98971 + Interview Questions in Primary School in Math

1.	Q3. Ram deposited Rs 589642 on Monday in his bank, on Wednesday he withdrew80450 by check from his account and on Friday he withdrew 20000 from ATM. What willbe the balance amount in Ram's bank account?
Answer» Answer: 489,192 Step-by-step explanation: 589642 -80450-20000 = 489192

1.

Q3. Ram deposited Rs 589642 on Monday in his bank, on Wednesday he withdrew80450 by check from his account and on Friday he withdrew 20000 from ATM. What willbe the balance amount in Ram's bank account?

Answer»

Answer:

489,192

Step-by-step explanation:

589642 -80450-20000 = 489192

Discussion

2.	Which letter occurred less than 30 times
Answer» Answer: (C) u letter OCCURRED less than 30 times. (d) a, e, o, i, u is the DECREASING order of their FREQUENCIES.

2.

Which letter occurred less than 30 times

Answer»

Answer:

(C) u letter OCCURRED less than 30 times. (d) a, e, o, i, u is the DECREASING order of their FREQUENCIES.

Discussion

3.	5. The piece of clothbe required for 18la shirt in 2m 65cm. How much cloth willrequired forSuch Shirt?
Answer» ANSWER: 20065÷18 so U GET the answer

3.

5. The piece of clothbe required for 18la shirt in 2m 65cm. How much cloth willrequired forSuch Shirt?

Answer»

ANSWER:

20065÷18 so U GET the answer

Discussion

4.	Venkat added 3x and 5yget 8xy. do you agree with venkat ?justify your answer
Answer» Answer: we cannot ADD 3X and 5y so we cannot get 8xy we get 15XY and that is if only we multiply Step-by-step EXPLANATION: HOPE this helped!!

4.

Venkat added 3x and 5yget 8xy. do you agree with venkat ?justify your answer

Answer»

Answer:

we cannot ADD 3X and 5y

so we cannot get 8xy

we get 15XY and that is if only we multiply

Step-by-step EXPLANATION:

HOPE this helped!!

Discussion

5.	Minus 3 upon 4 into 2 upon 3 + minus 5 upon 6 equal to minus 3 upon 4 into 2 upon 3 + minus 3 upon 4 minus 5 upon 6fastly
Answer» ANSWER: The CORRECT answer is 3.

5.

Minus 3 upon 4 into 2 upon 3 + minus 5 upon 6 equal to minus 3 upon 4 into 2 upon 3 + minus 3 upon 4 minus 5 upon 6fastly

Answer»

ANSWER:

The CORRECT answer is 3.

Discussion

6.	5. If x=5 then 20-5x2 =
Answer» 20-5 x 5 x 2 = 15 x 5 x 2 15 x 10 = 150 .

Discussion

7.	Divide Rs.20 int ratio 2:3.
Answer» ANSWER: Here is ur answer : Let the divided numbers be 2x and 3x. Now PUT the VALUE of x in divided numbers. RS 20 is divided into Rs 8 and Rs 12. Step-by-step explanation: plz mark me as brainliest

7.

Divide Rs.20 int ratio 2:3.

Answer»

ANSWER:

Here is ur answer : Let the divided numbers be 2x and 3x. Now PUT the VALUE of x in divided numbers. RS 20 is divided into Rs 8 and Rs 12.

Step-by-step explanation:

plz mark me as brainliest

Discussion

8.	Solve 3-4 and (½)-2 whose who will answer I will make them brain list answer
Answer» Answer: get it from you soon my FRIEND and my PHONE Step-by-step EXPLANATION: pkosjd

8.

Solve 3-4 and (½)-2 whose who will answer I will make them brain list answer

Answer»

Answer:

get it from you soon my FRIEND and my PHONE

Step-by-step EXPLANATION:

pkosjd

Discussion

9.	The formula to calculate the perimeter of the banner is (a) 2 (l + b) (b) 2πrh + 2πr2 (c) πr + (2l + b) (d) 2 (l + b) + πr2
Answer» ANSWER: a. 2(l+b) is the CORRECT answer

9.

The formula to calculate the perimeter of the banner is (a) 2 (l + b) (b) 2πrh + 2πr2 (c) πr + (2l + b) (d) 2 (l + b) + πr2

Answer»

ANSWER:

a. 2(l+b) is the CORRECT answer

Discussion

10.	Add 3 root 2 + 7 root 3 and root 2 -5 root 3
Answer» To add : $\longrightarrow \sf { (3\sqrt{2} + 7\sqrt{3}) \; \& \; (\sqrt{2}-5\sqrt{3} )} \\$ Answer : $\longrightarrow \sf { 4\sqrt{2} + 2\sqrt{3} }$ Solution : Put the addition sign (+) at the place of and. $\longrightarrow \sf {( 3\sqrt{2} + 7\sqrt{3}) +( \sqrt{2}-5\sqrt{3}) }\\ \\$ Now, removing the brackets. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\longrightarrow \sf { 3\sqrt{2} + 7\sqrt{3}+ \sqrt{2}-5\sqrt{3} }\\ \\$ Grouping the like terms i.e, COLLECT the like terms which has √3 and √2 as common, seperately. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\longrightarrow \sf { 3\sqrt{2}+ \sqrt{2} + 7\sqrt{3} -5\sqrt{3} }\\ \\$ We can see that √2 is common in 3√2 ans 1√2. Also, √3 is common in 7√3 and –5√3. Considering √2 and √3 as common, we can write , ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\longrightarrow \sf { (3+1)\sqrt{2}+ (7-5)\sqrt{3} }\\ \\$ Performing addition and subtraction. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\longrightarrow \sf { (4)\sqrt{2}+ (2)\sqrt{3} }\\ \\$ Removing the brackets. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\longrightarrow\boxed { \sf { 4\sqrt{2}+ 2\sqrt{3} }}\\ \\$ Therefore, 4√2 + 2√3 is our required answer. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ Some RELATED FORMULAE: INDICES identities : • (√a)² = a • √a√b = √ab • √a/√b = √a/b • (√a + √b)(√a - √b) = a - b • (a + √b)(a - √b) = a² - b • (√a ± √b)² = a ± 2√ab + b • (√a + √b)(√c + √d) = √ac + √ad + √bc + √bd

10.

Add 3 root 2 + 7 root 3 and root 2 -5 root 3

Answer»

To add :

$\longrightarrow \sf { (3\sqrt{2} + 7\sqrt{3}) \; \& \; (\sqrt{2}-5\sqrt{3} )} \\$

Answer :

$\longrightarrow \sf { 4\sqrt{2} + 2\sqrt{3} }$

Solution :

Put the addition sign (+) at the place of and.

$\longrightarrow \sf {( 3\sqrt{2} + 7\sqrt{3}) +( \sqrt{2}-5\sqrt{3}) }\\ \\$

Now, removing the brackets.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf { 3\sqrt{2} + 7\sqrt{3}+ \sqrt{2}-5\sqrt{3} }\\ \\$

Grouping the like terms i.e, COLLECT the like terms which has √3 and √2 as common, seperately.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf { 3\sqrt{2}+ \sqrt{2} + 7\sqrt{3} -5\sqrt{3} }\\ \\$

We can see that √2 is common in 3√2 ans 1√2. Also, √3 is common in 7√3 and –5√3. Considering √2 and √3 as common, we can write ,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf { (3+1)\sqrt{2}+ (7-5)\sqrt{3} }\\ \\$

Performing addition and subtraction.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf { (4)\sqrt{2}+ (2)\sqrt{3} }\\ \\$

Removing the brackets.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow\boxed { \sf { 4\sqrt{2}+ 2\sqrt{3} }}\\ \\$

Therefore, 4√2 + 2√3 is our required answer.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Some RELATED FORMULAE:

INDICES identities :

• (√a)² = a

• √a√b = √ab

• √a/√b = √a/b

• (√a + √b)(√a - √b) = a - b

• (a + √b)(a - √b) = a² - b

• (√a ± √b)² = a ± 2√ab + b

• (√a + √b)(√c + √d) = √ac + √ad + √bc + √bd

Discussion

11.	Q2. In a class test 5 marks are awarded for every correct answer and -2 marks areawarded for every incorrect answer If Reshma gets 5 answers correct and 6 incorrect,then what will be her score?
Answer» Answer: 13 Step-by-step EXPLANATION: RESHAMA score= correct =5×5=25 incorrrect=-2×6=-12 25-12=13

11.

Q2. In a class test 5 marks are awarded for every correct answer and -2 marks areawarded for every incorrect answer If Reshma gets 5 answers correct and 6 incorrect,then what will be her score?

Answer»

Answer:

13

Step-by-step EXPLANATION:

RESHAMA score=

correct =5×5=25

incorrrect=-2×6=-12

25-12=13

Discussion

12.	The HCF of 45 and 90 ka h.c.f.kya hoga
Answer» ANSWER: HCF = 90. HPE this HELPS you

12.

The HCF of 45 and 90 ka h.c.f.kya hoga

Answer»

ANSWER:

HCF = 90. HPE this HELPS you

Discussion

13.	Ul. Solve anySimplify (x - y) (2x - y) + (x - 2y) (3x - 2y) + (2x + y) (x + 7y).
Answer» ANSWER: please mark it as BRAINLIEST answer! Step-by-step EXPLANATION: =>(x-y)(2x-y)+(x-2y)(3x-2y)+(2x+y)(x+7y) =>x(2x-y)-y(2x-y)+x(3x-2y)-2y(3x-2y)+2x(x+7y)+y(x+7y) =>2x^2-xy-2xy+y^2+3x^2-2xy-6xy+4y^2+2x^2+14xy+xy+7y^2 =>(2x^2+3x^2+2x^2)+(y^2+4y^2+7y^2)+(-xy-2xy-2xy-6xy+14xy+xy) =>(7x^2)+(12y^2)+(4xy) =>7x^2+12y^2+4xy Ans.

13.

Ul. Solve anySimplify (x - y) (2x - y) + (x - 2y) (3x - 2y) + (2x + y) (x + 7y).

Answer»

ANSWER:

please mark it as BRAINLIEST answer!

Step-by-step EXPLANATION:

=>(x-y)(2x-y)+(x-2y)(3x-2y)+(2x+y)(x+7y)

=>x(2x-y)-y(2x-y)+x(3x-2y)-2y(3x-2y)+2x(x+7y)+y(x+7y)

=>2x^2-xy-2xy+y^2+3x^2-2xy-6xy+4y^2+2x^2+14xy+xy+7y^2

=>(2x^2+3x^2+2x^2)+(y^2+4y^2+7y^2)+(-xy-2xy-2xy-6xy+14xy+xy)

=>(7x^2)+(12y^2)+(4xy)

=>7x^2+12y^2+4xy Ans.

Discussion

14.	Find the absolute value of each of the followinga) 6×(-12) =b) (-9)×(-19)=c) (-81)divide 9=d) (-169)divide(-13)
Answer» Answer: a) 6×(-12) = -72 b) (-9)×(-19) = 171 c) (-81)divide 9 = -9 d) (-169)divide(-13) = 13 pls mark me as the brainliest...

14.

Find the absolute value of each of the followinga) 6×(-12) =b) (-9)×(-19)=c) (-81)divide 9=d) (-169)divide(-13)

Answer»

Answer:

a) 6×(-12) = -72

b) (-9)×(-19) = 171

c) (-81)divide 9 = -9

d) (-169)divide(-13) = 13

pls mark me as the brainliest...

Discussion

15.	Please fast i will mark you as brainlest.
Answer» ANSWER: 56 is the answer PLEASE MARK me BRAINLIST

15.

Please fast i will mark you as brainlest.

Answer»

ANSWER:

56 is the answer

PLEASE MARK me BRAINLIST

Discussion

16.	Add the following rational numbers:--⅙ and 3/10
Answer» Answer: 2/15 Step-by-step EXPLANATION: -1/6+3/10 take the lcm of 6 and 10 then we will get 30 ND then write 30 as DENOMINATOR nd-5+6in numerator.

16.

Add the following rational numbers:--⅙ and 3/10

Answer»

Answer:

2/15

Step-by-step EXPLANATION:

-1/6+3/10

take the lcm of 6 and 10

then we will get 30 ND then write 30 as DENOMINATOR nd-5+6in numerator.

Discussion

17.	2x+1 =x+1)²-x²2x+1 =19,x=919=10²-9²
Answer» Step-by-step EXPLANATION: your QUESTION is not COMPLETE

17.

2x+1 =x+1)²-x²2x+1 =19,x=919=10²-9²

Answer»

Step-by-step EXPLANATION:

your QUESTION is not COMPLETE

Discussion

18.	Simplify 18 2/3- 15 5/6+ 4 1/8
Answer» ANSWER: 18 2/3-15 5/6+4 1/8 · Answer · Answer · STILL have QUESTIONS?

18.

Simplify 18 2/3- 15 5/6+ 4 1/8

Answer»

ANSWER:

18 2/3-15 5/6+4 1/8 · Answer · Answer · STILL have QUESTIONS?

Discussion

19.	If the cost of 4 and half litre of milk is 39 and half rupees find the cost of 1 litre of milk
Answer» Answer: Answer: \begin{GATHERED} = 4 \times \frac{1}{2} \div 89 \times \frac{1}{2} \\ = \frac{9}{2} \ \div \frac{179}{2} \\ = \frac{9}{2} \times \frac{2}{179 } (reciprocl) \\ = \frac{9}{179} \END{gathered} =4× 2 1 ÷89× 2 1 = 2 9 ÷ 2 179 = 2 9 × 179 2 (reciprocl) = 179 9 Step-by-step explanation: Hope you understand.

19.

If the cost of 4 and half litre of milk is 39 and half rupees find the cost of 1 litre of milk

Answer»

Answer:

Answer:

\begin{GATHERED} = 4 \times \frac{1}{2} \div 89 \times \frac{1}{2} \\ = \frac{9}{2} \ \div \frac{179}{2} \\ = \frac{9}{2} \times \frac{2}{179 } (reciprocl) \\ = \frac{9}{179} \END{gathered}

=4×

2

1

÷89×

2

1

=

2

9

÷

2

179

=

2

9

×

179

2

(reciprocl)

=

179

9

Step-by-step explanation:

Hope you understand.

Discussion

20.	If the length of a line 7.5 cm and it is extended by 2.5cm , fine the mid point of this line??
Answer» Answer: 5 cm Step-by-step explanation: ADD 7.5 and 2.5 you will GET 10 cm. And then dived it by 2.

20.

If the length of a line 7.5 cm and it is extended by 2.5cm , fine the mid point of this line??

Answer»

Answer:

5 cm

Step-by-step explanation:

ADD 7.5 and 2.5 you will GET 10 cm.

And then dived it by 2.

Discussion

21.	.Lem of numeratorsHCF of denominators
Answer» ANSWER: is 2/5 Step-by-step EXPLANATION: MARK as BRAINLIEST answer

21.

.Lem of numeratorsHCF of denominators

Answer»

ANSWER:

is 2/5

Step-by-step EXPLANATION:

MARK as BRAINLIEST answer

Discussion

22.	If A = { 4 5 6 } and B = { x : 0
Answer» Step-by-step explanation: B is equal to number greater than 0 and less than 5 which includes 1,2,3 and 4 B={1,2,3,4} I hope it HELPS you thanks

22.

If A = { 4 5 6 } and B = { x : 0

Answer»

Step-by-step explanation:

B is equal to number greater than 0 and less than 5

which includes 1,2,3 and 4

B={1,2,3,4}

I hope it HELPS you

thanks

Discussion

23.	15 root 6 + root 216
Answer» Answer: 21 root 6 is the answer Step-by-step explanation: root 216 is BASICALLY 6 root 6 (since 216 is the CUBE of 6) So, 15 root 6 + 6 root 6 = root 6 (15+6) =21 root 6 =51.45 apprx. Step-by-step explanation:

23.

15 root 6 + root 216

Answer»

Answer:

21 root 6 is the answer

Step-by-step explanation:

root 216 is BASICALLY 6 root 6 (since 216 is the CUBE of 6)

So, 15 root 6 + 6 root 6

= root 6 (15+6)

=21 root 6

=51.45 apprx.

Step-by-step explanation:

Discussion

24.	राइट फाइव वन मल्टीपल ऑफ फाइव
Answer» Answer: 5, 10, 15, 20, 25, ….., 50, 55, 60,….., 120, 125,….. All NUMBERS which can be divided or are a product of 5 are multiples of 5. ... Hence, there is a DIFFERENCE between factors and multiples

24.

राइट फाइव वन मल्टीपल ऑफ फाइव

Answer»

Answer:

5, 10, 15, 20, 25, ….., 50, 55, 60,….., 120, 125,….. All NUMBERS which can be divided or are a product of 5 are multiples of 5. ... Hence, there is a DIFFERENCE between factors and multiples

Discussion

25.	Two acute angles cannot form a pair of supplementary angles justify
Answer» Step-by-step EXPLANATION: As each of the ANGLE is <900.So, the sum of two acute angles is always less than 1800. Hence they cannot FORM PAIR of supplementary angles. As each of the angle is <90 0 .So, the sum of two acute angles is always less than 180 0 .Hence they cannot form pair of supplementary angles.

25.

Two acute angles cannot form a pair of supplementary angles justify

Answer»

Step-by-step EXPLANATION:

As each of the ANGLE is <900.So, the sum of two acute angles is always less than 1800. Hence they cannot FORM PAIR of supplementary angles.

As each of the angle is <90

0

.So, the sum of two acute angles is always less than 180

0

.Hence they cannot form pair of supplementary angles.

Discussion

26.	If two straight lines intersect each other, and one angle is 40° then opposite angle is ______
Answer» Answer: if TWO straight lines intersect each other and one angle is 40 DEGREES then OPPOSITE angle is also EQUAL to 40 DEGREE

26.

If two straight lines intersect each other, and one angle is 40° then opposite angle is ______

Answer»

Answer:

if TWO straight lines intersect each other and one angle is 40 DEGREES then OPPOSITE angle is also EQUAL to 40 DEGREE

Discussion

27.	Expand (3x+2y)² by using identity
Answer» (3X+2Y)^2 (3x)^2+2×3x×2y+(2y)^2 9x^2+12xy+4y^2 Hope it HELPS you

27.

Expand (3x+2y)² by using identity

Answer»

(3X+2Y)^2

(3x)^2+2×3x×2y+(2y)^2

9x^2+12xy+4y^2

Hope it HELPS you

Discussion

28.	2 root 3 + 8 root 27
Answer» ANSWER: $26\sqrt{3}$ Step-by-step EXPLANATION: $2\sqrt{3}$ + $8\sqrt{27}$ = $2\sqrt{3}$ + $8\sqrt{93}$ = $2\sqrt{3}$ + $8\sqrt{9} \sqrt{3}$ = $2\sqrt{3}$ + $83 \sqrt{3}$ = $2\sqrt{3}$ + $24 \sqrt{3}$ = $(2+24)\sqrt{3}$ = $26\sqrt{3}$

28.

2 root 3 + 8 root 27

Answer»

ANSWER:

$26\sqrt{3}$

Step-by-step EXPLANATION:

$2\sqrt{3}$ + $8\sqrt{27}$

= $2\sqrt{3}$ + $8\sqrt{9*3}$

= $2\sqrt{3}$ + $8\sqrt{9} * \sqrt{3}$

= $2\sqrt{3}$ + $8*3* \sqrt{3}$

= $2\sqrt{3}$ + $24 \sqrt{3}$

= $(2+24)\sqrt{3}$

= $26\sqrt{3}$

Discussion

29.	4/3 divided by x = -5/2
Answer» ANSWER: $\frac{4}{3} \div x = \frac{ - 5}{2} \\ x = \frac{ - 5}{2} \times \frac{3}{4} \\ x = \frac{ - 15}{8} \\ so \: there \: is \: x \: value \: is \: \frac{ - 15}{8}$

29.

4/3 divided by x = -5/2

Answer»

ANSWER:

$\frac{4}{3} \div x = \frac{ - 5}{2} \\ x = \frac{ - 5}{2} \times \frac{3}{4} \\ x = \frac{ - 15}{8} \\ so \: there \: is \: x \: value \: is \: \frac{ - 15}{8}$

Discussion

30.	1. add 7x-5 and 3x+112.subract 4n-1 from 4+7n
Answer» Step-by-step explanation: 1. =7x-5 +3x+11 =10x+6 2. =4+7n-(4n-1) =4+7n-4n+1 =3n+5

30.

1. add 7x-5 and 3x+112.subract 4n-1 from 4+7n

Answer»

Step-by-step explanation:

1. =7x-5 +3x+11

=10x+6

2. =4+7n-(4n-1)

=4+7n-4n+1

=3n+5

Discussion

31.	Evaluate gggsggsushgsnigsjahxhbsjs ok hi sn
Answer» Step-by-step EXPLANATION: =(-4/5)³ = -64/125 Mark as BRAINLIST

31.

Evaluate gggsggsushgsnigsjahxhbsjs ok hi sn

Answer»

Step-by-step EXPLANATION:

=(-4/5)³

= -64/125

Mark as BRAINLIST

Discussion

32.	800 × (112/ 100 ) = _________
Answer» Answer: 896 Step-by-step explanation: 800 × (112/ 100 ) = 8 (112) = 896

32.

800 × (112/ 100 ) = _________

Answer»

Answer:

896

Step-by-step explanation:

800 × (112/ 100 )

= 8 (112)

= 896

Discussion

33.	4. The heart rates of different animalsare shown in the chart.AnimalHeart RateLarge dog 200 beats in 2 minLion40 beats in 1 minElephant 140 beats in 4 minChicken 120 beats in 30 sa) Write each rate as a unit rate(number of beats per minute).
Answer»

Discussion

34.	Father of Algebra is known asA) DiophantusB) GaussC) AryabhattaD) Euler
Answer»

Discussion

35.	Explain love in french and English both I will mark as brainlist
Answer»

Discussion

36.	Simplify : pls answer my question fast
Answer»

Discussion

37.	Answer the following step by step eXplaination solve 11, 12
Answer» ANSWER: ATTITUDE KIS KA ANDAF NHI HOYA SAB KA ANDAR HOTA HA

37.

Answer the following step by step eXplaination solve 11, 12

Answer»

ANSWER:

ATTITUDE KIS KA ANDAF NHI HOYA SAB KA ANDAR HOTA HA

Discussion

38.	The value of {-37 - (-15) - 2 } isplease answer!
Answer» ANSWER: Answer of the given question is ( –24) Step-by-step explanation: *First: (–×–=+) SECOND: so, –37+15(–2) THIRD*: =–22–2 = –24

38.

The value of {-37 - (-15) - 2 } isplease answer!

Answer»

ANSWER:

Answer of the given question is ( –24)

Step-by-step explanation:

First: (–×–=+)

SECOND: so, –37+15(–2)

THIRD: =–22–2 = –24

Discussion

39.	Write a pair of positive and negative integer whose difference is-9
Answer» ANSWER: -19+10 Step-by-step EXPLANATION: PLEASE MARK ME AS BRAINLIST !!!!

39.

Write a pair of positive and negative integer whose difference is-9

Answer»

ANSWER:

-19+10

Step-by-step EXPLANATION:

PLEASE MARK ME AS BRAINLIST !!!!

Discussion

40.	Find the value of x, if 25%-1 + 100 = 524-1
Answer» ANSWER: where is X Step-by-step EXPLANATION: in this EQUATION no x INCLUDE

40.

Find the value of x, if 25%-1 + 100 = 524-1

Answer»

ANSWER:

where is X

Step-by-step EXPLANATION:

in this EQUATION no x INCLUDE

Discussion

41.	Find the product of 7abc×-5abc ×9abc
Answer» ANSWER: -315a^3b^3c^3 Step-by-step explanation: *79 = 63 63-5 = -315* HOPE THIS HELPS YOU!!! PLEASE MARK ME AS BRAINLIEST IF IT DID!!

41.

Find the product of 7abc×-5abc ×9abc

Answer»

ANSWER:

-315a^3b^3c^3

Step-by-step explanation:

7*9 = 63

63*-5 = -315

HOPE THIS HELPS YOU!!!

PLEASE MARK ME AS BRAINLIEST IF IT DID!!

Discussion

42.	Shyama bought 5kg 300g apples and 3kg 250g mangoes. Sarala bought 4kg 800g oranges and 4kg 150g bananas. who bought more fruits? And by how much?
Answer» ANSWER: SHYAMA BOUGHT more fruits by 2KG 50g. Step-by-step explanation:

42.

Shyama bought 5kg 300g apples and 3kg 250g mangoes. Sarala bought 4kg 800g oranges and 4kg 150g bananas. who bought more fruits? And by how much?

Answer»

ANSWER:

SHYAMA BOUGHT more fruits by 2KG 50g.

Step-by-step explanation:

Discussion

43.	If 24 a is a multiple of 9 then the value of a is
Answer» Answer: 3 Step-by-step EXPLANATION: because when we MULTIPLY by 3 to 24 give 72

43.

If 24 a is a multiple of 9 then the value of a is

Answer»

Answer:

3

Step-by-step EXPLANATION:

because when we MULTIPLY by 3 to 24 give 72

Discussion

44.	19. A boy got 3 marks for each correct answer and lost 2 marks for each incorrect answer.He attended 17 correct answers and obtained 37 marks. Find the number of incorrectanswers he has written.
Answer» ANSWER: He LOST 14 marks. Step-by-step EXPLANATION:

44.

19. A boy got 3 marks for each correct answer and lost 2 marks for each incorrect answer.He attended 17 correct answers and obtained 37 marks. Find the number of incorrectanswers he has written.

Answer»

ANSWER:

He LOST 14 marks.

Step-by-step EXPLANATION:

Discussion

45.	Please give the answers fast
Answer» Step-by-step EXPLANATION: a=2 b=1/125 c=2√3+24√2 d=21√6 e=10 f=35^3/2 h=-3-√2 g=9

45.

Please give the answers fast

Answer»

Step-by-step EXPLANATION:

a=2

b=1/125

c=2√3+24√2

d=21√6

e=10

f=35^3/2

h=-3-√2

g=9

Discussion

46.	R.H.S of 3z+2=5-3Z ( ) A)3z+2 B)5-32 C)3 D)2j
Answer» ANSWER: Your answer is B)5-3Z Hope it HELPS

46.

R.H.S of 3z+2=5-3Z ( ) A)3z+2 B)5-32 C)3 D)2j

Answer»

ANSWER:

Your answer is B)5-3Z

Hope it HELPS

Discussion

47.	2. Draw a rough sketch of a quadrilateral ABCD. Draw its diagonals.aWhere do these diagonals intersect ?
Answer» Step-by-step explanation: Teh diagnols intersect each other at POINT o. Hope it helps you Pls MARK me as BRAINELIST

47.

2. Draw a rough sketch of a quadrilateral ABCD. Draw its diagonals.aWhere do these diagonals intersect ?

Answer»

Step-by-step explanation:

Teh diagnols intersect each other at POINT o.

Hope it helps you

Pls MARK me as BRAINELIST

Discussion

48.	16] Identify the following terms in the expression:A] coefficientsB] variablesC] constant9s - 6a + 45b - 11
Answer» Answer: 9s-6a+45b-11 constant TERMS are 11 coefficient terms are 9,-6,45 variables are s,a,and B

48.

16] Identify the following terms in the expression:A] coefficientsB] variablesC] constant9s - 6a + 45b - 11

Answer»

Answer:

9s-6a+45b-11

constant TERMS are 11

coefficient terms are 9,-6,45

variables are s,a,and B

Discussion

49.	(-15)×0×(-18) pls explain me
Answer» Answer: 0 Step-by-step EXPLANATION: because 0 is MULTIPLY by any NUMBER so it PRODUCE 0

49.

(-15)×0×(-18) pls explain me

Answer»

Answer:

0

Step-by-step EXPLANATION:

because 0 is MULTIPLY by any NUMBER so it PRODUCE 0

Discussion

50.	4. Starting from (-1) × 5, write various products showing some pattern to show(-1)× (-1)=1.
Answer» Answer: SOME IMPORTANT FORMULAS AND IDENTITY:- 1. (α+в)²= α²+2αв+в² 2. (α+в)²= (α-в)²+4αв 3. (α-в)²= α²-2αв+в² he 4. (α-в)²= (α+в)²-4αв 5. α² + в²= (α+в)² - 2αв. 6. α² + в²= (α-в)² + 2αв. 7. α²-в² =(α + в)(α - в) 8. 2(α² + в²) = (α+ в)² + (α - в)² 9. 4αв = (α + в)² -(α-в)² 10. αв ={(α+в)/2}²-{(α-в)/2}² 11. (α + в + ¢)² = α² + в² + ¢² + 2(αв + в¢ + ¢α) 12. (α + в)³ = α³ + 3α²в + 3αв² + в³ 13. (α + в)³ = α³ + в³ + 3αв(α + в) 14. (α-в)³=α³-3α²в+3αв²-в³ 15. α³ + в³ = (α + в) (α² -αв + в²) 16. α³ + в³ = (α+ в)³ -3αв(α+ в) 17. α³ -в³ = (α -в) (α² + αв + в²) 18. α³ -в³ = (α-в)³ + 3αв(α-в)

50.

4. Starting from (-1) × 5, write various products showing some pattern to show(-1)× (-1)=1.

Answer»

Answer:

SOME IMPORTANT FORMULAS AND IDENTITY:-

1. (α+в)²= α²+2αв+в²

2. (α+в)²= (α-в)²+4αв

3. (α-в)²= α²-2αв+в² he

4. (α-в)²= (α+в)²-4αв

5. α² + в²= (α+в)² - 2αв.

6. α² + в²= (α-в)² + 2αв.

7. α²-в² =(α + в)(α - в)

8. 2(α² + в²) = (α+ в)² + (α - в)²

9. 4αв = (α + в)² -(α-в)²

10. αв ={(α+в)/2}²-{(α-в)/2}²

11. (α + в + ¢)² = α² + в² + ¢² + 2(αв + в¢ + ¢α)

12. (α + в)³ = α³ + 3α²в + 3αв² + в³

13. (α + в)³ = α³ + в³ + 3αв(α + в)

14. (α-в)³=α³-3α²в+3αв²-в³

15. α³ + в³ = (α + в) (α² -αв + в²)

16. α³ + в³ = (α+ в)³ -3αв(α+ в)

17. α³ -в³ = (α -в) (α² + αв + в²)

18. α³ -в³ = (α-в)³ + 3αв(α-в)

Discussion

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