332354 + Interview Questions in Secondary School in Math

1.	He wants to be a scholar,he is studying hardchange into compound and complex sentence
Answer» Compound sentence =He want to be a scholar and he is STUDYING hard COMPLEX sentence =He is studying hard because he want to be a scholar HOPE it HELPS U!!!!

1.

He wants to be a scholar,he is studying hardchange into compound and complex sentence

Answer»

Compound sentence =He want to be a scholar and he is STUDYING hard

COMPLEX sentence =He is studying hard because he want to be a scholar

HOPE it HELPS U!!!!

Discussion

2.	An uncomfortable bed class. how was the narrator woken up
Answer» ANSWER: You don’t need to press a BUTTON when you want to call Bixby; you can do it hands-free with VOICE wake-up. Once this feature is set up, all you have to do is SAY “Hi, Bixby,” and Bixby will make your wish its command. ... More Voice wake-up options Read more on Brainly.in - brainly.in/question/12353261#readmore

2.

An uncomfortable bed class. how was the narrator woken up

Answer»

ANSWER:

You don’t need to press a BUTTON when you want to call Bixby; you can do it hands-free with VOICE wake-up. Once this feature is set up, all you have to do is SAY “Hi, Bixby,” and Bixby will make your wish its command. ... More Voice wake-up options

Read more on Brainly.in - brainly.in/question/12353261#readmore

Discussion

3.	400 mangoes were purchased at 125 per hundred and sold at a loos of 100 find the s.p. of one dozen mangoes.
Answer» Answer: 12 Step-by-step EXPLANATION: total cost = 400 × 125/100 = 500 loss = 100 sp = cp - loss = 500 - 100 = 400 for 400 mangoes sp of 1 MANGO = Re 1 sp of one DOZEN mangoes = 12 × 1 = RS 12

3.

400 mangoes were purchased at 125 per hundred and sold at a loos of 100 find the s.p. of one dozen mangoes.

Answer»

Answer:

12

Step-by-step EXPLANATION:

total cost = 400 × 125/100 = 500

loss = 100

sp = cp - loss = 500 - 100 = 400 for 400 mangoes

sp of 1 MANGO = Re 1

sp of one DOZEN mangoes = 12 × 1 = RS 12

Discussion

4.	A man moved 14 kilometers towards east from the position A.But another man moved 6 kilometers towards west from the position A.What is the distance between them?
Answer» ANSWER: SQUARE ROOT( 14^2 + 6^2) =root(196+36) =root(232) =2√58 KM

4.

A man moved 14 kilometers towards east from the position A.But another man moved 6 kilometers towards west from the position A.What is the distance between them?

Answer»

ANSWER:

SQUARE ROOT( 14^2 + 6^2) =root(196+36) =root(232) =2√58 KM

Discussion

5.	एक बिन्दु, बिन्दुओं (7,-6) और (3, 4) को मिलानेवाली रेखाखण्ड को 1 : 2 के अनुपात में अन्त विभाजितकरता है । बिन्दु सम्बन्धित है:6) प्रथम चतुर्थांश से (ii) द्वितीय चतुर्थाश से(ii) तृतीय चतुर्थांश से (iv) चतुर्थ चतुर्थांश से
Answer» Step-by-step explanation: X = 1(3)+2(7) / 1+2 X = 3+14/3 = 17/3 Y = 1(4)+2(-6)/ 1+2 Y = 4-12/3 = -8/3 point (X,Y) is SITUATED in fourth quadrant

5.

एक बिन्दु, बिन्दुओं (7,-6) और (3, 4) को मिलानेवाली रेखाखण्ड को 1 : 2 के अनुपात में अन्त विभाजितकरता है । बिन्दु सम्बन्धित है:6) प्रथम चतुर्थांश से (ii) द्वितीय चतुर्थाश से(ii) तृतीय चतुर्थांश से (iv) चतुर्थ चतुर्थांश से

Answer»

Step-by-step explanation:

X = 1(3)+2(7) / 1+2

X = 3+14/3 = 17/3

Y = 1(4)+2(-6)/ 1+2

Y = 4-12/3 = -8/3

point (X,Y) is SITUATED in fourth quadrant

Discussion

6.	Find the area of shaded region
Answer» ANSWER: Please take the PICTURE NEAT and tidy i can't understand

6.

Find the area of shaded region

Answer»

ANSWER:

Please take the PICTURE NEAT and tidy i can't understand

Discussion

7.	৯৬৭ সংখ্যা টি ৬ এর স্থানীয় মান ও প্রকৃত মানের যোগফল কত?
Answer» নির্নেয় যোগফল = ৬৬ সমাধান: ৯৬৭ সংখ্যাটিতে ৯ আছে শতকের ঘরে, ৬ আছে দশকের ঘরে ও ৭ আছে এককের ঘরে। অতএব, ৬ -এর স্থানীয় মান = ৬ × ১০ = ৬০ ও ৬ -এর প্রকৃত মান = ৬ ∴ নির্নেয় যোগফল = ৬০ + ৬ = ৬৬ ☆ কোনো সংখ্যার অঙ্কগুলির স্থানীয় মান নির্নয় করতে হলে, এককের স্থানের অঙ্ককে ১ দ্বারা গুণ করতে হবে, দশকের স্থানের অঙ্ককে ১০ দ্বারা গুণ করতে হবে, শতকের স্থানের অঙ্ককে ১০০ দ্বারা গুণ করতে হবে, হাজারের স্থানের অঙ্ককে ১০০০ দ্বারা গুণ করতে হবে, ... যথাক্রমে। আরো একটি ভালো প্রশ্ন: রাজিয়া তার টাকার 2/5 অংশ দেবনাথকে ও 3/10 অংশ সুনিতাকে দেওয়ার পরে তার কাছে 180 টাকা রইল। প্রথমে রাজিয়ার কাছে কতো টাকা ছিল? - brainly.in/question/8695672

7.

৯৬৭ সংখ্যা টি ৬ এর স্থানীয় মান ও প্রকৃত মানের যোগফল কত?

Answer»

নির্নেয় যোগফল = ৬৬

সমাধান:

৯৬৭ সংখ্যাটিতে ৯ আছে শতকের ঘরে, ৬ আছে দশকের ঘরে ও ৭ আছে এককের ঘরে।

অতএব, ৬ -এর স্থানীয় মান = ৬ × ১০ = ৬০

ও ৬ -এর প্রকৃত মান = ৬

∴ নির্নেয় যোগফল = ৬০ + ৬

= ৬৬

☆ কোনো সংখ্যার অঙ্কগুলির স্থানীয় মান নির্নয় করতে হলে, এককের স্থানের অঙ্ককে ১ দ্বারা গুণ করতে হবে, দশকের স্থানের অঙ্ককে ১০ দ্বারা গুণ করতে হবে, শতকের স্থানের অঙ্ককে ১০০ দ্বারা গুণ করতে হবে, হাজারের স্থানের অঙ্ককে ১০০০ দ্বারা গুণ করতে হবে, ... যথাক্রমে।

আরো একটি ভালো প্রশ্ন:

রাজিয়া তার টাকার 2/5 অংশ দেবনাথকে ও 3/10 অংশ সুনিতাকে দেওয়ার পরে তার কাছে 180 টাকা রইল। প্রথমে রাজিয়ার কাছে কতো টাকা ছিল? - brainly.in/question/8695672

Discussion

8.	ABCD is a parallelelogram with are 360cm square AB =30cm AE is perpendicular drawn to DC in such that DE =5cm find DC
Answer» Step-by-step EXPLANATION: In a PARALLELOGRAM OPPOSITE SIDES are equal. therefore AB=CD CD=30CM or DC=30CM

8.

ABCD is a parallelelogram with are 360cm square AB =30cm AE is perpendicular drawn to DC in such that DE =5cm find DC

Answer»

Step-by-step EXPLANATION:

In a PARALLELOGRAM OPPOSITE SIDES are equal.

therefore AB=CD

CD=30CM or DC=30CM

Discussion

9.	3^6×3^2×a^3/3^3×3^4×a = P . Find the value of P and P^2
Answer» Answer: 3^6×3^2×a^3/3^3×3^4×a=p 3^12×a^4=p×3^3 3^12/3^3×a^4=p 3^9×a^4=p Step-by-step EXPLANATION: PLZ..................MARK it as BRAINLIEST

9.

3^6×3^2×a^3/3^3×3^4×a = P . Find the value of P and P^2

Answer»

Answer:

3^6×3^2×a^3/3^3×3^4×a=p

3^12×a^4=p×3^3

3^12/3^3×a^4=p

3^9×a^4=p

Step-by-step EXPLANATION:

PLZ..................MARK it as BRAINLIEST

Discussion

10.	I am an integer when you subtract me from -6 the result will be -10 what I am
Answer» ANSWER: the correct answer is -16 -16-(-6) = -16+6 = -10 .. the correct answer is -16 ... please MARK as brainliest answer and follow me

10.

I am an integer when you subtract me from -6 the result will be -10 what I am

Answer»

ANSWER:

the correct answer is

-16

-16-(-6) = -16+6 = -10 ..

the correct answer is -16 ...

please MARK as brainliest answer and follow me

Discussion

11.	An article was bought for 1250 and sold at a loss of 12 1/2
Answer» ANSWER: What do we NEED to FIND here ? if it is s.p. then s.p.=1250-25/2 = 1237.5

11.

An article was bought for 1250 and sold at a loss of 12 1/2

Answer»

ANSWER:

What do we NEED to FIND here ?

if it is s.p.

then s.p.=1250-25/2

= 1237.5

Discussion

12.	Ahmed borrowed 1200 from his friend at 8% per annual of interest he returned the money after eight month what interest did he pay to his friend find the amount
Answer» INTEREST =8/100×1200 =₹96 total amount=1200+96 =₹1396

12.

Ahmed borrowed 1200 from his friend at 8% per annual of interest he returned the money after eight month what interest did he pay to his friend find the amount

Answer»

INTEREST =8/100×1200

=₹96

total amount=1200+96

=₹1396

Discussion

13.	4. Using a suitable identity, evaluate 49 x 51.
Answer» $\huge\mathcal\pink{Hey!}$ $49 \times 51 \\ (50 - 1)(50 + 1) \\ {50}^{2} - 1 \\ 2500 - 1 \\ 2499$

13.

4. Using a suitable identity, evaluate 49 x 51.

Answer»

$\huge\mathcal\pink{Hey!}$

$49 \times 51 \\ (50 - 1)(50 + 1) \\ {50}^{2} - 1 \\ 2500 - 1 \\ 2499$

Discussion

14.	An article was bought for $12500and sold at a loss of 121/2% find the loss and selling price
Answer» Step-by-step EXPLANATION: *COST* *Price (CP) of an article = ₹12,500 LOSS%* of *the* *article* = 121/2% Loss = Loss%/100×CP = 121/2÷100×12500= ₹7562.5 Now, SP of the article = CP-Loss = ₹12500-₹7562.5 = ₹4937.5 Hope you understand Please MAKE** me as brainliest ✌️✌️✌️

14.

An article was bought for $12500and sold at a loss of 121/2% find the loss and selling price

Answer»

Step-by-step EXPLANATION:

COST Price (CP) of an article = ₹12,500

LOSS% of the article = 121/2%

Loss = Loss%/100×CP = 121/2÷100×12500= ₹7562.5

Now, SP of the article = CP-Loss = ₹12500-₹7562.5 = ₹4937.5

Hope you understand

Please MAKE me as brainliest ✌️✌️✌️

Discussion

15.	Plzz give me solution
Answer» Step-by-step EXPLANATION: Principal = ₹1200 Rate of Interest = 8% Time = 8 months = 8/12 years = 2/3 years INTEREST (SI) = PTR/100 = 1200×2/3×8 ÷ 100 ------> 1200×2×8/100×3 ------> ₹64 So, Interest = ₹64 Amount = Principal+Simple Interest = 1200+64 = ₹1264. ----------------- Hope it helps you Please make me as brainliest ✌️✌️✌️

15.

Plzz give me solution

Answer»

Step-by-step EXPLANATION:

Principal = ₹1200

Rate of Interest = 8%

Time = 8 months = 8/12 years = 2/3 years

INTEREST (SI) = PTR/100 = 1200×2/3×8 ÷ 100

------> 1200×2×8/100×3

------> ₹64

So, Interest = ₹64

Amount = Principal+Simple Interest = 1200+64 = ₹1264.

-----------------

Hope it helps you

Please make me as brainliest ✌️✌️✌️

Discussion

16.	Size of class interval 0-9 , 1-9
Answer» ~9-O=9size ~9-1=8size ~i THINGS it ~will HELP y. ... ..

16.

Size of class interval 0-9 , 1-9

Answer»

~9-O=9size

~9-1=8size

~i THINGS it

~will HELP y. ... ..

Discussion

17.	M e positive oddnumbers is 143. Construct the equation anddetermine the numbers by applying SridharaAcharyya's formula.Answer any one question :-(i)x=2 + V3 and x + y = 4, then find the simplestvalue of xy +ху
Answer» Step-by-step EXPLANATION: LET, the 1st no be X and 2ND no be x + 2 so , x ( x + 2 ) = 143 x² + 2x - 143 = 0 comparing the equation from ax² + bx + c = 0 we get , a = 1 , b = 2 , c = - 143 Sridhara Acharyya's formula. $\frac{ - b \: ± \: \sqrt{ {b}^{2} - 4ac} }{2a} = \frac{ - 2 \: ± \: \: \sqrt{ { - 2}^{2} - 4.1.( - 143)} }{2.1} \\ \frac{ - 2 \: \: ± \: \sqrt{4 + 572} }{2} \\ \frac{ - 2 \: ± \: \sqrt{576} }{2} \\ \frac{ - 2 + 24}{2} = \frac{22}{2} = 11 \\ \frac{ - 2 - 24}{2} = \frac{ - 26}{2} = - 13$ therefore , 11 and -13 are the roots of given equation.

17.

M e positive oddnumbers is 143. Construct the equation anddetermine the numbers by applying SridharaAcharyya's formula.Answer any one question :-(i)x=2 + V3 and x + y = 4, then find the simplestvalue of xy +ху

Answer»

Step-by-step EXPLANATION:

LET, the 1st no be X and 2ND no be x + 2

so , x ( x + 2 ) = 143

x² + 2x - 143 = 0

comparing the equation from ax² + bx + c = 0 we get , a = 1 , b = 2 , c = - 143

Sridhara

Acharyya's formula.

$\frac{ - b \: ± \: \sqrt{ {b}^{2} - 4ac} }{2a} = \frac{ - 2 \: ± \: \: \sqrt{ { - 2}^{2} - 4.1.( - 143)} }{2.1} \\ \frac{ - 2 \: \: ± \: \sqrt{4 + 572} }{2} \\ \frac{ - 2 \: ± \: \sqrt{576} }{2} \\ \frac{ - 2 + 24}{2} = \frac{22}{2} = 11 \\ \frac{ - 2 - 24}{2} = \frac{ - 26}{2} = - 13$

therefore , 11 and -13 are the roots of given equation.

Discussion

18.	Please answer question no. 3.
Answer» Answer class 0 exercise 2.3 questions 3 PLZ thanks

18.

Please answer question no. 3.

Answer»

Answer

class 0 exercise 2.3 questions 3 PLZ thanks

Discussion

19.	What is the number1000 of pairs before it?
Answer» Answer: 1000 or one thousand is the NATURAL NUMBER following 999 and PRECEDING 1001. In most English-speaking COUNTRIES, it is often written with a comma separating the thousands unit: 1,000

19.

What is the number1000 of pairs before it?

Answer»

Answer:

1000 or one thousand is the NATURAL NUMBER following 999 and PRECEDING 1001. In most English-speaking COUNTRIES, it is often written with a comma separating the thousands unit: 1,000

Discussion

20.	8 cosec^2a - 8 cot^2a=?
Answer» Answer:8 cosec^2A - 8cot^2A = 8 Step-by-step explanation: 8/sin^2A - 8cos^2A/sin^2A (8 - 8 cos^2A)/sin^2A 8(1 - cos^2A)/sin^2A. [1cos^2A=sin^2A] 8 sin^2A/sin^2A 8

20.

8 cosec^2a - 8 cot^2a=?

Answer»

Answer:8 cosec^2A - 8cot^2A = 8

Step-by-step explanation:

8/sin^2A - 8cos^2A/sin^2A

(8 - 8 cos^2A)/sin^2A

8(1 - cos^2A)/sin^2A. [1cos^2A=sin^2A]

8 sin^2A/sin^2A

8

Discussion

21.	What is the number of pairs before it?
Answer» *Hyyy* *MATE* *the* *QUESTION* is *just* *incomplete* or UNNECESSARY.. THANK you**

21.

What is the number of pairs before it?

Answer»

Hyyy MATE the QUESTION is just incomplete or UNNECESSARY..

THANK you

Discussion

22.	(-23)+?=-23=(-23)+?
Answer» Answer: I don't KNOW if you can get the BEST answer so PLEASE TELL me

22.

(-23)+?=-23=(-23)+?

Answer»

Answer:

I don't KNOW if you can get the BEST answer so PLEASE TELL me

Discussion

23.	The point'P' moves such that the sum of the squares of its distance from A(a,0)B(-a, 0) is constant and is equal to 6a. The locus of P is
Answer» ANSWER: HI please HELP Step-by-step explanation: 1235864668 it is number of my GF

23.

The point'P' moves such that the sum of the squares of its distance from A(a,0)B(-a, 0) is constant and is equal to 6a. The locus of P is

Answer»

ANSWER:

HI

please HELP

Step-by-step explanation:

1235864668 it is number of my GF

Discussion

24.	a square of side 60 cm and a rectangle of length 80 cm have the same perimeter. which encloses more place
Answer» ANSWER: MARK as BRAINLIEST........ and hope it HELPS you.........

24.

a square of side 60 cm and a rectangle of length 80 cm have the same perimeter. which encloses more place

Answer»

ANSWER:

MARK as BRAINLIEST........

and

hope it HELPS you.........

Discussion

25.	a coin is tossed 1000 times wit the frequency of tail 448, what is the probability of getting a head
Answer» Answer: 552/1000=69/125 Step-by-step EXPLANATION: hope it is HELPFUL, MARK it brainliest, mark it brainliest,follow me for further help have a GOOD DAY

25.

a coin is tossed 1000 times wit the frequency of tail 448, what is the probability of getting a head

Answer»

Answer:

552/1000=69/125

Step-by-step EXPLANATION:

hope it is HELPFUL,

MARK it brainliest,

mark it brainliest,follow me for further help

have a GOOD DAY

Discussion

26.	2 x square - 5 x + 3 equal to zero in Quardartic formula
Answer» Step-by-step explanation: 2x^2-2x-3x+3 2x (x-1)-3 (x-1) x÷1 x=3/2

26.

2 x square - 5 x + 3 equal to zero in Quardartic formula

Answer»

Step-by-step explanation:

2x^2-2x-3x+3

2x (x-1)-3 (x-1)

x÷1 x=3/2

Discussion

27.	Plz solve....❤❤.....
Answer» ANSWER: π Step-by-step explanation: Solution-----> 1) Plzzz SEE the attachment 2) We know that, a) ( - x )³ = - x³ B ) Cos ( - x ) = COSX c) ∫√(a² - x² ) DX = x/2 √(a² - x²) + a²/2 Sin⁻¹ (x / a) + C

27.

Plz solve....❤❤.....

Answer»

ANSWER:

π

Step-by-step explanation:

Solution-----> 1) Plzzz SEE the attachment

2) We know that,

a) ( - x )³ = - x³

B ) Cos ( - x ) = COSX

c)

∫√(a² - x² ) DX = x/2 √(a² - x²) + a²/2 Sin⁻¹ (x / a) + C

Discussion

28.	Lf cosec theta =13/12 then find the values of cot theta and sin theta
Answer» ANSWER: SIN THETA =12/13.

28.

Lf cosec theta =13/12 then find the values of cot theta and sin theta

Answer»

ANSWER:

SIN THETA =12/13.

Discussion

29.	What must be added to 4x^2+12x+5 to make it as a perfect square
Answer» ANSWER: YES it is a PERFECT SQUARE

29.

What must be added to 4x^2+12x+5 to make it as a perfect square

Answer»

ANSWER:

YES it is a PERFECT SQUARE

Discussion

30.	Area of semicircle equal to of square equal to of into 38.5 by 2 equal =19.25
Answer» Step-by-step EXPLANATION: What's your QUESTION MATE? PLEASE COMPLETE the question ✌️✌️✌️

30.

Area of semicircle equal to of square equal to of into 38.5 by 2 equal =19.25

Answer»

Step-by-step EXPLANATION:

What's your QUESTION MATE?

PLEASE COMPLETE the question ✌️✌️✌️

Discussion

31.	Cosec 40 – cot 80 = tan 20 + cosec 80
Answer» Step-by-step EXPLANATION: sorry BRO CANT COME with the final ANSWER

31.

Cosec 40 – cot 80 = tan 20 + cosec 80

Answer»

Step-by-step EXPLANATION:

sorry BRO CANT COME with the final ANSWER

Discussion

32.	Which is greater -7 by 20 or -5 by 18
Answer» ANSWER: -5/18is GREATER here,,

32.

Which is greater -7 by 20 or -5 by 18

Answer»

ANSWER:

-5/18is GREATER here,,

Discussion

33.	The base of a parallelogram is 9cm and the area is 54cmsq find the height of the parallelogram
Answer» ANSWER: HOPE it HELPS you... plz plz MARK as brainliest.....

33.

The base of a parallelogram is 9cm and the area is 54cmsq find the height of the parallelogram

Answer»

ANSWER:

HOPE it HELPS you...

plz plz MARK as brainliest.....

Discussion

34.	Swer the following questions :sterm of two A.P.s are equal and the ratios of their commonofof first A.P. and 21th termdifferences is 1 : 2. If the 7th termsecond A.P. are 23 and 125 respectively. Find two A.P.S.
Answer» ANSWER: SORRY I don't KNOW Step-by-step EXPLANATION: sorry I don't know

34.

Swer the following questions :sterm of two A.P.s are equal and the ratios of their commonofof first A.P. and 21th termdifferences is 1 : 2. If the 7th termsecond A.P. are 23 and 125 respectively. Find two A.P.S.

Answer»

ANSWER:

SORRY I don't KNOW

Step-by-step EXPLANATION:

sorry I don't know

Discussion

35.	If 1, 4, x, 5 and 12 is 7, then the value of x is(A) 6(B)8(C) 13(d)9
Answer» Answer: 7=(1+4+5+12+x)/5 35=22+x x=13

35.

If 1, 4, x, 5 and 12 is 7, then the value of x is(A) 6(B)8(C) 13(d)9

Answer»

Answer:

7=(1+4+5+12+x)/5

35=22+x

x=13

Discussion

36.	What must be added to 4x^+12x+5 to make it as a perfect square
Answer» ANSWER: INAPPROPRIATE QUESTION

36.

What must be added to 4x^+12x+5 to make it as a perfect square

Answer»

ANSWER:

INAPPROPRIATE QUESTION

Discussion

37.	In a triangle ABC, DE//BC,AD=4.8cm,AE=6.4cm,Ec=9.6cm,FIND THE AB
Answer» ANSWER: USE the 1ST THEOREM of this CHAPTER

37.

In a triangle ABC, DE//BC,AD=4.8cm,AE=6.4cm,Ec=9.6cm,FIND THE AB

Answer»

ANSWER:

USE the 1ST THEOREM of this CHAPTER

Discussion

38.	Find the ratio between the circumference of two circle whose radio are in the radio 2:3
Answer» Answer: 2:3 Step-by-step EXPLANATION: R1:r2=2:3 ratio of CIRCUMFERENCE of RADIUS is 2:3 circumference of r1= 2πr1 circumference of r2=2πr2 ratio =2πr1/2πr2 where 2*π will cancel ratio =r1/r2 =2:3

38.

Find the ratio between the circumference of two circle whose radio are in the radio 2:3

Answer»

Answer:

2:3

Step-by-step EXPLANATION:

R1:r2=2:3

ratio of CIRCUMFERENCE of RADIUS is 2:3

circumference of r1= 2*π*r1

circumference of r2=2*π*r2

ratio =2*π*r1/2*π*r2

where 2*π will cancel

ratio =r1/r2

=2:3

Discussion

39.	The circumference of circle is 31.4cm. find the radius and the area of the circle ?
Answer» ANSWER: r=5cm Step-by-step EXPLANATION: USING the formula C=2πr Solving forr r=C 2π=31.4 2·π≈4.99747cm

39.

The circumference of circle is 31.4cm. find the radius and the area of the circle ?

Answer»

ANSWER:

r=5cm

Step-by-step EXPLANATION:

USING the formula

C=2πr

Solving forr

r=C

2π=31.4

2·π≈4.99747cm

Discussion

40.	Tan² O + cot²0+2= sec²o. cosec²o
Answer» ANSWER: the ANSWERS is GIVEN above

40.

Tan² O + cot²0+2= sec²o. cosec²o

Answer»

ANSWER:

the ANSWERS is GIVEN above

Discussion

41.	1.34256÷0.8929 please with steps
Answer» Step-by-step EXPLANATION: -£-_83:3738&__-_6375-_74;4674-373&333-4746384

41.

1.34256÷0.8929 please with steps

Answer»

Step-by-step EXPLANATION:

-£-_83:3738&__-_6375-_74;4674-373&333-4746384

Discussion

42.	X^5+2x^3+x^2+4x+12 in standard form
Answer» Step-by-step EXPLANATION: (x) × (x) × (x) × (x) × (x) + 2 × (x) × (x) × (x) + (x) × (x) +4 × (x) +10+2 bhi like or RATE to banta HAI

42.

X^5+2x^3+x^2+4x+12 in standard form

Answer»

Step-by-step EXPLANATION:

(x) × (x) × (x) × (x) × (x) + 2 × (x) × (x) × (x) + (x) × (x) +4 × (x) +10+2

bhi like or RATE to banta HAI

Discussion

43.	Find the value of and the working out
Answer» Step-by-step EXPLANATION: √3.7²+5.2² = 6.382005954

43.

Find the value of and the working out

Answer»

Step-by-step EXPLANATION:

√3.7²+5.2²

= 6.382005954

Discussion

44.	प्रश्न 26. अवकल समीकरण ydx-(r+2yhdy =ध्यापक हल ज्ञात कीजिए।
Answer» ANSWER: hfugf Step-by-step EXPLANATION: gxgcgdygufuhkgyfug0

44.

प्रश्न 26. अवकल समीकरण ydx-(r+2yhdy =ध्यापक हल ज्ञात कीजिए।

Answer»

ANSWER:

hfugf

Step-by-step EXPLANATION:

gxgcgdygufuhkgyfug0

Discussion

45.	Which command is used to move text from one new position to other position?
Answer» Step-by-step EXPLANATION: you MUST SEARCH it on GOOGLE

45.

Which command is used to move text from one new position to other position?

Answer»

Step-by-step EXPLANATION:

you MUST SEARCH it on GOOGLE

Discussion

46.	The total cost of a.packet of biscuit and a tofee is rs22 . If the cost of biscuit is rs 14 more than the cost of toffee find their cost.
Answer» let the COST of BISCUIT and a TOFEE be 14+x and x. now, the total is rs22 so, x+x+14=22 2x=22-14 x=8/2 so, x= rs4 cost of toffee=x= rs4 cost of biscuit=x+14=4+14= rs18 Hope it will HELP you.

46.

The total cost of a.packet of biscuit and a tofee is rs22 . If the cost of biscuit is rs 14 more than the cost of toffee find their cost.

Answer»

let the COST of BISCUIT and a TOFEE be 14+x and x.

now, the total is rs22

so, x+x+14=22

2x=22-14

x=8/2

so, x= rs4

cost of toffee=x= rs4

cost of biscuit=x+14=4+14= rs18

Hope it will HELP you.

Discussion

47.	What is the odd number after 999?
Answer» ANSWER: ODD no. is 1001

47.

What is the odd number after 999?

Answer»

ANSWER:

ODD no. is 1001

Discussion

48.	The breadth of a rectangle is 5m and its area is 100cmsq find the length of the rectangle
Answer» ANSWER: Step-by-step EXPLANATION:

48.

The breadth of a rectangle is 5m and its area is 100cmsq find the length of the rectangle

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

49.	Mani chooses 2hats from acolletion of 10hats.what fraction of the collection did he choose
Answer» Answer: 2/10 this is the FRACTIONS he CHOOSE

49.

Mani chooses 2hats from acolletion of 10hats.what fraction of the collection did he choose

Answer»

Answer:

2/10 this is the FRACTIONS he CHOOSE

Discussion

50.	Plz answer this question fast .its important
Answer» ANSWER: Rs 5000 Step-by-step explanation: area of trapezium = 1/2 × (SUM of parallel sides) × h as there are two trapezium so multiply by 2 = 1/2 × 2(15 + 10) × 40(HEIGHT of both trapezium) = 1/2 × 50 × 40 = 1/2 × 2000 = 1000 cm² cost = 50/10 × 1000 = 5000 Rs

50.

Plz answer this question fast .its important

Answer»

ANSWER:

Rs 5000

Step-by-step explanation:

area of trapezium = 1/2 × (SUM of parallel sides) × h

as there are two trapezium so multiply by 2

= 1/2 × 2(15 + 10) × 40(HEIGHT of both trapezium)

= 1/2 × 50 × 40

= 1/2 × 2000

= 1000 cm²

cost = 50/10 × 1000 = 5000 Rs

Discussion

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