Explore topic-wise InterviewSolutions in Current Affairs.

Answer:

can ANYONE SOLVE this questions in a paper and KEEP. any questions

Explanation:

____ REPRESENTS the relationships between objects and classes.

ANSWER:

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EXPLANATION:

LOSS of ELECTRON is oxidation

Gain of electron is REDUCTION

Answer:

2 OPP:C

3opp;b

4opp;c

5opp;d

ANSWER:

The answer is a OPTION B

METHANE and CO2 are CALLED GREENHOUSE GAS.

ANSWER:

ANS1) fluorine

ans2) SODIUM chloride

ans3) chlorides

qns4) yellow

ans5) NONE of these

ANSWER:

answer is it can SHARE ELECTRONS with CHLORINE

Answer:

answer is CU, CuCl2 and H2

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The given metals to us are ,

• Zinc ( Zn)
• Platinum ( Pt )
• Magnesium ( Mg )
• Iron ( Fe )

Among the given metals the metal which does not react with Sulphuric acid ( ) is Platinum .

This is so because all the other three elements Zinc , Magnesium and Iron are placed at a higher level than Hydrogen in reactivity series . So these metals have the ability to displace hydrogen .

WHEREAS Platinum is located below hydrogen in the activity series so it WOULD not react with sulphuric acid under any case. Also platinum is a noble metal.

_______________________________________

A reaction in which two or more reactants combine to form a single product is known as combination reaction.

A reaction in which of single product BREAKS down to form two or more simpler substances or products is known as decomposition reaction . This is further divided into :

A reaction in which a more reactive metal metal from its salt solution is known as displacement reaction. Elements placed at higher level in the reactivity series can displace elements placed below them .

A reaction in which the radicals of reactants are interchanged. A double decomposition or a double displacement reaction between acid and base is called neutralization reaction. precipitation reaction also double displacement reaction.

ANSWER: MARK IT AS BRAINLIEST PLEASE

All METAL carbonates react with water to

give SALT, water and carbondioxide.

Explanation:

ANSWER:

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Explanation:

ANSWER

Λ

m

∞

NH

4

OH=?

Λ

m

∞

(NH

4

Cl)=149.7 Ω

−1

CM

2

mol

−1

Λ

m

∞

(NAOH)=248.1 Ω

−1

cm

2

mol

−1

Λ

m

∞

(NaCl)=126.5 Ω

−1

cm

2

mol

−1

Λ

m

∞

(NH

4

Cl)=Λ

NH

4

+

∞

+Λ

Cl

−

∞

=149.7.....(i)

Λ

m

∞

NaOH=Λ

Na

+

∞

+Λ

OH

−

∞

=248.1.....(ii)

Λ

m

∞

NaCl=Λ

Na

+

∞

+Λ

Cl

−

∞

=126.5.....(iii)

Add equation (i) and (ii) and subtract equation (iii)

Λ

m

∞

NH

4

OH=Λ

NH

4

Cl

∞

+Λ

NaOH

∞

−Λ

NaCl

∞

=Λ

NH

4

+

∞

+Λ

OH

−

∞

=149.7+248.1−126.5

Λ

m

∞

NH

4

OH=271.3 Ω

−1

cm

2

mol

−1

ANSWER:

U SAY about which UNIT,PLEASE say

ANSWER:

I think it's option d CAESIUM(cs)

Explanation:

As atomic NO. of cs is 55 it electronic configuration is 2,8,18,18,1

EXPLANATION:

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ANSWER :

Let the vapour pressure of pure OCTANE be p10.

Then, the vapour pressure of the octane after DISSOLVING the non-volatile solute is 80/100 p10 = 0.8 p10.

• Molar mass of solute, M2 = 40 g mol - 1

• Mass of octane, w1 = 114 g

Molar mass of octane, (C8H18), M1 = 8 × 12 + 18 × 1 = 114 g mol - 1

Applying the relation,

=> (p10 - p1) / p10 = (W2 x M1 ) / (M2 x w1 )

=> (p10 - 0.8 p10) / p10 = (w2 x 114 ) / (40 x 114 )

=> 0.2 p10 / p10 = w2 / 40

=> 0.2 = w2 / 40

=> w2 = 8 g

Hence, the required mass of the solute is 8 g.

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ANSWER:

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Answer:

MATCH the following elements of column I with their prop

Column 1

Column II

1. CHLORINE

(a) Solid

halogen

2. Fluorine

(b) Radioactive

3. Bromine

(c) REDDISH brown liquid

4. Iodine

(d) Highest electron affinity

5. Astatine

(e) Most electronegative

Complete the following equations :

Na

Answer:

The NUMBER of FARADAYS(F) required to produce 20 g of calcium from MOLTEN CaCl, (Atomic mass of Ca = 40 g mol-) is. mohanaraopalivela13 is waiting for your help.

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ANSWER:

The FIRST REACTION will not be TAKE PLACE

all of the above are the CHARACTERISTIC of co-ordinate COMPOUND

The BASICITY of ACETIC ACID is ONE.

Answer:

ANSWER

A symbol REPRESENTS:

A. NAME of an element

B. One ATOM of element

C. Quantity of element equal in mass to its atomic mass.

Answer By

avatar

Toppr

sʏɴᴛʜᴇsɪs ᴏғ ʙᴜᴛᴀɴᴇ-1-ᴏʟ ғʀᴏᴍ 1 ᴄʜʟᴏʀᴏʙᴜᴛᴀɴᴇ: ᴛʜᴇ ᴄᴏɴᴠᴇʀsɪᴏɴ ʀᴇᴀᴄᴛɪᴏɴ ᴏғ 1ᴄʜʟᴏʀᴏʙᴜᴛᴀɴᴏʟ ᴛᴏ 1 ʙᴜᴛᴀɴᴏʟ ᴛᴀᴋᴇs ᴘʟᴀᴄᴇ ᴜɴᴅᴇʀ ᴀ sᴛʀᴏɴɢ ʙᴀsᴇ ʟɪᴋᴇ ᴋᴏʜ. ᴛʜᴇ 1ᴄʜʟᴏʀᴏʙᴜᴛᴀɴᴏʟ ʀᴇᴀᴄᴛs ᴡɪᴛʜ ᴋᴏʜ ᴛᴏ ɢɪᴠᴇ ʙᴜᴛᴀɴᴇ-1-ᴏʟ ᴀs ᴛʜᴇ ᴅᴇsɪʀᴇᴅ ᴘʀᴏᴅᴜᴄᴛ ᴀʟᴏɴɢ ᴡɪᴛʜ ʜᴄʟ ᴀs ᴀ ʙʏ-ᴘʀᴏᴅᴜᴄᴛ.

ATM ; PLOT atm.

ᴡᴇ ᴄᴀɴ ᴜsᴇ ᴛʜᴇ ɪᴅᴇᴀʟ ɢᴀs ʟᴀᴡ ᴛᴏ ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ᴘᴀʀᴛɪᴀʟ ᴘʀᴇssᴜʀᴇ.

Answer:

2-chloropropane also known as isopropyl choride could be prepared from propane and CL2 in a REACTION INVOLVING the formation of FREE radicals as intermediates during the reaction the reaction. This reaction requires either heating or UV light to occur. This reaction will also give 1-chloropropane as a by-product.

Explanation:

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ANSWER:

variables

Explanation:

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Answer:

Y, that is, the hardest naturally OCCURRING substance in the world is DIAMOND.

The substance Z, which is a good conductor of ELECTRICITY is Graphite.

Both diamond and Graphite COME from Carbon, a non-metal which lacks lustre, and also does not conduct electricity.

Carbon and diamond and graphite have different PROPERTIES due to the crystal structures of each.

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Explanation:

16) B) O^2-

20)A)

21)A)

ANSWER:

DESIRABLE is the answer for your QUESTION

ANSWER:

WRITE your QUESTION PROPERLY

Answer:

FIND it on doubt NOUT I'm SURE you will GET the CORRECT answer

Explanation:

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ANSWER:

i am not saure your intellient

Answer:

I cannot understand UR language it's PROBABLY Espanol PLEASE post it in English(US)

Explanation:

the oxidation number change method the underlying principle is that the gain in the oxidation number (number of ELECTRONS) in one reactant must be equal to the loss in the oxidation number of the other reactant.

Equation:

Zn + NO3- = NH4+ + Zn2+

ACIDIC medium Basic medium

Submit

Practice exercises Balanced equation

Step 1. Write down the unbalanced equation ('skeleton equation') of the chemical reaction. All reactants and products must be known. For a better result write the reaction in ionic form.

Zn + NO3- → NH4+ + Zn2+

Step 2. Separate the process into half reactions. A redox reaction is nothing but both oxidation and reduction reactions taking place simultaneously.

a) Assign oxidation numbers for each atom in the equation. Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers).

Zn0 + N+5O-23- → N-3H+14+ + Zn+22+

b) Identify and write out all redox couples in reaction. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Write down the transfer of electrons. Carefully, insert coefficients, if necessary, to make the numbers of oxidized and reduced atoms equal on the two sides of each redox couples.

O:Zn0 → Zn+22+ + 2e- (Zn)

R:N+5O-23- + 8e- → N-3H+14+ (N)

c) Combine these redox couples into two half-reactions: one for the oxidation, and one for the reduction (see: Divide the redox reaction into two half-reactions).

O:Zn0 → Zn+22+ + 2e-

R:N+5O-23- + 8e- → N-3H+14+

Step 3. Balance the atoms in each half reaction. A chemical equation must have the same number of atoms of each element on both sides of the equation. Add appropriate coefficients (stoichiometric coefficients) in front of the chemical formulas to balance the number of atoms. Never change any formulas.

a) Balance all other atoms except hydrogen and oxygen. We can use any of the species that appear in the skeleton equations for this purpose. Keep in mind that reactants should be added only to the left side of the equation and products to the right.

O:Zn0 → Zn+22+ + 2e-

R:N+5O-23- + 8e- → N-3H+14+

b) Balance the charge. For reactions in an acidic SOLUTION, balance the charge so that both sides have the same total charge by adding a H+ ion to the side deficient in positive charge.

O:Zn0 → Zn+22+ + 2e-

R:N+5O-23- + 8e- + 10H+ → N-3H+14+

c) Balance the oxygen atoms. Check if there are the same numbers of oxygen atoms on the left and right side, if they aren't equilibrate these atoms by adding water molecules.

O:Zn0 → Zn+22+ + 2e-

R:N+5O-23- + 8e- + 10H+ → N-3H+14+ + 3H2O

Balanced half-reactions are well tabulated in handbooks and on the web in a 'Tables of standard electrode potentials'. These tables, by convention, contain the half-cell potentials for reduction. To make the oxidation reaction, simply reverse the reduction reaction and change the sign on the E1/2 value.

Step 4. Make electron gain equivalent to electron lost. The electrons lost in the oxidation half-reaction must be equal the electrons gained in the reduction half-reaction. To make the two equal, multiply the coefficients of all species by integers producing the lowest common multiple between the half-reactions.

O:Zn0 → Zn+22+ + 2e-| *4

R:N+5O-23- + 8e- + 10H+ → N-3H+14+ + 3H2O| *1

O: 4Zn0 → 4Zn+22+ + 8e-

R:N+5O-23- + 8e- + 10H+ → N-3H+14+ + 3H2O

Step 5. Add the half-reactions together. The two half-reactions can be combined just LIKE two algebraic equations, with the arrow serving as the equals sign. Recombine the two half-reactions by adding all the reactants together on one side and all of the products together on the other side.

4Zn0 + N+5O-23- + 8e- + 10H+ → 4Zn+22+ + N-3H+14+ + 8e- + 3H2O

Step 6. Simplify the equation. The same species on opposite sides of the arrow can be canceled. Write the equation so that the coefficients are the smallest set of integers possible.

4Zn0 + N+5O-23- + 10H+ → 4Zn+22+ + N-3H+14+ + 3H2O

Finally, always check to see that the equation is balanced. First, verify that the equation contains the same type and number of atoms on both sides of the equation.

ELEMENT LEFT RIGHT DIFFERENCE

Zn 4*1 4*1 0

N 1*1 1*1 0

O 1*3 3*1 0

H 10*1 1*4 + 3*2 0

Second, verify that the sum of the charges on one side of the equation is equal to the sum of the charges on the other side. It doesn't matter what the charge is as long as it is the same on both sides.

4*0 + 1*-1 + 10*1 = 4*2 + 1*1 + 3*0

9 = 9

Since the sum of individual atoms on the left side of the equation matches the sum of the same atoms on the right side, and since the charges on both sides are equal we can write a balanced equation.

4Zn + NO3- + 10H+ → NH4+ + 4Zn2+ + 3H2O

Answer:

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ANSWER:

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Explanation:

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ANSWER:

C is your CORRECT answer 4:2

11th

Chemistry

Chemical Bonding and Molecular Structure

Basics of Chemical Bonding

Calculate formal charge of ...

CHEMISTRY

avatar

Asked on December 27, 2019 by

Rishika Brar

Calculate formal charge of ATOMS HClO

4

,CO

3

2

.

HARD

Help best friend

Study later

ANSWER

The formal charge on three oxygen atom has electron pair shared by chlorine,

Cl=

2S−L

v−1

=0=

2×2−6

6−1

=−1

The formal charge on the oxygen atom having an electron pair shared by chlorine and hydrogen, then the formal charge is :

0=

2×2−0

1−1

=0

Formal charge onH is 0=

2×2−0

1−1

=0

For the Co

3

2

For the oxygen:

6−4−

2

1

×4=0

For the carbon atom:

4−0−

2

1

×8=0

For the second oxygen:

6−6−

2

1

×2=−1

plz make my answer brilliant if my answer is CORRECT

ANSWER:

y7070yc07yc79cu9c0yviujobojcypuc8tyxi

ANSWER:

Answer. Y, that is, the hardest naturally OCCURRING substance in the world is diamond. The substance Z, which is a GOOD conductor of electricity is Graphite. Both diamond and Graphite come from Carbon, a non-metal which LACKS lustre, and also does not conduct electricity.

Answer:

1.The members of the ALKALINE earth metals include: BERYLLIUM (Be), magnesium (Mg), calcium (Ca), strontium (SR), barium (Ba) and radium (Ra). As with all families, these elements share traits. While not as reactive as the alkali metals, this family knows how to make bonds very easily.

The radioactive nuclei, or radionuclides, found naturally on Earth can be grouped into three series–headed by uranium-238, uranium-235, and thorium-232–plus several isolated beta-particle emitting nuclei, most prominently potassium-40 and rubidium-87. Average abundances of these nuclides are listed in Table 15-1.

The member LEAST reactive is LITHIUM

PLEASE MARK AS BRAINLIEST

ANSWER:

BOND ENTHALPY

Answer:

380 to 700 nanometers

The visible LIGHT spectrum is the SEGMENT of the

Explanation:

The visible light spectrum is the segment of the ELECTROMAGNETIC spectrum that the human eye can view. More simply, this range of wavelengths is CALLED visible light. TYPICALLY, the human eye can detect wavelengths from 380 to 700 nanometers.

Answer:

this is your answer bro

Explanation:

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ANSWER:

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ANSWER:

X = CARBON di OXIDE (CO2)

Y = Caboxy Acid (COOH)

ANSWER:

d is answer I am doing a LOT of PEOPLE who are SHARING QUESTIONS

Answer:

Acetaldehyde (systematic name ethanal) is an organic chemical compound with the formula CH3CHO, sometimes abbreviated by chemists as MeCHO (Me = methyl). It is one of the most IMPORTANT aldehydes, occurring widely in nature and being produced on a large scale in industry. Acetaldehyde occurs naturally in coffee, bread, and ripe fruit,[10] and is produced by plants. It is also produced by the partial oxidation of ETHANOL by the liver ENZYME alcohol dehydrogenase and is a contributing cause of hangover after alcohol consumption. Pathways of EXPOSURE include air, water, land, or groundwater, as well as drink and smoke.[11] Consumption of disulfiram inhibits acetaldehyde dehydrogenase, the enzyme responsible for the metabolism of acetaldehyde, thereby causing it to build up in the body.

ANSWER:

D lemon juice as it is an ACID which change Blue LITMUS to red.