332354 + Interview Questions in Secondary School in Math

1.	Draw a histogram for the following data Class interval0 - 1010 - 2020 - 3030 - 4040 - 5050 - 60No. of students5152320107
Answer» ONG>ANSWER: PLEASE MARK this brainliest please

Discussion

2.	LCM of 25 and 40 + HCF of 16 and 32 =
Answer» ONG>Step-by-step explanation: if we do lcm of 25 and 40 we will get 200 if we do HCF of 16 and 32 we get 16 so according to question 200+ 16 =216

2.

LCM of 25 and 40 + HCF of 16 and 32 =

Answer» ONG>Step-by-step explanation:

if we do lcm of 25 and 40 we will get 200

if we do HCF of 16 and 32 we get 16

so according to question 200+ 16 =216

Discussion

3.	The scale on a map is 1mm =5 m. find the distance on the map for an actual distance of 55 m.
Answer» ONG>Answer: 1m=1/5mm 55M =551/5=111=11

3.

The scale on a map is 1mm =5 m. find the distance on the map for an actual distance of 55 m.

Answer» ONG>Answer:

1m=1/5mm

55M =55*1/5=11*1=11

Discussion

4.	1) What are magnetic materials and non magnetic materials? Name two magnetic materials and two non magnetic materials
Answer» ong>Answer: MAGNETIC materials MEANS materials that ATTRACT the magnet. eg: Iron, nickel Non magnetic materials means materials that don't attract the magnet. eg: PAPER,wood

4.

1) What are magnetic materials and non magnetic materials? Name two magnetic materials and two non magnetic materials

Answer»

ong>Answer:

MAGNETIC materials MEANS materials that ATTRACT the magnet.

eg: Iron, nickel

Non magnetic materials means materials that don't attract the magnet.

eg: PAPER,wood

Discussion

5.	How many rational numbers are there between two given rational numbers ?
Answer» ONG>Step-by-step explanation: INFINITE HOPEFULLY it will HELP you

5.

How many rational numbers are there between two given rational numbers ?

Answer» ONG>Step-by-step explanation:

INFINITE

HOPEFULLY it will HELP you

Discussion

6.	पनि को पाका गण 4725 राहता पालना । हो तो उनका लापता
Answer» ONG>ANSWER: dtsstidiyfrtw tysewtsrywutd yrugtarysyofhisewguistyyyryr i

Discussion

7.	70%of 10 students are good in mathematics how many students are not good in mathematics
Answer» ONG>ANSWER: 70% of 10 students who good in maths is 7 and LEFT are 3.. so the answer is 3

7.

70%of 10 students are good in mathematics how many students are not good in mathematics

Answer» ONG>ANSWER:

70% of 10 students who good in maths is 7

and LEFT are 3.. so the answer is 3

Discussion

8.	1-2A = 0021 then eigen values of matrix are-30
Answer» ong>Answer: FIRST MARK me as BRAINLIST

8.

1-2A = 0021 then eigen values of matrix are-30

Answer»

ong>Answer:

FIRST MARK me as BRAINLIST

Discussion

9.	25 पैशांना 1 पेरू तर साडे तीन डझन पेरू ची किंमत किती?
Answer» ONG>ANSWER: fifdtufdfhhvdtkvg to SEE

Discussion

10.	Add in binary number eqation 110101+11111
Answer» ong>Step-by-step EXPLANATION: ACCORDING to my side the carrect ANSWER is 1010100

10.

Add in binary number eqation 110101+11111

Answer»

ong>Step-by-step EXPLANATION:

ACCORDING to my side the carrect ANSWER is 1010100

Discussion

11.	If f(2 X + 3) = 4 x + 7 and formula that defines f inverse.
Answer» ong>Answer: 1.5 Step-by-step explanation: 2x+3=4x+7 2x-4x=7-4 -2x=3 x=2/3 x=1.5 please start FLOWING me please make me BRAIN LIST

11.

If f(2 X + 3) = 4 x + 7 and formula that defines f inverse.

Answer»

ong>Answer:

1.5

Step-by-step explanation:

2x+3=4x+7

2x-4x=7-4

-2x=3

x=2/3

x=1.5

please start FLOWING me

please make me BRAIN LIST

Discussion

12.	Find X , Y and Z in the following figuresplz give answer
Answer» ong>ANSWER: ∠x = 50 ∠y = 130° ∠z = 20° Step-by-step explanation: In ΔABC ∠x = 180 - 70+60 (Angle Sum PROPERTY of a Δ) = 180 - 130 ∠x = 50° ∠x and ∠y are in linear pair ∴180 - ∠x ∠y = 180° - 50° = 130° In ΔACD ∠z = 180 - 30+130 (∠y = 130°) ∴∠z = 180 - 160 = 20°

12.

Find X , Y and Z in the following figuresplz give answer

Answer»

ong>ANSWER:

∠x = 50

∠y = 130°

∠z = 20°

Step-by-step explanation:

In ΔABC

∠x = 180 - 70+60 (Angle Sum PROPERTY of a Δ)

= 180 - 130

∠x = 50°

∠x and ∠y are in linear pair

∴180 - ∠x

∠y = 180° - 50° = 130°

In ΔACD

∠z = 180 - 30+130 (∠y = 130°)

∴∠z = 180 - 160 = 20°

Discussion

13.	Help! statement and reason
Answer» ONG>Answer: in the given TRIANGLES POQ and SOR we can see that OS=OP(COMMON) QOP=SOR (OPPOSITE ANGLES) PS=RQ (GIVEN ) HENCE TRIANGLE IS CONGRUENT PQ=RS BY CPCT (CORRESPONDING PARTS OF CONGRUENT TRIANGLE )

13.

Help! statement and reason

Answer» ONG>Answer:

in the given TRIANGLES POQ and SOR

we can see that

OS=OP(COMMON)

QOP=SOR (OPPOSITE ANGLES)

PS=RQ (GIVEN )

HENCE TRIANGLE IS CONGRUENT PQ=RS BY CPCT (CORRESPONDING PARTS OF CONGRUENT TRIANGLE )

Discussion

14.	Find the value of a and b if 7 + 4 √ 3 ÷ 7 - 2√ 3 = a - √ 3 b
Answer» ANSWER: Given: $\sf{(7 + 4\sqrt3) \div (7-2\sqrt3) = a-b\sqrt3}$ To FIND: VALUES of a and b Solution: $:\longrightarrow \sf{(7 + 4\sqrt3) \div (7-2\sqrt3) = a-b\sqrt3} \\\\:\implies \sf{\dfrac{7+4\sqrt3}{7-2\sqrt3} = a-b\sqrt3} \\\\\text{Rationalising the denominator on LHS,} \\\\:\implies \sf{\dfrac{7+4\sqrt3}{7-2\sqrt3} \times \dfrac{7+2\sqrt3}{7+2\sqrt3} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{(7+4\sqrt3)\times(7+2\sqrt3)}{(7-2\sqrt3)\times(7+2\sqrt3)} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{(49+14\sqrt3+28\sqrt3+8(\sqrt3)^2)}{(7^2 - (2\sqrt3)^2)} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{(49+24+42\sqrt3)}{(49-12)} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{73+42\sqrt3}{37} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{73}{37} + \dfrac{42\sqrt3}{37} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{73}{37} - \dfrac{(-42\sqrt3)}{37} = a-b\sqrt3} \\\\\text{Comparing the terms, in LHS and RHS,} \\\\\bf{:\implies a = \dfrac{73}{37}\: \& \:b = \dfrac{-42}{37}}$ Formula Used: (a + b)(a - b) = a² - b² Learn More: $\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identities}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\bf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\bf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\bf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) - B^{3}\\\\8)\bf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\9)\bf\: A^{3} - B^{3} = (A-B)(A^{2} + AB + B^{2})\\\\ \end{minipage}}$

14.

Find the value of a and b if 7 + 4 √ 3 ÷ 7 - 2√ 3 = a - √ 3 b

Answer» ANSWER:

Given:

$\sf{(7 + 4\sqrt3) \div (7-2\sqrt3) = a-b\sqrt3}$

To FIND:

VALUES of a and b

Solution:

$:\longrightarrow \sf{(7 + 4\sqrt3) \div (7-2\sqrt3) = a-b\sqrt3} \\\\:\implies \sf{\dfrac{7+4\sqrt3}{7-2\sqrt3} = a-b\sqrt3} \\\\\text{Rationalising the denominator on LHS,} \\\\:\implies \sf{\dfrac{7+4\sqrt3}{7-2\sqrt3} \times \dfrac{7+2\sqrt3}{7+2\sqrt3} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{(7+4\sqrt3)\times(7+2\sqrt3)}{(7-2\sqrt3)\times(7+2\sqrt3)} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{(49+14\sqrt3+28\sqrt3+8(\sqrt3)^2)}{(7^2 - (2\sqrt3)^2)} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{(49+24+42\sqrt3)}{(49-12)} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{73+42\sqrt3}{37} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{73}{37} + \dfrac{42\sqrt3}{37} = a-b\sqrt3} \\\\:\implies \sf{\dfrac{73}{37} - \dfrac{(-42\sqrt3)}{37} = a-b\sqrt3} \\\\\text{Comparing the terms, in LHS and RHS,} \\\\\bf{:\implies a = \dfrac{73}{37}\: \& \:b = \dfrac{-42}{37}}$

Formula Used:

(a + b)(a - b) = a² - b²

Learn More:

$\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identities}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\bf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\bf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\bf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) - B^{3}\\\\8)\bf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\9)\bf\: A^{3} - B^{3} = (A-B)(A^{2} + AB + B^{2})\\\\ \end{minipage}}$

Discussion

15.	Underoot of √5576 please send me
Answer» ONG>Step-by-step explanation: Epithelial CELLS. These cells are TIGHTLY attached to one ANOTHER. ... Nerve Cells. These cells are SPECIALIZED for communication. ... Muscle Cells. These

15.

Underoot of √5576 please send me

Answer» ONG>Step-by-step explanation:

Epithelial CELLS. These cells are TIGHTLY attached to one ANOTHER. ...

Nerve Cells. These cells are SPECIALIZED for communication. ...

Muscle Cells. These

Discussion

16.	Evaluate: [5-1x3-1]-1÷6-1]
Answer» ong>ANSWER: Ans)1.4 Step-by-step EXPLANATION: See the photo above.

16.

Evaluate: [5-1x3-1]-1÷6-1]

Answer»

ong>ANSWER:

Ans)1.4

Step-by-step EXPLANATION:

See the photo above.

Discussion

17.	2. If (0, a) and (b, 0) are the solutions of the following linear equations. 1 8x - y=34ii) 3x = 7y - 21fthe following is solution of the equation iii) 5x -2y +3 ==0 find a and b
Answer» ong>Answer: Mitochondria are membrane-bound cell organelles (MITOCHONDRION, singular) that generate most of the chemical ENERGY needed to power the cell's biochemical REACTIONS. Chemical energy produced by the mitochondria is stored in a SMALL molecule called adenosine TRIPHOSPHATE (ATP).

17.

2. If (0, a) and (b, 0) are the solutions of the following linear equations. 1 8x - y=34ii) 3x = 7y - 21fthe following is solution of the equation iii) 5x -2y +3 ==0 find a and b

Answer»

ong>Answer:

Mitochondria are membrane-bound cell organelles (MITOCHONDRION, singular) that generate most of the chemical ENERGY needed to power the cell's biochemical REACTIONS. Chemical energy produced by the mitochondria is stored in a SMALL molecule called adenosine TRIPHOSPHATE (ATP).

Discussion

18.	If A = (x:x is a multiple of 4) and B = (x:x is multiple of 5), find AB,
Answer» ONG>Step-by-step EXPLANATION: shxjxjsjdjxjxqkabsodbsgzjjfbsjzckzjzjkxkzkzkzjxjxkxjcjxjxjxj

Discussion

19.	What is geometry????nahi bta sakta sorry
Answer» ONG>ANSWER: it is a SUBJECT LIKE maths

Discussion

20.	(1) The sides of a triangular field are 51m,37m and 20 m. Find the number of rose beds that can be prepared in the field if each rose bed occupies a space of 6 m?
Answer» > ❍ Sides of the Triangular filed are 20 m, 37 m and 51 m respectively. ⠀ To Calculate AREA of the triangle we'll use Heron's formula. Heron's formula is used to calculate the area of triangle. ⠀ S E M I – P E R I M E T E R : $\bf{\dag}\;\;\boxed{\sf{Semi - Perimeter = \bigg(\dfrac{Sum\;of\;all\; sides}{2}\bigg)}}$ $:\implies\sf S = \dfrac{a + b + c}{2}\\\\\\:\implies\sf S = \dfrac{51 + 37 + 20}{2} \\\\\\:\implies\sf S =\cancel \dfrac{ 108}{2}\\\\\\:\implies\underline{\boxed{\frak{S = 54\;m}}}$ $\rule{250px}{.3ex}$ F I N D I N G⠀A R E A : $\bf{\star}\;\boxed{\sf{Area_{\triangle} = \Big(\sqrt{s(s - a)(s - b)(s - c)}\;\Big)}}$ ⠀ $\frak{we\;have}\begin{cases}\sf{ \: \: a = 20 \;m}&\\\sf{ \: \: b = 51\:m}&\\\sf{ \: \: c = 37\;m}&\\\sf{ \: \: s = 54\;m}\end{cases}$ ⠀ $\underline{\bf{\dag} \:\mathfrak{Substituting\;<klux>GIVEN</klux>\;values\: :}}$ ⠀⠀⠀⠀ ⠀ $:\implies\sf Area_{\triangle} = \sqrt{54(54 -20)(54 - 51)(54 - 37)}\\\\\\:\implies\sf Area_{\triangle} = \sqrt{54 \times 34 \times 3 \times 17} \\\\\\:\implies\sf Area_{\triangle} = \sqrt{2\times 3\times 3 \times 3 \times 2 \times 17 \times 3 \times 17}\\\\\\:\implies\sf Area_{\triangle} = 2 \times 3 \times 3 \times 17\\\\\\:\implies\underline{\boxed{\frak{\pink{Area_{\triangle} = 306\;m^2}}}}\;\bigstar$ ⠀ N O.⠀O F⠀R O S E : It is given that, each rose bed occupies space of 6 m. Therefore, ➠ AR. or field/Ar. of rose ➠ 306/6 ➠ 51 ⠀ $\therefore{\underline{\textsf{Hence, \;number\;of\;roses\;that\;can\;be\; prepared\;are\;\textbf{51}.}}}$ ⠀⠀⠀⠀

20.

(1) The sides of a triangular field are 51m,37m and 20 m. Find the number of rose beds that can be prepared in the field if each rose bed occupies a space of 6 m?

Answer»

>

❍ Sides of the Triangular filed are 20 m, 37 m and 51 m respectively.

⠀

To Calculate AREA of the triangle we'll use Heron's formula. Heron's formula is used to calculate the area of triangle.

⠀

S E M I – P E R I M E T E R :

$\bf{\dag}\;\;\boxed{\sf{Semi - Perimeter = \bigg(\dfrac{Sum\;of\;all\; sides}{2}\bigg)}}$

$:\implies\sf S = \dfrac{a + b + c}{2}\\\\\\:\implies\sf S = \dfrac{51 + 37 + 20}{2} \\\\\\:\implies\sf S =\cancel \dfrac{ 108}{2}\\\\\\:\implies\underline{\boxed{\frak{S = 54\;m}}}$

$\rule{250px}{.3ex}$

F I N D I N G⠀A R E A :

$\bf{\star}\;\boxed{\sf{Area_{\triangle} = \Big(\sqrt{s(s - a)(s - b)(s - c)}\;\Big)}}$

⠀

$\frak{we\;have}\begin{cases}\sf{ \: \: a = 20 \;m}&\\\sf{ \: \: b = 51\:m}&\\\sf{ \: \: c = 37\;m}&\\\sf{ \: \: s = 54\;m}\end{cases}$

⠀

$\underline{\bf{\dag} \:\mathfrak{Substituting\;<klux>GIVEN</klux>\;values\: :}}$ ⠀⠀⠀⠀

⠀

$:\implies\sf Area_{\triangle} = \sqrt{54(54 -20)(54 - 51)(54 - 37)}\\\\\\:\implies\sf Area_{\triangle} = \sqrt{54 \times 34 \times 3 \times 17} \\\\\\:\implies\sf Area_{\triangle} = \sqrt{2\times 3\times 3 \times 3 \times 2 \times 17 \times 3 \times 17}\\\\\\:\implies\sf Area_{\triangle} = 2 \times 3 \times 3 \times 17\\\\\\:\implies\underline{\boxed{\frak{\pink{Area_{\triangle} = 306\;m^2}}}}\;\bigstar$

⠀

N O.⠀O F⠀R O S E :

It is given that, each rose bed occupies space of 6 m. Therefore,

➠ AR. or field/Ar. of rose

➠ 306/6

➠ 51

⠀

$\therefore{\underline{\textsf{Hence, \;number\;of\;roses\;that\;can\;be\; prepared\;are\;\textbf{51}.}}}$ ⠀⠀⠀⠀

Discussion

21.	सही विकल्प में जिन पदार्थों से विद्युत धारा प्रवाहित होती है
Answer» ONG>ANSWER: What is this pls write it in ENGLISH

Discussion

22.	Aptitude Question 15 of 20There are 12 black, 16 blue and 8 red pens in a bag. Three pens are drawn from the bag without replacement. What is the probability that thefirst pen is blue, the second pen is red and the third pen is black?O 86/1875O 36/129053/1260O 64/1785
Answer»

Discussion

23.	Describe, sketch and label the focus, vertex and directrix of the parabola 16 2+ 24 − 32 + 25 = 0.
Answer» ong>Answer: PLS can U EXPLAIN so that we can be ABLE to help you

23.

Describe, sketch and label the focus, vertex and directrix of the parabola 16 2+ 24 − 32 + 25 = 0.

Answer»

ong>Answer:

PLS can U EXPLAIN so that we can be ABLE to help you

Discussion

24.	डायगोनल ऑफ़ ए पैरेललोग्राम पीक्यूआरएस इंटरसेप्ट ईच अदर इन पॉइंट ऑफ लेंथ ऑफ डायगोनल पीआर इज 8 पॉइंट 4 सेंटीमीटर फाइंड लेंथ ऑफ op
Answer» ONG>Answer: pls can U EXPLAIN so that we can be ABLE to help you. PLS write it in English

Discussion

25.	If p / q = 6 / 5 then find the value of q2/ p2note: / is upon
Answer» ONG>ANSWER: Q^2/P^2 = 5^2/6^2 = 25/36

Discussion

26.	If 5x +4y=17 and 4x+5y=19 then what is the value of x+y=?
Answer» ONG>Step-by-step EXPLANATION: x=17/9 y=17/9. x+y is 34/9

26.

If 5x +4y=17 and 4x+5y=19 then what is the value of x+y=?

Answer» ONG>Step-by-step EXPLANATION:

x=17/9 y=17/9.

x+y is 34/9

Discussion

27.	क) हमें अपने मुँह से क्या नहीं कहना चाहिए?
Answer» APNE MUH SE KISI KE BHI BRE ME BURI BT NHI BOLNI CHAHIYE..

Discussion

28.	Sr. FirstSecondCoordinatesY-一yx₂-xCoordinatesNo. PointPointof secondof first point(x,y)point x,y3-1 211AB1,13,3113-122BC С3,34,44-3 14-3 1113C С3-4A4, 41,111بینین3-4-3
Answer» ong>Answer: First Second Coordinates Y- 一y x₂-x Coordinates No. POINT Point of second of first point (x,y) point x,y 3-1 2 1 1 A B 1,1 3,3 11 3-1 2 2 B C С 3,3 4,4 4-3 1 4-3 1 11 3 C С 3-4 A 4, 4

28.

Sr. FirstSecondCoordinatesY-一yx₂-xCoordinatesNo. PointPointof secondof first point(x,y)point x,y3-1 211AB1,13,3113-122BC С3,34,44-3 14-3 1113C С3-4A4, 41,111بینین3-4-3

Answer»

ong>Answer:

First

Second

Coordinates

Y-

一y

x₂-x

Coordinates

No. POINT

Point

of second

of first point

(x,y)

point x,y

3-1 2

1

A

B

1,1

3,3

11

3-1

2

B

C С

3,3

4,4

4-3 1

11

3

C С

3-4

A

4, 4

Discussion

29.	TE COS@then find the value of :7 7 그 ㅋ२Scos1- Sin etCosIt Sino
Answer» ONG>ANSWER: if you give me VOTE I will answer your all questions and MARK me the brainliest

Discussion

30.	125x⁵ by 5√5x³. divide
Answer» ONG>ANSWER: x^2 Step-by-step explanation: 125x⁵/5√5x³ =(5√5)x⁵ / (5√5)x³ =x⁵ / x³ =x^2

30.

125x⁵ by 5√5x³. divide

Answer» ONG>ANSWER:

x^2

Step-by-step explanation:

125x⁵/5√5x³

=(5√5)x⁵ / (5√5)x³

=x⁵ / x³

=x^2

Discussion

31.	Question 16 of 20 A car was driven from Point X to Point Y. It was driven at a speed of 35 m/s for the first 3 hours 20 minutes and at a speed of 23.75 m/s forthe last 5 hours 0 minutes. What is the average speed of the car in kilometer per hour?93.7 km/h128.2 km/hO 86.4 km/h0 100.5 km/h0 132.3 km/hMark for Review< PREVIOUSNEXT >Instruction
Answer» ong>ANSWER: was driven at a speed of 35 m/s for the FIRST 3 hours 20 MINUTES and at a speed of 23.75 m/s for the last 5 hours 0 minutes. What is the average speed of the car in kilometer per hour? 93.7 km/h 128.2 km/h O 86.4 km/h 0 100.5 km/h 0 132.3 km/h Mark for Review

31.

Question 16 of 20 A car was driven from Point X to Point Y. It was driven at a speed of 35 m/s for the first 3 hours 20 minutes and at a speed of 23.75 m/s forthe last 5 hours 0 minutes. What is the average speed of the car in kilometer per hour?93.7 km/h128.2 km/hO 86.4 km/h0 100.5 km/h0 132.3 km/hMark for Review< PREVIOUSNEXT >Instruction

Answer»

ong>ANSWER:

was driven at a speed of 35 m/s for the FIRST 3 hours 20 MINUTES and at a speed of 23.75 m/s for

the last 5 hours 0 minutes. What is the average speed of the car in kilometer per hour?

93.7 km/h

128.2 km/h

O 86.4 km/h

0 100.5 km/h

0 132.3 km/h

Mark for Review

Discussion

32.	Find the number of permutation that can be made from the letters of the word OMEGA. (a) O and A occupying end places(b) E being always in the middle(c) vowels occupying odd places(d) vowels being never placed together
Answer» ONG>Answer: a 12 b 24 c 12 d 6 Step-by-step EXPLANATION: gjjbg hujgf tuhgf hijbv

32.

Find the number of permutation that can be made from the letters of the word OMEGA. (a) O and A occupying end places(b) E being always in the middle(c) vowels occupying odd places(d) vowels being never placed together

Answer» ONG>Answer:

a 12

b 24

c 12

d 6

Step-by-step EXPLANATION:

gjjbg

hujgf

tuhgf

hijbv

Discussion

33.	What is the ratio of 5:10
Answer» ONG>Answer: 1:2 is the RATIO of 5:10 Step-by-step explanation: ०plz FOLLOW if this correct०

33.

What is the ratio of 5:10

Answer» ONG>Answer:

1:2 is the RATIO of 5:10

Step-by-step explanation:

०plz FOLLOW if this correct०

Discussion

34.	Prove that the line which are parallel lines to the same lime parallel to each other
Answer» ong>Answer: Lines parallel to same line Since this is a theorem, LET's TRY to PROVE it. To prove: m is parallel to p, given m is parallel to n & n is parallel to p. Using I & ii, we get ∠ 1 = ∠ 3, but these are corresponding angles. This lime m is parallel to p using corresponding Angle Axiom.

34.

Prove that the line which are parallel lines to the same lime parallel to each other

Answer»

ong>Answer:

Lines parallel to same line

Since this is a theorem, LET's TRY to PROVE it. To prove: m is parallel to p, given m is parallel to n & n is parallel to p. Using I & ii, we get ∠ 1 = ∠ 3, but these are corresponding angles. This lime m is parallel to p using corresponding Angle Axiom.

Discussion

35.	(b) Solve ytt yxxupto t 0.5with a spacing of 0.1 subject to y 0,t 0; y 1,t 0; yt x,0 0and y x,0 10 x 1 x .——–––––––––
Answer» ONG>ANSWER: ctxoy86s74waeyurzohxyox7s47tzigx Step-by-step EXPLANATION: pucysia74a47yxi 8d58xti xts57xyihxo7s5st7ho uoc

35.

(b) Solve ytt yxxupto t 0.5with a spacing of 0.1 subject to y 0,t 0; y 1,t 0; yt x,0 0and y x,0 10 x 1 x .——–––––––––

Answer» ONG>ANSWER:

ctxoy86s74waeyurzohxyox7s47tzigx

Step-by-step EXPLANATION:

pucysia74a47yxi 8d58xti xts57xyihxo7s5st7ho uoc

Discussion

36.	72, 46, 521, ?___Ans is 612, but How????
Answer» ong>ANSWER: The pattern is this :- 1, 8, 72, 46, 521, 612, 343, 215 Step-by-step explanation: These NUMBERS are the cube numbers backwards. The pattern :- 1, 8, 72, 46, 521, 612, 343, 215 The cube numbers :- 1, 8, 27, 64, 125, 216, 343, 512

36.

72, 46, 521, ?___Ans is 612, but How????

Answer»

ong>ANSWER:

The pattern is this :- 1, 8, 72, 46, 521, 612, 343, 215

Step-by-step explanation:

These NUMBERS are the cube numbers backwards.

The pattern :- 1, 8, 72, 46, 521, 612, 343, 215

The cube numbers :- 1, 8, 27, 64, 125, 216, 343, 512

Discussion

37.	Square of 5576 please tell me
Answer» > $\huge \pink{a} \blue{n} \red{s} \green{w} \orange{e} r$ $\huge{\boxed{74.67261881037788.}}$

37.

Square of 5576 please tell me

Answer»

>

$\huge \pink{a} \blue{n} \red{s} \green{w} \orange{e} r$

$\huge{\boxed{74.67261881037788.}}$

Discussion

38.	Find the area of shaded region if ABCD is a rectangle.plz give answer
Answer» ONG>Step-by-step EXPLANATION: Area of of SHADED region is 35 CMSQ . Hope it helps you.

38.

Find the area of shaded region if ABCD is a rectangle.plz give answer

Answer» ONG>Step-by-step EXPLANATION:

Area of of SHADED region is 35 CMSQ .

Hope it helps you.

Discussion

39.	What is total surface area
Answer» e TOTAL surface AREA of a solid is the sum of the areas of all of the faces or SURFACES that enclose the solid. The sum of the areas of the rectangle and the two circles is the total surface area. ... This process can be IMAGINED with each of the solids to PICTURE the lateral surface and the base(s). Ⓖ︎Ⓞ︎Ⓞ︎Ⓓ︎ Ⓓ︎Ⓐ︎Ⓨ︎ Ⓑ︎Ⓤ︎Ⓓ︎Ⓓ︎Ⓨ︎..❤️❤️

39.

What is total surface area

Answer»

e TOTAL surface AREA of a solid is the sum of the areas of all of the faces or SURFACES that enclose the solid. The sum of the areas of the rectangle and the two circles is the total surface area. ...

This process can be IMAGINED with each of the solids to PICTURE the lateral surface and the base(s).

Ⓖ︎Ⓞ︎Ⓞ︎Ⓓ︎ Ⓓ︎Ⓐ︎Ⓨ︎ Ⓑ︎Ⓤ︎Ⓓ︎Ⓓ︎Ⓨ︎..❤️❤️

Discussion

40.	What is next 18, 53, 112, 199,??
Answer» ANSWER is 222 THANKYOU

40.

What is next 18, 53, 112, 199,??

Answer» ANSWER is 222

THANKYOU

Discussion

41.	If c>0, and a>b, then a correct statement is a) a-c>b-c b) a-c c)a-c d)a-c=b-c
Answer» ONG>ANSWER: a) a_c>b_c Step-by-step EXPLANATION: this MIGHT be the answer

41.

If c>0, and a>b, then a correct statement is a) a-c>b-c b) a-c c)a-c d)a-c=b-c

Answer» ONG>ANSWER:

a) a_c>b_c

Step-by-step EXPLANATION:

this MIGHT be the answer

Discussion

42.	8:10 या गुणोत्तराचे शतमनातील गुणोत्तरात रुपांतर करा
Answer» ONG>ANSWER: Step-by-step EXPLANATION: → 80% → हे तुझं उत्तर आहे. → कृपया मला सर्वोत्तम उत्तर म्हणून खूण करा. → इन्स्टाग्रामवर फॉलो करा = niral161

42.

8:10 या गुणोत्तराचे शतमनातील गुणोत्तरात रुपांतर करा

Answer» ONG>ANSWER:

Step-by-step EXPLANATION:

→ 80%

→ हे तुझं उत्तर आहे.

→ कृपया मला सर्वोत्तम उत्तर म्हणून खूण करा.

→ इन्स्टाग्रामवर फॉलो करा = niral161

Discussion

43.	the two positive integers a & b cab be written a=x^2y^2 & b=xy^3; where x & y are prime number. Find the HCF & LCM
Answer» ong>Answer: HCF=x y^2 LCM=x^2 y^3 Step-by-step explanation: HCF lowest POWER of x and y LCM HIGHEST power

43.

the two positive integers a & b cab be written a=x^2y^2 & b=xy^3; where x & y are prime number. Find the HCF & LCM

Answer»

ong>Answer:

HCF=x y^2

LCM=x^2 y^3

Step-by-step explanation:

HCF lowest POWER of x and y

LCM HIGHEST power

Discussion

44.	Sai myliby:04542444 xs) -5
Answer» ONG>Answer: g jillaa jattu empika a m mariyu me DSP supraja dhoorapu bandhuvu ys anil sunkara samyuktamgaa nirminchaaru a m mariyu me dsp supraja dhoorapu bandhuvu Step-by-step EXPLANATION: bubhbyvyvDg. hybubububuc gyvtvtctvhbubyhjj a m mariyu me dsp supraja dhoorapu bandhuvu ys anil sunkara samyuktamgaa nirminchaaru a m mariyu me dsp supraja dhoorapu bandhuvu ys anil sunkara samyuktamgaa nirminchaaru a

44.

Sai myliby:04542444 xs) -5

Answer» ONG>Answer:

g jillaa jattu empika a m mariyu me DSP supraja dhoorapu bandhuvu ys anil sunkara samyuktamgaa nirminchaaru a m mariyu me dsp supraja dhoorapu bandhuvu

Step-by-step EXPLANATION:

bubhbyvyvDg.

hybubububuc gyvtvtctvhbubyhjj a m mariyu me dsp supraja dhoorapu bandhuvu ys anil sunkara samyuktamgaa nirminchaaru a m mariyu me dsp supraja dhoorapu bandhuvu ys anil sunkara samyuktamgaa nirminchaaru a

Discussion

45.	If figure given PQ=PR and PS is bisector of angle QPR . 1] state three pairs of equal parts in triangle PSQ and PSR . 2] is ∆PSQ congruent to ∆PSR
Answer» ong>ANSWER: h all so so so do do to do to to to do do do STILL do do do to Step-by-step explanation: mark as brainliest

45.

If figure given PQ=PR and PS is bisector of angle QPR . 1] state three pairs of equal parts in triangle PSQ and PSR . 2] is ∆PSQ congruent to ∆PSR

Answer»

ong>ANSWER:

h all so so so do do to do to to to do do do STILL do do do to

Step-by-step explanation:

mark as brainliest

Discussion

46.	23. Factorise: 6 - 24(x-y)^2
Answer» ong>To FACTORISE : 6 - 24(x - y)² Solution : → 6 - 24(x - y)² → 6 - 24(x - y)(x - y) → 6 - 24(x(x - y) - y(x - y)) → 6 - 24(x² - xy)(xy + y²) → 6 - 24(x² - 2XY + y²) → 24x² - 48xy + 24y² + 6 ∴ REQUIRED answer : Answer is : 24x² - 48xy + 24y² + 6 Verification : 24x² - 48xy + 24y² + 6 → 6 - 24(x² - xy)(xy + y²) → 6 - 24(x(x - y) - y(x - y)) → 6 - 24(x - y)(x - y) → 6 - 24(x - y)² Hence, VERIFIED!

46.

23. Factorise: 6 - 24(x-y)^2

Answer»

ong>To FACTORISE :

6 - 24(x - y)²

Solution :

→ 6 - 24(x - y)²

→ 6 - 24(x - y)(x - y)

→ 6 - 24(x(x - y) - y(x - y))

→ 6 - 24(x² - xy)(xy + y²)

→ 6 - 24(x² - 2XY + y²)

→ 24x² - 48xy + 24y² + 6

∴ REQUIRED answer :

Answer is :

24x² - 48xy + 24y² + 6

Verification :

24x² - 48xy + 24y² + 6

→ 6 - 24(x² - xy)(xy + y²)

→ 6 - 24(x(x - y) - y(x - y))

→ 6 - 24(x - y)(x - y)

→ 6 - 24(x - y)²

Hence, VERIFIED!

Discussion

47.	R + 3 3yबाजूच्या आकृतीतील आयताच्या बाजूच्या लांबीदिल्या आहेत. या माहितीवरून खालीलपैकी कोणतेसमीकरण मिळते?x + 2y + 7= 2(A) x - 3y(C) x + 3y = 2(B) x - y = 4(D) x + y = -4
Answer» ong>Step-by-step EXPLANATION: HELLO friends GOOD morning

47.

R + 3 3yबाजूच्या आकृतीतील आयताच्या बाजूच्या लांबीदिल्या आहेत. या माहितीवरून खालीलपैकी कोणतेसमीकरण मिळते?x + 2y + 7= 2(A) x - 3y(C) x + 3y = 2(B) x - y = 4(D) x + y = -4

Answer»

ong>Step-by-step EXPLANATION:

HELLO friends GOOD morning

Discussion

48.	(1) Distance of point A (3, 4) from the origin is _________.(a) 7 (b) 12 (c) 5 (d) Cannot be found
Answer» ong>ANSWER: there are 2 PICS please see!!

48.

(1) Distance of point A (3, 4) from the origin is _________.(a) 7 (b) 12 (c) 5 (d) Cannot be found

Answer»

ong>ANSWER:

there are 2 PICS please see!!

Discussion

49.	If cost = 7 then find the value of25Cas 0 1- Sin 0Cos 0 I+ Sin 0
Answer» ONG>Step-by-step EXPLANATION: $\huge{\underline{\boxed{\sf{\red{answer}}}}}$ GIVEN that $\cos0 = \frac{7}{25} \: = \frac{b}{h} \\ {h}^{2} = {b}^{2} + {p}^{2} \\ here \: h = 25 \: and \: b = 7 \\ {25}^{2} = {7}^{2} + {p}^{2} \\ 625 = {p}^{2} + 49 \\ 625 - 49 = {p}^{2} \\ 576 = {p}^{2} \\ p = \sqrt{576} \\ p = 24$ so we GOT that h= 25 b=7 p= 24 therefore, $\cos + \sin \\ \frac{b}{h} + \frac{p}{h} \\ \\ \frac{7}{25} + \frac{24}{25} \\ \\ \frac{31}{25} \\ \\ \frac{31}{25} is \: the \: correct \: answer \\ hope \: it \: helps$

49.

If cost = 7 then find the value of25Cas 0 1- Sin 0Cos 0 I+ Sin 0

Answer» ONG>Step-by-step EXPLANATION:

$\huge{\underline{\boxed{\sf{\red{answer}}}}}$

GIVEN that

$\cos0 = \frac{7}{25} \: = \frac{b}{h} \\ {h}^{2} = {b}^{2} + {p}^{2} \\ here \: h = 25 \: and \: b = 7 \\ {25}^{2} = {7}^{2} + {p}^{2} \\ 625 = {p}^{2} + 49 \\ 625 - 49 = {p}^{2} \\ 576 = {p}^{2} \\ p = \sqrt{576} \\ p = 24$

so we GOT that

h= 25

b=7

p= 24

therefore,

$\cos + \sin \\ \frac{b}{h} + \frac{p}{h} \\ \\ \frac{7}{25} + \frac{24}{25} \\ \\ \frac{31}{25} \\ \\ \frac{31}{25} is \: the \: correct \: answer \\ hope \: it \: helps$

Discussion

50.	•Find out the squares of these numbers •⅔ •1½
Answer» ONG>ANSWER: the SQUARES are 4/9 and 9/4

Discussion

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