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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the distance travelled by a car moving at a speed of 7 3/4 km per hour in 1 5/31 hours |
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Answer» Answer: electric CIRCUIT to the store and get some rest and feel BETTER soon and that is the only WAY I can get the money to you MEAN by plasma therapy in the plasma therapy in the plasma therapy in the plasma therapy in the plasma Step-by-step explanation: use case of filter feature of the plasma therapy and I have to get a hold in the WORLD to go to go to a many many thanks to go back and get a many happy Republic and I are going out |
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| 2. |
: The traffic lights at three different road – crossing change after every 36 seconds,60 seconds and 72 seconds. If they change simultaneously at 8 a. m. after, whattime will they change again simultaneously? |
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Answer» Answer: The TRAFFIC LIGHTS at three different road – CROSSING change after every 36 seconds, 60 seconds and 72 seconds. If they change simultaneously at 8 a. m. after, what time will they change again simultaneously? |
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| 3. |
For equal roots in quadratic equation the value of discriminant must be equal to___ |
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Answer» Answer: The discriminant is the part under the square root in the quadratic formula, b²-4ac. If it is more than 0, the equation has two REAL solutions. If it's LESS than 0, there are no solutions. If it's equal to 0, there is one SOLUTION. |
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| 4. |
6.Аis a collection of numbers gathered to give information |
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| 5. |
Increase a salary of £ 15000 by 1.6 % |
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Answer» Answer: |
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| 6. |
2. An area of a rectangular plot is 156 square metre and breadth 12 metre. a. Findthe length of a rectangular plot ? b. Find the cost of fencing at the rate of Rs.6.25Your answe |
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Answer» Answer: (a) Length = 13 m (b) Cost of fencing = ₹312.5 Step-by-step EXPLANATION: (a) Given: Area of the rectangular plot = 156m² Breadth = 12m Area of a rectangle = Length × Breadth ⇒ 156m² = Length × 12m ⇒ Length = ⇒ Length = 13 m (b) Cost of fencing at the rate of 1M = ₹6.25 Perimeter of the rectangular plot = 2(length + breadth) = 2(13+12) = 2(25) = 50M Cost of fencing at the rate of 50m = 50 × ₹6.25 = ₹312.5 Please mark my answer as brainliest |
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| 8. |
Find the product: 4u (f - 4u). |
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Answer» Answer: 4u (f-4u) 4fu - 16u² -16u²+4fu |
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| 9. |
If x = -2 , then find the value of 8 x - 5 |
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Answer» your answer is-21 if CORRECT then MARK as the BRAINLIEST answer |
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| 10. |
Write the mark wise frequencies in the following frequency distribution table |
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Answer» Write the marks wise FREQUENCIES in the following frequency distribution table. Marks Up to 5 Up to 6 Up to 7 $ Up to 8 Up to Up to 10 No of STUDENTS 5 11 19 31 40 45 Solution Marks No of students Frequency (f) 5 5 5 6 11 6 7 19 8 8 31 12 9 40 9 10 45 5 Step-by-step explanation: Mark and follow please JAY sri ram |
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| 11. |
Find four rational numbers between 1/2, and 8/7 |
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Answer» Answer: 23/28 Step-by-step explanation: 1/2+8/7÷2 =7+16/14+1/2 =23/14×1/2 =23/28 |
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| 12. |
किसी वर्ग, जिसकी प्रत्येक भुजा 5 सेमी. हो तो उसके एक विकर्ण कीलंबाई ज्ञात कीजिए। |
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Answer» Answer: |
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| 13. |
In vedic mathas Guna is also called as |
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Answer» MULTIPLICATION Step-by-step EXPLANATION: |
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| 14. |
Abhay is 6times as old as Ajay.five years from now abhay will b two less than seven times ajay present age .find their present and ages after five years |
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Answer» Answer: let age of ARJUN be ′ ′ and age of Shriya be ′ y ′
then ACCORDING to question x=2y−−−(1) and FIVE years ago x−5=3(y−5) x−5=3y−15 x−3y+10=0−−−(2) USING eq(1) 2y−3y+10=0 y=10 and x=20 ∴ age of Arjun is 20 and age of Shriya is 10 |
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| 15. |
Find the rate of discount, if MP=rs1250 and discouny =rs. 75 |
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Answer» Answer: 6% Step-by-step explanation: |
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| 16. |
Which on is greater.a) 4/4 or 1b) 3/5 or 1 |
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Answer» a) 4/4=1 b) 3/5<1 Step-by-step EXPLANATION: |
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| 17. |
If a + b c = 7 and ab- bc - ca = 14, find the value of a^2 +b^2 +c^2 |
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Answer» Step-by-step EXPLANATION: |
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| 18. |
Multiply 2a^2b×4a^3b^2 |
Answer» THIS IS YOUR ANSWERStep-by-step explanation: 2a−3b−[4a−3b−{a−2c−a+2b+c}] =2a−3b−[4a−3b−{2b−c}] =2a−3b−[4a−5b+c] =2a−3b−4a+5b−c =−2a+2b−c |
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| 19. |
Find the value of x if 5^(2x+11)=5^41 |
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Answer» Step-by-step explanation: so 5^41 = 5 into itself 41 TIMES = 4.5474735e+28 now if we open the brackets |
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| 20. |
Find the perimeter and area |
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Answer» Answer: 34 is your perimeter Step-by-step explanation: perimeter is MADE by adding the side of your shape if U am right PLZ MARK me as BRAINIEST |
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| 21. |
(√7x/√4x-3)² = (7/4)² |
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Answer» HENCE, the ROOTS of the EQUATION are -√7/3 and √7/7.Read more on Sarthaks.com - HTTPS://www.sarthaks.com/147264/find-the-roots-of-37x-2-4x-7-0 |
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| 22. |
the ratio of the income of a person to his saving is 15:2. If his saving of one year is Rs.7500,what is his expenditure? |
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Answer» Answer: His monthly income is 4687.5 Step-by-step explanation: income = 15x and saving = 2x per YERS saving is = 7500 7500/2x = 3750₹ X = 3750 total income of 1 years is 3750 × 15 = 56250₹ monthly is 56250/12 = 4687.5₹ |
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| 23. |
A boy imagined five positive integer numbers and told his friend that the sums offour out of five numbers he imagined are 186, 203, 214, 228, and 233. What is themiddle number that boy imagined? |
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Answer» Question :- A boy IMAGINED five positive integer numbers and told his friend that the sums of four out of five numbers he imagined are 186, 203, 214, 228, and 233. What is the middle number that boy imagined ? Solution :- Let us assume that, five positive integer numbers are a, b , c, d and e . so, we have, → a + b + c + d = 186 ---------------- Eqn.(1) → b + c + d + e = 203 ---------------- Eqn.(2) → c + d + e + a = 214 ---------------- Eqn.(3) → d + e + a + b = 228 ---------------- Eqn.(4) → e + a + b + c = 233 ---------------- Eqn.(5) ADDING all 5 Equations we get, → (a + b + c + d) + (b + c + d + e) + (c + d + e + a) + (d + e + a + b) + (e + a + b + c) = 186 + 203 + 214 + 228 + 233 → 4a + 4b + 4c + 4d + 4e = 1064 → 4(a + b + c + d + e) = 1064 → (a + b + c + d + e) = 266 ---------------- Eqn.(6) therefore,
as we can see , → 33 < 38 < 52 < 63 < 80 . Hence, the middle number that boy imagined (in increasing order) is 52. Learn more :- If the sum of 3 natural numbers a,b, and c is 99 and a has 3 divisors then what will be the minimum value of b+c. Target Olympiad 1. Find the values of A and B if the given number 7A5798B8 is divisible by 33. |
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| 24. |
यदि 13 मीटर लम्बी लोहे की छड़ का भार23.4 किग्रा हो, तो 5 मीटर लम्बी उसी छड़ काभार कितना होगा? |
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Answer» Answer: 13×23.4=299.52 Step-by-step EXPLANATION: |
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| 25. |
If the roots of the equation mx? - 3mx +9=0 are real and equal, find thevalue of m.answer should come m=4 I want step |
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Answer» Step-by-step EXPLANATION: \huge\sf\underline\red{answer} answer
given, mx²-3mx+9 = 0 ROOTS are real and equal. to find, value of m let's understand:- to find the value of m given condition is that roots are real and equal .: ∆ = b²-4ac = 0. \huge\fcolorbox{black}{pink}{solution} solution
by comparing with ax²+bx+c we can SAY that: a = m b= -3m c = 9 .: b²-4ac = 0 (-3m)² - 4(m)(9) = 0 9m² - 36M = 0 9m ( m-4) = 0 .: 9m = 0. m - 4 = 0 m = 0. m = 4 .: m can't be zero so m = 4 |
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| 26. |
1729 is a Ramanujan number, this can be expressed as |
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Answer» RAMANUJAN Number, is the SMALLEST number which can be expressed as the sum of two different cubes in two different ways. 1729 is the sum of the cubes of 10 and 9 - cube of 10 is 1000 and cube of 9 is 729; adding the two numbers results in 1729. |
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| 27. |
100192515/25/355 /10115 20 |
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Answer» what do you MEAN I can't UNDERSTAND????? |
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| 28. |
Factorise 27x³ + 135x²y + 225y²+ 125y3 |
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Answer» .(3x+5y)(9x^2-15xy+25y^2) Step-by-step EXPLANATION: these is your answer |
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| 29. |
If X and Y are two independent random variables , show that E(XY) = E(X)E(Y) |
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Answer» VXOUFO Foudphxtiditslgxitxlhymgdlhhfozluf oslhxlzxjlx report it |
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| 30. |
Rationalise the denominator and find the values of a if5+2√3/7+4√3=a-6√3 |
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Answer» a= 59 you Rationalis FIRST LHS part and EQUATE you will get your a answer |
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| 31. |
The distance between these places on the ground is 1600km. Find the distance betweenthese places on a map (scale 1cm=400km) |
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Answer» Step-by-step EXPLANATION: |
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| 32. |
Rehan walks around a square parkwhose side is 70 m. One day hewalked around the park 5 times. Howmuch did he walk in all? |
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Answer» Answer: Step-by-step EXPLANATION: Just MULTIPLY the 70 by 5. |
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| 33. |
A path 2 m wide surrounds a garden 20 m by 10 m. Find the area of the path and the cost of constructing the path at ₹10 per m^2 |
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Answer» Answer: ◀ Method of Solution:◀ Given: Length of Garden= 20 metre → Breadth of Garden= 10 metres According to the QUESTION's Statement! → A Path made surrounds 2 metres Wide, → Length of Garden along with path = (20+2+2) = 24 metre ⇒ Breadth of Garden along with path = (10+2+2) = 14 metres → AREA of Garden = Area of outer SURFACE of Garden - Area of Inner Surface of Garden ⇒ Area of Garden = (24×14) - (20×10) [Area of Garden = 136m²] ⇒ Cost of Paving the path = 136 × 10 •°• → Cost of Paving the Path = Rs. 1360 Hence, Area of the garden and cost of Paving the path are 136m² and Rs. 1360 respectively.→ PLZ MARK AS BRIANLIEST,FLW ME AND THX FOR THE SUPERB QUESTION |
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| 34. |
4/3 tan2 60° + sin2 30° - 3 cos2 30° - 2 sec 2 30 - 3/4 cot 2 60 |
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Answer» USE a calculator.fjcbcbcncnfn |
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| 35. |
In the given figure, Find the distance of a chord of length 16 cm from the centre of a circle of radius 10 cm. |
Answer» The length of the chord = 16cmThe length of the chord = 16cmThe radius of the circle = 10cmWhen a perpendicular is drawn on the chord such that the chord is bisecting into two. Then the length of the chord will be halved, that is it becomes 8cm.Using the PYTHAGOREAN THEOREM,OA^2 = OC^2 + AC^2OA^2 = OC^2 + AC^210^2 = OC^2 + 8^2OA^2 = OC^2 + AC^210^2 = OC^2 + 8^2100 = OC^2 + 64OA^2 = OC^2 + AC^210^2 = OC^2 + 8^2100 = OC^2 + 64OC^2 = 36OA^2 = OC^2 + AC^210^2 = OC^2 + 8^2100 = OC^2 + 64OC^2 = 36OC = 6CMTherefore, the distance of the chord from the centre of the circle is 6cm. |
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| 36. |
Surface area of a cube is 96 then .find each side |
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Answer» |
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| 37. |
V. If a + b c = 7 and ab- bc - ca = 14, find the value of a^2 +b^2 +c^2 |
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Answer» Answer: 1=7 and abcb=7 into2ab |
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| 38. |
By चौगी, रुकी हैं रज जितने जी |
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Answer» Answer:
Step-by-step EXPLANATION: habzb ab sjksksshhsnsnsb
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| 39. |
Please solve question no 2 and 3 |
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Answer» too MUCH BORING much boring much boring much boring much boring much boring much boring much boring. Ewwwww it's too much boring |
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| 40. |
Rationalize the denominator of 30/ki5√3-3√5 |
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Answer» Answer: Here is your answer: To rationalize the expression: \frac{30}{5 \sqrt{3} -3 \sqrt{5} } 5 3
−3 5
30
Solution: To rationalize a number we must multiply and divide the number by it's conjugate. Conjugate of denominator is 5√3 + 3√5. Then, \frac{30}{5 \sqrt{3} -3 \sqrt{5} }= \frac{30}{5 \sqrt{3} -3 \sqrt{5} }\times \frac{5 \sqrt{3} +3 \sqrt{5}}{5 \sqrt{3} +3 \sqrt{5}} 5 3
−3 5
30
= 5 3
−3 5
30
× 5 3
+3 5
5 3
+3 5
We know that, ( a+B)(a-b) =a^{2}-b^{2}(a+b)(a−b)=a 2 −b 2
Using the identity to multiply the denominators , We GET. (5 \sqrt{3} -3 \sqrt{5})(5 \sqrt{3} +3 \sqrt{5}) = (5 \sqrt{3})^{2} -(3 \sqrt{5})^{2} = 75 -45 = 30(5 3
−3 5
)(5 3
+3 5
)=(5 3
) 2 −(3 5
) 2 =75−45=30 Then, \frac{30}{5 \sqrt{3} -3 \sqrt{5} }\times \frac{5 \sqrt{3} +3 \sqrt{5}}{5 \sqrt{3} +3 \sqrt{5}} = \frac{(30)(5 \sqrt{3} +3 \sqrt{5}) }{30} = \frac{5 \sqrt{3} -3 \sqrt{5} }{1} =5 \sqrt{3} -3 \sqrt{5} 5 3
−3 5
30
× 5 3
+3 5
5 3
+3 5
= 30 (30)(5 3
+3 5
)
= 1 5 3
−3 5
=5 3
−3 5
Hence the denominator is RATIONALIZED. |
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| 41. |
Rationalise the denominator of 3+√3 ÷ 2-√2 |
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Answer» EK ek s06d58s twfwfwrwetwg8wstsgus8e Step-by-step EXPLANATION: ENNA etfgete7t9zc3c3b3 enbev0ue ec8ecz e. enjeo |
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| 42. |
Add : 2 x + 4 Y and 3 x + y |
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Answer» Answer: Step-by-step explanation: 2X + 4Y + 3X +Y =2X + 3X + 4Y +Y =5X + 5Y |
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| 43. |
18. Perimeter of rectangle is 2x(1+b) |
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Answer» Step-by-step EXPLANATION: please TELL me if it help u |
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| 44. |
If 8x ^2 y 16xy^2 p are in continued then find the value of p |
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Answer» Why is distilled WATER USED in the BATTERIES and not the tap water? |
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| 45. |
In vedic mathas Guna is also called as dont spam |
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Answer» |
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| 47. |
Form a quadratic polyinomial where zero are 2and 3 |
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Answer» Step-by-step explanation: LET the zeros are= Zeros are 2 and 3 Formula :-
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| 48. |
310. Saumya used some cloth to make 4 banners and 2 tablecloths. If sheused 1.85m each to make a banner and 2.17 m each to make a tablecloth,how much cloth did she use in total? * |
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Answer» Answer: 10.9m Step-by-step explanation: cloth REQUIRED to MAKE 1 banner = 1.85m => cloth required to make 4 BANNERS = 1.85m x 4 =7.4m cloth required to make 1 TABLECLOTH = 1.85m => cloth required to make 2 tablecloths = 1.85m x2 =3.7m total she used = 7.4m + 3.5m = 10.9m |
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| 49. |
Stion:The sum of 5x2, -7x2,8x2, 11x2 and -9X2 is |
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Answer» Answer: 16 Step-by-step explanation: 16 is the CORRECT answer |
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| 50. |
Write the slope of line passing through (3, -1) and (2, 2). |
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Answer» ??????????????????????????????? |
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