Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Answer me fastfind the cube of number 9

Answer»

ANSWER:

\sqrt[3]{9}  = 3

2.

Q67. Which of the following organism can do anaerobic respiration?कौन सा जीव एनएरोबिक श्वसन करता है?(9) Yeast/ खमीर(b) Leech/sitesY) Amoeba/ अमीबा(d) Fish / मछली​

Answer»

(9) YEAST can do ANAEROBIC RESPIRATION.

3.

18. Case Study Based-Class X students of a secondary school in Krishnagar have been allotted a rectangular plot ofa land for gardening activity. Saplings of Gulmohar are planted on the boundary at a distanceof Im from each other. There is a triangular grassy lawn in the plot as shown in the figure.The students are to sow seeds of flowering plants on the remaining area of the plot.АААААААААААААААPR1(d) (-1,-1)1ΔΔΔΔΑΑA 6D1 2 3 4 5 6 7 8 9 10Considering A as origin, answer question (1) to (v).(1) Considering A as the origin, what are the coordinates of A?(a) (0, 1)(b) (1,0)(C) (0,0)(ii) What are the coordinates of P?(a) (4, 6)(b) (6,4)(c) (4,5)(iii) What are the coordinates of R?(a) (6,5)(b) (5,6)(c) (6,0)(iv) What are the coordinates of D?(a) (16,0)(b) (0,0)(c) (0, 16)(v) What are the coordinates of P if D is taken as the origin?(a) (12,2)(b) (-12, 6) (c) (12,3)(d) (5,4)1(d) (7,4)1(d) (16, 1)1(d) (6, 10)​

Answer»

Answer:

a hug and kiss eyye you are not the intended RECIPIENT you are not the intended recipient

Step-by-step explanation:

dgjyykfiifiyo you are re email with a GOOD MORNING ANNA o in in the same anna

4.

*ایک دائرہ میں دو نصف قتروں کے درمیان 130º پیمائش کا زاویہ ہے تو ان نصف قتروں کے بیرونی نقطوں سے گزرنے والے مماسوں سے بننے والا کی پیمائش ۔ ۔ ۔ ہوگا۔*10یہ​

Answer»

Answer:

PLEASE mark this brainliest PLEASED BHAI please POINT badha do

5.

Thie path of a train Als given by the syuation 3x + 4y - 12 = 0 and the path of another trainB is given by the equation 6x + 8y - 18 = . Represent this situation graphically..​

Answer»

Answer:

EQUATION of path (A) : 3x+4y−12=0

⇒x-intercept of (A) =4

⇒y-intercept of (A) =3

⇒Slope of (A) =

4

−3

Equation of path (B) : 6x+8y−48=0

⇒x-intercept of (B) =8

⇒y-intercept of (B) =6

⇒Slope of (B) =

8

−6

=

4

−3

⇒Both the paths are PARALLEL as there SLOPES are equal

6.

Urgentis 243 a perfect square explain

Answer»

ANSWER:

no,243 is not a PERFECT SQUARE

7.

If f(x) = tan3(2x). Find f′(π12) =?

Answer»

ANSWER:

do it yourself BEST WAY to LEARN

8.

In a class, 46%. Students are vegetarianswhat percentage of the students arenon vegetarians? ​

Answer»

Answer:

54%

Step-by-step EXPLANATION:

PLEASE MARK BRAINLIST

9.

Following properties are of which quadrilateral 1) Two pairs of adjacent sides are congruent 2) One pair of opposite angles is congruent *TrapeziumRhombusParallelogramKite​

Answer»

ANSWER:

RHOMBUS : all SIDES are equal

diagonals MEET at 90 degree

10.

हेक्टोमीटर के हिसाब से इसके चारों ओर तार लगवाने में कुलकितना व्यय होगा?(A) ₹56.90(B) ₹65.40(C) ₹84-20(D) ₹79.905. एक वर्गाकार बगीचे की भुजा 85 डेकामीटर है. इस बगीचे केचारों ओर 24 पैसे प्रति मीटर के भाव से बाड़ लगवाने में कुलकितना खर्च होगा?(A) ₹66.80(B) ₹24:20(C) ₹78.20(D) ₹81.606. एक वाटिका 180 मीटर लम्बी और 110 मीटर चौड़ी है. इसकेचारों ओर तार की पाँच पंक्तियाँ लगाई हैं. यदि एक मीटर ताका मूल्य 45 पैसे तो लगवाने की कुल कीमत बताओ.(A) 71400.50(D)+14​

Answer»

Answervysistsjtskeuejtetwjtsg

11.

Foxpro system menu can be hidden byफॉक्सप्रो सिस्टम मेनू द्वारा छिपाया जा सकता हैSelect one:O a. Set menu ofSet menu ofO b. Set sysmenu toSet sysmenu toO c. Set sysmenu to defaultSet sysmenu to defaultO d. Set menu toSet mercu toClear my choice​

Answer»

Step-by-step EXPLANATION:

POTENTIAL ENERGY, stored energy that depends upon the relative position of various PARTS of a system. A spring has more potential energy when it is compressed or stretched. A steel ball has more potential energy raised above the ground than it has after falling to Earth.

12.

The point of intersection of two lines x+y=6 and x-y=4 isx+y-6 మరియు X-y=4 రేఖల ఖండన బిందువుD(3.2​

Answer»

ANSWER:

y-6 మరియు X-y=4 రేఖల ఖండన బిందువు

D(3.2

13.

Which of following quadrilateral is having congruent diagonals? *SquareRombusRectangleParallelogram​

Answer»

ANSWER:

SQUARE

Step-by-step EXPLANATION:

THINKING it HELPS

14.

If f(x) = x√5 − x2; then find the value of the slope at x=1

Answer»

ANS : 4

steps :

to FIND f(x)

equate the equation to zero

hence ,

0 = x√5 - x

now REPLACE the x with 1

1√5 - 1 = 1

15.

10. A box contains 5 red marbles, 6 white marbles and 4 green marbles. If a marble is drawnrandom from the box, What is the probability that the marble will be white?​

Answer»

Answer:

0

Step-by-step explanation:

It's IMPOSSIBLE EVENT as there's no white ball.

So, the probability of GETTING white MARBLE is ZERO (0).

16.

.And. .or. .not. areAnd..or..not. हैंSelect one::a. Logical operatorलॉजिकल ऑपरेटरO b. Noneकोई नहींO c. Arithmetic operatorअरिथमेटिक ऑपरेटरO d. Relational operatorरिलेशनल ऑपरेटरClear my choice​

Answer»

ANSWER:

B. NONE कोई नहींबखछझजतणठखछधयभठखचद

17.

Find the compound interest, if the amount of a certain principal after 2 years is ₹ 4036.80 at a rate of 16 p.cp.a *1 point₹ 3000₹ 1035.80₹ 1036.80₹ 1020.00​

Answer»

\underline{ \underline{  \Large \pmb{\mathit{ {Given:}} }} }

• Amount (A) = ₹ 4036.80

RATE (R) = 16 % p.a

• Time (n years) = 2 years

\underline{ \underline{  \Large \pmb{\mathit{ {To  \: calculate:}} }} }

COMPOUND Interest (C.I)

\underline{ \underline{  \Large \pmb{\mathit{ {Calculation:}} }} }

As we know that,

\bigstar \: \boxed{\sf {C.I = Amount - Principal}} \\

We aren't given the Principal, let's calculate the Principal first.

As we know that,

\bigstar \: \boxed{\sf {A = {P \Bigg \lgroup 1 + \dfrac{R}{100} \Bigg \rgroup}^{n} }} \\

Where,

• P = Principal

• A = Amount

• n = number of years/time

• R = Rate

\longrightarrow \sf {4036.80 = {P \Bigg \lgroup 1 + \dfrac{16}{100} \Bigg \rgroup}^{2}}\\

\longrightarrow \sf {4036.80 = {P \Bigg \lgroup \dfrac{100 +16}{100} \Bigg \rgroup}^{2}}\\

\longrightarrow \sf {4036.80 = {P \Bigg \lgroup \dfrac{<klux>116</klux>}{100} \Bigg \rgroup}^{2}}\\

\longrightarrow \sf {4036.80 = P \times \dfrac{116}{100} \times \dfrac{116}{100} }\\

\longrightarrow \sf {4036.80 \times \dfrac{116}{100} \times \dfrac{100}{116} = P}\\

\longrightarrow \sf { \dfrac{403680}{\cancel{100}} \times \dfrac{\cancel{100}}{116} \times \dfrac{100}{116} =P } \\

\longrightarrow \sf {403680 \times \dfrac{1}{116} \times \dfrac{100}{116} = P } \\

\longrightarrow \sf { \dfrac{403680 \times 1 \times 100}{116 \times 116} = P } \\

\longrightarrow \sf { \dfrac{\cancel{403680} \times 1 \times 100}{\cancel{116} \times 116} = P }\\

\longrightarrow \sf { \dfrac{3480 \times 1 \times 100}{116} = P } \\

( Cancel 3480 in NUMERATOR and 116 in denominator by 4)

\longrightarrow \sf { \dfrac{ \cancel{870} \times 1 \times 100}{\cancel{29}} = P } \\

\longrightarrow \sf { 30 \times 1 \times 100= P }\\

\longrightarrow \sf { 30  \times 100= P } \\

\longrightarrow \boxed{ \sf { Rs. \: 3000= P }}\\

Therefore, principal us Rs. 3000. Now, substitute the values in the formula of C.I to find the compound interest.

\bigstar \: \boxed{\sf {C.I = Amount - Principal}} \\

\longrightarrow \sf {C.I =Rs. \: 4036.80 - 3000} \\

\longrightarrow \boxed { \pmb {\rm \red {C.I =Rs. \: 1036.80 } }}\\

Therefore, C.I is ₹ 1036.80 and Option C is correct.

18.

5. The cost price of 16 articles as equal to selling price of12 of them find the gain percent.D14​

Answer»

ANSWER:

what is COST PRICE DEAR

19.

FILL IN THE BLANKS :(1)place is just to the left of the hundreds place(2) The predecessor of 4,00,000 is(3) 46789 - 20532 == 320 x 599.(4) 599 x(5) The number by which the dividend is divided is called thedecalitres.(6) 1 hectolitres(7) All numbers are multiples of the numberof the product.(8) Each number is a(9) The area of a square of side 1cm is(10) Every number is a multiple of​

Answer»

ANSWER:

zvkdmxhdnfgajghajbkfjgmfysjbdhpgudydgsgdjxvzgfjetsgfkgkfustzfjddldkfjf

20.

Select the option that is correct for the bracketed numbers with respect to their inclusion in the given series.1, 10, 35, (87), 245, 562, (1511)​

Answer»

ANSWER:

all are ARRANGED CORRECTLY

21.

A multiple-choice test consists of 100 questions. Answer to each question has fourpossible options among which only one is correct. If a student answers all the questions by guessing at random, then what is the expected number of correct answers given by him?​

Answer»

ANSWER:

FIRST you SLOVE then ASK me

22.

The joint probability density function of a two-dimensional random variable (X,Y) isgiven byf(x,y) = { 2 0

Answer»

Answer:

Answer:

First term = 1

Common difference = 6

Given statements about the terms of an AP:

9th term = 7 × 2nd Term

9th term = 7 × 2nd Term12th term = 5 × 3rd term + 2

We have to find the following:

First term, a

Common difference, d

The STANDARD form of an AP is:

a , a + d, a + 2d , a + 3d, ... , a + (n - 1)d

Where,

a = first term of AP

d = common difference of AP

So, According to the formula,

aₙ = a + (n - 1)d

We have 9th term and 2nd term as a + 8d and a + d respectively. So According to the statement given,

⇒ 9th term = 7 × 2nd term

⇒ a + 8d = 7 (a + d)

⇒ a + 8d = 7a + 7d

⇒ 7a - a + 7d - 8d = 0

⇒ 6a - d = 0 ...(i)

Similarly, According to the second statement, we have

⇒ 12th term = ( 5 × 3rd term ) + 2

⇒ a + 11d = { 5(a + 2d) } + 2

⇒ a + 11d = 5a + 10d + 2

⇒ 5a - a + 10d - 11d = -2

⇒ 4a - d = -2 ...(ii)

Subtract EQ.(ii) from eq.(i), we get

⇒ 6a - d - (4a - d) = 0 - (-2)

⇒ 6a - d - 4a + d = 2

⇒ 6a - 4a = 2

⇒ 2a = 2

⇒ a = 1

We found the first term to be 1, Hence substitute the value of a in eq.(i), we get

⇒ 6a - d = 0

⇒ 6(1) - d = 0

⇒ 6 - d = 0

⇒ d = 6

23.

In triangle PQR , angle PQR =90° find sin p and cos ppls guys pls give me answer I need help​

Answer»

<P>ANSWER:

sin p = \frac{QR}{PQ} ;   COS p = \frac{PQ}{PR}

Step-by-step explanation:

The answer is CORRECT.

24.

In APQR and ASTU PQ 3.5 cm, QR 4.0 cm 20 60' and ST 3.5 cm, TU4.0 cm, 21 = 60' Then draw the figure and state that which type of congruency we canfind in the figure​

Answer»

ANSWER:

THANKS for your QUESTION but it is not INTRESTED

25.

Q.18 Construct a line segment whose length is the sum of thesegments whose length are(I) 2.3cm and 5.2cm solve​

Answer»

ANSWER:

OK

Step-by-step explanation:

GIVE ME EMAIL ID I WILL MAIL U

26.

A man is four times as old as his son. After 2 years the man will be three times as old as his son. What is the present age of the man? *plz answer me ​

Answer»

Step-by-step explanation:

LET the AGE of child is x

the age of man =4x

after two years

the age of child =x+2

after two years

the age of man =(4x+2)

as per problem 3(x+2)=4x+2

3x+6=4x+2

transporting 4x, 6

3x-4x=2-6

-x =-4

x=4

we can even CHECK this

3x6=4x4+2

18=18

HENCE PROVED

27.

- A bag contains 5 red balls and some blue balls. If the probability ofdrawing a blue ball at random from the bag is three times that of a redball, find the number of blue balls in the bag. ​

Answer»

ANSWER:

THERE ARE 15 BLUE BALLS IN THE BAG

28.

What is the number of 3-digit number thatcan be formed using the digits 0, 1 and 5,without repeating a digit in any number?​

Answer»

Answer:

0.9 is the CORRECT answer

please SET me BRAINLIST

29.

If α and β are the zeroes of the polynomial p(x) = x2 – p(x + 1) – c such that(α + 1) (β + 1) = 0, the c =

Answer»

Step-by-step EXPLANATION:

SEE this ATTACHMENT

HELPFUL to you

30.

A plant grows in heightby 33.33%in six months. If the plant is 180 cm now, what is the height of a plant after one year?​

Answer»

Given,

Plant grows 33.33% in 6 months.

Present height of plant = 180 cm

To FIND,

Height of plant after ONE YEAR.

Solution,

We can simply solve this mathematical problem by using the following mathematical PROCESS.

The total time period = 1 year = 12 months = 2 × 6 months

Height of the plant after first 6 months = 180 + (180 × 33.33/100) = 239.994 cm

Height of the plant after LAST 6 months = 239.994 + (239.994 × 33.33/100) = 319.984 cm

Hence, the height of the plant after one year will be approximately 319.984 cm.

31.

Description of egg structure?✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏nahi aap ne puchha tha kiya haal hai so hamne bola wahi haddi wahi khaal hai​

Answer»

ANSWER:

Good evening Nawab JI ap to mere sai baat hi nai karte AISA kyo

32.

(iv) If A(1, 3); B(-1, 2); C(x; 4) and D(2, 5) are vertices ofparallelogram then write the value of x.​

Answer»

ANSWER:

record record TREVOR ignore all all CRAMPED Uranus app

Step-by-step EXPLANATION:

zip BCOZ

33.

The data shows the weights recorded during a medical camp find the modalweight.Weight in BelowBelow Below Below Below Below Belowkg40 42 44 46 485052Number of 35914 283532studentsMaths

Answer»

ANSWER:

Hope it helps you

(sorry for BAD QUALITY)

34.

Question: (2 marks )A resultant force of magnitude 1200 N acting at a point,resolve this force along 350 on its one side& 250 on it'sanother side.(a) F2 along 250 = 947.08 N, F1 along 350 = 855.06 N(b) F along 250= 749.77N, F along 350 = 558.60 N(c) F2along 250= 794.77N, Fialong 350= 585.60 N(d) F2along 250=974.08 N, Fjalong 350 = 558.06NDABс​

Answer»

Step-by-step EXPLANATION:

BBB I am not UNDERSTANDING the OUESTION alsou

35.

The equation (x²+1)²-x²=0, has__ rootsfour real rootstwo real rootsno real rootsone real root​

Answer»

Answer:

2 REAL roots answer

Step-by-step EXPLANATION:

PLEASE MARK ME AS BRIANALIST

36.

26.A bag has 4 red balls and 2 yellow balls. (The balls are identical in all respects otherintothan colour). A ball is drawn from the bag without looking into the bag. What isprobability of getting a red ball? Is it more or less than getting a yellow ball?​

Answer»

<P>Step-by-step explanation:

Probability of an EVENT P(E)=

TotalNo.ofOutcomes

No.ofFavourableOutcomes

Here,

FAVOURABLE Outcomes = Getting a Red ball

Number of Favourable Outcomes = Number of Red BALLS =4

Total Number of Outcomes =6 = Total Number of Balls

⇒P(E)=

6

4

=

3

2

helpful to

37.

Factorise 14 pq -35 pqr.​?who will answer this question they will get 200rupees in online payment please send your number with answer 200 will get for the person who will answer first

Answer»

Answer:

7pq ( 2 - 5r)

Step-by-step explanation:

14pq - 35 PQR

7pq ( 2 - 5r )

(NOTE : I don't want any money thank you very MUCH I just want to help you)

Hope it helps!!

38.

Draw a histogram for the data by making a frequency table with intervals as 800-810, 810-820 and so on.The weekly wages (in ₹) of 30 workers in a factory are:830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840​

Answer»

Answer:

804, 808, 812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840 is the correct answer

please SET me Brainlist

39.

14. A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. Whatis the probability that the ball drawn is red?12 ​

Answer»

\large\maltese {\textsf{\textbf{\: Given~:}}}

It is given that a BAG CONTAINS 3 RED and 5 black balls.

\\

\large \maltese{\textsf{\textbf{ \: To \: find \: :}}}

We have to find the probability of red ball when DRAWN randomly from the bag.

\\

\large \maltese{\textsf{\textbf{ \: Solution \: :}}}

  • Total no. of balls in bag = 5+3 = 8
  • No. of red balls = 3

\boxed{\red{\pmb{\rm Probability \: of \: getting \: a \: red \: ball= \cfrac{No. \: of \: red \: balls}{Total \: no. \: of \: balls} }}}

{:\implies}\rm \cfrac{3}{8}

\boxed{\red{\pmb{\rm \therefore \: Probability \: of \: getting \: a \: red \: ball= \frac{3}{8}  \: (or) \: 0.375.}}}

\\

\large \maltese{\textsf{\textbf{ \: Must \: remember \: : }}}

  • If the total number of trials is 'n' then the probability of event D happening is :

\rm{P(D) =  \cfrac{No. \: of \: trials \: in \: which \:  the \: event \: happened}{Total \: no. \: of \: trials} }

  • Probability of event can be as :

\rm 0 \geqslant  P(E)\geqslant 1

\\

_____________________________

Swipe the screen from left to right in order to view the answer completely!

40.

1soluethe following question7 Factoris 11227 My representing thisnumber is a x2 + bxtcfro form)​

Answer»

ANSWER:

THANKS for the MEETING on

41.

18. Case Study based-2:In an international school in Hyderabad organised an Interschool Throwball Tournament forgiris just aftthe pre- board exam. The throw ball team was very excited. The team captain Anjali directed the teamassemble in the ground for practices. Only three girls Priyanshi, Swetha and Aditi showed up. The restnot come on the pretext of preparing for pre-boardexam. Anjali drew a circle of radius 5 m on the grouThe centre A was the position of Priyanshi. She marked a point N, 13 m away from centre A as herposition. From the point n, she drew two tangential lines NS and NR and gave positions S andSwetha and Aditi. Anjali throws the ball to Priyanshi, Priyanshi throws it to Swetha, Swetha throwsAnjali, Anjali throws it to Aditi, Aditi throws it to Priyanshi, Priyanshi throws it to Swetha and so on.sl-Shweta15 mnjali11N-A ('Piffanshi13 m​

Answer»

ANSWER:

BURNS untucked SHRUGS fundraise JAUNDICE ICEBERGS

42.

3. ) A rectangular prism measures 10 cm by 7 cm by 3 cm, what is the surfacearea?A 302 cm²B. 245 cm²C. 242 cm²D.200 cm²​

Answer»

Answer:

♢ Surface area of the prism = 242 cm².

SOLUTION

Length of the rectangular prism = 10cm.

Breadth of the rectangular prism = 7cm.

Height of the rectangular prism = 3cm.

The rectangular prism is actually in the shape of a cuboid.

TSA

Total Surface Area (TSA) of a cuboid = 2(lb + bh + LH) , Where l is the length , b is the breadth and h is the height of the cuboid.

Here ,

l = 10cm.

b = 7cm.

h = 3cm.

⇒ TSA of the cuboid = 2(10×7 + 7×3 + 10×3)

⇒ TSA of the cuboid = 2(70 + 21 + 30)

⇒ TSA of the cuboid = 2 × 121

⇒ TSA of the cuboid = 242 cm².

LSA

Lateral surface area (LSA) of a cuboid = 2(l + b) × h , Where l is the length , b is the breadth and h is the height of the cuboid.

Here ,

l = 10cm.

b = 7cm.

h = 3cm.

⇒ LSA of the cuboid = 2( 10 + 7) × 3

⇒ LSA of the cuboid = 2 × 17 × 3

⇒  LSA of the cuboid = 102 cm²

43.

A path 3 m wide runs along the inside of a rectangular plot of dimensions 30 m x 24 m. Find the cost oflevelling the path at the rate of Rs. 32 per sq. m.​

Answer»

Step-by-step EXPLANATION:

tgk-xgfd-tkp

or

8327740401

1111

come on.

44.

From a circular card sheet of radius 14cm, two circles of radius 3.5cm and a rectangle oflength 3cm and breadth 1cm are removed. Find the area of the remaning sheet22(Take a = )7​

Answer»

Answer:

23 is the correct answer

please set me Brainlist

45.

4. एक धन 15 वर्षों में स्वयं का तीन गुना होजाता है, तो वह कितने वर्षों में स्वयं का5 गुना हो जाएगा?(a) 21 वर्ष(b) 24 वर्ष(c) 18 वर्ष(d) 30 वर्ष​

Answer»

Answer:

L THINK answer number B 24 years

46.

X and x + y are the square of two consecutivenatural number. What is the square of the nextnatural number?​

Answer»

Question.

If x,x+y are the square of two consecutive NATURAL NUMBERS, what is the next square?

Keys.

For convenience, let the consecutive numbers be a-1,a,a+1.

We are going to look for the DIFFERENCE.

Solution.

Given that, two squares are x,x+y.

What is the next square?

Let the three consecutive numbers be a-1,a,a+1.

The difference of the 1st and 2nd squares is (x+y)-x=a^2-(a-1)^2.

\therefore y=2a-1

The difference of the 2nd and 3rd squares is (a+1)^2-a^2=2a+1=y+2.

So, the next square is \boxed{x+2y+2}.

Verification

We can find the next square without actual calculation.

Given that two squares are 99^2=9801, 100^2=10000 the next square is 9801+2\times 199+2=10201.

As 101^2=10201, we FOUND a new square using this LOGIC.

47.

The population ( in lakhs) of six Indian states as estimated in 2001 is given belowPopulation (in lakhs)820270StateBiharJharkhandUttar PradeshUttarakhandMadhya PradeshChhattisgarh106080600210Represent the above data by a bar graph using ruler and pencil.​

Answer»

Answer:

Employment 11 14 17 Total 1 18 56 89 163 0 13 16 8 37 Total 31 72 97 200 What is the VARIANCE of employment? GIVE your answer to two decimal places.

48.

The area of trapezium is 850cm2 and length of one of the parallel side is 34 cm and its height is 20cm find the length of the other parallel side​

Answer»

ANSWER:

Area of TRAPEZIUM is 850 cm

LENGTH is 34 cm

height is 20 cm

length of other SIDE is

1/2 (34+x) *20 =850

1/2(34+x) 10 =850

34*10 +x*10 =850

340 +10x= 850cm

10x=850-340

10x=510

x=510/10

x=51

49.

*2 रू 50 पैसे ; 3 रू 50 पैसे या दोन राशींमधील गुणोत्तर संक्षिप्त रुपात लिहा.*1️⃣ 5:72️⃣ 7:53️⃣ 5:64️⃣ 4:5​

Answer»

ANSWER:

5:6

Step-by-step EXPLANATION:

this is your answer OK

50.

11:34 AM I 10.5KB/s...ان تر استVo56mymapit.in/#/test/115674444Finish test00:44:52=Question No. 43 of 45Ue*(sinx+cosx) dx =COSX​

Answer»

ANSWER:

SORRY ... UMM what do you MEAN ??