332354 + Interview Questions in Secondary School in Math

1.	write first five whole numbers in p upon Q form where p and q are integers and q is not equal to zero
Answer» Answer: 1/1 , 2/1 , 1/3 , 1/4 , 0/1

1.

write first five whole numbers in p upon Q form where p and q are integers and q is not equal to zero

Answer»

Answer:

1/1 , 2/1 , 1/3 , 1/4 , 0/1

Discussion

2.	4 QC - 6TD - 3 TC + 82D
Answer» ANSWER: what is this to which it is RELATED to

2.

4 QC - 6TD - 3 TC + 82D

Answer»

ANSWER:

what is this

to which it is RELATED to

Discussion

3.	3,5,7,12,17,19 odd man out
Answer» Answer: 12 is odd because every NUMBER is not DIVISIBLE by 2 and 12 is the only DIGIT that is multiple of 2

3.

3,5,7,12,17,19 odd man out

Answer»

Answer:

12 is odd because every NUMBER is not DIVISIBLE by 2 and 12 is the only DIGIT that is multiple of 2

Discussion

4.	एक खेत समलंब के आकार का है जिसकी समांतर भुजाएँ 25 m और 10 m हैं। इसकी असमांतर भुजाएँ 14 m और 13 m हैं। इस खेत का क्षेत्रफल ज्ञात कीजिए।
Answer» Answer: समलंब ABCD का क्षेत्रफल 196 मी² है। Step-by-step explanation: यहां, ABCD एक समलंब है तथा AB \|\| DC C से होकर CM ⊥ AB and CE \|\| AD. दिया है : AB = 25 मी , CD = 10 मी , AD = 13 भी तथा BC = 14 मी BE = AB – AE = 25 – 10 = 15 मी ΔBCE में, माना, BC(a) = 14मी , CE (b) = 13 मी तथा BE (c) = 15 मी त्रिभुज ΔBCE का अर्द्ध परिमाप, s = (a + b + c)/2 s = (15 + 13 + 14)/2 s = 21 मी हीरोन के सूत्र से, त्रिभुज ΔBCE का क्षेत्रफल , A = √[s (s - a) (s - b) (s - c)] A = √21(21 – 14) (21 – 13) (21 – 15) A = √21 × 7 × 8 × 6 A = 84 मी² त्रिभुज ΔBCE का क्षेत्रफल = 84 मी² त्रिभुज ΔBCE का क्षेत्रफल = 1/2 × BE × CM 84 मी² = 1/2 × 15 × CM 84 × 2 = 15 CM ⇒ CM = 168/15 ⇒ CM = 56/5 CM = 11.2 मी समलंब ABCD का क्षेत्रफल = ½(समांतर भुजाओं का योग) × (समांतर भुजाओं के बीच की दूरी) = ½ (AB + CD) × CM = ½ × (25 + 10) × 11.2 = ½ × 35 × 11.2 = 35 × 5.6 = 196 मी² समलंब ABCD का क्षेत्रफल = 196 मी² अतः, समलंब ABCD का क्षेत्रफल 196 मी² है। आशा है कि यह उत्तर आपकी मदद करेगा। इस पाठ से संबंधित कुछ और प्रश्न : फर्श पर एक फूलों का डिजाइन 16 त्रिभुजाकार टाइलों से बनाया गया है, जिनमें से प्रत्येक की भुजाएँ 9 cm, 28 cm और 35 cm हैं (देखिए आकृति 12.18)। इन टाइलों को 50 पैसे प्रति $cm^{2}$ की दर से पालिश कराने का व्यय ज्ञात कीजिए। brainly.in/question/10317569 एक पतंग तीन भिन्न-भिन्न शेडों (shades) के कागजों से बनी है। इन्हें आकृति 12.17 में I,II और III से दर्शाया गया है। पतंग का ऊपरी भाग 32 cm विकर्ण का एक वर्ग है और निचला भाग 6 cm, 6 cm और 8 cm भुजाओं का एक समद्विबाहु त्रिभुज है। ज्ञात कीजिए कि प्रत्येक शेड का कितना कागज प्रयुक्त किया गया है। brainly.in/question/10316747

4.

एक खेत समलंब के आकार का है जिसकी समांतर भुजाएँ 25 m और 10 m हैं। इसकी असमांतर भुजाएँ 14 m और 13 m हैं। इस खेत का क्षेत्रफल ज्ञात कीजिए।

Answer»

Answer:

समलंब ABCD का क्षेत्रफल 196 मी² है।

Step-by-step explanation:

यहां, ABCD एक समलंब है तथा AB || DC

C से होकर CM ⊥ AB and CE || AD.

दिया है : AB = 25 मी , CD = 10 मी , AD = 13 भी तथा BC = 14 मी

BE = AB – AE = 25 – 10 = 15 मी

ΔBCE में,

माना, BC(a) = 14मी , CE (b) = 13 मी तथा BE (c) = 15 मी

त्रिभुज ΔBCE का अर्द्ध परिमाप, s = (a + b + c)/2

s = (15 + 13 + 14)/2

s = 21 मी

हीरोन के सूत्र से, त्रिभुज ΔBCE का क्षेत्रफल , A = √[s (s - a) (s - b) (s - c)]

A = √21(21 – 14) (21 – 13) (21 – 15)

A = √21 × 7 × 8 × 6

A = 84 मी²

त्रिभुज ΔBCE का क्षेत्रफल = 84 मी²

त्रिभुज ΔBCE का क्षेत्रफल = 1/2 × BE × CM

84 मी² = 1/2 × 15 × CM

84 × 2 = 15 CM

⇒ CM = 168/15

⇒ CM = 56/5

CM = 11.2 मी

समलंब ABCD का क्षेत्रफल = ½(समांतर भुजाओं का योग) × (समांतर भुजाओं के बीच की दूरी)

= ½ (AB + CD) × CM

= ½ × (25 + 10) × 11.2

= ½ × 35 × 11.2

= 35 × 5.6

= 196 मी²

समलंब ABCD का क्षेत्रफल = 196 मी²

अतः, समलंब ABCD का क्षेत्रफल 196 मी² है।

आशा है कि यह उत्तर आपकी मदद करेगा।

इस पाठ से संबंधित कुछ और प्रश्न :

फर्श पर एक फूलों का डिजाइन 16 त्रिभुजाकार टाइलों से बनाया गया है, जिनमें से प्रत्येक की भुजाएँ 9 cm, 28 cm और 35 cm हैं (देखिए आकृति 12.18)। इन टाइलों को 50 पैसे प्रति $cm^{2}$ की दर से पालिश कराने का व्यय ज्ञात कीजिए।

brainly.in/question/10317569

एक पतंग तीन भिन्न-भिन्न शेडों (shades) के कागजों से बनी है। इन्हें आकृति 12.17 में I,II और III से दर्शाया गया है। पतंग का ऊपरी भाग 32 cm विकर्ण का एक वर्ग है और निचला भाग 6 cm, 6 cm और 8 cm भुजाओं का एक समद्विबाहु त्रिभुज है। ज्ञात कीजिए कि प्रत्येक शेड का कितना कागज प्रयुक्त किया गया है।

brainly.in/question/10316747

Discussion

5.	Find the value of a, b, c
Answer» HOPE it HELPS u e) a=6,b=5 f)a=5,b=4,c=0 $Mark as brainliest Answer. and please follow me$

5.

Find the value of a, b, c

Answer»

HOPE it HELPS u

e) a=6,b=5

f)a=5,b=4,c=0

$Mark as brainliest Answer. and please follow me$

Discussion

6.	Pls pls pls pls pls pls pls pls pls pls solve this no spam answer
Answer» Answer: 17√2 Step-by-step EXPLANATION: CUBE ROOT of : 250=5√2 16=2√2 54=3√2 substituting VALUES of cube root in QUES we get 35√2+72√2-4*3√2 =15√2+14√2-12√2 =17√2

6.

Pls pls pls pls pls pls pls pls pls pls solve this no spam answer

Answer»

Answer:

17√2

Step-by-step EXPLANATION:

CUBE ROOT of :

250=5√2

16=2√2

54=3√2

substituting VALUES of cube root in QUES we get

3*5√2+7*2√2-4*3√2

=15√2+14√2-12√2

=17√2

Discussion

7.	(outside the circle) prove thatBE = DE.
Answer» ANSWER: where's IMAGE ? to PROVE BE=DE

7.

(outside the circle) prove thatBE = DE.

Answer»

ANSWER:

where's IMAGE ? to PROVE BE=DE

Discussion

8.	The sum of three consecutive odd number is 51. Find the number
Answer» Step-by-step EXPLANATION: The NUMBERS are are y,y+1 and y+4 as they are consecutive ODD numbers it is GIVEN that their sum is 51 therefore, y+y+1+y+4=51 3y+6=51 y=(51-6)/3=45/3 =15 hence the numbers are: y=15 y+2=17 y+4=19 the numbers are 15,17,19

8.

The sum of three consecutive odd number is 51. Find the number

Answer»

Step-by-step EXPLANATION:

The NUMBERS are are y,y+1 and y+4 as they are consecutive ODD numbers

it is GIVEN that their sum is 51

therefore,

y+y+1+y+4=51

3y+6=51

y=(51-6)/3=45/3 =15

hence the numbers are:

y=15

y+2=17

y+4=19

the numbers are 15,17,19

Discussion

9.	Write the following sets in roster form X by X is a factor of 18
Answer» ANSWER: {1,2,3,6,9,18} HOPES IT IS THE RIGHT ANSWER!

9.

Write the following sets in roster form X by X is a factor of 18

Answer»

ANSWER:

{1,2,3,6,9,18}

HOPES IT IS THE RIGHT ANSWER!

Discussion

10.	write the greatest and the smallest 4-digit numbers using four different digits with the condition that 5occurs at tens place
Answer» Answer: GREATEST 4 digit NUMBER = 9999 Greatest 4 digit number with 5 at tens PLACE using different DIGITS = 9857 Smallest 4 digit number = 1000 Smallest 4 digit number with 5 at tens place using different digits = 1052

10.

write the greatest and the smallest 4-digit numbers using four different digits with the condition that 5occurs at tens place

Answer»

Answer:

GREATEST 4 digit NUMBER = 9999

Greatest 4 digit number with 5 at tens PLACE using different DIGITS = 9857

Smallest 4 digit number = 1000

Smallest 4 digit number with 5 at tens place using different digits = 1052

Discussion

11.	Rules to build magic squares
Answer» Answer: Start in the middle of the TOP row, and LET N=1; Insert n into the current grid position; If n=N2 the grid is COMPLETE so stop. ... MOVE diagonally up and right, wrapping to the first column or last row if the move leads outside the grid. ... Return to step 2.

11.

Rules to build magic squares

Answer»

Answer:

Start in the middle of the TOP row, and LET N=1;

Insert n into the current grid position;

If n=N2 the grid is COMPLETE so stop. ...

MOVE diagonally up and right, wrapping to the first column or last row if the move leads outside the grid. ...

Return to step 2.

Discussion

12.	Lx-my-n=0 and mx-ly+n=0 show that x=y
Answer» Answer: Add two equations Step-by-step explanation: lx-my-N+mx-ly+n=0 -n and +n will GET cancelled. lx-my+mx-ly=0 Take the y on other side lx+mx=ly+my x(l+m)=y(l+m) l+m will get cancelled so x=y

12.

Lx-my-n=0 and mx-ly+n=0 show that x=y

Answer»

Answer:

Add two equations

Step-by-step explanation:

lx-my-N+mx-ly+n=0

-n and +n will GET cancelled.

lx-my+mx-ly=0

Take the y on other side

lx+mx=ly+my

x(l+m)=y(l+m)

l+m will get cancelled so

x=y

Discussion

13.	BEST BOOKS FOR PRMO?TOPIC WISE?
Answer» ANSWER: I THINK it is BETTER to GO through the OLYMPIAD books

13.

BEST BOOKS FOR PRMO?TOPIC WISE?

Answer»

ANSWER:

I THINK it is BETTER to GO through the OLYMPIAD books

Discussion

14.	Write the greatest and the smallest 4-digit numbers using four differentdigits with the condition that 5 occurs at ten's place.
Answer» SMALLEST 1051 greatest 9857

14.

Write the greatest and the smallest 4-digit numbers using four differentdigits with the condition that 5 occurs at ten's place.

Answer»

SMALLEST 1051

greatest 9857

Discussion

15.	A 300 m long wire is used to fence a rectangular plot whose length is twice it's width. Find the length and breadth of plot
Answer» 2l+2b = 300 L+2b=300 2 L+2b=150 L+b = 75 Use COMMON SENSE here... Length=50m Breadth=25m

Discussion

16.	A bag contains 5 white balls and 9 red balls. one ball is drawn at random from the bag . find the probability of getting :i) a white ballii) a red ball
Answer» ANSWER: i)5/14 ii)9/14 Step-by-step EXPLANATION:

16.

A bag contains 5 white balls and 9 red balls. one ball is drawn at random from the bag . find the probability of getting :i) a white ballii) a red ball

Answer»

ANSWER:

i)5/14

ii)9/14

Step-by-step EXPLANATION:

Discussion

17.	Find the number at the position of "?"
Answer» ANSWER: (3) 2 Step-by-step explanation: (6+6)÷(2+1)=4 (2+7)÷(8+1)=1 (7+3)÷(1+4)=2

17.

Find the number at the position of "?"

Answer»

ANSWER:

(3) 2

Step-by-step explanation:

(6+6)÷(2+1)=4

(2+7)÷(8+1)=1

(7+3)÷(1+4)=2

Discussion

18.	In a group of hundred percent 60% can read English and 50% can read Tamil assuming that every person can read at least one of the two languages find Number of persons who can read both languages
Answer» ANSWER: Step-by-step EXPLANATION: SEE the ATTACHMENT

18.

In a group of hundred percent 60% can read English and 50% can read Tamil assuming that every person can read at least one of the two languages find Number of persons who can read both languages

Answer»

ANSWER:

Step-by-step EXPLANATION: SEE the ATTACHMENT

Discussion

19.	A tower 50m high its shadow is x metres shorter when sun's altitude iz 45° than when it is 30° find x
Answer» ANSWER: $x \: = 50( \sqrt{3 } - 1)m$

19.

A tower 50m high its shadow is x metres shorter when sun's altitude iz 45° than when it is 30° find x

Answer»

ANSWER:

$x \: = 50( \sqrt{3 } - 1)m$

Discussion

20.	List 5 successive whole number after 59176
Answer» Answer: 59177, 59178, 59179, 59180, 59181 Step-by-step explanation: 5 SUCCESSIVE WHOLE Numbers after 59176 Successive Numbers: The number occuring one after another is CALLED CONSECUTIVE number or successive number. Example: Let a number be x Successor of x = x+1 Successive whole numbers after x= x+1, x+2, x+3, x+4 and so on..

20.

List 5 successive whole number after 59176

Answer»

Answer:

59177, 59178, 59179, 59180, 59181

Step-by-step explanation:

5 SUCCESSIVE WHOLE Numbers after 59176

Successive Numbers: The number occuring one after another is CALLED CONSECUTIVE number or successive number.

Example: Let a number be x

Successor of x = x+1

Successive whole numbers after x= x+1, x+2, x+3, x+4 and so on..

Discussion

21.	A-bc-c-abb-bca fill in the blank
Answer» Answer: a,ab,BC,AC,C,ad,abb,abc,BCA

21.

A-bc-c-abb-bca fill in the blank

Answer»

Answer:

a,ab,BC,AC,C,ad,abb,abc,BCA

Discussion

22.	If the distance between (0,2) (3,4) is 2√2 find a
Answer» ANSWER: hey mate here is ur answer hope it helps u

22.

If the distance between (0,2) (3,4) is 2√2 find a

Answer»

ANSWER:

hey mate here is ur answer hope it helps u

Discussion

23.	If a2+b2+c2=85 and ab+bc+ca=3 then find the value of a+b+c
Answer» Answer: HELLO Dear User__________ Here is Your Answer...!! ____________________ STEP by step SOLUTION: $Given \ a^{2} +b^{2} +c^{2}=85\\ \\and \ (ab+bc+ca)=3\\\\We \ have \ to \ find \ (a+b+c)\\\\First \ multiply \ by \ 2 \ in \ (ab+bc+ca)=3\\\\2 (ab+bc+ca)=3 \times2\\\\2 (ab+bc+ca)=3=6\\\\we \ know \ formula\\(a+b+c)^{2}=a^{2} +b^{2} +c^{2}+2(ab+bc+ca)\\\\putting \ value \ here\\\\(a+b+c)^{2}=85+6\\\\(a+b+c)^{2}=91\\\\(a+b+c)=\sqrt{91}$ Hope it is clear to you.

23.

If a2+b2+c2=85 and ab+bc+ca=3 then find the value of a+b+c

Answer»

Answer:

HELLO Dear User__________

Here is Your Answer...!!

____________________

STEP by step SOLUTION:

$Given \ a^{2} +b^{2} +c^{2}=85\\ \\and \ (ab+bc+ca)=3\\\\We \ have \ to \ find \ (a+b+c)\\\\First \ multiply \ by \ 2 \ in \ (ab+bc+ca)=3\\\\2 (ab+bc+ca)=3 \times2\\\\2 (ab+bc+ca)=3=6\\\\we \ know \ formula\\(a+b+c)^{2}=a^{2} +b^{2} +c^{2}+2(ab+bc+ca)\\\\putting \ value \ here\\\\(a+b+c)^{2}=85+6\\\\(a+b+c)^{2}=91\\\\(a+b+c)=\sqrt{91}$

Hope it is clear to you.

Discussion

24.	Determine the term of the given sentence 2,4,7,11
Answer» ANSWER: Tn= a+(n-1)d Tn= 2+(n-1)3 =2+3n-3 =n=3/5 that term of sentence please MARK as brainlist

24.

Determine the term of the given sentence 2,4,7,11

Answer»

ANSWER:

Tn= a+(n-1)d

Tn= 2+(n-1)3

=2+3n-3

=n=3/5

that term of sentence

please MARK as brainlist

Discussion

25.	Ifx-1/x=3+2squareroot find 1/4(x3_1/x3
Answer» Step-by-step EXPLANATION: HOPE it HELPS you in your LEARNING PROCESS.

25.

Ifx-1/x=3+2squareroot find 1/4(x3_1/x3

Answer»

Step-by-step EXPLANATION:

HOPE it HELPS you in your LEARNING PROCESS.

Discussion

26.	Draw the quadrilateral whose vertices are (1,1) (2,4) (8,4) (10,1)
Answer» Step-by-step EXPLANATION: I HOPE my ANSWERS was useful please MARK as BRAINLIST

26.

Draw the quadrilateral whose vertices are (1,1) (2,4) (8,4) (10,1)

Answer»

Step-by-step EXPLANATION:

I HOPE my ANSWERS was useful

please MARK as BRAINLIST

Discussion

27.	Two chords AB=12 cm And CD=8 cm are drawn on the alternative side of the circles of radius 6 cm. Find the distance between the curves
Answer» ANSWER: PLEASE check the question again The answer is BIT WEIRD

27.

Two chords AB=12 cm And CD=8 cm are drawn on the alternative side of the circles of radius 6 cm. Find the distance between the curves

Answer»

ANSWER:

PLEASE check the question again

The answer is BIT WEIRD

Discussion

28.	222222222222222222222222*0
Answer» ANSWER: answer is 0 Step-by-step explanation: 222222222222222222222222*0 = 0

28.

222222222222222222222222*0

Answer»

ANSWER:

answer is 0

Step-by-step explanation:

222222222222222222222222*0 = 0

Discussion

29.	If the radius of circle is 19 cm find the area
Answer» $<klux>AREA</klux> \: of \: a \: circle \: = \pi \: r ^{2} \\ given \: radius \: is \: 19cm \\$ then area =22/7 ×19×19 =1134.5 CM2

29.

If the radius of circle is 19 cm find the area

Answer»

$<klux>AREA</klux> \: of \: a \: circle \: = \pi \: r ^{2} \\ given \: radius \: is \: 19cm \\$

then area =22/7 ×19×19

=1134.5 CM2

Discussion

30.	Find five rationla number between -3/5 and -1/2
Answer» ANSWER: Step-by-step EXPLANATION: HOPE it HELPS Please mark it BRAINLIEST:)

30.

Find five rationla number between -3/5 and -1/2

Answer»

ANSWER:

Step-by-step EXPLANATION:

HOPE it HELPS

Please mark it BRAINLIEST:)

Discussion

31.	Add 2,3,4,5,6,7,8,9,10,11,12,13,14,15
Answer» The ANSWER will be 119 ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️ I HOPE it will HELPS you.. ❣️❣️❣️ I hope it will helps you.. ❣️❣️❣️Please MARK me as BRAINLIEST ✌️❤️

31.

Add 2,3,4,5,6,7,8,9,10,11,12,13,14,15

Answer»

The ANSWER will be 119

❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

I HOPE it will HELPS you.. ❣️❣️❣️

I hope it will helps you.. ❣️❣️❣️Please MARK me as BRAINLIEST ✌️❤️

Discussion

32.	Write three solution of x+√3y=6
Answer» the THREE SOLUTIONS of our EQUATION are FOLLOWING

Discussion

33.	Show that any positive odd integer is of the form 8 + 1, 8 + 3, 8 + 5 or 8 + 7 where is some integer
Answer» ANSWER: this is the answer for the question or it is clear that 8+1=9 8+3=11 8+5=13 8+7=15 hence all are POSITIVE odd integers

33.

Show that any positive odd integer is of the form 8 + 1, 8 + 3, 8 + 5 or 8 + 7 where is some integer

Answer»

ANSWER:

this is the answer for the question

or it is clear that 8+1=9

8+3=11

8+5=13

8+7=15

hence all are POSITIVE odd integers

Discussion

34.	Seven bells ring at intervals of 2 3 4 6 8 9 and 12 min,respectively.They started ringing simultaneously at 5:00 in the morning.What will be the next time when they all ring simultaneously?
Answer» ANSWER: so it is the sqme answer as GIVEN in the TOPIC..

34.

Seven bells ring at intervals of 2 3 4 6 8 9 and 12 min,respectively.They started ringing simultaneously at 5:00 in the morning.What will be the next time when they all ring simultaneously?

Answer»

ANSWER:

so it is the sqme answer as GIVEN in the TOPIC..

Discussion

35.	3×10^8×10^9÷750 i need the answer fast step by step
Answer» Answer: 40,00,000 Step-by-step EXPLANATION: ( 3 × 10^8 × 10^9 ) / 750 10^8(3×1×10)/750 10^8(3)/75 10^8/25 40,00,000

35.

3×10^8×10^9÷750 i need the answer fast step by step

Answer»

Answer:

40,00,000

Step-by-step EXPLANATION:

( 3 × 10^8 × 10^9 ) / 750

10^8(3×1×10)/750

10^8(3)/75

10^8/25

40,00,000

Discussion

36.	6 +3 root2 + K root 3 = 4 root 2
Answer» HOPE this will HELP you

Discussion

37.	What is the cube(3.5)3
Answer» Answer: 42.875 Step-by-step explanation: 3.53.53.5=42.875

37.

What is the cube(3.5)3

Answer»

Answer:

42.875

Step-by-step explanation:

3.5*3.5*3.5=42.875

Discussion

38.	Find the coordinates of the point whose lines ax=by and ay=ax intersect solve ir
Answer» ANSWER: sorry Step-by-step EXPLANATION: i do not. no. no no no do not no

38.

Find the coordinates of the point whose lines ax=by and ay=ax intersect solve ir

Answer»

ANSWER:

sorry

Step-by-step EXPLANATION:

i do not. no. no no no do not no

Discussion

39.	Simplify-nyt 25+ (2x)-> (8)
Answer» ANSWER: PLEASE EXPLAIN the QUESTION

39.

Simplify-nyt 25+ (2x)-> (8)

Answer»

ANSWER:

PLEASE EXPLAIN the QUESTION

Discussion

40.	Sanju purchased a two wheeler for rupees 43200 with Sale Tax if the rate of sale tax is 8% find the selling price of vehicle
Answer» 43200×8 100 =3456 Hope it HELPS

Discussion

41.	A rectangular sheet of paper is 60 by 4 cm long and 25 by 4 cm wide find its perimeter
Answer» Answer: 42.5 cm Explanation : Perimeter of a rectangle = 2 (l+b) GIVEN LENGTH = 60/4 Given breadth = 25/4 Putting the values in the FORMULA 2 (60/4 + 25/4) 2 (60+25/4) 2 (85/4) 2×85/4 85/2 42.5 *hence, the* *perimeter* is 42.5 cm Hope you liked this Plzz MARK it as BRAINLIEST

41.

A rectangular sheet of paper is 60 by 4 cm long and 25 by 4 cm wide find its perimeter

Answer»

Answer:

42.5 cm

Explanation :

Perimeter of a rectangle = 2 (l+b)

GIVEN LENGTH = 60/4

Given breadth = 25/4

Putting the values in the FORMULA

2 (60/4 + 25/4)

2 (60+25/4)

2 (85/4)

2×85/4

85/2

42.5

hence, the perimeter is 42.5 cm

Hope you liked this

Plzz MARK it as BRAINLIEST

Discussion

42.	-2916 × 1005 please answer
Answer» ANSWER: -2930580 Step-by-step EXPLANATION:

42.

-2916 × 1005 please answer

Answer»

ANSWER:

-2930580

Step-by-step EXPLANATION:

Discussion

43.	there is a circular path around a sports field. sonia takes 18 minutes to drive one round of the field, while ravi takes 12 minutes for the same. suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point
Answer» Answer: 36 Step-by-step EXPLANATION: TAKE the lcm of 12 and 15 12=223 18=233 lcm of (12,18) =223*3 =36

43.

there is a circular path around a sports field. sonia takes 18 minutes to drive one round of the field, while ravi takes 12 minutes for the same. suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point

Answer»

Answer:

36

Step-by-step EXPLANATION:

TAKE the lcm of 12 and 15

12=2*2*3

18=2*3*3

lcm of (12,18) =2*2*3*3

=36

Discussion

44.	Please only correct answers
Answer» 125 ...........................

Discussion

45.	12. If a=-9 and b=-6, show that (a - b) = (b -a).
Answer» ANSWER: ATQ a = -9 & b = -6 assume (a-b) as LHS AND (b-a) as RHS now solve LHS a=-9 b=-6 (a-b) SUBSTITUTE the values {-9-(-6)} {-9+6} -3 now solve RHS a=-9 b=-6 (b-a) substitute the values {-6-(-9)} {-6+9} 3 may be your question is wrong as the solution is perfect but the answer is not

45.

12. If a=-9 and b=-6, show that (a - b) = (b -a).

Answer»

ANSWER:

ATQ

a = -9 & b = -6

assume (a-b) as LHS

AND

(b-a) as RHS

now solve LHS

a=-9

b=-6

(a-b)

SUBSTITUTE the values

{-9-(-6)}

{-9+6}

-3

now solve RHS

a=-9

b=-6

(b-a)

substitute the values

{-6-(-9)}

{-6+9}

3

may be your question is wrong as the solution is perfect but the answer is not

Discussion

46.	The distance between Ritu's house and her school is 1 km 875m.Every day she walks both ways.Find the total distance covered by her in 6 da
Answer» HEYA MATE ! DISTANCE from RITU's HOUSE to her school=1.875km Distance of both sides=2×1.875 =3.750km Distance in 6days=6×3.750 =22.5km hope it helps Life☯️Love❤️Peace☮️

46.

The distance between Ritu's house and her school is 1 km 875m.Every day she walks both ways.Find the total distance covered by her in 6 da

Answer»

HEYA MATE !

DISTANCE from RITU's HOUSE to her school=1.875km

Distance of both sides=2×1.875

=3.750km

Distance in 6days=6×3.750

=22.5km

hope it helps

Life☯️Love❤️Peace☮️

Discussion

47.	Find the root of 55522558
Answer» *Heya❤ $\sqrt{55522558} = 7,451.34 \:$ Hope it HELPS you* ✌✌✌

47.

Find the root of 55522558

Answer»

Heya❤

$\sqrt{55522558} = 7,451.34 \:$

Hope it HELPS you

✌✌✌

Discussion

48.	Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.
Answer» Step-by-step explanation: O is the centre of the given circle.(draw any ) A tangent PR has been drawn touching the circle at point P. Draw QP ⊥ RP at point P, such that point Q LIES on the circle. ∠OPR = 90° (radius ⊥ tangent) ALSO, ∠QPR = 90° (Given) ∴ ∠OPR = ∠QPR Now, above case is possible only when centre O lies on the line QP. Hence, PERPENDICULAR at the point of CONTACT to the tangent to a circle passes through the centre of the circle.

48.

Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.

Answer»

Step-by-step explanation:

O is the centre of the given circle.(draw any )

A tangent PR has been drawn touching the circle at point P.

Draw QP ⊥ RP at point P, such that point Q LIES on the circle.

∠OPR = 90° (radius ⊥ tangent)

ALSO, ∠QPR = 90° (Given)

∴ ∠OPR = ∠QPR

Now, above case is possible only when centre O lies on the line QP.

Hence, PERPENDICULAR at the point of CONTACT to the tangent to a circle passes through the centre of the circle.

Discussion

49.	Write 250 words article on How algebra is useful in daily life
Answer» MEASURE the LENGTH of NOTEBOOK

49.

Write 250 words article on How algebra is useful in daily life

Answer»

MEASURE the LENGTH of NOTEBOOK

Discussion

50.	Find the value of a+b+c+d is the product of first 10 natural numbers
Answer» Answer: PRODUCT of 10 NATURAL no. =10/2×1+10 =5×11 =55 so the value of a,b,c, and d a =20 b=20 c=10 d=5

50.

Find the value of a+b+c+d is the product of first 10 natural numbers

Answer»

Answer:

PRODUCT of 10 NATURAL no. =10/2×1+10

=5×11

=55

so the value of a,b,c, and d

a =20

b=20

c=10

d=5

Discussion

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