332354 + Interview Questions in Secondary School in Math

1.	Themedianfollowingfinddata- 3117 2,5,9, 9,2,10
Answer» Answer: Hello mate Here is your answer There are 8 terms the middle two terms are ---> 5,9 Median = 5+9/2 = 14/2 = 7 Plz mark as brainliest....

1.

Themedianfollowingfinddata- 3117 2,5,9, 9,2,10

Answer»

Answer:

Hello mate Here is your answer

There are 8 terms

the middle two terms are ---> 5,9

Median = 5+9/2

= 14/2

= 7

Plz mark as brainliest....

Discussion

2.	E area of a square is (25a^2+ 70a + 49). Find its side.
Answer» ANSWER: Step-by-step EXPLANATION:

2.

E area of a square is (25a^2+ 70a + 49). Find its side.

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

3.	The probability of an event that cannot happen is
Answer» the PROBABILITY of an EVENT that cannot HAPPEN is ZERO (0)

Discussion

4.	(ii) Principal=10,500, Time = 3 years, Rate = 12 % per annum
Answer» Answer: Given P = 10000, R = 12%, N = 2. We know that A = P(1 + r/100)^n = > 10000(1 + 12/100)^2 = > 10000(112/100)^2 = > 10000(1.12)^2 = > 10000(1.2544) = > 12544. We know that CI = A - P = 12544 - 10000 = 2544. Hope this HELPS! Plz mark brainliest Step-by-step explanation:

4.

(ii) Principal=10,500, Time = 3 years, Rate = 12 % per annum

Answer»

Answer:

Given P = 10000, R = 12%, N = 2.

We know that A = P(1 + r/100)^n

= > 10000(1 + 12/100)^2

= > 10000(112/100)^2

= > 10000(1.12)^2

= > 10000(1.2544)

= > 12544.

We know that CI = A - P

= 12544 - 10000

= 2544.

Hope this HELPS!

Plz mark brainliest

Step-by-step explanation:

Discussion

5.	Only tell me the answer
Answer» ANSWER:- $lt \: (x \: -> \: <klux>0</klux>) = \frac{cos {}^{2} - <klux>SIN</klux> {}^{2}x \: - 1 }{ \sqrt{x {}^{2} + 1 - 1 } } \\ lt \: (x \: -> \: 0) = \frac{cos2x \: - 1}{ \sqrt{x {}^{2} + 1 } - 1}$ .°. cos $\theta$ -1 / √1 -1 =0/0 FORM. L'HOSPITAL RULE, $lt \: (x \: -> \: 0) = \: \frac{ - sin2x \: (2) - 0}{ \frac{1}{ \cancel1 \sqrt{x {}^{2} + 1 \: . \cancel1x - 0} } } \\ lt \: (x \: -> \: 0) = \: 2(\frac{sin2x}{1x} ) \times ( \sqrt{x {}^{2} + 1 }) \times 1$ .°. lt ( $\theta$ -> 0) = sin $\theta$ / $\theta$ =1 $lt \: (x \: -> \: 0) = - 2 \times 1 \times \sqrt{x {}^{2} + 1} \\ .°. \: lt \: (x \: -> \: 0) = \: - 2 \times \sqrt{0 + 1} \\ .°. \: lt \: (x \: -> \: 0) = \: - 2 \times 1 \\ .°. \: lt \: (x \: -> \: 0) = \red {- 2}$ .°. So FINAL answer is, ${\huge{\boxed{\tt{\red{-2}}}}}$

5.

Only tell me the answer

Answer»

ANSWER:-

$lt \: (x \: -> \: <klux>0</klux>) = \frac{cos {}^{2} - <klux>SIN</klux> {}^{2}x \: - 1 }{ \sqrt{x {}^{2} + 1 - 1 } } \\ lt \: (x \: -> \: 0) = \frac{cos2x \: - 1}{ \sqrt{x {}^{2} + 1 } - 1}$

.°. cos $\theta$ -1 / √1 -1 =0/0 FORM.

L'HOSPITAL RULE,

$lt \: (x \: -> \: 0) = \: \frac{ - sin2x \: (2) - 0}{ \frac{1}{ \cancel1 \sqrt{x {}^{2} + 1 \: . \cancel1x - 0} } } \\ lt \: (x \: -> \: 0) = \: 2(\frac{sin2x}{1x} ) \times ( \sqrt{x {}^{2} + 1 }) \times 1$

.°. lt ( $\theta$ -> 0) = sin $\theta$ / $\theta$ =1

$lt \: (x \: -> \: 0) = - 2 \times 1 \times \sqrt{x {}^{2} + 1} \\ .°. \: lt \: (x \: -> \: 0) = \: - 2 \times \sqrt{0 + 1} \\ .°. \: lt \: (x \: -> \: 0) = \: - 2 \times 1 \\ .°. \: lt \: (x \: -> \: 0) = \red {- 2}$

.°. So FINAL answer is,

${\huge{\boxed{\tt{\red{-2}}}}}$

Discussion

6.	in triangle pqr angle pqr is equals to 90 degree QS perpendicular to QR and ST perpendicular to QR if PQ is S6 edge and PS3 centimetre find the following a area of triangle QS upon area of triangle pqs be area of triangle area of triangle RST Si area of triangle QRS upon area of triangle u s t d area of triangle qsc upon area of triangle pqr if area of triangle RST of an area of triangle pqr if area of trapezium PQ PS upon area of triangle p q r
Answer» ANS. how can QR is papandicular to ST.

6.

in triangle pqr angle pqr is equals to 90 degree QS perpendicular to QR and ST perpendicular to QR if PQ is S6 edge and PS3 centimetre find the following a area of triangle QS upon area of triangle pqs be area of triangle area of triangle RST Si area of triangle QRS upon area of triangle u s t d area of triangle qsc upon area of triangle pqr if area of triangle RST of an area of triangle pqr if area of trapezium PQ PS upon area of triangle p q r

Answer»

ANS.

how can QR is papandicular to ST.

Discussion

7.	Tell me some foods that are almost protein
Answer» Answer: Eggs: Protein-rich eggs are among the healthiest and most NUTRITIOUS foods on EARTH. ... Greek yoghurt: One of the common dairy product Greek yogurt, is a very thick type of yogurt. ... MILK: ... Nuts and seeds: ... Cottage cheese: ... CHICKEN: ... Lentils Almonds: Plz MARK brainliest Step-by-step explanation:

7.

Tell me some foods that are almost protein

Answer»

Answer:

Eggs: Protein-rich eggs are among the healthiest and most NUTRITIOUS foods on EARTH. ...

Greek yoghurt: One of the common dairy product Greek yogurt, is a very thick type of yogurt. ...

MILK: ...

Nuts and seeds: ...

Cottage cheese: ...

CHICKEN: ...

Lentils

Almonds:

Plz MARK brainliest

Step-by-step explanation:

Discussion

8.	4. Find the value of √11 upto 8 decimal place and also say logically itis rational or irrational.
Answer» Answer: 3.3166247903554 is the VALUE of ROOT11

8.

4. Find the value of √11 upto 8 decimal place and also say logically itis rational or irrational.

Answer»

Answer:

3.3166247903554 is the VALUE of ROOT11

Discussion

9.	28. निम्नलिखित में से 104X50 के बराबर क्या है?(a) (100 X 5) + (4X5)(b) (100 X 5) + (4 X 50)(c) (100 X 50)+ (40X 50)(d) (100 X 50)+ (4X50)
Answer» ANSWER: D is the CORRECT answer mark me BRAINLIEST PLS.....

9.

28. निम्नलिखित में से 104X50 के बराबर क्या है?(a) (100 X 5) + (4X5)(b) (100 X 5) + (4 X 50)(c) (100 X 50)+ (40X 50)(d) (100 X 50)+ (4X50)

Answer»

ANSWER:

D is the CORRECT answer

mark me BRAINLIEST PLS.....

Discussion

10.	Find P cube minus Q cube if P minus Q is equal to minus 8, PQ is equal to minus 12
Answer» Answer: The value of P³ - Q³ is -224. STEP-by-step EXPLANATION: It is provided that: $P-Q=-8\\PQ=-12$ The formula of (a + b)² and (a - b)² are: $(a+b)^{2}=a^{2}+b^{2}+2ab\\(a-b)^{2}=a^{2}+b^{2}-2ab$ Use these relations to compute the value of P and Q as FOLLOWS: Step 1: Compute the value of P² + Q² as follows: $(P-Q)^{2}=P^{2}+Q^{2}-2PQ\\(-8)^{2}=P^{2}+Q^{2}-(2\times-12)\\64=P^{2}+Q^{2}+24\\P^{2}+Q^{2}=40$ Step 2: Compute the value of P + Q as follows: $(P+Q)^{2}=P^{2}+Q^{2}+2PQ\\=40+(2\times-12)\\=40-24\\=16\\P+Q=4$ Step 3: Add the equations P - Q = -8 and P + Q = 4 as follows; $P + Q = 4\\P - Q = -8\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\2P=-4\\P=-2$ Step 4: Use the value of P = - 2 in the equation P + Q = 4 and solve for Q as follows: $P+Q=4\\-2+Q=4\\Q=6$ Step 5: Compute the value of P³ - Q³ as follows: $P^{3} -Q^{3}=(-2)^{3}-(6)^{3}=-8-216=-224$ Hence the value of P³ - Q³ is -224.

10.

Find P cube minus Q cube if P minus Q is equal to minus 8, PQ is equal to minus 12

Answer»

Answer:

The value of P³ - Q³ is -224.

STEP-by-step EXPLANATION:

It is provided that:

$P-Q=-8\\PQ=-12$

The formula of (a + b)² and (a - b)² are:

$(a+b)^{2}=a^{2}+b^{2}+2ab\\(a-b)^{2}=a^{2}+b^{2}-2ab$

Use these relations to compute the value of P and Q as FOLLOWS:

Step 1: Compute the value of P² + Q² as follows:

$(P-Q)^{2}=P^{2}+Q^{2}-2PQ\\(-8)^{2}=P^{2}+Q^{2}-(2\times-12)\\64=P^{2}+Q^{2}+24\\P^{2}+Q^{2}=40$

Step 2: Compute the value of P + Q as follows:

$(P+Q)^{2}=P^{2}+Q^{2}+2PQ\\=40+(2\times-12)\\=40-24\\=16\\P+Q=4$

Step 3: Add the equations P - Q = -8 and P + Q = 4 as follows;

$P + Q = 4\\P - Q = -8\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\2P=-4\\P=-2$

Step 4: Use the value of P = - 2 in the equation P + Q = 4 and solve for Q as follows:

$P+Q=4\\-2+Q=4\\Q=6$

Step 5: Compute the value of P³ - Q³ as follows:

$P^{3} -Q^{3}=(-2)^{3}-(6)^{3}=-8-216=-224$

Hence the value of P³ - Q³ is -224.

Discussion

11.	A car travels 540 km in 39 l of petrol how far will travel in 20 l
Answer» Answer: 48 litres = 432 km 20 litres = X km x= (20*432)/48 = 180 km Plz MARK brainliest Step-by-step EXPLANATION:

11.

A car travels 540 km in 39 l of petrol how far will travel in 20 l

Answer»

Answer:

48 litres = 432 km

20 litres = X km

x= (20*432)/48 = 180 km

Plz MARK brainliest

Step-by-step EXPLANATION:

Discussion

12.	(1) If seco +tano = p then find the values of seco, tano & sino terms of p.
Answer» <P>Answer: sec THETA = p - tan tetha tan theta = p - sec theta sin theta = (p)(COS theta) - 1 Step-by-step EXPLANATION: If sec theta + tan theta = p then values of sec theta and tan theta can be identified easily sec theta + tan theta = p → 1/cos theta + sin theta/cos theta = p → 1 + sin theta/cos theta = p → 1 + sin theta =(p)(cos theta) → sin theta = (p)(cos theta) - 1

12.

(1) If seco +tano = p then find the values of seco, tano & sino terms of p.

Answer»

<P>Answer:

sec THETA = p - tan tetha

tan theta = p - sec theta

sin theta = (p)(COS theta) - 1

Step-by-step EXPLANATION:

If sec theta + tan theta = p then values of sec theta and tan theta can be identified easily

sec theta + tan theta = p

→ 1/cos theta + sin theta/cos theta = p

→ 1 + sin theta/cos theta = p

→ 1 + sin theta =(p)(cos theta)

→ sin theta = (p)(cos theta) - 1

Discussion

13.	8. Solve this need urgently
Answer» Step-by-step EXPLANATION: $\text{x = a sin Z}\\\text{a = }\frac{\text{x}}{\text{sin Z}}\\\\\text{y = b cos Z}\\\text{b = }\frac{\text{y}}{\text{cos Z}}\\\\\boxed{\text{To prove that: }\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1}\\\\\\\text{LHS: }\frac{\text{(a sin Z)}^2 \text{ x (sin Z)}^2}{\text{(a sin Z)}^2} + \frac{\text{(b cos Z)}^2 \text{ x (cos Z)}^2}{\text{(b cos Z)}^2}\\\\$ $= \frac{\text{a}^2 \text{sin}^2 \text{Z} \text{ x sin}^2 \text{Z}}{\text{a}^2 \text{sin}^2 \text{Z}} + \frac{\text{b}^2 \text{cos}^2 \text{Z} \text{ x cos}^2 \text{Z}}{\text{b}^2 \text{cos}^2 \text{Z}}\\\\= \text{sin}^2\text{ Z} + \text{cos}^2\text{ Z}\\\\= 1 \\\\\boxed{\text{Hence Proved.}}$ HOPE this HELPS! If it does, please MARK it as brainliest! THANKS :D

13.

8. Solve this need urgently

Answer»

Step-by-step EXPLANATION:

$\text{x = a sin Z}\\\text{a = }\frac{\text{x}}{\text{sin Z}}\\\\\text{y = b cos Z}\\\text{b = }\frac{\text{y}}{\text{cos Z}}\\\\\boxed{\text{To prove that: }\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1}\\\\\\\text{LHS: }\frac{\text{(a sin Z)}^2 \text{ x (sin Z)}^2}{\text{(a sin Z)}^2} + \frac{\text{(b cos Z)}^2 \text{ x (cos Z)}^2}{\text{(b cos Z)}^2}\\\\$

$= \frac{\text{a}^2 \text{sin}^2 \text{Z} \text{ x sin}^2 \text{Z}}{\text{a}^2 \text{sin}^2 \text{Z}} + \frac{\text{b}^2 \text{cos}^2 \text{Z} \text{ x cos}^2 \text{Z}}{\text{b}^2 \text{cos}^2 \text{Z}}\\\\= \text{sin}^2\text{ Z} + \text{cos}^2\text{ Z}\\\\= 1 \\\\\boxed{\text{Hence Proved.}}$

HOPE this HELPS! If it does, please MARK it as brainliest! THANKS :D

Discussion

14.	Sonal made 18 equal parts of aSameer and 4 parts to Sanjana. Find18 equal parts of a watermelon. She gave 3 parts to Rahul, 6 parts toa.Fraction of watermelon given to Rahul.Fraction of watermelon given to Sameer.Fraction of watermelon given to Sanjana.What fraction of watermelon is left with Sonal?
Answer» Answer: hey MATE 1) 3/6 hope this MAY HELP you

14.

Sonal made 18 equal parts of aSameer and 4 parts to Sanjana. Find18 equal parts of a watermelon. She gave 3 parts to Rahul, 6 parts toa.Fraction of watermelon given to Rahul.Fraction of watermelon given to Sameer.Fraction of watermelon given to Sanjana.What fraction of watermelon is left with Sonal?

Answer»

Answer:

hey MATE

1) 3/6

hope this MAY HELP you

Discussion

15.	Express the ratio in their simplest form 20 min to 1 hour
Answer» Answer: 1:3 Step-by-step explanation: 20/60 1/3 ratio : 1:3

15.

Express the ratio in their simplest form 20 min to 1 hour

Answer»

Answer:

1:3

Step-by-step explanation:

20/60

1/3

ratio : 1:3

Discussion

16.	If the point (5,2) lies on the graph of the linear equation kx 5y= 10k find k
Answer» Step-by-step EXPLANATION: K(5)+ 5(2)=10k 5k+10=10k 10=10k-5k 10=5k k=10/5 k=2

16.

If the point (5,2) lies on the graph of the linear equation kx 5y= 10k find k

Answer»

Step-by-step EXPLANATION:

K(5)+ 5(2)=10k

5k+10=10k

10=10k-5k

10=5k

k=10/5

k=2

Discussion

17.	What is the value of 6 tan square theta - 6 sec square theta
Answer» Step-by-step explanation: 6tan sq - 6sec sq 6( TAN sq - SEC sq) 6(1) =6

17.

What is the value of 6 tan square theta - 6 sec square theta

Answer»

Step-by-step explanation:

6tan sq - 6sec sq

6( TAN sq - SEC sq)

6(1)

=6

Discussion

18.	Find the equation for the denominator of the expression1÷√2−5
Answer» Answer: HERE GOES THE ANSWER = - $\sqrt{2}$ +5 23 Step-by-step EXPLANATION: BECAUSE: ON RATIONALISING WE GET, 1 X $\sqrt{2}$ + 5 $\sqrt{2}$ - 5 $\sqrt{2}$ + 5 ⇒ - $\sqrt{2}$ + 5 23 MAKE ME THE BRAINALIEST ANSWER

18.

Find the equation for the denominator of the expression1÷√2−5

Answer»

Answer:

HERE GOES THE ANSWER = - $\sqrt{2}$ +5

23

Step-by-step EXPLANATION:

BECAUSE:

ON RATIONALISING

WE GET,

1 X $\sqrt{2}$ + 5

$\sqrt{2}$ - 5 $\sqrt{2}$ + 5

⇒ - $\sqrt{2}$ + 5

23 MAKE ME THE BRAINALIEST ANSWER

Discussion

19.	The perimeter of the two similar trianglesearches are 12 cm and 72 cm if the area of smaller triangle is 6 cm square find the area of bigger triangle
Answer» Step-by-step explanation: area of BIGGER TRIANGLE is 36 cm SQ

19.

The perimeter of the two similar trianglesearches are 12 cm and 72 cm if the area of smaller triangle is 6 cm square find the area of bigger triangle

Answer»

Step-by-step explanation:

area of BIGGER TRIANGLE is 36 cm SQ

Discussion

20.	Construct a circle with diameter AB =5 cm and construct tangents at A and B.
Answer» Answer: 1) draw a LINE segment of 5 cm on the side of the copy. 2) taking its measure from the compass draw a circle. 3) name the centre O 4)take any point outside the circle and join it with the centre O. 5) name it A 6) draw a perpendicular bisector of OA. 7) name the point of intersection as P. 8) take the measurement of AP or OP. 9) draw a circle touching point A . 10) where the circle cuts the circle with centre O draw LINES . 11) name them B and C . 12) AB and AC are the tangents to the circle hope it HELPS

20.

Construct a circle with diameter AB =5 cm and construct tangents at A and B.

Answer»

Answer:

1) draw a LINE segment of 5 cm on the side of the copy.

2) taking its measure from the compass draw a circle.

3) name the centre O

4)take any point outside the circle and join it with the centre O.

5) name it A

6) draw a perpendicular bisector of OA.

7) name the point of intersection as P.

8) take the measurement of AP or OP.

9) draw a circle touching point A .

10) where the circle cuts the circle with centre O draw LINES .

11) name them B and C .

12) AB and AC are the tangents to the circle

hope it HELPS

Discussion

21.	Find the arithmetic mean of the values of sin0,sin30,cos60,tan45,cot45
Answer» Step-by-step EXPLANATION: sin 0°=0, sin 30°=1/2, sin 45°=1/√2, sin 60°=√3/2, sin 90° = 1 →Mean of GIVEN data = sin 0°+sin 30°+sin 45°+sin 60°+sin 90° all divided by 5 = 0 + 1/2 + 1/√2 + √3/2 + 1 / 5 = 1+√2+√3+2 / 2 × 5 = √2+√3+3 / 10

21.

Find the arithmetic mean of the values of sin0,sin30,cos60,tan45,cot45

Answer»

Step-by-step EXPLANATION:

sin 0°=0, sin 30°=1/2, sin 45°=1/√2, sin 60°=√3/2, sin 90° = 1

→Mean of GIVEN data = sin 0°+sin 30°+sin 45°+sin 60°+sin 90° all divided by 5

= 0 + 1/2 + 1/√2 + √3/2 + 1 / 5

= 1+√2+√3+2 / 2 × 5

= √2+√3+3 / 10

Discussion

22.	The midpoint of line segment joining the points (- 2, 9 and) 4 - 3 is
Answer» उपलब्धकरुनघेणेशक्यहोतेतेसर्वमाहितीमिळालीतरकधीनव्हे

Discussion

23.	Find the coordinates of the foot of the perpendicular and the perpendicular distance of the point (3,-2,4) from the plane 3x+y+6z+12=0.
Answer» HELLO! There are two FORMULAE to use in this question to REACH to the CORRECT ANSWER. Check out the ATTACHMENT for the solution. Thanks!

23.

Find the coordinates of the foot of the perpendicular and the perpendicular distance of the point (3,-2,4) from the plane 3x+y+6z+12=0.

Answer»

HELLO!

There are two FORMULAE to use in this question to REACH to the CORRECT ANSWER. Check out the ATTACHMENT for the solution.

Thanks!

Discussion

24.	What is the total surface area of an open hemisphere of radius r
Answer» Answer: 4πr^2 if the THICKNESS is negligible hope it HELPS

24.

What is the total surface area of an open hemisphere of radius r

Answer»

Answer:

4πr^2

if the THICKNESS is negligible

hope it HELPS

Discussion

25.	Two numbers are in the ratio 4 ratio 7 to difference of their square is 297 find the numbers
Answer» Answer: Let the common ratio be r The, 1ST no. will be 4r and 2ND no. will be 7r Then, ANS = 12 and 21 explained in picture

25.

Two numbers are in the ratio 4 ratio 7 to difference of their square is 297 find the numbers

Answer»

Answer:

Let the common ratio be r

The, 1ST no. will be 4r and 2ND no. will be 7r

Then,

ANS = 12 and 21

explained in picture

Discussion

26.	Give an example of a relation which is both symmetric and anti symmetric and explain it.
Answer» Answer: Reflexive relations can be SYMMETRIC, therefore a relation can be both symmetric and antisymmetric. For a simple example, CONSIDER the equality relation over the SET {1, 2}. This relation is symmetric, since it HOLDS that if a = b then b = a.

26.

Give an example of a relation which is both symmetric and anti symmetric and explain it.

Answer»

Answer:

Reflexive relations can be SYMMETRIC, therefore a relation can be both symmetric and antisymmetric. For a simple example, CONSIDER the equality relation over the SET {1, 2}. This relation is symmetric, since it HOLDS that if a = b then b = a.

Discussion

27.	The compond ratio of 3:4 and the inverse of ratio 4:5 as 45: x find x
Answer» 4562828wuwjusjajwsjsjjdhdhd

Discussion

28.	Answer ppzzzzzzzz who knows
Answer» ANSWER: The lady hair is compared to honey 3 option is right Hope it helps you please MARK it brainlist

28.

Answer ppzzzzzzzz who knows

Answer»

ANSWER:

The lady hair is compared to honey

3 option is right

Hope it helps you please MARK it brainlist

Discussion

29.	5. Using Euler formula in a solid where F=V=5 then find the number of edges in solid
Answer» The number of edges in solid (E) = 8 Step-by-step explanation: GIVEN by question, F = V = 5 To find, the number of edges in solid(E) = ? We know that, Euler's formula, V - E + F = 2 Where, V = The number of VERTICES, E = The number of edges F = The number of faces ∴ V - E + F = 2 Put F = V = 5, we get ⇒ 5 - E + 5 = 2 ⇒ 10 - E = 2 ⇒ E = 10 - 2 = 8 ∴ The number of edges in solid (E) = 8 Thus, the number of edges in solid (E) is 8.

29.

5. Using Euler formula in a solid where F=V=5 then find the number of edges in solid

Answer»

The number of edges in solid (E) = 8

Step-by-step explanation:

GIVEN by question,

F = V = 5

To find, the number of edges in solid(E) = ?

We know that,

Euler's formula,

V - E + F = 2

Where, V = The number of VERTICES,

E = The number of edges

F = The number of faces

∴ V - E + F = 2

Put F = V = 5, we get

⇒ 5 - E + 5 = 2

⇒ 10 - E = 2

⇒ E = 10 - 2 = 8

∴ The number of edges in solid (E) = 8

Thus, the number of edges in solid (E) is 8.

Discussion

30.	plot the following points using the same pair of Axes and the same scale for each one (a) o,6 (b) 2,9 (c) 5,8
Answer» Step-by-step EXPLANATION: here is your ANSWER .........

30.

plot the following points using the same pair of Axes and the same scale for each one (a) o,6 (b) 2,9 (c) 5,8

Answer»

Step-by-step EXPLANATION:

here is your ANSWER .........

Discussion

31.	in figure a(3, a+1) and p(-2,6) also the area ( ∆ oab) = ar(∆opq). find the coordinate of point a and its mirror image with respect to x axis
Answer» ANSWER: Step-by-step explanation: area ( ∆ oab) = ar(∆opq). find the COORDINATE of point a and its MIRROR IMAGE with RESPECT to x axis

31.

in figure a(3, a+1) and p(-2,6) also the area ( ∆ oab) = ar(∆opq). find the coordinate of point a and its mirror image with respect to x axis

Answer»

ANSWER:

Step-by-step explanation:

area ( ∆ oab) = ar(∆opq). find the COORDINATE of point a and its MIRROR IMAGE with RESPECT to x axis

Discussion

32.	Please solve these i need help
Answer» Answer: 1) c or a 2)c 3)b Step-by-step EXPLANATION: PLZ MARK as BRAINLIEST

32.

Please solve these i need help

Answer»

Answer:

1) c

or

a

2)c

3)b

Step-by-step EXPLANATION:

PLZ MARK as BRAINLIEST

Discussion

33.	which the help of remainder theorem find the remainder when the polynomial x cube + x square - 26 X + 24 is divided by X + 4
Answer» Answer: Plz mark brainliest Hope it HELPS U!! Step-by-step explanation:

33.

which the help of remainder theorem find the remainder when the polynomial x cube + x square - 26 X + 24 is divided by X + 4

Answer»

Answer:

Plz mark brainliest

Hope it HELPS U!!

Step-by-step explanation:

Discussion

34.	Hi please prove a^n+b^n=c^n
Answer» a=c-b because POWERS are same it will BECOME a+b=c and then a=c-b

34.

Hi please prove a^n+b^n=c^n

Answer»

a=c-b because POWERS are same it will BECOME a+b=c and then a=c-b

Discussion

35.	What is the formula for finding the height of an acute angled triangle.
Answer» ANSWER: HALF BREADTH HEIGHT

35.

What is the formula for finding the height of an acute angled triangle.

Answer»

ANSWER:

HALF *BREADTH *HEIGHT

Discussion

36.	In this question my doubt is "i solve it in rough and i got the answer 1.015 but the printed answer is 101.906!!!" if I was wrong then what is the correct answer? need step by step explanation or is it possible in this case that i was right nd the printed answer was wrong...?#needhelp#urgentneed #quick
Answer» the ANSWER will be ABSOLUTELY 101.906 . here is my method, as I can't understand ur method hope it HELPS Thanks mark brainliest @ join the ARMY of the SHADOWS

36.

In this question my doubt is "i solve it in rough and i got the answer 1.015 but the printed answer is 101.906!!!" if I was wrong then what is the correct answer? need step by step explanation or is it possible in this case that i was right nd the printed answer was wrong...?#needhelp#urgentneed #quick

Answer»

the ANSWER will be ABSOLUTELY 101.906 .

here is my method,

as I can't understand ur method

hope it HELPS

Thanks

mark brainliest

@ join the ARMY of the SHADOWS

Discussion

37.	Find the radius of a circle whose circumference 15 CM
Answer» Answer: The radius of the CIRCLE is 2.39 CM. Step-by-step explanation: The FORMULA to compute the CIRCUMFERENCE of a circle is: $Circumfmerence=2\pi <klux>R</klux>$ It is provided that the circumference is 15 cm. Compute the value of radius, r as follows: $Circumference=2\pi r\\15=2\pi r\\r=\frac{15}{2\pi}\\ =\frac{15}{2}\times\frac{7}{22} \\=2.39$ Thus, the radius of the circle is 2.39 cm.

37.

Find the radius of a circle whose circumference 15 CM

Answer»

Answer:

The radius of the CIRCLE is 2.39 CM.

Step-by-step explanation:

The FORMULA to compute the CIRCUMFERENCE of a circle is:

$Circumfmerence=2\pi <klux>R</klux>$

It is provided that the circumference is 15 cm.

Compute the value of radius, r as follows:

$Circumference=2\pi r\\15=2\pi r\\r=\frac{15}{2\pi}\\ =\frac{15}{2}\times\frac{7}{22} \\=2.39$

Thus, the radius of the circle is 2.39 cm.

Discussion

38.	Eulars relation for cube
Answer» Step-by-step explanation: Answer: V - E + F = 2; or, in words: the number of vertices, minus the number of edges, plus the number of FACES, is equal to TWO. ... V - E + F = 12 - 30 + 20 = 32 - 30 = 2, as we expected. Euler's formula is true for the cube and the icosahedron

38.

Eulars relation for cube

Answer»

Step-by-step explanation:

Answer: V - E + F = 2; or, in words: the number of vertices, minus the number of edges, plus the number of FACES, is equal to TWO. ... V - E + F = 12 - 30 + 20 = 32 - 30 = 2, as we expected. Euler's formula is true for the cube and the icosahedron

Discussion

39.	Factorise 16x² -16x -21 , 25 x² +25x +6 , 9x² -21xy +10y² , 49 x² -36x +6
Answer» saurav KUMAR Kohli and development projects on a regular THING I would be a good TIME and CONSIDERATION and

Discussion

40.	If x+y=3,xy=2 find (x+y)cube
Answer» Step-by-step explanation: Hope it helps you .......... PLZZ MARK me as a BRAINLIST

40.

If x+y=3,xy=2 find (x+y)cube

Answer»

Step-by-step explanation:

Hope it helps you ..........

PLZZ MARK me as a BRAINLIST

Discussion

41.	The Percentage from of 15/10 is ____ answer
Answer» Answer: 15/10×100 =150% HOPE it MAY HELP you

41.

The Percentage from of 15/10 is ____ answer

Answer»

Answer:

15/10×100

=150%

HOPE it MAY HELP you

Discussion

42.	What is the step by step solution for 1/6 × 3.14 × (100)²
Answer» Step-by-step explanation: 1/6×3.14×(100 × 100) 1/6 ×3.14×10000 5233.33

42.

What is the step by step solution for 1/6 × 3.14 × (100)²

Answer»

Step-by-step explanation:

1/6×3.14×(100 × 100)

1/6 ×3.14×10000

5233.33

Discussion

43.	45/80 so how to convert ?/55marks
Answer» Answer: 1.78 Step-by-step explanation: 45/80 9/16 1.78 I HOPE its HELP you

43.

45/80 so how to convert ?/55marks

Answer»

Answer:

1.78

Step-by-step explanation:

45/80

9/16

1.78

I HOPE its HELP you

Discussion

44.	Log xy^2- log y= log(x+y), then x can be expressed as?
Answer» Step-by-step EXPLANATION: In △ABC AB=AC ⇒∠B=∠C (Angles OPPOSITE to equal sides are equal) Now using angle SUM property ∠A+∠B+∠C=180 ∘ ⇒80 ∘ +∠C+∠C=180 ∘ ⇒2∠C=180 ∘ −80 ∘ ⇒∠C= 2 100 ∘ =50 ∘ now ∠C+∠x=180 ∘ (Angles MADE on straight LINE (AC) are supplementary) ⇒50 ∘ +∠x=180 ∘ ⇒∠x=180 ∘ −50 ∘ =130 ∘ hii hii hii hii hii hope it helps you qrsh

44.

Log xy^2- log y= log(x+y), then x can be expressed as?

Answer»

Step-by-step EXPLANATION:

In △ABC AB=AC

⇒∠B=∠C (Angles OPPOSITE to equal sides are equal)

Now using angle SUM property

∠A+∠B+∠C=180

∘

⇒80

∘

+∠C+∠C=180

∘

⇒2∠C=180

∘

−80

∘

⇒∠C=

2

100

∘

=50

∘

now ∠C+∠x=180

∘

(Angles MADE on straight LINE (AC) are supplementary)

⇒50

∘

+∠x=180

∘

⇒∠x=180

∘

−50

∘

=130

∘

hii

hope it helps you

qrsh

Discussion

45.	Solve 3 power x is equals to 5 power x + 2 using logarithms
Answer» ANSWER: 3powerx=5powerx+2 log3^x=log5^x+2 not SURE about answer

45.

Solve 3 power x is equals to 5 power x + 2 using logarithms

Answer»

ANSWER:

3powerx=5powerx+2

log3^x=log5^x+2

not SURE about answer

Discussion

46.	The solution of the equation Ydx+xdy=xy(dy-dx) is
Answer» Answer: SOORY BRO I don't KNOW this answer me aayi thi NA so

46.

The solution of the equation Ydx+xdy=xy(dy-dx) is

Answer»

Answer:

SOORY BRO I don't KNOW this answer me aayi thi NA so

Discussion

47.	SSLC Karnataka state level prepratory maths question paper 2020 y=p x
Answer» ANSWER: it is AVAILABLE on the GOOGLE

47.

SSLC Karnataka state level prepratory maths question paper 2020 y=p x

Answer»

ANSWER:

it is AVAILABLE on the GOOGLE

Discussion

48.	3 aur 07 ke bich Ek parimay sankhya gyat kijiye
Answer» Answer: 5 7-3=5 5 is a PRIMARY NUMBER.

48.

3 aur 07 ke bich Ek parimay sankhya gyat kijiye

Answer»

Answer:

5

7-3=5

5 is a PRIMARY NUMBER.

Discussion

49.	The rate of interest on a sum of money for the first two years is 6 % p.a., for the next two yearsit is 7% p.a. and 8% p.a. for the period exceeding four year; all at simple interest. If a personearns an interest of Rs. 7,536 by the end of the seven years, what is the amount at the end of theperiod of investment ?
Answer» ANSWER: 8734578 is the CORRECT answer

49.

The rate of interest on a sum of money for the first two years is 6 % p.a., for the next two yearsit is 7% p.a. and 8% p.a. for the period exceeding four year; all at simple interest. If a personearns an interest of Rs. 7,536 by the end of the seven years, what is the amount at the end of theperiod of investment ?

Answer»

ANSWER:

8734578 is the CORRECT answer

Discussion

50.	8 root x upon X + 3 - root x + 3 upon 2 equal to
Answer» Answer: 8rootx/[X+3]-rootx+3/2 bro GIVE the VALUE of x. OTHERWISE how this can be solve Step-by-step EXPLANATION:

50.

8 root x upon X + 3 - root x + 3 upon 2 equal to

Answer»

Answer:

8rootx/[X+3]-rootx+3/2

bro GIVE the VALUE of x. OTHERWISE how this can be solve

Step-by-step EXPLANATION:

Discussion

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BECAUSE:

ON RATIONALISING

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8. Solve this need urgently

HERE GOES THE ANSWER = - $\sqrt{2}$ +5

1 X $\sqrt{2}$ + 5

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⇒ - $\sqrt{2}$ + 5

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