332354 + Interview Questions in Secondary School in Math

1.	Question attached above.
Answer» ONG>Step-by-step explanation: ZEROES of F(X) is zero

1.

Question attached above.

Answer» ONG>Step-by-step explanation:

ZEROES of F(X) is zero

Discussion

2.	12654862+654555×99-555×58³×55²-1995² who will answer correctly with explanation will get thanks, brainliest and ratings
Answer» ONG>ANSWER: -337495183220 explanation: 12654862+654555×99-555×58³×55²-1995² 77455807-555×195112×3025-3980025 77455807-327568659000-3980025 77455807-327572639025 -337495183220

2.

12654862+654555×99-555×58³×55²-1995² who will answer correctly with explanation will get thanks, brainliest and ratings

Answer» ONG>ANSWER:

-337495183220

explanation:

12654862+654555×99-555×58³×55²-1995²

77455807-555×195112×3025-3980025

77455807-327568659000-3980025

77455807-327572639025

-337495183220

Discussion

3.	7/2Evaluate2x cos x dx
Answer» ONG>ANSWER: sdfyh adfgjkkfrhngretunfszgbnhddgjkklfdetui

Discussion

4.	Principal= 12000 R=10% T=4year
Answer» to find in that QUESTION Step-by-step EXPLANATION: I think find PROFIT percent

4.

Principal= 12000 R=10% T=4year

Answer»

to find in that QUESTION

Step-by-step EXPLANATION:

I think find PROFIT percent

Discussion

5.	10. x3 - 6x2 +12x -35बीज बोने सॉन्ग का गोली उत्पादक विश्लेषण करो
Answer» ONG>ANSWER: (x-5)(x^2−x+7) Step-by-step explanation: Factor x^3−6x^2+12x−35 = x^3−6x^2+12x−35 =(x−5)(x^2−x+7) (I hope this was HELPFUL) >;D

5.

10. x3 - 6x2 +12x -35बीज बोने सॉन्ग का गोली उत्पादक विश्लेषण करो

Answer» ONG>ANSWER:

(x-5)(x^2−x+7)

Step-by-step explanation:

Factor x^3−6x^2+12x−35

= x^3−6x^2+12x−35

=(x−5)(x^2−x+7)

(I hope this was HELPFUL) >;D

Discussion

6.	How many expressions are there in 5xy(2) what are they ?
Answer» ong>ANSWER: Only one TERM 5xy². . . have a GREAT day..

6.

How many expressions are there in 5xy(2) what are they ?

Answer»

ong>ANSWER:

Only one TERM 5xy².

.

have a GREAT day..

Discussion

7.	(d) 10cm (0 sm18. Case Study Based-2A 110 m hurdle race is organisedfor a group of 150 athletes.The time, in seconds, taken bythe athletes to run the race aretabulate below:Time (in sec) 13.8 -14.8 -14.0- 14.2- 14.4 14.6-14.0 14.215.014.4 14.6 14.8No. of athletes 24571 48 20(1) What is the class mark of class intervalcorresponding to frequency 48?(a) 14.5(b) 14.7(C) 14.75(d) 14.65(ii) What will be the upper limit of the medianclass?(a) 14.4 (b) 14.2 (C) 14.8 (d) 14.6(iii) Estimate the median time taken by an athleteto finish the race.(a) 14.76 sec(b) 14.58 sec(c) 14.42 sec(d) 14.6 sec(iv) The mean time taken by an athlete is 14.6 sec,then the mode of the given data is:(a) 14.54 sec(b) 14.64 sec(c) 14.94 sec(d) 14.44 sec(V) How many athletes finished the hurdle race inless than 14.6 seconds?(a) 71(b) 76(C) 82(d) 91
Answer» ONG>Answer: SORRY but I don't understand question pls MARK me as BRAINLIEST

7.

(d) 10cm (0 sm18. Case Study Based-2A 110 m hurdle race is organisedfor a group of 150 athletes.The time, in seconds, taken bythe athletes to run the race aretabulate below:Time (in sec) 13.8 -14.8 -14.0- 14.2- 14.4 14.6-14.0 14.215.014.4 14.6 14.8No. of athletes 24571 48 20(1) What is the class mark of class intervalcorresponding to frequency 48?(a) 14.5(b) 14.7(C) 14.75(d) 14.65(ii) What will be the upper limit of the medianclass?(a) 14.4 (b) 14.2 (C) 14.8 (d) 14.6(iii) Estimate the median time taken by an athleteto finish the race.(a) 14.76 sec(b) 14.58 sec(c) 14.42 sec(d) 14.6 sec(iv) The mean time taken by an athlete is 14.6 sec,then the mode of the given data is:(a) 14.54 sec(b) 14.64 sec(c) 14.94 sec(d) 14.44 sec(V) How many athletes finished the hurdle race inless than 14.6 seconds?(a) 71(b) 76(C) 82(d) 91

Answer» ONG>Answer:

SORRY but I don't understand question

pls MARK me as BRAINLIEST

Discussion

8.	Find the amount if p = ₹ 5000, R= 8 p.c.p.aN = 2 years with respect to compond interset compoundi
Answer» Solution:- ━━━━━━━━━━━━━━━━━━━━━━━━━━ $\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$ ◍ Here, the QUESTION has given us the principal, rate of interest and time that is RS. 5,000, 8% per annum and for 2 years respectively. Now, the question has asked us to find the COMPOUND interest on it. So to get the answer we need to apply the formula of amount FIRST then we will subtract the principal from amount to get CI. ANSWER:- ◈ Amount = Rs. 5,832 ◈ CI = Rs. 832 GIVEN:- ☆ Principal = Rs. 5,000 ☆ Rate of Interest = 8% per annum ☆ Time = 2 years TO FIND:- ↠Amount he will get back = ? FORMULA:- ⬤ Amount = P[1 + (R / 100)]^t ⬤ CI = Amount - Principal SOLVING BY APPLYING THE FORMULA:- ⇨ Principal = Rs. 5,000 ⇨ Rate = 8% ⇨ Time = 2 years ⇨ Simple Interest = P × R × T / 100 ➢ Amount = 5,000[1 + (8 / 100)]² ➢ Amount = 5,000[100 + 8 / 100]² ➢ Amount = 5,000[108 / 100]² ➢ Amount = 5,000 × 108/100 × 108/100 ➢ Cancelling the zeros. ➢ Amount = 5 × 108² / 10 ➢ Amount = 58,320 / 10 ➢ Amount = 58,320 / 10 = 5,832 ➢ Amount = Rs. 5,832 Thus, the amount is Rs. 5,832. ⇨ Compound Interest = Amount - Principal ➢ CI = 5,832 - 5,000 ➢ CI = 5,832 - 5,000 = 832 ➢ CI = Rs. 832 Hence, we got the answer. The CI is Rs. 832. ━━━━━━━━━━━━━━━━━━━━━━━━━━

8.

Find the amount if p = ₹ 5000, R= 8 p.c.p.aN = 2 years with respect to compond interset compoundi

Answer»

Solution:-

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$

◍ Here, the QUESTION has given us the principal, rate of interest and time that is RS. 5,000, 8% per annum and for 2 years respectively. Now, the question has asked us to find the COMPOUND interest on it. So to get the answer we need to apply the formula of amount FIRST then we will subtract the principal from amount to get CI.

ANSWER:-

◈ Amount = Rs. 5,832

◈ CI = Rs. 832

GIVEN:-

☆ Principal = Rs. 5,000

☆ Rate of Interest = 8% per annum

☆ Time = 2 years

TO FIND:-

↠Amount he will get back = ?

FORMULA:-

⬤ Amount = P[1 + (R / 100)]^t

⬤ CI = Amount - Principal

SOLVING BY APPLYING THE FORMULA:-

⇨ Principal = Rs. 5,000

⇨ Rate = 8%

⇨ Time = 2 years

⇨ Simple Interest = P × R × T / 100

➢ Amount = 5,000[1 + (8 / 100)]²

➢ Amount = 5,000[100 + 8 / 100]²

➢ Amount = 5,000[108 / 100]²

➢ Amount = 5,000 × 108/100 × 108/100

➢ Cancelling the zeros.

➢ Amount = 5 × 108² / 10

➢ Amount = 58,320 / 10

➢ Amount = 58,320 / 10 = 5,832

➢ Amount = Rs. 5,832

Thus, the amount is Rs. 5,832.

⇨ Compound Interest = Amount - Principal

➢ CI = 5,832 - 5,000

➢ CI = 5,832 - 5,000 = 832

➢ CI = Rs. 832

Hence, we got the answer. The CI is Rs. 832.

━━━━━━━━━━━━━━━━━━━━━━━━━━

Discussion

9.	Convert the given ratio into percentage . 8:10
Answer» ONG>Answer: 80 PERCENT. Step-by-step explanation: 8:10=8/10 percentage of the FOLLOWING FRACTION:- 8/10×100=80 percent.

9.

Convert the given ratio into percentage . 8:10

Answer» ONG>Answer:

80 PERCENT.

Step-by-step explanation:

8:10=8/10

percentage of the FOLLOWING FRACTION:-

8/10×100=80 percent.

Discussion

10.	I) Write the quadratic equation 2x + 3x4 = 9 in standerd form alsowrite values of a, b, c .
Answer» ONG>Answer: 2x+3x+4=9 [A} a=2 b=3 c=5

Discussion

11.	7cm long stick cut in three pieces. Length of each piece is natural number. What is the probability of forming triangle from the three pieces of stick?
Answer» ONG>Answer: 1+2+4 1+3+3 1+1+5 2+2+3

11.

7cm long stick cut in three pieces. Length of each piece is natural number. What is the probability of forming triangle from the three pieces of stick?

Answer» ONG>Answer:

1+2+4

1+3+3

1+1+5

2+2+3

Discussion

12.	Find the general solution of an + 5an-1+6 a,-2 = 3n2
Answer» ONG>ANSWER: _ _ L L _ N N _ _ _ _ Fill in the Blank (ANOTHER word for a time period)

Discussion

13.	In the adjoiningfigure, if AB \|\| CD,then x =In the adioining
Answer» Correct option is B 55 ∠GEF=180−∠CEF(∵∠GEF and ∠CEF are COMPLEMENTARY angles) ∴∠GEF=30 o and ∠GCD=∠GEF (from the FIGURE, CD∣∣EF) ⇒∠GCD=30 o Now, ∠BCD=∠BCG+∠GCD ⇒∠BCD=25 o +30 o =55 o ∠ABC=∠BCD(∵AB∣∣CD) ∠ABC=x=55 o Therefore the value of x is 55.

13.

In the adjoiningfigure, if AB || CD,then x =In the adioining

Answer»

Correct option is

B

55 ∠GEF=180−∠CEF(∵∠GEF and ∠CEF are COMPLEMENTARY angles)

∴∠GEF=30

o

and ∠GCD=∠GEF (from the FIGURE, CD∣∣EF)

⇒∠GCD=30

o

Now, ∠BCD=∠BCG+∠GCD

⇒∠BCD=25

o

+30

o

=55

o

∠ABC=∠BCD(∵AB∣∣CD)

∠ABC=x=55

o

Therefore the value of x is 55.

Discussion

14.	where a and b are natural number find (a + b).
Answer» $\begin{gathered}\Large{\bold{{\underline{Formula \: Used - }}}} \end{gathered}$ $\boxed{ \sf \: {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy}$ $\boxed{ \sf \: {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy}$ $\large\underline{\sf{Solution-}}$ CONSIDER, $\sf \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{13 + \sqrt{48} } } } \bigg)$ $\sf \: = \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{12 + 1 + \sqrt{2 \times 2 \times 4 \times 3} } } } \bigg)$ $\sf \: = \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{ {( \sqrt{12)} }^{2} + {(1)}^{2} + 2 \sqrt{12} } } } \bigg)$ $\sf \: = 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{ {\bigg( \sqrt{12} + 1 \bigg) }^{2} } } } \bigg)$ $\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \because \: {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy }$ $\sf \: = 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{12} - 1 } } \bigg)$ $\sf \: = 2\bigg( \sqrt{3 + \sqrt{4 - \sqrt{12} } } \bigg)$ $\sf \: = 2\bigg( \sqrt{3 + \sqrt{3 + 1 - \sqrt{2 \times 2 \times 3}} } \bigg)$ $\sf \: = 2\bigg( \sqrt{3 + \sqrt{ {( \sqrt{3)} }^{2} + {(1)}^{2} - 2 \sqrt{3}} } \bigg)$ $\sf \: = \: 2\bigg( \sqrt{3 + \sqrt{ {( \sqrt{3} - 1) }^{2} } } \bigg)$ $\sf \: = \: 2 \sqrt{\bigg(3 + \sqrt{3} - 1 \bigg) }$ $\sf \: = \: 2 \sqrt{\bigg(2 + \sqrt{3} \bigg) }$ $\sf \: = \: 2\sqrt{ \bigg( \dfrac{3}{2} + \dfrac{1}{2} + \sqrt{3} \times \dfrac{2}{ \sqrt{2} \times \sqrt{2} } \bigg) }$ $\sf \: = \: 2 \sqrt{\bigg( {\bigg(\dfrac{ \sqrt{3} }{ \sqrt{2} } \bigg) }^{2} + {\bigg(\dfrac{1}{ \sqrt{2} } \bigg) }^{2} + 2 \times \dfrac{ \sqrt{3} }{ \sqrt{2} } \times \dfrac{1}{ \sqrt{2} } \bigg) }$ $\sf \: = \: 2 \sqrt{ {\bigg(\dfrac{ \sqrt{3} }{ \sqrt{2} } + \dfrac{1}{ \sqrt{2} } \bigg) }^{2} }$ $\sf \: = \: 2\bigg( \dfrac{ \sqrt{3} }{ \sqrt{2} } + \dfrac{1}{ \sqrt{2} } \bigg)$ $\sf \: = \: \sqrt{2} \times \sqrt{2} \times \bigg(\dfrac{ \sqrt{3} }{ \sqrt{2} } + \dfrac{1}{ \sqrt{2} } \bigg)$ $\sf \: = \: \sqrt{6} + \sqrt{2}$ So, $\rm :\implies\:\sf \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{13 + \sqrt{48} } } } \bigg) = \sqrt{6} + \sqrt{2}$ As it is GIVEN that, $\sf \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{13 + \sqrt{48} } } } \bigg) = \sqrt{a} + \sqrt{b}$ So, On COMPARING we GET, $\rm :\implies\: \sqrt{a} + \sqrt{b} = \sqrt{6} + \sqrt{2}$ $\bf\implies \:a = 6 \: and \: b = 2 \: \: or \: a = 2 \: and \: b = 6$ So, $\bf\implies \:a + b = 2 + 6 = 8$ $\overbrace{ \underline { \boxed { \rm \therefore \: The \: value \: of \: a \: + \: b \: = \: 8 }}}$

14.

where a and b are natural number find (a + b).

Answer»

$\begin{gathered}\Large{\bold{{\underline{Formula \: Used - }}}} \end{gathered}$

$\boxed{ \sf \: {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy}$

$\boxed{ \sf \: {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy}$

$\large\underline{\sf{Solution-}}$

CONSIDER,

$\sf \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{13 + \sqrt{48} } } } \bigg)$

$\sf \: = \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{12 + 1 + \sqrt{2 \times 2 \times 4 \times 3} } } } \bigg)$

$\sf \: = \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{ {( \sqrt{12)} }^{2} + {(1)}^{2} + 2 \sqrt{12} } } } \bigg)$

$\sf \: = 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{ {\bigg( \sqrt{12} + 1 \bigg) }^{2} } } } \bigg)$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \because \: {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy }$

$\sf \: = 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{12} - 1 } } \bigg)$

$\sf \: = 2\bigg( \sqrt{3 + \sqrt{4 - \sqrt{12} } } \bigg)$

$\sf \: = 2\bigg( \sqrt{3 + \sqrt{3 + 1 - \sqrt{2 \times 2 \times 3}} } \bigg)$

$\sf \: = 2\bigg( \sqrt{3 + \sqrt{ {( \sqrt{3)} }^{2} + {(1)}^{2} - 2 \sqrt{3}} } \bigg)$

$\sf \: = \: 2\bigg( \sqrt{3 + \sqrt{ {( \sqrt{3} - 1) }^{2} } } \bigg)$

$\sf \: = \: 2 \sqrt{\bigg(3 + \sqrt{3} - 1 \bigg) }$

$\sf \: = \: 2 \sqrt{\bigg(2 + \sqrt{3} \bigg) }$

$\sf \: = \: 2\sqrt{ \bigg( \dfrac{3}{2} + \dfrac{1}{2} + \sqrt{3} \times \dfrac{2}{ \sqrt{2} \times \sqrt{2} } \bigg) }$

$\sf \: = \: 2 \sqrt{\bigg( {\bigg(\dfrac{ \sqrt{3} }{ \sqrt{2} } \bigg) }^{2} + {\bigg(\dfrac{1}{ \sqrt{2} } \bigg) }^{2} + 2 \times \dfrac{ \sqrt{3} }{ \sqrt{2} } \times \dfrac{1}{ \sqrt{2} } \bigg) }$

$\sf \: = \: 2 \sqrt{ {\bigg(\dfrac{ \sqrt{3} }{ \sqrt{2} } + \dfrac{1}{ \sqrt{2} } \bigg) }^{2} }$

$\sf \: = \: 2\bigg( \dfrac{ \sqrt{3} }{ \sqrt{2} } + \dfrac{1}{ \sqrt{2} } \bigg)$

$\sf \: = \: \sqrt{2} \times \sqrt{2} \times \bigg(\dfrac{ \sqrt{3} }{ \sqrt{2} } + \dfrac{1}{ \sqrt{2} } \bigg)$

$\sf \: = \: \sqrt{6} + \sqrt{2}$

So,

$\rm :\implies\:\sf \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{13 + \sqrt{48} } } } \bigg) = \sqrt{6} + \sqrt{2}$

As it is GIVEN that,

$\sf \: 2\bigg( \sqrt{3 + \sqrt{5 - \sqrt{13 + \sqrt{48} } } } \bigg) = \sqrt{a} + \sqrt{b}$

So,

On COMPARING we GET,

$\rm :\implies\: \sqrt{a} + \sqrt{b} = \sqrt{6} + \sqrt{2}$

$\bf\implies \:a = 6 \: and \: b = 2 \: \: or \: a = 2 \: and \: b = 6$

So,

$\bf\implies \:a + b = 2 + 6 = 8$

$\overbrace{ \underline { \boxed { \rm \therefore \: The \: value \: of \: a \: + \: b \: = \: 8 }}}$

Discussion

15.	Can AB=7cm,BC=10cm,CA=6cm can be use to construct a unique triangle?
Answer» ONG>Step-by-step EXPLANATION: YES we can. Hope it HELPS you.

15.

Can AB=7cm,BC=10cm,CA=6cm can be use to construct a unique triangle?

Answer» ONG>Step-by-step EXPLANATION:

YES we can.

Hope it HELPS you.

Discussion

16.	6202+18929 = ???-_-
Answer» ONG>Answer: 6202+18929 = 25,131 Step-by-step explanation: PLS MARK me as brainliest

16.

6202+18929 = ???-_-

Answer» ONG>Answer:

6202+18929 = 25,131

Step-by-step explanation:

PLS MARK me as brainliest

Discussion

17.	If a and b are co-prime numbers, then find the LCM (ma, mb).
Answer» ong>Answer: We KNOW that the LCM of TWO co-prime numbers is EQUAL to the PRODUCT of the two numbers. Since 'm' is present in both the numbers 'ma' and 'mb', so in the lcm of 'ma' and 'mb', we will multiply 'm'. Thus, the lcm of 'ma' and 'mb' is 'mab

17.

If a and b are co-prime numbers, then find the LCM (ma, mb).

Answer»

ong>Answer:

We KNOW that the LCM of TWO co-prime numbers is EQUAL to the PRODUCT of the two numbers. Since 'm' is present in both the numbers 'ma' and 'mb', so in the lcm of 'ma' and 'mb', we will multiply 'm'. Thus, the lcm of 'ma' and 'mb' is 'mab

Discussion

18.	Write a formula of nth term of A.P.
Answer» ong>ANSWER: The NTH TERM of AP an = a + (n – 1) × d Sum of n terms in AP S = n/2[2a + (n − 1) × d]

18.

Write a formula of nth term of A.P.

Answer»

ong>ANSWER:

The NTH TERM of AP an = a + (n – 1) × d

Sum of n terms in AP S = n/2[2a + (n − 1) × d]

Discussion

19.	1 Find the sum of the following numbers 62.099 2.505 6,75.694 75.889 B 1.38.673C. 8.16.178D. 8,16,187
Answer» ONG>ANSWER: TH answer is 816.187...

Discussion

20.	1) If Cos A=2/5then find the value of 4 + 4 tan²A.
Answer» ONG>Step-by-step EXPLANATION: REFER to the ATTACHMENT

Discussion

21.	X^x^x solved this problem
Answer» MATE!!! Your SOLUTION is in ATTACHMENT, HOPE it HELPS

21.

X^x^x solved this problem

Answer» MATE!!!

Your SOLUTION is in ATTACHMENT,

HOPE it HELPS

Discussion

22.	In the given fig O is centre of circle PT & QT are tangents to circle then LPOQ--------
Answer» ong>ANSWER: Write an essay about the GIVEN topic. "Your inspiration in brainly" (His USERNAME,his ACCOUNT,His rank,How do you know him/her,His QUALITIES,why you prefer him/her as your inspiration,what help did you get from him)

22.

In the given fig O is centre of circle PT & QT are tangents to circle then LPOQ--------

Answer»

ong>ANSWER:

Write an essay about the GIVEN topic.

"Your inspiration in brainly"

(His USERNAME,his ACCOUNT,His rank,How do you know him/her,His QUALITIES,why you prefer him/her as your inspiration,what help did you get from him)

Discussion

23.	The (V) correct option: - (1X5=5)il9c)d) None of these3a1. Multiplicative inverseof isa) b)2. (4/3) ==?b) 2/33. 70.9 x 71.6 = ?b) 1.24. (2x + 5) (2x - 5)a) 4x2 + 25b) 4x2 - 252c) 1d) 0a) 0.12c) 0.75d) 12c) 4x2 - 10x + 25d) 4x2 + 10x - 255. If 3 (t-3) = 5 (2t + 1) then t = ?a) -2 b) 2d) 3c)-3(1X5= 5)72. Fill in the blanks: -
Answer» ONG>Answer: 1357908742454666258380842

Discussion

24.	Simplifya) (-3) 3 x (-5) ² x (-10)
Answer» =(-3)3×25×(-10) =(-3)3×(-250) =(-9)×(-250) =2250

24.

Simplifya) (-3) 3 x (-5) ² x (-10)

Answer»

=(-3)3×25×(-10)

=(-3)3×(-250)

=(-9)×(-250)

=2250

Discussion

25.	draw a ray diagram to show the formation of image by a convex lens when object is placed at away from 2F1. Also write nature and size of image.
Answer» ong>Answer: The CASE when object is between F 1 and the OPTICAL centre O of the lens shows the use of convex lens as a magnifying glass . This is because here the image formed is erect and magnified . Step-by-step EXPLANATION: diagram below

25.

draw a ray diagram to show the formation of image by a convex lens when object is placed at away from 2F1. Also write nature and size of image.

Answer»

ong>Answer:

The CASE when object is between F

1

and the OPTICAL centre O of the lens shows the use of convex lens as a magnifying glass . This is because here the image formed is erect and magnified .

Step-by-step EXPLANATION:

diagram below

Discussion

26.	B) y^2 +1/3 y = 2 solve this equation using formula.
Answer» ONG>ANSWER: which class QUESTION i am 8TH form

Discussion

27.	How to find a equation whose sum of roots is given?
Answer» ong>Step-by-step explanation: the sum of its roots = –b/a and the product of its roots = c/a. A quadratic EQUATION MAY be EXPRESSED as a product of two binomials. Here, a and b are called the roots of the GIVEN quadratic equation. Now, let's calculate the roots of an equation x2+5x+6 = 0.

27.

How to find a equation whose sum of roots is given?

Answer»

ong>Step-by-step explanation:

the sum of its roots = –b/a and the product of its roots = c/a. A quadratic EQUATION MAY be EXPRESSED as a product of two binomials. Here, a and b are called the roots of the GIVEN quadratic equation. Now, let's calculate the roots of an equation x2+5x+6 = 0.

Discussion

28.	Please do help me for solving this problems
Answer» ong>ANSWER: It's your Open Book Test. Step-by-step explanation: Do it from your book. HINT:- See the questions you have solved earlier. In this test, only the values are changed. If you have concept and if you LISTENED to your teacher CAREFULLY, this is NOTHING for you but a piece of cake.

28.

Please do help me for solving this problems

Answer»

ong>ANSWER:

It's your *Open Book Test*.

Step-by-step explanation:

Do it from your book.

HINT:-

See the questions you have solved earlier.

In this test, only the values are changed.

If you have concept and if you LISTENED to your teacher CAREFULLY, this is NOTHING for you but a piece of cake.

Discussion

29.	Two digit numbers are formed using the digits 2, 3 and 5 without repeating them.write the sample space
Answer» 25, 32,35,52,53 total 6 POSSIBLE no.

Discussion

30.	किसी समकोण त्रिभुज ABC में angal b=90° है यदि AC=13 cm,BC= 5 cm है तो AB ज्ञात कीजिए।
Answer» er: 12 is the answer mate.. Step-by-step explanation: In this right TRIANGLE ABC, Angle B= 90° BC=5CM AC=13CM By applying PYTHAGORAS theorem- (H)²=(B)² + (A)² AC²= BC² + AB² 13² = 5² + AB² 169 = 25 + AB² AB² = 169-25 AB² =144 AB=√144 AB= 12 Hope it helps you

30.

किसी समकोण त्रिभुज ABC में angal b=90° है यदि AC=13 cm,BC= 5 cm है तो AB ज्ञात कीजिए।

Answer»

er:

12 is the answer mate..

Step-by-step explanation:

In this right TRIANGLE ABC,

Angle B= 90°

BC=5CM

AC=13CM

By applying PYTHAGORAS theorem-

(H)²=(B)² + (A)²

AC²= BC² + AB²

13² = 5² + AB²

169 = 25 + AB²

AB² = 169-25

AB² =144

AB=√144

AB= 12

Hope it helps you

Discussion

31.	Find the quadratic equation of (2x-1)(x-3)=(x+5)(x-1)
Answer» ONG>ANSWER: Step-by-step EXPLANATION: The answer is in the IMAGE

31.

Find the quadratic equation of (2x-1)(x-3)=(x+5)(x-1)

Answer» ONG>ANSWER:

Step-by-step EXPLANATION:

The answer is in the IMAGE

Discussion

32.	B) y2 +1/3 y = 2 solve this equation using formula.
Answer» ong>Answer: 0 Step-by-step explanation: y2 + 1/3y = 2 y2+3y = 1+2. , 5 y2 = 3 , y2 = 5-3 = 2 , y2 = 2 , y = 2/2= 0 .

32.

B) y2 +1/3 y = 2 solve this equation using formula.

Answer»

ong>Answer:

0

Step-by-step explanation:

y2 + 1/3y = 2

y2+3y = 1+2. , 5 y2 = 3 , y2 = 5-3 = 2 , y2 = 2 , y = 2/2= 0 .

Discussion

33.	6. Draw the graph of y=-3x
Answer» ong>Step-by-step explanation: y = mx + c , y = 3. MARK me as BRILLIANT

33.

6. Draw the graph of y=-3x

Answer»

ong>Step-by-step explanation:

y = mx + c , y = 3. MARK me as BRILLIANT

Discussion

34.	17. तीन घण्टे क्रमश: 15 सेकण्ड, 20 सेकण्ड और 24 सेकण्ड के अन्तर से बजते हैं। वे 12 मिनट तक लगातार बजते रहते हैं। इस अवधि में वेएकसाथ बजेंगे(a) 4 बार (b)3 बार (c)6 बार (d) 2 बार
Answer» ONG>ANSWER: COME here CHARU dko-vwmk-ugv

Discussion

35.	Find the polynomial that has a sum 3 and product -2
Answer» ONG>Answer: -b/a= sum of ZEROES =3 -b/a=3 -b/a=9/3 c/a = product of zeroes =-2 c/a=-2 c/a=-6/3 a=3 ,b=-9 ,c=-6 polynomial=ax^2+bx+c 3x^2-9x-6

35.

Find the polynomial that has a sum 3 and product -2

Answer» ONG>Answer:

-b/a= sum of ZEROES =3

-b/a=3

-b/a=9/3

c/a = product of zeroes =-2

c/a=-2

c/a=-6/3

a=3 ,b=-9 ,c=-6

polynomial=ax^2+bx+c

3x^2-9x-6

Discussion

36.	2764 reduced the fraction into lowest term.
Answer» > ${<klux>2</klux>}^{5}$ 2 $\times 2 \ \times 2 \times 2 \times 2 \times 2$

Discussion

37.	1 In the figureMN is parallel to QRpm - ccm PO = 10 cm(.(@) What is length of MQ ?(6) What is PN NR ?2ZQ
Answer» ONG>Answer: Step-by-step EXPLANATION: Answer:In the figure PM=6cm PQ=10cm THEREFORE MQ=PQ-PM=10-6=4cm MQ=4cm In the TRIANGLE PQR there are parallel line MQ We need to prove that PQ:NR For that we need to draw a parallel line from the point p and in the theorem of parallel line is any two line are parallel and a line passes through that point will be in the same ratio Therefore:PN:NR There the ratio will be 3:2 Because the length of side PM:MQ=6:4 and it is 3:2(a shortest form of 6:4)

37.

1 In the figureMN is parallel to QRpm - ccm PO = 10 cm(.(@) What is length of MQ ?(6) What is PN NR ?2ZQ

Answer» ONG>Answer:

Step-by-step EXPLANATION:

Answer:In the figure PM=6cm

PQ=10cm

THEREFORE MQ=PQ-PM=10-6=4cm

MQ=4cm

In the TRIANGLE PQR there are parallel line MQ

We need to prove that PQ:NR

For that we need to draw a parallel line from the point p and in the theorem of parallel line is any two line are parallel and a line passes through that point will be in the same ratio

Therefore:PN:NR

There the ratio will be 3:2

Because the length of side PM:MQ=6:4 and it is 3:2(a shortest form of 6:4)

Discussion

38.	2tandtevaluate oIta?
Answer» ONG>ANSWER: COME here CHARU dko-vwmk-ugv

Discussion

39.	Sin 30°tan 45° + cos 60°/sec 30° + cos 60° +cot 450
Answer» EGREE = 1/2 Tan 45degree=1 Cos60=1/2 Sec30=2/root3 Cot450=cos(390+60)

Discussion

40.	Which of the following numbers cannot represent probability a)0.893b)1.02c)4/5d)none of above
Answer» H of the FOLLOWING NUMBERS cannot REPRESENT probability d)NONE of above

40.

Which of the following numbers cannot represent probability a)0.893b)1.02c)4/5d)none of above

Answer» H of the FOLLOWING NUMBERS cannot REPRESENT probability

d)NONE of above

Discussion

41.	3a+1/2a=6, find 4a²+1/9a²
Answer» ONG>ANSWER: I am afraid only 4 people MAKE me brainleast pls make me brainleast Step-by-step explanation: pls follow mohdmansoorali2666 join

41.

3a+1/2a=6, find 4a²+1/9a²

Answer» ONG>ANSWER:

I am afraid only 4 people MAKE me brainleast pls make me brainleast

Step-by-step explanation:

pls follow mohdmansoorali2666 join

Discussion

42.	(2root 6 ) square(2)
Answer» ONG>ANSWER: 24 IA the answer of your QUESTIONS

Discussion

43.	Fnd the zeroes of the polynomial x²+ 2x + 1 ?
Answer» ong>Answer: Step-by-step EXPLANATION: x² + 2x + 1 = 0 ⇒x² + X + x + 1 = 0 ⇒(x² + x) + (x + 1) = 0 ⇒x(x + 1) + 1(x + 1) = 0 ⇒(x + 1) (x + 1) = 0 ⇒(x + 1) = 0 or (x + 1) = 0 ⇒x= -1 or x= -1

43.

Fnd the zeroes of the polynomial x²+ 2x + 1 ?

Answer»

ong>Answer:

Step-by-step EXPLANATION:

x² + 2x + 1 = 0

⇒x² + X + x + 1 = 0

⇒(x² + x) + (x + 1) = 0

⇒x(x + 1) + 1(x + 1) = 0

⇒(x + 1) (x + 1) = 0

⇒(x + 1) = 0 or (x + 1) = 0

⇒x= -1 or x= -1

Discussion

44.	Enumerate the functions of the presidentand Council of Ministeas
Answer» FUNCTIONS OF COUNCIL OF MINISTER:- The Council is collectively responsible to the Lok Sabha. It is the duty of the Prime Minister to communicate to the President all DECISIONS of Council of Ministers relating to administration of affairs of the Union and PROPOSALS for legislation and information relating to them. FUNCTION OF PRESIDENT :- The primary duty of the president is to preserve, protect and defend the constitution and the law of India per Article 60. The president appoints the Chief JUSTICE of India and other judges on the advice of the chief justice. HOPE IT HELPS ☺️✌️ MARK ME AS BRAINLIST ❤️

44.

Enumerate the functions of the presidentand Council of Ministeas

Answer» FUNCTIONS OF COUNCIL OF MINISTER:-

The Council is collectively responsible to the Lok Sabha. It is the duty of the Prime Minister to communicate to the President all DECISIONS of Council of Ministers relating to administration of affairs of the Union and PROPOSALS for legislation and information relating to them.

FUNCTION OF PRESIDENT :-

The primary duty of the president is to preserve, protect and defend the constitution and the law of India per Article 60. The president appoints the Chief JUSTICE of India and other judges on the advice of the chief justice.

HOPE IT HELPS ☺️✌️

MARK ME AS BRAINLIST ❤️

Discussion

45.	Plz tell bro plzbsbshduudududududududududuudud
Answer» ONG>Answer: THANK U have a nice DAY...

45.

Plz tell bro plzbsbshduudududududududududuudud

Answer» ONG>Answer:

THANK U

have a nice DAY...

Discussion

46.	A and B are friends and their ages differ by 4years, A being elder.. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C differ by 38 years. Find theages of A and B.
Answer» A n s w e r ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ G i v e n ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ A and B are FRIENDS and their ages differ by 4 YEARS & A is ELDER A's father D is TWICE as old as A B is twice as old as his sister C The age of D and C differ by 38 years ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ F i n d ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ The ages of A and B ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ S o l u t i o n ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Let the age of A be 'a' Let the age of B be 'b' Let the age of C be 'C' Let the age of D be 'D' ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Given that , ages of A and B differ by 4 years & A is elder ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Thus , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ a - b = 4 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ b = a - 4 ⚊⚊⚊⚊ ⓵ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Also given that , A's father D is twice as old as A ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Thus , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ D = 2a ⚊⚊⚊⚊ ⓶ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Given that , B is twice as old as his sister C ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Thus , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf C = \dfrac { b } { 2 }$ ⚊⚊⚊⚊ ⓷ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Also given that , the ages of D and C differ by 38 years ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Clearly D is older then C ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Thus , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ D - C = 38 ⚊⚊⚊⚊ ⓸ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting the value of C from ⓷ to ⓸ ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf D - \dfrac { b } { 2 } = 38$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf \dfrac { 2D - b } { 2 } = 38$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 2D - b = 38 × 2 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 2D - b = 76 ⚊⚊⚊⚊ ⓹ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting D = 2a from ⓶ to ⓹ ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 2(2a) - b = 76 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 4a - b = 76 ⚊⚊⚊⚊ ⓺ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting b = a - 4 from ⓵ to ⓺ ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 4a - b = 76 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 4a - (a - 4) = 76 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 4a - a + 4 = 76 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 3a = 76 - 4 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 3a = 72 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf a = \dfrac { 72 } { 3 }$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : : ➨ a = 24 ⚊⚊⚊⚊ ⓻ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Hence the age of A is 24 years ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting a = 24 from ⓻ to ⓵ ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ b = a - 4 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ b = 24 - 4 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : : ➨ b = 20 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Hence the age of B is 20 years ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ∴ The ages of A & B are 24 years & 20 years respectively

46.

A and B are friends and their ages differ by 4years, A being elder.. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C differ by 38 years. Find theages of A and B.

Answer»

A n s w e r

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

G i v e n

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

A and B are FRIENDS and their ages differ by 4 YEARS & A is ELDER
A's father D is TWICE as old as A
B is twice as old as his sister C
The age of D and C differ by 38 years

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

F i n d

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

The ages of A and B

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

S o l u t i o n

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Let the age of A be 'a'
Let the age of B be 'b'
Let the age of C be 'C'
Let the age of D be 'D'

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Given that , ages of A and B differ by 4 years & A is elder

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Thus ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ a - b = 4

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ b = a - 4 ⚊⚊⚊⚊ ⓵

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Also given that , A's father D is twice as old as A

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Thus ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ D = 2a ⚊⚊⚊⚊ ⓶

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Given that , B is twice as old as his sister C

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Thus ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf C = \dfrac { b } { 2 }$ ⚊⚊⚊⚊ ⓷

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Also given that , the ages of D and C differ by 38 years

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Clearly D is older then C

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Thus ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ D - C = 38 ⚊⚊⚊⚊ ⓸

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting the value of C from ⓷ to ⓸ ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf D - \dfrac { b } { 2 } = 38$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf \dfrac { 2D - b } { 2 } = 38$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 2D - b = 38 × 2

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 2D - b = 76 ⚊⚊⚊⚊ ⓹

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting D = 2a from ⓶ to ⓹ ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 2(2a) - b = 76

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 4a - b = 76 ⚊⚊⚊⚊ ⓺

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting b = a - 4 from ⓵ to ⓺ ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 4a - b = 76

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 4a - (a - 4) = 76

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 4a - a + 4 = 76

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 3a = 76 - 4

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 3a = 72

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf a = \dfrac { 72 } { 3 }$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: : ➨ a = 24 ⚊⚊⚊⚊ ⓻

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Hence the age of A is 24 years

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting a = 24 from ⓻ to ⓵ ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ b = a - 4

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ b = 24 - 4

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: : ➨ b = 20

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Hence the age of B is 20 years

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

∴ The ages of A & B are 24 years & 20 years respectively

Discussion

47.	I) Decide 9x² + 5 = 0 is quadratic equation or not?
Answer» ONG>ANSWER: YES, it is a quadratic EQUATION

Discussion

48.	Show that 2/5√3 is irrational
Answer» it HELPS Have a GREAT DAY AHEAD

48.

Show that 2/5√3 is irrational

Answer»

it HELPS

Have a GREAT DAY AHEAD

Discussion

49.	A pen that cost rupees 15 less than six times the cost of the Lost of board
Answer» ong>Answer: The cost of a pen is Rs.15. Its cost DECREASES by Rs.x. Then NEW cost of pen is Rs.(15−x) Rs(15−x):1 pen Rs.600:(?) 15−x 600 PENS.

49.

A pen that cost rupees 15 less than six times the cost of the Lost of board

Answer»

ong>Answer:

The cost of a pen is Rs.15.

Its cost DECREASES by Rs.x.

Then NEW cost of pen is Rs.(15−x)

Rs(15−x):1 pen

Rs.600:(?)

15−x

600

PENS.

Discussion

50.	Which has its centre at the point (4.3) and touches the starting line 5x-12y-10=0
Answer» ong>Answer: HEY MATE !! HERE IS UR ANS ⤵️⤵️ 5x-12y-10=0 5(4)-12(3)-10=0 20-36-10=0 -6=0 ... HOPE THIS HELPS U ALMOST ... ... THANK Q ... ꧁꧁ ༒ λKŞU ༒꧂꧂

50.

Which has its centre at the point (4.3) and touches the starting line 5x-12y-10=0

Answer»

ong>Answer:

HEY MATE !!

HERE IS UR ANS ⤵️⤵️

5x-12y-10=0

5(4)-12(3)-10=0

20-36-10=0

-6=0

... HOPE THIS HELPS U ALMOST ...

... THANK Q ...

꧁꧁ ༒ λKŞU ༒꧂꧂

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Question attached above.​

12654862+654555×99-555×58³×55²-1995² who will answer correctly with explanation will get thanks, brainliest and ratings​

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FORMULA:-

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Correct option is

B

55

∠GEF=180−∠CEF(∵∠GEF and ∠CEF are COMPLEMENTARY angles)

∴∠GEF=30

o

and ∠GCD=∠GEF (from the FIGURE, CD∣∣EF)

⇒∠GCD=30

o

Now, ∠BCD=∠BCG+∠GCD

⇒∠BCD=25

o

+30

o

=55

o

∠ABC=∠BCD(∵AB∣∣CD)

∠ABC=x=55

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Therefore the value of x is 55.

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Find the polynomial that has a sum 3 and product -2​

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G i v e n

F i n d

S o l u t i o n

I) Decide 9x² + 5 = 0 is quadratic equation or not?​

Show that 2/5√3 is irrational​

A pen that cost rupees 15 less than six times the cost of the Lost of board​

Which has its centre at the point (4.3) and touches the starting line 5x-12y-10=0

HEY MATE !!

Question attached above.

12654862+654555×99-555×58³×55²-1995² who will answer correctly with explanation will get thanks, brainliest and ratings

7/2Evaluate2x cos x dx

Principal= 12000 R=10% T=4year

10. x3 - 6x2 +12x -35बीज बोने सॉन्ग का गोली उत्पादक विश्लेषण करो

Find the amount if p = ₹ 5000, R= 8 p.c.p.aN = 2 years with respect to compond interset compoundi

Convert the given ratio into percentage . 8:10

I) Write the quadratic equation 2x + 3x4 = 9 in standerd form alsowrite values of a, b, c .

7cm long stick cut in three pieces. Length of each piece is natural number. What is the probability of forming triangle from the three pieces of stick?

In the adjoiningfigure, if AB || CD,then x =In the adioining

where a and b are natural number find (a + b).

6202+18929 = ???-_-

If a and b are co-prime numbers, then find the LCM (ma, mb).

Write a formula of nth term of A.P.

1 Find the sum of the following numbers 62.099 2.505 6,75.694 75.889 B 1.38.673C. 8.16.178D. 8,16,187

1) If Cos A=2/5then find the value of 4 + 4 tan²A.

X^x^x solved this problem

In the given fig O is centre of circle PT & QT are tangents to circle then LPOQ--------

Simplifya) (-3) 3 x (-5) ² x (-10)

draw a ray diagram to show the formation of image by a convex lens when object is placed at away from 2F1. Also write nature and size of image.

B) y^2 +1/3 y = 2 solve this equation using formula.

How to find a equation whose sum of roots is given?

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Find the quadratic equation of (2x-1)(x-3)=(x+5)(x-1)

B) y2 +1/3 y = 2 solve this equation using formula.

6. Draw the graph of y=-3x

Find the polynomial that has a sum 3 and product -2

2764 reduced the fraction into lowest term.

1 In the figureMN is parallel to QRpm - ccm PO = 10 cm(.(@) What is length of MQ ?(6) What is PN NR ?2ZQ

2tandtevaluate oIta?

Sin 30°tan 45° + cos 60°/sec 30° + cos 60° +cot 450

Which of the following numbers cannot represent probability a)0.893b)1.02c)4/5d)none of above

3a+1/2a=6, find 4a²+1/9a²

(2root 6 ) square(2)

Fnd the zeroes of the polynomial x²+ 2x + 1 ?

Enumerate the functions of the presidentand Council of Ministeas

Plz tell bro plzbsbshduudududududududududuudud

A and B are friends and their ages differ by 4years, A being elder.. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C differ by 38 years. Find theages of A and B.

I) Decide 9x² + 5 = 0 is quadratic equation or not?

Show that 2/5√3 is irrational

A pen that cost rupees 15 less than six times the cost of the Lost of board