332354 + Interview Questions in Secondary School in Math

1.	2. Do you want wpuun3. I......... heard her say that.
Answer» ANSWER: WHT do U WANT? Step-by-step EXPLANATION:

1.

2. Do you want wpuun3. I......... heard her say that.

Answer»

ANSWER:

WHT do U WANT?

Step-by-step EXPLANATION:

Discussion

2.	Please prove PM=PN=√3×a
Answer» Answer: *hope its HELPFUL* *plzz MARK as brainliest and FOLLOW me* on *BRAINLY*

2.

Please prove PM=PN=√3×a

Answer»

Answer:

hope its HELPFUL

plzz MARK as brainliest and FOLLOW me on BRAINLY

Discussion

3.	12 1/2% change into fraction
Answer» ANSWER: PLEASE MARK me as BRAINLIEST answer please YAAR please

3.

12 1/2% change into fraction

Answer»

ANSWER:

PLEASE MARK me as BRAINLIEST answer please YAAR please

Discussion

4.	Patna city ka purana name
Answer» ANSWER: PATLIPUTRA....................

4.

Patna city ka purana name

Answer»

ANSWER:

PATLIPUTRA....................

Discussion

5.	hi ,i have a request, plz if you don't know the answer so plz don't write anything eg- ( sorry don't know, it is hard question......etc.) becoz by doing this you are taking the chance of the one who knows the correct answer.and also upset the person who ask the question. so plz plz plz don't do this. who is agree with me touch the ❤ button.
Answer» ANSWER: What's UR QUESTION DUDE.....??

5.

hi ,i have a request, plz if you don't know the answer so plz don't write anything eg- ( sorry don't know, it is hard question......etc.) becoz by doing this you are taking the chance of the one who knows the correct answer.and also upset the person who ask the question. so plz plz plz don't do this. who is agree with me touch the ❤ button.

Answer»

ANSWER:

What's UR QUESTION DUDE.....??

Discussion

6.	11.what is the value of a?66656a31a
Answer» Answer: I think a = 6 But this is not a PROPER question. Hope this helps. Please FOLLOW me and MARK me as the BRAINLIEST answer.

6.

11.what is the value of a?66656a31a

Answer»

Answer:

I think a = 6

But this is not a PROPER question.

Hope this helps.

Please FOLLOW me and MARK me as the BRAINLIEST answer.

Discussion

7.	(c) In an orchard of 400 trees, 35% are mango trees. 42% are apple trees andthe rest were grape vines. How many grape vines are there?
Answer» Answer: 92 are GRAPE VINE TREES

7.

(c) In an orchard of 400 trees, 35% are mango trees. 42% are apple trees andthe rest were grape vines. How many grape vines are there?

Answer»

Answer:

92 are GRAPE VINE TREES

Discussion

8.	A plain carpet 10 m long and 6.5 m wide has a border of width 75 cm along
Answer» Step-by-step EXPLANATION: What is the QUESTION. PLEASE SEND the question ALSO.

8.

A plain carpet 10 m long and 6.5 m wide has a border of width 75 cm along

Answer»

Step-by-step EXPLANATION:

What is the QUESTION. PLEASE SEND the question ALSO.

Discussion

9.	If tan theta equals to 1 find the value of sin theta + cos theta
Answer» Answer: √2 Step-by-step EXPLANATION: tan THETA = 1 tan theta = tan 45 ° .......... (tan 45° = 1) therefore, theta = 45 ° SIN theta + cos theta = sin 45° + cos 45° = 1/√2 + 1/√2 = 2/√2 = √2

9.

If tan theta equals to 1 find the value of sin theta + cos theta

Answer»

Answer:

√2

Step-by-step EXPLANATION:

tan THETA = 1

tan theta = tan 45 ° .......... (tan 45° = 1)

therefore, theta = 45 °

SIN theta + cos theta = sin 45° + cos 45°
= 1/√2 + 1/√2
= 2/√2
= √2

Discussion

10.	The spee of light is .of 30m or 80 m per second
Answer» So what can we do PLZ WRITE FULL QUESTION

Discussion

11.	Find four rational number between 3/4 and 5/9
Answer» ANSWER:HOPE it MAY HELP you. Answer is cliped. Step-by-step EXPLANATION:

11.

Find four rational number between 3/4 and 5/9

Answer»

ANSWER:HOPE it MAY HELP you.

Answer is cliped.

Step-by-step EXPLANATION:

Discussion

12.	prove that tan squared theta + cot squared theta + 2 is equal to sec squared theta into cosec squared theta
Answer» HYY MATE ✌️ hope it will HELP you ❣️❣️

12.

prove that tan squared theta + cot squared theta + 2 is equal to sec squared theta into cosec squared theta

Answer»

HYY MATE ✌️

hope it will HELP you ❣️❣️

Discussion

13.	the area of a rectangular carpet is 120 metre square and its perimeter is 46 metre the length of its diagonal is
Answer» ANSWER: The length of the diagonal is 17 m. Step-by-step explanation: Given : AREA = 120 m² Perimeter = 46 m To find : Length of the Diagonal Solution : Let the - Length as l Breadth as b $\rule{300}{1.5}$ ★ Area = Length × Breadth ⇒ l × b = 120 ⇒ lb = 120 ⇒ b = 120/l $\rule{300}{1.5}$ ★ Perimeter = 2(Length + Breadth) ⇒ 2(l + b) = 46 ⇒ l + b = 46/2 ⇒ l + 120/l = 23 ⇒ l² + 120 = 23l ⇒ l² - 23l + 120=0 ⇒ l² - 15l - 8L + 120 = 0 ⇒ (l - 15) - 8(l - 15) = 0 ⇒ (l - 15)(l - 8) = 0 Length is 15m Breadth is 8m $\rule{300}{1.5}$ ★ Diagonal - By Pythogoras THEORUM, (Hypotenuse)² = (BASE)² + (Height)² ⇒ (Hypotenuse)² = (15)² + (8)² ⇒ (Hypotenuse)² = 225 + 64 ⇒ (Hypotenuse)² = 289 ⇒ Hypotenuse = $\sf{\sqrt{289}}$ ⇒ Hypotenuse = 17 m Diagonal = 17 m. Therefore, the length of the diagonal is 17 m.

13.

the area of a rectangular carpet is 120 metre square and its perimeter is 46 metre the length of its diagonal is

Answer»

ANSWER:

The length of the diagonal is 17 m.

Step-by-step explanation:

Given :

AREA = 120 m²

Perimeter = 46 m

To find :

Length of the Diagonal

Solution :

Let the -

Length as l
Breadth as b

$\rule{300}{1.5}$

★ Area = Length × Breadth

⇒ l × b = 120

⇒ lb = 120

⇒ b = 120/l

$\rule{300}{1.5}$

★ Perimeter = 2(Length + Breadth)

⇒ 2(l + b) = 46

⇒ l + b = 46/2

⇒ l + 120/l = 23

⇒ l² + 120 = 23l

⇒ l² - 23l + 120=0

⇒ l² - 15l - 8L + 120 = 0

⇒ (l - 15) - 8(l - 15) = 0

⇒ (l - 15)(l - 8) = 0

Length is 15m

Breadth is 8m

$\rule{300}{1.5}$

★ Diagonal -

By Pythogoras THEORUM,

(Hypotenuse)² = (BASE)² + (Height)²

⇒ (Hypotenuse)² = (15)² + (8)²

⇒ (Hypotenuse)² = 225 + 64

⇒ (Hypotenuse)² = 289

⇒ Hypotenuse = $\sf{\sqrt{289}}$

⇒ Hypotenuse = 17 m

Diagonal = 17 m.

Therefore, the length of the diagonal is 17 m.

Discussion

14.	The simplest from 8/50is
Answer» Step-by-step EXPLANATION: Simpest form $\frac{8}{50} = \frac{2}{25}$

14.

The simplest from 8/50is

Answer»

Step-by-step EXPLANATION:

Simpest form

$\frac{8}{50} = \frac{2}{25}$

Discussion

15.	At what rate % of compound interest will 1200 becomes 1348.22 in 2 years
Answer» ANSWER: Step-by-step EXPLANATION: WAIT a MINUTE i am TAKING out the answer

15.

At what rate % of compound interest will 1200 becomes 1348.22 in 2 years

Answer»

ANSWER:

Step-by-step EXPLANATION:

WAIT a MINUTE i am TAKING out the answer

Discussion

16.	22questionpppppppppppppllllllllllllllzzzzzzz
Answer» ANSWER: (19/3)X^2 - (5/3)x - 56/3

16.

22questionpppppppppppppllllllllllllllzzzzzzz

Answer»

ANSWER:

(19/3)X^2 - (5/3)x - 56/3

Discussion

17.	The principal solution of cot x =√3 are
Answer» COT 30° = √3 ....(i) Cot X° = √3 .....(II) From (i) and (ii), X = 30°

17.

The principal solution of cot x =√3 are

Answer»

COT 30° = √3 ....(i)

Cot X° = √3 .....(II)

From (i) and (ii),

X = 30°

Discussion

18.	Successor of 909 is
Answer» ANSWER: 910 Step-by-step EXPLANATION: the CORRECT answer is 910

18.

Successor of 909 is

Answer»

ANSWER:

910

Step-by-step EXPLANATION:

the CORRECT

answer is

910

Discussion

19.	A school has a hall which is 22m long and 15.5 m broad a school has a hall which is 22 metre long and 15.5 m broad. a carpet is laid inside the hall living all around margin of 75 cm from the walls find the area of the carpet and the area of strip left un covered if the width of the carpet is 82 cm find its cost at the rate of 60 rupees per metre
Answer» Answer: AREA of hall lxb 220x155 is 34100 sq.cm . area of carpet 75x82 is 6150 area left UNCOVERED is area of hall - area of carpet 34100 -6150 is 27950sq.cm cost of carpet 27950 X2 is 55900 RS

19.

A school has a hall which is 22m long and 15.5 m broad a school has a hall which is 22 metre long and 15.5 m broad. a carpet is laid inside the hall living all around margin of 75 cm from the walls find the area of the carpet and the area of strip left un covered if the width of the carpet is 82 cm find its cost at the rate of 60 rupees per metre

Answer»

Answer:

AREA of hall lxb 220x155 is 34100 sq.cm . area of carpet 75x82 is 6150

area left UNCOVERED is area of hall - area of carpet

34100 -6150 is 27950sq.cm

cost of carpet

27950 X2 is 55900 RS

Discussion

20.	a new bike was bought at Rs.98,500 in 2004.Its value depreciqted at the rate of 11% per annum.find its value
Answer» Its value will be Rs 15264.54 (APPROX) Step-by-step explanation: GIVEN that bike bought at Rs 98,500 in 2004 Rate of depriciation = 11 % Now its value in 2020 after 16 YEARS will be = 98500 $(1-\frac{11}{100}) ^{16}$ = 98500 $(.89)^{16}$ = 98500 *.15497 = Rs 15264.54 (approximately)

20.

a new bike was bought at Rs.98,500 in 2004.Its value depreciqted at the rate of 11% per annum.find its value

Answer»

Its value will be Rs 15264.54 (APPROX)

Step-by-step explanation:

GIVEN that bike bought at Rs 98,500 in 2004

Rate of depriciation = 11 %

Now its value in 2020 after 16 YEARS will be

= 98500 $(1-\frac{11}{100}) ^{16}$

= 98500 $(.89)^{16}$

= 98500 *.15497

= Rs 15264.54 (approximately)

Discussion

21.	The triangle with sides 3,4 & 5 units is
Answer» ANSWER: RIGHT angled triangle Plz MARK brainliest Step-by-step explanation:

21.

The triangle with sides 3,4 & 5 units is

Answer»

ANSWER:

RIGHT angled triangle

Plz MARK brainliest

Step-by-step explanation:

Discussion

22.	Q.9. If length of a diagoanl offlength of a diagoanl of a rhombus is 30 cm and its area is 240 sq.cm., find its perimeter.
Answer» ANSWER: the answer of your QUESTION is this

22.

Q.9. If length of a diagoanl offlength of a diagoanl of a rhombus is 30 cm and its area is 240 sq.cm., find its perimeter.

Answer»

ANSWER:

the answer of your QUESTION is this

Discussion

23.	6. Complete the following magic square so that the decimal numbers fromleft to right and top to bottom add up to 4.5.1.11.31.51.71.4
Answer» ANSWER: 1.3 is the CORRECT answer

23.

6. Complete the following magic square so that the decimal numbers fromleft to right and top to bottom add up to 4.5.1.11.31.51.71.4

Answer»

ANSWER:

1.3 is the CORRECT answer

Discussion

24.	Find the volume of a cylinder whose !height is 10 cm and radius of baris 5 cm
Answer» The volume of the cylinder is 785.71 CM^3 Step-by-step explanation: Given: H= 10 cm r= 5 cm Volume of cylinder = πr²h Substituting the given VALUES in the formula, V= 22/72510 = 785.71 Thus, the volume of the cylinder, v= 785.71 cm^3 LEARN MORE ABOUT: brainly.in/question/12936813

24.

Find the volume of a cylinder whose !height is 10 cm and radius of baris 5 cm

Answer»

The volume of the cylinder is 785.71 CM^3

Step-by-step explanation:

Given:

H= 10 cm

r= 5 cm

Volume of cylinder = πr²h

Substituting the given VALUES in the formula,

V= 22/7*25*10

= 785.71

Thus, the volume of the cylinder, v= 785.71 cm^3

LEARN MORE ABOUT:

brainly.in/question/12936813

Discussion

25.	If tan theta equals to 1 find the value of sin theta + cos theta
Answer» Answer:1/2 Let THETHA be x now, tan x = 1 (given ) or , sin x/cos x = 1 or , sin x = cos x so, x = 45 Degree =sin x + cos x / SEX x + COSEC x =(sin x + cos x ) / (1/cos x + 1/ sin x ) =( ( sin x + cos x ) / (sin x + cos x ) ) .sin x .cos x =sin x .cos x = sin 45 .cos 45 ( x = 45 ) =1/2 Mark as Brainiest

25.

If tan theta equals to 1 find the value of sin theta + cos theta

Answer»

Answer:1/2

Let THETHA be x

now,

tan x = 1 (given )

or , sin x/cos x = 1

or , sin x = cos x

so, x = 45 Degree

=sin x + cos x / SEX x + COSEC x

=(sin x + cos x ) / (1/cos x + 1/ sin x )

=( ( sin x + cos x ) / (sin x + cos x ) ) .sin x .cos x

=sin x .cos x

= sin 45 .cos 45 ( x = 45 )

=1/2

Mark as Brainiest

Discussion

26.	from 1 to 20 how many numbers have vertical line of symmetry and how many of them has horizontal line id symmetry
Answer» ANSWER: HEY I am not SURE if you have any QUESTIONS or concerns PLEASE

26.

from 1 to 20 how many numbers have vertical line of symmetry and how many of them has horizontal line id symmetry

Answer»

ANSWER:

HEY I am not SURE if you have any QUESTIONS or concerns PLEASE

Discussion

27.	Solve it by complex no. method
Answer» Answer: *HOPE* it *HELPS* *mate* *pls* *MARK* as *brainlist*......❤️❤️

27.

Solve it by complex no. method

Answer»

Answer:

HOPE it HELPS mate pls MARK as brainlist......❤️❤️

Discussion

28.	The length and breadth of a cuboidal store are inthe ratio 2 : 1 and its height is 3.5 metres. If thearea of its four walls (including doors) is 210 m²,then its volume is
Answer» ANSWER: Here it is. HOPE U FIND it better. Step-by-step EXPLANATION:

28.

The length and breadth of a cuboidal store are inthe ratio 2 : 1 and its height is 3.5 metres. If thearea of its four walls (including doors) is 210 m²,then its volume is

Answer»

ANSWER:

Here it is. HOPE U FIND it better.

Step-by-step EXPLANATION:

Discussion

29.	2One-third of the students in a class got grade A in a test. One - fourth got grade B. Whatfraction of the students got grade A or grade B.
Answer» Answer: one THIRD got A in test one FOURTH got B therefore, fraction of STUDENTS got A and B GRADE = 1/3+1/4 =7/12 Step-by-step EXPLANATION:

29.

2One-third of the students in a class got grade A in a test. One - fourth got grade B. Whatfraction of the students got grade A or grade B.

Answer»

Answer:

one THIRD got A in test

one FOURTH got B

therefore, fraction of STUDENTS got A and B GRADE = 1/3+1/4

=7/12

Step-by-step EXPLANATION:

Discussion

30.	How many faces does a cylinder have two or three.
Answer» ANSWER: two Step-by-step EXPLANATION: HOPE it HELPS you DEAR

30.

How many faces does a cylinder have two or three.

Answer»

ANSWER:

two

Step-by-step EXPLANATION:

HOPE it HELPS you DEAR

Discussion

31.	0.21. Radii of the circles are given below, find their areas.1) 28 cmsolution:Here r = 28 cm.Area of the circle = zar227x 2822* 28784· Area of the circle = 2464 sq.cm.2) 21 cm(3) 4.2 mSolution: dula of Ciucle = Tip? Solution:= 22 x 21²
Answer» Step-by-step EXPLANATION: r=28cm Area of CIRCLE =πr^2 =22/72828 =88*28 =2464cm^2

31.

0.21. Radii of the circles are given below, find their areas.1) 28 cmsolution:Here r = 28 cm.Area of the circle = zar227x 2822* 28784· Area of the circle = 2464 sq.cm.2) 21 cm(3) 4.2 mSolution: dula of Ciucle = Tip? Solution:= 22 x 21²

Answer»

Step-by-step EXPLANATION:

r=28cm

Area of CIRCLE =πr^2

=22/7*28*28

=88*28

=2464cm^2

Discussion

32.	The height of a parallelogram is 3DM if the area is 240 CM square find the base of parallelogram
Answer» ANSWER: Base=8cm or 0.8dm Step-by-step explanation: 3dm=30cm Area of parallelogram=BaseHeight 240=Base(30) Base=240/30 Base=8cm Hope it HELPS...*

32.

The height of a parallelogram is 3DM if the area is 240 CM square find the base of parallelogram

Answer»

ANSWER:

Base=8cm or 0.8dm

Step-by-step explanation:

3dm=30cm

Area of parallelogram=Base*Height

240=Base(30)

Base=240/30

Base=8cm

Hope it HELPS...

Discussion

33.	(p-2q)^2+(4p-3q) factorise this
Answer» ANSWER: this will HELP you BRO to SOLVE

33.

(p-2q)^2+(4p-3q) factorise this

Answer»

ANSWER:

this will HELP you BRO to SOLVE

Discussion

34.	What do you think about mathematics
Answer» Answer: TILL 5th it is best subject but from then it MAKES the life miserable if you like my thoughts PLEASE mark my ANS as brainliest

34.

What do you think about mathematics

Answer»

Answer:

TILL 5th it is best subject but from then it MAKES the life miserable

if you like my thoughts PLEASE mark my ANS as brainliest

Discussion

35.	change the sentence first into passive voice sentence into passive interrogative sentence I shall post the letter tomorrow
Answer» Answer: A CYLINDER has 2 faces i hope this will HELP u :) Step-by-step explanation:

35.

change the sentence first into passive voice sentence into passive interrogative sentence I shall post the letter tomorrow

Answer»

Answer:

A CYLINDER has 2 faces

i hope this will HELP u :)

Step-by-step explanation:

Discussion

36.	Arun wanted to buy a soap. The cost of the soap is ` 14. He gave 2 five -rupee coins, 6 one –rupee coins and 4 half-rupee coins to the shopkeeper. How much money did the shopkeeper return ?
Answer» Cost of Soap → RS. 14 Now, LET us find how much Arun gave. No. of Rs. 5 = 2 × 5 = Rs. 10 No. of Rs. 1 = 6 × 1 = Rs. 6 No. of Rs. 0.5 = 0.5 × 4 = Rs. 2 So, total money arun gave = 10+6+2 =Rs. 18 Therefore the shopkeeper gave arun → 18-14 = Rs. 4.

36.

Arun wanted to buy a soap. The cost of the soap is ` 14. He gave 2 five -rupee coins, 6 one –rupee coins and 4 half-rupee coins to the shopkeeper. How much money did the shopkeeper return ?

Answer»

Cost of Soap → RS. 14

Now, LET us find how much Arun gave.

No. of Rs. 5 = 2 × 5 = Rs. 10

No. of Rs. 1 = 6 × 1 = Rs. 6

No. of Rs. 0.5 = 0.5 × 4 = Rs. 2

So, total money arun gave = 10+6+2 =Rs. 18

Therefore the shopkeeper gave arun → 18-14 = Rs. 4.

Discussion

37.	Please solveno spamming
Answer» $\huge{\boxed{\mathbb\pink{\fcolorbox{red}{purple}{Mr\:Awesome}}}}$ A = 2 + 4x + 8x² A = 8x² + 4x + 2 B = -3 + 5x² B = 5x² - 3 A + 2B ( 8x² + 4x + 2 ) + 2(5x² - 3) (8x² + 4x + 2) + 10x² - 6 8x² + 10x² + 4x + 2 - 6 18x² + 4x - 4

37.

Please solveno spamming

Answer»

$\huge{\boxed{\mathbb\pink{\fcolorbox{red}{purple}{Mr\:Awesome}}}}$

A = 2 + 4x + 8x²

A = 8x² + 4x + 2

B = -3 + 5x²

B = 5x² - 3

A + 2B

( 8x² + 4x + 2 ) + 2(5x² - 3)

(8x² + 4x + 2) + 10x² - 6

8x² + 10x² + 4x + 2 - 6

18x² + 4x - 4

Discussion

38.	Radha pure of 3 container of 500 ml 800 ml and 200 ml represent Live Into the thermals now the thermos is exactly half filled find the capacity of the thermos
Answer» Answer: Touch and hold a CLIP to pin it. Unpinned CLIPS will be deleted after 1 hour.Tap on a clip to paste it in the TEXT box.Welcome to Gboard clipboard, any text that you COPY will be saved here.Use the EDIT icon to pin, add or delete clips.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Tap on a clip to paste it in the text box.Use the edit icon to pin, add or delete clips.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Tap on a clip to paste it in the text box.Welcome to Gboard clipboard, any text that you copy will be saved here.Use the edit icon to pin, add or delete clips.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Tap on a clip to paste it in the text box.Welcome to Gboard clipboard, any text that you copy will be saved here.Use the edit icon to pin, add or delete clips.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Tap on a clip to paste it in the text box.Welcome to Gboard clipboard, any text that you copy will be saved here.Use the edit icon to pin, add or delete clips.

38.

Radha pure of 3 container of 500 ml 800 ml and 200 ml represent Live Into the thermals now the thermos is exactly half filled find the capacity of the thermos

Answer»

Answer:

Touch and hold a CLIP to pin it. Unpinned CLIPS will be deleted after 1 hour.Tap on a clip to paste it in the TEXT box.Welcome to Gboard clipboard, any text that you COPY will be saved here.Use the EDIT icon to pin, add or delete clips.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Tap on a clip to paste it in the text box.Use the edit icon to pin, add or delete clips.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Tap on a clip to paste it in the text box.Welcome to Gboard clipboard, any text that you copy will be saved here.Use the edit icon to pin, add or delete clips.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Tap on a clip to paste it in the text box.Welcome to Gboard clipboard, any text that you copy will be saved here.Use the edit icon to pin, add or delete clips.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Tap on a clip to paste it in the text box.Welcome to Gboard clipboard, any text that you copy will be saved here.Use the edit icon to pin, add or delete clips.

Discussion

39.	Find the area of the trapezium PQRS where RQ \|\| SP.13 m12 m17m
Answer» Answer: 180 Step-by-step explanation: TAKING 17&13as SUMOF parallel sides and 12 as HT

39.

Find the area of the trapezium PQRS where RQ || SP.13 m12 m17m

Answer»

Answer:

180

Step-by-step explanation:

TAKING 17&13as SUMOF parallel sides and 12 as HT

Discussion

40.	-729×9+729×(-9) Sole by using property.
Answer» ANSWER: -13122 Step-by-step EXPLANATION:

40.

-729×9+729×(-9) Sole by using property.

Answer»

ANSWER:

-13122

Step-by-step EXPLANATION:

Discussion

41.	A rectangular lawn is 15 metre long and 9 metre wide it has a path 1.5 metre wide all around it find the area of the path(Answer = 81m square)Explain
Answer» ANSWER : ⋆ REFERENCE of IMAGE is in the DIAGRAM : $\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\thicklines\put(7.3,2){\large{12 m}}\put(9.2,0.7){\large{18 m}}\put(8,1){\line(1,0){3}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\setlength{\unitlength}{1.5cm}\put(8.4,2){\large{9 m}}\put(9.2,1.4){\large{15 m}}\put(8.3,1.26){\line(1,0){2.4}}\put(8.3,1.25){\line(0,2){1.5}}\put(10.7,1.25){\line(0,3){1.5}}\put(8.3,2.74){\line(3,0){2.4}}\put(8.3,1){\line(0,3){0.3}}\put(8,1.26){\line(3,0){0.3}}\put(8,1.1){\small{1.5}}\end{picture}$ $\rule{150}{1}$ $\bullet\:\textsf{Length of Lawn ( l ) = 15 m}\\\\\bullet\:\textsf{Breadth of Lawn ( b ) = 9 m}\\\\\bullet\:\textsf{Outer Length ( L ) = [15 + 2(1.5)] m}\\\textsf{\qquad\qquad\qquad\qquad\quad\:= [15 + 3] m = 18 m}\\\\\bullet\:\textsf{Outer Breadth ( B ) = [9 + 2(1.5)] m}\\\textsf{\qquad\qquad\qquad\qquad\qquad\!= [9 + 3] m = 12 m}$ $\rule{200}{2}$ $\underline{\bigstar\:\textsf{According to the Question Now :}}$ $:\implies\texttt{Area of Path = Outer Area - Inner Area}\\\\\\:\implies\tt Area\:of\:Path = (Length \times Breadth)-(length \times breadth)\\\\\\:\implies\tt Area\:of\:Path = (L \times B)- (l \times b)\\\\\\:\implies\tt Area\:of\:Path =(18m\times12m)-(15m\times 9m)\\\\\\:\implies\tt Area\:of\:Path =216 m^2- 135 m^2\\\\\\:\implies\boxed{\tt Area\:of\:Path = 81\:m^2}$ ⠀ $\therefore\:\underline{\textsf{Area of the Path around Lawn is \textbf{81 m$^2$.}}}$

41.

A rectangular lawn is 15 metre long and 9 metre wide it has a path 1.5 metre wide all around it find the area of the path(Answer = 81m square)Explain

Answer»

ANSWER :

⋆ REFERENCE of IMAGE is in the DIAGRAM :

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\thicklines\put(7.3,2){\large{12 m}}\put(9.2,0.7){\large{18 m}}\put(8,1){\line(1,0){3}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\setlength{\unitlength}{1.5cm}\put(8.4,2){\large{9 m}}\put(9.2,1.4){\large{15 m}}\put(8.3,1.26){\line(1,0){2.4}}\put(8.3,1.25){\line(0,2){1.5}}\put(10.7,1.25){\line(0,3){1.5}}\put(8.3,2.74){\line(3,0){2.4}}\put(8.3,1){\line(0,3){0.3}}\put(8,1.26){\line(3,0){0.3}}\put(8,1.1){\small{1.5}}\end{picture}$

$\rule{150}{1}$

$\bullet\:\textsf{Length of Lawn ( l ) = 15 m}\\\\\bullet\:\textsf{Breadth of Lawn ( b ) = 9 m}\\\\\bullet\:\textsf{Outer Length ( L ) = [15 + 2(1.5)] m}\\\textsf{\qquad\qquad\qquad\qquad\quad\:= [15 + 3] m = 18 m}\\\\\bullet\:\textsf{Outer Breadth ( B ) = [9 + 2(1.5)] m}\\\textsf{\qquad\qquad\qquad\qquad\qquad\!= [9 + 3] m = 12 m}$

$\rule{200}{2}$

$\underline{\bigstar\:\textsf{According to the Question Now :}}$

$:\implies\texttt{Area of Path = Outer Area - Inner Area}\\\\\\:\implies\tt Area\:of\:Path = (Length \times Breadth)-(length \times breadth)\\\\\\:\implies\tt Area\:of\:Path = (L \times B)- (l \times b)\\\\\\:\implies\tt Area\:of\:Path =(18m\times12m)-(15m\times 9m)\\\\\\:\implies\tt Area\:of\:Path =216 m^2- 135 m^2\\\\\\:\implies\boxed{\tt Area\:of\:Path = 81\:m^2}$

⠀

$\therefore\:\underline{\textsf{Area of the Path around Lawn is \textbf{81 m$^2$.}}}$

Discussion

42.	X and y are angles on a straight line AB. If twice of x is 30 degree less than y. Find x and y.
Answer» ANSWER: X is 50°and y is 130° Step-by-step EXPLANATION: The linear equation will be X + Y =180° 2X=Y-30. SOLVIMG IT Y = 180 - X SUBSTITUTING IN EQUATION 2 2X = 180 - X - 30 3X = 150 X = 50° Y = 180 - 50 = 130° Y = 130°

42.

X and y are angles on a straight line AB. If twice of x is 30 degree less than y. Find x and y.

Answer»

ANSWER:

X is 50°and y is 130°

Step-by-step EXPLANATION:

The linear equation will be

X + Y =180°

2X=Y-30.

SOLVIMG IT

Y = 180 - X

SUBSTITUTING IN EQUATION 2

2X = 180 - X - 30

3X = 150

X = 50°

Y = 180 - 50 = 130°

Y = 130°

Discussion

43.	Ten unbiased coins are tosssimultaneously. Find the probabilityobtaining.(i) Exactly 6 Heads(ii) Atleast 8 Heads(iii) No Heads(iv) Atleast one Headv) Not more than 3 Heads andvi) Atleast 4 heads.
Answer» Answer: (i) 0.2051 (ii) 0.0547 (iii) 0.0009765 (iv) 0.99902 (v) 0.1720 (VI) 0.828 Step-by-step explanation: The binomial expression is given by; $P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.........$ where, Number of trials, n = 10 COINS In all cases we are interested in getting head on a coin so, the probability of success(head), p = 0.5 r = number of successes (i) Probability of obtaining Exactly 6 Heads = P(X = 6) P(X = 6) = $\binom{10}{6}(0.5)^{6}(1-0.5)^{10-6}$ = 210 * $0.5^{6+<klux>4</klux>}$ = 210 * $0.5^{10}$ = 0.2051 (ii) Probability of obtaining at least 8 Heads = P(X >= 8) P(X >=8) = P(X = 8) + P(X = 9) + P(X = 10) = $\binom{10}{8}(0.5)^{8}(1-0.5)^{10-8} + \binom{10}{9}(0.5)^{9}(1-0.5)^{10-9}+\binom{10}{10}(0.5)^{10}(1-0.5)^{10-10}$ = 45 * $0.5^{10}$ + 10 * $0.5^{10}$ + 1 * $0.5^{10}$ = 0.0547 (iii) Probability of obtaining No Heads = P(X = 0) P(X = 0) = $\binom{10}{0}(0.5)^{0}(1-0.5)^{10-0}$ = 1 * $0.5^{10}$ = 0.0009765 (iv) Probability of obtaining at least one Head = P(X >= 1) P(X >=1) = 1 - Probability of obtaining No Heads = 1 - P(X = 0) = 1 - 0.0009765 = 0.99902 (v) Probability of obtaining Not more than 3 Heads = P(X <= 3) P(X <= 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = $\binom{10}{0}(0.5)^{0}(1-0.5)^{10-0}+\binom{10}{1}(0.5)^{1}(1-0.5)^{10-1}+\binom{10}{2}(0.5)^{2}(1-0.5)^{10-2}+\binom{10}{3}(0.5)^{3}(1-0.5)^{10-3}$ = 1 * $0.5^{10}$ + 10 * $0.5^{10}$ + 45 * $0.5^{10}$ + 120 * $0.5^{10}$ = $0.5^{10}$ * 176 = 0.1720 (vi) Probability of obtaining at least 4 Heads = 1 - Probability of obtaining not more than 3 Heads P(X >= 4) = 1 - P(X <= 3) = 1 - 0.1720 = 0.828 .

43.

Ten unbiased coins are tosssimultaneously. Find the probabilityobtaining.(i) Exactly 6 Heads(ii) Atleast 8 Heads(iii) No Heads(iv) Atleast one Headv) Not more than 3 Heads andvi) Atleast 4 heads.

Answer»

Answer:

(i) 0.2051

(ii) 0.0547

(iii) 0.0009765

(iv) 0.99902

(v) 0.1720

(VI) 0.828

Step-by-step explanation:

The binomial expression is given by;

$P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.........$

where, Number of trials, n = 10 COINS

In all cases we are interested in getting head on a coin so, the probability of success(head), p = 0.5

r = number of successes

(i) Probability of obtaining Exactly 6 Heads = P(X = 6)

P(X = 6) = $\binom{10}{6}(0.5)^{6}(1-0.5)^{10-6}$ = 210 * $0.5^{6+<klux>4</klux>}$ = 210 * $0.5^{10}$ = 0.2051

(ii) Probability of obtaining at least 8 Heads = P(X >= 8)

P(X >=8) = P(X = 8) + P(X = 9) + P(X = 10) = $\binom{10}{8}(0.5)^{8}(1-0.5)^{10-8} + \binom{10}{9}(0.5)^{9}(1-0.5)^{10-9}+\binom{10}{10}(0.5)^{10}(1-0.5)^{10-10}$

= 45 * $0.5^{10}$ + 10 * $0.5^{10}$ + 1 * $0.5^{10}$ = 0.0547

(iii) Probability of obtaining No Heads = P(X = 0)

P(X = 0) = $\binom{10}{0}(0.5)^{0}(1-0.5)^{10-0}$ = 1 * $0.5^{10}$ = 0.0009765

(iv) Probability of obtaining at least one Head = P(X >= 1)

P(X >=1) = 1 - Probability of obtaining No Heads

= 1 - P(X = 0) = 1 - 0.0009765 = 0.99902

(v) Probability of obtaining Not more than 3 Heads = P(X <= 3)

P(X <= 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) =

$\binom{10}{0}(0.5)^{0}(1-0.5)^{10-0}+\binom{10}{1}(0.5)^{1}(1-0.5)^{10-1}+\binom{10}{2}(0.5)^{2}(1-0.5)^{10-2}+\binom{10}{3}(0.5)^{3}(1-0.5)^{10-3}$

= 1 * $0.5^{10}$ + 10 * $0.5^{10}$ + 45 * $0.5^{10}$ + 120 * $0.5^{10}$ = $0.5^{10}$ * 176 = 0.1720

(vi) Probability of obtaining at least 4 Heads = 1 - Probability of obtaining not more than 3 Heads

P(X >= 4) = 1 - P(X <= 3) = 1 - 0.1720 = 0.828 .

Discussion

44.	Is 2+3=6 a linear equation
Answer» Answer: No, this is not LINEAR equation. PLEASE MARK me as brainliest answer please YAAR please

44.

Is 2+3=6 a linear equation

Answer»

Answer:

No, this is not LINEAR equation.

PLEASE MARK me as brainliest answer please YAAR please

Discussion

45.	Decimal representation of 246 / 2^8 × 5^−3 will be
Answer» ANSWER: $\tt{\frac{246}{2^{8} \times 5^{(-3)}}}\\$ => $\tt{\frac{123 \times 2}{2^{8} \times 5^{(-3)}}}\\$ => $\tt{\frac{123 \times 5^{3}}{2^{7}}}\\$ MULTIPLY and DIVIDE by 5^7: => $\tt{\frac{123 \times 5^{3} \times 5^{7}}{2^{7} \times 5^{7}}}\\$ => $\tt{\frac{1201171875}{10^{7}}}\\$ => 120.1171875 _____________

45.

Decimal representation of 246 / 2^8 × 5^−3 will be

Answer»

ANSWER:

$\tt{\frac{246}{2^{8} \times 5^{(-3)}}}\\$

=> $\tt{\frac{123 \times 2}{2^{8} \times 5^{(-3)}}}\\$

=> $\tt{\frac{123 \times 5^{3}}{2^{7}}}\\$

MULTIPLY and DIVIDE by 5^7:

=> $\tt{\frac{123 \times 5^{3} \times 5^{7}}{2^{7} \times 5^{7}}}\\$

=> $\tt{\frac{1201171875}{10^{7}}}\\$

=> 120.1171875

_____________

Discussion

46.	How many faces does a cylindrical have.
Answer» $\huge{\boxed{\mathbb\pink{\fcolorbox{red}{purple}{Mr\:Awesome}}}}$ A CYLINDER has 2 FACES

46.

How many faces does a cylindrical have.

Answer»

$\huge{\boxed{\mathbb\pink{\fcolorbox{red}{purple}{Mr\:Awesome}}}}$

A CYLINDER has 2 FACES

Discussion

47.	6 ka maths ka final exam paper 2020
Answer» ANSWER: which BOARD??????? Step-by-step EXPLANATION: ....

47.

6 ka maths ka final exam paper 2020

Answer»

ANSWER:

which BOARD???????

Step-by-step EXPLANATION:

....

Discussion

48.	Find the three stationalnumber between 1/4 and 1/3
Answer» Answer:HOPE it will helps. Andwer s cliped. Step-by-step explanation: We have to FIRST take the LCM of both the FRACTIONS.

48.

Find the three stationalnumber between 1/4 and 1/3

Answer»

Answer:HOPE it will helps.

Andwer s cliped.

Step-by-step explanation:

We have to FIRST take the LCM of both the FRACTIONS.

Discussion

49.	(3)IfA (5,2), B (2,-2) and C (-2, 1) are the vertices of a right-angledtriangle with B = 90°, then find the value of t.
Answer» ANSWER: refer STD 10 SEC text and digest LS no. 5 co-ordinate geometry

49.

(3)IfA (5,2), B (2,-2) and C (-2, 1) are the vertices of a right-angledtriangle with B = 90°, then find the value of t.

Answer»

ANSWER:

refer STD 10 SEC text and digest LS no. 5 co-ordinate geometry

Discussion

50.	Please answer the boxed question
Answer» ANSWER: HENCE PROVED! Here is your answer! once TRY to SOLVE it yourself!

50.

Please answer the boxed question

Answer»

ANSWER:

HENCE PROVED!

Here is your answer! once TRY to SOLVE it yourself!

Discussion

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