Explore topic-wise InterviewSolutions in Current Affairs.

WAVELENGTH of GAMMA rays 10^-5 m

answer is

Explanation:

10`-6 nm

Ethylene glycol is produced from ethylene (ethene), VIA the intermediate ethylene oxide. Ethylene oxide reacts with WATER to produce ethylene glycol according to the chemical equation: C2H4O + H2O → HO−CH2CH2−OH. ... The MAJOR BYPRODUCTS are the oligomers diethylene glycol, triethylene glycol, and tetraethylene glycol

ong>Answer:

Satellites are DESIGNED, developed, assembled, and tested at the U R Rao SATELLITE Centre (FORMERLY the ISRO Satellite Centre) in Bangalore. Launch VEHICLES are developed at the Vikram Sarabhai Space Centre in Thiruvananthapuram. Launches take PLACE at the Satish Dhawan Space Centre on Sriharikota Island, near Chennai.

HANS lipppershey

Explanation:

i it is HELPFUL to you

ong>Answer:

tendons

Explanation:

ND LEAVE a THANKS

Internal Revenue Service

Explanation:

please mark it brainliesst

>

The RIGHT ANSWER is FOLIC ACID..

hope it'll help you please make it brainliest

Cerebellum

Explanation:

It is correct HOPE it will help you

pata hai

Explanation:

jitna maine dusro ko samjha hai,

utna mujhko KOI samjh PAYA hi nahi hai,

jitna pyaar dusro diya hai,

utna kabhi paya hi nahi hai,

mujhe bhi koi yaad kare ,

shayad bhagwan NE mujhe aisa banaya hi nahi hai

cerebrum is the answer

cerebrum is the part of the BRAIN which occupies two-third of the human brain.

Mass of Ca(OH)2 = 1.5 x mass of each molecule. = 111 grams

ong>Answer:

Hydrogen is getting oxidised and this is a type of REDOX REACTION in ACIDIC MEDIUM

C. They tell us the number of MOLES of each COMPOUND

ong>Answer:

In chemistry, an element is a pure substance consisting only of atoms that all have the same numbers of protons in their atomic nuclei. Unlike chemical compounds, chemical elements cannot be broken down into simpler SUBSTANCES by chemical means.

I am always fine

tumhara fever KAISA HAI

c)LIMIT how fast the REACTION happens

ong>Answer:

The 7-segment display, also written as “seven segment display”, CONSISTS of seven LEDS (hence its name) arranged in a rectangular fashion as SHOWN. Each of the seven LEDs is CALLED a segment because when illuminated the segment forms part of a numerical digit (both Decimal and Hex) to be displayed.

The hydrogen bond is an attractive interaction between a hydrogen atom from a molecule or a molecular fragment X–H in which X is more electronegative than H, and an atom or a GROUP of atoms in the same or a different molecule, in which there is evidence of bond formation.

लिथियम एक रासायनिक तत्व है। साधारण परिस्थितियों में यह प्रकृति की सबसे हल्की धातु और सबसे कम घनत्व-वाला ठोस पदार्थ है। रासायनिक दृष्टि से यह क्षार धातु समूह का सदस्य है और अन्य क्षार धातुओं की तरह अत्यंत अभिक्रियाशील (रियेक्टिव) है, यानि अन्य पदार्थों के साथ तेज़ी से रासायनिक अभिक्रिया कर लेता है।

25) a) ETHANAL

B) BUTANONE

ong>Explanation:

नाम क्षारातु उदजारेय[कृपया उद्धरण जोड़ें]

अन्य नाम कास्टिक सोडा

लाई[1][2]

एस्कॅराइट

व्हाइट कास्टिक

क्षारातु हाईड्रेट[3]

पहचान आइडेन्टिफायर्स

सी.ए.एस संख्या [1310-73-2][CAS]

पबकैम 14798

EC संख्या 215-185-5

UN संख्या 1823

केईजीजी D01169

MeSH Sodium+Hydroxide

रासा.ई.बी.आई 32145

RTECS number WB4900000

SMILES

InChI

जी-मेलिन संदर्भ 68430

कैमस्पाइडर आई.डी 14114

गुण

आण्विक सूत्र क्षा.सा.ज

मोलर द्रव्यमान 39.9971 g mol-1

दिखावट श्वेत, मोम स्वरूप, अपारदर्शी क्रिस्टल

गंध गन्धरहित

घनत्व 2.13 ग्रा/सें.मी३

गलनांक

318 °C, 591 K, 604 °F

क्वथनांक

1388 °C, 1661 K, 2530 °F

जल में घुलनशीलता 111 g/100 ML (at 20 °C)

मीथेनॉल में घुलनशीलता 23.8 g/100 mL

ईथेनॉल में घुलनशीलता <<13.9 g/100 mL

वाष्प दबाव <2.4 kPa (at 20 °C)

अम्लता (pKa) 13

रिफ्रेक्टिव इंडेक्स (nD) 1.3576

ong>ANSWER:

Covalent bond

The CHEMICAL bond FORMED by the sharing of electrons between TWO atom is CALLED covalent bond .

This is the correct answer of your question

of CACO3 is 0.03mole

ong>Answer:

organic CHEMISTRY part 2

EXPLANATION:

organic chemistry part 2

organic chemistry part 2

ong>ANSWER:

The first bond between two atoms is always a sigma bond and the other bonds are always pi bonds.... and a HYBRIDIZED orbital cannot be INVOLVED in a pi bond. Thus we need to leave ONE electron (in case of CARBON double bond) to let the Carbon have the second bond as a pi bond.

ong>ANSWER:

I THINK it is Aldehyde is right

ong>Answer:

Mohr Salt Titration with KMnO4

To determine the strength of a given potassium permanganate solution against standard FERROUS AMMONIUM sulfate (Mohr's salt) solution.

The strength of and molarity of given KMnO4 solution is FOUND out as 2/y X 31.6 g/l and N/5 moles/liter, respectively.

1)true

2)true

3)true

4)false

5false

MARK AS BRAINLIEST

ong>Answer:

NOBLE gas atoms, LIKE the atoms in other groups, INCREASE steadily in ATOMIC radius from one PERIOD to the next due to the INCREASING number of electrons

dgggxkkgkxgxkgdkdgykdkydydydykddykkgdkyd

MOORE ROPES BBC OK to ACCC

Explanation:

answer (d)

There are 4 bond present in Methane.

Explanation:

As you can see in the above picture 4 Hydrogen atoms are attached with ONE Carbon atom, the lines CONNECTING them are called BONDS.

ong>Answer:

Hexane (as 'ane' denotes) is an ALKANE with six NUMBER of carbon ATOMS.

j,j,jzk ko o uuzjaiizkzkxjuxss. zxcd

Explanation:

for = 30. Verify that sin2g = 2sing COS

ong>Answer:

Answer:

Answer:

Width of rectangle is 25 cm.

Step-by-step explanation:

Given :-

A wire bend in form of square of side 30 cm.

Then wire is again bend in form of rectangle of length 35 cm.

To find :-

Width of the rectangle.

Solution :-

Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will EQUAL to perimeter of rectangle because we are not INCREASING length of wire by one measure we are bending it in square and rectangular shape.

So,

Perimeter of square = 4 × side

⟶ Perimeter = 4 × 30

⟶ Perimeter = 120

Thus,

Perimeter of square is 120 cm.

According to concept, Perimeter of square and perimeter of rectangle are equal.

So, Perimeter of rectangle is 120 cm.

Let, Breadth or width or rectangle be X cm.

We know,

Perimeter of rectangle = 2(Length + Breadth)

⟶ 120 = 2×(35 + x)

⟶ 120 = 70 + 2x

\⟶ 120 - 70 = 2x

⟶ 50 = 2x

⟶ 50/2 = x

⟶ x = 25

We take, Width of rectangle be x.

Therefore,

Width of rectangle is 25 cm.

ong>Answer:

a ) ओजोन

EXPLANATION:

please MARK me brainliest and follow and also GIVE THANKS if you have get any HELP from my answer.

ong>ANSWER:

no. of MOLES of ETHANOYL chloride REQUIRED for complete ACYLATION ofN, N-Dimethylaniline

ong>Explanation:

GENERAL Science - Chemistry GK In Hindi MCQs

1. जीवाणुओं को नष्ट करने के लिए निम्नलिखित में से किस गैस का प्रयोग किया जाता है?

[A] क्लोरीन

[B] ऑक्सीजन

[C] हाइड्रोजन

[D] नियॉन

Hide Answer

Correct Answer: A [क्लोरीन]

2. कहाँ काम करने वाले व्यक्तियों को ब्लैक लंग रोग हो जाता है?

[A] विद्युत्-लेपन उद्योग

[B] कार्बनिक विलायक उद्योग

[C] पेंट विनिर्माण उद्योग

[D] कोयला खान

Hide Answer

Correct Answer: D [कोयला खान]

AMMONIA is a GREAT PLACE to work with the same time

ong>Answer:P>

P is aluminium

Q is argentite

R is FERROUS (iron)

S is limestone rocks

Explanation:

please mark me brainliest and FOLLOW and also give Thanks if you have GET any help from my answer

yvfmugmyfmnsrgrsbfnutiy!mgseEabadbbdzxbtdn

my COMMENT in That equation

hope you understand

xd

lol

ong>Answer:

sanika THO PATA ha

OK

9th ma chali gai

1 April sa GAU gi school

from maharashtra

live Delhi,hapur

okkk

aaur kuch

OPTION 3 is the answer!!!!!!

ong>ANSWER:

14 - 8 = 6 is the RIGHT answer

C:- 2574030731

p:- HELLO

Z●●M

COME gir_ls

ong>EXPLANATION:

0.225

Radius ratio of TETRAHEDRAL VOID is 0.225.

ong>ANSWER:

WAX is the EXAMPLE of molecular crystal

ong>EXPLANATION:

SORRY I did not tell this answer

_______________❤️____________

˙❥˙๑Bismuth CHLORIDE (or butter of BISMUTH) is an inorganic compound with the chemical formula BICL3. It is a covalent compound and is the common source of the Bi3+ ion. In the gas phase and in the crystal, the species adopts a pyramidal structure, in accord with VSEPR theory.✧*。

_______________❤️______________