52639 + Interview Questions in Secondary School in Chemistry

1.	Why do doctors advise to put strips of wet cloth on the forehead of the person having high fever?
Answer» I it SUCKS the HEAT of the HUMAN COOL down thanks me PLEASE

1.

Why do doctors advise to put strips of wet cloth on the forehead of the person having high fever?

Answer»

I it SUCKS the HEAT of the HUMAN COOL down

thanks me PLEASE

2.	give one word answer of a definite gravity of matter, all samples of which have the same properties .
Answer» the ATTRACTIVE FORCE between EARTH and SMALLER OBJECT

Discussion

3.	Consider the reaction:Caco, * H,SO, Caso, * H,0 + CO2What will be the percent purity of Caco, if 200 gCaco, produces 22.4 L CO, at STP in excess ofH.SO?(1) 25%(2) 50%(3) 75%(4) 100%
Answer» Answer: 4 BeForE U JUDGE mE... MAKE SuRE thAt YOu'rE PERFECT....?

3.

Consider the reaction:Caco, * H,SO, Caso, * H,0 + CO2What will be the percent purity of Caco, if 200 gCaco, produces 22.4 L CO, at STP in excess ofH.SO?(1) 25%(2) 50%(3) 75%(4) 100%

Answer»

Answer:

4

BeForE U JUDGE mE...

MAKE SuRE

thAt YOu'rE PERFECT....?

Discussion

4.	Chemistry question Content - Quality
Answer» Answer: The yield of carbonic ACID H₂CO₃ is approximately 90.7%. Explanation: Relative atomic mass DATA from a modern periodic table: Na: 22.990, H: 1.008, C: 12.011, O: 15.999. Two formula units of sodium bicarbonate $\mathrm{NaHCO_3}$ decomposes to produce one $\mathrm{H_2 O}$ molecule and one $\mathrm{CO}_2$ molecule. $\rm 2\;NaHCO_3 \to Na_2CO_3 + H_2 O\; (g) + CO_2\; (g)$ . One $\mathrm{H_2O}$ molecule combines with one $\mathrm{CO}_2$ molecule to produce one $\mathrm{H_2CO_3}$ molecule. $\rm H_2O + CO_2 \to H_2CO_3$ . Combine the two equations: $\rm 2\;NaHCO_3 \to Na_2CO_3 + H_2CO_3$ . Overall, two formula units of $\mathrm{NaHCO_3}$ thermally decompose to produce one $\mathrm{H_2CO_3}$ molecule. What's the theoretical yield of this experiment? To answer this question, start by FINDING the number of moles of formula units in 2.36 grams of $\textbf{NaHCO_3}$ . $M(\mathrm{NaHCO_3}) = 22.990 + 1.008 + 12.011 + 3\times 15.999 = \rm 84.006\;g\cdot mol^{-1}$ . $\displaystyle n(\mathrm{NaHCO_3}) = \frac{m}{M} = \rm \frac{2.36\;g}{84.006\;g\cdot mol^{-1}} = 0.0280932\; mol$ . $\rm 0.0280932\; mol$ of $\mathrm{NaHCO_3}$ will make half as many moles of $\mathrm{H_2CO_3}$ molecules. In other words, $\displaystyle n(\mathrm{H_2CO_3})= \frac{1}{2} \; n(\mathrm{NaHCO_3}) = \rm \frac{1}{2}\times 0.0280932\; mol = 0.140466\; mol$ . What will be the mass of that $0.140466\; mol$ of $\mathrm{H_2CO_3}$ molecules? $M(\mathrm{H_2CO_3}) = \rm 2\times 1.008 + 12.011 + 3\times 15.999 = 62.024\; g\cdot mol^{-1}$ . $\begin{aligned}m(\mathrm{H_2CO_3}\text{, theoretical yield}) &= n \cdot M\\ &= \rm 0.140466\; mol \times 62.024\; g\cdot mol^{-1}\\&=\rm 0.871227\;g\end{aligned}$ . What's the actual yield of this experiment? The mass of the solid decreased by $2.36 - 1.57 = \rm 0.79\; g$ in this experiment. However, mass is conserved in chemical REACTIONS. The missing $\rm 0.79\; g$ must be the mass of the gaseous $\rm H_2O$ and $\rm CO_2$ that have escaped from the container. Similarly, assume that all $\rm H_2O$ and $\rm CO_2$ from the first reaction are converted to carbonic acid. The mass of the carbonic acid produced SHALL be the same as the sum of the mass of $\rm H_2O$ and $\rm CO_2$ . In other words, the actual yield of carbonic acid is $\rm 0.79\; g$ . $\displaystyle \begin{aligned}\text{Percentage Yield} &= \frac{\text{Actual Yield}}{\text{Theoretical Yield}}\times 100\%\\&=\rm \frac{0.79\; g}{0.871227\; g}\times 100\%\\&=\rm 90.7\%\end{aligned}$

4.

Chemistry question Content - Quality

Answer»

Answer:

The yield of carbonic ACID H₂CO₃ is approximately 90.7%.

Explanation:

Relative atomic mass DATA from a modern periodic table:

Na: 22.990,
H: 1.008,
C: 12.011,
O: 15.999.

Two formula units of sodium bicarbonate $\mathrm{NaHCO_3}$ decomposes to produce one $\mathrm{H_2 O}$ molecule and one $\mathrm{CO}_2$ molecule.

$\rm 2\;NaHCO_3 \to Na_2CO_3 + H_2 O\; (g) + CO_2\; (g)$ .

One $\mathrm{H_2O}$ molecule combines with one $\mathrm{CO}_2$ molecule to produce one $\mathrm{H_2CO_3}$ molecule.

$\rm H_2O + CO_2 \to H_2CO_3$ .

Combine the two equations:

$\rm 2\;NaHCO_3 \to Na_2CO_3 + H_2CO_3$ .

Overall, two formula units of $\mathrm{NaHCO_3}$ thermally decompose to produce one $\mathrm{H_2CO_3}$ molecule.

What's the theoretical yield of this experiment?

To answer this question, start by FINDING the number of moles of formula units in 2.36 grams of $\textbf{NaHCO_3}$ .

$M(\mathrm{NaHCO_3}) = 22.990 + 1.008 + 12.011 + 3\times 15.999 = \rm 84.006\;g\cdot mol^{-1}$ .

$\displaystyle n(\mathrm{NaHCO_3}) = \frac{m}{M} = \rm \frac{2.36\;g}{84.006\;g\cdot mol^{-1}} = 0.0280932\; mol$ .

$\rm 0.0280932\; mol$ of $\mathrm{NaHCO_3}$ will make half as many moles of $\mathrm{H_2CO_3}$ molecules. In other words,

$\displaystyle n(\mathrm{H_2CO_3})= \frac{1}{2} \; n(\mathrm{NaHCO_3}) = \rm \frac{1}{2}\times 0.0280932\; mol = 0.140466\; mol$ .

What will be the mass of that $0.140466\; mol$ of $\mathrm{H_2CO_3}$ molecules?

$M(\mathrm{H_2CO_3}) = \rm 2\times 1.008 + 12.011 + 3\times 15.999 = 62.024\; g\cdot mol^{-1}$ .

$\begin{aligned}m(\mathrm{H_2CO_3}\text{, theoretical yield}) &= n \cdot M\\ &= \rm 0.140466\; mol \times 62.024\; g\cdot mol^{-1}\\&=\rm 0.871227\;g\end{aligned}$ .

What's the actual yield of this experiment?

The mass of the solid decreased by $2.36 - 1.57 = \rm 0.79\; g$ in this experiment. However, mass is conserved in chemical REACTIONS. The missing $\rm 0.79\; g$ must be the mass of the gaseous $\rm H_2O$ and $\rm CO_2$ that have escaped from the container.

Similarly, assume that all $\rm H_2O$ and $\rm CO_2$ from the first reaction are converted to carbonic acid. The mass of the carbonic acid produced SHALL be the same as the sum of the mass of $\rm H_2O$ and $\rm CO_2$ . In other words, the actual yield of carbonic acid is $\rm 0.79\; g$ .

$\displaystyle \begin{aligned}\text{Percentage Yield} &= \frac{\text{Actual Yield}}{\text{Theoretical Yield}}\times 100\%\\&=\rm \frac{0.79\; g}{0.871227\; g}\times 100\%\\&=\rm 90.7\%\end{aligned}$

Discussion

5.	How atomic numer and mass number are denoted on atom?
Answer» ANSWER: Na²³ ¹¹ Explanation: atomic no. of sodium is 11.it is denoted below the name(symbol)of atom. MASS no. is 23 in this EXAMPLE...it is denoted above the symbol of atom

5.

How atomic numer and mass number are denoted on atom?

Answer»

ANSWER:

Na²³

¹¹

Explanation:

atomic no. of sodium is 11.it is denoted below the name(symbol)of atom.

MASS no. is 23 in this EXAMPLE...it is denoted above the symbol of atom

Discussion

6.	If m is an element of lanthanide series, during lanthanide contraction ?
Answer» Lanthanide contraction consequences Due to lanthanide contraction , the ionic SIZE from La 3+ to Lu 3+ ALONG lanthanide series GRADUALLY decreases. As a result, the COVALENT properties of lanthanide metal hydroxide compounds regularly INCREASES [according to Fajan's rule,]from lanthanum to lutetium .

6.

If m is an element of lanthanide series, during lanthanide contraction ?

Answer»

Lanthanide contraction consequences

Due to lanthanide contraction , the ionic SIZE from La 3+ to Lu 3+ ALONG lanthanide series GRADUALLY decreases. As a result, the COVALENT properties of lanthanide metal hydroxide compounds regularly INCREASES [according to Fajan's rule,]from lanthanum to lutetium .

Discussion

7.	Haloalkanes and haloarenes all chemical reaction
Answer» hey . do u want CLASS 12 haloalkanes and haloarens hand WRITTEN notes, if yes give me your mail ID

7.

Haloalkanes and haloarenes all chemical reaction

Answer»

hey . do u want CLASS 12 haloalkanes and haloarens hand WRITTEN notes, if yes give me your mail ID

Discussion

8.	Impact factor of reaction kinetics, mechanism and catalysis
Answer» Answer: HYDROGEN Generation from Formic ACID. DECOMPOSITION with a Ruthenium CATALYST Promoted by Functionalized Ionic LIQUIDS

8.

Impact factor of reaction kinetics, mechanism and catalysis

Answer»

Answer:

HYDROGEN Generation from Formic ACID. DECOMPOSITION with a Ruthenium CATALYST Promoted by Functionalized Ionic LIQUIDS

Discussion

9.	give one word answer of how much heat energy is absorbed by 1 kg of water at hundred degree Celsius to get converted into steam
Answer» 1000000 JULES of ENERGY is ABSORBED

9.

give one word answer of how much heat energy is absorbed by 1 kg of water at hundred degree Celsius to get converted into steam

Answer»

1000000 JULES of ENERGY is ABSORBED

Discussion

10.	Give me the value of sin16 degree... with explanation ...i will mark it as brainliest ❤❤☺☺
Answer» Here is UR answer : sin16° = 0.27564 sin 16° = 0.27564 sin 16 degrees = 0.27564 The sin of 16 degrees is 0.27564, the same as sin of 16 degrees in radians. To obtain 16 degrees in radian MULTIPLY 16° by π / 180° = 4/45 π. Sin 16degrees = sin (4/45 × π). Our results of sin16° have been rounded to five decimal places. If you want sine 16° with higher ACCURACY, then use the calculator below; our tool displays ten decimal places. To CALCULATE sin 16 degrees insert the angle 16 in the field labelled °, but if you want to calculate sin 16 in radians, then you have to press the swap unit button first. Hope it's help u MARK on brainlist

10.

Give me the value of sin16 degree... with explanation ...i will mark it as brainliest ❤❤☺☺

Answer»

Here is UR answer :

sin16° = 0.27564

sin 16° = 0.27564

sin 16 degrees = 0.27564

The sin of 16 degrees is 0.27564, the same as sin of 16 degrees in radians. To obtain 16 degrees in radian MULTIPLY 16° by π / 180° = 4/45 π. Sin 16degrees = sin (4/45 × π).

Our results of sin16° have been rounded to five decimal places. If you want sine 16° with higher ACCURACY, then use the calculator below; our tool displays ten decimal places.

To CALCULATE sin 16 degrees insert the angle 16 in the field labelled °, but if you want to calculate sin 16 in radians, then you have to press the swap unit button first.

Hope it's help u

MARK on brainlist

Discussion

11.	give one word answer of rapid formation and breaking of bubbles in the bulk of a liquid being heated
Answer» FLAME RAPID FORMS after BREAKING of BUBBLES

11.

give one word answer of rapid formation and breaking of bubbles in the bulk of a liquid being heated

Answer»

FLAME RAPID FORMS after BREAKING of BUBBLES

Discussion

12.	How do physical and chemical affect mass
Answer» ANSWER: There is no effect on mass during pjyscial or CHEMICAL change as according to law of conservation of mass the mass is neither be created nor be DESTROYED it only can be conserved.Mass remains constant

12.

How do physical and chemical affect mass

Answer»

ANSWER:

There is no effect on mass during pjyscial or CHEMICAL change as according to law of conservation of mass the mass is neither be created nor be DESTROYED it only can be conserved.Mass remains constant

Discussion

13.	Give one word answer of the space in between the constituent particles in any form of matter
Answer» ANSWER: INTERMOLECULAR SPACE is the answer

13.

Give one word answer of the space in between the constituent particles in any form of matter

Answer»

ANSWER:

INTERMOLECULAR SPACE is the answer

Discussion

14.	Write 10 line about P.M modi
Answer» Narendra MODI is the present Prime minister of India . He is the 14 th prime minister of India . He belongs to BJP party . He works for the BETTERMENT of the country. He was BORN in Gujarat in the year 1950. he completed an M.A. degree in political science from Gujarat University in Ahmadabad. He joined the pro-Hindu RASHTRIYA Swayamsevak Sangh (RSS) organization in the early 1970s *plzzzzzzzzzzz* *MARK* it as *brainliest*

14.

Write 10 line about P.M modi

Answer»

Narendra MODI is the present Prime minister of India .

He is the 14 th prime minister of India .

He belongs to BJP party .

He works for the BETTERMENT of the country.

He was BORN in Gujarat in the year 1950.

he completed an M.A. degree in political science from Gujarat University in Ahmadabad.

He joined the pro-Hindu RASHTRIYA Swayamsevak Sangh (RSS) organization in the early 1970s

plzzzzzzzzzzz MARK it as brainliest

Discussion

15.	10. How does a solution differ from an ordinary mixture?
Answer» ANSWER: solution is differ from MIXTURE because it is LIQUID in state and mixture is in SOLID state or powder

15.

10. How does a solution differ from an ordinary mixture?

Answer»

ANSWER:

solution is differ from MIXTURE because it is LIQUID in state and mixture is in SOLID state or powder

Discussion

16.	Give one word answer of the liquids which vaporise faster
Answer» ANSWER: VAPORISATION,EVAPORATION

16.

Give one word answer of the liquids which vaporise faster

Answer»

ANSWER:

VAPORISATION,EVAPORATION

Discussion

17.	Class : IXSubject : Chemistry (HAP)VIKAS会老得较多多指HOLIDAY WORKSHEET4Write the IUPAC names for the following skeletal formulae:Cecce.2.meno ac123.–4 CCC-CCI !CCCcc5.6.6 CC-CC
Answer» PLZZ post EDUCATIONAL QUESTIONS... follow me... #RAGHAV PANDEY

17.

Class : IXSubject : Chemistry (HAP)VIKAS会老得较多多指HOLIDAY WORKSHEET4Write the IUPAC names for the following skeletal formulae:Cecce.2.meno ac123.–4 CCC-CCI !CCCcc5.6.6 CC-CC

Answer»

PLZZ post EDUCATIONAL QUESTIONS...

follow me...

#RAGHAV PANDEY

Discussion

18.	What is sublimation? Give three example of substance which sublime on heating.
Answer» ANSWER: Sublimation is the PROCESS in which a SUBSTANCE changes DIRECTLY from solid to liquid.e.g. camphor, ammonia, naphthalene Explanation:

18.

What is sublimation? Give three example of substance which sublime on heating.

Answer»

ANSWER: Sublimation is the PROCESS in which a SUBSTANCE changes DIRECTLY from solid to liquid.e.g. camphor, ammonia, naphthalene

Explanation:

Discussion

19.	Define skeletal equation.
Answer» Answer: SKELETON Equations are the equations in which there is only chemical formula of reactants and products but no state mentioned and no BALANCING of atoms on either side of Equation done. For example: Mg + 02> equation 2Mg(s) 02(g) 2Mg0(s). MGO, it's a skeleton .

19.

Define skeletal equation.

Answer»

Answer:

SKELETON Equations are the equations in which there is only chemical formula of reactants and products but no state mentioned and no BALANCING of atoms on either side of Equation done. For example: Mg + 02> equation 2Mg(s) 02(g) 2Mg0(s). MGO, it's a skeleton .

Discussion

20.	Calculate the ΔG and equilibrium constant of the reaction at 27°CMg+ Cu2+ at equilibrium Mg2+ +CuE°Mg2+/Mg= -2.37V, E°Cu2+/Cu=+0.34V
Answer» $\Delta G$ Answer: = - 523030 Joules equilibrium constant = $1.12\times 10^{91}$ Explanation: $Mg+Cu^{2+}\rightarrow Mg^{2+}+Cu$ Here Mg undergoes oxidation by LOSS of ELECTRONS, thus act as anode. COPPER undergoes reduction by GAIN of electrons and thus act as cathode. $E^0=E^0_{cathode}- E^0_{anode}$ Where both $E^0$ are standard reduction potentials. $E^0_{[Mg^{2+}/Mg]}= -2.37V$ $E^0_{[Cu^{2+}/Cu]}=+0.34V$ $E^0=E^0_{[Cu^{2+}/Cu]}- E^0_{[Mg^{2+}/Mg]}$ $E^0=+0.34- (-2.37V)=2.71$ The standard emf of a cell is related to Gibbs free energy by following relation: $\Delta G=-nFE^0$ $\Delta G$ = gibbs free energy n= no of electrons GAINED or lost F= faraday's constant $E^0$ = standard emf $\Delta G=-2\times 96500\times (2.71)=-523030J$ The Gibbs free energy is related to equilibrium constant by following relation: $\Delta G=-2.303RTlog K$ R = gas constant = 8.314 J/Kmol T = temperature in kelvin = $27^0C=27+273=300K$ K = equilibrium constant $\Delta G=-2.303RTlog K$ $-523030=-2.303\times 8.314\times 300\times logK$ $K=1.12\times 10^{91}$

20.

Calculate the ΔG and equilibrium constant of the reaction at 27°CMg+ Cu2+ at equilibrium Mg2+ +CuE°Mg2+/Mg= -2.37V, E°Cu2+/Cu=+0.34V

Answer»

$\Delta G$ Answer: = - 523030 Joules

equilibrium constant = $1.12\times 10^{91}$

Explanation:

$Mg+Cu^{2+}\rightarrow Mg^{2+}+Cu$

Here Mg undergoes oxidation by LOSS of ELECTRONS, thus act as anode. COPPER undergoes reduction by GAIN of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Mg^{2+}/Mg]}= -2.37V$

$E^0_{[Cu^{2+}/Cu]}=+0.34V$

$E^0=E^0_{[Cu^{2+}/Cu]}- E^0_{[Mg^{2+}/Mg]}$

$E^0=+0.34- (-2.37V)=2.71$

The standard emf of a cell is related to Gibbs free energy by following relation:

$\Delta G=-nFE^0$

$\Delta G$ = gibbs free energy

n= no of electrons GAINED or lost

F= faraday's constant

$E^0$ = standard emf

$\Delta G=-2\times 96500\times (2.71)=-523030J$

The Gibbs free energy is related to equilibrium constant by following relation:

$\Delta G=-2.303RTlog K$

R = gas constant = 8.314 J/Kmol

T = temperature in kelvin = $27^0C=27+273=300K$

K = equilibrium constant

$\Delta G=-2.303RTlog K$

$-523030=-2.303\times 8.314\times 300\times logK$

$K=1.12\times 10^{91}$

Discussion

21.	How to calculate the equivalent mass of CH3 COOH
Answer» by MOLECULAR MASS and multiplying it by no. of particles. eg:- mass of C in this COMPOUND is 2*12= 24 u mass of hydrogen =4u oxygen=32u total mass =24+4+32=60u and this compound is ethanoic acid/acetic acid found in vinegar

21.

How to calculate the equivalent mass of CH3 COOH

Answer»

by MOLECULAR MASS and multiplying it by no. of particles. eg:- mass of C in this COMPOUND is 2*12= 24 u

mass of hydrogen =4u

oxygen=32u total mass =24+4+32=60u

and this compound is ethanoic acid/acetic acid found in vinegar

Discussion

22.	A white cocloured compound is heated in a testtube, brown fumes comes out and a brown residue is left behind.a.Name the chemical which gives the brown fumesb.Name the compound which gives the brown residue
Answer» a)NO2 *<U>Hope* it *HELPS* u........

22.

A white cocloured compound is heated in a testtube, brown fumes comes out and a brown residue is left behind.a.Name the chemical which gives the brown fumesb.Name the compound which gives the brown residue

Answer»

a)NO2

<U>Hope it HELPS u........

Discussion

23.	A white coloured compound is heated in a test tube, brown fumes comes out and a brown residue is left behind. (a) name the chemical which gives brown fumes (b) name the compound which gives brown residue. (c) write balanced chemical equation (d) identify the type of reaction.
Answer» ANSWER: leadnitrate on heating gives brown fumes Explanation: It gives yellow residue. It is THERMAL decomposition. 2Pb(NO3)2 on heating gives 2PbO+4NO2+O2 is the equation Hope this helps you........

23.

A white coloured compound is heated in a test tube, brown fumes comes out and a brown residue is left behind. (a) name the chemical which gives brown fumes (b) name the compound which gives brown residue. (c) write balanced chemical equation (d) identify the type of reaction.

Answer»

ANSWER:

leadnitrate on heating gives brown fumes

Explanation:

It gives yellow residue.

It is THERMAL decomposition.

2Pb(NO3)2 on heating gives 2PbO+4NO2+O2 is the equation

Hope this helps you........

Discussion

24.	At identical temperature and pressure, the rate of diffusion of hydrogen gas is 3 times that of a hydrocarbon having molecular formula cnh2n2. What is the value of n ?
Answer» Answer ⇒ n = 1. It is given confusing in question about mol. formula. As what I thinks, It should be, $C_nH_2_n_+_2$ Explanation ⇒ By the Graham's Law of DIFFUSION, the rate of diffusion of any gas is inversely proportional to the SQUARE root of Molar mass of that gas. Let Molar mass of Hydrocarbon be M and that of Hydrogen be m. Let rate of diffusion of Hydrocarbon be R and that of Hydrogen be r. Then, R/r = √(m/M) It is given, rate of diffusion of Hydrogen = 3 × rate of diffusion of Hydrocarbon. ∴ r = 3R Putting this in Graham's equation, we get, R/3R = √(m/M) ∴ 1/9 = m/M ∴ M = 9m ∴ M = 9 × 2 [Molar mass of Hydrogen = m = 2 g/mole.] ∴ M = 18 g/mole. Now, Molar mass of hydrocarbon = 12n + (2n + 2)1 = 12n + 2n + 2 = 14n + 2 ∴ 14n + 2 = 18 ∴ n = 16/14 ∴ n = 8/7 ∴ n ≈ 1 ∴ $C_nH_2_n_+_2 = CH_4$ Hope it helps.

24.

At identical temperature and pressure, the rate of diffusion of hydrogen gas is 3 times that of a hydrocarbon having molecular formula cnh2n2. What is the value of n ?

Answer»

Answer ⇒ n = 1.

It is given confusing in question about mol. formula. As what I thinks, It should be, $C_nH_2_n_+_2$

Explanation ⇒ By the Graham's Law of DIFFUSION, the rate of diffusion of any gas is inversely proportional to the SQUARE root of Molar mass of that gas.

Let Molar mass of Hydrocarbon be M and that of Hydrogen be m.

Let rate of diffusion of Hydrocarbon be R and that of Hydrogen be r.

Then, R/r = √(m/M)

It is given, rate of diffusion of Hydrogen = 3 × rate of diffusion of Hydrocarbon.

∴ r = 3R

Putting this in Graham's equation, we get,

R/3R = √(m/M)

∴ 1/9 = m/M

∴ M = 9m

∴ M = 9 × 2 [Molar mass of Hydrogen = m = 2 g/mole.]

∴ M = 18 g/mole.

Now, Molar mass of hydrocarbon = 12n + (2n + 2)1

= 12n + 2n + 2

= 14n + 2

∴ 14n + 2 = 18

∴ n = 16/14

∴ n = 8/7

∴ n ≈ 1

∴ $C_nH_2_n_+_2 = CH_4$

Hope it helps.

Discussion

25.	6 g of a substance of molecular weight 106 was dissolved
Answer» ANSWER: PLZ MENTION the AMOUNT or VOLUME

25.

6 g of a substance of molecular weight 106 was dissolved

Answer»

ANSWER:

PLZ MENTION the AMOUNT or VOLUME

Discussion

26.	Give the characteristic test for co2
Answer» Carbon dioxide PASSED into limewater gives a milky solution, due to precipitation of an insoluble SUSPENSION of calcium CARBONATE: Ca(OH)2 + CO2 → CaCO3 + H2O or bring burning candle near the gas and it will stop burning. MARK IT BRAINLIEST ANSWER

26.

Give the characteristic test for co2

Answer»

Carbon dioxide PASSED into limewater gives a milky solution, due to precipitation of an insoluble SUSPENSION of calcium CARBONATE: Ca(OH)2 + CO2 → CaCO3 + H2O

or

bring burning candle near the gas and it will stop burning.

MARK IT BRAINLIEST

ANSWER

Discussion

27.	Calculate the number of moles present in 1.5 into 10 to the power 20 molecules of H2O
Answer» Answer: 2.49 Explanation: YU can USE the FORMULA: no of MOLE = no of molecule/6.022x10²³

27.

Calculate the number of moles present in 1.5 into 10 to the power 20 molecules of H2O

Answer»

Answer:

2.49

Explanation:

YU can USE the FORMULA:

no of MOLE = no of molecule/6.022x10²³

Discussion

28.	Calculate the number of moles present in 2.8 ml of ozone gas at STP
Answer» No of MOLES of O3=2.8/22400 =125×10^-6 HOPE THIS WILL HELP YOU!!

28.

Calculate the number of moles present in 2.8 ml of ozone gas at STP

Answer»

No of MOLES of O3=2.8/22400

=125×10^-6

HOPE THIS WILL HELP YOU!!

Discussion

29.	Write the types of chemical reaction
Answer» ANSWER: The five BASIC types of chemical reactions are COMBINATION, decomposition, single-replacement, double-replacement, and COMBUSTION.

29.

Write the types of chemical reaction

Answer»

ANSWER:

The five BASIC types of chemical reactions are COMBINATION, decomposition, single-replacement, double-replacement, and COMBUSTION.

Discussion

30.	Write the name of animals who live in the water
Answer» *hey* *mate* *here* is *your* *ANSWER* : *SEA* *snakes, walruses, seals, DOLPHINS, whales, CROCODILES, frogs, sea* *horses, etc.*

30.

Write the name of animals who live in the water

Answer»

hey mate here is your ANSWER :

SEA snakes, walruses, seals, DOLPHINS, whales, CROCODILES, frogs, sea horses, etc.

Discussion

31.	A colour TV rated 150 w operates 6 hours per day what is the cost of energy to create it for 30 days at rupees 5.50per unit
Answer» The mathematical relationship between one electrical unit and electrical watt is; 1 unit = 1kilo-watt [1 unit = 1000 watt] So, ACCORDING to the data MENTIONED in the question,the total amount of used electricity in one day is; =150×6 = 900 w And the total amount of used electricity in one month or 30 days will be; =90×30 =2700 w So, 1000 w = 1 unit 1 w = 1/1000 unit 2700w = 2700/1000 unit = 2.7 unit Now the total cost will be; = (2.7×5.5)₹ = ₹ 14.85 (answer)

31.

A colour TV rated 150 w operates 6 hours per day what is the cost of energy to create it for 30 days at rupees 5.50per unit

Answer»

The mathematical relationship between one electrical unit and electrical watt is;

1 unit = 1kilo-watt

[1 unit = 1000 watt]

So, ACCORDING to the data MENTIONED in the question,the total amount of used electricity in one day is;

=150×6

= 900 w

And the total amount of used electricity in one month or 30 days will be;

=90×30

=2700 w

So,

1000 w = 1 unit

1 w = 1/1000 unit

2700w = 2700/1000 unit = 2.7 unit

Now the total cost will be;

= (2.7×5.5)₹

= ₹ 14.85 (answer)

Discussion

32.	How islove this √1.4×10^-6
Answer» ANSWER: The answer of this QUESTION is 14000

32.

How islove this √1.4×10^-6

Answer»

ANSWER:

The answer of this QUESTION is

14000

Discussion

33.	Ice at 0°C appears colder to the mouth than water at 0°C. Why?
Answer» Because the ice molecules are tightly PACKED and when the COME in CONTACT with the heat of surrounding the molecules bond has broken.And when Ice goes inside in our mouth ,The ice absorbs the heat from our tongue.That's why we feel cooler than water.

Discussion

34.	4x+8 =0 check it is quadratic
Answer» ANSWER: X=(-8) is the RIGHT ANS

34.

4x+8 =0 check it is quadratic

Answer»

ANSWER:

X=(-8) is the RIGHT ANS

Discussion

35.	Why greater the nuclear charge , grester will be the electronegative in magnitude of nuclear charge
Answer» Greater the nuclear charge greater will be the ELECTRONEGATIVITY. Electronegativity is the tendency of an atom to attract a SHARED PAIR of ELECTRON towards itself. So greater the nuclear charge greater will be the ability to attract ELECTRONS towards itself

Discussion

36.	Which chemical element has the shortest name?
Answer» ANSWER: Tin Symbol-Sn Lattin name-Stannum Please HIT the"MARK as BRAINLIEST" and FOLLOW me

36.

Which chemical element has the shortest name?

Answer»

ANSWER:

Tin

Symbol-Sn

Lattin name-Stannum

Please HIT the"MARK as BRAINLIEST" and FOLLOW me

Discussion

37.	Formula to calculate frequency of oscillation of pendulum
Answer» ANSWER: f=1/t. this is REALLY RIGHT answer PLEASE FOLLOW me

37.

Formula to calculate frequency of oscillation of pendulum

Answer»

ANSWER:

f=1/t.

this is REALLY RIGHT answer

PLEASE FOLLOW me

Discussion

38.	How to separate azeotropic mixture of ethyl acteate hexane?
Answer» Explanation: BeForE u JudGE mE... MAkE SuRE thAt YOu'rE PERFECT....?

38.

How to separate azeotropic mixture of ethyl acteate hexane?

Answer»

Explanation:

BeForE u JudGE mE...

MAkE SuRE

thAt YOu'rE PERFECT....?

Discussion

39.	What is the formula of disodium salt?
Answer» ANSWER: C10H16N2NA2O8+2 HOPE IT IS HELP FULL

39.

What is the formula of disodium salt?

Answer»

ANSWER:

C10H16N2NA2O8+2

HOPE IT IS HELP FULL

Discussion

40.	C-c-c-c-c-c=c \| c-c-cwrite the iupac name
Answer» IUPAC name=Dec-1-ene or SIMPLY Decene.

40.

C-c-c-c-c-c=c | c-c-cwrite the iupac name

Answer»

IUPAC name=Dec-1-ene

or SIMPLY Decene.

Discussion

41.	What is the Formula of propan
Answer» Answer: i hope it will help you MARK as Brainliest and FOLLOW me please Explanation: the FORMULA of PROPANE is C3H8

41.

What is the Formula of propan

Answer»

Answer:

i hope it will help you MARK as Brainliest and FOLLOW me please

Explanation:

the FORMULA of PROPANE is C3H8

Discussion

42.	Why do solids are generally denser than liquids and gases
Answer» In case of SOLIDS the molecules are tightly packed and HENCE LARGE MASS is concentrated in very small volume. ... But in case of liquids and gases, their molecules have intermolecular space and hence they don't have large mass concentrated in small volume. Hope it helps you...

42.

Why do solids are generally denser than liquids and gases

Answer»

In case of SOLIDS the molecules are tightly packed and HENCE LARGE MASS is concentrated in very small volume. ... But in case of liquids and gases, their molecules have intermolecular space and hence they don't have large mass concentrated in small volume.

Hope it helps you...

Discussion

43.	Why strong acid hn O3 act as base in liquid HF (hydrogen floured)?
Answer» ANSWER: SORRY i REALLY DONT KNOW

43.

Why strong acid hn O3 act as base in liquid HF (hydrogen floured)?

Answer»

ANSWER:

SORRY i REALLY DONT KNOW

Discussion

44.	Name ine plants that traps and feed on insects
Answer» Pitcher plant , VENUS flytap , DROSERA are some EXAMPLES of PLANTS that traps and FEED in insects

Discussion

45.	Assertion : the pka of acetic acid is lower than that of phenol. Reason : phenoxide ion is more resonance stabilized.
Answer» Answer: see i don't KNOW PLEASE SHARE it to your FRIENDS or search on GOOGLE

45.

Assertion : the pka of acetic acid is lower than that of phenol. Reason : phenoxide ion is more resonance stabilized.

Answer»

Answer:

see i don't KNOW PLEASE SHARE it to your FRIENDS or search on GOOGLE

Discussion

46.	Find ZACD.AT 309\| 400
Answer» DJ KARL SLAM Clarkson FROG DIMENSION from all from

46.

Find ZACD.AT 309| 400

Answer»

DJ KARL SLAM Clarkson FROG DIMENSION from all from

Discussion

47.	Give reason for the existence of three states of matter.
Answer» Explanation: The three states of matter EXIST due to the DIFFERENCE in the inter-molecular force of attraction between the MOLECULES of the substance. When the inter-molecular force of attraction is STRONGER and molecules are close-bound, then the matter exists as solid. When the inter-molecular force of attraction is strong but the molecules are less rigidly bound then the matter exists as liquid. Lastly, when the inter-molecular force of attraction is WEAK and the molecules are very weakly bound then the matter exists as gaseous. ===========☆☆☆☆☆☆☆☆========☆☆☆☆☆☆=======

47.

Give reason for the existence of three states of matter.

Answer»

Explanation:

The three states of matter EXIST due to the DIFFERENCE in the inter-molecular force of attraction between the MOLECULES of the substance.

When the inter-molecular force of attraction is STRONGER and molecules are close-bound, then the matter exists as solid.

When the inter-molecular force of attraction is strong but the molecules are less rigidly bound then the matter exists as liquid.

Lastly, when the inter-molecular force of attraction is WEAK and the molecules are very weakly bound then the matter exists as gaseous.

===========☆☆☆☆☆☆☆☆========☆☆☆☆☆☆=======

Discussion

48.	The nature of bond in h^2s is___________
Answer» COVALENT BOND will be there

Discussion

49.	When a compound contain both aldehyde and ketone group then priority given to aldehyde or ketone?
Answer» ANSWER: PRIORITY is GIVEN to ALDEHYDES.

49.

When a compound contain both aldehyde and ketone group then priority given to aldehyde or ketone?

Answer»

ANSWER: PRIORITY is GIVEN to ALDEHYDES.

Discussion

50.	Can anyone plsss answer them it's imp
Answer» Hêy Fríèñd... Here is the ANSWER... 1. Evaporating Dish (itself) 2. BUNSEN Burner 3. Test tube rack or test tube holder 4. Volumetric Glasswares 5. Wire Gauze . . . . . I HOPE This Will Help You ◉‿◉

50.

Can anyone plsss answer them it's imp

Answer»

Hêy Fríèñd...

Here is the ANSWER...

1. Evaporating Dish (itself)

2. BUNSEN Burner

3. Test tube rack or test tube holder

4. Volumetric Glasswares

5. Wire Gauze

.

I HOPE This Will Help You ◉‿◉

Discussion

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