਨਹੀਂ ਹੁੰਦਾ/कुछ भी नहीं होता/hii
Answer» SYNAPSE Between Two Neurons Mechanism Chemicals are released at the end of axon and this is caused by the electrical IMPULSE. These chemicals cross the synapse and similar electrical IMPULSES are created in the dendrite of the next neuron.

16.

What happens at the synapse between two neurons ? ਦੋ ਨਿਊਰੋਨ ਵਿਚਕਾਰ ਸਾਈਨੈਪਸ ਤੇ ਕੀ ਹੁੰਦਾ ਹੈ? दो न्यूट्रॉन के बीच स्नाइप्स पे क्या होता है? *Electric signal is converted to chemical signal/ ਬਿਜਲਈ ਸੰਕੇਤ, ਰਸਾਇਣਕ ਸੰਕੇਤ ਵਿੱਚ ਬਦਲ ਜਾਂਦਾ ਹੈ / बिजली संकेत, रासायनिक संकेत में बदल जाता है/Chemicals signal is converted into electrical signal / ਰਸਾਇਣਕ ਸੰਕੇਤ, ਬਿਜਲਈ ਸੰਕੇਤ ਵਿਚ ਬਦਲ ਜਾਂਦਾ ਹੈ/रासायनिक संकेत, बिजली संकेत में बदल जाता है/All signals ends at this snaps /ਸਭ ਸੰਕੇਤ ਇਸ ਸਾਈਨੈਪਸ ਤੇ ਖ਼ਤਮ ਹੋ ਜਾਂਦੇ ਹਨ/सभी संकेत जहां पर समाप्त हो जाते हैं/Nothing happens /ਕੁਝ ਨਹੀਂ ਹੁੰਦਾ/कुछ भी नहीं होता/hii

Answer»

SYNAPSE Between Two Neurons Mechanism

Chemicals are released at the end of axon and this is caused by the electrical IMPULSE. These chemicals cross the synapse and similar electrical IMPULSES are created in the dendrite of the next neuron.

Discussion

17.	What is the factor of x²-14x+49
Answer» ANSWER: x²-14x+49 x²-7x-7x+49 x(x-7)-7(x-7) (x-7)(x-7) HOPE it HELPS you...

17.

What is the factor of x²-14x+49

Answer»

ANSWER:

x²-14x+49

x²-7x-7x+49

x(x-7)-7(x-7)

(x-7)(x-7)

HOPE it HELPS you...

Discussion

18.	Question 6,7,8,9 pls tell these question
Answer» hhhhhhiiiiiiiiooooooooo

Discussion

19.	A particle is projected vertically upwards from the surface of earth with a velocitysufficient to carry it to the infinity. Prove that the time it takes to reach ajustheight his116][(-4)-3(Meerut 2004; Purvanchal 11, 14)where a is the radius of the earth.
Answer» Answer: it is related to this question Step-by-step explanation: A small body of mass is projected with a velocity just SUFFICIENT to MAKE it reach from the surface of a planet (of radius 2R and mass 3M) to the surface of another planet (of radius R and mass M). The distance between the centers of the two spherical planets is 6R. The distance of the body from the center of BIGGER planet is 'x' at any moment. During the JOURNEY, find the distance x where the speed of the body is maximum. ASSUME motion of body along the line joining centres of planets. Study later View Answer

19.

A particle is projected vertically upwards from the surface of earth with a velocitysufficient to carry it to the infinity. Prove that the time it takes to reach ajustheight his116][(-4)-3(Meerut 2004; Purvanchal 11, 14)where a is the radius of the earth.

Answer»

Answer:

it is related to this question

Step-by-step explanation:

A small body of mass is projected with a velocity just SUFFICIENT to MAKE it reach from the surface of a planet (of radius 2R and mass 3M) to the surface of another planet (of radius R and mass M). The distance between the centers of the two spherical planets is 6R. The distance of the body from the center of BIGGER planet is 'x' at any moment. During the JOURNEY, find the distance x where the speed of the body is maximum. ASSUME motion of body along the line joining centres of planets.

Study later

View Answer

Discussion

20.	FOR x= -1 ... find the value of x^2 5x+6.
Answer» SOLUTION: GIVEN:- $x=-1$ We have to FIND:- $x²(5x+6)$ Now,put the values:- $(-1)²(5(-1)+6)$ $=1(-5+6)$ $=-5+6$ $=1$ Note:- As there was no SYMBOL after x²,it should be multipled.

20.

FOR x= -1 ... find the value of x^2 5x+6.

Answer»

SOLUTION:

GIVEN:- $x=-1$

We have to FIND:-

$x²(5x+6)$

Now,put the values:-

$(-1)²(5(-1)+6)$

$=1(-5+6)$

$=-5+6$

$=1$

Note:- As there was no SYMBOL after x²,it should be multipled.

Discussion

21.	Find the compound interest on Rs. 5000 for 2.5 years at a rate of 6% per annum compounded annually
Answer» Answer: 5786.54 Step-by-step EXPLANATION: CI in first year=6/100×5000=300 CI in 2ND year is 5300+6/100×5300=5618 CI in next 1/2 year is 1/2 (6/100×5618)=168. 54 total money is 5618+168. 54=5786.54

21.

Find the compound interest on Rs. 5000 for 2.5 years at a rate of 6% per annum compounded annually

Answer»

Answer:

5786.54

Step-by-step EXPLANATION:

CI in first year=6/100×5000=300

CI in 2ND year is 5300+6/100×5300=5618

CI in next 1/2 year is 1/2 (6/100×5618)=168. 54

total money is 5618+168. 54=5786.54

Discussion

22.	एक अधयापक की उम्र उसके बालक की उम से 50% अधिक हैयदि बालक का उम्र 2 2 हो तोअध्यापक की उम्र बताए
Answer» Step-by-step explanation: 44 YEARS ANSWAR your QUESTION

22.

एक अधयापक की उम्र उसके बालक की उम से 50% अधिक हैयदि बालक का उम्र 2 2 हो तोअध्यापक की उम्र बताए

Answer»

Step-by-step explanation:

44 YEARS ANSWAR your QUESTION

Discussion

23.	A chord of a circle of radius10 cm subtends a right angle at the centre .Find the area of the corresponding 1)minor segment 2)major segment1
Answer» Solution : radius of a CIRCLE, AO = 10 cm ∠AOC = 90° AREA of AAOC = ½ X OA x OC = ½ x 10 x 10 = 50 cm² Area of sector OAECO = Ø/360° x πr² = 90°/360 x 3.14 x (10)² = 314/4 = 78.5 cm² i) Area of minor segment AECDA area of sector OAECO - area of ΔAOC = 78.5 - 50 = 28.5 cm² ii) Area of major sector OAFGCO Area of circle - Area of sector OAECO = 3.14 x (10)² - 78.5 = 314 - 78.5 = 235.5 cm²

23.

A chord of a circle of radius10 cm subtends a right angle at the centre .Find the area of the corresponding 1)minor segment 2)major segment1

Answer»

Solution :

radius of a CIRCLE, AO = 10 cm ∠AOC = 90°

AREA of AAOC = ½ X OA x OC

= ½ x 10 x 10

= 50 cm²

Area of sector OAECO = Ø/360° x πr²

= 90°/360 x 3.14 x (10)²

= 314/4

= 78.5 cm²

i) Area of minor segment AECDA

area of sector OAECO - area of ΔAOC

= 78.5 - 50

= 28.5 cm²

ii) Area of major sector OAFGCO

Area of circle - Area of sector OAECO

= 3.14 x (10)² - 78.5

= 314 - 78.5

= 235.5 cm²

Discussion

24.	Check whether p(x) is a multiple of g(x)=x³-5x²+4x-3g(x)=x-2.
Answer» YE I GOT your ANSWER if you WANT then INBOX me

24.

Check whether p(x) is a multiple of g(x)=x³-5x²+4x-3g(x)=x-2.

Answer»

YE I GOT your ANSWER if you WANT then INBOX me

Discussion

25.	If ABCD is a cyclic quadrilateral, then find which of the following statements is not correct.
Answer» ANSWER: B Step-by-step EXPLANATION: In a CYCLIC QUADRILATERAL ABCD A + C = 180 sin[A+C]=sin180=0 B + D = 180 cos[B+D]=cos180=-1 sin[A+B+C+D]=sin360=0 But it is not necessary that sin[A+B]=0 Hope it helps Mark it as the brainliest

25.

If ABCD is a cyclic quadrilateral, then find which of the following statements is not correct.

Answer»

ANSWER:

B

Step-by-step EXPLANATION:

In a CYCLIC QUADRILATERAL ABCD

A + C = 180

sin[A+C]=sin180=0

B + D = 180

cos[B+D]=cos180=-1

sin[A+B+C+D]=sin360=0

But it is not necessary that sin[A+B]=0

Hope it helps

Mark it as the brainliest

Discussion

26.	3. ਅੰਜਲੀ ਨੂੰ ਬਚਤ ਕਰਨ ਦੀ ਆਦਤ ਹੈ। ਉਸਨੇ ਪਿਛਲੇ 2 ਮਹੀਨਿਆਂ ਵਿੱਚ Rs. 60 ਦੀ ਬਚਤ ਕੀਤੀ. ਉਸਨੇ ਆਪਣੀ ਬਚਤ ਦਾ ⅚ ਹਿੱਸਾ ਦਾਨ ਕਰ ਦਿੱਤਾ, ਹੁਣ ਉਸਦੇ ਕੋਲ ਕਿੰਨੀ ਰਕਮ ਬਚੀ ਹੈ? Anjali has a habit of saving money. In last two months she saved Rs. 60. She donated ⅚ of her savings. How much money is left with her? अंजलि को बचत करने की आदत है । पिछले 2 महीनों में उसने Rs. 60 बचाए । उसने अपनी बचत का ⅚ भाग दान कर दिया अब उसके पास कितनी राशि बची? *(a) 50 Rsb) 10 Rsc) 20 Rsd) 30 Rs
Answer» ANSWER: 5/660 510 50 is RIGHT answer

26.

3. ਅੰਜਲੀ ਨੂੰ ਬਚਤ ਕਰਨ ਦੀ ਆਦਤ ਹੈ। ਉਸਨੇ ਪਿਛਲੇ 2 ਮਹੀਨਿਆਂ ਵਿੱਚ Rs. 60 ਦੀ ਬਚਤ ਕੀਤੀ. ਉਸਨੇ ਆਪਣੀ ਬਚਤ ਦਾ ⅚ ਹਿੱਸਾ ਦਾਨ ਕਰ ਦਿੱਤਾ, ਹੁਣ ਉਸਦੇ ਕੋਲ ਕਿੰਨੀ ਰਕਮ ਬਚੀ ਹੈ? Anjali has a habit of saving money. In last two months she saved Rs. 60. She donated ⅚ of her savings. How much money is left with her? अंजलि को बचत करने की आदत है । पिछले 2 महीनों में उसने Rs. 60 बचाए । उसने अपनी बचत का ⅚ भाग दान कर दिया अब उसके पास कितनी राशि बची? *(a) 50 Rsb) 10 Rsc) 20 Rsd) 30 Rs

Answer»

ANSWER:

5/6*60

5*10

50 is RIGHT answer

Discussion

27.	Prove that 1=2 by full explanation
Answer» ANSWER: KONSE world MEIN padte HO mere pyare BHAI..... 1+1 = 2 not 1=2.......

27.

Prove that 1=2 by full explanation

Answer»

ANSWER:

KONSE world MEIN padte HO mere pyare BHAI.....

1+1 = 2 not 1=2.......

Discussion

28.	If (x+5) is the factor of p(x) = x³-2x-23k then k
Answer» ANSWER: x+5=0 x=-5 p(-5)=(-5)³-2(-5)-23K 0= -125+10-23k 23k=-115 K=115/-23 k=. -5

28.

If (x+5) is the factor of p(x) = x³-2x-23k then k

Answer»

ANSWER:

x+5=0

x=-5

p(-5)=(-5)³-2(-5)-23K

0= -125+10-23k

23k=-115

K=115/-23

k=. -5

Discussion

29.	Find the unshaded are of triangle ABC with Ab=5 BC =4 and AC=3 and with 1 cm of each vertics
Answer» ANSWER: cccccccccccccccccccccccccccccccccccccccc

29.

Find the unshaded are of triangle ABC with Ab=5 BC =4 and AC=3 and with 1 cm of each vertics

Answer»

ANSWER:

cccccccccccccccccccccccccccccccccccccccc

Discussion

30.	Q- In theAD = 1.28cm ,DB = 2:56cmAE = 0 64cm0.64cm, De Coill be parallel to Beif Ec=
Answer» Answer: pata nhi BRO MAJA AA rha HAI

30.

Q- In theAD = 1.28cm ,DB = 2:56cmAE = 0 64cm0.64cm, De Coill be parallel to Beif Ec=

Answer»

Answer:

pata nhi BRO MAJA AA rha HAI

Discussion

31.	Ŧєєlเภﻮlєรร קєгร๏ภ๒zς ภ๏๏ภє ςคгєรfeeling less personbcz noone cares....lol
Answer» ANSWER: HERE IS YOUR ANSWER DEAR ❤️ sorry yr can't READ above two lines Step-by-step explanation: HOPE IT HELPS YOU DEAR PLEASE PLEASE MARK IT BRAINLIEST AND FOLLOW ME DEAR PLEASE

31.

Ŧєєlเภﻮlєรร קєгร๏ภ๒zς ภ๏๏ภє ςคгєรfeeling less personbcz noone cares....lol

Answer»

ANSWER:

HERE IS YOUR ANSWER DEAR ❤️

sorry yr can't READ above two lines

Step-by-step explanation:

HOPE IT HELPS YOU DEAR PLEASE PLEASE MARK IT BRAINLIEST AND FOLLOW ME DEAR PLEASE

Discussion

32.	What is meant by quantum physics
Answer» $\huge\underline\mathrm{AnSweR}$ PUT simply, it's the physics that explains how everything works: the best description we have of the nature of the particles that make up MATTER and the forces with which they interact. Quantum physics underlies how atoms work, and so why CHEMISTRY and biology work as they do.

32.

What is meant by quantum physics

Answer»

$\huge\underline\mathrm{AnSweR}$

PUT simply, it's the physics that explains how everything works: the best description we have of the nature of the particles that make up MATTER and the forces with which they interact. Quantum physics underlies how atoms work, and so why CHEMISTRY and biology work as they do.

Discussion

33.	Please help no spam or get reported
Answer» Step-by-step EXPLANATION: $4 \times {10}^{5} + 6 \times {10}^{4} + 9 \times {10}^{3} + 8 \times {10}^{1}$ $= 4 \times 100000 + 6 \times 10000 + 9 \times 1000 + 8 \times 10$ $= 469080$ OM NAMAH Shivaya Debasish BISWAL

33.

Please help no spam or get reported

Answer»

Step-by-step EXPLANATION:

$4 \times {10}^{5} + 6 \times {10}^{4} + 9 \times {10}^{3} + 8 \times {10}^{1}$

$= 4 \times 100000 + 6 \times 10000 + 9 \times 1000 + 8 \times 10$

$= 469080$

OM NAMAH Shivaya

Debasish BISWAL

Discussion

34.	6. Simplify:(i) ab(a? – b) + b3 (a - 2b)(ii) - 6x? (xy + 2y) – 3y2 (2x2 + y)(iii) 2x(x - y2) - 3y(xy + 2x) – xy(x + y)3 rd no. plzz solve kar dijye
Answer» ANSWER: skskbsbdjsmamamsnsnwiiwjw

34.

6. Simplify:(i) ab(a? – b) + b3 (a - 2b)(ii) - 6x? (xy + 2y) – 3y2 (2x2 + y)(iii) 2x(x - y2) - 3y(xy + 2x) – xy(x + y)3 rd no. plzz solve kar dijye

Answer»

ANSWER:

skskbsbdjsmamamsnsnwiiwjw

Discussion

35.	Divisibility rule of 125
Answer» Divisibility by 125: The number FORMED by the hundreds, tens and UNITS digit of the number MUST be DIVISIBLE by 125 125

Discussion

36.	ਜੇਕਰ ਸਮਰੂਪ ਤ੍ਰਿਭੁਜਾਂ ABC ਅਤੇ DEF ਵਿੱਚ AB = 4 cm, DE = 6 cm, EF = 9 cm ਅਤੇ FD = 12 cm ਹੈ ,ਤਾਂ ∆ABC ਦਾ ਪਰਿਮਾਪ ਪਤਾ ਕਰੋ। If ΔABC ~ ΔDEF, AB = 4 cm, DE = 6 cm, EF = 9 cm and FD = 12 cm, find the perimeter of ∆ABC. अगर समरूप त्रिभुजों ABC और DEF में AB = 4 cm, DE = 6 cm, EF = 9 cm और FD = 12 cm है तो ∆ABC का परिमाप पता करें। *(A) 18 cm(B) 20 cm(C) 21 cm(D) 22 cm
Answer» ANSWER: (B) 20 CM....................

36.

ਜੇਕਰ ਸਮਰੂਪ ਤ੍ਰਿਭੁਜਾਂ ABC ਅਤੇ DEF ਵਿੱਚ AB = 4 cm, DE = 6 cm, EF = 9 cm ਅਤੇ FD = 12 cm ਹੈ ,ਤਾਂ ∆ABC ਦਾ ਪਰਿਮਾਪ ਪਤਾ ਕਰੋ। If ΔABC ~ ΔDEF, AB = 4 cm, DE = 6 cm, EF = 9 cm and FD = 12 cm, find the perimeter of ∆ABC. अगर समरूप त्रिभुजों ABC और DEF में AB = 4 cm, DE = 6 cm, EF = 9 cm और FD = 12 cm है तो ∆ABC का परिमाप पता करें। *(A) 18 cm(B) 20 cm(C) 21 cm(D) 22 cm

Answer»

ANSWER:

(B) 20 CM....................

Discussion

37.	Seg PM is a median of APOR. If PQ = 40, PR = 42 and PM = 29, find QR.
Answer» Answer: Seg PM is a median of APOR. If PQ = 40, PR = 42 and PM = 29, FIND QR.

37.

Seg PM is a median of APOR. If PQ = 40, PR = 42 and PM = 29, find QR.

Answer»

Answer:

Seg PM is a median of APOR. If PQ = 40, PR = 42 and PM = 29, FIND QR.

Discussion

38.	Test the conriniuty & differentiability off (x)= x×1/sinx at x not equal to 0,f(0)=0
Answer» Step-by-step EXPLANATION: F(0)= x→0 lim XSIN x 1 We know ∀x∈R,sin x 1 ∈[−1,1] Hence, f(0)= x→0 lim xsin x 1 =0

38.

Test the conriniuty & differentiability off (x)= x×1/sinx at x not equal to 0,f(0)=0

Answer»

Step-by-step EXPLANATION:

F(0)=

x→0

lim

XSIN

x

1

We know ∀x∈R,sin

x

1

∈[−1,1]

Hence, f(0)=

x→0

lim

xsin

x

1

=0

Discussion

39.	3³ x k⁴ x 7k⁴ plz tell
Answer» Answer: 27×7×k^8 3³ X k⁴ x 7k⁴ 3^3=27 k^4 k^4 =k^4+4 =k^8 27×7×k^8

39.

3³ x k⁴ x 7k⁴ plz tell

Answer»

Answer:

27×7×k^8

3³ X k⁴ x 7k⁴

3^3=27

k^4 k^4

=k^4+4

=k^8

27×7×k^8

Discussion

40.	Find the remainder in expression,11+2+3++...10011005+..........1001100में शेषफल क्या11+2+3+....व्यंजक5होगा?(a) 1(b) 2(d) 4(c) 3
Answer» Answer: 3 hoga ab vo KESE hoga vo to NA bta skta kafi लम्बी ट्रिक H.. PLZZ bro add me brqinlist

40.

Find the remainder in expression,11+2+3++...10011005+..........1001100में शेषफल क्या11+2+3+....व्यंजक5होगा?(a) 1(b) 2(d) 4(c) 3

Answer»

Answer:

3 hoga ab vo KESE hoga vo to NA bta skta kafi लम्बी ट्रिक H.. PLZZ bro add me brqinlist

Discussion

41.	I need a clan, ID: #LYVJULQ2G
Answer» Answer: OK I INVITE you in 2 days Step-by-step explanation: *YOUR* *TOWN* *HALL*?

41.

I need a clan, ID: #LYVJULQ2G

Answer»

Answer:

OK I INVITE you in 2 days

Step-by-step explanation:

YOUR TOWN HALL?

Discussion

42.	Prove thatthat √(1-sin ø /1+ Sin ø)Sec ø - tanø
Answer» Step-by-step explanation: SQUARE root of (1-sinx/1+sinx) divide and MULTIPLY by (1-sinx) square root of (1-sinx)(1-sinx)/(1+sinx)(1-sinx) square root of (1-sinx)^2/1-sin^2x 1-sin^2x=cos^2x square root of (1+sin^2x-2sinx)/cos^2x square root of (1/cos^2x+sin^2x/cos^2x-2sinx/cos^2x) =1/cos^2x=sec^2x =sin^2x/cos^2x=tan^2x =2sinx/cos^2x=2tanxsecx square FOOT of sec^2x+tan^2x-2tanxsecx it is in the form of (a-b)^2=a^2+b^2-2ab square root of (secx-tanx)^2 square root and square canceled therefore secx-tanx square root of (1-sinx)/(1+sinx)=secx-tanx

42.

Prove thatthat √(1-sin ø /1+ Sin ø)Sec ø - tanø

Answer»

Step-by-step explanation:

SQUARE root of (1-sinx/1+sinx)

divide and MULTIPLY by (1-sinx)

square root of (1-sinx)(1-sinx)/(1+sinx)(1-sinx)

square root of (1-sinx)^2/1-sin^2x

1-sin^2x=cos^2x

square root of (1+sin^2x-2sinx)/cos^2x

square root of (1/cos^2x+sin^2x/cos^2x-2sinx/cos^2x)

=1/cos^2x=sec^2x

=sin^2x/cos^2x=tan^2x

=2sinx/cos^2x=2tanxsecx

square FOOT of sec^2x+tan^2x-2tanxsecx

it is in the form of (a-b)^2=a^2+b^2-2ab

square root of (secx-tanx)^2

square root and square canceled

therefore secx-tanx

square root of (1-sinx)/(1+sinx)=secx-tanx

Discussion

43.	1.- El valor absoluto de \|3-8\|=-5a) Verdaderob) Falso2.- El valor absoluto de \|x-5\|=-7a) Tiene dos solucionesb) Tiene una soluciónc) No tiene soluciones3.- El valor absoluto de \|2-11\|=9a) Verdaderob) Falso4.- El valor absoluto de \|2x+1=4a) Tiene dos solucionesb) Tiene una soluciónc) No tiene soluciones
Answer» ANSWER: bfjxbfndbfbdvtrhf FBG dhrnfb Step-by-step EXPLANATION: *dufufyfhfogjfucgsupYxgaoysyosyosylxjwcggwhdgxbgiryfudjchlOgzlggsylxlhcoyfjgug* *ifsypxpydupxoylhdpydpyxjfyor* *itsjxgidhlxgozorspgxhlzfTop*

43.

1.- El valor absoluto de |3-8|=-5a) Verdaderob) Falso2.- El valor absoluto de |x-5|=-7a) Tiene dos solucionesb) Tiene una soluciónc) No tiene soluciones3.- El valor absoluto de |2-11|=9a) Verdaderob) Falso4.- El valor absoluto de |2x+1=4a) Tiene dos solucionesb) Tiene una soluciónc) No tiene soluciones

Answer»

ANSWER:

bfjxbfndbfbdvtrhf FBG dhrnfb

Step-by-step EXPLANATION:

dufufyfhfogjfucgsupYxgaoysyosyosylxjwcggwhdgxbgiryfudjchlOgzlggsylxlhcoyfjgug ifsypxpydupxoylhdpydpyxjfyor itsjxgidhlxgozorspgxhlzfTop

Discussion

44.	Find the rate of interest which gives rupees 140 as interest on a sum of rupees 4200 in 5 months
Answer» ANSWER: ᴡᴇ ʜᴀᴠᴇ, ᴩ=ʀꜱ.56000, ᴛ=2yᴇᴀʀꜱ, ꜱɪ=ʀꜱ.280 ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ, ꜱɪ=100ᴩ×ʀ×ᴛ 280=10056000×ʀ×2 ʀ=2×560280 ʀ=0.25% ʜᴇɴᴄᴇ, ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏꜰ ᴛʜᴇ ʀᴀᴛᴇ ɪꜱ 0.25%.

44.

Find the rate of interest which gives rupees 140 as interest on a sum of rupees 4200 in 5 months

Answer»

ANSWER:

ᴡᴇ ʜᴀᴠᴇ,

ᴩ=ʀꜱ.56000,

ᴛ=2yᴇᴀʀꜱ,

ꜱɪ=ʀꜱ.280

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,

ꜱɪ=100ᴩ×ʀ×ᴛ

280=10056000×ʀ×2

ʀ=2×560280

ʀ=0.25%

ʜᴇɴᴄᴇ, ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏꜰ ᴛʜᴇ ʀᴀᴛᴇ ɪꜱ 0.25%.

Discussion

45.	Simplify : 1 ⁰ + 7 ⁰ + 4
Answer» Answer: 6 Step-by-step EXPLANATION: =1^0+7^0+4 =1+1+4(because m^0=1) =6 hope it HELPS.....

45.

Simplify : 1 ⁰ + 7 ⁰ + 4

Answer»

Answer:

6

Step-by-step EXPLANATION:

=1^0+7^0+4

=1+1+4(because m^0=1)

=6

hope it HELPS.....

Discussion

46.	Prove that: (secA+ tanA)^2= (Cosec A +1)/(CaseA-1)
Answer» Step-by-step explanation: (secA+tanA)^2 it is in the FORM of (a+b)^2=a^2+b^2+2ab sec^2A+tan^2A+2secAtanA 1/cos^2A+sin^2A/cos^2A+2sinA/cos^2A (1+sin^2A+2sinA)/cos^2A 1+sin^2A+2sinA is in the form of (a+b)^2 (1+SINA)^2/(cos^2A) (1+sinA)(1+sinA)/(1-sin^2A) (1+sinA)(1+sinA)/(1+sinA)(1-sinA) sinA can be written as 1/cosecA (1+1/cosecA)/(1-1/cosecA THEREFORE (cosecA+1)/(cosecA-1) (secA+tanA)^2=(cosecA+1)/(cosec-1)

46.

Prove that: (secA+ tanA)^2= (Cosec A +1)/(CaseA-1)

Answer»

Step-by-step explanation:

(secA+tanA)^2

it is in the FORM of

(a+b)^2=a^2+b^2+2ab

sec^2A+tan^2A+2secAtanA

1/cos^2A+sin^2A/cos^2A+2sinA/cos^2A

(1+sin^2A+2sinA)/cos^2A

1+sin^2A+2sinA is in the form of (a+b)^2

(1+SINA)^2/(cos^2A)

(1+sinA)(1+sinA)/(1-sin^2A)

(1+sinA)(1+sinA)/(1+sinA)(1-sinA)

sinA can be written as 1/cosecA

(1+1/cosecA)/(1-1/cosecA

THEREFORE (cosecA+1)/(cosecA-1)

(secA+tanA)^2=(cosecA+1)/(cosec-1)

Discussion

47.	Y C = (x:x is a two-digit natural number such that the sum of its digits is 8]
Answer» INBOX me to GET your ANSWER.........................

47.

Y C = (x:x is a two-digit natural number such that the sum of its digits is 8]

Answer»

INBOX me to GET your ANSWER.........................

Discussion

48.	Find the diameter of circle when its curcumference is given:i) 44cm(step by step explanation please)
Answer» Given: Circumference of the circle = 44 cm To Find: The DIAMETER of the circle. Formula: Circumference of a circle = 2πr where, π = pi and r = RADIUS of the circle Explanation: ACCORDING to the question, 2πr = 44 or, ${\tt {\frac {22}{7} \times r = \frac{44}{<klux>2</klux>} = 22}}$ or, ${\tt { r = 22 \times \frac{7} {22} = 7 \: cm}}$ ANSWER: The radius of the circle is 7 cm. The diameter will be 2(7) = 14 cm. Therefore, the diameter of the circle is 14 cm.

48.

Find the diameter of circle when its curcumference is given:i) 44cm(step by step explanation please)

Answer»

Given:

Circumference of the circle = 44 cm

To Find:

The DIAMETER of the circle.

Formula:

Circumference of a circle = 2πr

where, π = pi and r = RADIUS of the circle

Explanation:

ACCORDING to the question,

2πr = 44

or, ${\tt {\frac {22}{7} \times r = \frac{44}{<klux>2</klux>} = 22}}$

or, ${\tt { r = 22 \times \frac{7} {22} = 7 \: cm}}$

ANSWER:

The radius of the circle is 7 cm.

The diameter will be 2(7) = 14 cm.

Therefore, the diameter of the circle is 14 cm.

Discussion

49.	How many centimetersare there in 7kilometers
Answer» ANSWER: There are 700000 CM in 7 kilometers. Hope it's HELP you

49.

How many centimetersare there in 7kilometers

Answer»

ANSWER:

There are 700000 CM in 7 kilometers.

Hope it's HELP you

Discussion

50.	In an isosceles triangle, the vertex angle is 50:What are the base angle of the angle of thetriangle?
Answer» Answer: 65° Step-by-step explanation: As we know that the base angle of an ISOSCELES TRIANGLE are ALWAYS equal and sum of INTERIOR angles of a triangle is 180°. Let the base angles of the isosceles triangle be x° each. ∴x+x+50°=180° ⇒2x=180°−50° ⇒x= 2 130° =65° Hence the base angles will be of 65° each.

50.

In an isosceles triangle, the vertex angle is 50:What are the base angle of the angle of thetriangle?

Answer»

Answer:

65°

Step-by-step explanation:

As we know that the base angle of an ISOSCELES TRIANGLE are ALWAYS equal and sum of INTERIOR angles of a triangle is 180°.

Let the base angles of the isosceles triangle be x° each.

∴x+x+50°=180°

⇒2x=180°−50°

⇒x=

2

130°

=65°

Hence the base angles will be of 65° each.

Discussion

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