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ong>Answer:

First we draw a rough sketch of a quadrilateral ABCD and write down its dimensions as shown. We may divide it into two CONVENIENTLY constructible Δs ABC and ACD.

Steps of construction:

1. Draw AC = 7 cm.

2. With A as centre and radius 4.5 cm, draw an arc (below AC).

3. With C as centre and radius 5.5 cm, draw another arc cutting the previous arc at B.

4. Join AB and BC

5. With A as centre and radius 6 cm, draw an arc (above AC).

6. With C as centre and radius 4 cm, draw another arc cutting the previous arc and D.

7. Join AD = CD.

Then, ABCD is the required quadrilateral.

(ii) First we draw a rough sketch of a quadrilateral JUMP and write down its dimensions as shown.

We may divide it inot two conveniently constructible Δs PJU and PMU.

Steps of construction:

1. Draw PU = 6.5 cm

2. With P as centre and radius 4.5 cm, draw an arc(below (PU)

3. With U as centre and radius 3.5 cm, draw another arc cutting the previous arc at J.

4. Join PJ and JU.

5. With P as centre and radius 5 cm, draw an arc (abov PU).

6. With U as centre and radius 4 cm, draw another arc cutting the previous arc at M.

7. Join PM and UM.

Then, JUMP is the required quadrilateral.

(iii) We know that opposite sides of parallelogram are equal and parallel to each other.

∴ OR = ME and MO = ER.

Steps of Construction:

1. Draw OR = 5 cm

2. With R as centre and radius equal to 4.5 cm, cut an arc.

3. With O as centre and radius equal to 7.5 cm, cut another arc on the arc drawn in step-2 at point E.

4. With E as centre and radius equal to 6 cm, cut an arc.

5. With O as centre and radius equal to 4.5 cm, cut an arc on the arc drawn in step-4 at point M.

6. Join RE, OE, OM and ME.

Hence, MORE is the required parallelogram.

(iv) We know that all four sides of a rhombus are equal.

∴ BE = ES = ST = BT = 4.5 cm.

Steps of Construction:

1. Draw BE = 4.5 cm.

2. With B as centre and radius equal to 4.5 cm, draw an arc.

3. With E as centre and radius equal to 6 cm, draw another arc, cutting the previous arc at point T.

4. With E as centre and radius equal to 4.5 cm, cut an arc.

5. With T as centre and radius equal to 4.5 cm, cut another arc on the previous arc at point S.

6. Join BT, ES, ET and ST.

Hence, BEST is the required rhombus.

EXERCISE : 4.2

1. Construct the following quadrilaterals:

(i) LI = 4 cm,

IF = 3 cm

TL = 2.5 cm,

LF = 4.5 cm

IT = 4 cm

(ii) Quadrilateal GOLD

OL = 7.5 cm,

GL = 6 cm

GD = 6 cm,

LD = 5 cm

OD = 10 cm

(iii) Rhombus BEND

BN = 5.6 cm,

DE = 6.5 cm

Sol. (i) Let us draw a rough sketch of the required quadrilateral and write down the dimensions. Clearly, the two EASILY constructible triangles are LIT and LIF.

Steps of construction:

1. Draw LI = 4 cm

2. With L as centre and radius 2.5 cm, draw an arc.

3. With I as centre and radius 4 cm draw another arc to cut the previous arc at T.

moving a body

Step-by-step explanation:

a FORCE that ACTS on abody moving in circular path and is DIRECTED towards the CENTER around which the body is moving

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ong>Answer:

Each hour has 2 OCCURRENCES of 90 DEGREES. In 12 hrs, it OVERTAKES 24 TIMES.

ong>Step-by-step EXPLANATION:

HISTORY is the study of change over time, and it covers all aspects of human society. Political, social, economic, scientific, technological, medical, CULTURAL, intellectual, religious and military developments are all part of history.

ong>Answer:

Read SOLUTION (Total 13)

first of I SAY that above it is given it is a series so 3054 is not correct.

then solution is:-

difference bet first two term=1030-518=512=8^3.

then 1130-1030=100=10^2

then 2858-1130=1728=12^3

then 3054-2858=196=14^2

BUT 7160-2054=4106!=16^3(4096)

then if 7474-4096=324=18^2

So answer is 7160.

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3) rs.5600

100% CORRECT answer

hope it HELPS.

i don't know

.The WEIGHT of an object is DEFINED as the force of gravity on the object and may be calculated as the mass times the acceleration of gravity, w = mg. Since the weight is a force, its SI unit is the newton.

that's is your answer

ong>Answer:

Power FACTORS are usually stated as "leading" or "lagging" to show the SIGN of the phase angle. Capacitive loads are leading (current leads VOLTAGE), and inductive loads are lagging (current lags voltage). ... At low values of power factor, more apparent power needs to be transferred to get the same real power.

Step-by-step explanation:

ok

ong>ANSWER:

option a

Step-by-step explanation:

22 2/2 can be EXPRESSED as p/q

I. E. 46/2

re BANGTAN ARMY. OT7

ong>Answer:

45

2

−45+1=0

∴45

2

−25−25+1=0

∴25(25−1)−1(25−1)=0

∴(25−1)(25−1)=0

∴S=+1/2

∴ SUM of ROOTS =

2

1

+

2

1

=1...(1)

∴ Sum of roots verified =

a

−b

=

4

−(−4)

=1...(2)

ALSO, Product of roots =

a

c

=

4

1

Also, (

2

1

)(

2

1

)=

4

1

I'm very keen to answer questions

x=15

Step-by-step EXPLANATION:

LHS -p/q*r/s

sub p/q=-3/7 and r/s=11/15

=3/7*11/15=33/105

RHS r/s× p/q

sub p/q=-3/7 and r/s=11/15

=11/15*-3/7=(-33)/105

so LHS not EQUAL to RHS

To JUSTIFY:- Which is GREATER -13/7+6/7 or -3/5+19/5

Solve:- -13/7+6/7 = -13+6/7 = -7/7 = -1

And, -3/5+19/5 = -3+19/5 = 16/5

So, -3/5+19/5 is greater.

Hope it HELPS you ✌️

ong>ANSWER:

here a = 1 and C = (-5)

BRAINLIST plz..

ong>ANSWER:

No answer

Step-by-step EXPLANATION:

Your QUESTION is not clear,

Please be SPECIFIC and clear next time

ong>ANSWER:

In CASE of hollow cylinder, we measure two radius, one for inner circle and one for outer circle formed by the BASE of hollow cylinder. Suppose, r1 and r2 are the two RADII of the GIVEN hollow cylinder with 'h' as the height, then the volume of this cylinder can be written as; V = πh(r12 – r22)

ong>ANSWER:

its your exam right ?

do it by your SELF

because in offline exam brainly will not be there

best of luck

This is a FALSE STATEMENT

So the ANSWER is 5x√7 = 2/3

Step-by-step EXPLANATION:

SWAN HAJ

s hklkncdgiln cvnjllm hjllnn

3+2+24+18=47

Step-by-step explanation:

HOPE u UNDERSTAND

ong>Answer:

COSINE theta equals x, sine theta equals y and tangent theta equals y over x, where x and y are the coordinates of the point on the terminal side of the ANGLE. And the 3 new functions are secant theta, cosecant theta and COTANGENT theta. Secant theta is defined as 1 over x.

-137+65=-73

-35+195=160

160 is GREATER

ong>ANSWER:

hello MASSAGE me on WHATAPP now 9389974682

ong>Step-by-step explanation:

Two PARALLEL chords of a circle of radius 5CM are on the same SIDE of the CENTRE. If the lengths of the two chords are 16 cm and 9CM , then the distances and I Two parallel chords of a circle of radius 5cm are on the same side of the centre. If the lengths of the two chords are 16 cm and 9cm , then the distance between the two chords will be between the two chords will be

1m 85cm

Step-by-step explanation:

I HOPE this will HELP you mark me as braillianest

7

Step-by-step EXPLANATION:

please mark me as BRAIN list

Mitochondria are membrane-bound CELL organelles (MITOCHONDRION, singular) that GENERATE most of the chemical energy needed to POWER the cell's biochemical reactions. Chemical energy produced by the mitochondria is stored in a small molecule called adenosine triphosphate (ATP).

ong>Answer:

Total OUTCOME of 1 rolling dice is 6

Then the total outcome of rolling two dice is 6*6 = 36

Different outcomes are as

(1,1) (1,2) (1,3) & goes till to (4,6) (5,6) (6,6)

The outcomes that GIVE outcome as 8 are

(2,6) (3,5) (4,4) (5,3) (6,2) these 5.

So the probability to GET sum as 8 are

= 5/36.

Hope this helps

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commutitativity under ADDITION

LARGE NUMBER IS 12 * 5 = 60

Step-by-step EXPLANATION:

LARGE NUMBER IS 12 * 5 = 60

3.33333333×6=20

Step-by-step explanation:

3.33333333×6=20

3.33333333 देगे

ong>Answer:

CIK Kayal meminjam dari Bank DESA sebanyak RM X dengan KADAR faedah 5% setahun.

Tempoh bayar balik adalah selama 8 TAHUN. Jika ansuran bulanan yang dibayar ialah RM218.75,

berapakah jumlah WANG yang dipinjam oleh Cik Kayal

it is the CORRECT answer of the QUEST

s solve both the questions one by one!

• The breadth of the rectangle is 8 cm.

Given :-

• A wire is in the shape of a SQUARE of side 10 cm.
• The wire is rebent into a rectangle of length 12 cm.

To find :-

• It's breadth.

Step-by-step explanation :-

• Here, it has been given that a wire is in the shape of a square of side 10 cm. We are asked to find the breadth of the wire if it is rebent into a rectangle of length 12 cm.

To find the breadth of the rectangle MADE using the wire, we first have to find it's length.

• Length of the wire will be equal to the perimeter of the square, because it's the boundary of the figure. So, to find the length of the wire, we first have to find the perimeter of the square.

We know that :-

Here,

• Side = 10 cm.

Hence,

• Perimeter of the square = 40 cm.
• So, the length of the wire is 40 cm.

-------------------

Now, since the wire is rebent into the shape of a rectangle, THEREFORE perimeter of the rectangle will be equal to the length of the wire.

• Length of the wire = 40 cm.

• Hence, the perimeter of the rectangle is 40 cm.

Let's use the length and perimeter of the rectangle to find it's breadth.

We know that :-

Here,

• Perimeter = 40 cm.
• Length = 12 cm.

• Let the breadth be b.

Removing the brackets by multiplying,

Transposing 24 from RHS to LHS, changing it's sign,

Subtracting 24 from 40,

Transposing 2 from RHS to LHS, changing it's sign,

Dividing 16 by 2,

-------------------

• Hence, the breadth of the rectangle is 8 cm.

-----------------------------------------------------------

• The wheel will make 200 revolutions for covering 176 m.

Given :-

• The diameter of a wheel is 28 cm.

To find :-

• The number of revolutions it will make for covering 176 m.

Step-by-step explanation :-

• Here, the diameter of a wheel and the distance to be covered has been given to us. We have to find the number of revolutions the wheel will make for covering 176 m.

• The distance covered by the wheel in one revolution will be equal to it's circumference.

• So, to find the number of revolutions the wheel will make for covering 176 m, we have to find the circumference of the wheel.

-----------------

For finding the circumference of the wheel, it is essential for us to find it's radius.

We know that :-

Here,

• Diameter = 28 cm.

Hence,

Dividing 28 by 2,

-----------------

Now let's find it's circumference!

We know that :-

Here,

• Radius = 14 cm.

• pi = 22/7.

Hence,

Reducing the numbers,

Now let's multiply the remaining numbers, since we can't reduce them anymore.

Multiplying the numbers,

-----------------

We know the circumference of the wheel now. So let's find the number of revolutions it will make to cover 176 m.

• The wheel covers 88 cm in one revolution.

So, the number of revolutions needed by the wheel is :-

First let's convert the distance to be covered in centimetres, so the units become same.

1 m = 100 cm.

Hence,

Multiplying 176 by 100,

Now, let's apply the given formula!

Here,

• Distance to be covered = 17600 cm.

• Distance covered by the wheel in one revolution = 88 cm.

So,

Dividing 17600 by 88,

-----------------

• Hence, 200 revolutions will be needed by the wheel to cover 176 m.

-----------------------------------------------------------

ong>Answer:

10 CM as 12 + 14 is 26 and 36 - 26 is 10

ong>ANSWER:

hey

ans is 120

At 60 miles PER hour, the car will go 15*80%=12 miles on a gallon of gas.

So, 1 {gallon} = 12 {miles}; multiply both sides with TEN: 10 {gallon} = 120 {miles}.

en

• Circumference of the BASE of the CONE= 484cm
• Height = 105 cm

To Find

• Volume Of Cone

Solution

Figure Of Cone

ong>Answer:

TQ<TP<PQ

Here's your answer..

Hope it helps you..

Mark as Brainliest...

ong>ANSWER:

The mean of the

distribution GIVEN is 56.

[3]

CLASS interval 0-20 20-40 40-60 60-80 80-100 100-120

16

f

11

16

12

frequency

10

√ 0.9 = √9/10 = 3/√10

= 0.949

HOPE IT WILL HELP YOU :-)