332354 + Interview Questions in Secondary School in Math

1.	Subsititution method2и - y -2 = 0 Чи -3y + 2= 0
Answer» ANSWER: she had gave s! SC grubष BRICK MATTOCK woman q WILLIAM

1.

Subsititution method2и - y -2 = 0 Чи -3y + 2= 0

Answer»

ANSWER:

she had gave s! SC grubष BRICK MATTOCK woman q WILLIAM

Discussion

2.	Find two consecutive numbers so that the smaller number is increased by 3 times the larger one is 39
Answer» ✨✨Answer is here✨✨ ➡️✨✨see this PIC...✨✨ ✔️✔️

2.

Find two consecutive numbers so that the smaller number is increased by 3 times the larger one is 39

Answer»

✨✨Answer is here✨✨

➡️✨✨see this PIC...✨✨

✔️✔️

Discussion

3.	9 Write the successor of the following numer(a) 82,31,700(c) 9,54,619(e) 43,21,789
Answer» ANSWER: a)8231701 b)954620 c)4321790

3.

9 Write the successor of the following numer(a) 82,31,700(c) 9,54,619(e) 43,21,789

Answer»

ANSWER:

a)8231701

b)954620

c)4321790

Discussion

4.	write the the denominator of the following rationalnumber in 2n5m form where n and m are non negative integers and then write them in their decimal form
Answer» ANSWER: okkkkkkkkkkkkkkkhshshhshshwhwwhhw Step-by-step EXPLANATION: HU

4.

write the the denominator of the following rationalnumber in 2n5m form where n and m are non negative integers and then write them in their decimal form

Answer»

ANSWER:

okkkkkkkkkkkkkkkhshshhshshwhwwhhw

Step-by-step EXPLANATION:

HU

Discussion

5.	C) Sides of triangles are 11, 12, 15. Determine if it is a right angled triangle.
Answer» Step-by-step EXPLANATION: It cannot be a RIGHT angled TRIANGLE as 11,12,15 are not pythagoras TRIPLETS

5.

C) Sides of triangles are 11, 12, 15. Determine if it is a right angled triangle.

Answer»

Step-by-step EXPLANATION:

It cannot be a RIGHT angled TRIANGLE as 11,12,15 are not pythagoras TRIPLETS

Discussion

6.	Swimming Pools in club A and club B contain 500 and 200 liters of water,respectively. Water is pumped out of swimming pool A at the rate of Qliters per minute and water is being added to swimming pool B at the rateof G liters per minute. , How many hours will elapse before the two tankscontain equal amounts of water?
Answer» Given: Water in swimming POOL of club A = 500 litres Water in swimming pool of club B = 200 litres Rate at which water is pumped out from A = Q litres/min Rate at which water is pumped out from B = G litres/min To find: Number of HOURS at which volume of both the pools become equal. Solution: LET 't' be the number minutes taken so that the volume of the two pools become equal. Volume taken out from pool A after 't' minutes: $Q \times t$ So, volume left in pool A after 't' minutes = 500- $Q\times t$ Volume PUT to pool B after 't' minutes: $G \times t$ So, volume of pool B after 't' minutes = 200 + $G \times t$ Now, let US put both the volumes equal: $500-Qt=200+Gt\\\Rightarrow 300 = Gt+Qt\\\Rightarrow 300 = (G+Q)t\\\Rightarrow t = \dfrac{300}{G+Q}\ minutes\\\Rightarrow t = \dfrac{300}{60\times (G+Q)}\ hours\\\Rightarrow t = \dfrac{5}{G+Q}\ hours$ So, after $\frac{5}{G+Q}\ hours$ the volume of the two pools will be equal.

6.

Swimming Pools in club A and club B contain 500 and 200 liters of water,respectively. Water is pumped out of swimming pool A at the rate of Qliters per minute and water is being added to swimming pool B at the rateof G liters per minute. , How many hours will elapse before the two tankscontain equal amounts of water?

Answer»

Given:

Water in swimming POOL of club A = 500 litres

Water in swimming pool of club B = 200 litres

Rate at which water is pumped out from A = Q litres/min

Rate at which water is pumped out from B = G litres/min

To find:

Number of HOURS at which volume of both the pools become equal.

Solution:

LET 't' be the number minutes taken so that the volume of the two pools become equal.

Volume taken out from pool A after 't' minutes: $Q \times t$

So, volume left in pool A after 't' minutes = 500- $Q\times t$

Volume PUT to pool B after 't' minutes: $G \times t$

So, volume of pool B after 't' minutes = 200 + $G \times t$

Now, let US put both the volumes equal:

$500-Qt=200+Gt\\\Rightarrow 300 = Gt+Qt\\\Rightarrow 300 = (G+Q)t\\\Rightarrow t = \dfrac{300}{G+Q}\ minutes\\\Rightarrow t = \dfrac{300}{60\times (G+Q)}\ hours\\\Rightarrow t = \dfrac{5}{G+Q}\ hours$

So, after $\frac{5}{G+Q}\ hours$ the volume of the two pools will be equal.

Discussion

7.	Make tree diagram by using prime factors method of the following number : 6588 , 4242
Answer» ANSWER: This is the answer my FRIEND

7.

Make tree diagram by using prime factors method of the following number : 6588 , 4242

Answer»

ANSWER:

This is the answer my FRIEND

Discussion

8.	Explain.those who gave me wrong answers, I won't follow them. if you have me correct answer I will follow you and Mark as brainliest
Answer» Answer: HOPE this HELP U Step-by-step explanation: SUN is the answer DEAR..

8.

Explain.those who gave me wrong answers, I won't follow them. if you have me correct answer I will follow you and Mark as brainliest

Answer»

Answer:

HOPE this HELP U

Step-by-step explanation:

SUN is the answer DEAR..

Discussion

9.	is 292 a perfect square? if not then find the smallest number which must be multiplied so it becomes a perfect cube
Answer» ANSWER: To Find : To find whether 292 is a perfect CUBE or not, To find the smallest natural number by which it must be multipiled so that the product is a perfect cube. 292 = 2 x 2 x 73 , which doesn't have triplet of any prime factors, HENCE, to make it perfect cube, we must make the the prime factors to FORM triplets,. 292 x 2 x 73 x73 = 2 x 2 x 2 x 73 x 73 x 73 => Hence, it should be MULTIPLIED by 2 x 73 x 73 = 5329 x 2 = 10658. hope this clears your doubt

9.

is 292 a perfect square? if not then find the smallest number which must be multiplied so it becomes a perfect cube

Answer»

ANSWER:

To Find :

To find whether 292 is a perfect CUBE or not, To find the smallest natural number by which it must be multipiled so that the product is a perfect cube.

292 = 2 x 2 x 73 , which doesn't have triplet of any prime factors,

HENCE, to make it perfect cube, we must make the the prime factors to FORM triplets,.

292 x 2 x 73 x73 = 2 x 2 x 2 x 73 x 73 x 73

=> Hence, it should be MULTIPLIED by 2 x 73 x 73 = 5329 x 2 = 10658.

hope this clears your doubt

Discussion

10.	1- x3 / 7x - 1411742+)-(27= x +114.
Answer» Step-by-step EXPLANATION: nzKaknwiNdnzn,jwkzka

10.

1- x3 / 7x - 1411742+)-(27= x +114.

Answer»

Step-by-step EXPLANATION:

nzKaknwiNdnzn,jwkzka

Discussion

11.	What isa quadratic equation
Answer» ANSWER: In algebra, a QUADRATIC equation is any equation that can be rearranged in standard FORM as where X represents an unknown, and a, b, and c represent known numbers, where a ≠ 0. If a = 0, then the equation is LINEAR, not quadratic, as there is no term.

11.

What isa quadratic equation

Answer»

ANSWER:

In algebra, a QUADRATIC equation is any equation that can be rearranged in standard FORM as where X represents an unknown, and a, b, and c represent known numbers, where a ≠ 0. If a = 0, then the equation is LINEAR, not quadratic, as there is no term.

Discussion

12.	Solve for x and y: (a-b)x+(a+b)y=a^2-2ab-b^2 (a+b)(x+y)=a^2+b^2
Answer» ANSWER: VALUE of X is (a+b) Value of y is -2ab/(a+b) GIVEN: (a-b)x+(a+b)y = a²-2ab-b² (a+b)(x+y) = a²+b² TO FIND: Value of x and y. SOLUTION: => (a-b)x+(a+b)y = a²-2ab-b² .....(i) => (a+b)(x+y) = a²+b² => (a+b)x+(a+b)y = a²+b² .....(II) Subtracting eq (i) from (ii) => (a+b)x-(a-b)x = a²+b² -(a²-2ab-b²) => (a+b)x -(a-b)x = a²+b²-a²+2ab+b² => ax+bx-ax+bx = 2b²+2ab => 2bx = 2b(a+b) => x = (a+b) Putting x = (a+b) in eq(i) => (a-b)(a+b)+(a+b)y = a²-2ab-b² => a²-b²+(a+b)y = a²-2ab-b² => (a+b)y = -2ab => y = -2ab/(a+b) Value of x is (a+b) Value of y is -2ab/(a+b)

12.

Solve for x and y: (a-b)x+(a+b)y=a^2-2ab-b^2 (a+b)(x+y)=a^2+b^2

Answer»

ANSWER:

VALUE of X is (a+b)
Value of y is -2ab/(a+b)

GIVEN:

(a-b)x+(a+b)y = a²-2ab-b²
(a+b)(x+y) = a²+b²

TO FIND:

Value of x and y.

SOLUTION:

=> (a-b)x+(a+b)y = a²-2ab-b² .....(i)

=> (a+b)(x+y) = a²+b²

=> (a+b)x+(a+b)y = a²+b² .....(II)

Subtracting eq (i) from (ii)

=> (a+b)x-(a-b)x = a²+b² -(a²-2ab-b²)

=> (a+b)x -(a-b)x = a²+b²-a²+2ab+b²

=> ax+bx-ax+bx = 2b²+2ab

=> 2bx = 2b(a+b)

=> x = (a+b)

Putting x = (a+b) in eq(i)

=> (a-b)(a+b)+(a+b)y = a²-2ab-b²

=> a²-b²+(a+b)y = a²-2ab-b²

=> (a+b)y = -2ab

=> y = -2ab/(a+b)

Value of x is (a+b)

Value of y is -2ab/(a+b)

Discussion

13.	(4) 352 रु.एक व्यक्ति ने 3600 रू. का कुछ भाग 8% वार्षिक ब्याज की दर से और शेष 10%ब्याज की दर से लगाया। दो वर्ष बाद उसे 636 रु. व्याज के रूप में मिला। बताएँ कि8% ब्याज दर पर कितना धन और 10% ब्याज दर पर कितना धन क्रमशः लगा था?(1) 2100 रु.1500 रु.XM
Answer» ANSWER: answer is 50000 FOLLOW me now

13.

(4) 352 रु.एक व्यक्ति ने 3600 रू. का कुछ भाग 8% वार्षिक ब्याज की दर से और शेष 10%ब्याज की दर से लगाया। दो वर्ष बाद उसे 636 रु. व्याज के रूप में मिला। बताएँ कि8% ब्याज दर पर कितना धन और 10% ब्याज दर पर कितना धन क्रमशः लगा था?(1) 2100 रु.1500 रु.XM

Answer»

ANSWER:

answer is 50000 FOLLOW me now

Discussion

14.	What is the value of a and d in the given AP -15 , -71
Answer» ANSWER: a=-15 d=-71-(-15) d=-56 please MARK it as BRAINLIEST

14.

What is the value of a and d in the given AP -15 , -71

Answer»

ANSWER:

a=-15

d=-71-(-15)

d=-56

please MARK it as BRAINLIEST

Discussion

15.	Find the value of - 7 / 11 + 1 / 4
Answer» ANSWER: -7/11 + 1/4 = (-28+11)/44 = -17/44

15.

Find the value of - 7 / 11 + 1 / 4

Answer»

ANSWER:

-7/11 + 1/4

= (-28+11)/44

= -17/44

Discussion

16.	Name any two saplings that you want to plant in your garden or nearby park
Answer» ANSWER: WATER apple PLANT and BENGALURU chamanthi. mark me as brainlist PLEASEEEEEEEEE mark me as brainlist pleaseeeeeeeee mark me as brainlist pleaseeeeeeeee

16.

Name any two saplings that you want to plant in your garden or nearby park

Answer»

ANSWER:

WATER apple PLANT and BENGALURU chamanthi.

mark me as brainlist PLEASEEEEEEEEE mark me as brainlist pleaseeeeeeeee mark me as brainlist pleaseeeeeeeee

Discussion

17.	Sai have 780rs note of 10 20 50 the ratio of 50 and 10 note is 3:2 if he had 32 notes how many notes each will get
Answer» Answer: 3×100 = 300x 2×100 =200x 500x = 10X + 50x 500x = 60x 500×60 = x × x 30000 = x2 Square ROOT of both sides approx 174 = x 10×x = 1740 20×x = 2480 50×x = 870 Step-by-step explanation: Plz FOLLOW and give me a HEART

17.

Sai have 780rs note of 10 20 50 the ratio of 50 and 10 note is 3:2 if he had 32 notes how many notes each will get

Answer»

Answer:

3×100 = 300x

2×100 =200x

500x = 10X + 50x

500x = 60x

500×60 = x × x

30000 = x2

Square ROOT of both sides

approx

174 = x

10×x = 1740

20×x = 2480

50×x = 870

Step-by-step explanation:

Plz FOLLOW and give me a HEART

Discussion

18.	Half of the total population of a village are men if 1/3ofthe men in the village are illiterate how much part of the village population is illiterate men
Answer» Answer: 2/3 Step-by-step explanation: 3/3-1/3 = 1/3

18.

Half of the total population of a village are men if 1/3ofthe men in the village are illiterate how much part of the village population is illiterate men

Answer»

Answer:

2/3

Step-by-step explanation:

3/3-1/3 = 1/3

Discussion

19.	111 cows,185sheeps and 296 giats are to be taken acroos river.there is only one boat and the boat mam says that he will take the same number and same kind of animals in each trip .find the greatest number of animaks in each trip and number of trips he will make
Answer» Answer: Step-by-step explanation: To calculate the HIGHEST number which can divide all these three numbers, we will have to FIND their HCF . the factors of 111 are - 3 and 37 of 185 are -- 5 and 37 and of 296 are -- 2 ,2,2 and 37 so, HCF is 37. therefore, maximum 37 animals can be TAKEN in the boat at a time. total no. of animals = 111+185+296 = 592 so, no. of trips = 592 divided by 37 = 16

19.

111 cows,185sheeps and 296 giats are to be taken acroos river.there is only one boat and the boat mam says that he will take the same number and same kind of animals in each trip .find the greatest number of animaks in each trip and number of trips he will make

Answer»

Answer:

Step-by-step explanation:

To calculate the HIGHEST number which can divide all these three numbers, we will have to FIND their HCF .

the factors of 111 are - 3 and 37

of 185 are -- 5 and 37

and of 296 are -- 2 ,2,2 and 37

so, HCF is 37.

therefore, maximum 37 animals can be TAKEN in the boat at a time.

total no. of animals = 111+185+296 = 592

so, no. of trips = 592 divided by 37 = 16

Discussion

20.	Find the value of x if line l\|\|m
Answer» Answer: the VALUE of x WOULD be equal to L parallel to m Step-by-step explanation: MARK me as BRAINLIEST pls......

20.

Find the value of x if line l||m

Answer»

Answer:

the VALUE of x WOULD be equal to L parallel to

m

Step-by-step explanation:

MARK me as BRAINLIEST pls......

Discussion

21.	Divide by synthetic division method.(2x⁴+3x³+4x-2x²)-(x+3)
Answer» HOPE it HELPS you thankyou

21.

Divide by synthetic division method.(2x⁴+3x³+4x-2x²)-(x+3)

Answer»

HOPE it HELPS you

thankyou

Discussion

22.	Express each of the following in p/q form
Answer» Let us consider the number as (x) So , accordingly ; the equation becomes : $\tt{ x \implies 3.88888... or \: 3.\bar{8}}$ -- (1) The number after 3 is 8 and it is only getting repeated ; so we can conclude that the periodicity is 1 . So , we will multiply both the sides of the equation by 10 as 10 is the only number that has 1 zero after 1 . MULTIPLYING both the sides by 10 gives us : $\tt{ 10x \implies 38.8888....}$ --(2) Now , we will Subtract equation (1) from (2). $\tt{ 10 x - x \implies 38.8888...(-)3.888....}$ $\tt{ 9x \implies 35}$ $\large{\boxed{\tt{ x \implies \dfrac{35}{9}}}}$ Supplementary INFORMATION : The numbers which can be expressed in p by q FORM where p and q are integers and q is not equal to zero and known as rational numbers. They are either terminating or recurring. Eg : 1/2 , -5/7 The numbers which cannot be expressed in p by q form are known as irrational numbers. They are NON terminating and non recurring. Eg : √2 , √3 , √7 , 1.373924937390183

22.

Express each of the following in p/q form

Answer»

Let us consider the number as (x)

So , accordingly ; the equation becomes :

$\tt{ x \implies 3.88888... or \: 3.\bar{8}}$ -- (1)

The number after 3 is 8 and it is only getting repeated ; so we can conclude that the periodicity is 1 .

So , we will multiply both the sides of the equation by 10 as 10 is the only number that has 1 zero after 1 .

MULTIPLYING both the sides by 10 gives us :

$\tt{ 10x \implies 38.8888....}$ --(2)

Now , we will Subtract equation (1) from (2).

$\tt{ 10 x - x \implies 38.8888...(-)3.888....}$

$\tt{ 9x \implies 35}$

$\large{\boxed{\tt{ x \implies \dfrac{35}{9}}}}$

Supplementary INFORMATION :

The numbers which can be expressed in p by q FORM where p and q are integers and q is not equal to zero and known as rational numbers. They are either terminating or recurring.
Eg : 1/2 , -5/7

The numbers which cannot be expressed in p by q form are known as irrational numbers. They are NON terminating and non recurring.
Eg : √2 , √3 , √7 , 1.373924937390183

Discussion

23.	(25½/16½)×(2³/81½)×(125⅓/27⅓)
Answer» ANSWER: HOPE it will HELP you...........

23.

(25½/16½)×(2³/81½)×(125⅓/27⅓)

Answer»

ANSWER:

HOPE it will HELP you...........

Discussion

24.	What is £31.40 as a percentage
Answer» Answer: PLZ WRITE full questions Step-by-step explanation: if u want percentage u have to mention both the TERM so SUPPOSE u want %out of 100 THEREFORE ans will be 31.40%

24.

What is £31.40 as a percentage

Answer»

Answer:

PLZ WRITE full questions

Step-by-step explanation:

if u want percentage u have to mention both the TERM so SUPPOSE u want %out of 100

THEREFORE ans will be 31.40%

Discussion

25.	Round off 49730 to the nearest
Answer» Answer: 49700 to the NEAREST 100 50000 to the nearest 1000

25.

Round off 49730 to the nearest

Answer»

Answer:

49700 to the NEAREST 100

50000 to the nearest 1000

Discussion

26.	If ( a,3) is laying on the point of the graph of the equation 5x +2y =_4 then find a?
Answer» ANSWER: HOPE it will HELP you......

26.

If ( a,3) is laying on the point of the graph of the equation 5x +2y =_4 then find a?

Answer»

ANSWER:

HOPE it will HELP you......

Discussion

27.	If 10 persons stand in a line then what is the probabilitythat two assigned persons will stand together?
Answer» ANSWER: $\frac{1}{5}$

27.

If 10 persons stand in a line then what is the probabilitythat two assigned persons will stand together?

Answer»

ANSWER:

$\frac{1}{5}$

Discussion

28.	Rearrange the number in which the each part of the largest smallest
Answer»

Discussion

29.	Sridevi bhai 12 roses for rupees 60 it she wants to buy 20 more roses how much will she need to pay
Answer» Answer: Rs160 Step-by-step explanation: for 12 roses 60 Rs hence for 1 rose PRICE =60/12=5 she wants to BUY 20 more roses hence TOTAL no of roses=12+20=32 Now price of 32 roses=5×32= =Rs160

29.

Sridevi bhai 12 roses for rupees 60 it she wants to buy 20 more roses how much will she need to pay

Answer»

Answer:

Rs160

Step-by-step explanation:

for 12 roses 60 Rs

hence for 1 rose PRICE =60/12=5

she wants to BUY 20 more roses

hence TOTAL no of roses=12+20=32

Now price of 32 roses=5×32=

=Rs160

Discussion

30.	X-1/x-2+x-3/x-4=3 1/3,x not equal to 2,4 solve by using quadratic formula
Answer» $\begin{lgathered}\red{\bf{Given}}\begin{cases}\bf\dfrac{x-1}{x-2}+\dfrac{x-3}{x-4}=3(\dfrac{1}{3}) = \dfrac{10}{3}\\ \\ \bf \:x \ne \: 2 \: and \: 4. \end{cases}\end{lgathered}$ $\huge{\mathfrak{\overbrace{\underbrace{\pink{\fbox{\green{\blue{\bf\:S}\pink{o}\red{l}\orange{u}\purple{t}\blue{i}\green{o}\red{n}}}}}}}}$ $\red\leadsto\footnotesize\frac{x-1}{x-2}+\frac{x-3}{x-4}=\frac{10}{3} \\ \\ \red\leadsto\footnotesize\frac{(x-1)(x-4)+(x-3)(x-2)}{(x-2)(x-4)}=\frac{10}{3} \\ \\ \red\leadsto\footnotesize\frac{x^{2}-4x-x+4+x^{2}-2x-3x+6}{x^{2}-4x-2x+8}=\frac{10}{3} \\ \\ \red\leadsto\footnotesize\frac{2x^{2}-10x+10}{x^{2}-6x+8}=\frac{10}{3} \\ \\ \red\leadsto\footnotesize\:3(2x^{2}-10x+10)=10(x^{2}-6x+8) \\ \\ \red\leadsto\footnotesize\:6x^{2}-30x+30=10x^{2}-60x+80 \\ \\\red\leadsto\footnotesize \: 10x^{2}-60x+80-6x^{2}+30x-30 = 0 \\ \\\red\leadsto\footnotesize \:4x^{2}-30x+50=0 \\ \\\red\leadsto\footnotesize \: 2(2x^{2}-15x+25)=0 \\ \\\red\leadsto\footnotesize \:2x^{2}-15x+25=0 \\ \\ \underline{\textbf{\green{Splitting the Middle Term Now,}}} \\ \\\red\leadsto\footnotesize 2x^{2}-10x-5x+25=0 \\ \\ \red\leadsto\footnotesize 2x(x-5)-5(x-5)=0 \\ \\ \red\leadsto\footnotesize(x-5)(2x-5)=0 \\ \\\red\leadsto\footnotesize\:x-5 = 0 \\ \\ \blue{\bf{Or}} \\ \\\red\leadsto\footnotesize \: 2x-5 = 0 \\ \\\bf \: Hence \\ \\ \red\leadsto\large\red{\boxed{\tt\blue{x}\purple{=} \green {5}\orange,\pink{ \frac{5}{2}}}}\: \: \: \: \bold{\boxed{\huge{\boxed{\orange{\small{\boxed{\huge{\red{\bold{\huge\bold{\red{\ddot{\smile}}}}}}}}}}}}}$ $\rule{200}{4}$ $\boxed{\begin{minipage}{7 cm}\boxed{\underline{\underline{\bigstar\:\bf\:Algebric\:Identity\:\bigstar}}}\\\\1] (A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2] (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3] A^{2} - B^{2} = (A+B)(A-B)\\\\4] (A+B)^{2} = (A-B)^{2} + 4AB\\\\5] (A-B)^{2} = (A+B)^{2} - 4AB\\\\6] (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7] (A-B)^{3} = A^{3} - 3AB(A-B) + B^{3}\\\\8] A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\9] A^{3} - B^{3} = (A-B)(A^{2} + AB + B^{2})\\\\10] (A+B+C)^{2} = A^{2} + B^{2} + C^{2} + 2(AB + BC + CA)\\\\\end{minipage}}$ $\rule{200}{4}$

30.

X-1/x-2+x-3/x-4=3 1/3,x not equal to 2,4 solve by using quadratic formula

Answer»

$\begin{lgathered}\red{\bf{Given}}\begin{cases}\bf\dfrac{x-1}{x-2}+\dfrac{x-3}{x-4}=3(\dfrac{1}{3}) = \dfrac{10}{3}\\ \\ \bf \:x \ne \: 2 \: and \: 4. \end{cases}\end{lgathered}$

$\huge{\mathfrak{\overbrace{\underbrace{\pink{\fbox{\green{\blue{\bf\:S}\pink{o}\red{l}\orange{u}\purple{t}\blue{i}\green{o}\red{n}}}}}}}}$

$\red\leadsto\footnotesize\frac{x-1}{x-2}+\frac{x-3}{x-4}=\frac{10}{3} \\ \\ \red\leadsto\footnotesize\frac{(x-1)(x-4)+(x-3)(x-2)}{(x-2)(x-4)}=\frac{10}{3} \\ \\ \red\leadsto\footnotesize\frac{x^{2}-4x-x+4+x^{2}-2x-3x+6}{x^{2}-4x-2x+8}=\frac{10}{3} \\ \\ \red\leadsto\footnotesize\frac{2x^{2}-10x+10}{x^{2}-6x+8}=\frac{10}{3} \\ \\ \red\leadsto\footnotesize\:3(2x^{2}-10x+10)=10(x^{2}-6x+8) \\ \\ \red\leadsto\footnotesize\:6x^{2}-30x+30=10x^{2}-60x+80 \\ \\\red\leadsto\footnotesize \: 10x^{2}-60x+80-6x^{2}+30x-30 = 0 \\ \\\red\leadsto\footnotesize \:4x^{2}-30x+50=0 \\ \\\red\leadsto\footnotesize \: 2(2x^{2}-15x+25)=0 \\ \\\red\leadsto\footnotesize \:2x^{2}-15x+25=0 \\ \\ \underline{\textbf{\green{Splitting the Middle Term Now,}}} \\ \\\red\leadsto\footnotesize 2x^{2}-10x-5x+25=0 \\ \\ \red\leadsto\footnotesize 2x(x-5)-5(x-5)=0 \\ \\ \red\leadsto\footnotesize(x-5)(2x-5)=0 \\ \\\red\leadsto\footnotesize\:x-5 = 0 \\ \\ \blue{\bf{Or}} \\ \\\red\leadsto\footnotesize \: 2x-5 = 0 \\ \\\bf \: Hence \\ \\ \red\leadsto\large\red{\boxed{\tt\blue{x}\purple{=} \green {5}\orange,\pink{ \frac{5}{2}}}}\: \: \: \: \bold{\boxed{\huge{\boxed{\orange{\small{\boxed{\huge{\red{\bold{\huge\bold{\red{\ddot{\smile}}}}}}}}}}}}}$

$\rule{200}{4}$

$\boxed{\begin{minipage}{7 cm}\boxed{\underline{\underline{\bigstar\:\bf\:Algebric\:Identity\:\bigstar}}}\\\\1] (A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2] (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3] A^{2} - B^{2} = (A+B)(A-B)\\\\4] (A+B)^{2} = (A-B)^{2} + 4AB\\\\5] (A-B)^{2} = (A+B)^{2} - 4AB\\\\6] (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7] (A-B)^{3} = A^{3} - 3AB(A-B) + B^{3}\\\\8] A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\9] A^{3} - B^{3} = (A-B)(A^{2} + AB + B^{2})\\\\10] (A+B+C)^{2} = A^{2} + B^{2} + C^{2} + 2(AB + BC + CA)\\\\\end{minipage}}$

$\rule{200}{4}$

Discussion

31.	the ratio of water and the remaining portion in a syrup is 89:11 how much litre of water is to be e added to the syrup to make the ratio 90:10?
Answer» Answer: Step-by-step explanation: Consider 100 litre of mixture. 89 litre is water and 11 litre is SYRUP . Adding x lite of water, makes a new mixture 0F 100 + x litre and in it the volume of syrup remain the same as 11 litre. In ( 100 + x ) volumes Of mixture THETE is 11 litre of syrup, In 100 volume, the liter of syrup is 1100/ (100 + x) = 10/100 x = 10 litre. Water to be added is 10 litre for every 100 litre of mixture. Consider 100 litre of mixture. 89 litre is water and 11 litre is syrup . If x litre of water is added, ( 89 + x) / (100+x) = 90/100 x = 10 litre for every litre. Hope this helps you Please mark me brainlist My humble request

31.

the ratio of water and the remaining portion in a syrup is 89:11 how much litre of water is to be e added to the syrup to make the ratio 90:10?

Answer»

Answer:

Step-by-step explanation: Consider 100 litre of mixture. 89 litre is water and 11 litre is SYRUP .

Adding x lite of water, makes a new mixture 0F 100 + x litre and in it the volume of syrup remain the same as 11 litre.

In ( 100 + x ) volumes Of mixture THETE is 11 litre of syrup,

In 100 volume, the liter of syrup is 1100/ (100 + x) = 10/100

x = 10 litre.

Water to be added is 10 litre for every 100 litre of mixture.

Consider 100 litre of mixture. 89 litre is water and 11 litre is syrup .

If x litre of water is added,

( 89 + x) / (100+x) = 90/100

x = 10 litre for every litre.

Hope this helps you

Please mark me brainlist

My humble request

Discussion

32.	What is pattern for 15,25,45,75
Answer» ANSWER:- DIVIDE by 5 for the next term : 20/5 = 4 4/5 =0.8 0.8/5 = 0.16 . so the next term is : 0.16/5 = 0.032 . I HOPE THIS WILL HELP YOU AND PLEASE SEND THANKS

32.

What is pattern for 15,25,45,75

Answer»

ANSWER:-

DIVIDE by 5 for the next term : 20/5 = 4 4/5 =0.8 0.8/5 = 0.16 . so the next term is : 0.16/5 = 0.032 .

I HOPE THIS WILL HELP YOU

AND PLEASE SEND THANKS

Discussion

33.	Find x so that x,x+2,x+6are consecutive terms of a geometric progression
Answer» HOPE it hlllpsss.. please MARK me as BRAINLIEST.... and plzzz follow me.......

33.

Find x so that x,x+2,x+6are consecutive terms of a geometric progression

Answer»

HOPE it hlllpsss..

please MARK me as BRAINLIEST....

and plzzz follow me.......

Discussion

34.	The difference of two numbers is 4 the larger number exceeds 3 times of smaller number by 2 then the smaller number is
Answer» *HEY* *FRIEND.. here* is *you* *answer* *hope* it *HELPS* *uhh*❤❤❤

34.

The difference of two numbers is 4 the larger number exceeds 3 times of smaller number by 2 then the smaller number is

Answer»

HEY FRIEND.. here is you answer

hope it HELPS uhh❤❤❤

Discussion

35.	Find the subset of the following set:-A={5,7}
Answer» Answer: {5},{7} Step-by-step EXPLANATION: subset means writing all NUMBERS in aset

35.

Find the subset of the following set:-A={5,7}

Answer»

Answer:

{5},{7}

Step-by-step EXPLANATION:

subset

means writing all NUMBERS in aset

Discussion

36.	Multiply the rational number 5/7to inverse to -7/15
Answer» Answer: The answer is 1/3 and you haven't mentioned WHETHER U talkin bout additive or MULTIPLICATIVE inverse. I've done additive inverse. Step-by-step explanation: 5/7 × 7/15 = 1/3

36.

Multiply the rational number 5/7to inverse to -7/15

Answer»

Answer:

The answer is 1/3 and you haven't mentioned WHETHER U talkin bout additive or MULTIPLICATIVE inverse. I've done additive inverse.

Step-by-step explanation:

5/7 × 7/15

= 1/3

Discussion

37.	Represent these number on the number line. 1) 7/5
Answer» ANSWER: HEY Here's your answer hope it HELPS you.

37.

Represent these number on the number line. 1) 7/5

Answer»

ANSWER:

HEY

Here's your answer

hope it HELPS you.

Discussion

38.	Form 2n5m, where n and m aresion which terminates.Do THISWrite the denominator of the following rational numbers inon-negative integers and then write them in their decimal for351 1480(1)(iv)(v)64 25100(ت)742250 (ili25 (ii)NON-TERMINATING, RECURRING DECIMALS IN FRSet us now consider rational numbers whose decimal exna
Answer» ANSWER: this is too MUCH of LONG QUESTION......

38.

Form 2n5m, where n and m aresion which terminates.Do THISWrite the denominator of the following rational numbers inon-negative integers and then write them in their decimal for351 1480(1)(iv)(v)64 25100(ت)742250 (ili25 (ii)NON-TERMINATING, RECURRING DECIMALS IN FRSet us now consider rational numbers whose decimal exna

Answer»

ANSWER:

this is too MUCH of LONG QUESTION......

Discussion

39.	3 ke power (2+loga ke base a ke power x)=243
Answer» Step-by-step EXPLANATION: ANSWER of the QUESTION is x=1/5

39.

3 ke power (2+loga ke base a ke power x)=243

Answer»

Step-by-step EXPLANATION:

ANSWER of the QUESTION is x=1/5

Discussion

40.	Phil is paid £240 per week
Answer» ANSWER: there you GO Step-by-step EXPLANATION:

40.

Phil is paid £240 per week

Answer»

ANSWER:

there you GO

Step-by-step EXPLANATION:

Discussion

41.	-3= 7 on the dameDraw thegraphs of linear equations2-2y = 1 and 2x+y = 7 on thegraph paper and find their commensolutionSexpand eachsuitable identityDE2x + 5y - 32) (ii)_ (20-3b)3of thefollowingusingno
Answer» ANSWER: what is this QUESTION I don't UNDERSTAND

41.

-3= 7 on the dameDraw thegraphs of linear equations2-2y = 1 and 2x+y = 7 on thegraph paper and find their commensolutionSexpand eachsuitable identityDE2x + 5y - 32) (ii)_ (20-3b)3of thefollowingusingno

Answer»

ANSWER:

what is this QUESTION I don't UNDERSTAND

Discussion

42.	1. Differenciate x: sin inverse(3x-4x^3)
Answer» REFER to the IMAGE below for the SOLUTION.

Discussion

43.	Solve by Factorisation
Answer» Answer: Step-by-step explanation: a / (x - a) + b / (x - b) = 2c / (x - C) => [a(x - b) + b (x - a)] / (x - a) (x - b) = 2c / (x - c) => [(a + b) x - 2ab] (x - c) = 2c [x^2 - (a + b)x + AB] => (a + b) x^2 - [2ab + c(a + b)]x + 2abc = 2cx^2 - 2c(a + b)x + 2abc => (a + b - 2c) x^2 = (2ab + AC + bc - 2ca - 2bc) x => (a + b - 2c) x^2 = (2ab - ca - bc) x => x = 0 or x = (2ab - ca - bc) / (a + b - 2c) Hope this HELPS make me the Brainliest , THANK me and rate !!!!!

43.

Solve by Factorisation

Answer»

Answer:

Step-by-step explanation:

a / (x - a) + b / (x - b) = 2c / (x - C)

=> [a(x - b) + b (x - a)] / (x - a) (x - b) = 2c / (x - c)

=> [(a + b) x - 2ab] (x - c) = 2c [x^2 - (a + b)x + AB]

=> (a + b) x^2 - [2ab + c(a + b)]x + 2abc = 2cx^2 - 2c(a + b)x + 2abc

=> (a + b - 2c) x^2 = (2ab + AC + bc - 2ca - 2bc) x

=> (a + b - 2c) x^2 = (2ab - ca - bc) x

=> x = 0

or x = (2ab - ca - bc) / (a + b - 2c)

Hope this HELPS make me the Brainliest , THANK me and rate !!!!!

Discussion

44.	Sum of the zeroes of the polynomial 6x^2 + 1 + 8x is..
Answer» Answer: 6x²+ 8X + 1 Sum of the ZEROES = -b/a = -8/6 = -4/3 Thank you ✌️

44.

Sum of the zeroes of the polynomial 6x^2 + 1 + 8x is..

Answer»

Answer:

6x²+ 8X + 1

Sum of the ZEROES = -b/a

= -8/6

= -4/3

Thank you ✌️

Discussion

45.	Find the value of each of the following determinants. 5/-3, -2/1
Answer» HOPE it HELPS you mark as BRAINLEST

45.

Find the value of each of the following determinants. 5/-3, -2/1

Answer»

HOPE it HELPS you

mark as BRAINLEST

Discussion

46.	Ii) Concurrent lines pass throughpoint(s)v) Sides opposite to equal angles of a triangle are
Answer» ANSWER: a SINGLE point Step-by-step explanation: MARK ME AS BRAIN LIST ,.......

46.

Ii) Concurrent lines pass throughpoint(s)v) Sides opposite to equal angles of a triangle are

Answer»

ANSWER:

a SINGLE point

Step-by-step explanation:

MARK ME AS BRAIN LIST ,.......

Discussion

47.	Timothy climbed a mountain in two days. Timothy spent a total of 14 hours climbingthe mountain. On the second day, Timothy walked at an average speed that was halfa kilometer per hour faster, but was two hours less than what Timothy walked onthe first day. If the total distance Timothy covered during the two days, was 52 kms,how many kms per hour did Timothy walk on the second day?
Answer» Given: Timothy climbed a mountain in two days. Timothy spent a total of 14 hours climbing the mountain. On the second day, Timothy walked at an average SPEED that was half a kilometer per hour faster, but was two hours less than what Timothy walked on the first day. To find: If the total DISTANCE Timothy COVERED during the two days, was 52 km, how many kms per hour did Timothy walk on the second day? Solution: Timothy spent a total of 14 hours climbing the mountain. On the second day, Timothy walked two hours less than what Timothy walked on the first day. Let time TRAVELLED during first day = x Let time travelled during the second day = x - 2 Total time = 14 x + (x - 2) = 14 x = 8 hours Therefore, Timothy walked 8 hours on the first day and (8 - 2) = 6 hours on the second day. The total distance Timothy covered during the two days, was 52 km we use the formula, speed = distance/time speed × time = distance On the second day, Timothy walked at an average speed that was half a kilometre per hour faster s × 8 + (s + 0.5) (6) = 52 s × 8 + (s + 1/2) (6) = 52 8s + 6s + 3 = 52 14s = 49 s = 49/14 = 3.5 s = 3.5 km/hr Thus the speed on the first day = 3.5 km/hr Thus the speed on the second day = 3.5 + 0.5 = 4 km/hr Therefore, Timothy walked 4 km/hr on the second day.

47.

Timothy climbed a mountain in two days. Timothy spent a total of 14 hours climbingthe mountain. On the second day, Timothy walked at an average speed that was halfa kilometer per hour faster, but was two hours less than what Timothy walked onthe first day. If the total distance Timothy covered during the two days, was 52 kms,how many kms per hour did Timothy walk on the second day?

Answer»

Given:

Timothy climbed a mountain in two days. Timothy spent a total of 14 hours climbing the mountain.

On the second day, Timothy walked at an average SPEED that was half a kilometer per hour faster, but was two hours less than what Timothy walked on the first day.

To find:

If the total DISTANCE Timothy COVERED during the two days, was 52 km, how many kms per hour did Timothy walk on the second day?

Solution:

Timothy spent a total of 14 hours climbing the mountain. On the second day, Timothy walked two hours less than what Timothy walked on the first day.

Let time TRAVELLED during first day = x

Let time travelled during the second day = x - 2

Total time = 14

x + (x - 2) = 14

x = 8 hours

Therefore, Timothy walked 8 hours on the first day and (8 - 2) = 6 hours on the second day.

The total distance Timothy covered during the two days, was 52 km

we use the formula, speed = distance/time

speed × time = distance

On the second day, Timothy walked at an average speed that was half a kilometre per hour faster

s × 8 + (s + 0.5) (6) = 52

s × 8 + (s + 1/2) (6) = 52

8s + 6s + 3 = 52

14s = 49

s = 49/14 = 3.5

s = 3.5 km/hr

Thus the speed on the first day = 3.5 km/hr

Thus the speed on the second day = 3.5 + 0.5 = 4 km/hr

Therefore, Timothy walked 4 km/hr on the second day.

Discussion

48.	И 88 and - y = 2, find the value of 2n't2ину2
Answer» ANSWER: WO wo APP all zn all wo all zn do SUL do do do do do do do do do do do cm zn xl xhxhxysrkfucjfkffidu

48.

И 88 and - y = 2, find the value of 2n't2ину2

Answer»

ANSWER:

WO wo APP all zn all wo all zn do SUL do do do do do do do do do do do cm zn xl xhxhxysrkfucjfkffidu

Discussion

49.	If 6x= sec θ and 6/x= tan θ, find the value of 9(x^2-1/x^2)
Answer» ✨✨Answer is here✨✨ ➡️✨✨see this PIC...✨✨ ✔️✔️

49.

If 6x= sec θ and 6/x= tan θ, find the value of 9(x^2-1/x^2)

Answer»

✨✨Answer is here✨✨

➡️✨✨see this PIC...✨✨

✔️✔️

Discussion

50.	A lady purchased jeans for 1900. She wants to sell it at a profit of 15%, after allowing a discount of15%. What should be the marked price of the jeans?
Answer» Answer: 1217 Step-by-step explanation: COST price = 900 after PROFIT 15% then selling price =900+900×15/100 =1035 Main price =? LET total price of jeans with discount =X Then, X - X of 15% =1035 20X-3X =20700 17X =20700 X =1217 appx. i *hope* *this* *helps* *you.. plzz* *mark* me as a *brainlist*!!!

50.

A lady purchased jeans for 1900. She wants to sell it at a profit of 15%, after allowing a discount of15%. What should be the marked price of the jeans?

Answer»

Answer:

1217

Step-by-step explanation:

COST price = 900

after PROFIT 15% then selling price =900+900×15/100

=1035

Main price =?

LET total price of jeans with discount =X

Then,

X - X of 15% =1035

20X-3X =20700

17X =20700

X =1217 appx.

i hope this helps you..

plzz mark me as a brainlist!!!

Discussion

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ANSWER:

GIVEN:

TO FIND:

SOLUTION:

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What is pattern for 15,25,45,75

ANSWER:-

Find x so that x,x+2,x+6are consecutive terms of a geometric progression

The difference of two numbers is 4 the larger number exceeds 3 times of smaller number by 2 then the smaller number is

HEY FRIEND.. here is you answer

hope it HELPS uhh❤❤❤

Find the subset of the following set:-A={5,7}

Multiply the rational number 5/7to inverse to -7/15

Represent these number on the number line. 1) 7/5​

3 ke power (2+loga ke base a ke power x)=243​

Phil is paid £240 per week

-3= 7 on the dameDraw thegraphs of linear equations2-2y = 1 and 2x+y = 7 on thegraph paper and find their commensolutionSexpand eachsuitable identityDE2x + 5y - 32) (ii)_ (20-3b)3of thefollowingusingno​

1. Differenciate x: sin inverse(3x-4x^3)​

Solve by Factorisation​

Sum of the zeroes of the polynomial 6x^2 + 1 + 8x is..

6x²+ 8X + 1

Sum of the ZEROES = -b/a

= -8/6

= -4/3

Thank you ✌️

Find the value of each of the following determinants. 5/-3, -2/1​

Ii) Concurrent lines pass throughpoint(s)v) Sides opposite to equal angles of a triangle are​

И 88 and - y = 2, find the value of 2n't2ину2​

If 6x= sec θ and 6/x= tan θ, find the value of 9(x^2-1/x^2)

A lady purchased jeans for 1900. She wants to sell it at a profit of 15%, after allowing a discount of15%. What should be the marked price of the jeans?​

i hope this helps you..

plzz mark me as a brainlist!!!

Subsititution method2и - y -2 = 0 Чи -3y + 2= 0

9 Write the successor of the following numer(a) 82,31,700(c) 9,54,619(e) 43,21,789

write the the denominator of the following rationalnumber in 2n5m form where n and m are non negative integers and then write them in their decimal form

C) Sides of triangles are 11, 12, 15. Determine if it is a right angled triangle.

Explain.those who gave me wrong answers, I won't follow them. if you have me correct answer I will follow you and Mark as brainliest

is 292 a perfect square? if not then find the smallest number which must be multiplied so it becomes a perfect cube

1- x3 / 7x - 1411742+)-(27= x +114.

What isa quadratic equation

What is the value of a and d in the given AP -15 , -71

Express each of the following in p/q form

If 10 persons stand in a line then what is the probabilitythat two assigned persons will stand together?

the ratio of water and the remaining portion in a syrup is 89:11 how much litre of water is to be e added to the syrup to make the ratio 90:10?

Represent these number on the number line. 1) 7/5

3 ke power (2+loga ke base a ke power x)=243

-3= 7 on the dameDraw thegraphs of linear equations2-2y = 1 and 2x+y = 7 on thegraph paper and find their commensolutionSexpand eachsuitable identityDE2x + 5y - 32) (ii)_ (20-3b)3of thefollowingusingno

1. Differenciate x: sin inverse(3x-4x^3)

Solve by Factorisation

Find the value of each of the following determinants. 5/-3, -2/1

Ii) Concurrent lines pass throughpoint(s)v) Sides opposite to equal angles of a triangle are

И 88 and - y = 2, find the value of 2n't2ину2

A lady purchased jeans for 1900. She wants to sell it at a profit of 15%, after allowing a discount of15%. What should be the marked price of the jeans?